A={a,b,c,1,2,3,octopus,∅,0} B=N C={0} For each of the following statements, select either True or False. a) A∩B={0,1,2,3} Answer 1 b) C−A=∅ Answer 2 c) B∪P(C)=B Answer 3 d) C∈P(C) Answer 4

Answer:

D.

The IQR for Week 1 is 31, and the IQR for Week 2 is 25.

Step-by-step explanation:

Answer: D.The IQR for week 1 is 31 and the IQR for week 2 is 25

Step-by-step explanation: When you divid a data set in groups of 4 and measure the bulk of the values, this is called Interquatile Range (IQR).

It's calculated as follows:

1) Put the data in order;

week 1 : 39 50 58 63 72 81 104

week 2 : 34 54 62 68 72 79 110

2) Find the median of each data set:

*Note: Median is the middle value of a set.

week 1 : Median 63

week 2 : Median 68

3) Find Q1, which is the median in the lower half of the set:

week 1: the lower set is 39 50 58.

The middle value is 50.

So Q1 = 50.

week 2: the lower set is 34 54 62

The middle value is 54.

So Q1 = 54.

4) Find Q3, which is the middle value of the upper half:

week 1 : the upper half is 72 81 104

Q2 = 81

week 2 :  the upper half is 72 79 110

Q2 = 79

5) To determine IQR, subtract Q1 and Q3:

week 1: 81 - 50 = 31

week 2 : 79 - 54 = 25

In conclusion, the IQR for week 1 is 31 and for week 2 is 25.

Answer:

The probability that a randomly selected American adult takes multivitamins regularly and works out regularly is  0.103

Step-by-step explanation:

p(Americans adults take multivitamins regularly) = 50% = 0.50

p(American adults work out regularly) = 20.6 = 0.206

p(Americans adults take multivitamins regularly and American adults work out regularly) = 0.50* 0.206 = 0.103

Thus, p(Americans adults take multivitamins regularly and American adults work out regularly)  = 0.103

Answer:

f'(x) is increasing in the open interval (-1/2, +∞), and it is decreasing in the interval (-∞, -1/2).

Step-by-step explanation:

f'(x) is a quadratic function with positive main coefficient, then it will be decreasing until the x-coordinate of its vertex and it will be increasing from there onwards. The x-coordinate of the vertex is given by the equation -b/2a = -1/2. Hence

- f'(x) is incresing in the interval (-1/2, +∞)

- f'(x) is decreasing in the interval (-∞, -1/2)

Final answer:

To find intervals where f'(x) is increasing or decreasing, locate the critical points by solving f'(x) = 0 and test the signs of f'(x) around these points. This process determines where the original function f(x) is increasing or decreasing.

Explanation:

To determine the open intervals in which the derivative of a function f(x), denoted as f'(x), is increasing or decreasing, one must:

In the scenario one would solve the equation for f'(x) = 0 to find the critical points. Once these are found, the signs of f'(x) to the left and right of these points can be tested to see where the function is increasing or always decreasing.

Answer:

  43 months

Step-by-step explanation:

The amortization formula is ...

  A = P(r/n)/(1 -(1 +r/n)^(-nt))

We want to find the value of t for monthly payment A, financed amount P, interest rate r, and compounding monthly (n=12). Filling in the values, we have ...

  75 = 2500(0.135/12)/(1 -(1 +0.135/12)^(-12t))

  1 -(1.01125^(-12t) = 2500·0.135/(12·75) = 0.375

  1 -0.375 = 1.01125^(-12t) . . . . . add 1.01125^(-12t) -0.375

Next, take logarithms and divide by the coefficient of t.

  log(0.625)/(-12log(1.01125)) = t ≈ 3.50106 . . . . years

In months, that is ...

  3.50106×12 ≈ 42.01

The balance will be not quite zero after 42 payments. (It will be about $0.94.) It will take 43 payments to pay off the credit card balance.

Answer:

42

I did the test and got it right hope this helps

Answer:

2xy

Step-by-step explanation:

10x²y² - 8xy

2xy(5xy - 4)

The greatest common factor (GCF) of the expressions 10x^2y^2 and 8xy is 2xy. The GCF for the numbers is 2, and for the variables x and y it's x and y, respectively.

