You happen to be visiting Northem California and you are driving by Suisun Bay, a notorious graveyard for old ships You notice that all of these ships appear to be nusting may Which of the following statements is true?

a. The rusting of the metal is neither a chemical change nor a physical change
b. The rusting of the metal is a chemical change
c. The rusting of the metal is both a chemical change and a physical change
d. The rusting of the metal is a physical change

Answer : The final temperature of the mixture is [tex]61.4^oC[/tex]

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

[tex]q_1=-q_2[/tex]

[tex]m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)[/tex]

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

[tex](\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)[/tex]

where,

[tex]c_1[/tex] = [tex]c_2[/tex] = specific heat of water = same

[tex]m_1[/tex] = [tex]m_2[/tex] = mass of water  =  same

[tex]\rho_1[/tex] = [tex]\rho_2[/tex] = density of water = 1.0 g/mL

[tex]V_1[/tex] = volume of water at [tex]80.0^oC[/tex]  = [tex]370cm^3=370mL[/tex]

[tex]V_2[/tex] = volume of water at [tex]4^oC[/tex]  = [tex]120cm^3=120mL[/tex]

[tex]T_f[/tex] = final temperature of mixture = ?

[tex]T_1[/tex] = initial temperature of water = [tex]80.0^oC[/tex]

[tex]T_2[/tex] = initial temperature of water = [tex]4^oC[/tex]

Now put all the given values in the above formula, we get:

[tex](\rho_1\times V_1)\times (T_f-T_1)=-(\rho_2\times V_2)\times (T_f-T_2)[/tex]

[tex](1.0g/mL\times 370mL)\times (T_f-80.0)^oC=-(1.0g/mL\times 120mL)\times (T_f-4)^oC[/tex]

[tex]T_f=61.4^oC[/tex]

Therefore, the final temperature of the mixture is [tex]61.4^oC[/tex]

The question is incomplete, here is the complete question:

By titration, 15.0 mL of 0.1008 M sodium hydroxide is needed to neutralize a 0.2053-g sample of an organic acid. What is the molar mass of the acid if it is monoprotic.

Answer: The molar mass of monoprotic acid is 135.96 g/mol

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]

Molarity of NaOH solution = 0.1008 M

Volume of solution = 15.0 mL

Putting values in above equation, we get:

[tex]0.1008M=\frac{\text{Moles of NaOH}\times 1000}{15.0}\\\\\text{Moles of NaOH}=\frac{(0.1008\times 15.0)}{1000}=0.00151mol[/tex]

As, the acid is monoprotic, it contains 1 hydrogen ion

1 mole of [tex]OH^-[/tex] ion of NaOH neutralizes 1 mole of [tex]H^+[/tex] ion of monoprotic acid

So, 0.00151 moles of [tex]OH^-[/tex] ion of NaOH will neutralize [tex]\frac{1}{1}\times 0.00151=0.00151mol[/tex] of [tex]H^+[/tex] ion of monoprotic acid

In monoprotic acid:

1 mole of [tex]H^+[/tex] ion is released by 1 mole of monoprotic acid

So, 0.00151 moles of [tex]H^+[/tex] ion will be released by [tex]\frac{1}{1}\times 0.00151=0.00151mol[/tex] of monoprotic acid

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of monoprotic acid = 0.00151 mole

Given mass of monoprotic acid = 0.2053 g

Putting values in above equation, we get:

[tex]0.00151mol=\frac{0.2053g}{\text{Molar mass of monoprotic acid}}\\\\\text{Molar mass of monoprotic acid}=\frac{0.2053g}{0.00151mol}=135.96g/mol[/tex]

Hence, the molar mass of monoprotic acid is 135.96 g/mol

Answer : The work done is, [tex]1.98\times 10^4J[/tex]

Explanation :

The given balanced chemical reaction is:

[tex]N_2(g)+3H_2(g)\rightarrow 2NH_3(g)[/tex]

When 4 moles of [tex]N_2[/tex] react with 12 moles of [tex]H_2[/tex] then it gives 8 moles of [tex]NH_3[/tex]

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of [tex]N_2[/tex] + Moles of [tex]H_2[/tex]

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of [tex]NH_3[/tex]

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

[tex]PV=nRT[/tex]

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]

T = Temperature of gas = [tex]25^oC=273+25=298K[/tex]

Putting values in above equation, we get:

