Answer:
The answer to the question is;
1637.769 grams of water will need to be perspired in order to maintain his original temperature.
Explanation:
Energy intake of the person = 4000 kJ
Energy required to vaporize 1 mole of water = 44.0 kJ
That is 44.0 kJ/mole
Therefore
The number of moles of water that can be vaporized by 4000 kJ is given by
(4000 kJ)/ (44.0 kJ/mole) = 90.91 moles.
Mass of one mole of water = Molar mass of water = 18.01528 g/mol
Since number of moles of water = ([tex]\frac{Mass .of. water}{Molar. mass. of. water}[/tex])
We therefore have
Mass of water = (Number of moles of water)× (Molar mass of water)
Mass of water = 90.91 moles× 18.01528 g/mol = 1637.769 g
The mass (in grams) of water that he would need to perspire in order to maintain his original temperature is 1637.769 g.
The person would need to perspire approximately [tex]\( 1638.86 \, \text{g} \)[/tex] (or about 1.64 kg) of water to maintain their original temperature after consuming 0.50 pounds of cheese with an energy intake of 4000 kJ.
To determine the mass of water the person needs to perspire to maintain their original temperature, we need to calculate the amount of water required to dissipate the energy intake through perspiration. Given:
Energy intake: [tex]\( 4000 \, \text{kJ} \)[/tex]
Heat of vaporization of water: [tex]\( 44.0 \, \text{kJ/mol} \)[/tex]
First, we need to find out how many moles of water need to be vaporized to dissipate 4000 kJ.
[tex]\[ \text{Moles of water} = \frac{\text{Total energy intake}}{\text{Heat of vaporization per mole}} = \frac{4000 \, \text{kJ}}{44.0 \, \text{kJ/mol}} \][/tex]
[tex]\[ \text{Moles of water} = \frac{4000}{44.0} \approx 90.91 \, \text{moles} \][/tex]
Next, we convert the number of moles to mass. The molar mass of water [tex](\( \text{H}_2\text{O} \))[/tex] is approximately [tex]\( 18.015 \, \text{g/mol} \).[/tex]
[tex]\[ \text{Mass of water} = \text{Moles of water} \times \text{Molar mass of water} = 90.91 \, \text{moles} \times 18.015 \, \text{g/mol} \][/tex]
[tex]\[ \text{Mass of water} = 1638.86 \, \text{g} \][/tex]
The relationship between heat (q), work (w), and internal energy (U) can be described with which of the following?a. q = ΔU × wb. ΔU = qwc. w = ΔUqd. ΔU = q + w
Answer:
d. ΔU = q + w
Explanation:
Internal energy is the sum of kinetic energy (which comes from motion of molecules) and potential energy ( which comes from chemical bonds between atoms and other intermolecular forces that maybe present).
First law of thermodynamics states that: "the change in internal energy of a closed system is equal to the energy added to it in form of heat(q) and work (w) done on the system by the surroundings.
Mathematically written as:
[tex]E_{internal}[/tex] = q + w
Conventionally, the first law is based on the system doing work and the surrounding doing work.
[tex]E_{internal}[/tex] can also be written as ΔU.
Therefore [tex]E_{internal}[/tex] = ΔU = q + w
ΔU = q + w
A concrete highway is built of slabs 12 m long .How wide should be the expansion cracks between the slabs at 15 Celsius to prevent buckling if the range of temperature is -30 to 50 Celsius?
Answer:
[tex]x=4.2\ mm[/tex]
Explanation:
Given:
length of the concrete slab, [tex]l=12\ m[/tex]temperature of observation, [tex]T_o=15^{\circ}C[/tex]we've the coefficient of linear expansion for concrete, [tex]\alpha=10^{-5}\ ^{\circ}C^{-1}[/tex]lower temperature limit, [tex]T_l=-30^{\circ}C[/tex]upper temperature limit, [tex]T_u=50^{\circ}C[/tex]Change in length due to temperature can be given as:
[tex]\Delta l=l.\alpha.(T_u-T_l)[/tex]
[tex]\Delta l=12\times 10^{-5}\times (50-(-30))[/tex]
[tex]\Delta l=0.0096\ m=9.6\ mm[/tex]
Now at temperature 15°C:
[tex]\Delta l'=12\times 10^{-5}\times (15-(-30))[/tex]
[tex]\Delta l'=0.0054\ m=5.4\ mm[/tex]
Hence the expansion crack between the slabs at this temperature must be:
[tex]x=\Delta l-\Delta l'[/tex]
[tex]x=9.6-5.4[/tex]
[tex]x=4.2\ mm[/tex]
Total peripheral resistance is related to all of the following except the
Options to the question :
A- blood viscosity
B- osmolarity of interstitial fluid
C- turbulence
D-length of a blood vessel
E- blood vessel diameter
Answer:
Total peripheral resistance is NOT related to B ( osmolarity of interstitial fluid).
