You have an SRS of 23 observations from a large population. The distribution of sample values is roughly symmetric with no outliers. What critical value would you use to obtain a 95% confidence interval for the mean of the population?

Answers

Answer 1

Answer:

Therefore the critical value= 2.073

Step-by-step explanation:

The number of observation = 23.

For the mean of the population the confidence interval  = 95%.

Here mean and stander deviation of the distribution is not given. So we use t distribution.

T distribution is called as student's t distribution.

Sample number =n =23.

Confidence level = c= 95% =0.95

The degree of freedom is sample size decreased by 1

df=n-1 = 23-1 =22.

The critical value [tex]t^*[/tex] can be found in the row df = 22 and column with 0.95 of the T distribution table .

[tex]t^*[/tex] = 2.073

Therefore the critical value= 2.073

Answer 2

To calculate the critical value for a 95% confidence interval when the sample size is small (less than 30), we need to use the t-distribution. The critical value from the t-distribution will depend on the sample size (specifically, the degrees of freedom) and the desired level of confidence.
Here's how you could calculate this step by step without using the Python function mentioned:
**Step 1: Identify the desired confidence level.**
For a 95% confidence interval, we are interested in capturing the central 95% of the t-distribution.
**Step 2: Determine the degrees of freedom.**
The degrees of freedom (df) for a t-distribution is equal to the sample size minus 1. So with 23 observations, df = 23 - 1 = 22.
**Step 3: Find the critical t-value.**
We want to find the critical t-value for the t-distribution with 22 degrees of freedom that corresponds to the 95% confidence interval. This means we want to find the t-value such that 95% of the distribution lies between -t and +t. Because the t-distribution is symmetric, we can look up the critical value for 97.5% (to split the remaining 5% evenly on both tails of the distribution).
Using a t-distribution table (often found in the appendices of statistics textbooks) or a statistical computing resource, you would find the t-value that corresponds to a cumulative probability of 0.975 with 22 degrees of freedom.
**Step 4: Interpret the table or resource correctly.**
If you were looking at a table, you would look down the degrees of freedom column until you find 22, then right to the column that represents the 97.5% cumulative probability (remember, this is for the two-tailed test). That entry is the critical t-value that corresponds to a 95% confidence interval.
**Step 5: Use the critical t-value for constructing the interval.**
Once you have the critical t-value, you would use it to construct the confidence interval for the population mean by multiplying this t-value by the standard error of the sample mean and then add and subtract this value from the sample mean.
**Important Note:**
Please be aware that the exact t-value varies depending on the source of the statistical tables or the statistical software being used. The value also depends on the precision (number of decimals) presented in the table.
If you perform these steps with a standard statistical table or software, you should find that the critical t-value for a 95% confidence interval with 22 degrees of freedom is approximately 2.074.


Related Questions

A boat is spotted in the water with an angle of depression of 25° from the top of a lighthouse that is 89 feet tall. To the nearest foot, how far away is the boat from the base of the lighthouse?A)37 feetB)42 feetC)98 feetD)191 feet

Answers

Answer:

D)191 feet

Step-by-step explanation:

Let the height of the light house be |AB| and the Boat be at point C as shown in the diagram.

The angle of depression of the boat from the top A of the lighthouse is given as 25 degrees

Angle BCA = 25 degrees (Alternate Angles are Equal)

We want to determine the distance of the boat C from the base of the lighthouse B i.e. |BC|

[tex]Tan\alpha =\frac{opposite}{adjacent}[/tex]

Tan 25=[tex]\frac{89}{|BC|}[/tex]

Cross multiply

|BC| X tan 25 =89

|BC| = [tex]\frac{89}{tan 25}[/tex]=190.86 feet

The distance of the boat C from the base of the lighthouse B is 191 feet (to the nearest feet).

A plastic rod 1.5 m long is rubbed all over with wool, and acquires a charge of -9e-08 coulombs. We choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out of the page. In order to calculate the electric field at location A = < 0.7, 0, 0 > m, we divide the rod into 8 pieces, and approximate each piece as a point charge located at the center of the piece. 1. What is the length of one of these pieces? 2. What is the location of the center of piece number 2? 3. How much charge is on piece number 2?

