A car travels around a racetrack at aconstant speed. During what parts of the coursedoes the car experience acceleration?

Answers

Answer 1
At any part where it is moving in a circle or even part of a circle (centripetal acceleration) 
Answer 2

Answer:

If the racetrack’s length is 36 inches and is set to a height of 8 inches, 16 inches and 24 inches and each roll of the toy car is 7.8 seconds, 7.3 seconds and 6.6 seconds respectively, then, it only shows that the higher the racetrack, the faster the toy car will roll down because velocity, which measures how fast something is moving, is affected by gravity. Motion, as shown in this kind of scenario, is a kind of concept that depicts movement or change in position under given circumstances or factors over a period of time.

Explanation:


Related Questions

In which phase transition do molecules directly move from state to state involving a vibration of particles in a fixed position to a state involving random movement of high speed particles
Evaporation
Sublimation
Freezing
Depostion

Answers

sublimation is the correct answer

Inside a NASA test vehicle, a 3.50kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. The force constant of the spring is 229 N/m. The vehicle has a steady acceleration of 5.00m/s^2, and the ball is not oscillating. Suddenly, when the vehicle's speed has reached 45.0m/s, its engines turn off, thus eliminating its acceleration but not its velocity. What is the frequency? ...?

Answers

Final answer:

The frequency of the spring in the NASA test vehicle is approximately 2.28 Hz.

Explanation:

To determine the frequency of the spring in the NASA test vehicle, we need to use the equation for the frequency of a mass-spring system:



f = 1 / (2π) * sqrt(k / m)



Where f is the frequency, k is the force constant of the spring, and m is the mass of the ball.



Plugging in the given values, we get:



f = 1 / (2π) * sqrt(229 N/m / 3.50 kg)



Calculating this, we find that the frequency is approximately 2.28 Hz.

What environmental factors affect kinetic energy and diffusion?

Answers

1) Temperature (High temperature  increase the kinetic energy of a substance, speeding diffusion rates)

2) Particle size (Larger particles require more kinetic energy to move, causing lower rates of diffusion)

3) Concentration 

Hope this helps!

A gas is at 5 Kelvin and 1 m3. The temperature is raised to 10 Kelvin. What is the new volume?

2 m3
2 m
5 m

Answers

I think that this answer is 2m!!!!!!!!!!!!!!

Answer:

The new volume of the gas is 2 m³

Explanation:

It is given that,

Initial temperature, [tex]T_1=5\ K[/tex]

Initial volume, [tex]V_1=1\ m^3[/tex]            

Final temperature, [tex]T_2=10\ K[/tex]

We need to find the new volume. The Charles law gives the relation between the temperature and the volume of the gas.    

i.e

[tex]V\propto T[/tex]

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]V_2=\dfrac{V_1}{T_1}\times T_2[/tex]

[tex]V_2=\dfrac{1}{5}\times 10[/tex]

[tex]V_2=2\ m^3[/tex]

So, the new volume of the gas is 2 m³. Hence, this is the required solution.

what is the best definition of the term due process of law?

Answers

fair treatment through the normal judicial system, especially as a citizen's entitlement

Due process of law is a legal concept that mandates the fair and equal application of the law, ensuring that no individual is deprived of life, liberty, or property without proper legal procedures and protections, as stated in the Fifth and Fourteenth Amendments of the U.S. Constitution.

The best definition of the term due process of law is a legal principle that ensures the government respects all legal rights owed to a person. According to the Fifth and Fourteenth Amendments of the U.S. Constitution, no one shall be "deprived of life, liberty, or property without due process of law." This includes two aspects: procedural due process, which pertains to the methods and processes the government must follow, and substantive due process, which relates to the government's obligations to treat individuals fairly and not to violate certain fundamental rights.

How can matter be exchanged between spheres

Answers

Spheres are open systems. Matter and energy are constantly exchanged between the spheres via chemical reactions, radioactive decay, radiation (light&heat), growth and decay of organisms. 

ingrid kicks a football with an initial velocity at 12 m/s at an angle of 45 relative to the ground

Answers

Equation of movement is

y(x) = x * tg (a)  -    [tex] \frac{g}{2 * u^{2} * cos (a)^{2} } * x^{2} [/tex]

where y is y-coordinate, x - x coordinate,  u - your initial speed, a = angle above horizon.

differentiate it to get dy/dx (speed)
 

The question involves analyzing the motion of a football being kicked with given initial velocity and angle in Physics.