Explanation:
Total peripheral resistance( also called systemic vascular resistance) is defined as the total opposition to the flow of blood in systemic circulation. Increase in total peripheral resistance leads to high blood pressure while it's decrease leads to low blood pressure. Factors that contributes to total peripheral resistance in systemic circulation includes:
- blood vessel diameter
- blood viscosity,
- lengthy of a blood vessel and
- turbulence.
In a manufacturing process, a large, cylindrical roller is used to flatten material fed beneath it. The diameter of the roller is 1.00 m and while being driven into rotation around a fixed axis, its angular position is expressed as
θ = 2.50t2 - 0.600t3
where θ is in radians and t is in seconds.
a) Find the maximum angular speed of the roller
b) what is the maximum tangential speed of the point an the rim of the roller?
c) at what time t should the driven force be removed from the roller so that the roller does not reverse its direction of rotation?
d) Through how many rotations has the roller turned between t=0 and the time found in part c?
Explanation:
Below is an attachment containing the solution.
A sealed tank contains 30 moles of an ideal gas at an initial temperature of 270 K. The pressure of the gas is increased until the final pressure equals 1.4 times the initial pressure. The heat capacity at constant pressure of the gas is 32.0 J(mol*K) What is the change in the internal energy of the gas? Let the ideal-gas constant R = 8.314 J/(mol • K).
130 kJ
77 kJ
-23 kJ
100 kJ
-50 kJ
The isochoric process involving a gas at constant volume undergoes a temperature change from 270 K to 378 K, resulting in a change in internal energy of approximately 40.4 kJ.
1. Identify the process:
This problem describes an isochoric process, meaning the volume of the gas remains constant throughout the pressure change. Since the volume doesn't change, we can utilize the pressure-temperature relationship for ideal gases.
2. Apply the pressure-temperature relationship:
The pressure-temperature relationship for an ideal gas at constant volume is:
P₁V₁ = P₂V₂
where:
P₁ is the initial pressure
V₁ is the initial volume (constant in this case)
P₂ is the final pressure
V₂ is the final volume (constant in this case)
Since the volume remains constant, we can rewrite the equation as:
P₁ = P₂ * (T₁ / T₂)
where:
T₁ is the initial temperature (270 K)
T₂ is the final temperature (unknown)
3. Solve for the final temperature:
We are given that the final pressure (P₂) is 1.4 times the initial pressure (P₁). Substitute this information into the equation:
P₁ = 1.4 * P₁ * (T₁ / T₂)
Simplify the equation:
1 = 1.4 * (T₁ / T₂)
Solve for T₂:
T₂ = 1.4 * T₁
T₂ = 1.4 * 270 K
T₂ = 378 K
4. Calculate the change in internal energy:
For an ideal gas at constant volume, the change in internal energy (ΔU) is given by:
ΔU = n * Cv * ΔT
where:
n is the number of moles (30 mol)
Cv is the heat capacity at constant volume (unknown)
ΔT is the change in temperature (T₂ - T₁)
5. Relate Cv and Cp:
We are given the heat capacity at constant pressure (Cp) as 32.0 J/(mol*K). However, we need Cv for the internal energy calculation. We can utilize the relationship between Cv and Cp for ideal gases:
Cv = Cp - R
where:
R is the gas constant (8.314 J/(mol*K))
Substitute the given value of Cp:
Cv = 32.0 J/(mol*K) - 8.314 J/(mol*K)
Cv = 23.686 J/(mol*K)
6. Calculate the change in internal energy:
Now, substitute all the known values into the equation for ΔU:
ΔU = 30 mol * 23.686 J/(mol*K) * (378 K - 270 K)
ΔU = 40429.8 J
7. Convert to kilojoules and round the answer:
Convert the answer to kilojoules:
ΔU = 40429.8 J / 1000 J/kJ
ΔU ≈ 40.4 kJ
Therefore, the change in internal energy of the gas is approximately 40.4 kJ.