Answers

Answer:

Answer:

a) k = 0.1875 m

b) r2 = 0.46875 m

c) q = -1.125*10^-8 C

Step-by-step explanation:

Given:

- The total Length of rod L = 1.5 m

- The total charge of the rod Q = -9 * 10^8 C

- Total section of a rod n = 8

Find:

1. What is the length of one of these pieces?

2. What is the location of the center of piece number 2?

3. How much charge is on piece number 2?

Solution:

- The entire rod is divided into 8 pieces, so the length of each piece would be k:

                                     k = L / n

                                     k = 1.5 / 8

                                     k = 0.1875 m

- The distance from center of entire rod and center of section 2 is 2.5 times the section length

                                     r2 = 2.5*k

                                     r2 = 2.5*(0.1875)

                                     r2 = 0.46875 m

- Assuming the charge on the rod is uniformly distributed. The the charge for each section of rod is given by q:

                                     q = Q / n

                                     q = -9 * 10^8 / 8

                                     q = -1.125*10^-8 C

Final answer:

The length of one of the eight pieces of the rod is 0.1875 m. The center of piece number 2 is at <0.28125, 0, 0> m. The charge on piece number 2 is -1.125e-08 Coulombs.

Explanation:

The problem involves the concepts of electric field, charge distribution, and coordinate system in Physics. Let's answer the question part by part:

The length of one of these pieces is the total length divided by the number of pieces. That is, 1.5 m / 8 = 0.1875 m.The center of piece number 2 would be one and a half times the length of one piece, to the right of the origin in the x-direction; hence, it is at <0.28125, 0, 0> m.The charge on piece number 2 is the total charge divided by the number of pieces. That is, -9e-08 C / 8 = -1.125e-08 Coulombs.

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Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationalized.

Answers

Answer:

the answer is 7

Step-by-step explanation:

angle 30°

x=14/2

x=7

The value of x is 7 cm.

How to solve the variable?

If you have the hypotenuse, multiply it by sin(θ) to get the length of the side opposite to the angle.

y = 14* sin 30°

y = 14* 0.5

y = 7

y = 7cm

What's the base of a triangle?

The bottom line of a triangle is the base of the triangle, and it can be one of the three sides of the triangle. In a triangle, one side is the base side and the remaining two sides can be the height or the hypotenuse side.

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Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.
y = 3/4x + 1
3x − 4y = −4
4x − 3y = −3
y – 2 = –3/4(x – 4)
y + 2 = 3/4 (x+4)

Answers

Option A: [tex]y=\frac{3}{4}x+1[/tex] is the equation of the line.

Option E: [tex]y+2=\frac{3}{4}(x+4)[/tex] is the equation of the line.

Explanation:

Given that the line is [tex]3 x-4 y=7[/tex] and passes through the point [tex](-4,-2)[/tex]

We need to determine the equation of the line.

Formula:

The equation of the line can be determined using the formula,

[tex]y-y_1=m(x-x_1)[/tex]

Slope:

Since, the lines are parallel, from the equation [tex]3 x-4 y=7[/tex], we shall determine the slope.

Thus, we have,

[tex]-4 y=-3x+7[/tex]

   [tex]y=\frac{3}{4} x+\frac{7}{4}[/tex]

Thus, the slope of the equation is [tex]m=\frac{3}{4}[/tex]

Equation of line:

Substituting [tex]m=\frac{3}{4}[/tex] and the point [tex](-4,-2)[/tex] in the formula, we get,

[tex]y+2=\frac{3}{4}(x+4)[/tex]

Hence, the equation of line is [tex]y+2=\frac{3}{4}(x+4)[/tex]

Thus, Option E is the correct answer.

Let us write the equation of line [tex]y+2=\frac{3}{4}(x+4)[/tex] in slope - intercept form.

Thus, we have,

[tex]y+2=\frac{3}{4}x+3[/tex]

     [tex]y=\frac{3}{4}x+3-2[/tex]

     [tex]y=\frac{3}{4}x+1[/tex]

Thus, the equation of the line is [tex]y=\frac{3}{4}x+1[/tex]

Hence, Option A is the correct answer.