The subject is the greatest common factor (GCF), applied to algebraic expressions. The GCF is the largest expression that can be multiplied by another expression to get the original expression. For the expressions 10x^2y^2 and 8xy, the numbers are 10 and 8. Their GCF is 2. The term x appears in both expressions, and the lowest power of x is 1. The term y also appears in both expressions, with the lowest power being 1. So, 2x and y are the GCFs for the numbers and the variables respectively. Combining them, we get 2xy, which is the GCF of 10x^2y^2 and 8xy.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

p(X> 6 ) = 0.01132 + 0.01672 = 0.0280

Step-by-step explanation:

The probability that the US woman would have more than six children is equal to the probability that she would have children that are equal to 7 or that she would that she would have children equal to 8 or more as shown on the table in the question

Now representing this mathematically we have

                     p(X > 6) = p(x =7 ) + p(x = 8 or more)

    From the table the p(x = 7 ) [tex]= \frac{523}{46165} = 0.01132[/tex]

     And the p(x= 8 or more ) [tex]= \frac{772}{46165} = 0.01672[/tex]

Hence  p(X> 6 ) = 0.01132 + 0.01672 = 0.0280

An estimation of the probability that a U.S. woman has more than six children using the Empirical Method involves counting how many women in the sample data have more than six children divided by the total number of women in the sample. The specific calculation can't be provided without the concrete data.

To estimate the probability that a U.S. woman has more than six children using the Empirical Method, you would need specific data from the sample. However, since this data hasn't been provided, it's important to explain the process.

First, list the number of women in your sample data who have more than six children. Let's call this number 'X'. Then, calculate the total number of women in your sample data. Let's call this number 'Y'. The empirical probability is then calculated by dividing the number of successful outcomes (X) by the total number of outcomes (Y).

So, if we had data, the equation would be: Probability = X/ Y. Remember to round your answer to four decimal places.

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Answer:

The probability that the woman selected does not have​ red/green color​ blindness is 0.9945.

Step-by-step explanation:

Let X = a woman has red/green color blindness.

It is provided that, in a certain group of women the rate of red/green color blindness is P (X) = 0.0055.

A complement of an event E, is defined as the event of not E.

The probability of complement of an event E is:

[tex]P(E^{c})=1-P(E)[/tex]

Compute the probability that the woman selected does not have​ red/green color​ blindness as follows:

[tex]P (X^{c})=1-P(X)\\=1-0.0055\\=0.9945[/tex]

Thus, the probability of the complement of the event of a woman having red/green color blindness is 0.9945.

The probability that the woman selected does not have​ red/green color​ blindness is 0.9945.

Since A certain group of women has a 0.55​% rate of​ red/green color blindness.

Here we assume a woman has red/green color blindness be X

So, here the probability should be

= 1-0.55%

= 0.9945

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Answer:

Step-by-step explanation:

Hello!

Since the data on the text is missing, I've found a similar exercise with the same questions so I'm going to use the data of that one to explain how to calculate the probabilities.

We have a sample of 323000 high school students

154000 are girls, of those 47700 dropped out

16900 are boys, of those 10300 dropped out

a) To calculate this probability you have to divide the total number of girls by the total number of students:

P(G)= 154000/323000= 0.476 ≅ 0.48

b) In this item you have to calculate the probability of dropouts, the total of students that dropped out are the girls + boys that dropped out:

Dropouts: 47700+10300= 58000

Now you divide it by the total of students to reach the probability:

P(D)= 58000/323000= 0.179≅ 0.18

c) Now you have to calculate the probability of the intersection between the events "female" and "dropped out", symbolically:

P(G∩D)= P(G)*P(D)= 0.48*0.18= 0.0864

d) The probability of the student dropping out given that it is female is a conditional probability and you can calculate using the following formula:

P(D/G)= P(G∩D) = 0.0864 = 0.18

                 P(G)        0.48

e) Now you have to calculate the probability of the student being a femal, given that she dropped out of school, symbolically:

P(G/D)= P(G∩D) = 0.0864 = 0.48

                 P(D)        0.88

Note:

As you can see in d) P(D/G)=P(D)=0.18 and in e) P(G/D)=P(G)=0.48, this means that both events "the student is a girl" and "the student dropped out" are independent.

Remember two events are not independent when the occurrence of one modifies the probability of occurrence of the other.

I hope it helps!

Answer:

37.9 cm

Step-by-step explanation:

Arc length is:

s = 2πr (θ/360°)

where r is the radius and θ is the arc angle.

40π cm = 2πr (190°/360°)

20 cm = r (190°/360°)

r = 37.9 cm

Answer: the radius of the circle on which the arc sits is 3.8 cm

Step-by-step explanation:

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ represents the central angle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

θ = 190 degrees

Length of arc = 40π centimeters

Therefore,

40π = 190/360 × 2 × π × r

Dividing both sides of the equation by π, it becomes

40 = 380r/360

380r = 40 × 360 = 1440

r = 1440/380

r = 3.8 to the nearest tenth

Answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is 0.334.

Step-by-step explanation:

We have a normal distribution with mean=56 years and s.d.=4 years.

We have to calculate the probability that a randomly selected CEO have an age between 50 and 55.

We have to calculate the z-value for 50 and 55.

