A student is working in a lab to determine how time affects impulse. The student keeps the force the same in each trial but changes the impact time. Some data is shown. Which trial has the greatest impulse?

The gravitational force on a 9.0kg sphere inside the space shuttle orbiting 340km above the Earth's surface cannot be precisely determined with the information provided. However, astronauts and objects appear weightless in orbit, not because there is no gravity, but because they are in a state of continuous free-fall towards Earth, experiencing what is known as microgravity.

The sensation of weightlessness experienced by astronauts in the space shuttle is due to the phenomenon of microgravity. While it may seem that gravitational forces are absent in space, this is not the case. The space shuttle, and everything inside it, is in a constant state of free fall towards Earth. This happens because the shuttle is moving forward at a speed that matches the rate at which it falls towards the Earth, creating a steady orbit. According to Newton's law of universal gravitation, the force of gravity decreases with the square of the distance from the center of the Earth, but it is never zero. At the altitudes where the ISS and space shuttles orbit, gravity is only slightly weaker than on Earth's surface. Therefore, the 9.0kg sphere is subject to Earth's gravity, but it appears to float because it is in free-fall along with the shuttle.

Answer:

10 m and 17.3 m

Explanation:

We can notice that the vector B represents the hypothenuse of a right triangle, in which the x-component of the vector is the side opposite to the [tex]30^{\circ}[/tex] angle, while the y-component of the vector corresponds to the side adjacent to the [tex]30^{\circ}[/tex] angle. This means that we can find the two components of the vector by using the sine and cosine function as follows:

[tex]B_x = B sin 30^{\circ} = (20 m) sin 30^{\circ}=10 m[/tex]

[tex]B_y = B cos 30^{\circ} = (20 m) cos 30^{\circ}=17.3 m[/tex]

A pulsar (pulsating star)   is a neutron star that emits very intense jets of electromagnetic radiation in the range of radio waves, X-rays or gamma rays, at short and periodic intervals due to its intense magnetic field that induces this emission.

This jet is "observable" on Earth, when the magnetic pole of the star "points" to our planet and then stops pointing a thousandth of a second later due to the fast rotation of the star, appearing again when the same pole returns to point towards Earth.

Then, what is observed in the terrestrial sky are pulses of radiation with a very exact period, which are repeated again and again.

The radio pulses of a pulsar are produced due to its spinning action. As the star spins, it emits beams of radio radiation that sweep through space. We observe these as pulses when they point towards Earth.

The radio pulses of a pulsar are produced by the spinning of the star. As the star spins, it emits beams of radio radiation that sweep through space. If one of these beams points toward Earth, we observe it as a pulse.

The other options provided are not the reasons behind the radio pulses of a pulsar. These radio pulses are not due to the star vibrating or undergoing nuclear explosions. Similarly, it's not the star's dark orbiting companion periodically eclipsing the radio waves nor a black hole near the star absorbing energy and re-emitting it as radio pulses.

So, the correct answer to this question is option (b): As the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward Earth, we observe a pulse.

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The speed of a wave is given by:

[tex]v=f.\lambda[/tex]  (1)

Where [tex]f[/tex] is the frequency and  [tex]\lambda[/tex] the wavelength.

In the case of light, its speed is:

[tex]c=f.\lambda[/tex] (2)

On the other hand, the described situation is known as Refraction,   a phenomenon in which the light changes its direction when passing through a medium with a refractive index different from the other medium.  

In this context, the Refractive index [tex]n[/tex] is a number that describes how fast light propagates through a medium or material, and is defined as the relation between the speed of light in vacuum ([tex]c=3(10)^{8}m/s[/tex]) and the speed of light [tex]v[/tex] in the second medium:

[tex]n=\frac{c}{v}[/tex] (3)

In addition, as the light changes its direction, its wavelength changes as well:

[tex]n=\frac{\lambda_{air}}{\lambda_{glass}}[/tex] (4)

Knowing this, let's begin with the answers:

From equation (2) we can find [tex]f[/tex]:

[tex]f=\frac{c}{\lambda}[/tex]  (5)

Knowing that [tex]1nm=(10)^{-9}m[/tex]:

[tex]f=\frac{3(10)^{8}m/s}{632.8(10)^{-9}m}[/tex]  

[tex]f=4.74(10)^{14}Hz}[/tex]     (6)   >>>Frequency of the helium-neon laser light

We already know the wavelength of the light in air [tex]\lambda_{air}[/tex] and the index of refraction of the glass.