Andy is thinking of a number that has a digit less than 5 in the tens place. It has a digit greater than 7 in the ones place. Fill in the bubble next to all the numbers that could be Andy's number

Answers

Andy 's Number = {18,19,10,28,29,20,38,39,30,48,49 or 40}

Step-by-step explanation:

Here, given:

Let us assume the number on Tens place  = M

The number in Units place  = N

So, the actual value of the number   = 10 M + N

The number can be written as MN.

Now, The value of M ( Tens digit) is Less than 5.

So, M  = 1, 2 , 3 or 4  ( 0 not included)

Also, The value of N(Unit digit)  is greater than 7.

So, N  = 8, 9 or 0  ( 0  included)

So, by combining all possibilities for M and N , the possible number chosen by Andy can be expressed as MN :

Number = {18,19,10,28,29,20,38,39,30,48,49 or 40}

Any number can be chosen from the above set as all the numbers match the given restrictions.

1. The difference of a number and 3 equals 5
added to twice the number. Find the number.

Answers

Answer:

  -8

Step-by-step explanation:

Let n represent the number. Then we have ...

  n -3 . . . . the difference of a number and 3

  = . . . . . .  equals

  5 +2n . . . 5 added to twice the number

Adding -n-5 to both sides of the equation gives ...

  n -3 -n -5 = 5 +2n -n -5

  -8 = n . . . . . simplify

The number is -8.

Steve, an entrepreneur, decides to open a flower shop and looks for an appropriate location for his shop. He wants to use the center-of-gravity method for the purpose. He researches the zip codes in his area and finds the following information: Identify a true statement about the best center of gravity for the possible shop location.
A) The x-axis and the y-axis are less than 5.0.
B) The x-axis is less than 7.0 and the y-axis is more than 7.0.
C) The x-axis is more than 7.0 and the y-axis is less than 7.0.
D) The x-axis and the y-axis are more than 7.0.

Answers

Answer:

C

Step-by-step explanation:

The x-axis is more than 7.0 and the y-axis is less than 7.0.

Cheers

Jesse takes his dog and cat for Their annual vet visit. Jesse's dog weigh's 23 pounds. The vet tells him his cat weighs 5/8 as much as his dogs weighs. How much does his cat weigh

Answers

Answer:

14.375 pounds

Step-by-step explanation:

Jesse's dog: 23 lb

Cat: 5/8*23=115/8

Therefore, Jesse's cat weighs 14.375 pounds

Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6 how much would her bucket weigh if she took out the two items.

Answers

Answer:

[tex]2\frac{1}{6}[/tex] pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

[tex]\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}[/tex]

Let us convert mixed fractions into improper fractions as:

[tex]1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}[/tex]

Combine numerators:

[tex]\text{Weight of bucket}=\frac{36-10-13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=2\frac{1}{6}[/tex]

Therefore, the weight of the bucket is [tex]2\frac{1}{6}[/tex] pounds.

9-114. While setting up a mathematical sentence to solve a problem, Paulina and Aliya came up with the equations below. Since the equations did not look alike, the girls turned to you for help. Paulina: 4x+2y=6 Aliya: 12x+6y=18

Answers

Step-by-step explanation:

Below is an attachment containing the solution.

Final answer:

Paulina and Aliya's equations, 4x+2y=6 and 12x+6y=18, are multiples of each other. This means they represent the same line and indicate an infinite number of solutions rather than a single intersection point typically sought after in a system of distinct linear equations.

Explanation:

Paulina and Aliya have created linear equations to solve a mathematical problem. Paulina has the equation 4x+2y=6 and Aliya has 12x+6y=18. At a glance, these equations may look different, but upon closer inspection, Aliya's equation is actually just Paulina's equation multiplied by 3. This realization is pertinent because it suggests both equations represent the same line. Therefore, these two equations should have the same solution set.

To analytically solve simultaneous equations, one could use methods such as substitution, elimination, or matrix and determinant-based approaches. Using elimination or substitution, we aim to isolate one variable and solve for it. For example, because Aliya's equation is a multiple of Paulina's, if they were meant to be a system of separate lines, one way to solve them would be to simplify Aliya's equation by dividing by 3, revealing it to be identical to Paulina's, which indicates that this system has an infinite number of solutions (all points on the line represented by the equation).