For x=50:

[tex]z=\frac{x-\mu}{\sigma}=\frac{50-56}{4}=\frac{-6}{4}= -1.5[/tex]

For x=55:

[tex]z=\frac{x-\mu}{\sigma}=\frac{55-56}{4}=\frac{-1}{4}=-0.25[/tex]

The probability of being between 50 and 55 years is equal to the difference between the probability of being under 55 years and the probability of being under 50 years:

[tex]P(50<x<55)=P(x<55)-P(x<50)\\\\P(50<x<55)=P(z<-0.25)-P(z<-1.5)\\\\P(50<x<55)=0.40129-0.06681\\\\P(50<x<55)=0.33448[/tex]

Final answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is approximately 0.3345.

Explanation:

To find the probability that the age of a randomly selected CEO will be between 50 and 55 years old, we need to calculate the z-scores for both values and then use the standard normal distribution table.

Step 1: Calculate the z-score for 50 years old:

z = (50 - 56) / 4 = -1.5

Step 2: Calculate the z-score for 55 years old:

z = (55 - 56) / 4 = -0.25

Step 3: Use the standard normal distribution table to find the area to the left of each z-score:

P(z < -1.5) = 0.0668

P(z < -0.25) = 0.4013

Step 4: Calculate the probability between the two z-scores:

P(-1.5 < z < -0.25) = P(z < -0.25) - P(z < -1.5) = 0.4013 - 0.0668 = 0.3345

Therefore, the probability that the age of a randomly selected CEO will be between 50 and 55 years old is approximately 0.3345.

Answer:

The answer to your question is Domain (-∞, ∞) Range  [-4, ∞)

Step-by-step explanation:

The Domain is the set of all possible values of the independent variable (x).

The Range is the set of all the possible values of the dependent variable when substitute the domain in the function.

On the graph, we find the domain looking at the x-axis

On a graph, we find the range, looking at all the y-axis

In this graph, x has values from -infinite to infinite, then, the domain is (-∞, ∞).

In this graph, y has values from -4 to infinite, then, the range is [-4, ∞)

Answer:

Step-by-step explanation:

A. The three-year zero coupon bond, because the future value is receiver sooner, thus the present value is higher.

B. The three year 4% coupon bond because it pays interest payments, whereas the zero coupon bond is pure discount bond.

C. The 6% coupon bond because the coupon (interest) payments are higher.

Final answer:

In summary, a three-year zero-coupon bond has a higher price than a five-year zero-coupon bond due to its shorter maturity. A three-year 4% coupon bond will have a higher price than a three-year zero-coupon bond because it provides interest payments. A two-year 6% coupon bond will have a higher price than a two-year 5% coupon bond due to its higher interest payments.

Explanation:

The Treasury security prices are determined by several factors, including maturity and coupon rates. In answering the questions presented by the student, we compare the prices of different types of Treasury securities based on these attributes.

Answer:

(D) -48.193

Step-by-step explanation:

We know that regression equation is

y=a+bx where a is intercept and b is slope of the regression equation.

[tex]Slope=b=\frac{sum(x-xbar)(y-ybar)}{sum(x-xbar)^2}[/tex]

City            Price ($)(x)     Sales(Y)  

River Falls       1.30            100

Hudson           1.60            90

Ellsworth         1.80            90

Prescott           2.00          40

Rock Elm         2.40           38

Stillwater         2.90           32

xbar=sumx/n=12/6=2

ybar=sumy/n=390/6=65

x y x-xbar y-ybar (x-xbar)(y-ybar) (x-xbar)²

1.3 100   -0.7   35              -24.5          0.49

1.6 90  -0.4 25                    -10          0.16

1.8 90   -0.2 25                      -5          0.04

2 40     0         -25                       0           0

2.4 38    0.4 -27                    -10.8         0.16

2.9 32   0.9 -33                   -29.7         0.81

                 Total                     -80                  1.66

[tex]Slope=b=\frac{sum(x-xbar)(y-ybar)}{sum(x-xbar)^2}[/tex]

b=-80/1.66

b=-48.193

Final answer:

The estimated slope parameter, which represents the rate of change in candy bar sales for every dollar change in price, is -3.810, indicating that there is a decrease in sales as the price increases. So the correct option is C.

Explanation:

To estimate the slope parameter of the regression line representing the relationship between candy bar price and sales, we can apply the formula for the slope (m) of the linear regression line:

m = Σ((Xi - μx) × (Yi - μy)) / Σ(Xi - μx)²

where Xi and Yi are the individual sample points and μx and μy are the mean values for the independent (X) and dependent (Y) variables, respectively.

Using the data provided, we can calculate the means (μx and μy) and then use the points to calculate the sum of the products of the deviations and the sum of the squared deviations. We substitute these into the slope formula to find the estimated slope parameter, which would provide the rate of change in candy bar sales concerning the price change.

After performing the calculations, we find that the estimated slope parameter is -3.810. Thus, the correct answer is (C).

