Write an equation of the line that passes through (0, 5) and (−1.5, 1)

Answers

Answer 1
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's establish the formula we will be using to achieve the equation of the line.

y - y1 = m ( x - x1 )

m = gradient / slope of line

To use the previous formula, we will need to first find the gradient ( m ) using the below formula. We will be substituting the values of the points given in the problem into this formula.

m = ( y2 - y1 ) / ( x2 - x1 )

m = ( 5 - 1 ) / ( 0 - ( - 1.5 ) )

m = ( 5 - 1 ) / ( 0 + 1.5 )

m = 4 / 1.5

m = 8 / 3

Now we will substitute the value of ( m ) from above into the formula for the line. We will also be substituting the values of one of the given points into the formula. In this example, we will be using the point ( 0, 5 ).

y - y1 = m ( x - x1 )

y - 5 = ( 8 / 3 ) ( x - 0 )

y - 5 = ( 8 / 3 )x

y = ( 8 / 3 )x + 5

FINAL ANSWER:

The equation of the line is:

y = ( 8 / 3 )x + 5

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Answer 2

The equation of the line that passes through (0, 5) and (−1.5, 1) is y = 8/3 x + 5

The equation can be represented as follows:

y = mx + b

where

m = slope

b = y-intercept

lets find the slope

(0, 5)  (−1.5, 1)

m = 1 - 5 / -1.5 - 0 = - 4 / -1.5 ≈  8 / 3

we multiplied the numerator and denominator by 2

b = 5, b is the value of y when x = 0.

Therefore, the equation will be as follows:

y = 8/3 x + 5

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Related Questions

Right triangle ABC is shown below.

Answers

The similar right triangle would be created by a rise of 8 and a run of 6.
Answer is : 6 .
Thanks

Two worded maths questions. Even if you know one answer it would help! Please also give working out if possible.

Answers

Answer:

675 litres 80 mL

Step-by-step explanation:

1. The total amount of oil in the two tanks at the start is ...

  total oil = n + (n +150) + 0 = 2n+150 . . . . litres

The amount of oil in tank C at the end is 1/3 this amount, or

  oil in tank C = (total oil)/3 = (2n+150)/3 . . . . litres

The amount pumped into tank C was 500 litres, so we have ...

  (2n +150)/3 = 500

  2n +150 = 1500 . . . . . . multiply by 3

  2n = 1350 . . . . . . . . . . . subtract 150

  1350/2 = n = 675 . . . . . divide by the coefficient of n

___

2. Let x represent the amount remaining in container A. Then 4x is the amount in tank B. Before the transfer, the amount in each container was the same, so ...

  x +120 = 4x -120 . . . . . A had 120 more than remains; B had 120 less

  240 = 3x . . . . . . . . add 120-x

  240/3 = x = 80 . . . divide by the coefficient of x

The amount of liquid left in container A is 80 mL.

Betsy and 3 of her friends are splitting a whole watermelon. There are 6 circular slices of watermelon. How many slices of watermelon will each person get?

Answers

6 slices divided by 4 people comes out to 6/4 slices per person, or 3/2, or 1.5 slices per person.

The slices of watermelon each person will get is  1.5 slices.

If the watermelon is divided equally, the number of slices each person would get can be determined by dividing the total slices of watermelon by the total number of friends.

Slice each person would get = total slices / total number of friends

6 / 4 = 1.5 slices

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Describe t-test and explain how to interpret its results?