So, we only have to find the wavelength in glass [tex]\lambda_{glass}[/tex] from equation (4):

[tex]\lambda_{glass}=\frac{\lambda_{air}}{n}[/tex]

[tex]\lambda_{glass}=\frac{632.8(10)^{-9}m}{1.48}[/tex]

[tex]\lambda_{glass}=427(10)^{-9}m=427nm[/tex]   (7)   >>>Wavelength of the helium-neon laser light in glass

From equation (3) we can find the speed [tex]v[/tex]of this light in glass:

[tex]v=\frac{c}{n}[/tex]

[tex]v=\frac{3(10)^{8}m/s}{1.48}[/tex]

[tex]v=2.027(10)^{8}m/s[/tex]   (8)  >>>Speed of the helium-neon laser light in glass

The frequency of the red helium-neon laser light is approximately 4.74 x 10^14 Hz. When it travels in glass (with index of refraction 1.48), its wavelength shortens to 427.6 nm, and its speed reduces to about 203 Mm/s.

The wavelength of the red helium-neon laser light in air is given as 632.8 nm.

(a) Frequency: To calculate the frequency of the light, we can use the formula: frequency = speed of light / wavelength. Given the speed of light (c) is approximately 3.00 x 10^8 m/s, we can convert the wavelength from nm to m (1 nm = 1 x 10^-9 m), giving us 632.8 x 10^-9 m. Therefore, frequency (f) = 3.00 x 10^8 m/s / 632.8 x 10^-9 m = 4.74 x 10^14 Hz.

(b) Wavelength in Glass: The wavelength of light is smaller in a medium as compared to vacuum. We use the formula: wavelength in medium = wavelength in vacuum / index of refraction. Substituting the values: wavelength in glass = 632.8 nm / 1.48 = 427.6 nm.

(c) Speed in Glass: The speed of light in a medium is also dependent on refractive index, calculated with the formula: speed in medium = speed in vacuum / index of refraction. Therefore, speed in glass = 3.00 x 10^8 m/s / 1.48 ≈ 2.03 x 10^8 m/s, which is 203 Mm/s when converted to Mm/s.

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Answer:

B) decreases

Explanation:

The density of water is maximum at a temperature of [tex]4^{\circ} C[/tex]. This means that:

- For temperatures between 0 and 4 degrees C, as the temperature increases, the density increases

- For temperatures above 4 degrees C, as the temperature increases, the density decreases

The density is related to the volume by the formula:

[tex]d=\frac{m}{V}[/tex]

where m is the mass and V the volume. Therefore, density is inversely proportional to the volume. This means that, for a constant amount of mass:

- For temperatures between 0 and 4 degrees C, as the temperature increases, the volume decreases

- For temperatures above 4 degrees C, as the temperature increases, the volume increases

Therefore, for a sample of water at 0 degrees C, if the temperature is slightly increased, the volume of the water will decreases, because its density will increase.

Final answer:

If the temperature of water slightly increases from 0 degrees Celsius, the volume decreases because of the anomalous expansion of water until it approaches 4 degrees Celsius, where it begins to expand normally again.

Explanation:

When considering a sample of water at 0 degrees Celsius, if the temperature is slightly increased, the volume of water decreases. This is due to the anomalous expansion of water, which is a unique property where water expands as it cools down from 4 degrees Celsius to 0 degrees Celsius and reaches its maximum density at 4 degrees Celsius. As the temperature rises slightly above 0 degrees Celsius, water begins to contract until it approaches 4 degrees Celsius, where it will start expanding again. This is in contrast to most substances which expand when heated.

