Answer:
a) Tc = 750 [N] ;b) See the explanation below.
Explanation:
To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.
b)
The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.
a)
In this way we can find by means of a sum of forces on the y axis equal to zero:
- 850 - 450 + 550 + Tc = 0
Tc = 750 [N]
Why and how is oil used to reduce the effects of friction in large machines
By reducing friction
Explanation:
A big machine is composed of several moving and stationary parts. Some of these parts are in a state of constant motion hence they periodically rub against each other. The friction between the body parts causes the body part to wear out and heat up in the process. This heat is symbolic of waste of energy.
The lubricating agents are a saviour in such conditions. Lubricating oils with high viscosities reduces friction. If we go deep into the working of the lubrication we find that the interacting parts of machines are quite rough when viewed under microscope. These rough surfaces when interact produce bumpy motion, wear and tear, heat etc.
Oil fills these microscopic voids and thus provides temporary relief. When these lubricated body parts interact, they encounter plain surface with decreased friction (due to high viscosity of the oils) and thus glide over each other freely thereby producing smooth movements, noiseless working.
is there carbon atoms in the compound Ca3N2
No, there are not any carbon atoms inside this compound.
The compound is [tex]Ca_3N_2[/tex]. This means there are 3 "Ca" atoms and 2 "N" atoms.
Ca is calciumN is nitrogenThus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!
~ Padoru
a heavy object falls with the acceleration as a light object during free fall. Why?
A heavy object falls with the acceleration as a light object during free fall because of acceleration due to gravity.
Explanation:
A motion can be termed as free fall when the object is completely under the influence of gravity. So in this case, no other force will be acting on the object other than the gravitational force. As the gravity influences the object in free fall, the acceleration attained by any object in free fall is same. And this acceleration is termed as acceleration due to gravity. Since, the gravity gives the acceleration to every object experiencing free fall, then the acceleration should be constant. Thus, a heavy object and a light object will have same acceleration during free fall.
The answer and how to do it?? Thanks
The acceleration of the block is 4 m/s².
To find the acceleration of the 1kg block in the given diagram, we need to calculate the total force acting on the block and then divide it by the mass of the block.
Since there are three forces acting on the block, we can find the resultant force by adding these forces together.
In this case, the forces are 5N, 4N, and 5N in different directions.
Combining these forces, we get a net force of 4N in the horizontal direction.
Since the mass of the block is 1kg, the acceleration can be calculated using Newton's second law of motion: F = ma.
Therefore, the acceleration of the block is 4 m/s².
What contributes the most to food waste in America
According to the USDA, 40% of our food worth $161 billion is not even harvested, lost in processing, thrown away in restaurants and homes or ended up rotting in America’s landfills. It is also reported that 50% of the produce is never consumed.
Disparities in food distribution and availability imply that numerous communities and neighborhoods have very constrained access to fresh affordable food. Also, a significant number of those with a bounty of food choose to toss it rather than donate it.
Another type of food waste comes from produce discarded by millions of backyard cultivators due to their gardens producing far more fruits and vegetables than they might use, preserve or give to friends and neighbours.
what device is made of coils of wire with an electrical current passing through it in order to generate a magnetic field
Transformer
Explanation:
A transformer is a device with two or more magnetically coupled windings. A time varying current in one coil (primary winding) generates a magnetic field which induces a voltage in the other coil (secondary winding). Transformers are capable of either increasing or decreasing the voltage and current levels of their supply, without modifying its frequency, or the amount of electrical power being transferred from one winding to another via the magnetic circuit. There are two types of transformer:
1. Step up transformer - increases voltage
2. Step down transformer - decreases voltage
in which medium does sound travel the fastest
Answer:
Solids
Explanation:
Aluminum
Explanation:
A 82-kg skydiver has a speed of 40 m/s at an altitude of 490 m above the ground. Calculate the total mechanical energy of the skydiver.
Answer:
[tex]ME=459,364J[/tex]
Explanation:
Mechanical Energy=Potential Energy+ kinetic Energy
[tex]m=82kg,g=9.8N/kg,h=490m,v=40m/s[/tex]
To calculate Kinetic Energy:-
[tex]KE=\frac{1}[2}mv^2\\=\frac{1}{2}\times82kg \times(40m/s)^2\\=65600J[/tex]
To calculate Potential Energy:-
[tex]PE=mgh\\=82kg \times9.8N/kg \times490\\=393764[/tex]
therefore,
[tex]ME=KE+PE\\=65600+393764\\=459364J[/tex]
The skydiver's total mechanical energy is 459365J
Final answer:
The total mechanical energy of an 82-kg skydiver moving at 40 m/s at an altitude of 490 m above the ground is calculated as 458876 Joules, which includes both kinetic and potential energy.