____ is a structural engineered wood that utilizes wood from species of wood that are not large or strong enough to be useful in solid lumber products, uses 12 in. long strands that are cut from logs, dried, and immersed in resin before being pressed into solid billets, and strands are aligned parallel to each other to take advantage of the natural strength of the wood.
Answer:
Explanation:
UR MOM SUCKQ
PLS HELP! WILL MARK BRANLIEST!!!
A numerical scale of earthquake magnitude that takes into account the size of the fault rupture is the ____.
A) Richter scale
B) modifies Mercalli scale
C) moment magnitude scale
D) epicentral distance scale
Answer:
d. epicentral distance scale
Explanation:
The depth of focus from the epicenter, called as Focal Depth, is an important parameter in determining the damaging potential of an earthquake. Most of the damaging earthquakes have shallow focus with focal depths less than about 70km. Distance from epicenter to any point of interest is called epicentral distance
Awning windows can be 100% openable and are best used where extreme weather conditions require a tight seal when the window is closed, although these windows are in common use everywhere.1. True2. False
Answer: True
Explanation: Awning windows
are Weather-tight, good choice in damp climates and can protect your home against moisture, even when they’re open during a rainstorm. Because of the way awning windows are constructed, they allow for nearly 100 percent of viable ventilation, without the threat of water seeping into the home. They also offer a superior seal against air pass through
These windows form a slant (of about 45 degree) after opening hence do not open 100%; this slant opening is advantageous in preventing rain from entering the building.
The windows can also be tightly sealed (from the inside) during extreme/cold weather conditions.
True, awning windows can be fully opened and are beneficial for creating a tight seal in extreme weather conditions. They also allow for maximum ventilation while preventing unwanted energy transfer, making them widely used regardless of climate. Design elements like overhangs and window orientation further enhance energy efficiency.
True, awning windows can be 100% openable and are indeed best used in areas that experience extreme weather conditions, thanks to their capability to form a tight seal when closed. The design of these windows allows them to prevent unwanted energy transfers by keeping the harsh weather out when they are closed, while still allowing for maximum ventilation when opened. This makes them highly versatile and thus they are in common use in various locations, not just those with extreme weather. Factors such as the orientation of the windows, the use of overhangs, and the placement of deciduous trees also play important roles in maximizing energy efficiency by modulating the amount of sunlight and heat entering a building.
For instance, overhangs above south-facing windows help keep a house cool in summer by casting a shadow over the window when the sun is high, and allowing sunlight to warm the rooms in winter when the sun stays closer to the horizon. Moreover, in climates where preventing heat gain is crucial, the largest windows may face north to avoid the sun, with south-facing windows being smaller and well insulated to allow for cross-ventilation without admitting much sunlight. Additionally, windows equipped with weatherstripping, and double-paned, low-emissivity glass can significantly reduce energy losses, contributing to a building's overall energy efficiency.
Two masses exert a force of 1,161 N on each other when they are 20 km apart. How much force will these two masses exert on each other when they are 40 km apart?
Explanation:
Below is an attachment containing the solution.
A block in the shape of a rectangular solid has a crosssectional area of 3.50 cm2 across its width, a front-to-rear length of 15.8 cm, and a resistance of 935 0. The block’s material contains 5.33 $ 1022 conduction electrons/m3. A potential difference of 35.8 V is maintained between its front and rear faces. (a) What is the current in the block? (b) If the current density is uniform, what is its magnitude? What are (c) the drift velocity of the conduction electrons and (d) the magnitude of the electric field in the block?