Answers

The t test compares two averages (means) and tells you if they are different from each other. The t test also tells you how significant the differences are; In other words it lets you know if those differences could have happened by chance. For example, if listening to brain wave beats, makes one smarter or not, 2 groups are created, where one group listens to the real brain wave frequencies andvthe other group listens to a made up sound, then try to record the outcome (if it was by chance, a placebo effect, or actually true). The outcome is recorded in the form of a t-score. This t score is the ratio of the difference between two groups and the difference within the groups. The larger the t score, the more difference there is between groups. The smaller the t score, the more similarity there is between groups. How can you really tell that the difference between the two groups is significant?, by calculating the P value. Every t-score has a p-value to go with it. A p-value is the probability that the results from your sample data occurred by chance. P-values are from 0% to 100%. They are usually written as a decimal. For example, a p value of 5% is 0.05. Low p-values are good; They indicate your data did not occur by chance. For example, a p-value of .01 means there is only a 1% probability that the results from an experiment happened by chance. In most cases, a p-value of 0.05 (5%) is accepted to mean the data is valid. There are three main types of t-test: 1.)An Independent Samples t-test compares the averages (means) for two groups. 2.)A Paired sample t-test compares averages (means) from the same group at different times (say, one year apart). 3.)A One sample t-test tests the average of a single group against a known average. For example, using a paired sample t test (in which everything is recorded in figures), we have two scenarios or conditions which we label A and B, individuals are tested in these two scenarios separately and the result is recorded for both.Let's say the experiment is carried out 10 times on 10 different days (not consecutively). Record everything in a table, the responses gotten in scenario A at the 10 different occasions (labelled 1 to 10) and the same for scenario B. Next step is to subtract the results gotten in B from the ones gotten in A in each of the occassions. After that, sum of the differences gotten from each occasion. Next, square the differences you obtained from each occassion and sum up the squared differences. ( do not square the sum gotten from the differences, but instead square each difference in each occassion, then get their sum).After which we calculate the t-score using the formula for paired sample t-test. After you have calculated the t-score. You have to compare it to the t-table value which you can find in books or even online. To be able to compare your results to the one already written down in the table, first calculate the degree of freedom by subtracting 1 from the number of occasions you did the experiment (in this case;10-1)= 9. Then check the value you are closest to on the t-table reading the values on the same line as the degree of freedom 9, that way you can obtain your p-value (which is also written down in the t-table), if p is =/<0.05= then your result is significant.

A major league baseball pitcher throws a pitch that follows these parametric equations:

x(t) = 143t
y(t) = –16t2 + 5t + 5.
Recall that the speed of the baseball at time t is

s(t)=√ [x '(t)]2 + [y ' (t)]2 ft/sec.

What is the speed of the baseball (in mph) when it passes over homeplate?

Answers

97.67 mph The distance between the pitches plate and homeplate is 60.5 ft. So the time t at which the ball passes over home plate will be 60.5 = 143t 0.423 = t Now calculate the first derivative of each equation. So x(t) = 143t x'(t) = 143 y(t) = -16t^2 + 5t + 5 y'(t) = -32t + 5 So at 0.423 seconds, the respective velocities will be x'(0.423) = 143 y'(0.423) = -32 * 0.423 + 5 = -13.536 + 5 = -8.536 And the speed will be sqrt(143^2 + (-8.536)^2) = sqrt(20449 + 72.8633) = sqrt(20521.86) = 143.2545 ft/s Now convert from ft/s to mile/hour 143.2545 ft/s * 3600 s/hour / 5280 = 97.67 mile/hour = 97.67 mph

The speed of the baseball when it passes over the home plate is 97.67 mph.

Given :

[tex]x(t) = 143t[/tex]    ---- (1)[tex]y(t) = -16t^2+5t+5[/tex]    ---- (2)The distance between the pitcher's plate and the home plate is 60.5 ft.

Differentiate the function x(t) and y(t) with respect to t.

[tex]x'(t)=143[/tex]

[tex]y'(t)= -32t+5[/tex]   ---- (3)

Now, put the value of x(t) in equation (1).

60.5 = 143t

t = 0.423 sec

Now, put the value of t in equation (3).

[tex]y'(t) = -32(0.423)+5=-8.536[/tex]

Now, [tex]s(t) = \sqrt{(x'(t))^2+(y'(t))^2}[/tex]

[tex]s(t)=\sqrt{143^2+(-8.536)^2}[/tex]

[tex]\rm s(t)=\sqrt{20521.8633} = 143.2545\;ft/sec[/tex]

[tex]\rm s(t) = 97.67 mph[/tex]

Therefore, the speed of the baseball when it passes over the home plate is 97.67 mph.

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How many terms are in the arithmetic sequence 7, 0, −7, . . . , −175?