Explanation:
Calculating Total Mechanical Energy of a Skydiver
To calculate the total mechanical energy of a 82-kg skydiver moving at a speed of 40 m/s at an altitude of 490 m above the ground, we need to consider both kinetic and potential energy.
Kinetic energy (KE) is given by the formula: KE = 0.5 Times m times v2
Gravitational potential energy (PE) is given by the formula: PE = m times g Times h
Where:
m is the mass of the skydiver (82 kg)
v is the velocity (40 m/s)
g is the acceleration due to gravity (9.8 m/s2)
h is the height above the ground (490 m)
Now we perform the calculations:
KE = 0.5 imes 82 kg times (40 m/s)2 = 0.5 times 82 times 1600 = 65600 J
PE = 82 kg times 9.8 m/s2 times 490 m = 82 times 9.8 times 490 = 393276 J
The total mechanical energy (Etotal) is the sum of kinetic and potential energy:
Etotal = KE + PE = 65600 J + 393276 J = 458876 J
Therefore, the total mechanical energy of the skydiver is 458876 Joules.
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, what is his speed ?
Answer:
71
Explanation:
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, his speed 71 m/sec.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Using conservation of energy
m*g*h + 0.5 m*v² = 150023 joule
59*9.8*2.6 + 0.5*59*v² = 150023
1503.32 + 29.5 v² = 150023
29.5 v² = 148519.60
v² = 5034.56
v = 70.95 = 71 m/sec
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, his speed 71 m/sec.
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A driver starts is parked car and within 5 seconds reaches a speed of 60km/h, as he travels east. What his acceleration?
The acceleration of the car is 3.3 m/s²
Explanation:
Given-
Speed of the car, (we can represent as s) = 60 km/hr = 60 × [tex]\frac{5}{18}[/tex] = 16.67 m/s
Time,(we can represent as t) = 5 s
Acceleration, (we can represent as a) = ?
We know,
a = [tex]\frac{s}{t}[/tex]
a = [tex]\frac{16.67}{5}[/tex]
a = 3.334 m/s²
The acceleration of the car is 3.3 m/s²
_____ All elements in this series are radioactive?
Answer:
Actinide series : All the elements in the actinides series are radiactive
Explanation:
The question is to fill in the blank which series of elements in the periodic table are radiactive.
The answer is the actnide series.
The actinide series is the elements in the same row as actinide since the same actnide (atomic number 89) to the lawrencium (atomic number 103).
Among other elements, this series include thorium, uranium and plutonium which are very known as radiactive elements, since they are used in nuclear reactors, which use nuclear fission reactions.
The reason for the radioactivity of these elements is the massive unstable nucleus.
A heavy nucleus means a large amount of positive charge (protons) concentrated in a tiny region (the nucleus of the atom).
The electrostatic repulsion among those so many protons is not balanced by the strong nuclear force (from the neutrons) resulting in the unstability (radioactivity) of the nucleus.
In a radioactive decay series, not all elements are radioactive. The series includes most of the naturally radioactive elements, but each series concludes with a stable, non-radioactive end-product, typically a stable isotope of lead.
Explanation:The question you've asked relates to Radioactive Decay Series. Naturally occurring radioactive isotopes of the heaviest elements fall into decay series. These series include most of the naturally radioactive elements of the periodic table such as the uranium series, the actinide series, and the thorium series. However, not all elements in these series are radioactive; each chain ultimately concludes with a stable end-product. For example, for all three mentioned series, the end-product is a stable isotope of lead. The concept of a decay series results from heavy nuclei decaying to a lighter one, with the lighter, daughter nucleus becoming the parent nucleus for the next decay.
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a 60 kg child sits on on the outer edge a playground merry-go-around with radius of 4 meters that spins around at 1 revolution every 5 seconds, mercilessly bringing the child ever closer to nausea. What is the child's angular momentum? ( Remember to include the units.) What is the angular momentum of another child with the same mass who is sitting half way out from the center?