Physics: The question involves analyzing the motion of a football being kicked with given initial velocity and angle.

Example: Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45 degrees relative to the ground.

Concepts: Projectile motion, velocity, angle, and distance traveled are essential in solving such problems in physics.

A 14,700 N car is traveling at 25 m/s. The brakes are applied suddenly, and the car slides to a stop. The average braking force between the tires and the road is 7100 N. How far will the car slide once the brakes are applied? ...?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

vo = 25 m/sec 
vf = 0 m/sec 
Fμ = 7100 N (Force due to friction) 
Fg = 14700 N 
With the force due to gravity, you can find the mass of the car: 
F = ma 
14700 N = m (9.8 m/sec²) 
m = 1500 kg 
Now, we can use the equation again to find the deacceleration due to friction: 
F = ma 
7100 N = (1500 kg) a 
a = 4.73333333333 m/sec² 
And now, we can use a velocity formula to find the distance traveled: 
vf² = vo² + 2a∆d 
0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d 
0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d 
-625 m²/sec² = (-9.466666666667 m/sec²) ∆d 
∆d = 66.0211267605634 m 
∆d = 66.02 m

From the calculations and the data supplied, the braking distance is 65 m

What is the braking force?

The braking force is the force that is applied as the object comes to rest.

We know that the mass of the car is obtained from; 14,700 N/10 m/s^2 = 1470 Kg

Now;

a = F/m = 7100 N/1470 Kg

a = 4.8 m/s^2

Given that;

v^2 = u^2 - 2as

u^2 = 2as

s =  u^2/2a

s = (25)^2/2 * 4.8

s = 625/9.6

s = 65 m

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A Styrofoam slab has thickness h and density ρs. When a swimmer of mass m is resting on it, the slab floats in fresh water with its top at the same level as the water surface. Find the area of the slab. (Use any variable or symbol stated above along with the following as necessary: ρw for the density of water.)

Answers

 A = area of styrofoam 
M = mass of stryofoam = A*h*rho_s 
m = mass of swimmer 

Total mass = m + M = m + A*h*rho_s 
Downward force = g*(total mass) = g*[m + A*h*rho_s] 

The slab is completely submerged. 
Buoyant force = g*(mass of water displaced) = g*[A*h*rho_w] 

Equate these 
g*[m + A*h*rho_s] = g*[A*h*rho_w] 
m + A*h*rho_s = A*h*rho_w 
A*h*[rho_w - rho_s] = m 
A = m/[h*(rho_w - rho_s)]

This question involves the concepts of the bouyant force, weight, and volume.

The area of the slab is "[tex]\frac{m}{h(\rho_w-\rho_s)}[/tex]".

In order for the styrofoam slab to float on the water, the buoyant force acting on it must be equal to its weight:

[tex]Weight = Buoyant\ Force\\(m+M)g=\rho_w Vg\\m+M=\rho_w V[/tex]

where,

m = mass of swimmer

A = area of styrofoam slab = ?

h = thickness of strrofoam slab

[tex]\rho_s[/tex] = density of styrofoam slab

[tex]\rho_w[/tex] = density of water

M = mass of styrofoam slab = [tex]Ah\rho_s[/tex]

V = volume of styrofoam slab = Ah

Therefore,

[tex]m+(Ah\rho_s) = Ah\rho_w\\m= Ah(\rho_w-\rho_s)\\\\A=\frac{m}{h(\rho_w-\rho_s)}[/tex]

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Which statement about dwarf planets is true?
a. pluto was the first dwarf planet to be discovered.
b. all dwarf planets likely contain a mixture of rock and ice.
c. dwarf planets lie beyond the outer planets

Answers

Answer:

All dwarf planets likely contain a mixture of rock and ice

Explanation:

The true statement about dwarf planets is that Pluto was the first to be discovered. Dwarf planets share common features like orbiting the sun and having a near-spherical shape but have not cleared their orbits of other objects.

