Zoe payed $18.60 in sales tax and tips for her dinner. The sales tax is 11% and she tipped 20%. What was the price of Zoe's dinner, before sales tax and tip

Explanation:

DeMoivre's theorem tells you the 7th roots of unity are the 7 points evenly spaced around (on) the unit circle, including 1∠0°. They will be located at angles ...

  {0, 2π/7, 4π/7, 6π/7, 8π/7, 10π/7, 12π/7} . . . in radians

Given that the circle shown is graduated in increments of π/6, you will need to do some estimating as to the actual location of the root.

___

The attached graph shows lines at increments of π/7 radians, so your graph will match every other one.

ANSWER

[tex]{(x - 3)}^{3} = {x}^{3} - 9 {x}^{2} + 27x - 27[/tex]

EXPLANATION

We want to expand:

[tex] {(x - 3)}^3[/tex]

Using the identity;

[tex] {(x - y)}^{3} = {x}^{3} - 3 {x}^{2}y + 3x {y}^{2} - {y}^{3} [/tex]

We substitute y=3 into the above identity to obtain:

[tex] {(x - 3)}^{3} = {x}^{3} - 3 {x}^{2}(3) + 3x( {3}^{2} ) - {(3)}^{3} [/tex]

Let us simplify to get:

[tex]{(x - 3)}^{3} = {x}^{3} - 9 {x}^{2} + 27x - 27[/tex]

Answer:

Step-by-step explanation:

Following your description I got

sin 29° = opp/hyp = 4.6/c

csin29 = 4.6

c = 4.6/sin29

= 9.48826.. or appr 9.5

Answer:

Option (D)

Step-by-step explanation:

Answer:

The answer would be D.4.

Step-by-step explanation:

So first you would have to find the mean of the data by taking into account the amount of each type of numbers like this 1,2,2,3,3,3,4,4,4,4,5,5,5,6,6,7. Then add those all up which would give 64, since their is 16 numbers in total divide 64 by 16 which would give 4.

Answer:

cl   +   1/(N+1)

Step-by-step explanation:

If we assume that the Nth harmonic number is cl. Then we are assuming that 1+1/2+1/3+1/4+...+1/N=cl

And we know that the (N+1)th harmonic number can be found by doing

1+1/2+1/3+1/4+...+1/N+1/(N+1)

=cl    +   1/(N+1)

The (N+1)th harmonic number is cl   +   1/(N+1) given that the Nth term is cl

Other way to see the answers:

Maybe you want to write it as a single fraction so you have

[cl(N+1)+1]/(N+1)=[cl*N+cl+1]/(N+1)

The expression value is [tex]hn+(\frac{1}{n+1} )[/tex].

Assume that [tex]n[/tex] is an integer variable whose value is some positive integer [tex]N[/tex].

Assume also that [tex]hn[/tex] is a variable whose value is the [tex]N_{th} [/tex] harmonic number.

An expression whose value is the [tex](N+1)th[/tex] harmonic number is [tex]hn+(\frac{1}{n+1} )[/tex].

Learn more: https://brainly.com/question/14307075

Answer:

[tex]y^2=\frac{1}{8}x[/tex]

Step-by-step explanation:

The focus lies on the x axis and the directrix is a vertical line through x = 2.  The parabola, by nature, wraps around the focus, or "forms" its shape about the focus.  That means that this is a "sideways" parabola, a "y^2" type instead of an "x^2" type.  The standard form for this type is

[tex](x-h)=4p(y-k)^2[/tex]

where h and k are the coordinates of the vertex and p is the distance from the vertex to either the focus or the directrix (that distance is the same; we only need to find one).  That means that the vertex has to be equidistant from the focus and the directrix.  If the focus is at x = -2 y = 0 and the directrix is at x = 2, midway between them is the origin (0, 0).  So h = 0 and k = 0.  p is the number of units from the vertex to the focus (or directrix).  That means that p=2.  We fill in our equation now with the info we have:

[tex](x-0)=4(2)(y-0)^2[/tex]

Simplify that a bit:

[tex]x=8y^2[/tex]

Solving for y^2:

[tex]y^2=\frac{1}{8}x[/tex]

Answer: x = -1/8y^2

Step-by-step explanation

Focus: (-2,0)

Directrix: x=2

It meets the criteria.

