Answer:
20 bicycles and 10 tricycles.
Step-by-step explanation:
Let the number of bicycles and tricycles be x and y respectively.
Each vehicle has 1 seat. Each bicycle 2 wheels and each tricycle 3 wheels.
Then we have the system of equations:
x + y = 30 ............ (1)
2x + 3y = 70.........(2)
Multiply the first equation by -2:
-2x - 2y = -60......(3)
Adding (2) + (3):
y = 10
Substituting for y in equation (1):
x + 10 = 30
x = 20.
By simultaneous equation, there are a total of 20 bicycles and 10 tricycles.
What is the number of given quantity from simultaneous equation ?Let the number of bicycles and tricycles be x and y respectively.
It is given that there is a total of 30 seats and 70 wheels.
Each vehicle has 1 seat. Each bicycle 2 wheels and each tricycle 3 wheels.
Then we have the system of simultaneous equations:-
x + y = 30 ............ (1)
2x + 3y = 70.........(2)
Multiply the first equation by -2:
-2x - 2y = -60......(3)
Adding (2) + (3):
y = 10
Substituting for y in equation (1):
x + 10 = 30
x = 20.
Therefore, by simultaneous equation, there are a total of 20 bicycles and 10 tricycles.
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Right triangle ABC is shown on the graph below. If the point (-4, y) lies on the line that goes through side BC of the triangle, then what should be the value of y?
the answers given were
A. 0
B. -5
C. 1
D. -1
Answer:
C. 1
Step-by-step explanation:
The line containing segment BC has a slope of 1 and a y-intercept of 5 (at point B). Thus, its equation is ...
y = x + 5
For the value of x = -4, the value of y is ...
y = -4 +5 = 1
Point (-4, 1) is on the line containing segment BC.
Answer:
C. 1
Step-by-step explanation:
Given: EFGH inscribed in k(O) m∠FHE = 45°, m∠EGH = 49° Find: m∠FEH
Answer:
[tex]m<FEH=86\°[/tex]
Step-by-step explanation:
we know that
The inscribed angle measures half that of the arc comprising
step 1
Find the measure of arc EF
[tex]m<FHE=\frac{1}{2}(arc\ EF)[/tex]
we have
[tex]m<FHE=45\°[/tex]
substitute
[tex]45\°=\frac{1}{2}(arc\ EF)[/tex]
[tex]arc\ EF=90\°[/tex]
step 2
Find the measure of arc EH
[tex]m<EGH=\frac{1}{2}(arc\ EH)[/tex]
we have
[tex]m<EGH=49\°[/tex]
substitute
[tex]49\°=\frac{1}{2}(arc\ EH)[/tex]
[tex]arc\ EH=98\°[/tex]
step 3
Find the measure of arc FGH
[tex]arc\ FGH=360\°-(arc\ EH+arc\ EF)[/tex]
substitute the values
[tex]arc\ FGH=360\°-(98\°+90\°)[/tex]
[tex]arc\ FGH=172\°[/tex]
step 4
Find the measure of angle FEH
[tex]m<FEH=\frac{1}{2}(arc\ FGH)[/tex]
we have
[tex]arc\ FGH=172\°[/tex]
substitute
[tex]m<FEH=\frac{1}{2}(172\°)=86\°[/tex]
A right triangle △ABC with right angle C is inscribed in a circle. Find the radius of this circle if: Given m∠C = 90°, k(O, r) inscribed in △ABC, AC = 8 cm, BC = 6 cm. Find r.
Answer:
The radius is [tex]r=5\ cm[/tex]
Step-by-step explanation:
we know that
The inscribed angle is half that of the arc it comprises.
so
[tex]m<C =(1/2)[arc\ AB][/tex]
[tex]m<C =90\°[/tex]
substitute
[tex]90\°=(1/2)[arc\ AB][/tex]
[tex]arc\ AB=180\°[/tex]
That means----> The length side AB of the inscribed triangle is a diameter of the circle
Applying Pythagoras Theorem
Calculate the length side AB
[tex]AB^{2}=AC^{2}+BC^{2}[/tex]
[tex]AB^{2}=8^{2}+6^{2}[/tex]
[tex]AB^{2}=100[/tex]
[tex]AB=10\ cm[/tex] -----> is the diameter
Find the radius
[tex]r=10/2=5\ cm[/tex] -----> the radius is half the diameter
CAN SOMEONE HELP ME ANSWER THIS
Answer:
5 timesStep-by-step explanation:
[tex]30\cdot\dfrac{1}{6}=\dfrac{30}{6}=5[/tex]
Kara rotates a square around its horizontal axis of symmetry to make a solid figure. Which of following could be the shape of a horizontal cross section of the solid figure
Answer:
I am pretty sure the answer is square
How many solutions does the equation -5x+10x+3=5x+6 have?