Answer:

Step-by-step explanation:

Consider first

[tex]y_1(t) = t^2\\[/tex]

We differentiate this two times to get

[tex]y_1'(t) = 2t\\y_1"(t) =2[/tex]

Substitute in the given equation

[tex]t^2 (2) -2(t^2 =0[/tex]

Hence satisfied

Consider II equation

[tex]y_2(t) = t^{-1} \\y_2'(t) = - t^{-2}\\y_2"(t) = -2 t^{-3}[/tex]

Substitute in the given equation to get

[tex]t^2 (-2 t^{-3})+2 t^{-1} = 0[/tex]

Hence satisfied

Together if we have

[tex]y = c_1 t^2 +c_2 t^{-1}[/tex]

being linear combination of two solutions

automatically this also will satisfiy the DE Or

this is a solution to the given DE

Since this expression is identically zero for any values of c1 and c2, we can conclude that y=c1t2 +c2t−1 is also a solution of the differential equation for t > 0.

Verifying that y1(t) =t2 is a solution of the differential equation t2y−2y=0:

Substituting y1(t) =t2 into the differential equation, we get:

t2(t2) - 2(t2) = 0

t4 - 2t2 = 0

2t2(t2 - 1) = 0

Since t > 0, t2 - 1 = 0

t2 = 1

t = 1 or t = -1

However, t > 0, so the only valid solution is t = 1. Therefore, y1(t) =t2 is indeed a solution of the differential equation for t > 0.

Verifying that y2(t) =t−1 is a solution of the differential equation t2y−2y=0:

Substituting y2(t) =t−1 into the differential equation, we get:

t2(t−1) - 2(t−1) = 0

t3 - t - 2t + 2 = 0

t3 - 3t + 2 = 0

(t - 1)(t2 - 2t + 2) = 0

Since t > 0, t2 - 2t + 2 = 0

(t - 1)(t - 1) = 0

t = 1 or t = 1

However, t > 0, so the only valid solution is t = 1. Therefore, y2(t) =t−1 is indeed a solution of the differential equation for t > 0.

Showing that y=c1t2 +c2t−1 is also a solution of this equation for any c1 and c2:

Substituting y=c1t2 +c2t−1 into the differential equation, we get:

t2(c1t2 +c2t−1) - 2(c1t2 +c2t−1) = 0

c1t4 +c2t3 - 2c1t2 - 2c2t + 2 = 0

Answer:

[tex] \frac{dP}{\sqrt{P}} = k dt[/tex]

And if we integrate both sides we got:

[tex] 2 \sqrt{P} = kt +C[/tex]

Where C is a constant., we can rewrite the expression like this:

[tex] \sqrt{P} = \frac{1}{2} (kt +C)[/tex]

If we square both sides we got:

[tex] P = \frac{1}{4} (kt +C)^2 [/tex]

If we use the initial condition we have that:

[tex] P(0) = 100 = \frac{1}{4} (k*0 +C)^2 [/tex]

And we can solve for C like this:

[tex] 400 = C^2[/tex]

[tex] C = 20[/tex]

And now we can find the derivate of the function and we got:

[tex] P'(t) = 2* \frac{1}{4} (kt + 20) * k[/tex]

Using the condition [tex] P'(0) = 10 [/tex] we got:

[tex] 10 = \frac{1}{2} k (k*0 +20)[/tex]

[tex] 20 = 20 k[/tex]

k= 1

And then the model is defined as:

[tex] P = \frac{1}{4} (t +20)^2 [/tex]

And for t =12 months we have:

[tex] P(12) = \frac{1}{4} (12 +20)^2 = 256 [/tex]

Step-by-step explanation:

For this case we cna use the proportional model given by:

[tex] \frac{dP}{dt} = k \sqrt{P}[/tex]

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition [tex] P(0) =100[/tex] and [tex] P'(0) = 10 [/tex]

we can rewrite the differential equation like this:

[tex] \frac{dP}{\sqrt{P}} = k dt[/tex]

And if we integrate both sides we got:

[tex] 2 \sqrt{P} = kt +C[/tex]

Where C is a constant., we can rewrite the expression like this:

[tex] \sqrt{P} = \frac{1}{2} (kt +C)[/tex]

If we square both sides we got:

[tex] P = \frac{1}{4} (kt +C)^2 [/tex]

If we use the initial condition we have that:

[tex] P(0) = 100 = \frac{1}{4} (k*0 +C)^2 [/tex]

And we can solve for C like this:

[tex] 400 = C^2[/tex]

[tex] C = 20[/tex]

And now we can find the derivate of the function and we got:

[tex] P'(t) = 2* \frac{1}{4} (kt + 20) * k[/tex]

Using the condition [tex] P'(0) = 10 [/tex] we got:

[tex] 10 = \frac{1}{2} k (k*0 +20)[/tex]

[tex] 20 = 20 k[/tex]

k= 1

And then the model is defined as:

[tex] P = \frac{1}{4} (t +20)^2 [/tex]

And for t =12 months we have:

[tex] P(12) = \frac{1}{4} (12 +20)^2 = 256 [/tex]

Answer:

Yes.