Answer:

(0,4) vertex and (1,3) another pt

Step-by-step explanation:

The parabola has been shifted up 4 units from parent function (there is also a reflection)...but we only really care about the shift 4 units up from (0,0) for our vertex... Our vertex is (0,4)

Now just plug in another number to find another point...let's do x=1

Plug in you get -1^2+4=-1+4=3 so another point is (1,3)

Answer: [tex]115in^3[/tex]

Step-by-step explanation:

The volume of a cone can be calculated with the following formula:

[tex]V_{(cone)}=\frac{1}{3}\pi r^2h[/tex]

Where "r" is the radius and "h" is the height.

The radius is half the diameter, then "r" is:

[tex]r=\frac{7in}{2}\\\\r=3.5in[/tex]

Since we know that radius and the height, we can substitute them into the formula.

The volume of the cone  to the nearest cubic inch is:

 [tex]V_{(cone)}=\frac{1}{3}\pi (3.5in)^2(9in)[/tex]

 [tex]V_{(cone)}=115in^3[/tex]

Answer:

The  volume of cone = 115 cubic inches

Step-by-step explanation:

Points to remember

Volume of cone = (πr²h)/3

Where r - Radius of cone and

h - Height of cone

To find the volume of cone

Here diameter = 7 in then r = 7/2 = 3.5 in and h = 9 in

Volume = (πr²h)/3

 = (π * 3.5² * 9)/3

 = (3.14  * 12.25 * 9)/3

 = 115.395 ≈ 115 cubic inches

Therefore volume of cone = 115 cubic inches

Answer:

  48

Step-by-step explanation:

The total number of ratio units is 3+2 = 5, and the 3 ratio units representing large bandages make up 3/5 of that total. Thus, large bandages will make up 3/5 of the total number of bandages:

  3/5×80 = 48 . . . . number of large bandages in the kit

Answer: Hence, there are 36 total number of invited guests.

Step-by-step explanation:

Let the total number of invited guests be 'x'

Part of those invited had already arrived = [tex]\dfrac{2}{3}x[/tex]

Number of people just arrived = 6

According to question, it brings the number at the party to [tex]\dfrac{5}{6}[/tex] of those invited.

So, it becomes,

[tex]\dfrac{2}{3}x+6=\dfrac{5}{6}x\\\\6=\dfrac{5}{6}x-\dfrac{2}{3}x\\\\6=\dfrac{5x-4x}{6}\\\\6=\dfrac{x}{6}\\\\x=6\times 6\\\\x=36[/tex]

Hence, there are 36 total number of invited guests.

Answer:

42 People

Step-by-step explanation:

P is the total amount of people. Before Cedric arrived, there were (2/3)P people at the party. After Cedric and six other people arrived, there are (2/3)P+7 people at the party. Since this is the same as (5/6)P, we solve (2/3)P+7=(5/6)P to find that P=42.

Formula and set up:

A = P(1 + r/n)^(nt)

You want A.

A = 1200(1 + (0.06)/2)^(0.06)(2)

Plug right side into calculator to find A.

Answer:

  all real numbers less than or equal to –3

Step-by-step explanation:

Look at the y-values that the graph shows. There are none greater than -3. Any value of -3 or less is possible.

Answer: D. all real numbers less than or equal to –3

Answer:

(7,2)

Step-by-step explanation:

If you compare (4,1) to (x,y)

You should see that in place of x you have 4

and in place of y you have 1

so just plug them in

(4+3,1+1)

(7,2)

Answer:

C. –120a2b2c2

Step-by-step explanation:

We'll just the multiplications one at a time...

10ac × 6ab × (–2bc) = 60a²bc * (-2bc)  (multiplying 10ac × 6ab)

60a²bc * (-2bc)  = -120a²b²c²

We just have to multiply the numbers together (like 10 and 6),

then all similar letters together (like ac * ab = a²bc).  If a letter is already present (like a in this  example), then we add up its powers a * a = a², a² * a would be a³ and so on).  If the letter is not present (like 'b' in 'ac', we suppose it's there as b^0 which is equal to 1)... so we still add up its exponent (power)... so it makes b^0 * b = b

[tex]3^{4}[/tex] + 2 × 5

To evaluate apply the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

Parentheses  

There are none for this steps so go on to the next step

Exponent:

[tex]3^{4}[/tex]

81

so...

81 + 2 × 5

Multiplication:

81 + 2 × 5

2 × 5

10

so...

81 + 10

No division in this equation so skip this step and go to the next one

Addition:

81 + 10

91

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

44

Step-by-step explanation:

Order of operations

PEMDAS

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Do multiply from left to right.

2*5=10

Add the numbers from left to right to find the answer.

34+10=44

44 is the correct answer.

I hope this helps you, and have a wonderful day!

let's multiply both sides in each equation by the LCD of all fractions in it, thus doing away with the denominator.

