A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens to the box?

Answers

Answer 1
The resultant force is 5N.So the box moves to right with constant acceleration.
Answer 2

Answer: The box will displace towards right side.

Explanation:

In the given problem, a 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. The net force acting on the force is 5 N.

The magnitude of the force acting on the box from the left side is more than the force acting on the box from the right side. The body will displace in that direction in which the magnitude of the applied force is more.

The box is displaced to right by a net force of 5 N.

Therefore, the box will displace towards right side.


Related Questions

explain how does air resistance affect acceleration and speed of an object?

Answers

I don't know the correct vocabulary but...The air depending on the variables of the speed of the object and the variables of wind speed, and what the object is, can affect the speed by slowing it down or speeding it up.

Need to ask more specific question for a more specific answer.

Hope this helps.
Air resistance acts as a friction force which limits the acceleration of an object travelling through the air. Regardless of whether this acceleration is negative (an object falling due to gravity) or positive (a projectile launched upward), air resistance will act as a dragging force on this acceleration, making it a smaller number than it would otherwise be. For this reason, when calculating ballistics problems, we usually neglect air resistance to keep the problem more simple. 

A 5.0 kg rock is dropped from the top of a building. The speed of the rock after it has fallen for 2.2 seconds is?

Answers

5x2.2/3 Because that's how you calculate velocity.

How does energy move predictably between a lien water in the air above it

Answers

is the question about the movement of heat??

Calculate the diffraction limit of the human eye, assuming a wide-open pupil so that your eye acts like a lens with diameter 0.8 centimeter, for visible light of 500-nanometer wavelength.
How does this compare to the diffraction limit of a 10-meter telescope?

Answers

he Dawes limit says that the resolving power is 11.6 / d, where d is your eye's pupil's diameter in centimeters. You're eye's pupil can dialate to about 7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc minute. However, the standard answer for what people can really see is about 1 arc minute. It's linear, so 10000 / 7 = 1428 times better for the 10 meter scope. However, unless the scope is in space, the atmosphere will take a big chunk from that.

an airplane travels from St. Louis to Portland, Oregon in 4.33 hours. If the distance traveled is 2742 km what is the airplanes average speed?

Answers

distance divided by time 2742km/4.33hr
Answer is 633.256 or rounded 633.26.






A dancer lifts his partner above his head with an acceleration of 2.5 m/s2. The dancer exerts a force of 200 N. What is the mass of the partner?

Answers

Super helpful formula in physics:
Force = acceleration * mass
F = am
Remember your F=am!

mass = Force/acceleration
mass = 200 N / (2.5 meters/seconds^2)
mass = 80 kilograms (about the mass of an average person)

The image shows the displacement of a motorboat. The data table shows the magnitudes of the components of each displacement vector.

What is the value of Rx?

km

What is the value of Ry?

km


Answers

Rx= 3.5 km

Ry= 2.9 km

[tex]R_x = A_x + B_x + C_x[/tex]

[tex]A_x[/tex] is negative as the vector is in third quadrant.

[tex]B_x[/tex] is positive as it points in the first quadrant.

[tex]C_x[/tex] is positive as it points in the fourth quadrant.

Hence,

[tex]R_x = -1.6 + 3.9 + 1.2[/tex]

[tex]R_x = 3.5[/tex] km

[tex]R_y = A_y + B_y + C_y[/tex]

[tex]A_y[/tex] is negative as it is in third quadrant.

[tex]B_y[/tex] is positive as it is in first quadrant.

[tex]C_y[/tex] is negative as it is in fourth quadrant.

[tex]R_y = -2.8 + 6.4 - 0.7[/tex]

[tex]R_y = 2.9[/tex] km

A student is trying to calculate the density of a can. He already knows the mass, but he needs to determine the volume as well. Which of the following formulas can be used to calculate the volume of the can?

Answers

Final answer:

To calculate the density of a can, the student must first determine its volume, which can be done using the formula for the volume of a cylinder V = πr²h or through displacement methods. Once the volume is known, density is calculated by dividing the mass by the volume.

Explanation:

To calculate the density of a can, the student needs to determine its volume. The volume of a cylindrical can be calculated using the formula for the volume of a cylinder, which is π (pi) times the radius squared times the height (V = πr²h). The student already knows the mass of the can, so once the volume is calculated, density can be found by dividing the mass by the volume

The formula provided (D = m/V) can also be transformed to solve for volume, providing another formula: Volume (V) = Mass (m) divided by Density (D).

In cases where the volume needs to be found through displacement, the formula V = m/p (where p is the density) is used, such as determining the volume of a coin by the water displacement method.

What is the instantaneous speed at 5 seconds? (remember s=d/t)



1 m/s


25 m/s


5 m/s


15 m/s

Answers

5 seconds is a poor time to ask about, because the speed abruptly changes at exactly 5 seconds.