The true statement about dwarf planets is that Pluto was the first dwarf planet to be discovered. Dwarf planets are celestial bodies that meet two of the three criteria set by the International Astronomical Union (IAU) for being a planet: they orbit the sun and have sufficient mass for a nearly spherical shape, but they have not cleared their orbits of other objects. While not all dwarf planets are beyond the outer planets (Ceres, for example, is located in the asteroid belt between Mars and Jupiter), all discovered dwarf planets have a mixture of rock and ice, and with the exception of Ceres, they are found beyond Neptune. Pluto, which was initially classified as one of the major planets, became known as a dwarf planet due to the redefinition of what constitutes a planet in 2006.

When compared to others, how is a greater velocity represented on a motion map?

with shorter vectors
with longer vectors
with larger dots
with smaller dots

Answers

motion map has the points spaced farther apart (because the car would go a further distance in each second), and the velocity vectors (arrows) are longer, because the car is moving faster. So 'with longer vectors' is the correct answer

Answer:

with longer vectors

Explanation:

In any motion map of vectors we know that length of vectors is used to represent the magnitude

while the direction of the vector is represented by the angle made by the vector.

So here we have to represent the larger or greater velocity

This represents the magnitude of the vector to be more

so the correct answer would be

"with Longer vectors" we can show or represent velocity vector of greater velocity.

A substance that is made up of only one kind of atom is a(an)

Answers

I guess the answer is element

A substance that is made up of only one kind of atom is called an element.

Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical or physical means. Each element is unique and consists entirely of one type of atom. For example, hydrogen, calcium, and iron are all elements, as they are each made up of only one type of atom.

The Periodic Table of the Elements lists all known elements, providing information about their atomic structure and properties. Many substances in the world are made up of combinations of different elements.

When a person jumps from tree to ground, what happens to the momentum of the person upon striking the ground? ...?

Answers

When a person jumps from a tree to ground, what happens to the momentum of the person upon striking the ground is that it is transferred to earth. The momentum is not lost, it is conserved by being transferred to the ground. But it can also be lost to the impulse. 
Final answer:

Upon striking the ground, the person's momentum goes to zero as they stop, with the momentum transferred to the Earth. Bending the knees upon landing extends the stopping distance, reducing the force experienced.

Explanation:

When a person jumps from a tree to the ground, the momentum of the person upon striking the ground changes drastically. Momentum is a product of the mass of an object and its velocity. In this case, the person carries momentum as they fall, due to their velocity and mass. Upon impact with the ground, this momentum is quickly reduced to zero because the person comes to a stop. According to the law of conservation of momentum, the momentum lost by the person is transferred to the Earth.

However, because the Earth's mass is so immense compared to that of the person, the change in the Earth's velocity is negligible and unobservable. If the person lands with stiff knees, a large force is experienced over a shorter stopping distance, while bending the knees extends the stopping distance, resulting in a smaller force felt by the person.

A cream tangerine is thrown directly upward past three evenly spaced windows of equal heights. Rank the windows according to (a) the average speed of the cream tangerine while passing them, (b) the time the cream tangerine takes to pass them, (c) the magnitude of the acceleration of the cream tangerine while passing them, and (d) the change in velocity in the speed of the cream tangerine during the passage, greatest first. I just need help with C.

Answers

Final answer:

The magnitude of the acceleration of the cream tangerine as it passes by each window is constant at approximately 9.8 m/s² due to Earth's gravity.

Explanation:

You asked about the magnitude of the acceleration of a cream tangerine as it passes by three evenly spaced windows. When any object is thrown upward or downward close to the Earth's surface, it is accelerated by gravity. This acceleration is constant and has a magnitude of approximately 9.8 m/s² downward. This means that no matter which window the cream tangerine is passing, the magnitude of its acceleration will be the same because gravity is a constant force close to the surface of the Earth. Therefore, when ranking the windows according to the magnitude of acceleration of the cream tangerine while passing them, they will all be the same and thus tied for first place.

The number of revolutions of two pulleys is inversely proportional to their diameters. If a 24-inch diameter pulley making 400 revolutions per minute is belted to an 8-inch diameter pulley, find the number of revolutions per minute of the smaller pulley.
133 1/3
800
1,200 ...?

