A football player completes a pass 69.4​% of the time. Find the probability that​ (a) the first pass he completes is the second​ pass, (b) the first pass he completes is the first or second​ pass, and​ (c) he does not complete his first two passes.

Answers

Answer 1
Final answer:

The student asked for the calculations of probabilities concerning a football player's passes. The answers are: (a) 21.18%, (b) 90.58%, (c) 8.68%. This involves the use of probability rules and calculations carried out to two decimal places.

Explanation:

The subject of this question is probability, particularly in the context of repeated independent trials. The football player has a 69.4% chance of completing a pass, so we can use this information to answer the questions.

The first pass he completes is the second pass: This means that he fails the first pass and succeeds on the second. Both of these are independent events. So, we multiply the probabilities: (1 - 0.694) * 0.694 = 0.2118 or 21.18%.The first pass he completes is the first or second pass: We've already calculated the probability for the second pass. The probability for the first pass is simply his success rate, 0.694 or 69.4%. To find the probability of either event occurring, we add the two probabilities together: 0.2118 + 0.694 = 0.9058 or 90.58%.He does not complete his first two passes: This means he fails both passes. Since these are independent events, we multiply the probabilities: (1 - 0.694) * (1 - 0.694) = 0.0868 or 8.68%.

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Answer 2

(a) The probability that the first pass he completes is the second pass is [tex]$\frac{3099}{10000}$[/tex].

(b) The probability that the first pass he completes is the first or second pass is [tex]$\frac{3499}{5000}$[/tex].

(c) The probability that he does not complete his first two passes is [tex]$\frac{9826}{2500}$[/tex].

To solve this problem, we will use the given completion rate of 69.4% and convert it into a fraction to make the calculations easier. The completion rate is equivalent to [tex]$\frac{694}{1000}$[/tex] or [tex]$\frac{347}{500}$[/tex].

(a) To find the probability that the first pass he completes is the second pass, we need to consider two events: he must fail the first pass and then succeed on the second pass. The probability of failing the first pass is [tex]$1[/tex] - [tex]\frac{347}{500}$[/tex], and the probability of succeeding on the second pass is [tex]$\frac{347}{500}$[/tex]. Multiplying these two probabilities gives us the desired probability:

[tex]$$ \left(1 - \frac{347}{500}\right) \times \frac{347}{500} = \frac{153}{500} \times \frac{347}{500} = \frac{3099}{25000}. $$[/tex]

Simplifying this fraction by dividing both the numerator and the denominator by 4, we get:

[tex]$$ \frac{3099}{25000} = \frac{77475}{62500} = \frac{3099}{10000}. $$[/tex]

(b) To find the probability that the first pass he completes is the first or second pass, we need to consider the probability of completing the first pass and the probability of failing the first pass but completing the second pass. We add these two probabilities because they are mutually exclusive events. The probability of completing the first pass is [tex]$\frac{347}{500}$[/tex], and the probability of failing the first pass but completing the second pass is the same as calculated in part (a), [tex]$\frac{3099}{10000}$[/tex]. Adding these probabilities gives us:

[tex]$$ \frac{347}{500} + \frac{3099}{10000} = \frac{694}{1000} + \frac{3099}{10000} = \frac{3499}{5000}. $$[/tex]

(c) To find the probability that he does not complete his first two passes, we need to consider the probability of failing both passes. The probability of failing one pass is [tex]$1[/tex]- [tex]\frac{347}{500}$[/tex], so for two consecutive failures, we square this probability:

[tex]$$ \left(1 - \frac{347}{500}\right)^2 = \left(\frac{153}{500}\right)^2 = \frac{23409}{25000}. $$[/tex]

Simplifying this fraction by dividing both the numerator and the denominator by 4, we get:

[tex]$$ \frac{23409}{25000} = \frac{585025}{62500} = \frac{9826}{2500}. $$[/tex]

These calculations provide the probabilities for each of the specified events.


Related Questions

A 76.00 pound flask of mercury costs $162.50. The density of mercury is 13.534g/cm 3.
A. Find the price of one cubic inch of mercury by calculating intermediate values.
B. What is the price of one pound of mercury?
C. What is the price of one gram of mercury?
D. What is the price of one cubic centimeter of mercury?
E. What is the price of one cubic inch of mercury?