Answer:
a) [tex]1209.6 kg m^2/s[/tex]
b) [tex]302.4 kg m^2/s[/tex]
Explanation:
a)
The angular momentum of an object in circular motion is given by the formula
[tex]L=m\omega r^2[/tex]
where
m is its mass
[tex]\omega[/tex] is its angular velocity
r is the distance of the object from the axis of rotation
For the child in this problem, we have:
m = 60 kg is his mass
r = 4 m is the radius of the merry-go-around
Here the child completes 1 revolution every 5 seconds; so his frequency is
[tex]f=\frac{1}{5}=0.2 Hz[/tex]
And so his angular speed is
[tex]\omega=2\pi f=2\pi 0.2=1.26rad/s[/tex]
Therefore, the angular momentum is
[tex]L=(60)(1.26)(4)^2=1209.6 kg m^2/s[/tex]
b)
For a child sitting halfway of the merry-go-around, his distance from the axis of rotation is
[tex]r=\frac{4 m}{2}=2 m[/tex]
The mass of the child is the same as before,
m = 60 kg
And the angular speed is the same as well: in fact, the merry go around is a rigid body, so all its points cover the same angle in the same time; so, they all have the same angular speed. Therefore,
[tex]\omega=1.26 rad/s[/tex]
Therefore, the angular momentum here is:
[tex]L=m\omega r^2 = (60)(1.26)(2)^2=302.4 kg m^2/s[/tex]
A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from
the wire.
Answer:
[tex]1.67\cdot 10^{-5} T[/tex]
Explanation:
The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where:
[tex]\mu_0=4\pi \cdot 10^{-7} H/m[/tex] is the vaacuum permeability
I is the current in the wire
r is the distance from the wire
The direction of the magnetic field lines is tangential to concentric circles around the wire.
In this problem, we have:
[tex]I=37.9 A[/tex] is the current in the wire
[tex]r=45.5 cm = 0.455 m[/tex] is the distance from the wire
Solving for B, we find the magnitude of the magnetic field:
[tex]B=\frac{\mu_0 I}{2\pi r}=\frac{(4\pi \cdot 10^{-7})(37.9)}{2\pi (0.455)}=1.67\cdot 10^{-5} T[/tex]
Objects that are not moving have NO _____. A. mass (only) B. mass and momentum (only) C. velocity and momentum (only) D. mass, velocity, and momentum
Answer:
Objects that are not moving have NO velocity and momentum (only)
Explanation:
This best explains the potential energy of an object, when an object is at rest. it is said to have possessed a potential energy but without velocity and momentum i.e energy at rest
Girl who’s mass is 52kg, experienced a net force of 1800N at bottom of a roller coster loop during her school physics field to the local amusement park, determine Sophia’s acceleration at location.
Answer:
34.62m/s^2
Explanation:
Force = mass x acceleration
Given
Force = 1800N
Mass = 52kg
Therefore
1800 = 52 x a
Divide both sides by 52
1800/52 = 52/52 x a
34.62 = a
a = 34.62m/s^2
You serve a volleyball with mass of 2.1kg. The call leaves your hand at 30m/s. The ball has Energy calculate it
Answer: 945 joules
Explanation:
Given that:
mass of volleyball = 2.1kg.
Speed at moving volleyball = 30m/s. Energy possessed by volleyball = ?
Recall that the energy possessed by a moving object is known as kinetic energy. Thus, the moving volleyball has kinetic energy.
So, apply the formula for kinetic energy
K.E = 1/2 x mass x speed^2
K.E = 1/2 x 2.1kg x (30m/s)^2
K.E = 0.5 x 2.1kg x 900
K.E = 945 Joules
Thus, the volleyball has kinetic energy of the 945 joules
5. A 5.5 x10-6 C charge is located 0.28 m from a -3.5 x 10-6 C charge.
a) What is the magnitude of the force that the positive charge exerts on the negative charge?
b) If the negative charge was doubled, how would the force change?
(a) The magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
Explanation:
The force acting between two charged particles separated by a distance is termed as Coloumb's force or electrostatic force. It can be termed as electrostatic force of attraction if the the force acting between the charges are oppositely charged. And it can be termed as electrostatic force of repulsion if the charges are similar or like charges.
In the present case, there is a positive and negative charge, so electrostatic force of attraction will be acting between them. As per Coloumb's law, the electrostatic force of attraction is directly proportional to the product of charges and inversely proportional to the square of distance of separation.
[tex]F = \frac{kQq}{d^{2} }[/tex]
Here, k is the constant of proportionality which is equal to 9 ×[tex]10^{9}[/tex] and Q, q are the two charges, d is the distance of separation.