Answer:

-10.9 rad/s²

Explanation:

ω² = ω₀² + 2α(θ - θ₀)

Given:

ω = 13.5 rad/s

ω₀ = 22.0 rad/s

θ - θ₀ = 13.8 rad

(13.5)² = (22.0)² + 2α (13.8)

α = -10.9 rad/s²

Use the formula

[tex]{\omega_f}^2-{\omega_i}^2=2\alpha\Delta\theta[/tex]

[tex]\implies\left(13.5\dfrac{\rm rad}{\rm s}\right)^2-\left(22.0\dfrac{\rm rad}{\rm s}\right)^2=2\alpha(13.8\,\mathrm{rad})[/tex]

[tex]\implies\alpha=-10.9\dfrac{\rm rad}{\mathrm s^2}[/tex]

so the magnitude is 10.9 rad/s^2.

- Two opposite charges:

The electrostatic force between two opposite charges is attractive. This means that if we have a positive charge and a negative charge, the electrostatic force between them is attractive.

- Two like charges:

The electrostatic force between two like charges is repulsive. This means that if we have two positive charges, or two negative charges, the force exerted by one charge on the other one is repulsive.

- A charge in an electric field:

The direction of the electric force on a charge in an electric field depends on the sign of the charge. In fact, we have

[tex]F=qE[/tex]

where F is the electric force, q is the charge, and E the electric field. We have the two following situations:

- If the charge is positive, q > 0, then the electric force has the same direction as the electric field (so the charge will be accelerated in the same direction as the electric field)

- If the charge is negative, q < 0, then the electric force has opposite direction to the electric field (so the charge will be accelerated in the opposite direction to the electric field)

Like charges repel each other and unlike charges attract each other. The direction of the force when a charge is placed in an electric field depends on whether the charge is positive (same direction as the field) or negative (opposite direction as the field).

The electric force that exists between two charges can be determined by their nature. If the charges are similar, that is, both are either positive or negative, then the direction of the electric force will be repulsive, and they push each other away. The electric field lines in this case would emanate away from the charges.

On the other hand, if the charges are dissimilar (that is, one positive and one negative), then the direction of the electric force is attractive—they pull towards each other. The electric field lines in this case would point from the positive charge towards the negative one.

When a charge is placed in an electric field, the direction of the force it experiences depends on its nature. If the charge is positive, it will experience a force in the direction of the field. If it's negative, the force will be in the opposite direction to the field.

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To find the distances and times at which the two cars pass each other, we can use equations of motion. The car passes the Porsche at 20 meters and 2 seconds after the light turns green. The Porsche passes the car at 60 meters and 5 seconds after the light turns green.

To solve this problem, we will use equations of motion to find the distances and times at which the two cars pass each other. Given that the Porsche starts from rest and accelerates at 3 m/s², we can use the equation x = xo + vot + ½at² to find the distance it travels before the other car reaches it. Similarly, for the other car which is traveling at a constant speed of 10 m/s, we can use the equation x = Ut. By solving these equations simultaneously, we can find the distances and times at which the two cars pass each other.

a. The distance at which you pass the Porsche can be found by setting the distances traveled by both cars equal to each other: 10t = 15 + 0.5(3)(t²). By solving this equation, we find that you pass the Porsche at a distance of 20 m from the stop line and at a time of 2 seconds after the light turns green.

b. To find the distance at which the Porsche passes you, we need to find the time at which the Porsche catches up to you. We can do this by setting the equation for the Porsche's distance equal to your distance: 15 + 0.5(3)(t²) = 10t. Solving this equation gives us a time of 5 seconds after the light turns green. Plugging this time into the equation for your distance, we find that the Porsche passes you at a distance of 60 meters from the stop line.

c. To determine if either of you will be pulled over for speeding, we need to compare your speeds to the speed limit of 50 km/h. Your speed is given as 36 km/h (10 m/s), which is less than the speed limit. The Porsche's speed can be found by taking the derivative of its distance equation with respect to time: v = at. Plugging in the time at which it passes you, we find that its speed is 30 m/s, which is also less than the speed limit. Therefore, neither of you will be pulled over for speeding.