[tex]1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K[/tex]

[tex]V=195.7L[/tex]

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

[tex]w=-p\Delta V[/tex]

where,

w = work done

p = pressure of the gas = 1.0 atm

[tex]\Delta V[/tex] = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

[tex]w=-p\Delta V[/tex]

[tex]w=-(1.0atm)\times (-195.7L)[/tex]

[tex]w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J[/tex]

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, [tex]1.98\times 10^4J[/tex]

Final answer:

The work done against a pressure of 1.0 atm at 25°C can be calculated using the equation work = -PΔV. In this case, the change in volume (ΔV) is calculated using the ideal gas law and the moles of gases involved in the reaction. Calculating the work done gives a value of -179,200 J.

Explanation:

To calculate the work done against a pressure of 1.0 atm at 25°C, we need to use the equation: work = -PΔV. In this case, the change in volume (ΔV) can be calculated using the ideal gas law: PV = nRT. We can assume the reaction takes place at constant temperature and convert the moles of gases to volume using the molar volume of gases at standard temperature and pressure (STP).

In the given reaction, 4 moles of N₂ react with 12 moles of H₂ to form 8 moles of NH₃. According to the balanced equation, the reaction produces 2 moles of NH₃ for every 1 mole of N₂. Therefore, the change in volume (ΔV) is (8 - 0) x 22.4 L/mol = 179.2 L.

Now we can calculate the work done:

work = -PΔV = -(1.0 atm) x (179.2 L) = -179.2 L-atm = -179,200 J

Answer:

liquid's heat of vaporization = 38.4 kJ/mol

Explanation:

given data

vapor pressure P1 = 6.91 mmHg

at temperature = 0 °C = 273.15 K

boiling temperature = 105 °C

solution

for vapor pressure and temperature we get here

P2 = 760.0 mmHg

T2 = 68.73°C = 378.15 K

we use here the Clausius-Clapeyron Equation that is

ln [tex]\frac{P1}{P2}[/tex] = [tex]\frac{\Delta H}{R} (\frac{1}{T2} -\frac{1}{T1} )[/tex]     .................1

put here value

In [tex]\frac{6.91}{760} = \frac{x}{8.31447} (\frac{1}{378.15} -\frac{1}{273.15} )[/tex]

solve it we get

x = 38445 J/mol

liquid's heat of vaporization = 38.4 kJ/mol

The liquid's heat of vaporization = 38.4 kJ/mol

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The problem is about calculating the least amount of total illuminance from two light sources of differing intensities. This is tackled through understanding and applying the Inverse Square Law for Light, which is a concept in Physics.

In this problem, we are dealing with the concept of the Inverse Square Law for Light which states that the intensity (illuminance) of light or radiation at any point is inversely proportional to the square of the distance from the source. This means, if the distance from the source of light is doubled, the illuminance will decrease to (1/2)^2 = 1/4 of its original value, and if the distance is tripled, illuminance will decrease to (1/3)^2 = 1/9 of its original value etc.

Here, we have two light source, one having an intensity of nine times that of the other, and they are 11 m apart. We need to find the distance from the stronger light where the total illuminance is least. This involves setting up an equation that includes the intensities of both lights, and their respective distances from the point in question, and then differentiating it with respect to the distance to find a minimum.

In solving this problem, we consider the increased illuminance from the stronger light, and where the decrease in illuminance from the weaker light would result in the least total illuminance along the line between the two light sources. This represents a practical application of the inverse square law for light in the field of physics.

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The intensity of illumination is less at points farther from a light source because of the inverse square law for light. The point at which total illumination is least from two light sources depends on their intensities and separation.

The question relates to the inverse square law for light, which states that the intensity of light is inversely proportional to the square of the distance from the source. In other words, as the distance from the light source increases, the intensity of illumination decreases at a rate that's the square of this distance increase.

If you are standing between two light sources, the total illumination at the point where you stand will be a combination of the intensity of the two sources. Given that one source is nine times stronger than the other, the stronger light source will dominate the illumination at closer distances. As you move away from the stronger source and towards the weaker one, the intensity from the stronger light source will diminish quickly according to the inverse square law.

However, because the weaker light is so much less intense to begin with, even as you approach it, it can't compensate for the lost illumination from the stronger light. There will thus be a point at which the total illumination starts to decrease again. The total illumination will be least at a point where the diminishing intensity of the stronger light just balances with the increasing intensity of the weaker light as we move towards it. This point depends on the specific intensities of the two lights and their separation, and would require further computation to ascertain exact placement.

