You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound of the blows exactly synchronized with the blows you see. And then you hear one more blow after you see the hammering stop. Explain how you calculate that Sally is 340 m away from you.?

Answer:

(a) 72°

(b) 40°

Explanation:

PENTAGON

First, we calculate the total angles in a Pentagon using:

180(n - 2)

Where n = number of sides of the polygon, in this case, 5.

Hence, the total angle in a polygon is

180(5 - 2) = 180 * 3 = 540°

Therefore, each angle will be:

540°/5 = 108°

Because the interior angle and exterior angle form a straight line (180°), the exterior angle of a regular pentagon will be:

180 - 108 = 72°

The exterior angle of a regular Pentagon is 72°

NONAGON

First, we calculate the total angles in a Nonagon using:

180(n - 2)

Where n = number of sides of the polygon, in this case, 9.

Hence, the total angle in a polygon is

180(9 - 2) = 180 * 7 = 1260°

Therefore, each angle will be:

1260°/9 = 140°

Because the interior angle and exterior angle form a straight line (180°), the exterior angle of a regular nonagon will be:

180 - 140 = 40°

The exterior angle of a regular Nonagon is 40°

Final answer:

Each exterior angle of a regular pentagon, which measures 72 degrees, is greater than each exterior angle of a regular nonagon, which measures 40 degrees, because the sum of the exterior angles of any polygon is always 360 degrees.

Explanation:

The question asks how the measure of each exterior angle of a regular pentagon compares to the measure of each exterior angle of a regular nonagon. To answer this, first, we need to understand that the sum of the exterior angles of any polygon is always 360 degrees, no matter the number of sides. Therefore, to find the measure of each exterior angle of a polygon, we simply divide 360 degrees by the number of sides.

For a pentagon, which has five sides, each exterior angle has a measure of 360 ÷ 5 = 72 degrees. For a nonagon, which has nine sides, each exterior angle has a measure of 360 ÷ 9 = 40 degrees. Therefore, the measure of each exterior angle of a regular pentagon is greater than the measure of each exterior angle of a regular nonagon.

Answer:

[tex]r_{P}=2.58 m[/tex]

Explanation:

If we want to find how far up the ladder can a person climb before the ladder begins to slip, the total force in the y-direction and the total torque must be zero, it is an equilibrium condition.

So, let's start whit y-direction forces.

[tex]\Sigma F_{y}=0[/tex]  

[tex]N_{L}-W_{L}-W_{P}=0[/tex]

So, we can find the normal force:

[tex]N_{L}=m_{L}g+m_{P}g=g(m_{L}+m_{P})=9.8(267+1068)=13083 N[/tex]

We know that the friction force is the product of the coefficient of static friction times the normal force. Let's find it.

[tex]F_{f}=\mu N_{L}=0.53*13083=6934 N[/tex]

Referent to the x-direction forces, we can say that the total sum must be equal to zero too.

[tex]\Sigma F_{x}=0[/tex]  

[tex] -N_{wall}+F_{f}=0[/tex]

[tex] N_{wall}=F_{f}=6934 N[/tex]

Now, as we said before, the total torque must be zero, so we have:

[tex]\Sum \tau=\tau_{wall}+\tau_{L}+\tau_{P}=0[/tex] (1)

We will choose the pivot point at the bottom of the ladder, then we have:

Each force acting on the ladder must be perpendicular to the ladder, so we need to use the components.        

[tex]\tau_{wall}=r_{wall}*N_{wall}sin(32.7)=8.6*6934*sin(32.7)=32215.8Nm[/tex] (positive due to the counterclockwise rotation)

[tex]\tau_{L}=r_{L}*W_{L}sin(57.3)=(8.6/2)*2616.6*sin(57.3)=-9468.2 Nm[/tex] (negative due to the clockwise rotation)

[tex]\tau_{P}=r_{P}*W_{P}sin(57.3)=r_{P}*10466.4*sin(57.3)=-r_{P}8807.6 Nm[/tex] (negative due to the clockwise rotation)

We use 57.3° because is the angle between the ladder weight vector and the ladder surface, we use the same angle to the person.

Now we can use (1) to find the distance

[tex]\Sum \tau=\tau_{wall}+\tau_{L}+\tau_{P}=32215.8-9468.2-r_{P}8807.6=0[/tex]

Therefore [tex]r_{P}=2.58 m[/tex]

I hope it helps you!

