You need a 40% alcohol solution. On hand, you have a 100 mL of a 25% alcohol mixture. You also have 65% alcohol mixture. How much of the 65% mixture will you need to add to obtain the desired solution

Answers

Answer 1

Answer: 60 ml of the 65% mixture will you need to add to obtain the desired solution.

Explanation:

According to the dilution law,

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

= concentration of given alcohol solution = 25 %

[tex]V_1[/tex] = volume of given alcohol solution = 100 ml

[tex]C_2[/tex] = concentration of another alcohol solution=65 %

[tex]V_2[/tex] = volume of another acid solution= x ml

[tex]C_3[/tex]  = concentration of resulting alcohol solution = 40 %

[tex]V_3[/tex] = volume of resulting acid solution = (100+x)

[tex]25\times 100+65\times x=40\times (100+x)[/tex]

[tex]x=60ml[/tex]

Thus 60 ml of the 65% mixture will you need to add to obtain the desired solution.


Related Questions

How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2S3 + HCl (Remember to balance the equation.)

Answers

Answer:

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Explanation:

Step 1: Data given

Number moles of H2S = 3.0 moles

Step 2: The balanced equation

2HSbCl4 + 3H2S → Sb2S3 + 8HCl

Step 3: Calculate moles HCl

For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl

For 3.0 moles H2S we'll have 8.0 moles HCl

Step 4: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 8.0 moles * 36.46 g/mol

Mass HCl = 291.7 grams

We will produce 8.0 moles of HCl , this is 291.7 grams HCl

Final answer:

From the balanced equation, it is determined that 2 moles of HCl are produced from 1 mole of HSbCl4. Therefore, 6 moles of HCl will be produced from the reaction of an excess of HSbCl4 with 3 moles of H2S.

Explanation:

The balanced equation for the reaction is:

HSbCl4 + H2S → Sb2S3 + 2HCl

The mole ratio between HSbCl4 and HCl is 1:2, which means that for every 1 mole of HSbCl4, 2 moles of HCl are produced.

Since there is an excess of HSbCl4, we can assume that all 3 moles of H2S will react.

Therefore, the number of moles of HCl produced will be:

(3 moles H2S) x (2 moles HCl/1 mole HSbCl4) = 6 moles HCl

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