[tex]\begin{cases} \cfrac{1}{2}x+\cfrac{1}{3}y&=7\\\\ \cfrac{1}{4}x+\cfrac{2}{3}y&=6 \end{cases}\implies \begin{cases} \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{6}}{6\left( \cfrac{1}{2}x+\cfrac{1}{3}y \right)=6(7)}\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{1}{4}x+\cfrac{2}{3}y\right)=12(6)} \end{cases}\implies \begin{cases} 3x+2y=42\\ 3x+8y=72 \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf \stackrel{\textit{using elimination}}{ \begin{array}{llll} 3x+2y=42&\times -1\implies &\begin{matrix} -3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-2y=&-42\\ 3x+8y-72 &&~~\begin{matrix} 3x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+8y=&72\\ \cline{3-4}\\ &&~\hfill 6y=&30 \end{array}} \\\\\\ y=\cfrac{30}{6}\implies \blacktriangleright y=5 \blacktriangleleft \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf \stackrel{\textit{substituting \underline{y} on the 1st equation}~\hfill }{3x+2(5)=42\implies 3x+10=42}\implies 3x=32 \\\\\\ x=\cfrac{32}{3}\implies \blacktriangleright x=10\frac{2}{3} \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left(10\frac{2}{3}~~,~~5 \right)~\hfill[/tex]

Answer:

y = 3x - 2

Step-by-step explanation:

You can easily find the equation of a line through two points by using the point-slope form, [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is one of the points.

First, let's find the slope of the line through (0, -2) and (4, 10).

[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1} = \frac{10-(-2)}{4-0}=\frac{12}{4}=3[/tex]

Next, we plug this into point-slope form. Remember that we let (0, -2) be our first point, [tex](x_1,y_1)[/tex].

[tex]y-(-2)=3(x-0)[/tex]

Finally, we rearrange this equation to get the slope-intercept form [tex]y=mx+b[/tex], where b is the y-intercept.

[tex]y+2=3x \\ y=3x-2[/tex]

We can verify using the attached graph that both points lie on this line.

Answer:

1. [tex]\frac{x}{x+3}+\frac{x+2}{x+5}[/tex] = [tex]\frac{2x^2+10x+6}{(x+3)(x+5)}\\[/tex]

2. [tex]\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}[/tex] = [tex]\frac{1}{(x+2)(x-4)}[/tex]

3. [tex]\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}[/tex] = [tex]\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}[/tex]

4. [tex]\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}[/tex] = [tex]\frac{1}{(x-2)(x-4)}[/tex]

Step-by-step explanation:

1. [tex]\frac{x}{x+3}+\frac{x+2}{x+5}[/tex]

Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

[tex]=\frac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}\\=\frac{x^2+5x+(x)(x+3)+2(x+3)}{(x+3)(x+5)} \\=\frac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)} \\=\frac{x^2+x^2+5x+3x+2x+6}{(x+3)(x+5)} \\=\frac{2x^2+10x+6}{(x+3)(x+5)}\\[/tex]

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.

2. [tex]\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}[/tex]

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)

Putting factors

[tex]=\frac{x+4}{(x+3)(x+2)}*\frac{x+3}{(x-4)(x+4)}\\\\=\frac{1}{(x+2)(x-4)}[/tex]

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.

3. [tex]\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}[/tex]

Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)

Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)

Putting factors

[tex]\frac{2}{(x+3)(x-3)}-\frac{3x}{(x+3)(x-2)}[/tex]

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)

[tex]\frac{2(x-2)-3x(x+3)(x-3)}{(x+3)(x-3)(x-2)}[/tex]

[tex]=\frac{2(x-2)-3x(x+3)}{(x+3)(x-3)(x-2)}\\=\frac{2x-4-3x^2-9x}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-9x+2x-4}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}[/tex]

Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.

4. [tex]\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}[/tex]

Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

[tex]\frac{x+4}{(x-2)(x+3)}\div\frac{(x-4)(x+4)}{x+3}[/tex]

Converting ÷ sign into multiplication we will take reciprocal of the second term

[tex]=\frac{x+4}{(x-2)(x+3)}*\frac{x+3}{(x-4)(x+4)}\\=\frac{1}{(x-2)(x-4)}[/tex]

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.

The given equations are the algebric equations for obtaining solution the equation can be simplified by algebric operations.

1).

[tex]\dfrac{x}{x+3} + \dfrac{x+2}{x+5}[/tex]

Taking LCM of denomenator (x+3) and (x+5).

[tex]=\dfrac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}[/tex]

Further simplification has been done by multtiplication in the numerator.

[tex]=\dfrac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)}=\dfrac{2x^2+10x+6}{(x+3)(x+5)}[/tex]

2).