Answer:

v(t) = 27 units

Explanation:

The function s(t) represents the position of an object at time t moving along a line such that,

[tex]s(2)=146[/tex]

and

[tex]s(6)=254[/tex]

We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :

[tex]v(t)=\dfrac{s(6)-s(2)}{6-2}[/tex]

[tex]v(t)=\dfrac{254-146}{6-2}[/tex]

v(t) = 27 units

So, the  average velocity of the object is 27 units. Hence, this is the required solution.

Answer:

B. 66.4 V

Explanation:

for a Y-Y connection (star connection), the relationship between the line voltages and the phase voltages is governed by the formula:

[tex]V_{L} = \sqrt{3} (V_{ph})[/tex]

Where [tex]V_{L}[/tex] = Line Voltage = 115 V (AC there just shows that the current is alternating current )

and [tex]V_{ph}[/tex] = Phase Voltage

⇒  [tex]V_{ph}[/tex] =  [tex]V_{L}[/tex] / [tex]\sqrt{3}[/tex]

[tex]V_{ph}[/tex] = 115 / [tex]\sqrt{3}[/tex]

[tex]V_{ph}[/tex] = 66.4 V

Hence the secondary Line to neutral voltage is 66.4 Volts

The secondary line to neutral voltage is Option B 66.4 V.

Given that,

Based on the above information, the calculation is as follows:

[tex]V_{ph} = V_L \div \sqrt{3}\\\\= 115 \div \sqrt{3}[/tex]

= 66.4 V

Learn more: https://brainly.com/question/952353?referrer=searchResults

Answer:

Magnitude = 4.056 m

Direction = 42.3⁰

Explanation:

The vector is resolved in terms of the vertical and horizontal components. Let's look each of these separately.

The vector 4.40 is directed East. This automatically becomes a horizontal component.

But we know that there is a vector 3.40 North West. The angle the vector makes with the horizontal is 61⁰.

Resolving the vectors should yield the horizontal and vertical components:

Horizontal components

The first component is 4.40 m

The second one is derived by resolving 3.40 to the horizontal like this 3.40 × - cos 61⁰ = -1.648 m

Adding the horizontal component gives 4.40 m + ( -1.648 m) = 2.752 m

Vertical components

Resolve 3.40 with the angle 61⁰ like this: vertical comp = 3.41 × sin 61

                                                                                           = 2.98 m

The magnitude is given by √[(2.98)²+ (2.752)²] = 4.056 m Ans

The direction us given by tan⁻¹ (2.98/2.752) = 42.3⁰ Ans

Final answer:

The charge on A should be -2.0 C in order for the force on B to be zero.

Explanation:

In order for the force on charge B to be zero, the charge on A must be equal in magnitude but opposite in sign to the combined charge of charges C and D at the other corners of the square. Since both B and C have a charge of +1.0 C, A must have a charge of -2.0 C. This creates a symmetric distribution of charges, resulting in a net force of zero on charge B.

Explanation:

Radius , r = 7 m

Centripetal acceleration, a = 2.25 g = 22.07 m/s²

We have equation for centripetal acceleration

              [tex]a=\frac{v^2}{r}[/tex]

Substituting

              [tex]a=\frac{v^2}{r}\\\\22.07=\frac{v^2}{7}\\\\v=12.43m/s[/tex]

We have equation for frequency

             [tex]f=\frac{2\pi }{\omega }\\\\f=\frac{2\pi r}{v}\\\\f=\frac{2\pi \times 7}{12.43}=3.54Hz[/tex]

Revolutions per minute = 3.54 x 60 = 212.4

Revolutions per minute of rider is 212.4

Explanation:

We have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = 22.2 m/s    

     Time, t = 3.42 s

     Substituting

                      v = u + at  

                      22.2 = 0 + a x 3.42

                      a = 6.49 m/s²

     Acceleration is 6.49 m/s²

Average acceleration is 6.49 m/s²

Answer:

10,624J

Explanation:

KE = 1/2 m*v²

KE = 1/2 83*16²

KE = 41.5*256

KE = 10,624J

Answer:

neither one has a net force on it

Explanation:

Both vehicles are moving at steady velocity hence the acceleration zero.