If a system has two distinct equations, elimination involves adding or subtracting equations from one another to eliminate one of the variables, and substitution involves solving for one variable in terms of the other and then substituting this expression into the other equation. When equations are actually multiples of each other, this indicates either an infinite number of solutions or no solutions dependant if the equations are consistent or inconsistent respectively.

tickets for a harlem globetrotter show cost $28 general admission, $43 courtside, or $173 bench seats. Nine times as many general admission tickets were sold as bench tickets, & the number of general admission tickets sold was 55 more than the sum of the number of courtside tickets & bench tickets. Sales of all three kinds of ticks totaled $97,605. How many of each kind of ticket were sold algebra

Answers

Answer:

general admission tickets  1170

courtside tickets  985

tickets bench seats.  130

Step-by-step explanation:

To solve the problem, it is necessary to generate a system of equations with the information provided by the statement.

First be

x = # general admission tickets

y = # courtside tickets

z = # tickets bench seats.

The first equation would be that they sold nine times more general admission tickets than bench seats tickets.

That is: x = 9 * z (1)

And the second equation is that the number of general admission tickets sold was 55 more than the sum of the number of courtside tickets and bench seats tickets.

That is: x = 55 + y + z (2)

Now the third equation would be the money raised.

28 * x + 43 * y + 173 * z = 97605 (3)

Now if I replace I rearrange (1):

z = x / 9 (4) and replacement in 2, I have:

x = 55 + y + x / 9, rearranging:

y = (8/9) * x - 55 (5)

Now replacing (4) and (5) in 3, we have:

28 * x + 43 * ((8/9) * x - 55) + 173 * (x / 9) = 97605

Solving the above:

x = 1170, therefore

y = (8/9) * 1170 55 = 985

z = 1170/9 = 130

We can confirm this with equation (3)

28 * x + 43 * y + 173 * z = 97605

28 * 1170 + 43 * 985 + 173 * 130 = 97605

Final answer:

450 general admission tickets, 171 courtside tickets, and 50 bench tickets were sold for the Harlem Globetrotter show.

Explanation:

Let's assign variables to represent the number of tickets sold for each category:

Lets  x  = number of general admission tickets sold

Lets  y   = number of courtside tickets sold

Lets  z  = number of bench tickets sold

According to the given information:

The cost of the general admission ticket = $28

The cost of the courtside ticket = $43

The cost of the bench ticket = $173

There were 9 times as many general admission tickets sold as bench tickets: x = 9z

The number of general admission tickets sold was 55 more than the sum of the courtside and bench tickets: x = y + z + 55

The total sales for all three types of tickets was $97,605: 28x + 43y + 173z = 97605

Now, we have a system of three equations with three variables:

x = 9z

x = y + z + 55

28x + 43y + 173z = 97605

We can use substitution or elimination method to solve this system of equations. Solving this system, we find that x = 450, y = 171, and z = 50. Therefore, 450 general admission tickets, 171 courtside tickets, and 50 bench tickets were sold for the Harlem Globetrotter show.

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Give a big-O estimate for the number of operations, where an operation is a comparison or a multiplication, used in this segment of an algorithm (ignoring comparisons used to test the conditions in the for loops, where a1, a2, ..., an are positive real numbers). m :

Answers

Answer:

O(n2)

Step-by-step explanation:

the first iteration algorithm of the i-for loop (the outer loop), the j-for loop (the inner loop) will run 2 to

n times which is represented as

(n − 1 times).

the second iteration algorithm of the i-for loop, the j-for loop will run 3 to n times represented as

(n − 2 times).

the third to the last iteration algorithm of the i-for loop, the j-for loop will run n − 1 to n times (2 times).

And the second to the last iteration of the i-for loop, the j-for loop will run from n to n times (1 time)

For the last iteration of the i-for loop, the j-for loop will run 0 times because i + 1 > n.

Now we know that the number of times the loops are run is

1 + 2 + 3 + . . . + (n − 2) + (n − 1) = n(n − 1)/2

So we can express the number of total iterations as n(n − 1)/2.

Since we have two operations per loop (one comparison and one multiplication), we have

2 ·n(n−1)/2 = n

2 − n operations.

So f(n) = n2 − n

f(n) ≤ n2

for n > 1.

Therefore, the algorithm is O(n2) with

C = 1 and k = 1.

What is the answer to this question??

Answers

Option B:

Point R on the number line best represents [tex]\frac{-6}{2}[/tex]

Solution:

In the number line,

The numbers which are left side of 0 are -1, -2, -3, -4, -5, -6, -7, -8.