So here Q = 5.5 ×[tex]10^{-6} C[/tex] and q = - 3.5 ×[tex]10^{-6} C[/tex] and d = 0.28 m
Then, [tex]F=-\frac{9*10^{9}*5.5*10^{-6} * 3.5 * 10^{-6} }{(0.28)^{2} } = 2209.82*10^{-3}[/tex]
So the magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
The question requires the calculation of the electric force between two point charges using Coulomb's law and understanding how changes in the magnitude of one charge affect the force.
Explanation:The question involves understanding and applying Coulomb's law, which describes the electric force between two point charges.
a) Magnitude of the Force
To find the magnitude of the force that one charge exerts on another, we use the formula given by Coulomb's law:
[tex]F = k * |q1 * q2| / r^2[/tex]
Where:
F is the magnitude of the force between charges,k is the Coulomb's constant [tex](8.9875 x 10^9 N m^2/C^2),[/tex]q1 and q2 are the charges [tex](5.5 x 10^-6 C and -3.5 x 10^-6 C respectively),[/tex]r is the separation between the charges (0.28 m).Plugging in the values, we calculate F.
b) Effect of Doubling the Negative Charge
If the negative charge was doubled, the new charge would become [tex]-7.0 x 10^-6 C.[/tex] Since the force is directly proportional to the product of the two charges, doubling one of the charges would double the force as well.
help? the first line is supposed to say "all _ has heat"
click the image
A sample of gas has a volume of 42 L at a pressure of 200 kPa and a temperature of 30^ * C . What would be the volume, if the pressure were increased to 250 kPa and the temperature were decreased to 5^ * C ?
Answer:
30 L
Explanation:
Ideal gas law:
PV = nRT
Rearranging:
PV / T = nR
Since n and R are constant:
P₁ V₁ / T₁ = P₂ V₂ / T₂
Plugging in values and solving:
(200 kPa) (42 L) / (30 + 273.15 K) = (250 kPa) V / (5 + 273.15 K)
V = 30.8 L
Rounded to one significant figure, the new volume is 30 L.
The centre of gravity of a body may not be necessary on the body. Justify
Answer:
Your center of gravity
Explanation:
like everyone has there own center of gravity by there weight because that is going to see hows your balance, if I'm right
The center of gravity is the point where the total weight of a body is concentrated, but it may not always be on the body itself. This can be observed in situations like an unbalanced car wheel or a human standing, where the center of mass does not align with the geometric center.
The center of gravity of a body is the point where the total weight of the body is assumed to be concentrated. However, it does not necessarily need to be located on the body itself. This concept is particularly important in understanding the balance and stability of objects. For instance, a car wheel that has not been balanced properly has a center of mass that does not coincide with its geometrical center. Moreover, in a situation like a human standing, by shifting their weight, they can cause the center of mass to hang in space - a point that might not correspond with any actual material part of the body.
Three-dimensional bodies demonstrate this when they are in motion, such as when a stick is thrown in the air and seems to rotate around a single point. This occurs because the center of mass carries the whole mass of the body, contributing to the observed motion. Even large structures, such as buildings or cruise ships, despite their size, are located in a uniform gravitational field on Earth, which means the acceleration due to gravity is constant and the center of gravity and center of mass coincide.
Objects with odd shapes or missing parts can also have a center of gravity outside their physical form. Imagine a horseshoe where the center of gravity would be somewhere near the bottom, even though there's no material there.
Consider a hollow ring, the mass is concentrated around the rim, not in the center. As a result, the center of gravity would lie somewhere within the ring, not necessarily on the actual body.
How do you find the value of e?
refractive index = sin i / sin e
where i is the angle of incidence
e is the angle of refraction
1.5 = sin 35 / sin e
1.5 = 0.5736/sin e
sin e = 0.5736/ 1.5
sin e = 0.3824
e = 22.48°
Desiree has a scientific question that she wants to investigate. She has developed a hypothesis and method for her experiment. Which step of scientific inquiry should Desiree take next?
Desiree should present her findings to her teacher and classmates.
Desiree should collect data, which may support or refute her hypothesis.
Desiree should provide an explanation for her results.
Answer:
Desiree should collect data, which may support or refute her hypothesis.
Explanation:
The next step Desiree must take is to collect data which might likely support or refute her hypothesis.
This is usually done by carrying out experiments or field studies.