[tex]\dfrac{x+4}{x^2+5x+6}\times \dfrac{x+3}{x^2-16}[/tex]

For further simplification of above equation factorization of [tex]x^2+5x+6[/tex] and [tex]x^2-16[/tex] has been performed.

[tex]= \dfrac{x+4}{(x+3)(x+2)}\times \dfrac{x+3}{(x-4)(x+4)}[/tex]

[tex]= \dfrac{1}{(x+2)(x-4)}[/tex]

3).

[tex]\dfrac{2}{x^2-9}-\dfrac{3x}{x^2-5x+6}[/tex]

For further simplification of above equation factorization of [tex]x^2-5x+6[/tex] and [tex]x^2-9[/tex] has been performed.

[tex]=\dfrac{2}{(x-3)(x+3)}-\dfrac{3x}{(x-3)(x-2)}[/tex]

Taking LCM of denomenator (x+3)(x-3) and (x-3)(x-2).

[tex]=\dfrac{(2\times(x-2))-(3x\times(x+3))}{(x-3)(x+3)(x-2)}=\dfrac{2x-4-3x^2-9x}{(x-3)(x+3)(x-2)}[/tex]

[tex]= -\dfrac{3x^2+7x+4}{(x-3)(x+3)(x-2)}[/tex]

4).

[tex]\dfrac{\dfrac{x+4}{x^2-5x+6}}{\dfrac{x^2-16}{x+3}}[/tex]

For further simplification of above equation factorization of [tex]x^2-5x+6[/tex] and [tex]x^2-16[/tex] has been performed.

[tex]=\dfrac{\dfrac{x+4}{(x-3)(x-2)}}{\dfrac{(x-4)(x+4)}{x+3}}=\dfrac{x+3}{(x-3)(x-2)(x-4)}[/tex]

For more information, refer the link given below

https://brainly.com/question/21450998

Answer:

D. –X+XY–7y

Step-by-step explanation:

We just have to combine (add) the similar terms... so all terms that have an x in them for example.

–3x + 2xy + 4y – xy + 2x – 11y

Let's first re-write it placing similar terms next to each other

(-3x + 2x) + (2xy - xy) + (4y - 11y)

Then we sum them up, for each similar terms

1x + 1xy -7y

so, x + xy -7y

Answer D.

Answer:

about 0.81 miles

Step-by-step explanation:

Alyssa's route can be considered a right triangle with legs of length 19 and 28 (hundredths). The Pythagorean theorem tells us the hypotenuse (x) will satisfy ...

x^2 = 19^2 +28^2

x^2 = 1145

x = √1145 ≈ 34 . . . . hundredths of a mile

Then Alyssa's total route is ...

0.19 + 0.28 + 0.34 = 0.81 . . . . miles

Answer:

about 0.81 miles

Step-by-step explanation:

Alyssa's route can be considered a right triangle with legs of length 19 and 28 (hundredths). The Pythagorean theorem tells us the hypotenuse (x) will satisfy ...

x^2 = 19^2 +28^2

x^2 = 1145

x = √1145 ≈ 34 . . . . hundredths of a mile

Then Alyssa's total route is ...

0.19 + 0.28 + 0.34 = 0.81 . . . . miles

Answer:

1/3

Step-by-step explanation:

if you multiply 24 by 1/3, you recieve 8 which is the reduced dilation

Answer:

  (3, 5, 2)

Step-by-step explanation:

Many authors interpret the triangle inequality to mean the sum of the two short sides must exceed the length of the long side. For side measures 2, 3, 5, the sum of the two short sides is exactly equal to the long side, in violation of the triangle inequality. Hence (3, 5, 2) is not a triangle.

___

Comment on the triangle inequality

Other authors allow the "or equal to" case, meaning sides of lengths 2, 3, 5 will be considered to be a triangle because 2+3=5. This interpretation of the triangle inequality will result in no solution to your question.

A (3, 5, 2) "triangle" will look like a line segment of length 5. It will have an area of zero.

Answer:

The answer to your question would be

3, 5, 2.