Answers

Answer:

a) 1805.55$

b) 2.14$

c)0.005$

d)0.064$

e)1805.55$

Step-by-step explanation:

Density of mercury is 844.9 lb/ft3.

a) 76 pound flask of mercury is 76/844.9=0.09 ft^3. 0.09 ft^3 mercury cost 162.5$, then 1 ft^3 mercury is

[tex]p=(162.5/0.09)=1805.55[/tex]

1805.55$

b) One pound of mercury is 2.14$

[tex]p=162.5/76=2.14[/tex]

c)76 pound equals 34473 grams. It makes:

[tex]p=162.5/34473=0.005[/tex]

0.005$ is the price of one gram mercury.

d)Total amount of mercury is 34473 grams. Then total volume of mercury is:

[tex]V=34473/13.534=2547.14[/tex]

2547.14 cm3. And the unit price is:

[tex]p=162.5/2547.14=0.064[/tex]

e) 1805.55$. It is found already.

Olga purchases a rectangular mirror (the shaded region) that fits exactly inside a frame. The outer perimeter of the frame measures 60 cm by 80 cm. The width of each side of the frame is 10 cm. What is the area of the mirror?

Answers

Answer:

2,400cm^2

Step-by-step explanation:

This is quite an interesting question.

Now, we know the frame measures 60 by 80. We also know that the thickness of the frame is 10cm in length. Hence from the side of the mirror to the other side of the frame is 10cm.

We have the 10cm on each side of the frame. Making a total of 40cm and 20cm each allowance on the length and breadth of the mirror. The length and breadth of the mirror is thus 40cm by 60cm.

The area of a rectangle is L * B

The area of the mirror is 40 * 60 = 2,400cm^2

The fact that the width of each side of the frame is 10 cm means that each side of the mirror is 20 cm smaller than the corresponding side of the frame. Therefore, the mirror measures 40 cm by 60 cm, with an area of 2400.

Jerome solved the equation 1 3 x + 5 6 = 1 as shown. 1. Subtraction property of equality: 1 3 x + 5 6 − 5 6 = 1 1 − 5 6 2. LCD: 1 3 x = 1 6 − 5 6 3. Multiply by the reciprocal: ( 3 1 ) 1 3 x = −4 6 ( 3 1 ) 4. Solve and simplify: x = −12 6 = −2 Analyze Jerome's steps. In which step did he make an error?

Answers

Answer:

In step 2, the LCD was not used correctly to make equivalent fractions.

Step-by-step explanation:

Answer:

In step 2, the LCD was not used correctly to make equivalent fractions.

Step-by-step explanation:

Construct a dotplot for the following data. 4.85 4.94 5.12 5.14 4.80 4.99 5.19 4.94 4.85 5.12 5.04 4.96 5.28 5.05 4.83 5.27 5.12 5.19 4.89 5.15 5.04 5.17 5.24 5.04 4.91 5.26

Answers

Answer:

x             frequency

4.8        1

4.83       1

4.85     2

4.89     1

4.91     1

4.94    2

4.96   1

4.99   1

5.04    3

5.05    1

5.12    3

5.14   1

5.15   1

5.17   1

5.19   2

5.24    1

5.26     1

5.27     1

5.28     1

find the dot plot as attached below

Step-by-step explanation:

Construct a dotplot for the following data. 4.85 4.94 5.12 5.14 4.80 4.99 5.19 4.94 4.85 5.12 5.04 4.96 5.28 5.05 4.83 5.27 5.12 5.19 4.89 5.15 5.04 5.17 5.24 5.04 4.91 5.26

Rearranging the data into frequency table

x             frequency

4.8        1

4.83       1

4.85     2

4.89     1

4.91     1

4.94    2

4.96   1

4.99   1

5.04    3

5.05    1

5.12    3

5.14   1

5.15   1

5.17   1

5.19   2

5.24    1

5.26     1

5.27     1

5.28     1

The following is a histogram showing the distribution per year of the commutative property damage caused by tornadoes, over the period 1950 to 1999, in each of the 50 states and Puerto Rico. The data are in millions of dollars, and the class intervals are 0 to < 10, 10 to < 20, and so forth.

Answers

Final answer:

The histogram depicts the year-by-year damage in millions of dollars caused by tornadoes from 1950 to 1999. It uses class intervals to display the frequency of damage costs, where each bar represents a specific cost range.