Answer:
No Solutions
Step-by-step explanation:
-5x+10x+3=5x+6
5x+3=5x+6
5x=5x+3, which isn't true
ANSWER
The equation has no solution.
EXPLANATION
The given equation is
-5x+10x+3=5x+6
Group similar terms
-5x-5x+10x=6-3
-10x+10x=6-3
0=3
This statement is not true.
Hence the equation has no solution.
Priya has completed 9 exam questions. This is 60% of the questions on the exam. How many questions are on the exam?
Answer:
15
Step-by-step explanation:
Since 9 questions is 60% of the exam, you must find 100%. You could find the value of 10% by dividing 60 by 6. You do the same to 9, divide by 6 to get 1.5. Now that you have the value of 10% you can multiply 10% by 10 to get 100. You also do the same to 1.5. Your answer should be 15, if not check your work again. Work hard!!
The total number of questions in the exam is 15 and this can be determined by using the unitary method.
Given :
Priya has completed 9 exam questions. This is 60% of the questions on the exam.
The unitary method can be used in order to determine the total number of questions in the exam.
According to the given data, Priya has completed 9 exam questions which are 60% of the questions on the exam. So, the 100% questions in the exam are:
[tex]= \dfrac{9}{60}\times 100[/tex]
Multiply 9 by 100 in the above expression.
[tex]=\dfrac{900}{60}[/tex]
Divide 900 by 60 in the above expression.
= 15 questions
So, the total number of questions in the exam is 15.
For more information, refer to the link given below:
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how many times would you expect the result to be a number less than 6
Answer:
5 if its a dice.
Step-by-step explanation:
On a dice, 5. The probability of it landing on 6 is 1/6
Compare the three functions below. Which has a greater period? A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)
Comparing the periods of the given cosine functions indicates that functions A) and C) both have the greatest period of π, which is longer than the period of function B), π/2.
Explanation:To compare the periods of the given functions, let's first understand what the general form of a cosine function tells us about its period.
The general form is y = A cos(Bx + C), where A is the amplitude, B affects the period, and C is the phase shift.
The period of such a function is given by 2π / |B|.
For function A) y = 3cos(2x+1), B = 2, thus its period is π.
For function B) y=5cos(4x +8), B = 4, yielding a period of π/2.
Lastly, for function C) y=cos(2x+4) (4.3), assuming the (4.3) is an unrelated notation and focusing on the given cos component with B = 2, its period is also π.
The function with the greatest period among A, B, and C is thus A) and C), both having the same period of π, which is greater than the period of B).
A parabola opening upward shifted 7 units rights and 4 units down
Answer:
y + 4 = a(x - 7)^2
Step-by-step explanation:
The standard vertex form of a parabola with vertex at (h, k) is
y - k = a(x - h)^2
and if we start with the simplest case, y = a(x)^2 and translate its graph 7 units to the right and 4 units down, we get y - {-4] = a(x - 7)^2, or
y + 4 = a(x - 7)^2
The answer is y + 4 = a(x - 7)^2.
The standard vertex form of a parabola with vertex at (h, k) is
y - k = a(x - h)^2
And if we start with the simplest case,
y = a(x)^2 and
translate it Into 7 units to the right and 4 units down,
we get
y - {-4] = a(x - 7)^2
then we get the equation is y + 4 = a(x - 7)^2.
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Explain the relationship between the volumes of a square pyramid and a rectangular prism if they each have a square bass with side length of 5 inches and they each have a height oh h inches.
Answer:
The volume of the pyramid is one third the volume of the rectangular prism
or
The volume of the prism is three times the volume of the pyramid
Step-by-step explanation:
step 1
Find the volume of the rectangular prism
The volume is equal to
[tex]V=Bh[/tex]
where
B is the area of the base
h is the height of the prism
Find the area of the base B
[tex]B=5^{2}=25\ in^{2}[/tex]
substitute
[tex]Vprism=25h\ in^{3}[/tex]
step 2
Find the volume of the square pyramid
The volume is equal to
[tex]V=(1/3)Bh[/tex]
where
B is the area of the base
h is the height of the pyramid
Find the area of the base B
[tex]B=5^{2}=25\ in^{2}[/tex]
substitute
[tex]Vpyramid=(1/3)25h\ in^{3}[/tex]
Remember that
[tex]Vprism=25h\ in^{3}[/tex]
substitute
[tex]Vpyramid=(1/3)Vprism[/tex]
The volume of the pyramid is one third the volume of the rectangular prism
or
[tex]Vprism=3Vpyramid[/tex]
The volume of the prism is three times the volume of the pyramid
What is 265,200 rounded to the nearest hundred thousand
265,000
Hope this helps!