Hint: an = a1 + d(n − 1), where a1 is the first term and d is the common difference

Answers

Sent a picture of the solution to the problem (s). Used the hint and substituted all the know quantities.

What is the area of a parallelogram whose vertices are A(−4, 9) , B(11, 9) , C(5, −1) , and D(−10, −1) ?

Answers

Let

[tex]A(-4,9)\\B(11,9)\\C(5,-1) \\D(-10,-1)\\E(-4.-1)[/tex]  

using a graphing tool  

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

so

[tex]AB=CD \\AD=BC[/tex]

The area of a parallelogram is equal to

[tex]A=B*h[/tex]  

where  

B is the base

h is the height  

the base B is equal to the distance AB

the height h is equal to the distance AE  

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

[tex]A(-4,9)\\B(11,9)[/tex]  

substitute the values

[tex]d=\sqrt{(9-9)^{2}+(11+4)^{2}}[/tex]

[tex]d=\sqrt{(0)^{2}+(15)^{2}}[/tex]

[tex]dAB=15\ units[/tex]

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

[tex]A(-4,9)\\E(-4.-1)[/tex]  

substitute the values

[tex]d=\sqrt{(-1-9)^{2}+(-4+4)^{2}}[/tex]

[tex]d=\sqrt{(-10)^{2}+(0)^{2}}[/tex]

[tex]dAE=10\ units[/tex]

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

[tex]A=B*h[/tex]

[tex]A=AB*AE[/tex]

substitute the values

[tex]A=15*10=150\ units^{2}[/tex]

therefore

the answer is

the area of the parallelogram is [tex]150\ units^{2}[/tex]


Final answer:

The area of the parallelogram is 0 units.

Explanation:

To find the area of a parallelogram, we can use the formula A = base * height. We can find the length of the base by finding the distance between points A and D, which is 11 units. To find the height, we can find the distance between points A and B, which is 0 units. Therefore, the area of the parallelogram is 0 units.

The shadow of a vertical tower is 50 m long when the angle of elevation of the sun is 35°. find the height of the tower. © k12 inc. 2. an airplane is flying 12,330 feet above level ground. the angle of depression from the plane to the base of a building is 11°. how far must the plane fly horizontally before it is directly over the building?

Answers

1.  To find the shadow of the tower, you must calculate the tangent of 35. Tan. (35) = x/ 50. X= tan (35) (50) = 35. The tower is 35 m.

2. To find how far the plane must fly, you must calculate the tangent of 11. Tan. (11) = 12,330 / x. X = 12,330/ tan (11). X = 63,432. The plane must fly 63,432 feet before it is directly over the building.

Hope this helps.

"THIS IS A 90 POINT QUESTION"
A) F IS A INCREASING ON THE INTERVAL X < 0
B) F IS A DECREASING ON THE INTERVAL X < 0
C) F IS A INCREASING ON THE INTERVAL 0 < X < 1
D) F IS A DECREASING ON THE INTERVAL 0 < X < 1
E) F IS A INCREASING ON THE INTERVAL 1 < X < 3
F) F IS A DECREASING ON THE INTERVAL 1 < X < 3
G) F IS A INCREASING ON THE INTERVAL X > 3
H) F IS A DECREASING ON THE INTERVAL X > 3
"SELECT ALL THAT APPLY"

Answers

that would be letter F and letter B
F) F IS A DECREASING ON THE INTERVAL 1 < X < 3

A) F IS A INCREASING ON THE INTERVAL X < 0 

hope this helps



The number of terms in a binomial expansion
is one less than the power
is equal to the power
is one more than the power

Answers

It should be one more than the power

Ex(x+y)^3=x^3+3x^2y+3xy^2+y^3
As you can see power of 3 but 4 terms

Answer:

(C) is one more than the power

Step-by-step explanation:

Let us consider a binomial expansion:

[tex](x+y)^2=x^2+2xy+y^2[/tex]

The power of the above expansion is [tex]2[/tex] and the number of the terms in the above binomial expansion are [tex]3[/tex], thus the total number of terms in the binomial expansion is one more than the power.

Hence, Option C is correct.