The numbers which are right side of 0 are 1, 2, 3, 4, 5, 6, 7, 8.

Q is 6 points left of 0. That is Q = -6

R is 3 points left of 0. That is R = -3

S is 2 points left of 0. That is s = -2

T is 3 points right of 0. That is T = 3

[tex]$\frac{-6}{2}=-3[/tex]

In the number line -3 is the point of R.

Therefore point R on the number line best represents [tex]\frac{-6}{2}[/tex].

Option B is the correct answer.

hey, help me with this pls i only have 10 minutes. 30 points each :)

Answers

Answer:

y=-2x

Step-by-step explanation:

First you want to remember rise over run. Your rise is -2 and your run is 1. So -2/1 is your answer. And -2/1 is equal to -2.

Answer:

[tex]\frac{2} {-1}[/tex]=-2

Step-by-step explanation:

A telemarketer calls people and tries to sell them a subscription to a daily newspaper. On 22% of her calls, there is no answer or the line is busy. She sells subscriptions to 10% of the remaining calls. For what proportion of calls does she make a sale? Give your answer as a decimal, and do not round.

Answers

Answer:

She makes 7.8% portion of sales collectively.

Step-by-step explanation:

Let us assume she makes total of 100 calls.

The percentage of calls which are busy or unanswered = 22 %

So, now calculating 22% of 100 , we get:

[tex]\frac{22}{100} \times 100 = 22[/tex]

So, 22 of her calls are UNANSWERED.

Now, let us find out the number of calls successfully made by telemarketer.

Total successful calls = Total Calls made - Number of unanswered calls

                                    = 100 - 22  = 78

So, she makes a total of 78 calls successfully.

Now, he sells subscriptions to 10% of the 78 calls made successfully.

So, now calculating 10% of 78 , we get:

[tex]\frac{10}{100} \times 78 = 7.8[/tex]

So, she sold 7.8 subscriptions in total out of 100 attempts.

Also, as we know 7.8 out of 100  = 7.8% of 100.

Hence, she makes 7.8% portion of sales collectively.

find the area of a rectangle that has a base of (4a) cm and a height (2a + b)

Answers

Answer:

area = 8a^2 +4ab

Step-by-step explanation:

Area = (4a)(2a + b)

= 8a^2 +4ab

Step-by-step explanation:

[tex]Area of rectangle \\ = base \times height \\ = (4a) \times (2a + b) \\ = 4a \times 2a + 4a \times b \\ = 8 {a}^{2} + 4ab \\ [/tex]

Find the indicated sum for each sequence. S9 of –9, 36, –144, 576, ...

Answers

Answer:

-471,861

Step-by-step explanation:

The sum of 9 terms in the sequence –9, 36, –144, 576, ... is -471861.

What is a sequence?

An ordered collection of objects that allows repetitions is referred to as a sequence. It has members, just like a set does. The length of the sequence is determined by the number of items.

Given:

–9, 36, –144, 576, ...

Calculate the ratio of the sequence as shown below,

ratio = 36 / -9

ratio = -4

Calculate the sum of 9 terms as shown below,

S₉ = -9 (1 - (-4)⁹) / (1 - (-4))

S₉ = -9 (1 + 262144) / 5

S₉ = -9 (262145) / 5

S₉ = -2359305 / 5

S₉ = -471861

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WILL MARK 1ST RIGHT ANSWER AS BRAINIEST
Bob placed three regular pentagons together at a vertex, thinking he might be able to form a tessellation. However, they left a gap. What is the number of degrees in the measure indicated?

Answers

Answer:

36

Step-by-step explanation:

The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to $3 * 108 = 324, which means the indicated angle measures 360 - 324 = 36.

Answer:

36

Step-by-step explanation:

The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to 3* 108 = 324, which means the indicated angle measures 360 - 324 = 36

_____ requires constructing and applying statistical models that predict labor demand for the next year, given relatively objective statistics from the previous year. Select one: a. Propensity analysis b. A leading indicator c. A yield ratio d. Transitional matrix e. Trend analysis

Answers

Answer:

e) Trend Analysis

Final answer:

The term is 'trend analysis'. This refers to a statistical method used to evaluate and predict future trends based on historical data. This technique is specifically referenced in prediction of labor demand using prior year’s data.