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In the given reaction, the equilibrium concentration of NO2 is calculated as 5.1 mol/L. The equilibrium constant, K, is then calculated as [NO]^2 [O2] / [NO2]^2, giving a final result of 0.984 mol/L.

The chemical reaction we are looking at is: 2NO2(g) ⇌ 2NO(g) + O2(g). In this reaction, 2 moles of gaseous Nitrogen Dioxide (NO2) decompose into 2 moles of Nitric Oxide (NO) and 1 mole of Oxygen (O2).

At equilibrium, we know that the concentration of NO is 2.9 mol/L. However, since two moles of NO are produced for every two moles of NO2 consumed, the decrease in concentration of NO2 and the increase in concentration of NO are equal. Thus, the equilibrium concentration of NO2 is the initial concentration (8.0 mol/L) minus the change in concentration, which in this case is the concentration of NO at equilibrium (2.9 mol/L), giving us [NO2] = 8.0 - 2.9 = 5.1 mol/L.

The equilibrium constant, K, is then calculated using the equilibrium concentrations of the reactants and products. In this case, the concentrations are raised to the power of their stoichiometric coefficients in the balanced chemical equation. Therefore, K = [NO]^2 [O2] / [NO2]^2 = (2.9)^2 * (2.9) / (5.1)^2.

After performing the calculation, you should get out your final value for K as 0.984 mol/L. Remember, the units for K depend on the balance of the stoichiometric coefficients in the equation, but in this case, because the coefficients are balanced, the units for K are simply mol/L.

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To find the equilibrium constant K for the decomposition of NO₂, we used the equilibrium concentrations of NO, O₂, and NO₂. The calculated value of K is approximately 0.32.

To calculate the equilibrium constant (K) for the decomposition reaction of NO₂:

2NO₂(g) ⇌ 2NO(g) + O₂(g)

we need to find the equilibrium concentrations of all species involved. Initially, we have 8.0 mol of NO₂ in a 1.0-L container, so the initial concentration of NO₂ is:

[tex][NO_2]_i_n_i_t_i_a_l[/tex] = 8.0 mol/L

At equilibrium, the concentration of NO is given as 2.9 M. From the balanced equation, we see that 2 moles of NO are produced for every 2 moles of NO₂ decomposed, meaning the concentration of NO₂ that decomposed is also 2.9 M. Therefore, the remaining concentration of NO₂ at equilibrium is:

[tex][NO_2]_e_q_u_i_l_i_b_r_i_u_m[/tex] = 8.0 M - 2.9 M = 5.1 M

Using the stoichiometry from the balanced equation, 2.9 M of NO₂ yields 1.45 M of O₂:

[tex][O_2]_e_q_u_i_l_i_b_r_i_u_m[/tex] = 1.45 M

Now, we can write the expression for the equilibrium constant:

K = ([NO]² [O₂]) / ([NO₂]²)

Substituting the equilibrium concentrations:

K = ((2.9)² x 1.45) / (5.1)² = 8.41 / 26.01 ≈ 0.32

Thus, the value of equilibrium constant (K) for the reaction is 0.32.

Answer:

The answer to your question is empirical formula   Al₃O₉S

Explanation:

Data

Al = 31.5 %

O = 56.1 %

S = 12.4 %

Process

1.- Look for the atomic masses of the elements

Al = 27 g

O = 16

S = 32

2.- Represent the percentages as grams

Al = 31.5 g

O = 56.1 g

S = 12.4 g

3.- Convert these masses to moles

                               27 g of Al ----------------- 1 mol

                               31.5 g ----------------------  x

                                x = 1.17 moles

                               16 g of O ----------------  1 mol

                               56.1 g of O -------------  x

                                  x = 3.5 mol

                               32 g of S ---------------  1 mol

                               12.4 g of S -------------   x

                                x = 0.39 moles

4.- Divide by the lowest number of moles

Al =   1.17 / 0.39  = 3

O =    3.5 / 0.39 = 8.9 ≈ 9

S  =   0.39 / 0.39 = 1

5.- Write the empirical equation

                                Al₃O₉S

The empirical formula of the compound with mass percentages of Al 31.5%, O 56.1%, and S 12.4% is Al3O9S.