Step-by-step explanation:

According to the Transitive property of the Algebraic properties of equality, two values are said to be equal is they are differently equal to a corresponding third party. This is, If a=b and b=c then a=c.

Hence, if x=5 and 5=y, then following the transitive property of Algebraic properties of equality, x=y, hence the Algebraic property of equality Justifies the statement.

Answer:

Option A) 0.012

Step-by-step explanation:

We are given the following information:

We treat customers asking for water as a success.

P(customers ask for water) = [tex]\dfrac{3}{5}[/tex] = 0.6

Then the number of customers follows a binomial distribution, where

[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

[tex]P(x < 3) = P(x = 0) + P(x = 1) + P(x = 2) \\= \binom{10}{0}(0.6)^0(1-0.6)^{10} +\binom{10}{1}(0.6)^1(1-0.6)^{9} + \binom{10}{2}(0.6)^2(1-0.6)^{8}\\= 0.0001 +0.0015 + 0.0106\\=0.012[/tex]

0.012 is the probability that less than 3 customers ask for water with their meal.

The correct answer is option a) 0.012

The probability of success in each trial is 3 out of 5 (or 0.6), and the probability of failure is 2 out of 5 (or 0.4). Denoting the number of customers who ask for water as a binomial random variable X with n = 10 and p = 0.6.

The binomial probability formula is given by:

[tex]P(X=k) ={n \choose k}p^k(1-p)^{n-k}[/tex]

where:

n is the number of trials (10 in this case),
k is the number of successes (in this case, less than 3),
p is the probability of success (0.6), and
1−p is the probability of failure (0.4).

Probability that fewer than 3 customers ask for water needs to be found. This means we need to find:

P(X<3)=P(X=0)+P(X=1)+P(X=2)

Calculating each of these probabilities using the binomial formula:

For k=0:
[tex]P(X=0) ={10 \choose 0}(0.6)^0(0.4)^{10-0} = 1\times1\times0.4^{10} = 0.0001048576[/tex]

For k=1:

[tex]P(X=1) ={10 \choose 1}(0.6)^1(0.4)^{10-1} = 10\times0.6\times0.4^{9} = 0.001572864[/tex]

For k=2:

[tex]P(X=2) ={10 \choose 2}(0.6)^2(0.4)^{10-2} = 45\times0.36\times0.4^{8} = 0.010616832[/tex]

Now, we sum these probabilities to get the total probability that fewer than 3 customers ask for water:

P(X<3) = P(X=0) + P(X=1) + P(X=2)

P(X<3) = 0.0001048576 + 0.001572864 + 0.010616832

P(X<3) = 0.0122945536

Therefore rounding this value results in a probability of approximately 0.012.

Answer:

See the pictures attached

Step-by-step explanation:

Using the combination formula, the student can make 165 different possible schedules for next semester if she is planning to take three classes from the eleven available that she has met the prerequisites for.

This problem is a combination problem where students need to select 3 classes from 11 available classes to plan her schedule. The combination formula is used when the order of election does not matter. Here, the formula to find a combination is written as C(n, r) = n! / [r!(n - r)!].

In this particular case, the student has 11 classes (n=11) and plans to take 3 classes (r=3). So, the combination becomes C(11,3) = 11! / [3!(11-3)!] = (11*10*9) / (3*2*1) = 165.

This means, the student can make 165 different possible schedules for next semester assuming she is planning to take three classes from the eleven available classes.

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The student could make 165 different schedules.

The formula for combinations is given by:

[tex]\[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \][/tex]

where n! (n factorial) is the product of all positive integers up to n, and r is the number of items to choose.

 Given that the student has 11 classes left and she plans to take 3 classes next semester, we substitute n = 11 and r = 3 into the combination formula:

[tex]\[ \binom{11}{3} = \frac{11!}{3!(11-3)!} \][/tex]

 Now, we simplify the factorial expressions:

[tex]\[ \binom{11}{3} = \frac{11!}{3! \times 8!} \][/tex]

We can cancel out the common terms in the numerator and the denominator:

[tex]\[ \binom{11}{3} = \frac{11 \times 10 \times 9}{3 \times 2 \times 1} \][/tex]

Now, we perform the arithmetic:

[tex]\[ \binom{11}{3} = \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = \frac{990}{6} = 165 \][/tex]

Thus, the student has 165 different possible schedules for next semester if she is to take 3 classes out of the remaining 11.

By first reducing the following function f(x, y) to g(x)=x3 with y=0 and then determining its derivative at x=1, we can obtain fx(1, 0) equals 3.