Answers

The correct answer is 1200.
Answer;

1200

Explanation;Since diameter (d) is inversely proportional to the revolutions (n) are

Then; dn=k  

We can use the relationship to find the unknown, k:  

k = dn  

k = (24)(400) = 9600  

Then use k to find the unknown n:  

k= dn  

9600 = 8n  

n = 1200  

= 200 rpm


A hot air balloon is traveling vertically upward at a constant speed of 2.8 m/s. When
it is 29 m above the ground, a package is
released from the balloon.
After it is released, for how long is the
package in the air? The acceleration of gravity
is 9.8 m/s^2.
Answer in units of s


What is its speed just before impact with the
ground?
Answer in units of m/s

Answers

why is your formula x=? if i'm reading it right the formula is the height of the object at time t. That being the case, set your setup (which looks right) equal to 0 and solve for t. This will tell you how long it takes to hit the ground. Plug this value of t into the forumla -9.8t+2.8 and that will tell you the speed at time t.
We can use the equation of motion: 
2as = v² - u²; where s = 29 m, a = 9.8 m/s², u = -2.8 m/s
v = √(2 x 29 x 9.8 + 2.8²)
v = 24. 0 m/s 

If a galaxy is located 200 million light years from Earth, what can you conclude about the light from that galaxy?

A. The light will take 200 million years to reach Earth.

B.The light will travel 200 million kilometers per second to reach Earth.

C.The light will travel a total of 300,000 kilometers to reach Earth.

D.The light will travel a total of 200 million kilometers to reach Earth.

Answers

The answer is not D.  Just got it incorrect on my quiz.


Answer:

A.  The light will take 200 million years to reach Earth.

Explanation:

In one scene in the movie The Godfather II, a solid gold phone is passed around a large table for everyone to see. Suppose the volume of gold in the phone were equal to the volume of a 10-centimeter cube of gold. The density of gold is 19,300 kg/m3.
Could such a phone be casually passed around a table from hand to hand? What is the weight of the phone? 1 kg of mass is about 2.2 lb.

1. Yes; it weighs about 9 lbs.
2. No; it weighs about 90 lbs.
3. No; it weighs about 45 lbs.
4. Yes; it weighs about 4.5 lbs. ...?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

the weight of the phone? 1 kg of mass is about 2.2 lb. is no. 3 which is "No; it weighs about 45 lbs."

Final answer:

Given the density of gold and the dimensions of a 10-centimeter cube, a solid gold phone would weigh about 45 lbs, making it too heavy to casually pass around a table. Therefore, the correct answer is 3.

Explanation:

The question asks if a solid gold phone, with a volume equal to a 10-centimeter cube of gold, could be casually passed around a table from hand to hand. Given the density of gold is 19,300 kg/m³, we first calculate the volume of the cube in cubic meters (m³) by converting its dimensions from centimeters to meters (0.1 m x 0.1 m x 0.1 m = 0.001 m³). Multiplying this volume by the density of gold gives us the mass of the gold phone (0.001 m³ x 19,300 kg/m³ = 19.3 kg). Converting this mass into pounds (1 kg ≈ 2.2 lbs), the weight of the phone is approximately 42.46 lbs.

Therefore, the correct answer is 3: No; it weighs about 45 lbs. Such a phone would be quite heavy and not easily passed around from hand to hand.

What particles are added together to get the atomic mass?

Answers

neutrons and protons

 hope this helps you
Neutrons & Protons. 

It is because, Atomic mass = Number of proton + Number of neutrons.

pls.. help me with this i really need it.. pls. A gas in a cylinder expands from a volume of 0.110 m3 to 0.320 m3. Heat flows into the gas just rapidly enough to keep the pressure constant at 1.65 x 105 Pa during the expansion. The total heat added is 1.15 x 105 J. (a) Find the work done by the gas. (b) Find the change in internal energy of the gas. (c) Does it matter whether the gas is ideal? Why or why not?

Answers

 a)

At constant pressure, the work done for gas to expand is given by:

W = PΔV

⇒W = 1.65 × 10⁵Pa × (0.320 - 0.110)m³= 3.46 × 10⁴J

b)

The total heat (Q) added to the system is used in work done and the remaining energy goes into internal energy.

ΔU = ΔQ-ΔW

⇒ΔU = 1.15 ×10⁵J - 3.46 × 10⁴J = 0.8 × 10⁵ J

c)

It does not matter that the gas is ideal or real because the work done would remain same. It would vary for real gases only at very high pressure.