Answer:
a) 38.3mA
b) 109.396A/m^2
c) 1.283cm/s
d) 226.582V/m
Explanation:
The equation for current is given by:
I = V/R = 35.6/ 935 = 0.03829 A Approximately 38.3mA
b) The equation to find the magnitude is given by:
J = I/A = 0.03829/ 0.000350m^2
J = 109.396A/m^2
c) The equation to calculate drift velocity of the electron is given by: Vd = J/ ne = 109.396/( 5.33×10^23 )(1.60×10^-19)
Vd = 0.01283 approximately 1.283cm/s
d) The magnitude of electric field in the block, E = V/L = 35.8/ 0.158m = 226.582V/m
1) Calculate the torque required to accelerate the Earth in 5 days from rest to its present angular speed about its axis. 2) Calculate the energy required. 3) Calculate the average power required.
Final answer:
To find the torque to accelerate Earth in 5 days to its angular speed, calculate the moment of inertia and use τ = Iα. The energy required is given by E_k = (1/2)Iω^2, and average power is P = E_k / t.
Explanation:
To calculate the torque required to accelerate the Earth from rest to its present angular speed about its axis in 5 days, we first need to determine the Earth's moment of inertia (I) and its angular acceleration (α). The Earth's moment of inertia can be estimated using the formula I = (2/5)MR^2, where M is the mass of the Earth and R is its radius. The angular speed (ω) is 2π rad/day since there are 2π radians in a full rotation and the Earth completes one rotation per day. The angular acceleration, α, is then ω divided by the time in seconds to accelerate, which is 5 days or 5 x 24 x 3600 seconds. The formula τ = Iα is used to calculate torque.
To find the energy required, we can use the rotational kinetic energy formula E_k = (1/2)Iω^2, where ω is the final angular velocity. Subsequently, the average power required is the energy divided by the time over which it is expended, P = E_k / t, where t is the time in seconds.
A 1 kg rock is suspended by a massless string from one end of a meter stick at the 0 cm mark. What is the mass m suspended from the meter stick at the 75 cm mark if the system is balanced?
Answer:
2 kg
Explanation:
Note: For the meter stick to be balanced,
Sum of clock wise moment must be equal to sum of anti clock wise moment
Wd = W'd' ................ Equation 1
Where W = weight of the rock, d = distance of the meter stick from the point of support, W' = weight of the that must be suspended for the meter stick to be balanced, d' = distance of the mass to the point of support.
make W' the subject of the equation
W' = Wd/d'............... Equation 2
Taking our moment about the support,
Given: W = mg = 1 ×9.8 = 9.8 N, d = 50 cm, d' = (75-50) = 25 cm
Substitute into equation 2
W' = 9.8(50)/25
W' = 19.6 N.
But,
m = W'/g
m = 19.6/9.8
m = 2 kg.
To find the mass M suspended from the meter stick, we can use the principle of rotational equilibrium. By setting the torques on either side of the fulcrum equal to each other, we can calculate the mass M at the 75 cm mark to be 3 kg.
Explanation:To determine the mass M suspended from the meter stick at the 75 cm mark, we can use the principle of rotational equilibrium. Since the system is balanced, the torques on both sides of the meter stick must be equal.
The torque of the rock can be calculated using its weight, which is equal to its mass multiplied by the acceleration due to gravity. The torque of the mass M can be calculated by multiplying its mass by the distance from the fulcrum (75 cm) to its center of mass. By setting the torques equal to each other, we can solve for M.
The torque of the rock: TR = (1 kg)(9.8 m/s²)(0.75 m).
The torque of the mass M: TM = M(9.8 m/s²)(0.25 m).
Setting TR equal to TM and solving for M, we get M = (1 kg)(0.75 m)/(0.25 m) = 3 kg.
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A man stands on a scale and holds a heavy object in his hands. What happens to the scale reading if the man quickly lifts the object upward and then stops lifting it?
Answer:
Explanation:
When he accelerates the heavy object up , the reading increases because an extra downward normal force acts on it, then scale reading returns to the same reading as when standing stationary, and then decreases as although he is lifting the heavy object , the acceleration is decreasing ,so the extra upward normal force acts.
Two small balls, A and B, attract each other gravitationally with a force of magnitude F. If we now double both masses and the separation of the balls, what will now be the magnitude of the attractive force on each one?A) 16F
B) 8F
C) 4F
D) F
E) F/4
The magnitude of the attractive force on each one will be F.