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You pass the Porsche 16.65 meters beyond the stop line at 3.33 seconds, while the Porsche catches up 66.7 meters from the stop line at 6.67 seconds. Only the Porsche would be pulled over for speeding. The primary topic is the analysis of two moving vehicles using physics.

Your car's constant speed is [tex]36 km/h[/tex] or [tex]10 m/s[/tex] . The Porsche accelerates from rest at [tex]3 m/s^2[/tex].

Calculate the time it takes for the Porsche to reach your speed:
Using the equation: [tex]v = u + at[/tex],
where[tex]v = 10 m/s[/tex],[tex]u = 0[/tex], and[tex]a = 3 m/s^2[/tex], we get [tex]t = v/a = 10/3 \approx 3.33 seconds[/tex].

Now, find the distance the Porsche covers in this time with the equation: [tex]s = ut + 0.5at^2[/tex], where[tex]u = 0[/tex], [tex]a = 3 m/s^2[/tex] and [tex]t = 3.33 seconds[/tex],
thus [tex]s = 0.5 \times 3 \times 3.332 \approx 16.65 meters[/tex].

Your car covers [tex]3.33 \times 10 = 33.3 meters[/tex] in this same time.

Hence, you pass the Porsche [tex]33.3 - 16.65 = 16.65 meters[/tex] beyond the stop line.

To find when the Porsche catches up, consider the distance equations for both vehicles:

Your distance: [tex]d_{you}(t) = 10t[/tex].

Porsche’s distance: dporsche(t) = 0.5 * 3 * t2.

Set the distances equal to solve for [tex]t: 10t = 1.5t2[/tex],  leading to [tex]t = 0[/tex] or [tex]t = 10/1.5 = 6.67 seconds[/tex].

The Porsche catches up [tex]0.5 \times 3 \times 6.672 = 66.7[/tex]meters from the stop line.

Determine both cars' speeds when the Porsche passes you again:

Your speed:[tex]10 m/s = 36 km/h[/tex], under the limit.

Porsche’s speed: [tex]v = u + at = 3 \times 6.67 = 20.01 m/s \approx 72 km/h[/tex], over the limit.

Thus, only the Porsche would be pulled over for speeding.

Answer:

increases

Explanation:

In a circuit, the power supplied by the source is given by:

[tex]P=VI[/tex] (1)

where V is the voltage of the source and I is the current in the circuit.

Using Ohm's law, we can rewrite the current as:

[tex]I=\frac{V}{R}[/tex]

where R is the equivalent resistance of the circuit. Substituting into (1), we can rewrite the power as

[tex]P= \frac{V^2}{R}[/tex] (2)

so we see that the power is inversely proportional to the resistance.

For resistors added in parallel, the equivalent resistance is given by the formula

[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}[/tex]

so we see that when adding new resistors in parallel, the term [tex]\frac{1}{R}[/tex] increases, so the equivalent resistance R will decreases. As a result, the power supplied by the source (given by eq.(2)) wil increase.

As more resistors are added in parallel across a constant voltage source the power will; increase

Formula for Poweer across a circuit with constant voltage is;

P = I²R

Where;

1/R = 1/R1 + 1/R2 + 1/R3....

Where R is total resistance.

This means that the more resistors you add in parallel, the greater the value of R.

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Answer:

Positive Z direction (out of screen)

Explanation:

Magnetic force is given by [tex]F = il \wedge B[/tex]. A quick way to gauge the components is to put your left middle finger on the direction of the current, your index on the direction of the magnetic field, and the thumb gives you the answer you want.