(a). The work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex].

(b). The change in the internal energy of the gas is [tex]\boxed{8.03 \times {{10}^4}\,{\text{J}}}[/tex].

(c). There is no effect of the gas being ideal gas or real gas on the work done by the gas.

Further Explanation:

Given:

The initial volume of the gas is [tex]0.110\,{{\text{m}}^{\text{3}}}[/tex] .

The final volume of the gas is [tex]0.320\,{{\text{m}}^{\text{3}}}[/tex] .

The constant pressure at which the expansion of the gas takes place is [tex]1.65 \times {10^5}\,{\text{Pa}}[/tex] .

The amount of heat added to the gas is [tex]1.15 \times {10^5}\,{\text{J}}[/tex].

Concept:

Part (a):

The expansion of the gas is taking place at constant pressure. Therefore, the work done by the gas is:

[tex]W = P\left( {{V_f} - {V_i}}\right)[/tex]

Here, [tex]P[/tex] is the pressure and [tex]{V_f}[/tex] is the final volume and [tex]{V_i}[/tex] is the initial volume of the gas.

Substitute the values of [tex]P[/tex] , [tex]{V_i}[/tex] and [tex]{V_f}[/tex] in above expression .

[tex]\begin{aligned}W&= \left( {1.65 \times {{10}^5}} \right) \times \left( {0.320 - 0.110} \right)\\&= 3.465 \times {10^4}\,{\text{J}}\\&\approx 3.{\text{47}} \times {\text{1}}{{\text{0}}^4}\,{\text{J}}\\\end{aligned}[/tex]

Therefore, the work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex]

Part (b):

The change in internal energy of the gas is given by the first law of thermodynamics:

[tex]\begin{aligned}\Delta Q = \Delta U + W \hfill\\\Delta U = \Delta Q - W \hfill\\\end{aligned}[/tex]

Here, [tex]\Delta Q[/tex] is the heat added, [tex]\Delta U[/tex] is the change in internal energy of system and  [tex]W[/tex] is the work done by the gas.

Substitute the values of [tex]\Delta Q[/tex] and [tex]W[/tex] in above equation.

Part (c):

The ideal gas or the real gas does not affect the process of the expansion of gas because the change in energy of the gas is given by the First law of thermodynamics. The first law of thermodynamics is based on the conservation of energy.

The energy of a system will always remain conserved whether it has the real gas or the ideal gas.

Thus, there is no effect of the gas being ideal gas or real gas on the work done by the gas.

Learn More:

1. In the calorimetry experiment which energy will be calculated during the heat exchange https://brainly.com/question/2566525

2. According to Charles’ law, for a fixed quantity of gas at constant pressure, https://brainly.com/question/7316997

3.What is the kinetic energy of the emitted electrons when cesiumhttps://brainly.com/question/9059731

Answer Details:

Grade: High School

Subject: Physics

Chapter: Law of Thermodynamics

Keywords:  Ideal gas, cylinder, first law of thermodynamics, pressure constant, 0.110m^3 to 0.320 m^3, expansion, change in internal energy, work done by gas.

What is the function of the commutator in a DC motor?

Answers

a torque on a DC motor from reversing every time the coil moves through the plane perpendicular to the magnetic field, a split-ring device called a commutator is used to reverse the current at that point.

Answer:

c for plato users

Explanation:

The answer is c, to change alternating current into direct current.

Please mark me as brainliest :)

Which of the following is not an example of kinetic energy?

mechanical energy
nuclear energy
electrical energy
thermal energy

Answers

Only first is kinetic.
So 2-3-4 are not

Final answer:

Nuclear energy is not an example of kinetic energy; it is a form of potential energy stored within the nucleus of atoms. Kinetic energy is associated with the motion of objects, while nuclear energy involves the potential stored and released during nuclear reactions.

Explanation:

Kinetic energy is the energy that an object possesses due to its motion. It can be expressed mathematically as KE = ½mv², where 'm' is the object's mass and 'v' is its velocity. Examples of kinetic energy include a moving vehicle, a spinning turbine, and the thermal energy of atoms and molecules moving within a substance. However, not all forms of energy listed are examples of kinetic energy.