Explanation:
As two small balls are experiencing gravitational force between them ,then they will obey universal law of gravity. As per the universal law of gravity, the gravitational force acting between two objects will be directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the two objects.
So if the mass of the two small balls A and B are considered as M and m, respectively, with the distance of separation be considered as r. Then the gravitational force of attraction acting between A and B will be
[tex]F = \frac{GMn}{r^{2} }[/tex] , This is the original or initial gravitational force between A and B.
Now, if the masses of A and B are doubled, then the new masses will be M' = 2 M and m' = 2m, respectively. Similarly, if the separation of the balls is also doubled then r' = 2r. So the new gravitational force exerting between A and B is
[tex]F' = \frac{GM'm'}{r'^{2} } = \frac{G*2M*2m}{(2r)^{2} } =\frac{4GMm}{4r^{2} } = \frac{GMm}{r^{2} }=F[/tex]
So after doubling the masses as well as the distance of separation, there will be no change in the gravitational force. So the magnitude of the attractive force on each one will be F.
A soccer ball is rolling with a constant acceleration of -1.5 m/s2 . At ti = 0 s, the ball has an instantaneous velocity of 14 m/s. After 3s of rolling, what would be the velocity of the ball (in m/s)?
Answer:
[tex]v_{f} = 9.5\,\frac{m}{s}[/tex]
Explanation:
The final velocity is:
[tex]v_{f} = v_{o} + a \cdot t[/tex]
[tex]v_{f} = 14\,\frac{m}{s} + (-1.5\,\frac{m}{s^{2}} )\cdot (3\,s)[/tex]
[tex]v_{f} = 9.5\,\frac{m}{s}[/tex]
The velocity of the soccer ball after 3 s of rolling would be 9.5 m/s.
For a soccer ball rolling with a constant acceleration of -1.5 m/s², we can use the equation for velocity with constant acceleration: v = (initial velocity) + (acceleration)(time). At t = 3 s, the ball has an initial velocity of 14 m/s and has been rolling for 3 s, so we can plug these into the equation to find the velocity:
v = 14 m/s + (-1.5 m/s²)(3 s) = 14 m/s - 4.5 m/s = 9.5 m/s
Therefore, after 3 s of rolling, the velocity of the ball would be 9.5 m/s.
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While you are in a bus that moves at 100 km/h you walk from the back to the front at 10 km/h. What is your speed relative to the road outside?
Answer: 110km/h
100+10=110km/h
Explanation:
Motion is defined as a change of position. The frame of reference is usually assumed to be at rest. If one is sitting on a bus, the road appears to be moving backwards relative to the observer. If he/she now walks to the front of the bus, he has a speed relative to the earth which is now greater than that of the bus hence the answer.
Your speed relative to the road, when walking from the back to the front of a bus moving at 100km/h, is 110km/h.
Explanation:Your speed relative to the road outside in this scenario will be the sum of the speed of the bus and your own speed walking within the bus. The bus is moving at 100 km/h, and you're moving toward the front of the bus at 10 km/h. Because you're moving in the same direction as the bus, you add your speeds together. Hence, your speed relative to the road outside would be 100 km/h (bus) + 10 km/h (you) = 110 km/h.
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(Atwood’s Machine): Two masses, 9 kg and 12 kg, are attached by a lightweight cord and suspended over a frictionless pulley. When released, find the acceleration of the system and the tension in the cord.
Answer:
Acceleration = 1.428m/s2
Tension = 102.85N
Explanation:
The detailed solution is attached
Answer:
The acceleration of the system is 1.401 m/s² and
The tension in the cord is 100.902 N
Explanation:
Let the 9 kg mass be m
Let the 12 kg mass be M
By Newton's second law of motion we have
For the 9 kg mass, T - mg = ma and for the 12 kg mass we have T - Mg = -Ma
Here we took the upward acceleration as positive a of the 9 kg mass and the downward acceleration of the 12 kg mass as -a
Solving for T for the 9 kg mass we have
T = mg + ma
Substituting the value of T in to the 12 kg mass equation, we have
mg + ma - Mg = -Ma or a = [tex](\frac{M-m}{M+m} )g[/tex] therefore the acceleration is
1.401 m/s²
and the tension is T = mg + ma = 9×(9.81+1.401) = 100.902 N
Approximately how fast is Jupiter orbiting the Sun? Approximately how fast is Jupiter orbiting the Sun? 10 km/skm/s a little less than 15 km/skm/s 20 km/skm/s cannot be determined from the information provided
Answer:
The correct answer is
a little less than 15 km/s.
