You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from overfishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day

Answer:

[tex] SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58[/tex]

[tex] ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073[/tex]

[tex] \bar X - ME = 237- 14.073 = 222.927[/tex]

[tex] \bar X + ME = 237+ 14.073 = 251.073[/tex]

[tex]n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238[/tex]

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis:[tex]\mu \geq 247[/tex]  

Alternative hypothesis:[tex]\mu <247[/tex]  

[tex]z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165[/tex]  

[tex]p_v =P(z<-1.165)=0.122[/tex]  

If we compare the p value and the significance level given [tex]\alpha=0.1[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

[tex] \bar X =237[/tex] represent the sample mean

[tex]\sigma = 47[/tex] represent the population deviation

[tex] n =30[/tex] represent the sample size selected

[tex]\mu_0 = 247[/tex] represent the value that we want to test.

The standard error for this case is given by:

[tex] SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58[/tex]

For the 90% confidence the value of the significance is given by [tex] \alpha=1-0.9 = 0.1[/tex] and [tex] \alpha/2 = 0.05[/tex] so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

[tex] z_{\alpha/2}= 1.64[/tex]

And the margin of error would be:

[tex] ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073[/tex]

The confidence interval for this case would be given by:

[tex] \bar X - ME = 237- 14.073 = 222.927[/tex]

[tex] \bar X + ME = 237+ 14.073 = 251.073[/tex]

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex]   (b)

Replacing into formula (b) we got:

[tex]n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238[/tex]

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \geq 247[/tex]  

Alternative hypothesis:[tex]\mu <247[/tex]  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex] (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

[tex]z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165[/tex]  

P-value  

Since is a left tailed test the p value would be:  

[tex]p_v =P(z<-1.165)=0.122[/tex]  

Conclusion  

If we compare the p value and the significance level given [tex]\alpha=0.1[/tex] we see that [tex]p_v>\alpha[/tex] so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Answer:

6

Step-by-step explanation:

2x² + 4xy − 48y²

2 (x² + 2xy − 24y²)

2 (x − 4y) (x + 6y)

Answer:

The median is located at the 2.5th position, which is halfway between the values 52 and 57.

Step-by-step explanation:

The Median is referred to as the Middle term of a set of Data when ordered in Ascending/Descending order.

Consider the numbers 50, 230, 52, and 57

Arranging them in an Ascending Order

50, 52, 57, 230

The number of data in the set is even.

Dividing the data into two halves (50, 52 and 57, 230)

The median is halfway between the two halves.

The median is located at the 2.5th position, which is halfway between the values 52 and 57.

Answer:

note:

solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment

Answer:

  43 months

Step-by-step explanation:

The amortization formula is ...

  A = P(r/n)/(1 -(1 +r/n)^(-nt))

We want to find the value of t for monthly payment A, financed amount P, interest rate r, and compounding monthly (n=12). Filling in the values, we have ...

  75 = 2500(0.135/12)/(1 -(1 +0.135/12)^(-12t))

  1 -(1.01125^(-12t) = 2500·0.135/(12·75) = 0.375

  1 -0.375 = 1.01125^(-12t) . . . . . add 1.01125^(-12t) -0.375

Next, take logarithms and divide by the coefficient of t.

  log(0.625)/(-12log(1.01125)) = t ≈ 3.50106 . . . . years

In months, that is ...

  3.50106×12 ≈ 42.01

The balance will be not quite zero after 42 payments. (It will be about $0.94.) It will take 43 payments to pay off the credit card balance.

Answer:

42

I did the test and got it right hope this helps

Answer:

a) 4.2%

b) 14.1%

Step-by-step explanation:

a) 0.9³⁰ = 0.0423911583

b) 30C1 × 0.1 × 0.9²⁹ = 0.1413038609

Answer:

a.) 4.2%

b.) 14.1%

Step-by-step explanation:

We solve using the probability distribution formula for selection and this formula uses the combination formula for estimation.

When choosing a random selection of "r" items from a sample of "n" items, The formula is generally denoted by:

P(X=r) = nCr × p^r × q^n-r.

Where p = probability of success

q= probability of failure.