The empirical formula of a compound is the simplest whole number ratio of the atoms present in the compound. To determine the empirical formula, we can assume that we have 100 grams of the compound. From the given mass percentages, we can convert the mass of each element to moles and then divide the moles by the smallest number of moles to get the mole ratio. From the mole ratio, we can determine the empirical formula.

In this case, if we assume we have 100 grams of the compound, we would have 31.5 grams of Al, 56.1 grams of O, and 12.4 grams of S. Converting these masses to moles, we find that we have approximately 1.17 moles of Al, 3.51 moles of O, and 0.775 moles of S. Dividing these values by the smallest number of moles (0.775), we get a mole ratio of Al:O:S as approximately 1.51:4.53:1.

Now, we need to simplify the mole ratio to whole number ratios. Multiplying the ratio by 2, we get 3.02:9.06:2, which can be rounded to 3:9:2. Therefore, the empirical formula of the compound is Al3O9S.

Answer:

the answer i a

Explanation:

Answer:

answer is d ( An object with kinetic energy can only move for a certain amount of time and then it stops.)

Explanation:

Answer:

10⁻⁴ M is the hydrogen ion concentration of the lake.

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

pH scale generally runs from 1 to 14 where pH = 7 represents neutral medium, pH < 7 represents acidic medium and pH > 7 represents basic medium.

Given that, pH = 4.0

So,

4.0 = - log [H⁺]

OR,

[H⁺]  = antilog (-4) = 10⁻⁴ M

10⁻⁴ M is the hydrogen ion concentration of the lake.

the hydrogen ion concentration of the lake is [tex]10^{-4}[/tex] M, which is equal to 0.0001 M. So, the correct answer is [tex]10^{-4}[/tex] M. Correct option is B.

The pH of a solution is a measure of its acidity and is defined as the negative logarithm (base 10) of the hydrogen ion (H⁺) concentration. The formula to calculate the hydrogen ion concentration (H⁺) from pH is:

H⁺ concentration (M) = [tex]10^{-pH}[/tex]

In this case, the pH of the lake is 4.0. Plugging this value into the formula:

H⁺ concentration = [tex]10^{-4.0}=10^{-4}[/tex]

Therefore, the hydrogen ion concentration of the lake is [tex]10^{-4}[/tex] M, which is equal to 0.0001 M. This means that the lake has a relatively high concentration of hydrogen ions, indicating it is acidic.

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Answer: Eggs and produce estrogen

Explanation: Ovaries are part of the female reproductive organ which produces eggs cells female gametes. These kind og gametes produces estrogen a hormone commonly found on females.

Answer:

-2

Explanation:

Gibbs free energy is defined by enthalpy of the system minus the product of the temperature and entropy and represented by the formula below:

G = H - TS where G = Gibbs free energy, H = enthalpy and T =  temperature and S = entropy

change in entropy is defined by the formula below

ΔG = ΔH - Δ(TS)  if the temperature is not constant, but if the temperature is constant then

ΔG = ΔH - TΔS

in according to the question (TS) is treated together.

to the solution

increase in H = 10 units , increase in the product of temperature and entropy = 12 units

ΔG = 10 - 12 = -2

Answer:

Option B. 10

Explanation:

If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.

(number of atoms  / NA)

6.02 x 10²³ atoms ___ 1 mol

6×10²⁴ atoms will occupy (6×10²⁴ / NA) = 9.96 moles

H, has 10 moles in the butano formula.

The subscript for hydrogen in the molecular formula for butanol is 10, indicating there are 10 hydrogen atoms in each molecule of butanol.

The student has asked, "If 1.0 mol of butanol contains 6.0 x 1024 atoms of hydrogen, what is the subscript for the hydrogen atom in the molecular formula for butanol?". One mole of a substance always contains Avogadro's number of atoms, which is approximately 6.022 x 1023. The student has 6.0 x 1024 hydrogen atoms, which is ten times Avogadro's number, indicating there are 10 hydrogen atoms for every mole of butanol. Therefore, the subscript for hydrogen in the molecular formula for butanol is 10, based on the molecular formulas of similar alcohols. The correct answer is (b) 10.