since acceleration is zero , the net force on it is zero. therefore neither one has a net force on it

Answer:

2 and 4

Explanation:

Since it is at a position Q it is stationary ball, for a body to be at a point two opposite forces must act on it

Answer:

[tex]v_1=\frac{L}{t_1}[/tex]

[tex]v_2=\frac{-L}{t_2}[/tex]

[tex]v_{avg}=\frac{L-L}{t_1+t_2} =0[/tex]

Explanation:

Given:

Velocity of the athlete from start to the end of the pool in positive direction:

[tex]\rm velocity=\frac{displacement}{time}[/tex]

[tex]v_1=\frac{L}{t_1}[/tex]

Velocity of the athlete from end returning to the start of the pool in negative direction:

Here we have the negative displacement.

[tex]v_2=\frac{-L}{t_2}[/tex]

Now the total average velocity:

[tex]\rm v_{avg}=\frac{total\ displacement}{total\ time}[/tex]

Here we have total displacement as zero because the athlete is finally at the initial starting point.

so,

[tex]v_{avg}=\frac{L-L}{t_1+t_2} =0[/tex]

Final answer:

The symbolic average velocities of an athlete swimming the length of a pool are positive for the trip in one direction (v1 = L / t1) and negative for the return trip (v2 = -L / t2). These reflect the direction of motion related to the positive x-direction.

Explanation:

Average Velocities of an Athlete in a Pool

The average velocity of the athlete for the trip in the positive x-direction is the length of the pool L divided by the time taken t1, which can be symbolically written as v1 = L / t1. Since the swimmer is moving in the positive x-direction, the average velocity v1 is taken as positive.

For the return trip in the negative x-direction, the average velocity is the negative of the length of the pool L divided by the time taken t2, represented as v2 = -L / t2. The average velocity v2 is negative because the swimmer is moving in the opposite direction to the initial positive x-direction.

The concept of average velocity involves both the displacement of the swimmer and the time taken. If, at the end of two trips (to the end of the pool and back), the swimmer's displacement is zero (since they return to the start), the average velocity for the entire trip is also zero.

Answer:

The electric field at point a =( 0.232N/c)k

Explanation:

E = E1+E2=(6/2Eo)K+(-6/2Eo)[1-(2/(sqrtz^2+R^2)k

E= 6z/2Eo(sqrtz^2+R^2)k

E= (4.5×10^-12)×(2.56×10^-2) /2(8.85×10^-12)sqrt(2.56×10^-2)^2+(1.30×10^-2)^2k

E= 1.152×10^-13/(1.77×10^-11)×(2.8×10^-2)k

E= 1.152×10^-13/(4.956×10^-13)k

E=( 0.232N/c)K

Answer:[tex]\vec{C}-\vec{B}[/tex]

Explanation:

Given

[tex]\vec{A}[/tex] is displacement of student from Hostel to house

[tex]\vec{B}[/tex] is displacement of student from house to school

And [tex]\vec{C}[/tex] is displacement of student from Hostel to school    

According to the triangle law of vector addition  

If two vectors are acting on a body simultaneously that are shown by magnitude and direction by two sides of a triangle taken in order then the third side is the resultant of two vectors that are taken in opposite direction.

[tex]\vec{A}+\vec{B}=\vec{C}[/tex]

[tex]\vec{A}=\vec{C}-\vec{B}[/tex]

so option c is correct

Answer:

Explanation:

We know that flux is defined as the density of any energy field passing through a given area parallel to the area vector.

Mathematically:

[tex]\phi=\bar E.A\cos\theta[/tex]

where:

[tex]\phi=[/tex] flux through the area

[tex]A=[/tex] area of concern

[tex]\bar E=[/tex] density of energy field per unit area

[tex]\theta=[/tex] angle between the energy field lines and the normal to area.

When we hold a bucket in the rain then assuming that the base of the bucket is normal to the direction of rainfall then the angle between the area vector and the rain drop is zero when observed from inside.

The angle between the raindrops and the surface area of the bucket is 180 degrees. Hence the flux will be negative and in the outward direction of the bucket.

The value of flux will be zero when the base of the bucket has been cut and then hold in rain.

The electric flux can be defined as the property of an electric field that shows the number of electric field lines intersecting a given area.

The electric flux can be written in an equation form as given below.