From the given question,

n = number of samples =30,

p = Probability that a student is late = 10% = 0.1,

q=0.9

a.) when no student is late, that is when r = 0, then

P(X=0) = 30C0 × 0.1^0 × 0.9^30

P(X=0) = 0.0424 = 4.24 ≈ 4.2%

b.) when exactly one student is late, that is when r=1, then

P(X=1) = 30C1 × 0.1¹ × 0.9^29

P(X=1) = 0.1413 = 14.13 ≈ 14.1%

Option C: The sum of the infinite geometric series is [tex]\frac{15}{2}[/tex]

Explanation:

The sum of infinite geometric series can be determined using the formula,

[tex]S_{\infty}=\frac{a}{1-r}[/tex]

Substituting the values [tex]a=5[/tex] and [tex]r=\frac{1}{3}[/tex] in the above formula, we have,

[tex]S_{\infty}=\frac{5}{1-\frac{1}{3} }[/tex]

Simplifying the denominator by taking LCM.

Thus, we have,

[tex]S_{\infty}=\frac{5}{\frac{2}{3} }[/tex]

Simplifying, we get,

[tex]S_{\infty}=5\times{\frac{3}{2} }[/tex]

Multiplying, we get,

[tex]S_{\infty}={\frac{15}{2} }[/tex]

Thus, the sum of the infinite geometric series is [tex]\frac{15}{2}[/tex]

Hence, Option C is the correct answer.

Answer:

C

Step-by-step explanation:

Sum = a/(1 - r)

= 5/(1 - ⅓)

= 5/(⅔)

= 5 × 3/2

= 15/2

= 7.5

Answer:

2 mL

Step-by-step explanation:

If the drug is mixed in a solution of 0.5%, it means that for each ml of the solution, there is 0.5% or 0.005 grams of the drug. In order to get 10 mg of the drug, the volume required is:

[tex]0.005\frac{g}{mL}*V = 10*10^{-3} g\\ V= 2\ mL[/tex]

You should add 2 mL of the solution.

*Note that the volume of the bag should not be used since the amount of drug needed was specified in weight and not in concentration.

Answer:

Option A) 0.012

Step-by-step explanation:

We are given the following information:

We treat customers asking for water as a success.

P(customers ask for water) = [tex]\dfrac{3}{5}[/tex] = 0.6

Then the number of customers follows a binomial distribution, where

[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

[tex]P(x < 3) = P(x = 0) + P(x = 1) + P(x = 2) \\= \binom{10}{0}(0.6)^0(1-0.6)^{10} +\binom{10}{1}(0.6)^1(1-0.6)^{9} + \binom{10}{2}(0.6)^2(1-0.6)^{8}\\= 0.0001 +0.0015 + 0.0106\\=0.012[/tex]

0.012 is the probability that less than 3 customers ask for water with their meal.

The correct answer is option a) 0.012

The probability of success in each trial is 3 out of 5 (or 0.6), and the probability of failure is 2 out of 5 (or 0.4). Denoting the number of customers who ask for water as a binomial random variable X with n = 10 and p = 0.6.

The binomial probability formula is given by:

[tex]P(X=k) ={n \choose k}p^k(1-p)^{n-k}[/tex]

where:

n is the number of trials (10 in this case),
k is the number of successes (in this case, less than 3),
p is the probability of success (0.6), and
1−p is the probability of failure (0.4).

Probability that fewer than 3 customers ask for water needs to be found. This means we need to find:

P(X<3)=P(X=0)+P(X=1)+P(X=2)

Calculating each of these probabilities using the binomial formula:

For k=0:
[tex]P(X=0) ={10 \choose 0}(0.6)^0(0.4)^{10-0} = 1\times1\times0.4^{10} = 0.0001048576[/tex]

For k=1:

[tex]P(X=1) ={10 \choose 1}(0.6)^1(0.4)^{10-1} = 10\times0.6\times0.4^{9} = 0.001572864[/tex]

For k=2:

[tex]P(X=2) ={10 \choose 2}(0.6)^2(0.4)^{10-2} = 45\times0.36\times0.4^{8} = 0.010616832[/tex]

Now, we sum these probabilities to get the total probability that fewer than 3 customers ask for water:

P(X<3) = P(X=0) + P(X=1) + P(X=2)

P(X<3) = 0.0001048576 + 0.001572864 + 0.010616832

P(X<3) = 0.0122945536

Therefore rounding this value results in a probability of approximately 0.012.