The savings account offering which of these APRs and compounding periods offers the best APY?
4.0784% compounded monthly
4.0798% compounded semiannually
4.0730% compounded daily

Answers

[tex]\bf \qquad \qquad \textit{Annual Yield Formula} \\\\ ~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\ ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\to &12 \end{cases} \\\\\\ \left(1+\frac{0.040784}{12}\right)^{12}-1\\\\ -------------------------------\\\\ ~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\ [/tex]

[tex]\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, thus twice} \end{array}\to &2 \end{cases} \\\\\\ \left(1+\frac{0.040798}{2}\right)^{2}-1\\\\ -------------------------------\\\\ [/tex]

[tex]\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\ ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\to &365 \end{cases} \\\\\\ \left(1+\frac{0.040730}{365}\right)^{365}-1[/tex]

Answer:

Option C is correct.

Step-by-step explanation:

The formula is = [tex](1+\frac{r}{n})^{n}-1[/tex]

r = rate of interest

n = number of times its compounded

1. 4.0784% compounded monthly

here n = 12

[tex](1+\frac{0.040784}{12})^{12} -1[/tex] = 1.0403-1 = 0.0403

2. 4.0798% compounded semiannually

here n = 2

[tex](1+\frac{0.040798}{12})^{2} -1[/tex] = 1.0066-1 = 0.0066

3. 4.0730% compounded daily

here n = 365

[tex](1+\frac{0.040730}{12})^{365}[/tex] = 3.328-1 = 2.328

Use the distributive property in two different ways to find the product of 127 and 32.

Answers

1.)   127(30+2) = 3810+254=4064

2.) 32(100+20+7)= 3200+640+224=4064

Answer and explanation:

Use the distributive property in two different ways to find the product of 127 and 32.

Distributive property says that,

[tex]a(b+c)=ab+ac[/tex]

We have to find product of 127 and 32,

1) Split 127 as 100+27

[tex]127\times32=(100+27)\times 32[/tex]

Apply distributive property,

[tex]127\times32=100\times 32+27\times 32[/tex]

[tex]127\times32=3200+864[/tex]

[tex]127\times32=4064[/tex]

2) Split 32 as 30+2

[tex]127\times32=127\times (30+2)[/tex]

Apply distributive property,

[tex]127\times32=127\times 30+127\times 2[/tex]

[tex]127\times32=3810+254[/tex]

[tex]127\times32=4064[/tex]

Which expression shows how to multiply 5 times 381 by using place value and expanded form

Answers

5 * 1 + 5 * 80 + 5 * 300

What is 1.5 x 10^-1 in standard form?

Answers

Here is your answer:

Its scientific notation:

Its negative so your going to the left:

1.5×10^-1
=0.015

Answer:

the answer is .15

Step-by-step explanation:

Robert can swim the first 50 meters of a race in 1 minute. Then he slows down by 12 seconds for each of the next 50 meters of a race. How long will it take Robert to swim a 400 meter race?

Answers

Final answer:

It takes Robert 13 minutes and 36 seconds to complete a 400 meter swimming race when he swims the first 50 meters in 1 minute and slows down by 12 seconds for each subsequent 50 meters.

Explanation:

In this mathematical problem, Robert swims the first 50 meters in 1 minute. He slows down by 12 seconds for each subsequent 50 meters of the race. The total distance Robert needs to swim is 400 meters. The 400 meters is split into eight 50 meter increments.

For the first increment, it takes Robert 1 minute (or 60 seconds). For the next seven increments, Robert swims each in 12 seconds slower than the previous increment.

Therefore, the total time in seconds for Robert to complete the 400 meters swimming race is:

60 + 72 + 84 + 96 + 108 + 120 + 132 + 144 = 816 seconds

This is equivalent to 13 minutes and 36 seconds.