Up until that time, the speed has been 1 m/s. And then, at exactly 5 seconds, it becomes zero.
_________

It's also a poor question because speed is calculated from the distance covered, but the graph shows displacement, not distance. You can't really tell the distance covered from a displacement graph. For example, if an object happens to be moving in a circle around the place where it started, then the total distance covered keeps increasing, but its displacement is constant.

Answer:

5 seconds is a poor time to ask about, because the speed abruptly changes at exactly 5 seconds.

Up until that time, the speed has been 1 m/s. And then, at exactly 5 seconds, it becomes zero.

_________

It's also a poor question because speed is calculated from the distance covered, but the graph shows displacement, not distance. You can't really tell the distance covered from a displacement graph. For example, if an object happens to be moving in a circle around the place where it started, then the total distance covered keeps increasing, but its displacement is constant.

Read more on Brainly.com - https://brainly.com/question/6618489#readmore

Explanation:

what is the volume of 325 g of metal with a density of 9.0 g/cm3

Answers

9.0g/cm3 = 325g/Xcm3
x= 36 1/9 cm3

The volume of 325 g of metal with a density of 9.0 g/cm³ is 36.11cm³

HOW TO CALCULATE VOLUME:

The volume of a substance can be calculated by dividing the mass of the substance by its density as follows:

Volume(mL) = mass(g) ÷ density (g/mL)

According to this question, the density of 325g of metal is given as 9.0 g/cm³, hence, the volume can be calculated as follows:

Volume = 325g ÷ 9g/cm³

Volume = 36.11cm³

Therefore, the volume of 325 g of metal with a density of 9.0 g/cm³ is 36.11cm³

Learn more at: https://brainly.com/question/2058404?referrer=searchResults

A student practicing for a cross country meet runs 250 m in 30 s. What is her average speed?

Answers

It's 8.3 m per second

When a student practicing for a cross country meet runs 250 m in 30 s, then her average speed would be 8.33 m/s.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

The mathematical expression for speed is given by

speed = total distance /Total time

As given in the problem a student practicing for a cross country meet runs 250 m in 30 s,

Total distance covered by the student while running =  250 m

Time is taken by the student while running = 30 seconds,

Her average speed = 250/30

                                 =8.33 m/s.

Thus. her average speed would be 8.33 m/s.

Learn more about speed from here, refer to the link;

brainly.com/question/7359669

#SPJ2

Choose all that apply. Solids, liquids, and gases can be distinguished by their:

molecular weight
shape
temperature
kinetic energy
mass
density

Answers

i believe its by there shape

Solids, liquids, and gases can be distinguished by their shape, density, and kinetic energy, while molecular weight and mass remain consistent across the states of matter.

Solids, liquids, and gases, the three common phases of matter, can be distinguished by several properties. Solids have a definite shape and volume. Liquids have a definite volume but adapt to the shape of their containers. Gases, on the other hand, have neither a definite shape nor a specific volume, as they expand to fill their containers.

The characteristics that distinguish these states include:

Shape: Solids have a fixed shape, while liquids take the shape of their container and gases have no fixed shape.Density: Typically, solids are denser than liquids, which are in turn denser than gases, although there are exceptions when substances change phase.Kinetic Energy: Gases have the highest kinetic energy due to the fast movement of their molecules, while solids have the least.

The properties that do not generally differ across the different states of matter include molecular weight and mass. A substance's mass or molecular weight remains consistent regardless of whether it is a solid, liquid, or gas.

How does the law of conservation of mass apply to this reaction Mg+HCL->H2+MgCl2?

Answers

Answer :

Law of conservation of mass : It states that the mass of reactant molecules must be equal to the mass of product molecules.

The given unbalanced reaction is,

[tex]Mg+HCl\rightarrow H_2+MgCl_2[/tex]

First we have to balance the chemical reaction.

The balanced chemical reaction is,

[tex]Mg+2HCl\rightarrow H_2+MgCl_2[/tex]

Now we have  to calculate the mass of reactant side molecules and product side molecules.

Mass of reactants = [tex]Mg+2HCl=(24)+2(1+35.5)=97g[/tex]

Mass of products = [tex]H_2+MgCl_2=2(1)+(24+2(35.5))=97g[/tex]

From this we conclude that the mass of reactant is equal to the mass of product.

Answer:

Law of conservation of mass do not apply to this equation.

Explanation:

The law of conservation of mass states that the mass of objects/element before any reaction must be equal to the mass of objects/element after the reaction.  

Here in this case –  

Mg+HCL->H2+MgCl2

Mass of Mg before reaction = 1

Mass of H before reaction = 1

Mass of Cl before reaction = 1

Mass of Mg after reaction = 1

Mass of H after reaction = 2

Mass of Cl after reaction = 2

Thus it is clear that mass of H and Cl before and after the reaction is not equal and thus law of conservation of mass do not apply to this equation.

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