Answer:

The half life of the element = 8 minutes

Explanation:

Solution:

The initial amount = 10g

final amount = 1.25g

elapsed time = 24 minutes

Half life formula

t1/2 = t/(log1/2(Nt/N0))

or (Nt/N0) = 0.5^(t/(t1/2))

or 1.25/10 = 0.5^((24×60)/(t1/2))

Log of both sides gives

0.125 = 0.5^(1440/(t1/2))

-0.903 = 1440/t1/2×log(0.5)

-0.903 = 1440/t1/2×(-0.301)

3 = 1440/t1/2

t1/2 = 1440/3 = 480

Solving we have

t1/2 or the half life = 480s

= 480/60 minutes or

= 8 minutes

Answer: The new pressure of the gas in Pa is 388462

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas at STP = [tex]10^5Pa[/tex]

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = 700.0 ml

[tex]V_2[/tex] = final volume of gas = 200.0 ml

[tex]T_1[/tex] = initial temperature of gas = 273 K

[tex]T_2[/tex] = final temperature of gas = [tex]30^oC=273+30=303K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{10^5\times 700.0ml}{273K}=\frac{P_2\times 200.0ml}{303K}[/tex]

[tex]P_2=388462Pa[/tex]

The new pressure of the gas in Pa is 388462

The new pressure of the gas is 388462 Pa. The pressure of the gas in the system can be calculated by the combination of gas laws.

The pressure of the gas in the system can be calculated by the combination of gas laws that is used for an ideal gas at STP.

[tex]\dfrac {P_1V_1}{T_1} =\dfrac {P_2V_2}{T_2}[/tex]

Where,

[tex]P_1[/tex] = initial pressure of gas at STP = [tex]10^5 Pa.[/tex]

[tex]V_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex]= initial volume of gas = 700.0 ml

[tex]V_2[/tex]= final volume of gas = 200.0 ml

[tex]T_1[/tex] = initial temperature of gas = 273 K

[tex]T_2[/tex] = final temperature of gas = 30°C = 303 K

Put the values in the formula,

[tex]\dfrac {10^5 \times 700 }{273 } =\dfrac {P_2\times200 }{ 303}\\\\P_2 = 388462 \rm \ Pa[/tex]

Therefore, the new pressure of the gas is 388462 Pa.

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Answer:

E

Explanation:

A. Is wrong

To prepare chicken noodle soup, several things are needed to be mixed. This is what makes it a mixture

B is wrong

Powerade is not a compound.

C is wrong

The air inside a balloon is usually helium which is an element and not a compound

D. Lead pipe is not a compound

E. Baking soda is a compound as it contains elements in different ratios

Answer:baking soda

Explanation:

A compound is formed by chemical reaction of atoms of elements. A compound is actually formed by chemical combination of elements. A soul, a Powerade, air and a lead like are not compounds. In the first three items mentioned, on!y a mixture of substances are involved. There isn't any chemical combination at all. Lead pipe only consists of one kind of element. No other thing combines with it at all.

Answer:i think it is A

Explanation:

Answer:

The concentration of the unknown acid (HA) is 0.434M

The molar mass of HA is 13.3g/mole

Explanation:

DETERMINATION OF MOLARITY OF THE UNKNOWN ACID

CaVa/CbVb = Na/Nb

From the equation of reaction and at equivalence point, Na = Nb = 1

Therefore, CaVa = CbVb

Va (volume of acid solution) = 20mL = 20/1000 = 0.2L

Cb (concentration of KOH) = 0.715M

Vb (volume of KOH) = 12.15mL

Ca (concentration of acid) = CbVb/Va

Ca = 0.715M × 12.15mL/20mL = 0.434M

DETERMINATION OF MOLAR MASS OF HA

Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole

Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole

The molar mass of unknown HA solution has been 132.8 g/mol.

Titration has been given as the neutralization reaction for acid and base to result in the formation of salt and water.

The balanced chemical equation for the reaction has been:

[tex]\rm HA\;+\;KOH\;\rightarrow\;KA+\;H_2O[/tex]

The molarity of the unknown acid solution has been given as:

[tex]M_1V_1=M_2V_2[/tex]

Where, the molarity of KOH solution, [tex]M_2=0.715\;\rm M[/tex]

The volume of the KOH solution, [tex]V_2=12.15\;\rm mL[/tex]

The volume of the HA solution, [tex]V_1=20.0\;\rm mL[/tex]

Substituting the values for the molarity of HA, [tex]M_1[/tex]

[tex]M_1\;\times\;20=0.715\;\times\;12.15\\M_1=\dfrac{0.715\;\times\;12.15}{20} \\M_1=0.434\;\rm M[/tex]

The concentration of the HA solution has been 0.434 M.