[tex]\phi = EA cos\theta[/tex]

Where [tex]\phi[/tex] is the electric flux, E is the electric field, A is the area of surface and [tex]\theta[/tex] is the angle between the electric field lines and the normal (perpendicular) to A.

Let us consider that the base of the bucket is normal to the direction of the rainfall when we hold the bucket in rain. In this case, the angle between the raindrops and the normal to the surface will be zero inside the bucket.

From the outer surface, the angle formed between the surface area of the bucket and the direction of the rain is 180 degrees. When we put the value of the angle in the formula of flux, we will get a negative flux for the angle of 180 degrees in the outward direction of the bucket.

The flux depends on the surface area. If we cut the base of the bucket and hold it in rain then there will be no surface area that is intersecting by the rainfall. Hence the value of flux will be zero for the no surface area of the bucket.

To know more about the flux, follow the link given below.

https://brainly.com/question/7944455.

Answer:

8.00 kJ

Explanation:

The first thing is to determine what quantities are there.

the mass of water = 1 000 kg

initial velocity, u = 6 m/s

final velocity, v = 4 m/s

the generator is operating at 100 % efficiency, so there is no energy loss.

The kinetic energy, Ek is converted to electrical energy, therefore Ek = electrical energy.

The kinetic energy is calculated as follows:

Ek = 1/2 mv²

    = 1/2×(1 000)× (4)²

    = 8 000 J/s

    = 8.00 kJ  Ans

Answer:

a) v = 34.5 mph, b)   v = 50 mph

Explanation:

The average speed is defined.

             v = (x₂ -x₁) / (t₂ -t₁)

If the movement is with uniform speed we can also obtain the average speed, averaging the speeds with a time weight factor, if the time is equal for each speed

            v = (v₁ + v₂) / 2

a) For the outward journey

            v = (69.0 +0) / 2

            v = 34.5 mph

b) For the return trip

              v = (69.0 + 31.0) / 2

              v = 50 mph

Answer:

The number of grains of sand on all the beaches on Earth

Explanation:

if we assume grain of sand has an average size , then the number of grains of sand on all the beaches on Earth is roughly [tex]7.5 \times 10^{18}[/tex]

The total number of stars in the observable universe is roughly equivalent to 1 billion trillion. which is roughly  equal to the number of grains of sand on all the beaches on Earth.

Answer:

The net electric field = 1016.96 x 10 raised to power 3 N/C

Explanation:

The detailed steps and mathematical explanation is as shown in the attached file.

Answer:

0.0257259766982 m

Explanation:

[tex]P_2[/tex] = Atmospheric pressure = 101325 Pa

[tex]d_1[/tex] = Initial diameter = 1.5 cm

[tex]d_2[/tex] = Final diameter

[tex]\rho[/tex] = Density of water = 1000 kg/m³

h = Depth = 40 m

The pressure is

[tex]P_1=P_2+\rho gh\\\Rightarrow P_1=101325+1000\times 9.81\times 40\\\Rightarrow P_1=493725\ Pa[/tex]

From ideal gas law we have

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow \dfrac{P_1\dfrac{4}{3\times8}\pi d_1^3}{T_1}=\dfrac{P_2\dfrac{4}{3\times8}\pi d_2^3}{T_2}\\\Rightarrow \dfrac{P_1d_1^3}{T_1}=\dfrac{P_2d_2^3}{T_2}\\\Rightarrow d_2=(\dfrac{P_1d_1^3T_2}{P_2T_1})^{\dfrac{1}{3}}\\\Rightarrow d_2=(\dfrac{493725\times 0.015^3\times (20+273.15)}{101325\times (10+273.15)})^{\dfrac{1}{3}}\\\Rightarrow d_2=0.0257259766982\ m[/tex]

The diameter of the bubble is 0.0257259766982 m

Answer:

B

Explanation:

With projectiles, the maximum range is always achieved at a 45 degree launch angle.