The scientific method provides the steps through which knowledge of science is investigated. It usually starts with observation. After an observation is made, a scientific question is asked. This leads to the development of hypothesis. Then, experiments are carried out and data collect to either bolster the claim or refute it. Interpretation follows and conclusion is draw.Desiree should proceed to the step of collecting data, which may support or refute her hypothesis. Therefore option B is correct.
Collecting data is a crucial stage in the scientific inquiry process. It involves conducting experiments or observations to gather information that can either confirm or contradict the hypothesis she has formulated.
By systematically collecting and analyzing data, Desiree can draw conclusions based on empirical evidence. This step forms the backbone of scientific investigation as it provides the tangible information required to validate or revise her hypothesis.
Once she has sufficient data, Desiree can move on to analyzing her results and drawing meaningful conclusions, paving the way for the interpretation and potential communication of her findings.
Therefore option B is correct.
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In lab, your instructor generates a standing wave using a thin string of length L = 1.65 m fixed at both ends. You are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude A = 3.65 mm and a speed vx = 13.5 m/s . The first antinode of the standing wave is a distance of x = 27.5 cm from the left end of the string, while a light bead is placed a distance of 13.8 cm to the right of the first antinode. What is the maximum transverse speed vy of the bead?
The given standing wave on a string has a wavelength (λ) of 0.55 m, a frequency (f) of 24.54 Hz, a wave number (k) of 11.46 rad/m, and an angular frequency (ω) of 154.3 rad/s. The displacement of the bead at its position is given by the wave equation, and the maximum transverse speed (vy_max) is estimated to be approximately 0.4 m/s.
Length of the string (L) = 1.65 m
Amplitude of the traveling wave (A) = 3.65 mm
Speed of the traveling wave (vx) = 13.5 m/s
Distance of the first antinode from the left end (x) = 27.5 cm
Distance of the bead from the first antinode (d) = 13.8 cm
2. Finding the wavelength (λ):
Since the antinode is the point of maximum displacement, the first antinode is located at half the wavelength from the fixed end. Therefore,
λ = 2 * x = 2 * 0.275 m = 0.55 m
3. Finding the frequency (f):
We can use the relationship between wave speed, wavelength, and frequency:
v = λf
f = v / λ = 13.5 m/s / 0.55 m = 24.54 Hz
4. Finding the wave equation:
The equation for a standing wave on a string can be written as:
y(x, t) = A sin(kx) cos(ωt)
where:
k = wave number (k = 2π/λ)
ω = angular frequency (ω = 2πf)
5. Finding the wave number (k):
k = 2π/λ = 2π / 0.55 m = 11.46 rad/m
6. Finding the angular frequency (ω):
ω = 2πf = 2π * 24.54 Hz = 154.3 rad/s
7. Finding the displacement of the bead at its position:
The bead is located at x = x1 + d, where x1 is the distance of the first antinode from the left end (0.275 m) and d is the distance of the bead from the first antinode (0.138 m).
x1 + d = 0.275 m + 0.138 m = 0.413 m
Substitute this value of x in the wave equation:
y(0.413 m, t) = 3.65 mm * sin(11.46 rad/m * 0.413 m) * cos(154.3 rad/s * t)
8. Finding the maximum transverse speed (vy):
The maximum transverse speed occurs when the derivative of the displacement with respect to time (dy/dt) is at its maximum.
vy(t) = dy/dt = -Aω * cos(kx) sin(ωt)
The maximum value of sin(ωt) is 1, and the maximum value of cos(kx) depends on the position of the bead. Since the bead is not at a node or antinode, cos(kx) will not be 0 or 1.
Therefore, the maximum transverse speed (vy_max) can be estimated as:
vy_max ≈ Aω ≈ 3.65 mm * 154.3 rad/s ≈ 0.4 m/s
which type of energy is stored in a stretched string on the bow in the following figure
Answer:
potential energy
Explanation:
Answer: Elastic Potential Energy
Explanation: For stretched material such as ropes or strings they have a certain form of energy that allows them to stretch or compress. The energy is called elastic energy. For the case of the string on the bow it possess Elastic Potential Energy since there is no motion in the string.
Four ball are simultaneously launched with the same speed from the same height and h above the ground. At the same instant, ball 5 is released from the rest at the same height. Rank in order, from shortest to longest, the amount of time it takes each of these balls to hit the ground ( some maybe simultaneously.)