The molar mass from molarity has been given by:

[tex]\rm Molar \;mass=\dfrac{Mass}{Molarity}\;\times\;\dfrac{1000}{Volume\;mL}[/tex]

Substituting the values for the molar mass of HA:

[tex]\rm Molar \;mass=\dfrac{1.153}{0.434}\;\times\;\dfrac{1000}{\;20}\\Molar\;mass=2.656\;\times\;50\\Molar \;mass=132.8\;g/mol[/tex]

The molar mass of unknown HA solution has been 132.8 g/mol.

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Approximately 809 grams of TiCl4 are needed for the complete reaction with 170 L of H2 at 450 ∘C and 785 mm Hg pressure.

To determine the amount of TiCl4 needed for the reaction, we can use the ideal gas law. The ideal gas law equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature in Kelvin.

First, we need to convert the given temperature from Celsius to Kelvin. We add 273 to the temperature:

450 ∘C + 273 = 723 K

Next, we need to convert the given pressure from mm Hg to atm. Since 1 atm = 760 mm Hg, we divide 785 mm Hg by 760 mm Hg/atm:

785 mm Hg / 760 mm Hg/atm = 1.034 atm

Now, we can rearrange the ideal gas law equation to solve for the number of moles:

n = PV / RT

n = (1.034 atm) * (170 L) / [(0.0821 L*atm/mol*K) * (723 K)]

Calculating this, we find:

n ≈ 4.27 mol

Finally, we can convert moles of TiCl4 to grams using its molar mass. The molar mass of TiCl4 is approximately 189.7 g/mol.

Grams of TiCl4 = (4.27 mol) * (189.7 g/mol)

Calculating this, we find:

Grams of TiCl4 ≈ 809 g

Therefore, approximately 809 grams of TiCl4 are needed for the complete reaction with 170 L of H2 at 450 ∘C and 785 mm Hg pressure.

Answer: An electron having a quantum number of one is closer to the nucleus

Explanation:

The Bohr model relies on electrostatic attraction between the nucleus and orbital electron. Hence, the closer an electron is to the nucleus the more closely it is held by the nucleus and the lesser its energy (the more stable the electron is and the more difficult it is to ionize it). The farther an electron is from the nucleus ( in higher shells or energy levels), the less the electrostatic attraction of such electron to the nucleus due to shielding effect. Hence it is less tightly held.

Answer:

Below.

Explanation:

1. At quantum number 3 it is further from the positive protons in the nucleus.

2. The inner electrons have a shielding effect on the attraction from the protons in the nucleus.

The heat lost by silver equates to the heat gained by water. We can plug in the known values (temperature changes and specific heat of silver and water) into the equation and solve for the mass of the silver block.

The question involves the concept of conservation of energy, where the heat lost by the silver block is equal to the heat gained by the water. This concept is captured in the equation Cmetal × mmetal × ([tex]T_f[/tex],metal – [tex]T_i[/tex], metal) = −Cwater × mwater × ([tex]T_f[/tex],water - [tex]T_i[/tex],water) which expresses energy conservation.

In this case, the energy lost by silver (Csilver × msilver × ([tex]T_f[/tex] - 58.5)) is equal to the energy gained by the water (Cwater × mwater × (26.2 - 24.8)).

Plugging in the known variables (including the specific heat of silver (Csilver) as 0.2350 J/g°C and water (Cwater) as 4.18 J/g°C), we can solve the equation to find the unknown mass of the silver (msilver).

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Using the principle of conservation of energy and the formula for heat transfer, we determined that the mass of the silver block is 77.6 g.

To solve for the mass of the silver block, we need to use the principle of conservation of energy, which states that the heat lost by the silver block will equal the heat gained by the water since the container is insulated.

The formula for heat transfer (q) is:

q = m × c × ΔT

Where:

m = mass

c = specific heat capacity

ΔT = change in temperature

For the water:

mwater = 100.0 g

cwater = 4.18 J/g°C (specific heat of water)

ΔTwater = 26.2°C - 24.8°C = 1.4°C

q water = 100.0 g × 4.18 J/g°C × 1.4°C = 585.2 J

For the silver block:

csilver = 0.235 J/g°C (specific heat of silver)

ΔTsilver = 58.5°C - 26.2°C = 32.3°C

qsilver must equal qwater:

m silver × 0.235 J/g°C × 32.3°C = 585.2 J

Solving for msilver:

msilver = 585.2 J / (0.235 J/g°C × 32.3°C)

msilver = 77.6 g

Therefore, the mass of the silver block is 77.6 g.