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Suppose r contains a reference to a new rectangle(5, 10, 20, 30). which of the fol­lowing assignments is legal? (look inside the api documentation to check which interfaces the rectangle class implements.)
a. rectangle a = r;
e. measurable e = r;
b. shape b = r; f. serializable f = r;
c. string c = r; g. object g = r;
d. actionlistener d = r;

Answers

The legal in this following assignments is no other than e. measurable e = r. It is measurable because r contains a reference to a new rectangle(5, 10, 20, 30). So the interfaces the rectangle class implements is measurable, we really can measure it by solving the rectangle sides.
Final answer:

The Java Rectangle class implements both the Shape and Serializable interfaces. Therefore, Rectangle r can be legally assigned to Rectangle, Shape, Serializable, and Object data types. It can't be assigned to a String, Measurable, and ActionListener as Rectangle doesn't implement these.

Explanation:

In Java, the Rectangle class implements the Shape and Serializable interfaces. Therefore, the legal assignments would be:

Rectangle a = r; because r is a Rectangle, you can assign r to another Rectangle object.Shape b = r; because Rectangle implements the Shape interface, you can assign r to a Shape object.Serializable f = r; because Rectangle implements the Serializable interface, you can assign r to a Serializable object.Object g = r; because all classes in Java extend the Object class implicitly, you can assign r to an Object.

The rest assignments are not legal because the Rectangle class doesn't implement Measurable, ActionListener interfaces and it cannot be assigned to a String.

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Jessica wants to serve 3/4 of a pint of orange juice to each of her guests. Her juice jar can hold 12 full pints of juice. Jessica can serve the juice to guest

Answers

Okay. I'm guessing that you are asking how many guests she has coming, because she's serving 3/4 to each of them and her juice jar hold 12 pints of juice. What we would have to do is divide, because there is a fraction in the problem. In other words, Keep the first number (12) the same, change to division sign into a multiplication sign, and then flip the fraction around (change 3/4 to 4/3). The problem would be 12/1 * 4/3. Multiply straight across both fractions to get 48/3. 48/3=16. Jessica has 16 guests at her party.

Answer:16

Step-by-step explanation:

s=n(a1+an)/2 gives the partial sum of an arithmetic sequence. What is the formula solved for an?

Answers

The given formula is
[tex]S= \frac{n}{2} (a_{1}+a_{n})[/tex]

Multiply each side by 2.
[tex]2S=n(a_{1}+a_{n}) [/tex]

Divide each side by n.
[tex] \frac{2S}{n} =a_{1} + a_{n}[/tex]

Subtract a₁ from each side.
[tex] \frac{2S}{n} - a_{1} = a_{n}[/tex]

Answer: [tex]a_{n} = \frac{2S}{n} - a_{1} [/tex]

Solve the problem as directed. The rate traveled from Amarillo to Austin by a bus averages 65 miles per hour. The bus arrived in Austin after eight hours of travel. An automobile averages 80 miles per hour. Using the inverse variation relationship, show what the time would be for the automobile to complete the trip. a0 hours

Answers

65*8 = 520 miles traveled

520/80 = 6.5 hours for the car

Answer:

The automobile would take 6.5 hours to complete the trip.

Step-by-step explanation:

This is a case of a inverse variation relationship because when you increase the speed of traveling the time of arriving will reduce, now we have to define the equation and the variables:

Inverse variation equation: [tex]x1y1=x2y2[/tex]

[tex]x1[/tex]: speed of the bus, 65 miles per hour

[tex]y1[/tex]: time to Austin by bus, 8 hours

[tex]x2[/tex]: speed of the automobile, 80 miles per hour

[tex]y2[/tex]: time to Austin by automobile, unknown

Now we can replace the values in the equation and clear [tex]y2[/tex], this is:

[tex]65*8=80*y2\\y2=\frac{65*8}{80} =\frac{520}{80} =6.5\\[/tex]

The automobile would take 6.5 hours to complete the trip.

A rocket is launched with an initial velocity of 360 ft/s. The height of the rocket in meters is modeled by the function shown below, where t is time in seconds. h(t)=‒10t2 + 360t Which statement is true?
A. The rockets maximum height is 324 feet.
B. The rockets maximum height is 3240 feet.
C. In the interval from 9 seconds to 18 seconds, the rocket is descending.
D. The rocket hits the ground in 18 seconds.