Answer:

1) n = 39916800

2) n = 1663200

3) n = 330

Step-by-step explanation:

1) If the blue balls are distinguishable as are the red balls

Then you can arrange these balls in the following ways, we must use a permutation

In totally we have 11 balls, then

n = 11P11

[tex]n = \frac{11!}{(11-11)!} = 11! = 39916800\\[/tex]  

2) If Blue balls are distinguishable, but the red balls are identical

In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls

[tex]n = \frac{11!}{4!} = \frac{39916800}{24} = 1663200[/tex]

3) If the balls of each color are indistinguishable

We proceed equal to the before case but we include a correction due to blue balls also

[tex]n = \frac{11!}{4!*7!} = \frac{39916800}{24*5040} = 330[/tex]

Answer:

solution attached below

Step-by-step explanation:

To find the sinusoids in the given equations, we can use the derivative and integral properties of phasors. For the first equation, υ2(t) = 1/100 dυ1(t)/dt + 20υ1(t), you can find the phasor representation of υ1(t) using the given equation υ1(t) = 10cos(100t + 90°) V and apply the derivative property of phasors. For the second equation, i2(t) = 10∫i1(t)dt - 3i1(t), you can find the phasor representation of i1(t) using the given equation i1(t) = -4cos(5t) A and apply the integral property of phasors. Therefore, the sinusoids in the given equations are υ2(t) ≈ 10cos(100t + 90°) + 2000cos(100t + 90°) V and i2(t) ≈ (4/5)cos(5t + 180°) + 12cos(5t + 180°) A·s.

To find the sinusoids in the given equations, we can use the derivative and integral properties of phasors.

For the first equation, υ2(t) = 1/100 dυ1(t)/dt + 20υ1(t), we can start by finding the phasor representation of υ1(t) using the given equation υ1(t) = 10cos(100t + 90°) V:

υ1(t) = 10e^(j(100t + 90°))

Next, we differentiate υ1(t) with respect to t to find dυ1(t)/dt:

dυ1(t)/dt = -1000sin(100t + 90°) V/s

Using the derivative property of phasors (multiplying by jω), we have:

jωυ1(t) = j(100)(10)e^(j(100t + 90°)) = 1000ej(100t + 90°) V/s

Now, we can substitute these phasor representations back into the original equation:

υ2(t) = 1/100 (1000ej(100t + 90°) V/s) + 20(10e^(j(100t + 90°)) V

Simplifying, we get:

υ2(t) ≈ 10ej(100t + 90°) + 2000ej(100t + 90°) V

For the second equation, i2(t) = 10∫i1(t)dt - 3i1(t), we can find the phasor representation of i1(t) using the given equation i1(t) = -4cos(5t) A:

i1(t) = -4e^(j(5t + 180°))

Next, we can integrate i1(t) with respect to t to find ∫i1(t)dt:

∫i1(t)dt = (-4/5)e^(j(5t + 180°)) A·s

Using the integral property of phasors (dividing by jω), we have:

(1/jω)i1(t) = (-1/(j5))(4)e^(j(5t + 180°)) = (4/5)ej(5t + 180°) A·s

Substituting these phasor representations back into the original equation, we get:

i2(t) ≈ (4/5)ej(5t + 180°) - 3(-4)e^(j(5t + 180°)) A·s

Therefore, the sinusoids in the given equations are υ2(t) ≈ 10cos(100t + 90°) + 2000cos(100t + 90°) V and i2(t) ≈ (4/5)cos(5t + 180°) + 12cos(5t + 180°) A·s.

Answer:

Which of the following is a quantitative continuous variable?

b. Distance a family travels on vacation

e. Amount spent on the vacation, to the nearest $100.

Step-by-step explanation:

Quantitative variables use numbers to express attributes, there are 2 types:

1. Quantitave continuous variables use numbers to express the attributes but, could have an infinite value between its maximum and minimum values, and are able to be divided into smaller values, such as in options b and e.

2. Quantitative discrete, also use numbers to express attributes, but they may have some, but not all the values, and must be integers, such as in options:

c. Number of vacations a family takes per year

d. Number of consecutive years that a family goes on a vacation (Let a trip of at least 200 miles from home be defined as "vacation").

e. Amount spent on the vacation, to the nearest $100.