Answer:

positive-z direction (out of the screen)

Explanation:

As we know that length vector of the current carrying conductor is always along the direction of conventional current

So here direction of length vector will be + X direction

magnetic field is along + Y direction

now we will have

[tex]\vec F = I(\vec L \times \vec B)[/tex]

now we will have

[tex]\vec F = ILB(\hat i \times \hat j)[/tex]

[tex]\vec F = ILB\hat k[/tex]

so magnetic force will be along +Z direction (out of the screen)

answer:

absorption spectrum

Answer:

0.775 m

Explanation:

As the car collides with the bumper, all the kinetic energy of the car (K) is converted into elastic potential energy of the bumper (U):

[tex]U=K\\frac{1}{2}kx^2 = \frac{1}{2}mv^2[/tex]

where we have

[tex]k=2\cdot 10^6 N/m[/tex] is the spring constant of the bumper

x is the maximum compression of the bumper

[tex]m=30\cdot 10^4 kg[/tex] is the mass of the car

[tex]v=2.0 m/s[/tex] is the speed of the car

Solving for x, we find the maximum compression of the spring:

[tex]x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(30\cdot 10^4 kg)(2.0 m/s)^2}{2\cdot 10^6 N/m}}=0.775 m[/tex]

Answer:

0.6 m

Explanation:

The law of conservation of energy states that:

[tex]\Delta E_m=0[/tex]

The mechanical energy ([tex]E_m[/tex]) is the sum of the kinetic energy and the potential energy:

[tex]\Delta K+\Delta U=0\\K_f-K_i+U_f-U_i=0\\\frac{mv_f^2}{2}-\frac{mv_i^2}{2}+\frac{kx_f^2}{2}-\frac{kx_i^2}{2}=0[/tex]

[tex]U_i[/tex] is zero since the spring is not initially compressed and [tex]K_f[/tex] is zero since all kinetic energy becomes potentital energy:

[tex]\frac{kx_f^2}{2}=\frac{mv_i^2}{2}[/tex]

Finally, we solve for x and replace the given values:

[tex]x_f^2=\frac{mv_i^2}{k}\\x_f=\sqrt{\frac{mv_i^2}{k}}\\x_f=\sqrt{\frac{(30*10^4kg)(2\frac{m}{s})^2}{2*10^6\frac{N}{m}}}\\x_f=0.6 m[/tex]

Answer:44(,5 v

Explanation:

Ggthnu

Answer:

The correct answer is B. Producers

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Explanation:

Answer:

B. 3

Explanation:

The half-life of a radioisotope is the time it needs for the mass of the radioisotope to halve with respect to its original value.

In this problem, the initial mass of the radioisotope at t=0 is

m0 = 50.0 mg

We see that after t = 1 min, the mass of the isotope is

m(1 min) = 25.0 mg

so, exactly half the initial mass: this means that 1 minute is exactly the half-life of this radioisotope.

So, the amount of mass left after each minute is the following:

m (1 min ) = 25.0 mg (1 half-life)

m (2 min) = 12.5 mg (2 half-lives)

m (3 min) = 6.25 mg (3 half-lives)

so, when we are left with 6.25 mg of isotope, 3 minutes have passed, which means that 3 half-lives have passed.

26 protons are in single nucleus of 5626fe

Two positively charged balls will repel with greater force as the charge on one of them is increased. Grounding the second ball would cause it to lose its charge, making both balls positively charged after the process, with reduced repulsion between them.

When one ball is kept positively charged and the charge on the other ball is increased, making it more positive, the two balls will repel each other with greater force. This phenomenon is due to Coulomb's Law, which states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

If the second ball, which is also positively charged, is momentarily grounded while a negatively charged rod is nearby, it would lose its negative charge to the ground. This is because grounding provides a path for the charge to dissipate into the Earth, effectively neutralizing the charged object. After being ungrounded, if the negatively charged rod is still present, the second ball will have a positive charge due to the removal of its excess electrons. Therefore, both balls would end up with a positive charge, but the magnitude of the charge on the second ball would be reduced by the grounding process, potentially changing the dynamics of their interaction.

The charge on the first ball will remain positive throughout this process, as the presence of the negatively charged rod induces the transfer of electrons from the first ball to the second ball when they are in contact, leaving the first ball positively charged.

The water pushes the shower curtain. Push is a force. The water basically thrusts the shower curtain and the curtain will then not stop immediately as it has a bit of braking distance. Then braking distance differs on the total force the water has on the curtain. Simple way: The curtain moves because the water acts as a push to propel the curtain forwards.