Explanation:
The distance between the sun and Jupiter varies by about 75 million km between the perihelion and the aphelion with an average distance of 778 million km from the sun for which it takes Jupiter about 12 years to complete its orbit round the sun giving it an orbital speed of about 13.07 km/s
The size of Jupiter is more than the twice the combined size of all the other planets, which is about 1.300 times the size of earth.
Jupiter is orbiting the Sun from b. 15 km/s.
Jupiter orbits the Sun at an average distance (semi-major axis) of about 5.2 Astronomical Units (AU), where 1 AU is the average distance from the Earth to the Sun, approximately 149.6 million kilometers.
Using Kepler's third law of planetary motion and the fact that Jupiter takes approximately 11.86 Earth years to complete one orbit around the Sun, we can estimate its average orbital speed. The orbital speed (v) of a planet can be roughly calculated by the formula:
[tex]v = \frac{2 \pi r}{T}[/tex]
where:
[tex]r[/tex] is the average orbital radius (semi-major axis in meters), and[tex]T[/tex] is the orbital period in seconds.Converting the semi-major axis from AU to kilometers:-
[tex]r = 5.2 \times 149.6 \times 10^6 \text{ km} \\= 777.92 \times 10^6 \text{ km}[/tex]
Converting the orbital period from years to seconds:
[tex]T = 11.86 \text{ years} \times 3.154 \times 10^7 \text{ seconds/year} \\= 3.74 \times 10^8 \text{ seconds}[/tex]
Now, plugging in these values to our formula:
[tex]v = \frac{2 \pi \times 777.92 \times 10^6}{3.74 \times 10^8} \text{ km/s} \\\approx 13.07 \text{ km/s} \ {or} 15 km[/tex]
Consider the following tasks: A. Draw a closed curve around the system. B. Identify "the system" and "the environment." C. Draw a picture of the situation. Which of these are steps used to identify the forces acting on an object? 1. A only 2. B only 3. C only 4. A, B, and C 5. None of them
Answer:
Explanation:
To identify forces acting on an object
1. Draw a closed curve around the system.
2.Identify "the system" and "the environment."
3. Draw a picture of the situation. Which of these are steps used to identify the forces acting on an object?
All of these are correct.
A close loop doesn't allow external forces to act on the system and this only allows the the forces on the object to act alone.
Drawing the free body diagram will show the forces acting on the body.
Also, isolating the system from the environment so that it won't be affected by external forces or resistance
In the absence of an electric field, a radioactive beam strikes a fluorescent screen at a single point. When an electric field is applied, the radioactive beam is separated into three different components. One of the components is deflected toward the positive electrode because it is negatively charged, one of the components is deflected toward the negative electrode because it is positively charged, and one component is not deflected in any direction; instead, it moves along a straight path. Identify the charges possessed by the different components of the radioactive beam by observing their behavior under the influence of an electric field.
Answer: Beta, alpha and gamma ray
Explanation: The component being deflected to the positive side is the beta radiation because it is negatively charged and thus is attracted by the positive terminal of the Electric Field.
The component being deflected to the negative side is the alpha radiation, it's is positively charged and thus being attracted by the negative part of the Electric Field.
The component that went straight down without deflection is the gamma radiation. It is neutral and possess no charge and thus is not deflected.
Answer:
Beta rays (symbol β) are negatively charged because they are electrons.
Alpha rays (symbol α) are positively charged because they are helium nuclei.
Gamma rays (symbol γ or. ) are neutral, since they are photons only. Comprises of the shortest electromagnetic wavelength and thus provides the highest photon energy.
This is a change in the position of a body with respect to time relative to a reference point.