And there are the cualitative variables, which use words to express attributes, such as in:

a. Where a family goes on vacation.

Answer: 0.0935

Step-by-step explanation: p(business major) = 0.17, p(receiving financial aids) = 0.55

The two events are independent that's the occurrence of one does not affect the other.

Hence, the probability of that the student is a business major and receiving financial aid is given below as

p(business major and financial aid) = 0.17×0.55 = 0.0935.

Answer:

0.8753

Step-by-step explanation:

Total Population=194+142+89=425

Population of those who smoke=48+33+20=101

Population of non smokers=425-101=324

Population of those in 18-22 bracket=194

Population of nonsmoker's in 18-22 age bracket=194-48=146

Probability of getting someone who is age​ 18-22 = [TeX]\frac{194}{425}[/TeX]

Probability of getting someone who does not smoke = [TeX]\frac{324}{425}[/TeX]

Let the event that the person is in age bracket 18-22 be A

Let the event that the person does not smoke be B

Therefore, the probability of getting someone who is age​ 18-22 or does not smoke

=Probability of getting someone who is age​ 18-22 + Probability of getting someone who does not smoke - Probability of those who do not smoke and are in the age bracket 18-22

P(A or B)=P(A)+P(B)-P(A and B)

=[TeX]\frac{194}{425}+\frac{324}{425}-\frac{146}{425}[/TeX]

[TeX]=\frac{194+324-146}{425}=\frac{372}{425}=0.8753[/TeX]

Answer:

D.

The IQR for Week 1 is 31, and the IQR for Week 2 is 25.

Step-by-step explanation:

Answer: D.The IQR for week 1 is 31 and the IQR for week 2 is 25

Step-by-step explanation: When you divid a data set in groups of 4 and measure the bulk of the values, this is called Interquatile Range (IQR).

It's calculated as follows:

1) Put the data in order;

week 1 : 39 50 58 63 72 81 104

week 2 : 34 54 62 68 72 79 110

2) Find the median of each data set:

*Note: Median is the middle value of a set.

week 1 : Median 63

week 2 : Median 68

3) Find Q1, which is the median in the lower half of the set:

week 1: the lower set is 39 50 58.

The middle value is 50.

So Q1 = 50.

week 2: the lower set is 34 54 62

The middle value is 54.

So Q1 = 54.

4) Find Q3, which is the middle value of the upper half:

week 1 : the upper half is 72 81 104

Q2 = 81

week 2 :  the upper half is 72 79 110

Q2 = 79

5) To determine IQR, subtract Q1 and Q3:

week 1: 81 - 50 = 31

week 2 : 79 - 54 = 25

In conclusion, the IQR for week 1 is 31 and for week 2 is 25.

Answer:

Yes.

Step-by-step explanation:

According to the Transitive property of the Algebraic properties of equality, two values are said to be equal is they are differently equal to a corresponding third party. This is, If a=b and b=c then a=c.

Hence, if x=5 and 5=y, then following the transitive property of Algebraic properties of equality, x=y, hence the Algebraic property of equality Justifies the statement.

Answer:

[tex]P(x \geq 9)=P(X=9)+P(X=10)[/tex]

[tex]P(X=9)=(10C9)(0.9)^9 (1-0.9)^{10-9}=0.387[/tex]

[tex]P(X=10)=(10C10)(0.9)^{10} (1-0.9)^{10-10}=0.349[/tex]

And adding we got:

[tex]P(x \geq 9)=P(X=9)+P(X=10)=0.387+0.349=0.736[/tex]

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

[tex]X \sim Binom(n=10, p=1-0.1=0.9)[/tex]

Where 1-p = 1-0.1=0.9 represent the probability of being NOT defective

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

And we want to find this probability:

[tex]P(x \geq 9)=P(X=9)+P(X=10)[/tex]

[tex]P(X=9)=(10C9)(0.9)^9 (1-0.9)^{10-9}=0.387[/tex]

[tex]P(X=10)=(10C10)(0.9)^{10} (1-0.9)^{10-10}=0.349[/tex]

And adding we got:

[tex]P(x \geq 9)=P(X=9)+P(X=10)=0.387+0.349=0.736[/tex]

Answer:

Gene would pay approximately $56.19 for his total purchase of two pairs of shorts, one polo shirt, and one pair of shoes.