Your shower curtain swings towards you when the water is on full blast due to a principle of physics involving pressure variations in rapidly moving fluids. The high-velocity water and air create lower pressure inside the shower, and with standard atmospheric pressure outside the shower, a net inward force results, causing the curtain to swing in.

This phenomenon is explained with the principles of physics and more specifically, fluid dynamics. When you have the shower on full blast, a high-velocity stream of water and air is created, which result in a region of lower pressure inside the shower. On the other side of the curtain, the pressure remains at standard atmospheric pressure. This difference in pressure results in a net force that pushes the curtain inward. This interaction with rapidly moving fluids and pressure is the reason why your shower curtain swings or bulges towards you when the water is at full blast. It is similar to the effect observed when passing a truck on the highway, where your car tends to veer towards it - the high velocity of air between the car and the truck creates a region of lower pressure, and the vehicles are pushed together by greater pressure from the outside.

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Answer:

Duration of the total trip

Explanation:

Acceleration is defined as the rate of change of velocity of an object:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

where

[tex]\Delta v[/tex] is the change in velocity

[tex]\Delta t[/tex] is the duration of the change in velocity

Acceleration is measured in meters per squared seconds, [tex]m/s^2[/tex]. Also, we should note that acceleration is a vector quantity, so in order to completely define acceleration we also need to specify the direction.

Answer: Time

Explanation: Took the test and got it right! :)

Identify a problem

Do background research

Form a hypothesis

Create and plan an experiment

Perform the experiment

Analyze the result

Create a conclusion

Communicate results

The major steps of a scientific method includes, observation, hypothesis, experiment, result and discussion and evaluation of the results and conclusion.

A scientific method includes several stages to find a solution for the scientific problem under study. The first step of the study includes an observation on the incident under study.

Based on the observations made make a scientific hypothesis which predict the solution of the problem. Later the hypothesis is tested with a well designed experiment.

So the next step is the planning of the experiment. Then perform the experiment and attain the results. Later the results are thoroughly evaluated and arrive at a conclusion.

The last step is to reveal and publish the results to communicate the important results and discussions.

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During the day, the atmosphere lets through solar radiation that heats the Earth's surface. Once the surface of the planet has warmed up, this heat is returned to space in the form of infrared radiation.

However, not all infrared radiation is returned to space, because the same atmosphere (specifically carbon dioxide and water vapor present in it) prevents the release of much of this thermal radiation, reflecting part of it and returning it to the surface; thus maintaining the heat and allowing life on our planet. This phenomenon is known as the greenhouse effect.

Thus, of the solar energy that reaches the Earth by radiation, only a small percentage is reflected back into space by the surface and the atmosphere.

In fact, if the atmosphere did not exist, all that heat would completely escape into space and the Earth would cool rapidly during the night.

Therefore, the correct option is B:

Final answer:

Low pH indicates a high hydrogen-ion concentration, showcasing that the environment is acidic.

Explanation:

Low pH means that the hydrogen-ion concentration is high. The pH scale is a logarithmic representation of hydrogen ion concentration, where a low pH number indicates a higher concentration of H+ ions, creating an acidic environment. In contrast, a high pH suggests a lower concentration of hydrogen ions and a basic or alkaline condition. For example, a pH of 3 is ten times more acidic than a pH of 4 due to the logarithmic scale of pH, where each whole number change represents a tenfold change in ion concentration.

The tension in the string corresponds to the gravitational attraction between the Sun and any planet.

Answer:

Explanation:

While Steve is whirling a rubber cork, it developes a situation which is similar to the Solar System. In the rubber cork movement, there's "circular" motion which is possible thanks to the string, that is, the string works as "attraction force", allowing the system to maintain its movement.

Now, in the Solar System, the graviational force is like the string, it's the physical magnitude that maintains planets on their movements, attached to the Sun someway.

Answer: B) wave nature of light

I got 0.0126, but it feels wrong.

Answer:

Theories can be proven.

Explanation:

A theory in physics is formed by a group of hypothesis based on experimentation, it can never be proven. As much as you experience many times and in all agree the results with the theory, you can never be sure that the next time the result will not contradict it. Rather, a theory can be refuted by finding a single observation that disagrees with its predictions.