Because the number in the ten thousands place is over 4, it’s going to turn the 2 in the hundred thousands place into a 3, making the answer 300,000
I need help please?!!!!
The answer is -2. X is -2.
what is the solution to 8(y + 7) > 8y + 3
Answer:
y can be any real number
Step-by-step explanation:
8(y + 7) > 8y + 3
Distribute
8y+56 > 8y+3
Subtract 8y from each side
8y-8y +56 > 8y-8y +3
56 > 3
This is always true so the inequality is always true
y can be any real number
ABCD is a rhombus. = 8 cm, and = 3.5 cm. What is the area of the rhombus? A. 14 cm2 B. 21 cm2 C. 28 cm2 D. 56 cm2
Answer:
A) 14 cm^2
Step-by-step explanation:
Given
Rhombus ABCD
let the given length be diagonal 1, a= 8cm
diagonal 2,b= 3.5cm
Area of ABCD=?
Area of rhombus= ab/2
Putting the values in above :
Area of ABCD= 8(3.5)/2
=28/2
=14 !
Answer:
14cm^2
Step-by-step explanation:
Given the following graph where are the solutions located?
I and III
II only
I only
II and III
I and II
When a graph has a solid line, solutions lie ON that line, whereas if it was a dotted line, solutions lie only on the shaded side of that line, not the line itself.
Tim mails two boxes of cookies to friends. One box weighs 1 3/4 pounds, and the other weighs 2 2/3 pounds. What is the total weight of the two boxes?
the answer would be 4 5/12 pounds
The total weight of the two boxes will be 4 and 5/12 pounds.
What is Algebra?Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.
Tim mails two boxes of cookies to friends. One box weighs 1 and 3/4 pounds, and the other weighs 2 and 2/3 pounds.
Then the total weight of the two boxes will be
Total weight = 1 + 3/4 + 2 + 2/3
Total weight = 3 + 17/12
Total weight = 3 + 1 + 5/12
Total weight = 4 + 5/12
The total weight of the two boxes will be 4 and 5/12 pounds.
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Which math sentence can be used to determine if this triangle is a right triangle? 20+21 = 2920 squared +21 squared equals 29 squared 29+21 = 29 squared +21 squared equals 20 squared
20^2+21^2=29^2 can be used to determine if the triangle is a right triangle
Answer:
Step-by-step explanation:
The two smaller line lengths are squared separately and added. The square of the third line is noted. If squares of the two small ones equal the square of the largest one, you are working with a right angle triangle.
The one that puts into a formula what is stated above is B. D is close, but the longest line must be by itself.
5. Solve by using the square root property.
(x - 3)² +6=1
Answer:
x = 3 + i+√5
x = 3 + i-√5
OR
x= 4 - √6
x= 4 +√6
Step-by-step explanation:
(x - 3)² +6=1
(x - 3)² + 6 = 1
-6 -6
sq root > (x - 3)² = -5
x-3 = i±√5 (i because neg. number)
x = 3 + i±√5
since its ±
two possible answers
x = 3 + i+√5
x = 3 + i-√5
Or
(x - 3)² +6=1
(x-3)+ √6= √ 1
x-3 = 1 - (±) √6
x= 4 - (±) √6
Answers
x= 4 - √6
x= 4 +√6
Which function is equivalent to f(x) = lnx?
f(x) = log3x
f(x) = log10x
f(x) = logbx
f(x) = logex
Answer:
[tex]f(x)=log_ex[/tex]
Step-by-step explanation:
By definition, we can write ln instead of log. WHEN??
Whenever the base of the logarithm is the number "e".
Hence, when we have:
[tex]Log_e[/tex]
We can write it in shortcut as:
[tex]Log_e=ln[/tex]
Hence, ln x can also be written as [tex]Log_ex[/tex]
Fourth answer choice is right.