Step-by-step explanation:

First identify what you know:

1) Every item in the store is 40% off the ticketed price (original price)

2) Gene buys two pairs of shorts for $18.77 each.

3) Gene buys one polo shirt for $21.87.

4) Gene buys one pair of shoes for $34.24.

5) Discount is taken at the register.

So, assuming that each price given, IS the original price, we need to figure out exactly how much Gene paid with the 40% discount. We can solve this in two different ways.

1) Individually calculate 40% of each price of each item, and then add them up to find the total discounted price of all the items.

2) Add all the original items and calculate 40% off the original price, and subtract that amount from the original price.

I find it simplest to add up the original prices, and find the total, and then calculate the discounted (40%) total.

Original total = (2 x $18.77) + ($21.87) + ($34.24)

Original Price = ($37.54) + ($21.87) + ($34.24)

Original Total Price: $93.65

Now, we know that without the discount, the total for ALL the items would be $93.65. Now, we just need to find out what 40% of 93.65 is! TO do this, simply multiply 93.65 by 40% OR multiply 93.65 by 0.40.

93.65 x 0.40 = 37.46

So, 40% of $93.65 is $37.46. Now we just need to subtract that percentage to find the discounted price!

$93.65 - $37.46 = $56.19

Gene paid approximately $56.19 for two pairs of short, one polo shirt, and one pair of shoes, at a discount of 40% off.

Hope this helps! :)

Answer:

10 bags of chips

Step-by-step explanation:

15(2)+3x=60

30+3x=60

3x=30

x=10

Therefore, 10 bags of chips

Answer:

0.44290869

Step-by-step explanation:

The Maclaurin series for sin⁻¹(x) is given by

sin⁻¹(x) = x + [tex]x^{\alpha } _{n=1}[/tex] [tex]\frac{1.3.5...(2n - 1)}{2.4.6...(2n)} * \frac{x^{2n + 1} }{2n + 1}[/tex]

Use the first five terms of the Maclaurin series above to approximate sin⁻¹ [tex]\frac{3}{7}[/tex]. (Round your answer to eight decimal places.)

Answer

sin⁻¹(x) = x + [tex]x^{\alpha } _{n=1}[/tex] [tex]\frac{1.3.5...(2n - 1)}{2.4.6...(2n)} * \frac{x^{2n + 1} }{2n + 1}[/tex]

in the above equation [tex]x^{\alpha } _{n=1}[/tex]  summation from n=1 to ∞

we are estimating this for the first 5 terms as follows

sin⁻¹(x) = x +   [tex]\frac{1}{2} * \frac{x^{3} }{3}[/tex]  +  [tex]\frac{1*3}{2*4} * \frac{x^{5} }{5}[/tex]  +  [tex]\frac{1*3*5}{2*4*6} * \frac{x^{7} }{7}[/tex]  +  [tex]\frac{1*3*5*7}{2*4*6*8} * \frac{x^{9} }{9}[/tex]

sin⁻¹(x) = x +  [tex]\frac{x^{3} }{6}[/tex]  +  [tex]\frac{3x^{5} }{40}[/tex]  +[tex]\frac{15x^{7} }{336}[/tex]  +  [tex]\frac{105x^{9} }{3456}[/tex]  

now to get

sin⁻¹([tex]\frac{3}{7}[/tex]) substitute

hence,

sin⁻¹([tex]\frac{3}{7}[/tex]) = [tex]\frac{3}{7} + \frac{\frac{3}{7} ^{3} }{6} + \frac{3 * \frac{3}{7} ^{5} }{40} + \frac{15* \frac{3}{7} ^{7} }{336} + \frac{105* \frac{3}{7} ^{9} }{3456}[/tex]  

sin⁻¹([tex]\frac{3}{7}[/tex]) = 0.42857142 + 0.01311953 + 0.00108437 + 0.00011855 + 0.00001482

           =  0.44290869

Answer:

Step-by-step explanation:

a) November sales = (Total Uncollected Sales - Uncollected Sales from December) / Collection rate after two months