Answer:

1 pi: 3pi

Step-by-step explanation:

Step 1: Formula of surface area and volume of sphere

Surface area of sphere = 4 x pi x r^2

Volume of sphere = 4 x pi x r^3

                                 3

Step 2: Apply values in the formula

r = radius

radius = diameter/2

r=18/2 = 9

S.A = 4 x pi x 9^2

S.A = 324pi

Volume = 4 x pi x 9^3

                3

Volume = 972pi

Step 3 : Show in ratio

Surface area : Volume

324pi : 972pi

= 1 pi: 3pi

Answer:

[tex]\frac{1}{10c^{3}d^{4} }[/tex]

Step-by-step explanation:

THE GIVEN EXPRESSION IS

[tex]\sqrt[3]{\frac{1}{1000c^{9}d^{12} } }[/tex]

To simplify this expression, we just have to apply the cubic root to each part of the fraction, as follows

[tex]\frac{\sqrt[3]{1} }{\sqrt[3]{1000c^{9} d^{12} } }[/tex]

Then, we solve each root. Remember that to solve roots of powers, we just need to divide the exponent of the power by the index of the root, as follows

[tex]\frac{1}{10c^{\frac{9}{3} } d^{\frac{12}{3} } }[/tex]

Therefore, the equivalent expression is

[tex]\frac{1}{10c^{3}d^{4} }[/tex]

So, the right answer is the third choice.

Answer:

x = - 10

Step-by-step explanation:

Answer:

x > 1/6

Step-by-step explanation:

Perform the indicated multiplication.  Then:

-16x + 8 < 2x + 5

Combining the x terms, we get:

8 < 18x + 5.

Simplifying further, we get:

3 < 18x, so that   3/18 < x, or x > 1/6

Answer:

  y = -6x -9

Step-by-step explanation:

The derivative is ...

  f'(x) = 2x

so the slope at x=-3 is ...

  f'(-3) = 2(-3) = -6

Then the point-slope form of the tangent line can be written ...

  y = m(x -h) +k . . . . . . for line with slope m through point (h, k)

  y = -6(x -(-3))+9 = -6x -18 +9 . . . . . filling in your values, eliminating parens

So, the slope-intercept equation of the tangent line is ...

  y = -6x -9

Let n = how much each new member must pay each month.

$160 - $28 = $132

n = $132 ÷ 12 months in a year

n = $11

You can also look at it this way:

n = (160 - 28)/12

After paying a $28 registration fee, the remaining cost of the membership is divided into 12 monthly payments of $11. The variable 'M' can be defined to represent the monthly payments.

The subject of the question is Mathematics, particularly in the area of basic algebraic operations and real life applications of mathematics. The problem involves calculating the cost of a membership at recplex. This is a real-world problem that uses mathematical concepts of subtraction and division. First, we isolate the cost that will be paid on a monthly basis. The total cost of the membership is $160, but $28 is paid up front; hence, the total amount to be divided into monthly payments is $160 - $28, which equals $132. The question doesn't specify the number of months, but since this is a yearly membership, we can assume it is 12. Therefore, $132 divided by 12 is $11 per month.

In this scenario, the variable could be defined as 'M', where 'M' represents the monthly payment.

https://brainly.com/question/32959670

#SPJ11

Answer:

Y = 2/3x - 3

Step-by-step explanation:

Recall the general equation for a straight line is

y = mx + b

where m is the gradient and b is the y-intercept

given 2 points whose coordinates are (x1, y1) and (x2, y2), m can be found with the following formula:

m = [tex]\frac{y1-y2}{x1-x2}[/tex]

in this case, x1 = 3, y1 = -1, x2 = 6, y2=1

applying these values to the formula for m will give

m =  (-1 -1) / (3-6) = 2/3

We can see immediately that only the first (top-most) answer has this value for m and we can guess that this is probably the answer.

But we can still check to confirm:

If we substitute this back into the general equation, we get:

y = (2/3)x + b

In order to find the value for b, we substitute any one of the 2 given points back into this equation. Lets choose (6,1)

1 = (2/3)(6) + b

1 = 4 + b

b = -3

Confirm  Y = 2/3x - 3 is the answer.

Answer:

Value of cos B is B)12/13

The value of cos B in triangle ΔABC cannot be definitively determined without additional information such as side lengths. However, assuming a right triangle configuration with an adjacent side of length 12 and a hypotenuse of length 13, the cos B could be calculated as 12/13.

In the triangle ΔABC, the value of cos B can be calculated if we know the measures of the sides of the triangle. Without the values of the sides, we can't give an exact value for cos B. However, from the given options, we would assume that the triangle is a right-triangle, and B is the angle formed by the adjacent side of length 12 and the hypotenuse of length 13. Thus, the value of cos B would be equal to the adjacent side (b) divided by the hypotenuse (c), which matches option B) 12/13.

Remember that in a right triangle:
The cosine of an angle (cos B) is defined as the ratio of the length of the adjacent side to the length of the hypotenuse. This formula, cos B = b/c is a direct application of the Pythagorean theorem.

https://brainly.com/question/11694323

#SPJ2