Answer: MOTION
Explanation:
motion is defined as the displacement of an object with respect to time relative to a stationary object (reference point). A good example of an object that can serve as a reference point includes: a tree or a building. The movement of a body at constant speed towards a particular direction at regular intervals of time can be determined and it's called uniform motion.
There are different types of motion, these includes: simple harmonic motion,
linear motion,
circular motion,
Brownian motion,
Rotatory motion
Answer:rest
Explanation:
A first-order reaction has a rate constant of 0.241/min. If the initial concentration of A is 0.859 M, what is the concentration of A after 10.0 minutes? 0.0772 M 0.00334 M 0.736 M 0.280 M
Answer:
option A.
Explanation:
given,
rate constant. k = 0.241/min
[A_0] = 0.859 M
[A_t] = ?
t = 10 minutes.
using first order reaction formula
[tex]k=\dfrac{2.303}{t}log(\dfrac{[A_0]}{[A_t]})[/tex]
[tex]0.241=\dfrac{2.303}{10}log(\dfrac{[0.859]}{[A_t]})[/tex]
[tex]log(\dfrac{[0.859]}{[A_t]}) = 1.0464[/tex]
[tex]\dfrac{[0.859]}{[A_t]} = 11.129[/tex]
[tex][A_t]=\dfrac{0.859}{11.129}[/tex]
[tex][A_t]=0.0772\ M[/tex]
the concentration of A after 10 minutes is equal to 0.0772 M.
Hence, the correct answer is option A.
Air masses are identified on the basis of temperature and
Answer:
Moisture content
Explanation:
Air mass is a volume of air spread through a vast area may it cover hundred to thousand Kilometers and is identified on the basis of nearly equal temperature and water vapour content of the air thorough out the area.
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with grams of a radioactive isotope, how much will be left after half-lives
Answer:
Incomplete questions
This is the complete question
The half-life of a radioactive isotope is the time it takes for a quantity for the isotope to be reduced to half its initial mass. Starting with 150 grams of a radioactive isotope, how much will be left after 6 half-lives
Explanation:
Let analyse the question generally first,
The the mass of the radioactive element be M.
We want to know it mass after n half life
Then,
After first half life, it mass is
M1=M×½
After second half life, it mass is
M2= M×(½)²
After third half life, it mass is
M3= M×(½)³
But now we can see a pattern developing, because for each new half-life we are dividing the quantity by 2 to a power that increases as the number of half-lives.
Then we can take the original quantity and quickly compute for
nth half-lives:
So after nth half life will be
Mn= M × (½)ⁿ
Generally,
Now, let apply it to our questions
Give that the mass of the radioactive isotope is 150grams
It mass after 6th half life
Then, n=6
So applying the formula
Mn= M × (½)ⁿ
M6= 150 ×(½)^6
M6= 150×1/64
M6=2.34grams
The mass of the radioactive isotope after 6th half life is 2.34grams
Determine the number of revolutions through which a typical automobile tire turns in 1 yr. Suppose the automobile travels 13500 miles each year on tires with radius 0.220 m.
Answer:
Number of revolution made by tire is 1.57 x 10⁷
Explanation:
Radius of tire, r = 0.220 m
Circumference of tire, C = 2πr
Substitute the value of r in the above equation.
C = 2 x π x 0.220 m = 1.38 m
Total distance covered by tire in a year, D = 13500 miles
But 1 mile = 1609.34 m
So, D = 13500 x 1609.34 m
Number of revolutions take by tire, N = [tex]\frac{D}{C}[/tex]
[tex]N=\frac{13500\times1609.34}{1.38}[/tex]
N = 15743543
A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. Find the magnitude of the force on the wire if it carries a current of 2.2 A.
Answer : 0.814 newton
Explanation:
force (magnetic) acting on the wire is given by
F= ? , I=2.2amp , B = 0.37 T
F = B i l sin (theta) = 0.37 x 2.2 x 2x 0.5 = 0.814N
A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. The magnitude of the force is
F= 0.814N
What is the magnitude of the force?Generally, the equation for the magnitude of the force is mathematically given as
[tex]F = B i l sin (\theta)[/tex]
Therefore
F= 0.37 x 2.2 x 2x 0.5
F= 0.814N
In conclusion, the magnitude of the force
F= 0.814N
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A spring with a force constant of 5.0 N/m has a relaxed length of 2.59 m. When a mass is attached to the end of the spring and allowed to come to rest, the vertical length of the spring is 3.86 m. Calculate the elastic potential energy stored in the spring. Answer in units of J.