= ($121,100 - $87,300) / 0.20

November sales = $169, 000.00

b) December sales = Uncollected sales from December / Collection rate of the previous month sales,

Therefore: December sales = $87,300 / 0.45 = $194,000

December sales = $194,000.00

c) Each month's collection for the company are:

Collections for ech month = 0.20(Sales from 2 months ago) + 0.25(Last month's sales) + 0.55 (Current sales)

January collections = 0.20($169000.00) + 0.25($194,000.00) + 0.55($132,000)

January collections = $154,900.00

February collections = 0.20($194,000.00) + 0.25($132,000) + 0.55($149,000)

February collections = $153,750.00

March collections = 0.20($132,000) + 0.25($149,000) + 0.55($164,000)

March collections = $153,850.00

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

[tex]SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2} } }{N} }[/tex]

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

[tex]X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\[/tex]

3. Caclulate Standard deviation:

[tex]SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2} } }{5} }[/tex]

[tex]SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251[/tex]

Answer:

See the pictures attached

Step-by-step explanation:

Answer and Step-by-step explanation:

(a)

E[XY] = 1/4*0*1 + 1/4*1*0 + 1/4*-1*0 +1/4*0*-1 = 0

(b)

E[X] = 0, E[Y] = 0

Thus, Cov(X,Y) = E[XY] - E[X]E[Y] = 0

So, Var(X + Y) = Var(X) + Var(Y) is True

The answer is Yes

(c) No, the converse is not true

(a) The value of E[XY] is zero.

(b) Yes  For this pair of random variables (X, Y) is true for the given relation.

(c) No, the converse is not true.

Variance is the value of the squared variation of the random variable from its mean value, in probability and statistics.

The given data in the problem will be;

(X, Y)  is a random variable

pairs of values is given as  (0,1), (1,0), (−1,0), (0,−1).

E[XY] =?

(a) The value of E[XY] is zero.

[tex]E[XY] = \frac{1}{4}\times 0\times1 +\frac{1}{4}\times 1\times 0 + \frac{1}{4} \times 1\times 0 +\frac{1}{4}\times0\times1 = 0[/tex]

Hence the value of E[XY] is zero.

(b) Yes or this pair of random variables (X, Y) is true for the given relation.

[tex]E[X] = 0, E[Y] = 0[/tex]

[tex]\rm Cov(X,Y) = E[X,Y] - E[X]E[Y] = 0Var(X + Y) = Var(X) + Var(Y)[/tex]

Hence ) Yes  For this pair of random variables (X, Y) is true for the given relation.

(c) No, the converse is not true

X and Y are independent

[tex]Var(X+Y)=Var(X)+Var(Y).[/tex]

Hence ) No, the converse is not true

To learn more about the variance refer to the link;

https://brainly.com/question/7635845

Answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is 0.334.

Step-by-step explanation:

We have a normal distribution with mean=56 years and s.d.=4 years.

We have to calculate the probability that a randomly selected CEO have an age between 50 and 55.

We have to calculate the z-value for 50 and 55.

For x=50:

[tex]z=\frac{x-\mu}{\sigma}=\frac{50-56}{4}=\frac{-6}{4}= -1.5[/tex]

For x=55:

[tex]z=\frac{x-\mu}{\sigma}=\frac{55-56}{4}=\frac{-1}{4}=-0.25[/tex]

The probability of being between 50 and 55 years is equal to the difference between the probability of being under 55 years and the probability of being under 50 years:

[tex]P(50<x<55)=P(x<55)-P(x<50)\\\\P(50<x<55)=P(z<-0.25)-P(z<-1.5)\\\\P(50<x<55)=0.40129-0.06681\\\\P(50<x<55)=0.33448[/tex]

Final answer:

The probability that the age of a randomly selected CEO will be between 50 and 55 years old is approximately 0.3345.

Explanation:

To find the probability that the age of a randomly selected CEO will be between 50 and 55 years old, we need to calculate the z-scores for both values and then use the standard normal distribution table.