Explanation:

In the given question, we discuss a histogram that represents the commutative property damage caused by tornadoes from 1950 to 1999 across the 50 US states and Puerto Rico. The histogram's class intervals are set from 0 to < 10, 10 to < 20, and so forth, and the data are in millions of dollars. A histogram is a type of graphical representation used in statistics to display the distribution of data. Each bar in a histogram represents the tabulated frequency at each interval. In this case, the frequency is the year count in which the commutative property damage caused by tornadoes falls within a specific monetary range.

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The demand d for a companys product cost x is predicted by the function d(x) = 500-2x. The price p in dollars that the company can charge for the product is given by p(x)=x+5

Answers

Final answer:

The student is given two functions, d(x) = 500-2x and p(x) = x+5, which represent the demand and price, respectively, of a company's product. To find the relationship between price and quantity, we can substitute the demand function into the price function.

Explanation:

The subject of this question is Mathematics. The student is given two functions, d(x) = 500-2x and p(x) = x+5, which represent the demand and price, respectively, of a company's product. To find the relationship between price and quantity, we can substitute the demand function into the price function:

p(x) = x + 5 = d(x) + 5 = (500 - 2x) + 5 = 505 - 2x

So the price can be represented by the equation p(x) = 505 - 2x.

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hi :) this lesson is about 30-60-90 triangles.
I need a formula to find the long side. I dont need the actual length if the long side, I just need the equation to find it. help would be much appreciated​.

Answers

Answer:

5 times the square root of 3

Step-by-step explanation:

To get the longest side of a 30-60-90 triangle, you take the shortest side and multiply it by the square root of 3.

5*(square root of 3)

Find x.
- show details and examples to show your answer.

Answers

Sin(25 degrees) * 45 equals x. About 19.1

Answer: 17.3

Step-by-step explanation:

Since it is a right angled triangle , we will use the application of SOHCAHTOA in solving it  ,which means

sine Ф = opposite / hypotenuse

cosine Ф = adjacent / hypotenuse

Tangent Ф = opposite / adjacent

Ф stands for the given angle.

From the diagram , the given angle is 25 ,this means that

opposite = x

hypotenuse = 41

This means that we will use sine Ф = opposite / hypotenuse to find the value of x.

Therefore:

sin 25 = x/41

x = 41 sin 25

x = 41 x 0.4226

x = 17.3273

x ≈ 17.3

James buys a 3 books from the bookstore for $39.99. He has a coupon for 25% off the original price. He is charged 8.5% sales tax. What is the total cost of his purchase?

Answers

Answer:

Step-by-step explanation:

The cost of the three books that James bought from the bookstore.

He has a coupon for 25% off the original price. This means that the amount by which the original price was reduced would be

25/100 × 39.99 = 0.25 × 39.99 = $9.8325

The cost of the books would be

39.99 - 9.8325 = $30.1575

He is charged 8.5% sales tax. This means that the amount paid for tax would be

8.5/100 × 30.1575 = 0.085 × 30.1575 = $2.56

the total cost of his purchase would be

2.56 + 30.1575 = $32.7175

Answer:

$32.7175

Step-by-step explanation:

While our weight is typically displayed without decimal places (e.g., 165 lbs), it can be displayed with great decimal precision. Limited only by the precision we place on it, the variable of weight is ______.

Answers

Answer:

Continuous observation

Step-by-step explanation:

Generally, the weight of any person is displaced in whole numbers without the inclusion of decimal numbers. The decimal numbers are mostly rounded up to the whole number. Based on the argument made in the given problem, the type of weight variable for this type of analysis is known as continuous observation.

HELP! Given a pyramid l = w = 9.0 mm and V = 324.0 cubic mm , find h in mm

Answers

Answer:

The answer to your question is height = 12 mm

Step-by-step explanation:

Data

l = w = 9 mm

V = 324 mm³

h = ?

Formula

V = [tex]\frac{Ab x h}{3}[/tex]

Solve for h

                       3V = Ab h

                       3V / Ab = h    or     h = 3V / Ab

Find the area of the base

Ab = l x w

     = 9 x 9

     = 81 mm²

Substitution

                       h = [tex]\frac{3(324)}{81}[/tex]

Simplification

                       h = [tex]\frac{972}{81}[/tex]

Result

                       h = 12 mm                    

Which of the following represent Exponential Decay? Choose all that apply.

Answers

Answer:

y = (7/8)x

Step-by-step explanation:

Exponential decay is represented when the number used is less than 1. 7/8 is the only choice that is less than 1.

y = (7/8)ˣ is an exponential decay because b = 7/8 < 1.