Nuclear energy is different from kinetic energy. It is a form of potential energy that is stored within the nucleus of atoms and is released during nuclear reactions such as fission or fusion. Therefore, nuclear energy is the correct answer to the question, as it is not a form of kinetic energy.

Other forms of energy such as electrical energy and chemical energy can involve kinetic energy when charges travel through a conductor or when molecular bonds are broken and rearranged, respectively. However, at a fundamental level, these forms also incorporate potential energy components.

What are 3 examples of elastic collisions?

Answers

Final answer:

Elastic collisions, where kinetic energy and momentum are conserved, can be demonstrated through the collision of glass marbles, steel blocks on ice, and carts with spring bumpers on an air track. These examples showcase momentum transfer and energy conservation in a nearly perfect manner, providing insight into the principles of physics.

Explanation:Examples of Elastic Collisions

Elastic collisions are fascinating phenomena where total kinetic energy and momentum are conserved. Here are three examples:

Glass Marbles Collision: Two glass marbles suspended from the ceiling and colliding with each other nearly perfectly conserve kinetic energy and momentum. This setup provides a clear demonstration of how momentum is transferred from one object to another in an elastic collision.Steel Blocks on Ice: Two steel blocks sliding and colliding on ice represent another nearly perfect example of an elastic collision. Thanks to the reduced friction on icy surfaces, the blocks come very close to conserving kinetic energy fully.Carts with Spring Bumpers on an Air Track: This example involves two carts equipped with spring bumpers colliding on an air track. The air track’s nearly frictionless surface allows for a close approximation of an elastic collision, where kinetic energy is largely conserved.

Although truly elastic collisions are rare in everyday experiences and more common in the microscopic realm of subatomic particles, these examples provide a good understanding of the concept within observable scenarios.

If you lift a 200 newton box 1 meter with a rope and is the system and you apply 20 newtons to lift this box, what to mechanical advantage of the system? How far do you have pull the rope when you are applying the input force? If you do this work in 5 seconds, what is the power?

Answers

The mechanical advantage of the system is 0.1.

When you are applying the input force, rope is pulled by 10m.

The power is 40 Watt.

What is mechanical advantage?

Mechanical advantage is the ratio of power output to the power input.

M.A= 20 N / 200 N

M.A = 0.1

Thus, the mechanical advantage is 0.1.

The length of rope pulled = 1m / M.A

= 1/0.1

= 10m

Thus, when you are applying the input force, rope is pulled by 10m.

Work done by the force = force * distance traveled

W = 200N * 1m = 200 J

Power = Work done /time

P = 200 J/5s

P = 40 Watt

Thus, the power is 40 Watt.

Learn more about Mechanical advantage.

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Final answer:

To lift a 200N box 1 meter with a MA of 10, you must pull the rope 10 meters. The mechanical advantage is calculated by dividing the output force by the input force. The power required to lift the box in 5 seconds is 40 Watts.

Explanation:

To calculate the mechanical advantage (MA) of the system, we divide the output force by the input force. In this case, the output force is 200 newtons, and the input force is 20 newtons. Therefore, the MA of the system is 200N / 20N = 10.

To find out how far you must pull the rope, we use the concept that work input equals work output, assuming negligible losses due to friction or inefficiency. Because the MA is 10, and to lift the load 1 meter, you have to pull the rope 10 meters. The distance you have to pull the rope is directly proportional to the MA when lifting a load using a pulley system.

The power of the system can be calculated by dividing the work done by the time taken. Work done is force times distance (Output force * height lifted = 200N * 1m = 200 Joules) and the time taken is 5 seconds. Power = Work/Time = 200J/5s = 40 Watts.

Which of the following is evidence of Earth's age provided by fossils?

Fossils are found only in sedimentary rock.
Fossils range from simple to complex across rock layers.
Fossils formed gradually over time.
Fossils are found in rock above water.

Answers

I think the answer is Fossils formed gradually over time.

Answer: Fossils range from simple to complex across rock layers.

Explanation:

The finding of the fossils in the different layers of the earth crust suggests that the evolution of the living organisms from simple primitive one to the most complex organisms. The examination and determination of the morphological, anatomical and molecular features of the organisms in the fossils have helped in determining the chronological age and has also been helped in determination of the age of earth with respect to the fossils.