Answer:
[tex]f(x) = log_e(x)[/tex]
Step-by-step explanation:
[tex]f(x) = ln x[/tex]
For logarithmic function ln(x) the base of ln is 'e'
[tex]f(x) = log_3(x)[/tex]
The base of log is 3 . so it is not equivalent to [tex]f(x) = lnx[/tex]
[tex]f(x) = log_{10}(x)[/tex]
The base of log is 10 . so it is not equivalent to [tex]f(x) = lnx[/tex]
[tex]f(x) = log_b(x)[/tex]
The base of log is b . so it is not equivalent to [tex]f(x) = lnx[/tex]
[tex]f(x) = log_e(x)[/tex]
The base of log is e . so it is equivalent to [tex]f(x) = lnx[/tex]
Consider the net of a triangular prism where each unit on the coordinate plane represents four feet. If a sheet of plywood measures 4 ft x 8 ft, how many sheets of plywood will a carpenter need to build the prism?
A) 3
B) 3.5
C) 4
D) 4.5
Answer:
B) 3.5 ^_^
Step-by-step explanation:
find a • b. u = <8,7>, v=<9,7>
Answer:
[tex]\large\boxed{\vec{u}\circ\vec{v}=121}[/tex]
Step-by-step explanation:
[tex]\vec{a}=<x_a,\ y_a>,\ \vec{b}=<x_b,\ y_b>\\\\\vec{a}\circ\vec{b}=x_ax_b+y_ay_b\\\\====================================\\\\\vec{u}=<8,\ 7>,\ \vec{v}=<9,\ 7>\\\\\vec{u}\circ\vec{v}=(8)(9)+(7)(7)=72+49=121[/tex]
Halp?
The cargo area of a truck is 8 1\2 feet long, 6 feet wide, and 10 1\2 feet high. The volume of the cargo area is cubic feet.
The formula for finding the volume of a rectangular prism (the cargo area of the truck is the shape of a rectangle in 3D; a rectangular prism) is V = (l)(w)(h); where l = length, w = width, and h = height.
First, substitute the known values into the equation:
l = 8.5
w = 6
h = 10.5
V = (8.5)(6)(10.5)
(Note: .5 = 1/2)
Now, all we need to do is simplify:
V = 535.5 ft³ OR 535 1/2 ft³
(Note: ft³ is the condensed form of cubic feet)
You can pick whichever form your test directs you to use. They are both the same value though.
Hope this helps!
The volume of the cargo area of the truck is 519.75 cubic feet.
The volume of the cargo area of the truck can be calculated by multiplying its length, width, and height. Given the dimensions in feet are:
Length = 8 1/2 feet = 8.5 feet = 8 + 1/2 feet
Width = 6 feet
Height = 10 1/2 feet = 10.5 feet = 10 + 1/2 feet
To find the volume, we convert the mixed numbers to improper fractions and then multiply:
Length in fractions = 8 + 1/2 = 17/2 feet
Width in fractions = 6 = 6 * 2/2 = 12/2 feet
Height in fractions = 10 + 1/2 = 21/2 feet
Now, multiply the dimensions to find the volume:
Volume = Length * Width * Height
Volume = (17/2 feet) * (12/2 feet) * (21/2 feet)
Volume = (17 * 12 * 21) / (2 * 2 * 2) cubic feet
Volume = 4158 / 8 cubic feet
Simplifying the fraction, we get:
Volume = 519.75 cubic feet
What is f(g(x)) for x > 5?
Answer:
[tex]\large\boxed{B.\ 4x^2-41x+105}[/tex]
Step-by-step explanation:
[tex]f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105[/tex]
Answer: Option B
[tex]f(g(x)) = 4x^2 -41x + 105[/tex]
Step-by-step explanation:
We have 2 functions
[tex]f(x) = 4x -\sqrt{x}[/tex]
[tex]g(x) = (x-5)^2[/tex]
We must find [tex]f(g(x))[/tex]
To find this composite function enter the function g(x) within the function f(x) as follows
[tex]f(g(x)) = 4(g(x)) -\sqrt{(g(x))}[/tex]
[tex]f(g(x)) = 4(x-5)^2 -\sqrt{(x-5)^2}[/tex]
By definition [tex]\sqrt{a^2} = |a|[/tex]
So
[tex]f(g(x)) = 4(x-5)^2 -|x-5|[/tex]
Since x is greater than 5 then the expression [tex](x-5)> 0[/tex].
Therefore we can eliminate the absolute value bars
[tex]f(g(x)) = 4(x-5)^2 -(x-5)[/tex]
[tex]f(g(x)) = 4(x^2 -10x + 25) -(x-5)[/tex]
[tex]f(g(x)) = 4x^2 -40x + 100 -x+5[/tex]
[tex]f(g(x)) = 4x^2 -41x + 105[/tex]
Give some examples of perpendicular lines inside or outside your classroom.