Exponential function

An exponential decay is in the form:

y = abˣ

where y, x are variables, a is the initial value of y and b is the multiplier which is less than 1.

From the question y = (7/8)ˣ is an exponential decay because b = 7/8 < 1.

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Charlie has two dimes for Nichols and some quarters in his pocket if the probability of drawing a quarter out of his pocket is 1/2 how many quarters does he

Answers

Answer:

He has 2 quarters in his pocket.

Determine whether the underlined number describes a population parameter or a sample statistic. Explain your reasoning. Modifying Sixty minus five with underline of the 97 passengers aboard an airship survived an explosion.

Answers

Answer:

Step-by-step explanation:

Which equation represents the function graphed on the coordinate plane? g(x) = |x + 4| – 2 g(x) = |x – 4| – 2 g(x) = |x – 2| – 4 g(x) = |x – 2| + 4. Which equation represents the function graphed on the coordinate plane?

g(x) = |x + 4| – 2
g(x) = |x – 4| – 2
g(x) = |x – 2| – 4
g(x) = |x – 2| + 4

On a coordinate plane, an absolute value graph has a vertex at (negative 4, negative 2).

Answers

Answer:

[tex]g(x)=|x+4|-2[/tex]

Step-by-step explanation:

All the absolute value functions given in the option are of the form:

[tex]g(x)=|x-h|+k[/tex], where (h,k) is the vertex

From your description the absolute value graph has vertex at (-4,-2)

Hence h=-4 and k=-2.

We substitute to get:

[tex]g(x)=|x--4|+-2[/tex]

We simplify to get:

[tex]g(x)=|x+4|-2[/tex]

Graph f(x)= square root of 9

Answers

Attached is a graph of the function [tex]f(x)=\sqrt{9}[/tex]

To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first three algebra tests. What minimum score does Mary need to make on her fourth test to earn an A in her algebra course?

Answers

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x =  265+x

Average score = (Sum of all scores) ÷ (Number of tests)

[tex]=\dfrac{265+x}{4}[/tex]

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

[tex]\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90[/tex]

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

A bag of baby carrots and a container of hummus dip contain a total of 650 calories. For a snack, Rosarita ate of the bag of carrots and of the container of hummus. Her snack contained a total of 260 calories. If x represents the total number of calories in the bag of carrots and y represents the total number of calories in the container of hummus, what is one of the equations for this scenario? X+y=650 x+y=260

Answers

Answer:

[tex]x + y = 650[/tex]              

Step-by-step explanation:

We are given the following in the question:

Total calories in a bag of carrot and a container of hummus dip = 650

Rosarita's snack:

Some of the bag of carrots and some of the container of hummus.

Total calories in Rosarita's snack = 260

Let x represents the total number of calories in the bag of carrots and y represents the total number of calories in the container of hummus.

Then, we can write the following equation to represent total number of calories in both a bag of carrot and a container of hummus dip:

[tex]x + y = 650[/tex]

Since Rosarita did not eat the whole bag of carrot and the whole container of hummus and also x and y are the total calories in whole bag of carrot and container of hummus respectively.

Answer:

x+y=650

Step-by-step explanation:

its right on edge 8th grade math

The Cinema Center consists of four theaters: Cinemas I, II, III, and IV. The admission price for one feature at the Center is $5 for children, $7 for students, and $9 for adults. The attendance for the Sunday matinee is given by the matrixChildren - Students - AdultsCinema I - 225 - 110 - 70Cinema II - 95 - 160 - 225Cinema III - 280 - 65 - 110Cinema IV - 0 - 240 - 225a. Write a column vector B representing the admission prices.b. Compute AB, the column vector showing the gross receipts for each theater.c. Find the total revenue collected at the Cinema Center for admission that Sunday afternoon.

Answers

Answer:

a) Matrix B = [tex]\left[\begin{array}{c}5\\7\\9\end{array}\right][/tex]

b) Matrix AB = [tex]\left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right][/tex]

c) $12,695

Step-by-step explanation:

Matrix A = [tex]\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right][/tex]

a) Matrix B = [tex]\left[\begin{array}{c}5\\7\\9\end{array}\right][/tex]

Gross Receipt = AB

[tex]\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right][/tex] . [tex]\left[\begin{array}{c}5\\7\\9\end{array}\right][/tex] = [tex]\left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right][/tex]

c) Total revenue is the sum of receipts from 4 cinemas given in part b

Hence,

Total revenue = $2525 + $3620 + $2845 + $3705 = $12,695

Caleb made $105 mowing lawns and walking dogs, charging the rates shown. If he mowed half as many lawns as dogs walked, how many lawns did he now and how many dogs did he walk?