You are required to determine the value of fx(1, 0) in the given function f(x, y) = x(x(x2 + y2)3/2 e)(sin(x2y)). The tip suggests that you can address this problem by computing g'(1) where g(x) = f(x, 0). When y = 0, the function changes to f(x,0) = x * x2 * e0, which is then expressed as x3. G(x)=x3 has a derivative, g(x)=3x2. Consequently, fx(1, 0) equals g'(1), which equals 3.

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Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Plug in the values and solve for 'z'. This gives,

[tex]z=\frac{2.33-1.75}{0.22}=2.64[/tex]

So, the z-score of the distribution is 2.64.

Now, we need the probability [tex]P(x\geq 2.33 )=P(z\geq 2.64)[/tex].

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

[tex]P(z\geq 2.64)=1-0.9959=0.0041=0.41\%[/tex]

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Answer:

a) For this case the intercept of 2.52 represent a common effect of measure for any student without taking in count the other variables analyzed, and we know that if HSGPA=0, ACT= 0 and skip =0 we got [tex] colGPA=2.52[/tex]

b) This value represent the effect into the ACT scores in the GPA, we know that:

[tex]\hat \beta_{ACT} = 0.015[/tex]

So then for every unit increase in the ACT score we expect and increase of 0.015 in the GPA or the predicted variable

c) If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: [tex]\beta_i = 0[/tex]

Alternative hypothesis: [tex]\beta_i \neq 0[/tex]

Or in other wouds we want to check if an specific slope is significant.

The significance level assumed for this case is [tex]\alpha=0.05[/tex]

Th degrees of freedom for a linear regression is given by [tex]df=n-p-1 = 45-3-1 = 41[/tex], where p =3 the number of variables used to estimate the dependent variable.

In order to test the hypothesis the statistic is given by:

[tex]t=\frac{\hat \beta_i}{SE_{\beta_i}}[/tex]

And replacing we got:

[tex] t = \frac{-0.5}{0.0001}=-5000[/tex]

And for this case we see that if we find the p value for this case we will get a value very near to 0, so then we can conclude that this coefficient would be significant for the regression model .

Step-by-step explanation:

For this case we have the following multiple regression model calculated:

colGPA =2.52+0.38*HSGPA+0.015*ACT-0.5*skip

Part a

(a) Interpret the intercept in this model.

For this case the intercept of 2.52 represent a common effect of measure for any student without taking in count the other variables analyzed, and we know that if HSGPA=0, ACT= 0 and skip =0 we got [tex] colGPA=2.52[/tex]

(b) Interpret [tex]\hat \beta_{ACT}[/tex] from this model.

This value represent the effect into the ACT scores in the GPA, we know that:

[tex]\hat \beta_{ACT} = 0.015[/tex]

So then for every unit increase in the ACT score we expect and increase of 0.015 in the GPA or the predicted variable

(c) What is the predicted college GPA for someone who scored a 25 on the ACT, had a 3.2 high school GPA and missed 4 lectures. Show your work.

For this case we can use the regression model and we got:

[tex] colGPA =2.52 +0.38*3.2 +0.015*25 - 0.5*4 = 26.751[/tex]

(d) Is the estimate of skipping class statistically significant? How do you know? Is the estimate of skipping class economically significant? How do you know? (Hint: Suppose there are 45 lectures in a typical semester long class).

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: [tex]\beta_i = 0[/tex]

Alternative hypothesis: [tex]\beta_i \neq 0[/tex]

Or in other wouds we want to check if an specific slope is significant.

The significance level assumed for this case is [tex]\alpha=0.05[/tex]

Th degrees of freedom for a linear regression is given by [tex]df=n-p-1 = 45-3-1 = 41[/tex], where p =3 the number of variables used to estimate the dependent variable.

In order to test the hypothesis the statistic is given by:

[tex]t=\frac{\hat \beta_i}{SE_{\beta_i}}[/tex]

And replacing we got:

[tex] t = \frac{-0.5}{0.0001}=-5000[/tex]

And for this case we see that if we find the p value for this case we will get a value very near to 0, so then we can conclude that this coefficient would be significant for the regression model .

Answer:

We conclude that the value of the mean is 40.

Step-by-step explanation:

We know that the researcher records the following estimates: 40, 46, 30, 50, and 34. If the researcher removes the estimate of 40 (say, due to an experimenter error).  

Now we have the following estimates: 46, 30, 50, and 34.

We calculate  the value of the mean. We get:

[tex]x=\frac{46+30+50+34}{4}\\\\x=\frac{160}{4}\\\\x=40\\[/tex]

We conclude that the value of the mean is 40.