Explanation:

The concept referred to in the question is e. Trend analysis. Trend analysis is a statistical method used to evaluate and predict future trends based on historical data. In the context of labor demand, a trend analysis would involve examining labor demand data from the previous year, identifying patterns and trends within that data, and using statistical models to make predictions about labor demand for the upcoming year.

For example, suppose a company has seen a steady increase in labor demand over the past five years. Based on this trend, they can build a statistical model that predicts an increase in labor demand for the next year as well. This strategy helps companies plan for their future staffing needs, ensuring they have the necessary resources to meet their objectives.

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X-1 0 1 2 fx 18 6 2 2/3 what is the decay factor of the exponential function represented by the table 1/3 2/3 2 6

Answers

Final answer:

The decay factor of the exponential function represented by the provided table is 1/3 as the ratio of the consecutive y-values of the function is consistently 1/3.

Explanation:

The decay factor of an exponential function can be found by comparing the ratio of the y-values of the function.

In the given question, a table of x/f(x) values is provided.

A decay happens if the ratios of the consecutive y-values (outputs) are consistently less than 1.

Let's find the ratio between successive y-values. Between 18 and 6, the ratio is 6/18 = 1/3. Going from 6 to 2, the ratio is 2/6 = 1/3. Lastly, transitioning from 2 to 2/3, the ratio is (2/3)/2 = 1/3.

Since we find the ratio of successive outputs (y-values) to consistently be 1/3, it is safe to say that 1/3 is the decay factor for the exponential function represented by the given table.

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Mary collected $2.75 in nickels and dimes. Ten less than twice the number of nickels represents the number of dimes she has. How many of each kind of coin does she have?

Answers

Answer: There are 15 nickles and 20 dimes.

Step-by-step explanation:

Since we have given that

Let the number of nickles be 'x'

Let the number of dimes be '2x-10'.

Total amount = $2.75

According to question, we get that

[tex]0.1(2x-10)+0.05x=2.75\\\\0.2x-1+0.05x=2.75\\\\0.25x=2.75+1\\\\0.25x=3.75\\\\x=\dfrac{3.75}{0.25}\\\\x=15[/tex]

Hence, there are 15 nickles and [tex]2x-10=2(15)-10=30-10=20[/tex] dimes.

Therefore, there are 15 nickles and 20 dimes.

Final answer:

Mary has 15 nickels and 20 dimes.

Explanation:

Let's solve this problem step-by-step:

Let's assume the number of nickels as N and the number of dimes as D.According to the given information, the value of the nickels is 0.05N and the value of the dimes is 0.10D.The total amount collected is $2.75, so we can write the equation: 0.05N + 0.10D = 2.75According to the second piece of information, ten less than twice the number of nickels represents the number of dimes. So, we can write another equation: D = 2N - 10We now have a system of two equations with two variables:0.05N + 0.10D = 2.75D = 2N - 10Solve the system of equations to find the values of N and D.Substitute the value of D from the second equation into the first equation: 0.05N + 0.10(2N - 10) = 2.75Expand and simplify the equation: 0.05N + 0.20N - 1 = 2.750.25N - 1 = 2.750.25N = 3.75N = 3.75/0.25N = 15Substitute the value of N into the second equation to find the value of D: D = 2(15) - 10D = 30 - 10D = 20Therefore, Mary has 15 nickels and 20 dimes.:

Line l is parallel to line m. The slope of line l is . What is the slope of line m? 4/9

Answers

Final answer:

The slope of Line m that is parallel to Line l is also 4/9.

Explanation:

The slope of a line determines its steepness and direction. When two lines are parallel, they have the same slope. In this case, Line l is parallel to Line m, and the slope of Line l is 4/9. Therefore, the slope of Line m is also 4/9.

To find the depth of a well, a farmer lowers a 50-foot rope vertically into the well. If 15 feet of rope remain above the well, how deep (in feet) is the well?

Answers

The well is 35 feet deep.

Step-by-step explanation:

Given,

Length of rope = 50 feet

Length of remaining rope = 15 feet

Let,

x be the depth of well.

Total length of rope = Length of remaining + Depth of well

[tex]50=15+x\\50-15=x\\x=35[/tex]

The well is 35 feet deep.