Answers

Question is Incomplete;Complete question is given below;

Caleb made $105 mowing lawns and walking dogs, charging the rates shown. If he mowed half as many lawns as dogs walked, how many lawns did he mow and how many dogs did he walk? $7.50 for walking dogs and $20 for mowing lawns

Answer:

Caleb mowed 3 lawns and walked 10 dogs.

Step-by-step explanation:

Let the number of dogs he walked be 'd'.

Let number of lawn he mowed be 'l'.

Given:

If he mowed half as many lawns as dogs walked

So we can say that;

[tex]l=\frac{1}{2}d=0.5d \ \ \ \ equation\ 1[/tex]

Now given:

Cost for mowing each lawn = $20

Cost for walking each dog = $7.50

Total amount made = $105

Now we can say that;

Total amount made is equal to Cost for mowing each lawn multiplied by number of lawn he mowed and Cost walking each dog multiplied by number of lawn he mowed.

framing in equation form we get;

[tex]20l+7.5d=105 \ \ \ \ \ equation \ 2[/tex]

Substituting equation 1 in equation 2 we get;

[tex]20(0.5d)+7.5d=105[/tex]

Applying distributive property we get;

[tex]10d+7.5d=105\\\\17.5d=105[/tex]

Dividing both side by 17.5 we get;

[tex]\frac{17.5d}{17.5}=\frac{105}{17.5}\\\\d= 6[/tex]

Substituting the value of 'd' in equation 1 we get;

[tex]l=0.5d=0.5\times6=3[/tex]

Hence Caleb mowed 3 lawns and walked 10 dogs.

Figure FGHJ is shown below.
Figure F G H J has 4 sides. Sides F J and G H are congruent and parallel, and sides G F and H J are congruent and parallel. Angles G and J are 130 degrees.

Which names accurately describe figure FGHJ? Select two options.

parallelogram
quadrilateral
rectangle
rhombus
trapezoid

Answers

Answer:

parallelogramquadrilateral

Step-by-step explanation:

The figure has 4 sides, so is a quadrilateral. Opposite sides are parallel, so the figure is a parallelogram.

Angles are not 90°, so the figure is not a rectangle. Sides are not all the same length, so the figure is not a rhombus. Because the figure has two pairs of parallel sides (not just one pair), it is not a trapezoid.

Answer:

a and b on edge

Step-by-step explanation:

The talent show committe sold a total of 530 tickets in advance. Student tickets cost $3 each and the adult tickets cost $5 each. Id the total receipts were $1740, how many of each type of ticket was sold?

Answers

Answer:445 student tickets were sold.

75 adult tickets were sold.

Step-by-step explanation:

Let x represent the number of student tickets that were sold in the talent show.

Let y represent the number of adult tickets that were sold in the talent show.

The talent show committee sold a total of 530 tickets in advance. This means that

x + y = 530

Student tickets cost $3 each and the adult tickets cost $5 each. The total receipts were $1740. This means that

3x + 5y = 1740 - - - - - - - - - - - - 1

Substituting x = 530 - y into equation 1, it becomes

3(530 - y) + 5y = 1740

1590 - 3y + 5y = 1740

- 3y + 5y = 1740 - 1590

2y = 150

y = 150/2 = 75

x = 530 - y = 530 - 75

x = 455

.

Find f(-1) when f(x)=x^2-3x+6

Answers

Answer:

f(-1) = 10

Step-by-step explanation:

f(x)=x² - 3x + 6

when x = -1, substitute x=-1 into the equation above

f(-1) = (-1)² - 3(-1) + 6

= 1 + 3+6

= 10

Two cartons weigh 3x-2 and 2x-3 pounds, respectively. If the average weight of the cartons is 10 pounds, the heavier carton weights how many more pounds than the lighter carton

Answers

Final answer:

By setting up an equation using the average weight formula and solving for x, we find that x equals 5. Subsequently, the heavier carton weighs 13 pounds, and the lighter carton weighs 7 pounds, making the heavier carton weigh 6 pounds more than the lighter carton.

Explanation:

The question involves finding out how many more pounds the heavier carton weighs compared to the lighter carton when given their weights in terms of x and the average weight.