A. 6.67 cm

The focal length of the lens can be found by using the lens equation:

[tex]\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}[/tex]

where we have

f = focal length

s = 12 cm is the distance of the object from the lens

s' = 15 cm is the distance of the image from the lens

Solving the equation for f, we find

[tex]\frac{1}{f}=\frac{1}{12 cm}+\frac{1}{15 cm}=0.15 cm^{-1}\\f=\frac{1}{0.15 cm^{-1}}=6.67 cm[/tex]

B. Converging

According to sign convention for lenses, we have:

- Converging (convex) lenses have focal length with positive sign

- Diverging (concave) lenses have focal length with negative sign

In this case, the focal length of the lens is positive, so the lens is a converging lens.

C. -1.25

The magnification of the lens is given by

[tex]M=-\frac{s'}{s}[/tex]

where

s' = 15 cm is the distance of the image from the lens

s = 12 cm is the distance of the object from the lens

Substituting into the equation, we find

[tex]M=-\frac{15 cm}{12 cm}=-1.25[/tex]

D. Real and inverted

The magnification equation can be also rewritten as

[tex]M=\frac{y'}{y}[/tex]

where

y' is the size of the image

y is the size of the object

Re-arranging it, we have

[tex]y'=My[/tex]

Since in this case M is negative, it means that y' has opposite sign compared to y: this means that the image is inverted.

Also, the sign of s' tells us if the image is real of virtual. In fact:

- s' is positive: image is real

- s' is negative: image is virtual

In this case, s' is positive, so the image is real.

E. Virtual

In this case, the magnification is 5/9, so we have

[tex]M=\frac{5}{9}=-\frac{s'}{s}[/tex]

which can be rewritten as

[tex]s'=-M s = -\frac{5}{9}s[/tex]

which means that s' has opposite sign than s: therefore, the image is virtual.

F. 12.0 cm

From the magnification equation, we can write

[tex]s'=-Ms[/tex]

and then we can substitute it into the lens equation:

[tex]\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}\\\frac{1}{f}=\frac{1}{s}+\frac{1}{-Ms}[/tex]

and we can solve for s:

[tex]\frac{1}{f}=\frac{M-1}{Ms}\\f=\frac{Ms}{M-1}\\s=\frac{f(M-1)}{M}=\frac{(-15 cm)(\frac{5}{9}-1}{\frac{5}{9}}=12.0 cm[/tex]

G. -6.67 cm

Now the image distance can be directly found by using again the magnification equation:

[tex]s'=-Ms=-\frac{5}{9}(12.0 cm)=-6.67 cm[/tex]

And the sign of s' (negative) also tells us that the image is virtual.

H. -24.0 cm

In this case, the image is twice as tall as the object, so the magnification is

M = 2

and the distance of the image from the lens is

s' = -24 cm

The problem is asking us for the image distance: however, this is already given by the problem,

s' = -24 cm

so, this is the answer. And the fact that its sign is negative tells us that the image is virtual.

The correct answers to the questions are:

To find the image distance for the question in question G is by the use of the magnification equation which is:

s1= -Ms

=> -5/9(12cm)

=>  -6.67cm.

Because the value is negative, we know that the image is virtual.

Read more about lenses here:
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a. 12,500 turns

The transformer equation states that

[tex]\frac{N_p}{V_p}=\frac{N_s}{V_s}[/tex]

where

Np is the number of turns in the primary coil

Ns is the number of turns in the secondary coil

Vp is the voltage in the primary coil

Vs is the voltage in the secondary coil

For the transformer in the problem,

Vp = 15,000 V

Vs = 120 V

Ns = 100

So we can find Np by rearranging the equation:

[tex]N_p = V_p \frac{N_s}{V_s}=(15,000 V)\frac{100}{120 V}=12,500[/tex]

b.  2 A

For an ideal transformer, the output power is equal to the input power:

[tex]P_i = P_o\\V_p I_p = V_s I_s[/tex]

where

[tex]V_p = 15,000 V[/tex] is the voltage in the primary coil

[tex]I_p[/tex] is the current in the primary coil

[tex]V_s = 120 V[/tex] is the voltage in the secondary coil

[tex]I_s = 250 A[/tex] is the current in the secondary coil

Solvign the formula for Ip, we find:

[tex]I_p = \frac{V_s I_s}{V_p}=\frac{(120 V)(250 A)}{15,000 V}=2 A[/tex]

The primary coil of the transformer has 12500 turns, and the current in the 15,000 V line from the electrical substation is 2 A.