Answer:

Option B)  (197773, 228207)    

Step-by-step explanation:

We are given the following in the question:

Sample mean, [tex]\bar{x}[/tex] = 212990

Sample size, n = 6

Alpha, α = 0.05

Sample standard deviation = 14500

95% Confidence interval:

[tex]\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}[/tex]  

Putting the values, we get,  

[tex]t_{critical}\text{ at degree of freedom 5 and}~\alpha_{0.05} = \pm 2.5705[/tex]  

[tex]212990 \pm 2.5705(\dfrac{14500}{\sqrt{6}} ) \\\\= 212990 \pm 15216.33 \\= (197773.67 ,228206.33)\\\approx (197773, 228207)[/tex]  

Option B)  (197773, 228207)

Using the t-distribution, it is found that the 95% confidence interval for the average price of a home in Gainesville of this size is (197773, 228207).

The first step is finding the number of degrees of freedom, which is the sample size subtracted by 1, so df = 6 - 1 = 5.

Now, we look at the t-table for the critical value for a 95% confidence interval with 5 df, which is t = 2.5706.

The margin of error is:

[tex]M = t\frac{s}{\sqrt{n}}[/tex]

For this problem, [tex]s = 14500, n = 6[/tex], thus:

[tex]M = 2.5706\frac{14500}{\sqrt{6}}[/tex]

[tex]M = 15217[/tex]

The confidence interval is:

[tex]\overline{x} \pm M[/tex]

For this problem, [tex]\overline{x} = 212990[/tex], then:

[tex]\overline{x} - M = 212990 - 15217 = 197773[/tex]

[tex]\overline{x} + M = 212990 + 15217 = 228207[/tex]

The correct option is (197773, 228207).

A similar problem is given at https://brainly.com/question/15872108

Answer:

a) 4.2%

b) 14.1%

Step-by-step explanation:

a) 0.9³⁰ = 0.0423911583

b) 30C1 × 0.1 × 0.9²⁹ = 0.1413038609

Answer:

a.) 4.2%

b.) 14.1%

Step-by-step explanation:

We solve using the probability distribution formula for selection and this formula uses the combination formula for estimation.

When choosing a random selection of "r" items from a sample of "n" items, The formula is generally denoted by:

P(X=r) = nCr × p^r × q^n-r.

Where p = probability of success

q= probability of failure.

From the given question,

n = number of samples =30,

p = Probability that a student is late = 10% = 0.1,

q=0.9

a.) when no student is late, that is when r = 0, then

P(X=0) = 30C0 × 0.1^0 × 0.9^30

P(X=0) = 0.0424 = 4.24 ≈ 4.2%

b.) when exactly one student is late, that is when r=1, then

P(X=1) = 30C1 × 0.1¹ × 0.9^29

P(X=1) = 0.1413 = 14.13 ≈ 14.1%

Answer:

2 mL

Step-by-step explanation:

If the drug is mixed in a solution of 0.5%, it means that for each ml of the solution, there is 0.5% or 0.005 grams of the drug. In order to get 10 mg of the drug, the volume required is:

[tex]0.005\frac{g}{mL}*V = 10*10^{-3} g\\ V= 2\ mL[/tex]

You should add 2 mL of the solution.

*Note that the volume of the bag should not be used since the amount of drug needed was specified in weight and not in concentration.

Answer:

For part  ;a)

probability that the Atlanta Braves win the World Series=0.40

For part b ;b)

average number of games played regardless of winner =5.8

Step-by-step explanation:

using the  rand() function for the simulation of  the probabilities and  compare with given probabilites if less than above then Atlanta wins otherwise loses

a)

probability that the Atlanta Braves win the World Series=0.40

b)

average number of games played regardless of winner =5.8

Answer:

a) c = 2

b) 0.99

c) 0.84

d) 0.8485

Step-by-step explanation:

We are given the following in the question:

[tex]f(x) = \dfrac{c}{x^3}, x > 1[/tex]

a) Value of c

Property of probability density function

[tex]\displaystyle\int^{\infty}_{-\infty} f(x) = 1[/tex]

Putting values, we get,

[tex]\displaystyle\int^{\infty}_{1} \frac{c}{x^3} = 1\\\\\Rightarrow -\frac{c}{2}\bigg[\frac{1}{x^2}\bigg]^{\infty}_{1} = 1\\\\\Rightarrow \frac{c}{2} = 1\\\\\Rightarrow c = 2[/tex]

Thus, the value of c is 2.

[tex]f(x) = \dfrac{2}{x^3}, x > 1[/tex]

b) proportion of contaminating particles are PM10

We have to evaluate

[tex]P( x \leq 10) =\displaystyle\int ^{10}_{1}\frac{2}{x^3}dx\\\\=\bigg(\frac{2}{-2x^2}\bigg)^{10}_{1}\\\\=-(\frac{1}{100}-1)\\\\=0.99[/tex]

c) proportion of contaminating particles are PM2.5

[tex]P( x \leq 2.5) =\displaystyle\int ^{2.5}_{1}\frac{2}{x^3}dx\\\\=\bigg(\frac{2}{-2x^2}\bigg)^{2.5}_{1}\\\\=-(\frac{1}{6.25}-1)\\\\=0.84[/tex]

d)  proportion of the PM10 particles are PM2.5

[tex]P(PM ~2.5|PM~10) = \dfrac{0.84}{0.99} = 0.8485[/tex]

Answer:

a) $15,406,443

b) 279.04 years = 279 years.

c) 5246.9 years = 5247 years.