The force of attraction between two objects, which is related to the object's mass is the definition of

Answers

This would be the definition of gravitational force, I believe. The force of attraction between 2 objects based on the mass of the objects.

Answer:

Explanation:

The gravitation force of attraction between the two bodies is directly proportional tp the product of masses of two bodies and inversely proportional to the square of distance between them.

The range of all electromagnetic radiation is known as the
HR diagram
Electromagnetic spectrum
sources of light chart
radio wave graph

Answers

B.) The range of all electromagnetic radiation is known as the "Electromagnetic Spectrum"

Hope this helps!

two trains start from towns 240 mi apart and travel towards each other on parallel tracks. they pass each other 1.6 hr later. If one train travels 10 mph faster than the other, find the speed of each train ...?

Answers

Let the speed of one train be s.
Speed of second train is s + 10
The speeds will add since they are traveling towards one another.
Distance = speed x time
speed = distance / time
s + s + 10 = (240/1.6)
s = 70 mph
Speed of first train is 70 mph
Speed of second train is 80 mph

"A copper wire loop is constructed so that its radius, r, can change. It is held near a solenoid that has a constant current through it.
a. Suppose that the radius of the loop were increasing. Use Lenz' law to explain why there would be an induced current through the wire. Indicate the direction of that current.

b. Check your answer regarding the direction of the induced current by considering the magnetic force that is exerted on the charge in the wire of the loop. "

"A copper wire loop is constructed so that its radius, r, can change. It is held near a solenoid that has a constant current through it.
a. Suppose that the radius of the loop were increasing. Use Lenz' law to explain why there would be an induced current through the wire. Indicate the direction of that current.

b. Check your answer regarding the direction of the induced current by considering the magnetic force that is exerted on the charge in the wire of the loop. "

Answers

Below are the answers:

a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page atthe bottom

V=-Δφ/ Δt = -B·ΔA/ Δt

b. As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radiallyoutward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law

F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvBˆ

Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because theforce is pointing into the center of the loop, we know we have positive current at that point (into the page).
Final answer:

According to Lenz's law, an induced current is generated in a copper wire loop when its radius near a solenoid increases. The direction of this induced current opposes the increasing radius of the loop. This direction can also be determined by considering the magnetic force on the charges in the wire loop.

Explanation:

a. According to Lenz's law, when the radius of the copper wire loop near the solenoid increases, an induced current is generated in the loop. This induced current flows in a direction that creates a magnetic field opposing the change in magnetic flux through the loop. Therefore, the direction of the induced current would be such that it opposes the increasing radius of the loop.

b. To check the direction of the induced current, we can consider the magnetic force on the charges in the wire loop. As the radius of the loop increases, the magnetic field due to the solenoid through the loop also increases. By applying the right-hand rule for the direction of the magnetic force on a moving charge, we find that the induced current in the loop would flow in a direction opposite to the increasing radius, in order to resist the change in magnetic field.

Learn more about Lenz's law and induced current here:

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a 1250 kg car accelerates from rest to 6.13m/s over a distance of 8.58m calculate the average force of traction

Answers

Final answer:

To find the average force of traction for the car, you can use the work-energy principle to determine the work done, which equals the change in kinetic energy. The work done is equal to the force multiplied by the distance, and from this, the average force can be calculated. The average force of traction in this case is 2723.17 N.

Explanation:

To calculate the average force of traction for a 1250 kg car that accelerates from rest to 6.13 m/s over a distance of 8.58 m, we can use the work-energy principle. This principle states that the work done by a force on an object is equal to the change in kinetic energy of the object.

First, let's find the final kinetic energy (KE) of the car:

KE = 0.5 * m * v^2

KE = 0.5 * 1250 kg * (6.13 m/s)^2

KE = 23369.8125 J (joules)

The work done (W) by the traction force is also the change in kinetic energy, so W = KE = 23369.8125 J. Since work is defined as the force multiplied by the distance (W = F * d), we can rearrange the formula to solve for the average force (F):

F = W / d

F = 23369.8125 J / 8.58 m

F = 2723.17 N (newtons)

Therefore, the average force of traction that the car experienced was 2723.17 N.

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