Firstly, we are given that the weights of the two cartons are 3x - 2 and 2x - 3 pounds, and their average weight is 10 pounds.

To find the value of x, we need to set up an equation using the average weight formula, which is:

(Weight of Carton 1 + Weight of Carton 2) / 2 = Average Weight

Substituting the given weights and average weight into the formula, we get:

((3x - 2) + (2x - 3)) / 2 = 10

Solving the equation by combining like terms and multiplying both sides by 2 to eliminate the fraction gives:

5x - 5 = 20

Adding 5 to both sides and then dividing by 5:

x = 5

Now, let's find the actual weight of each carton:

Weight of the first carton = 3x - 2 = 3(5) - 2 = 13 pounds

Weight of the second carton = 2x - 3 = 2(5) - 3 = 7 pounds

Lastly, we determine how many more pounds the heavier carton weighs compared to the lighter one:

13 pounds - 7 pounds = 6 pounds

Therefore, the heavier carton weighs 6 pounds more than the lighter carton.

Mattie is making a collar for her dog. She needs to buy some chain,a clasp, and a name tag. She wants the chain to be 40 centimeters long. One meter of chain costs $9.75. The clasp is $1.29 and the name tag is$3.43. How much will it cost to make a collar?

Answers

Answer:the total cost of the collar is $5.11

Step-by-step explanation:

To make a collar for her dog, she needs to buy some chain,a clasp, and a name tag.

The length of the chain that she wants to buy is 40 centimeters.

1000 centimeters = 1 meter

40 centimeters = 40/1000 = 0.04 meters.

One meter of chain costs $9.75. Therefore, 0.04 meters of chain would cost

0.04 × 9.75 = $0.39

The clasp is $1.29 and the name tag is $3.43. Therefore, the total cost of the collar would be

0.39 + 1.29 + 3.43 = $5.11

At the end of the season, the coach took ten students to burger box.The coach and three students ordered steak-on-a-bun while the other students ordered queen-size burgers. The total bill was $15.15. If a steak-in-a-bun cost $0.90 more than a queen-size burger, find the cost of one of each.

Answers

Answer:

Cost of steak-in-a-bun burger is $1.95 and cost of queen-size burger is $1.05.

Step-by-step explanation:

Let the cost of queen-size burger be 'q'.

Let the cost of steak-in-a-bun be 's'.

Given:

a steak-in-a-bun cost $0.90 more than a queen-size burger.

So we can say that;

[tex]s=0.9+q \ \ \ \ equation\ 1[/tex]

Given:

the coach took ten students to burger box.

Hence Number of person at burger box = 11

The coach and three students ordered steak-on-a-bun while the other students ordered queen-size burgers.

So we can say that;

Number of queen sized burger = 11 - 4 =7

Number of steak on a bun burger = 4

Also Given:

Total bill = $15.11

Now we can say that;

Total bill is equal to sum of Number of queen sized burger multiplied by Cost of queen sized burger and Number of steak on a bun burger multiplied by cost of steak on a bun burger.

framing in equation form we get;

[tex]4s+7q =15.15\ \ \ \ equation\ 2[/tex]

Substituting equation 1 in equation 2 we get;

[tex]4(0.9+q)+7q=15.15[/tex]

Applying distributive property we get;

[tex]3.6+4q+7q=15.15\\\\3.6+11q=15.15[/tex]

Subtracting both side by 3.6 we get;

[tex]3.6+11q-3.6 =15.15-3.6\\\\11q=11.55[/tex]

Dividing both side by 11 we get;

[tex]\frac{11q}{11}=\frac{11.55}{11}\\\\q=\$1.05[/tex]

Substituting the value of q in equation 1 we get;

[tex]s=0.9+q=0.9+1.05=\$1.95[/tex]

Hence Cost of steak-in-a-bun burger is $1.95 and cost of queen-size burger is $1.05.

Final answer:

The cost of one steak-on-a-bun is $2.055, and the cost of one queen-size burger is $1.155.

Explanation:

The student's question involves finding the cost of one steak-on-a-bun and one queen-size burger given that the total bill for a group order at a restaurant was $15.15 and that a steak-on-a-bun costs $0.90 more than a queen-size burger.

Let's define Q as the price of a queen-size burger.

Therefore, the price of a steak-on-a-bun would be Q + $0.90. According to the problem, four people (the coach and three students) ordered steak-on-a-bun, and six students ordered queen-size burgers.