Step-by-step explanation:

Compound interest

The final amount obtainable, A, from saving an initial amount, P, compounded at a rate of r in t number of years is given as

A = P (1 + r)ᵗ

A = ?

P = $100

r = 6% = 0.06

t = 2005 - 1800 = 205

A = 100 (1 + 0.06)²⁰⁵ = 100 × 154064.43 = $15406443

b) Radioactivity

Let the initial amount of Strontium be A

After 1 half life,

Amount remaining is A/2

After two half lives,

Amount remaining = A/2²

After 3 half lives,

Amount remaining = A/2³

After n half lives,

Amount remaining = A/2ⁿ

So, for this question,

(A)/(A/2ⁿ) = 1000

2ⁿ = 1000

In 2ⁿ = In 1000

n = (In 1000)/(In 2)

n = 9.966

1 half life = 28 years

n half lives = n × 28 = 9.966 × 28 = 279.04 years.

c) Carbon dating

The general relation of amount left to amount of Carbon-14 that is started with follows a first order rate of decay kinetics like every radioactive decay

A = A₀ e⁻ᵏᵗ

A = amount of Carbon-14 left at any time

A₀ = initial amount of Carbon-14

k = rate constant = (In 2)/(half life) = 0.693/5730 = 0.000121 /year.

(A/A₀) = 53% = 0.53

e⁻ᵏᵗ = 0.53

-kt = In 0.53 = -0.6349

t = 0.6349/k = 0.6349/0.000121 = 5246.9 years = 5247 years

Using the principles of compound interest, radioactive decay and carbon dating, we calculate that the investment made in 1800 would equal about $8,680,204 in 2005, that it would take approximately 280 years to reduce the amount of Strontium-90 by a factor 1000, and that the seeds were harvested around 8463 years ago.

The sum you would've collected in the year 2005 from a 100 dollars investment at 6 percent annual interest, compounded yearly since the year 1800 depends on the principle of compound interest. The formula to calculate compound interest is A = P(1 + r/n)^(nt), where A is the total sum, P is the principal amount, r is the annual rate of interest, n is the number of compounding periods a year, and t is the time in years. In your case, we have P = 100, r = 0.06, n = 1 (compounded yearly), and t = 2005 - 1800 = 205 years. So, A = 100(1 + 0.06/1)^(1*205) which equals approximately $8,680,204.

Strontium-90, with a half life of 28 years, would require waiting for a certain amount of years to reduce by a factor of 1000. For half life calculations, use the formula N = N0*(1/2)^(t/h), where N is the final amount, N0 is the initial amount, t is time and h is the half life. We want N0/N = 1000, so log2(1000) = t/28, which gives t = 28*log2(1000) = approximately 280 years.

The carbon-14 dating principle lets us calculate the age of the seeds. Using log2(1/0.53) = t/5730 to get t = 5730 * log2(1/0.53), we find the seeds were harvested about 8463 years ago.

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Answer:

Gene would pay approximately $56.19 for his total purchase of two pairs of shorts, one polo shirt, and one pair of shoes.

Step-by-step explanation:

First identify what you know:

1) Every item in the store is 40% off the ticketed price (original price)

2) Gene buys two pairs of shorts for $18.77 each.

3) Gene buys one polo shirt for $21.87.

4) Gene buys one pair of shoes for $34.24.

5) Discount is taken at the register.

So, assuming that each price given, IS the original price, we need to figure out exactly how much Gene paid with the 40% discount. We can solve this in two different ways.

1) Individually calculate 40% of each price of each item, and then add them up to find the total discounted price of all the items.

2) Add all the original items and calculate 40% off the original price, and subtract that amount from the original price.

I find it simplest to add up the original prices, and find the total, and then calculate the discounted (40%) total.

Original total = (2 x $18.77) + ($21.87) + ($34.24)

Original Price = ($37.54) + ($21.87) + ($34.24)

Original Total Price: $93.65

Now, we know that without the discount, the total for ALL the items would be $93.65. Now, we just need to find out what 40% of 93.65 is! TO do this, simply multiply 93.65 by 40% OR multiply 93.65 by 0.40.

93.65 x 0.40 = 37.46

So, 40% of $93.65 is $37.46. Now we just need to subtract that percentage to find the discounted price!

$93.65 - $37.46 = $56.19

Gene paid approximately $56.19 for two pairs of short, one polo shirt, and one pair of shoes, at a discount of 40% off.

Hope this helps! :)