Answer:

In the yeast signal transduction pathway, after both types of mating cells have released the mating factors and the factors have bound to specific receptors on the correct cells:

a. binding induces changes in the cells that lead to cell fusion.

Explanation:

There have been several studies about yeast cells and how they respond to the mating factors, a-factor and α-factor:

option b: the cells then produce the a factor and the  factor, is not correct as they are mating factors.

These studies have greatly contributed to help understanding the way  signals are transduced from a cell-surface receptor into a cell.

When yeast a cells are exposed to α-factor, they exhibit three responses, which are initiated in the moment the mating factor (a signaling molecule that acts between organisms, hence called a “pheromone”) binds to the receptor:

(1) they arrest in the G1 phase of the cell cycle, not option c: one cell nucleus binds the mating factors and produces a new nucleus in the opposite cell.

(2) they synthesize a variety of proteins involved in cell fusion, not option e: a growth factor is secreted that stimulates mitosis in both cells.

(3) they grow towards their mating partner, not option d: the cell membranes fall apart, releasing the mating factors that lead to new yeast cells.

The activated receptor triggers a so-called “MAP kinase cascade" protein kinase, followed by a transcriptional activator protein, Ste12. Ste12 inducing synthesis of assorted proteins that play an important role in arresting the cell cycle (the Far1 protein) and for cell fusion (the Fus1 protein).

Answer:

There is a couple different ways to determine if a bond is ionic or covalent. By definition, an ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals. So you usually just look at the periodic table and determine whether your compound is made of a metal/nonmetal or is just 2 nonmetals.

Explanation:

To determine the number of water molecules in the hydrate of copper(II) sulfate, we can use the given information. We start with a 14.220 g sample of the hydrate and heat it to 300°C. After heating, the resulting anhydrous salt, CuSO4, has a mass of 8.9935 g. The difference in mass, 14.220 g - 8.9935 g = 5.2265 g, represents the mass of the water that has been driven off.

To determine the number of water molecules in the hydrate of copper(II) sulfate, we can use the given information. We start with a 14.220 g sample of the hydrate and heat it to 300°C. After heating, the resulting anhydrous salt, CuSO4, has a mass of 8.9935 g. The difference in mass, 14.220 g - 8.9935 g = 5.2265 g, represents the mass of the water that has been driven off. To calculate the number of moles of water, we need to convert the mass to moles using the molar mass of water which is approximately 18 g/mol. Therefore, the number of moles of water is 5.2265 g / 18 g/mol = 0.2904 mol. Lastly, to determine the value of 'n' in the hydrate formula CuSO4 · nH2O, we consider the ratio of moles of water to moles of anhydrous salt. From the equation, 1 mole of CuSO4 corresponds to 5 moles of water, so for 0.2904 mol of water, we have 0.2904 mol / 5 = 0.0581 mol of CuSO4. Therefore, the empirical formula for the hydrate is CuSO4 · 0.0581H2O.

To find the molecular formula, we need the molar mass of the hydrate. The molar mass of the anhydrous salt CuSO4 is approximately 159.6 g/mol. From the given information, the molar mass of the hydrate is 94.1 g/mol. To find the value of 'n', we divide the molar mass of the hydrate by the molar mass of the empirical formula unit. Therefore, 94.1 g/mol / 159.6 g/mol = 0.590. Lastly, we multiply the subscripts in the empirical formula by the value of 'n'. The molecular formula for the hydrate of copper(II) sulfate is CuSO4 · 0.590H2O.

Answer:

6.98 km/hour.

Explanation:

Average speed = total distance / total time taken

= 16.34 / 2.34

= 6.98 km/hour.