The second side of a triangular deck is 3 feet longer than the shortest​ side, and the third side is 3 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 80 ​feet, what are the lengths of the three​ sides?

Answers

Answer: the lengths are 20 feet, 23 feet and 37 feet

Step-by-step explanation:

Let x represent the length of the shorter side of the triangular deck.

The second side of a triangular deck is 3 feet longer than the shortest​ side. This means that the length of the second side is (x + 3) feet.

The third side is 3 feet shorter than twice the length of the shortest side. This means that the length of the third of the triangle is (2x - 3) feet.

If the perimeter of the deck is 80 ​feet, it means that

x + x + 3 + 2x - 3 = 80

4x = 80

x = 80/4

x = 20

The length of the second side is

20 + 3 = 23 feet

The length of the third side is

20 × 2 - 3 = 40 - 3 = 37 feet

Is the product of 25 and 3/5 more or less than 14? Explain your answer. Write the product of 3/5 and 25.

Answers

Answer:

More. The product of 25 and 3/5 is 15 which is greater than 14.

Step-by-step explanation:

I really need help oof-
Angle α lies in quadrant II, and tanα=−12/5 . Angle β lies in quadrant IV, and cosβ=3/5.

What is the exact value of cos(α−β) ?

Enter your answer in the box.

cos(α−β) = __

Answers

From the given info (and the linked question) we find

[tex]\cos\alpha=-\dfrac5{13}[/tex]

[tex]\sin\alpha=\dfrac{12}{13}[/tex]

[tex]\sin\beta=-\dfrac45[/tex]

Then using the angle-sum identity for cosine, we have

[tex]\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta[/tex]

[tex]\cos(\alpha-\beta)=\left(-\dfrac5{13}\right)\dfrac35+\dfrac{12}{13}\left(-\dfrac45\right)=-\dfrac{63}{65}[/tex]

Final answer:

To find the exact value of cos(α-β), we use the cosine sum and difference identity and the respective sine and cosine values calculated from the given tangent and cosine values for angles α and β. Using this approach, we find that cos(α-β) equals 63/65.

Explanation:

The exact value of cos(α-β) can be found by using the sum and difference identities for cosine. Since tanα = -12/5, in quadrant II, we can find the corresponding sine and cosine values for α using the Pythagorean identity sin²α + cos²α = 1. For cosβ = 3/5, in quadrant IV, we do a similar procedure to find the sine of β. With both sine and cosine for α and β, we use the identity cos(A-B) = cosA cosB + sinA sinB to find cos(α-β).

To find the sine and cosine for α, given that tanα = -12/5, we know that the opposite side is -12, and the adjacent side is 5, so the hypotenuse using the Pythagorean theorem is √(12² + 5²) = √(144+25) = √169 = 13. Thus sinα = -12/13 (negative because α lies in the second quadrant where sine is negative) and cosα = 5/13 (positive because cosine in the second quadrant is positive).

For β, we already have cosβ = 3/5. The sine can be found using the Pythagorean identity 1 - cos²β = sin²β, which gives sinβ = -√(1 - (3/5)�) = -√(1 - 9/25) = -√(16/25) = -4/5 (negative because β is in the fourth quadrant where sine is negative).

Now, we can find the exact value of cos(α-β) by plugging in the values:

cos(α-β) = cosα cosβ + sinα sinβ = (5/13)*(3/5) + (-12/13)*(-4/5)
= 15/65 + 48/65 = 63/65.

Therefore, the exact value of cos(α-β) is 63/65.

If a standard dartboard's diameter is 17.75 inches, what is the area of once sector?

Answers

Answer:

  12.37 square inches

Step-by-step explanation:

The area of the dartboard can be figured from the diameter as ...

   A = (π/4)d² = (π/4)(17.75 in)² ≈ 247.4495 in²

There are 20 sectors, all the same size, so the area of one of them is ...

  sector area = (1/2)(247.4495 in²) ≈ 12.37 in²

The coordinates for the L-shaped are given to you. And number one. Where will the L shape be if it is. . .(find the new coordinates and then draw the image of the L-Shape)​

Answers

Answer:

  see below

Step-by-step explanation:

As always, the coordinate transformations are ...

  a. 180° — (x, y) ⇒ (-x, -y)

  b. 270° CCW or 90° CW — (x, y) ⇒ (y, -x)

  c. 90° CCW or 270° CW — (x, y) ⇒ (-y, x)

___

It can be quick and easy to use a transparency or tracing paper to locate the rotated position of the image.