Answer : The time passed in years is [tex]1.49\times 10^4\text{ years}[/tex]

Explanation :

Half-life = 5000 years

First we have to calculate the rate constant, we use the formula :

[tex]k=\frac{0.693}{t_{1/2}}[/tex]

[tex]k=\frac{0.693}{5000\text{ years}}[/tex]

[tex]k=1.39\times 10^{-4}\text{ years}^{-1}[/tex]

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  = [tex]1.39\times 10^{-4}\text{ years}^{-1}[/tex]

t = time passed by the sample  = ?

a = let initial amount of the reactant  = X

a - x = amount left after decay process = [tex]\frac{X}{8}[/tex]

Now put all the given values in above equation, we get

[tex]t=\frac{2.303}{1.39\times 10^{-4}}\log\frac{X}{(\frac{X}{8})}[/tex]

[tex]t=14962.706\text{ years}=1.49\times 10^4\text{ years}[/tex]

Therefore, the time passed in years is [tex]1.49\times 10^4\text{ years}[/tex]

Answer:

Part A 12.9 m/s

Part B 36.9 m

Explanation:

Henrietta ran at 3.95 m/s. She was 6.5 seconds away from from the window when Bruce throws the bagel. This equates to a distance of d

[tex]d= 3.95\times6.5=25.675[/tex] (distance = speed x time)

If Bruce throws the bagel horizontally, the vertical component of the motion is purely under gravity with initial speed of 0 m/s. Using one of the equations of motion for the vertical motion,

[tex]h=ut+0.5at^2[/tex]

h = 39.9 m (height of the building)

a = 9.8 (acceleration of gravity)

[tex]t=\sqrt{\dfrac{2\times39.9}{9.8}}= 2.85[/tex]

During this time, Henrietta will have travelled another distance e

[tex]e =3.95\times2.85=11.2575[/tex]Therefore, Henrietta would have jogged a total distance of 25.675 + 11.2575 m = 36.9325 m.

The horizontal speed with which Bruce must throw the bagel is the total distance travelled by Henrietta divided by the time it takes to land vertically i.e.

[tex]v=\dfrac{36.9325}{2.85}=12.96[/tex]

Therefore, the speed of throw is 13.0 m/s.

Henrietta was 36.9 m from the window when she caught the bagel.

Part A. The speed at which the bagel was thrown horizontally is 12.9 m/s.

Part B. The total distance traveled by Henrietta when she caught the bagel from the window is 36.9325 m.

Given that, the speed of Henrietta is 3.95 m/s. When Bruce throws the bagel, the time difference between both of them is 6.5 seconds. Hence the distance can be calculated as given below.

Distance D = Speed [tex]\times [/tex] Time

[tex]D = 3.95 \times 6.50[/tex]

[tex]D = 25.675 \;\rm m[/tex]

Part A

Given that Bruce throws the bagel horizontally, then during the motion, the initial speed will be zero and the vertical component will have gravitational acceleration. In this case, the time required in motion can be calculated by the equation given below.

[tex]s = ut + \dfrac {1}{2} at^2[/tex]

Where, s is the distance, a is the acceleration, t is time and u is the initial speed.

For the horizontal motion, s = 39.9 m, g = 9.8 m/s^2 and u = 0 m/s. The time will be,

[tex]39.9 = 0 + \dfrac {1}{2}\times 9.8\times t^2[/tex]

[tex]t = 2.85 \;\rm s[/tex]

The time required to reach the bagels is 2.85 seconds. But in this time, the distance traveled by Henrietta is given below.

[tex]D' = 2.85 \times 3.95[/tex]

[tex]D' = 11.2527 \;\rm m[/tex]

Hence the total distance traveled by Henrietta is given below.

Distance = 25.675 + 11.2527

Distance = 36.9325 m.

The speed of the bagel is calculated as given below.

Speed = Total Distance / Time

[tex]v = \dfrac {36.9325 }{2.85}[/tex]

[tex]v = 12.9 \;\rm m/s[/tex]

Hence we can conclude that the speed at which the bagel was thrown horizontally is 12.9 m/s.

Part B

The total distance traveled by Henrietta is 36.9325 m. At this distance, Henrietta catches the bagel from the window.

To know more about the speed, follow the link given below.

https://brainly.com/question/7359669.

Answer:

D. The net force on an object applied over a distance

Explanation:

Work can be defined as the product of force multiplied by a distance

Where

F = force [Newtons]

d = distance = [meters]

Therefore:

Work = F * d

Work in units of Joules [J]

Answer:

Compression Test

Explanation:

The Specimen is undergoing a compression test. It is similar to tensile test with the difference that the force is compressive and applied along the direction of stress. Both Tensile and compression tests are performed on Universal Testing machine. Compression test is done to determine the product's reaction when it is compressed, squashed and crushed.