Answer: the concentration of H in the stomach acid is greater than that of the lemon juice

Explanation:Please see attachment for explanation

Answer:

The answer to your question is 62.16 g of CaO

Explanation:

Data

mass = ?

moles = 1.11 of CaO

molecular mass of CaO = 40 + 16 = 56 g

Process

1.- Use proportions and cross multiplication to solve this problem

                          56 g of CaO ------------------- 1 mol of CaO

                            x  g of CaO ------------------- 1.11 moles of CaO

                            x = (1.11 x 56) / 1

2.- Simplification

    mass of CaO = 1.11 x 56

                           = 62.16 g

Answer:

The answer to your question is   1, 1 , 1 , 2

Explanation:

Reaction

                          CuCl₂  +   H₂S   ⇒   CuS  +  HCl

                   Reactants       Elements      Reactants

                          1                  Copper           1

                          2                 Chlorine          1

                          2                 Hydrogen       1

                          1                  Sulfur              1

This reaction is unbalanced

                       CuCl₂  +   H₂S   ⇒   CuS  +  2HCl

                   Reactants       Elements      Reactants

                          1                  Copper           1

                          2                 Chlorine         2

                          2                 Hydrogen      2

                          1                  Sulfur              1

Just add 2 to hydrochloric acid, now the reaction is balanced.

The coefficient of reactants [tex]\rm CuCl_2[/tex] and [tex]\rm H_2S[/tex] has been 1, while the coefficient of product CuS has been 1, and HCl has been 2.

The balanced equation has been given as the reaction in which the atoms of each elements in the product and the reactant side has been equal.

The reaction has been given as:

[tex]\rm CuCl_2\;+\;H_2S\;\rightarrow\;CuS\;+\;HCl[/tex]

In the reaction, the number of atoms of elements have been:

Product = 1

Product = 1

Product = 1

Product = 1

The atoms of H and Cl has been 2 at the reactant side, and 1 at the product side. The reaction has been balanced by adding coefficient 2 to HCl.

Thus, the balanced reaction has been:

[tex]\rm CuCl_2\;+\;H_2S\;\rightarrow\;CuS\;+\;2\;HCl[/tex]

The coefficient of reactants [tex]\rm CuCl_2[/tex] and [tex]\rm H_2S[/tex] has been 1, while the coefficient of product CuS has been 1, and HCl has been 2.

For more information about the balanced equation, refer to the link:

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Answer: The concentration of the sodium hydroxide solution is 0.05 M

Explanation:

[tex]H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O[/tex]

To calculate the concentration of the sodium hydroxide solution, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=2\\M_1=0.05M\\V_1=150.0mL\\n_2=1\\M_2=?\\V_2=300.0mL[/tex]

Putting values in above equation, we get:

[tex]2\times 0.05\times 150.0=1\times M_2\times 300.0\\\\M_2=0.05M[/tex]

Thus the concentration of the sodium hydroxide solution is 0.05 M

Answer: B

Explanation:

Cross contamination refers to the in unintentional transfer of bacteria or toxins from one individual or surface to another. The individual receiving or even the fellow giving out the cloth may be unaware of the risk involved in the transfer of such contaminated materials. Hence, the other individual is cross contaminated with the toxins originally carried by the individual wearing the cloth.

The likely result of a person with skin coated in a toxic substance giving their clothing to another is cross-contamination. This refers to the transfer of contaminants which may cause exposure and subsequent health risks.

If a person whose skin is coated with a toxic substance gives his/her contaminated clothing to another individual, this likely will result in what is known as cross-contamination. Cross-contamination refers to the transfer of contaminants from one person, object, or substance to another, potentially causing harm. In this scenario, the toxic substance on the skin can be transferred to the clothes, and then to the person who handles those clothes, potentially leading to exposure and health risks.

Exposure to toxic substances can occur through various pathways, including skin or eye contact. For example, workers in agricultural or industrial settings might be exposed to pesticides, which can lead to acute or chronic health problems. It's important to handle such contaminated clothing with proper precautions to avoid health hazards.

Answer:

5.71% was the percent increase in the population of City K from 1980 to 1990 .

Explanation:

In 1970 the population of City K = 160,000

In 1980 the population of City K was 20 percent greater than it was in 1970:

160,000 + 20% of 160,000 =160,000 + 32,000 = 192,000

In 1990 the population of City K was 30 percent greater than it was in 1970:

160,000 + 30% of 160,000 =160,000 + 48,000 = 208,000

Percent increase in the population of City K from 1980 to 1990:

[tex]\frac{208,000-192,000}{192,000}\times 100=8.33\%[/tex]

8.33% was the percent increase in the population of City K from 1980 to 1990 .