The number of turns in the primary coil of the transformer can be found using the transformer equation, which states that the ratio of the secondary voltage to the primary voltage equals the ratio of the number of loops in the secondary coil to the number of loops in the primary coil.

Therefore, if the secondary coil has 100 turns, and the voltages are 15000 V (primary) and 120 V (secondary), we can set up the equation (15000 V / 120 V) = (x turns / 100 turns), where x is the number of turns in the primary coil. Solving for x gives us x = 12500 turns.

The power input to the primary coil equals the power output from the secondary coil, since no energy is lost in an ideal transformer. Power (P) equals voltage (V) times current (I), so Pin = Pout, or (15,000 V * Iin) = (120 V * 250 A). Solving for Iin, the current in the 15,000 V line from the substation, gives us Iin = 2 A.

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Answer: at the center of curvature of the mirror on the same side of the mirror as the object

A concave mirror has a reflective surface that is curved inwards.  This type of mirrors reflects the light making it converge in a focal point, therefore they are used to focus the light.

This occurs because the light is reflected with different angles, since the normal to the surface varies from one point to another of the mirror.

Nevertheless, it is important to note the object must be within the radius of curvature of the mirror.

In addition, it is important to state clear the following:

-If the object is at a distance greater than the focal distance, a real and inverted image is formed that may be greater or less than the object.

-If the object is at a distance smaller than the focal distance, a virtual image is formed, right and larger than the object.

In this case the object is placed a great distance (it can be said at infinite) from the concave mirror, hence the image formed will be real, inverted and smaller than the object.

When we say real, it means the image is formed in the same side of the mirror as the object and the image can be seen on a screen.

Answer:

At the focal length of the mirror on the same side of the mirror as the object

Explanation: I had this question on USA test prep and I used the answer that the other guy said and it was incorrect. so the correct answer is

A)

at the focal length of the mirror on the same side of the mirror as the object

(a) [tex]2.5\cdot 10^{-6}eV[/tex]

The energy of a photon is given by:

[tex]E=\frac{hc}{\lambda}[/tex]

where

[tex]h=6.63\cdot 10^{-34}Js[/tex] is the Planck constant

[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light

[tex]\lambda[/tex] is the wavelength

For the microwave photon,

[tex]\lambda=50.00 cm = 0.50 m[/tex]

So the energy is

[tex]E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{0.50 m}=4.0\cdot 10^{-25} J[/tex]

And converting into electronvolts,

[tex]E=\frac{4.0\cdot 10^{-25}J}{1.6\cdot 10^{-19} J/eV}=2.5\cdot 10^{-6}eV[/tex]

(b) [tex]2.5 eV[/tex]

For the energy of the photon, we can use the same formula:

[tex]E=\frac{hc}{\lambda}[/tex]

For the visible light photon,

[tex]\lambda=500 nm = 5 \cdot 10^{-7}m[/tex]

So the energy is

[tex]E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-7} m}=4.0\cdot 10^{-19} J[/tex]

And converting into electronvolts,

[tex]E=\frac{4.0\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.5 eV[/tex]

(c) [tex]2500 eV[/tex]

For the energy of the photon, we can use the same formula:

[tex]E=\frac{hc}{\lambda}[/tex]

For the x-ray photon,

[tex]\lambda=0.5 nm = 5 \cdot 10^{-10}m[/tex]

So the energy is

[tex]E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-10} m}=4.0\cdot 10^{-16} J[/tex]

And converting into electronvolts,

[tex]E=\frac{4.0\cdot 10^{-16}J}{1.6\cdot 10^{-19} J/eV}=2500 eV[/tex]