Explanation:

If a positive test charge is placed in an electric field, it will exert the force in the test charge in the direction of electric field vector. We know that the direction of electric field is given by electric field lines. The field lines for a positive charge is outwards. The electric force acting on the charge is given by :

F = q E

Hence, this is the required solution.

Final answer:

A positive test charge placed in an electric field will experience a force in the direction of the field lines, being repelled by positive charges and attracted to negative charges.

Explanation:

When a positive test charge is placed in an electric field, it experiences a force. This force is in the direction of the electric field lines. So, a positive test charge will be repelled by a positive charge and attracted to a negative charge, consistent with Coulomb's law, which states that like charges repel and unlike charges attract. Additionally, if a positive test charge is placed near two negative charges, it will be attracted towards both, as the electric field lines point towards negative charges.

The electric field vectors point in the direction that a positive test charge would move, which is away from positive charges and towards negative charges. By studying various positions of a test charge and the forces experienced, we can map out these vectors to visualize the electric field.

Answer:

The correct answer is: Free Jazz.

Explanation:

Free jazz is a music genre developed around the year 1964 and is considered a subgenre of Jazz where musicians are asked to break the traditional conventions related to the interpretation of jazz music.

In free jazz, the most important technique is improvisation, where musicians simply perform and play their instruments freely.

The key to performing free jazz is to try to express spontaneous feelings through the instrument, while not being aware of certain conventions traditional to jazz music.

In this particular case, to the question Which style of jazz music released performers from traditional rules and placed importance on each performer contributing his or her own feelings for the music in the moment, the correct answer is: Free Jazz.

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 95 m/s

        Acceleration, a = -0.700 m/s²  

        Time, t = 1 minute = 60 seconds

     Substituting

                      s = ut + 0.5 at²

                      s = 95 x 60 + 0.5 x -0.700 x 60²

                      s = 4440 m

      Distance traveled is 4440 m

The airplane travels 4440 m in 1 minute

To find the distance the airplane will travel in 1.00 minute, use the equation d = [tex]vi * t + (1/2) * a * t^2[/tex]e, vi is the initial velocity, t is the time, and a is the acceleration. Substitute the given values into the equation and solve to find the distance.

To find the distance the airplane will travel in 1.00 minute, we need to use the equation:

d = vi * t +[tex](1/2) * a * t^2[/tex]

Where:

d = distance traveled

vi = initial velocity

t = time

a = acceleration

Using the given values:

vi = 95.0 m/s (initial velocity)

a = -[tex]0.700 m/s^2[/tex] (deceleration)

t = 1.00 minute = 60 seconds

Now we can substitute the values into the equation:

d = (95.0 * 60) + (1/2) * [tex](-0.700) * (60^2)[/tex]

Solving this equation will give us the distance traveled by the airplane in 1.00 minute.

Answer:

e. 2800 m/s²

Explanation:

Acceleration: This is the rate of change of velocity. The S.I unit of acceleration is m/s²

Applying Newton's equation of motion,

a = (v-u)/t ................................... Equation 1

Where a = acceleration, v = Final velocity, u = Initial velocity, t = time.

Note: Let the direction of the initial velocity be negative, and the direction of the final velocity be positive

Given: v = 26 m/s, u = -30 m/s, t = 20 ms = 0.02 s

Substitute into equation 1

a = [26-(-30)]/0.02

a = (26+30)/0.02

a = 56/0.02

a = 2800 m/s².

Hence the right option is e. 2800 m/s²

Answer:

Growth of Bread Mold

Explanation:

The controlled variables are the type of containers used and also the different temperatures.

In Sarah's experiment about the influence of temperature on bread mold, the dependent or responding variable is the growth of bread mold. Her experiment is structured to determine if the mold's growth changes in response to different temperatures.

In Sarah's experiment, the dependent or responding variable is the growth of the bread mold. The dependent variable is what changes or responds based on the changes in the independent variable. In this case, Sarah is checking to see if different temperatures (the independent variable) cause different rates of bread mold growth (the dependent variable). An experiment like this can demonstrate how environmental factors, like temperature, affect living organisms such as mold.

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