Answers

the answer for this question is d 
hope it helps

A rainstorm in Portland Oregon wiped out the electricity in 5% of the households in the city. Suppose that a random sample of 60 Portland households is taken after the rainstorm. a. Estimate the number of households in the sample that lost electricity by giving the mean of the relevant distribution (that is the expectation of the relevant random variable do not round your response.) b. Quantify the uncertainty of your estimate by giving the standard deviation of the distribution run your response to at least three decimal places.

Answers

I dont think im right but i think the answer is three. 

ps Portland is the most fun city in Oregon.

Trina's employer purchased a health insurance plan that cost $550 per month Trina pays $85 toward the plan each month what is the annual value of the employer's contribution

Answers

$ 5580.00 this isn't the correct answer from apex

The annual value of the employer's contribution towards Trina's health insurance plan is $5,580.

Here, we have to find the annual value of the employer's contribution, we need to determine how much the employer pays towards the health insurance plan in one month.

Trina's employer purchased a health insurance plan that costs $550 per month, and Trina pays $85 toward the plan each month.

Therefore, the employer's contribution is the difference between the total cost of the plan and what Trina pays:

Employer's contribution = Total cost of the plan - Trina's contribution

Employer's contribution = $550 - $85

Employer's contribution = $465 per month

Now, to find the annual value of the employer's contribution, we multiply the monthly contribution by 12 (since there are 12 months in a year):

Annual employer's contribution = $465 * 12

Annual employer's contribution = $5,580

So, the annual value of the employer's contribution towards Trina's health insurance plan is $5,580.

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Solve the simultaneous equations
5x-4y=19
x+2y=8

Answers

the answer are x= 5 and y = 3/2
So to solve for x and y you need to add the two equations together, and to do this when you add them either the x or the y need to cross out.

For this equation we’re going to multiply the bottom equation by 2 so that the y’s will cancel out when we ad the equations together so that we can solve for x

5x-4y=19
2(x+2y=8)

Distribute the 2

5x-4y=19
2x+4y=16

Next add the two equations together

7x=35

As you can see the y was cancelled out. Now divide each side by 7 to solve for x

x=5

Now take this answer and plug it back into either equation to solve for y. I am going to plug it into the second equation, but you can choose either

x+2y=8

Replace x with its value, 5

5+2y=8

Subtract 5 from each side

2y=3

Divide each side by 2

y=3/2 (or 1.5)

ANSWER:

x = 5

y = 3/2 (or 1.5)

Cours hero a simple random sample of 64 8th graders at a large suburban middle school indicated that 89% of them are involved with some type of after school activity. find the 98% confidence interval that estimates the proportion of them that are involved in an after school activity.
a.[0.799, 0.981]
b.[0.699, 0.931]
c.[0.849, 0.854]
d.[0.799, 0.781]
e.[0.719, 0.981] f) none of the above

Answers

Final answer:

Using the formula for the confidence interval of a proportion, and after calculating standard error and margin of error, the 98% confidence interval for the proportion of 8th graders involved in after school activities is [0.799, 0.981]. Therefore, option a is correct.

Explanation:

To find the 98% confidence interval for the proportion of 8th graders involved in some type of after school activity, we can use the formula for the confidence interval of a proportion:

CI = ± z * √((p*(1-p))/n), where p is the sample proportion, n is the sample size, and z is the z-score corresponding to the confidence level.

In this case, we have p = 0.89 (since 89% of the sample is involved in after school activities), n = 64, and for a 98% confidence interval, the z-score (from z-tables or statistical software) is approximately 2.33.

First, let's calculate the standard error (SE): SE = √((0.89*(1-0.89))/64) = √((0.89*0.11)/64) = √(0.0989/64) = 0.0392.

Next, calculate the margin of error (ME): ME = z * SE = 2.33 * 0.0392 = 0.09136.

Now we can calculate the confidence interval: the lower limit is p - ME = 0.89 - 0.09136 = 0.79864 and the upper limit is p + ME = 0.89 + 0.09136 = 0.98136.

After rounding to three decimal places, the 98% confidence interval for the proportion is [0.799, 0.981]. Hence, option a is correct.

Tony and some friends went to the movies. They bought 4 drinks and 2 tubs of popcorn and spent a total of $32.50 on the food. Each drink cost $3.50 less than a tub of popcorn. Define a variable. Write and equation that can be used to find the cost of one tub of popcorn.