The equation representing the total cost is:

4(Q + $0.90) + 6Q = $15.15

Solving for Q, we first expand the equation:

4Q + $3.60 + 6Q = $15.15

Combining like terms, we get 10Q + $3.60 = $15.15.

Subtracting $3.60 from both sides, we get 10Q = $11.55.

Dividing both sides by 10, we find that Q = $1.155, which is the cost of a queen-size burger.

Finally, the cost of a steak-on-a-bun is Q + $0.90 = $1.155 + $0.90 = $2.055.

The cost of one steak-on-a-bun is $2.055, and the cost of one queen-size burger is $1.155.

The student council memebers are making decorative labels to cover 20 identical empty coffee cans for charity drive. Each label will cover the entire lateral surface area of a can. Which is the closest to the lateral surface coffee can

Answers

Answer:

127.48 in²

Explanation:

The image attached shows the dimensions of the coffe cans considered for this question.

The figure is a cylinder with dimensions:

[tex]\text {radius }3\frac{1}{16}\text {inches and height }6\frac{5}{8}\text {inches}[/tex]

Thus, to find the lateral surface of a coffe can, you use the formula for the lateral area of a cylinder:

[tex]LA=2\pi\times r\times h[/tex]

Where, LA is the lateral area, r is the radius, and h is the height.

Substituting the dimensions given in the figure, you get:

[tex]LA=2\pi\times 3\frac{1}{16}\times 6\frac{5}{8}[/tex]

To multiply, first convert the mixed numbers into improper fractions:

[tex]3\frac{1}{16}=3+\frac{1}{16}=\frac{3(16)+1}{16}=\frac{48+1}{16}=\frac{49}{16}\\ \\ 6\frac{5}{8}=6+\frac{5}{8}=\frac{6(8)+5}{8}=\frac{48+5}{8}=\frac{53}{8}[/tex]

Now, you can multiply:

[tex]LA=2\pi\times \frac{49}{16}\times \frac{53}{8}[/tex]

[tex]LA=127.48in^2[/tex]

Match the units with the rotational quantity angular displacement angular velocity angular acceleration tangential acceleration tangential velocity radius a. meters per second b. meters per second-squared c. radians per second-squared d. radians e. radians per second f. meters.

Answers

Answer:

Below.

Step-by-step explanation:

a  = tangential velocity

b  = tangential acceleration

c  = Angular acceleration

d  = angular displacement

e  =  Angular velocity

f   =   radius.

600 units of electricity and 100 units of gas were used for a total cost of $388. Next month, 400 units of electricity and 150 units of gas were used for a total cost of $277. Find the cost per unit of gas.

Answers

Answer:

Cost per Electricity Unit= $0.61

Cost per Gas Unit= $0.22

Step-by-step explanation:

Suppose,

Cost per Electricity Unit: e

Cost per Gas Unit: g

for the first month condition, equation would be

[tex]600*e+100*g=388...........................................(i)[/tex]

and for the next month condition, equation would be like

[tex]400*e+150*g=277...........................................(ii)[/tex]

By solving both linear equations simultaneously, we get

e=0.61    and     g=0.22

A study of voting chose 663 registered voters at random shortly after an election. Of these, 72% said they had voted in the election. Election records show that only 56% of registered voters voted in the election.
Which of the following statements is true about the percentages?
a. 72% is a sample; 56% is a population.
b. 72% and 56% are both statistics.
c. 72% is a statistic and 56% is a parameter.
d. 72% is a parameter and 56% is a statistic.
e. 72% and 56% are both parameters.

Answers

Answer: c. 72% is a statistic and 56% is a parameter.

Step-by-step explanation:

A population is a large group of all possible observations required for a study by the researcher's point of view.A Sample is a finite subset of population that is used by researcher to represent the entire population in an analysis.A parameter is a number that measure a characteristic for the entire population.A statistic is a number that measure a characteristic for the sample.A statistics given an estimate to the population parameter.

Given : A study of voting chose 663 registered voters at random shortly after an election.

Population of interest : "registered voters"

Sample : " 663 registered voters "

72%  of 663 registered voters said they had voted in the election.

⇒ Statistic = sample proportion registered voters voted in the election.= 72%

Election records show that only 56% of registered voters voted in the election.

⇒ Parameter = Population proportion of registered voters voted in the election =  56%

Hence, the correct answer is "c. 72% is a statistic and 56% is a parameter."

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