Help ASAP Please




The following two-way frequency table shows information collected from a survey of students regarding their grade level and how they spend their screen time.
Grade vs.
Screen Time Uses the
Internet Watches
TV Plays Video
Games Total
7th Grader 6 3 6 15
8th Grader 8 3 2 13
Total 14 6 8 28
What is the probability that a student uses the Internet, given that he or she is in eighth grade?

Enter your answer rounded to two decimal places, like this: 0.42

Enter your answer as a fraction in simplest form, formatted like this: 3/14

Answers

Final answer:

The probability of an eighth-grade student using the Internet, based on the data provided, is approximately 0.62, or simply 8/13 as a fraction.

Explanation:

To calculate the probability that a student uses the Internet given he or she is in eighth grade, we look at the eight graders' behaviors in the table. There are 13 students in total in the eighth grade, and 8 of these use the Internet.

So, the probability can be expressed as P(Internet|8th grader) = number of internet users in 8th grade / total number of 8th graders = 8 / 13.

When rounded to two decimal places, this probability would be approximately 0.62. In terms of fractions, it can simply be left as 8/13.

Learn more about Probability here:

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The probability that a student uses the Internet, given that he or she is in eighth grade, is 2/3.

We are asked for the probability that a student uses the Internet, given that he or she is in eighth grade. This is the conditional probability [tex]$P({\text{Internet}} | {\text{8th Grade}})$[/tex], which can be calculated using Bayes' Theorem: \begin{align*}

[tex]P({\text{Internet}} | {\text{8th Grade}}) &= \frac{P({\text{8th Grade}} | {\text{Internet}})P({\text{Internet}})} {P({\text{8th Grade}})} \\&= \frac{\frac{8}{28} \cdot \frac{14}{28}} {\frac{13}{28}} \\&= \frac{2}{3}[/tex]

\end{align*}

Therefore, the probability that a student uses the Internet, given that he or she is in eighth grade, is [tex]$\boxed{\frac{2}{3}}$[/tex].

Here is a more detailed explanation of how we arrived at our answer:

Step 1: Calculate the probability of being in eighth grade, given that the student uses the Internet. This is the conditional probability [tex]$P({\text{8th Grade}} | {\text{Internet}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{8th Grade}} | {\text{Internet}}) = \frac{8}{14}$[/tex]

Step 2: Calculate the probability of using the Internet.** This is the marginal probability [tex]$P({\text{Internet}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{Internet}}) = \frac{14}{28}$[/tex].

Step 3: Calculate the probability of being in eighth grade.This is the marginal probability [tex]$P({\text{8th Grade}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{8th Grade}}) = \frac{13}{28}$[/tex].

Step 4: Apply Bayes' Theorem to calculate the conditional probability [tex]$P({\text{Internet}} | {\text{8th Grade}})$[/tex].

Therefore, the probability that a student uses the Internet, given that he or she is in eighth grade, is[tex]$\boxed{\frac{2}{3}}$[/tex].

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The data shown represent the number of runs made each year during Bill Mazeroski’s career. Check for normality.

30 59 69 50 58 71 55 43 3

66 52 56 62 36 13 29 17 31

Answers

Answer:

The given data is not normal.

Step-by-step explanation:

We are given the following data:

30, 59, 69, 50, 58, 71, 55, 43, 3,  66, 52, 56, 62, 36, 13, 29, 17, 31

Condition for normality:

Mean = Mode = Median

[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]

[tex]Mean =\displaystyle\frac{800}{18} = 44.44[/tex]

Mode is the most frequent observation of the data.

Since all the value appeared once, there is no mode.

[tex]Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}[/tex]

Sorted data: 3, 13, 17, 29, 30, 31, 36, 43, 50, 52, 55, 56, 58, 59, 62, 66, 69, 71

Median =

[tex]=\dfrac{9^{th}+10^{th}}{2} = \dfrac{50+52}{2}=51[/tex]

Since the mean, mode and median of data are not equal, the data is not normal.

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