Step 1: Calculate the z-score for 50 years old:

z = (50 - 56) / 4 = -1.5

Step 2: Calculate the z-score for 55 years old:

z = (55 - 56) / 4 = -0.25

Step 3: Use the standard normal distribution table to find the area to the left of each z-score:

P(z < -1.5) = 0.0668

P(z < -0.25) = 0.4013

Step 4: Calculate the probability between the two z-scores:

P(-1.5 < z < -0.25) = P(z < -0.25) - P(z < -1.5) = 0.4013 - 0.0668 = 0.3345

Therefore, the probability that the age of a randomly selected CEO will be between 50 and 55 years old is approximately 0.3345.

Answer:

The answer to your question is Domain (-∞, ∞) Range  [-4, ∞)

Step-by-step explanation:

The Domain is the set of all possible values of the independent variable (x).

The Range is the set of all the possible values of the dependent variable when substitute the domain in the function.

On the graph, we find the domain looking at the x-axis

On a graph, we find the range, looking at all the y-axis

In this graph, x has values from -infinite to infinite, then, the domain is (-∞, ∞).

In this graph, y has values from -4 to infinite, then, the range is [-4, ∞)

Answer:

37.9 cm

Step-by-step explanation:

Arc length is:

s = 2πr (θ/360°)

where r is the radius and θ is the arc angle.

40π cm = 2πr (190°/360°)

20 cm = r (190°/360°)

r = 37.9 cm

Answer: the radius of the circle on which the arc sits is 3.8 cm

Step-by-step explanation:

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ represents the central angle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

θ = 190 degrees

Length of arc = 40π centimeters

Therefore,

40π = 190/360 × 2 × π × r

Dividing both sides of the equation by π, it becomes

40 = 380r/360

380r = 40 × 360 = 1440

r = 1440/380

r = 3.8 to the nearest tenth

Answer:

Expected value: 3/7

Change landing on purple to -1.5

Step-by-step explanation:

Expected value

=3(1/7) + 1(2/7) + 0(2/7) - 1(2/7) = 3/7

Fair game: Expected value = 0

Change the value of 0 to -1.5

Answer:

3/7

change 0 to -1.5

Step-by-step explanation:

Got a 100

Complete Question

Experiments on learning in animals sometimes measure how long it takes a gerbil to nd its way through a maze. The mean time is 14 seconds for one particular maze. A researcher thinks that playing soothing music will cause the gerbils to complete the maze slower. She measures how long each of 34 gerbils takes with a noise stimulus.

She measures how long each of 34 gerbils takes with a noise stimulus. The sample mean is x = 16.5 seconds.

The alternative hypothesis for the significance test is

a. Ha:μ≠14

b. Ha:μ=16.5.

c. Ha:μ>14

Answer:

Option C is correct.

The alternative hypothesis for the significance test is Ha:μ>14

Step-by-step explanation:

The researcher sets up a maze and notes that the mean time to complete the maze is 14 seconds for gerbils.

She then theorizes that playing soothing music for the gerbils while they complete the maze slows the gerbils down.

Using a sample of 34 gerbils, she tests her hypothesis, and truly, the sample mean, when she plays soothing noise in the background, rises from 14 to 16.5 seconds; indicating that the noise stimulus indeed, slows down the gerbils.

Alternative hypothesis theorizes that there is a relationship between two variables. A relationship that is significant enough statistically, that when the hypothesis is introduced, it affects the result of the experiment just in the way that the conductors of the experimemt have predicted.

So, if the alternative hypothesis for this 'gerbils completing maze experiment' is represented by Ha, just like the researcher theorizes, when Ha is introduced, the gerbils become slower and the mean time for completing the maze is evidently higher than the mean.

Mathematically, it can be written as

Ha:μ>14

Again, this is interpreted as, when Ha is introduced (soothing music), the mean time for the gerbils completing the maze is higher than the original mean (14).

Hope this Helps!!!

Answer:

The slope is -5/6

Step-by-step explanation:

To find the slope of a line given two points, we use the formula

m= (y2-y1)/(x2-x1)

  = (-1-4)/(4--2)

  =-5/(4+2)

  =-5/6

Answer: the slope of the line between the two points is - 5/6

Step-by-step explanation:

Slope, m = change in value of y on the vertical axis / change in value of x on the horizontal axis.

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (- 2, 4) and (4, - 1),

y2 = - 1

y1 = 4

x2 = 4

x1 = - 2

Slope,m = (- 1 - 4)/(4 - - 2) = - 5/6