Answer: Well for example two roads that are meeting with each other and they form a right angle,
Step-by-step explanation:
Answer:
1. A Christian cross.
2. Roads that meet at intersections
3. Hospital crosses.
Step-by-step explanation:
Perpendicular lines are lines that touch each other, or are slanted in a way that they will eventually touch each other. The examples I used are all crosses, which are two line that cross.
PLS HELP!!!!What are the sine, cosine and tangent ratios of
angle W in the triangle below
Step-by-step explanation:
Remember SOH-CAH-TOA:
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
The side adjacent to W is 4. The side opposite of W is 3. The hypotenuse is 5.
Therefore:
Sine = 3 / 5
Cosine = 4 / 5
Tangent = 3 / 4
The width of a rectangle is 12 cm less than the length. The area is 64cm^2 find the length and width. Use quadratic equations by factoring.
Answer:
length=16, width=4
Step-by-step explanation:
Use l as length and make an equation:
64 = x*(x-12)
Solve using quadratics, x=16.
Subtract 12 and get 4.
The basketball team sold t-shirts and hats as a fundraiser they sold a total of 23 items and made a profit of $246 they made a profit of $10 for every t shirt they sold and $12 for every hat they sold dertermine the number of t shirts and the number of hats the basketball team sold
The basketball team sold a total of 23 items (t-shirts and hats) and made $246. By setting up and solving a system of equations, it was determined that they sold 15 t-shirts and 8 hats.
To determine the number of t-shirts and hats sold by a basketball team for a fundraiser, given that they sold a total of 23 items and made a profit of $246, with a profit of $10 per t-shirt and $12 per hat sold. To solve this problem, we can set up a system of linear equations and solve for the two variables representing the number of t-shirts (T) and the number of hats (H).
Let T represent the number of t-shirts and H represent the number of hats.
We know that T + H = 23 (since 23 items were sold in total).
We also know that the profit from t-shirts is $10 per t-shirt, and the profit from hats is $12 per hat. Therefore, 10T + 12H = $246 (total profit).
We can now set up the equations:
T + H = 23
10T + 12H = $246
From the first equation, we can express H in terms of T: H = 23 - T.
Substitute H = 23 - T into the second equation:
10T + 12(23 - T) = $246
Simplify and solve for T:
10T + 276 - 12T = $246
-2T + 276 = $246
-2T = $246 - 276
-2T = -$30
T = 15 (number of t-shirts sold)
Now, we can find the number of hats by substituting T back into H = 23 - T. Since T is 15, H = 23 - 15 = 8 (number of hats sold).
Therefore, the basketball team sold 15 t-shirts and 8 hats.
Simplify (x5/8)2/3 look at the picture
Answer:
[tex]x^{\frac{5}{12} }[/tex]
Step-by-step explanation:
In the question given we use the law of exponents;
[tex](a^{b})^{c} = a^{bc}[/tex]
If a base a is raised to a power b and the entire expression raised to a power c, the resulting expression is simply equal to the base a raised to the product of the two exponents b and c, that is bc.
In the case given,
a = x
b = 5/8
c = 2/3
To simplify the expression we simply multiply b and c;
bc = 5/8 * 2/3
= 5/12
The simplified expression is thus;
[tex]x^{\frac{5}{12} }[/tex]
Answer:
The correct answer is ((x⁵/⁸)²/³) = x⁵/¹²
Step-by-step explanation:
Points to remember:-
Identity
(xᵃ)ᵇ = xᵃᵇ
Here it is given that, ((x⁵/⁸)²/³)
To find the value of ((x⁵/⁸)²/³)
(5/8) * (2/3) = (5 * 2) /(8 * 3) = 10/24 = 5/12
By using identity (xᵃ)ᵇ = xᵃᵇ we can write,
((x⁵/⁸)²/³) = x⁽⁵/⁸⁾ˣ⁽²/³⁾
= x⁵/¹²
Therefore the correct answer is ((x⁵/⁸)²/³) = x⁵/¹²
Ignore the top just answer both of the questions at the bottom plz
Answer:
y = 5x+2 , y=x-6
Step-by-step explanation:
just by looking at the table you can see for the first one 5x + 2 satisfies the table, and x-6 satisfies the right table.
for the first table the equation is:
[tex]x(5) + 2 = y[/tex]
and for the second it's:
[tex]x - 6 = y[/tex]