In this scenario of Physics involving free fall and projected motion, all the balls launched, whether from rest or different angles, from the same height will hit the ground simultaneously. The time of flight in such a case, considering no air resistance, will only depend on the initial height from the ground and the acceleration due to gravity, not on the initial speed or direction of projection.
Explanation:The question pertains to the physics concept of free fall and their time of flights. To reiterate, all the balls are being launched from the same height, h, including ball 5 which is released from rest. According to physics, irrespective of their initial velocities or launch angles, all objects in free fall will hit the ground at the same time assuming they are dropped from the same height. This is because the time a projectile is in the air is governed by its vertical motion alone and in this scenario, all the balls have the same vertical component which is the same height from which they are dropped. So, all of the balls including ball 5 will hit the ground simultaneously.
This understanding is backed by two key principles. One, that the horizontal and vertical motions of a projectile are independent of each other, meaning the horizontal velocity does not affect the vertical fall. Two, that the time of flight of a projectile is linearly proportional to the initial velocity in the y direction (height in this case) and inversely proportional to g (acceleration due to gravity). Considering the fact that all the balls start from rest, have the same height, and experience the same acceleration due to gravity, the time of flight for all balls becomes equal.
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The moon’s relative motion causes
Answer: Different cycles of the moon and ocean currents are all I can think of.
Answer:
Different cycles of the moon and ocean currents.
Explanation:
A cetain car weighs 25,000 N. Calculate the mass of the car.
245.000 kg
25,000 kg
9.81 m/s2
2,500 kg
Answer:2500kg
Explanation:
Weight of car(w)=25000N
Acceleration due to gravity approximately(g) 10m/s^2
Mass=w/g
Mass=25000/10
Mass=2500kg
A 63 kg astronaut drifting with 7.0 m/s to the right with
respect to a spacecraft uses a jetpack to slow down.
Suppose it takes 14.0 s to come to a stop with respect to the spacecraft. What is the force exerted by the jetpack?
Answer:
31.5N
Explanation:
M = 63kg, v = 7.0m/s t = 14.0s F =?
Force = Mass * acceleration
but acceleration = change in velocity / time
a = dV/dt
F = (63 * 7.0) / 14
F = 31.5N
To calculate the force exerted by the jetpack, we use the astronaut's deceleration and mass. The deceleration is obtained from the change in velocity (from 7.0 m/s to 0 m/s in 14.0 s). Applying Newton's second law, the force equals to the mass (63 kg) multiplied by the deceleration (-0.5 m/s²), resulting in a force of 31.5 newtons in magnitude.
Explanation:The question is asking to calculate the force exerted by a jetpack that an astronaut uses to come to a stop relative to a spacecraft. First, we'll use the formula for acceleration (a) which is the change in velocity (Δv) divided by the change in time (Δt). In this case, the astronaut decelerates from 7.0 m/s to 0 m/s in 14.0 s, so the acceleration is -7.0 m/s divided by 14.0 s, which equals -0.5 m/s² (the negative sign indicates deceleration).
The next step is to apply Newton's second law of motion: F = ma, where F is the force, m is the mass, and a is the acceleration. Plugging in the values we have: F = 63 kg * (-0.5 m/s²) = -31.5 N. The negative sign indicates that the force is in the opposite direction of the initial velocity, i.e., to the left if the initial movement was to the right.
The magnitude of the force exerted by the jetpack is 31.5 newtons.
A 10 N force is applied to a hockey puck over a period of 0.1 s. What is the change in momentum of the hockey puck?
Final answer:
The change in momentum of the hockey puck is 1 kg·m/s.
Explanation:
The change in momentum of an object can be calculated using the equation: change in momentum = force x time.
In this case, the force applied to the hockey puck is 10 N and the time period over which the force is applied is 0.1 s. Therefore, the change in momentum of the hockey puck is 10 N x 0.1 s = 1 kg·m/s.
a current-carrying wire has the maximum magnetic force in it when it is placed in a constant magnetic field when
Answer:
Maximum magnetic force on current carrying wire when wire is placed at 90 degree with magnetic field
Explanation:
As we know that the magnetic force on current carrying conductor is given as
[tex]\vec F = i(\vec L \times \vec B)[/tex]
here we have
[tex]F = i L Bsin\theta[/tex]
here we know that
[tex]\theta [/tex] = angle between length vector and magnetic field vector
so if we would like to have maximum magnetic force on the current carrying wire then
[tex]\theta = 90 [/tex]
so we have
[tex]F_{mex} = iLB[/tex]