Answers

1 tub of popcorn = t
1 drink = t - 3.5

4(t - 3.5) + 2t = $32.50
4t - 14 + 2t = 32.5
6t = 32.5 + 14
6t = 46.5
t = 46.5 / 6
t = $7.75

David is playing a trivia game where he gains points for correct answers and loses points for incorrect answers. At the start of round 3 his score is −1500 points. During round 3 he answered five 1000 point questions correctly and three 500 points questions incorrectly. What is his score at the end of round 3?
A) −2000
B) −500
C) 2000
D) 3500

Answers

start of round 3....score is -1500
he answered 5 one thousand point questions....5 * 1000 = 5000
so he now has -1500 + 5000 = 3500
he answered 3 five hundred point question incorrectly...3 * -500 = -1500
3500 + (-1500) = 3500 - 1500 = 2000

so he ended up with 2000

Answer:

2000 points

Step-by-step explanation:

Topic: Substraction, Addition and Products

You have to organize the problem, as you can see

at Start of Round 3 David Has: - 1500

During Round 3:

5 Questions: 1000 each correctly

so 5 x 1000 = 5000

3 Questions: - 500 each incorrectly

so 3 x -500 = -1500

at the End of Round 3:

Starting: -1500

During Round 3: 5000 - 1500 = 3500

the end of round 3: -1500 + 3500 = 2000

John has painted 4/5 of his house the next day he painted 2/3 of what he had left what fraction of the house is left to paint

Answers

a whole, is whatever/whatever.

so... he painted 4/5 of the house first..... now the whole house is 5/5,  from 4/5 to 5/5 is just 1/5, so 1/5 was left for the next day.

the next day, he painted only 2/3 of what was left, what is 2/3 of 1/5?  well is just their product.

[tex]\bf \cfrac{2}{3}\cdot \cfrac{1}{5}\implies \cfrac{2}{15}\impliedby \textit{only painted the next day the slacker} \\\\\\ \textit{so he has painted in total }\cfrac{4}{5}+\cfrac{2}{15}\impliedby \textit{LCD of 15}\implies \cfrac{12+2}{15} \\\\\\ \stackrel{painted}{\cfrac{14}{15}}\qquad \qquad \stackrel{whole}{\cfrac{15}{15}}-\stackrel{painted}{\cfrac{14}{15}}\implies \stackrel{unpainted}{\cfrac{1}{15}}[/tex]

What is 31/2 times 3 1/2

Answers

217/4
  because 31/2 * 3 1/2 is 31/2 * 7/2

A certain airplane has two independent alternators to provide electrical power. the probability that a given alternator will fail on a one-hour flight is 0.019. (a) what is the probability that both will fail? (round your answer to 4 decimal places.) probability (b) what is the probability that neither will fail? (round your answer to 4 decimal places.) probability (c) what is the probability that at least one fails? (round your answer to 4 decimal places.) probability referencesebook & resources

Answers

The probability that both alternators fail is approximately 0.0004, the probability that neither fails is approximately 0.9612, and the probability that at least one fails is approximately 0.0388, all rounded to four decimal places.

(a) The probability that both Alternator will fail is calculated by multiplying the probabilities of each failing:
P(Both Fail) = P(Alternator 1 Fails) x P(Alternator 2 Fails) = 0.019 x 0.019 ≈ 0.000361 = 0.0004 (rounded to four decimal places).

(b) The probability that an alternator does not fail is 1 minus the probability that it fails.
P(Neither Fail) = (1 - P(Alternator Fails))^2 = (1 - 0.019)^2 ≈ 0.9612 (rounded to four decimal places).

(c) To find the probability of at least one alternator failing, we subtract the probability of neither failing from 1:
P(At Least One Fails) = 1 - P(Neither Fail) = 1 - 0.9612 ≈ 0.0388 (rounded to four decimal places)

Select "Rational" or "Irrational" to classify each number.   Rational Irrational 0.25 √ 0.25 √0.33

Answers

0.25: Rational
√0.25: Rational (=0.5)
√0.33: Irrational
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