Answer:
Explanation:
Given
Spring force constant [tex]k=5\ N/m[/tex]
Relaxed length [tex]l_0=2.59\ m[/tex]
mass is attached to the end of spring and allowed to come at rest with relaxed length [tex]l_2=3.86\ m[/tex]
Potential energy stored in the spring
[tex]U=\frac{1}{2}k(\Delta x)^2[/tex]
[tex]\Delta x=l_2-l_0[/tex]
[tex]U=\frac{1}{2}\times 5\times (3.86-2.59)^2[/tex]
[tex]U=4.03\ J[/tex]
Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The separated spheres are then connected with a wire then uncouth to retain only negligible charge. (a) What is the ratio V_1/V_2 of the final potentials of the spheres? (b) what fraction of q ends up on sphere? (c) What fraction of q ends up on sphere 2? (d) What is the ratio q_1/q_2 of the surface charge densities of the spheres?
Answer:
Explanation:
capacitance of sphere 2 will be 4.5 times sphere 1
a ) when spheres are in contact they will have same potential finally . So
V_1 / V_2 = 1
b )
Charge will be distributed in the ratio of their capacity
charge on sphere1 = q x 1 / ( 1 + 4.5 )
= q / 5.5
fraction = 1 / 5.5
c ) charge on sphere 2
= q x 4.5 / 5.5
fraction = 4.5 / 5.5
d ) surface charge density of sphere 1
= q /( 5.5 x A ) where A is surface area
surface charge density of sphere 2
= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area
= q /( 5.5 x 4.5 A )
q_1/q_2 = 4.5
while driving his sports car at 20.0 m/s down a four lane highway, eddie comes up behind a slow moving dump truck and decides to pass it in the left hand lane. of eddie can accelerate at 5.00 m/s^2, how long will it take for him to reach a speed of 30.0 m/s
Explanation:
Given:
u = 20 m/s
a = 5 m/s^2
v = 30 m/s
t = ?
Use the first kinematic equation of motion:
v = u + at
t = (v - u)/a = 10/5 = 2 seconds
Eddie will take 2 sec to reach a speed of 30 m/s
What is velocity ?
velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :
[tex]\begin{aligned}v&=\frac{\Delta d}{\Delta t}\end{aligned}[/tex]
Here it is given that :
initial speed of car (u) = 20 m/s
acceleration of car (a) = 5 m/s²
final speed of car (v) = 30 m/s²
it is to find the time t to achieve this speed which is calculated using the first equation of motion:
[tex]\begin{aligned}v&=u+at\\30&=20+5t\\&t=\frac{10}{5}\\&=2\text{\:sec}\end{aligned}[/tex]
Therefore, Eddie will take 2 sec to reach a speed of 30 m/s
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A box contains 9 new light bulbs and 6 used light bulbs. Each light bulb is the same size and shape. Meredith will randomly select 2 light bulbs from the box without replacement. What is the probability Meredith will select a new light bulb and then a used light bulb
Answer:
(9/35) = 0.257
Explanation:
Box contains 9 new light bulbs and 6 used light bulbs, total number of bulbs = 15.
Probability of selecting two bulbs; a new light bulb and then, a used light bulb in that order = [(probability of selecting a new bulb) × (probability of selecting a used bulb from the rest)] = [(9/15) × (6/14)] = (9/35) = 0.257
The probability that Meredith will select a new bulb and then a used bulb in sequential order without replacement is around 26%.
Explanation:The question asks about the probability of selecting a new light bulb and then a used light bulb from a box containing 9 new light bulbs and 6 used light bulbs. Probability events like these are solved using multiplication rules of probability that each event is independent.
First, the probability of picking a new bulb is 9/15 (total bulbs are 15). If you pick one out, you don't replace it, so there are only 14 bulbs left. Thus, the probability of picking a used bulb now is 6/14. Hence the probability of both events happening in order is the multiplication of both, i.e., (9/15)*(6/14) = 54/210 = 0.257 or around 26%.
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