With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/ second 2 ? Assume that the ball undergoes motion along a straight line.
A. 10 newtons
B. 19 newtons
C. 33.3 newtons
D. 40 newtons

Answer:

Continental climates have WARM summers and COLD winters. People who live with areas that experience continental climates must be prepared for the seasonal changes.

Explanation:

Answer: The correct answer is pulses.

Explanation:

Wave is a disturbance which carries energy from one particle to another. Wave is a continuous disturbance.

Pulse is a single disturbance. It travels through one point to another.

Sound wave consists of rarefaction and compression. It need medium to travel.

In the circular wave, the particles move both parallel and perpendicular to the motion of the wave.

Therefore, all waves consist of a continuous series of the pulses.

As per the question the car has a mass of 12,00 kg.

The engine exerts a force of 600 N.  [ here newton i.e N is the unit of force]

We are asked to calculate the acceleration of the particle .

From Newton's second law of motion we know that force acting on a particle is mass times the acceleration of the particle . Mathematically it can be written as-

                                   F = ma             [Here F is the applied force,m is the mass which is constant here and ' a' is the acceleration]

Here m =1200 kg

        F = 600 N

Hence the acceleration produced due to the force exerted by the engine on car is-                                        

                                     [tex]a =\frac{F}{m}[/tex]

                                           [tex]=\frac{600 N}{1200 kg}[/tex]

                                             [tex]=0.5 m/s^2[/tex]      [ans]  

Shearing

The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.

Hope this helps! :)

Answer:

A.  Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.

Explanation:

Speed is the distance an object travels within a specific unit of time. The average speed of an object can be calculated by dividing distance over time. Acceleration, on the other hand, is the rate at which the speed or direction of an object is changing. Acceleration can be positive or negative.

The weight of an object is calculated by multiplying its mass by the acceleration due to gravity. With the mass of the African elephant as 6050 kg and Earth's gravity at 9.80 m/s², the elephant's weight would be 59,290 Newtons.

The weight of an object is the force exerted on it due to gravity. It can be calculated using the formula Weight = Mass × Gravity. In this case, the mass of the African elephant is given as 6,050 kg, and the acceleration due to gravity on Earth is 9.80 m/s².

Thus by multiplying the mass of the elephant with the acceleration due to gravity, we get: Weight = 6,050 kg × 9.80 m/s² = 59,290 N. So the weight of the African elephant on Earth would be 59,290 Newtons.

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Without the graph, we can't calculate the exact masses. However, by finding the slope of the line representing each object on a force-versus-acceleration graph, and using Newton's Second Law (F=ma), we can solve for the objects' masses.

The question refers to an acceleration-versus-force graph for three objects but unfortunately no graph was provided. However, in order to calculate the mass of the objects from an acceleration-versus-force graph, we could potentially use Newton's Second Law (F = ma), where F is the force, m is the mass, and a is the acceleration. Here's how it would be done:

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The masses of objects 1 and 3 are 0.25 kg and 1.5 kg, respectively.

To find the masses of objects 1 and 3, we can use Newton's second law of motion, which states that force is equal to mass times acceleration:

F = ma

We can rewrite this equation to solve for mass:

m = F / a

Step 1: Find the slope of the line for each object

The slope of a line is equal to rise over run. In an acceleration-versus-force graph, the rise is the acceleration and the run is the force.

For object 1, the slope of the line is 4a / 1 = 4a. This means that object 1 has an acceleration of 4a for every 1 unit of force.

For object 2, the slope of the line is 3a / 2 = 1.5a. This means that object 2 has an acceleration of 1.5a for every 1 unit of force.

For object 3, the slope of the line is 2a / 3 = 0.67a. This means that object 3 has an acceleration of 0.67a for every 1 unit of force.

Step 2: Calculate the mass of each object

Now that we know the acceleration of each object, we can use Newton's second law to calculate their masses.

Mass of object 1:

m1 = F / a1 = 1 / 4a = 0.25 kg

Mass of object 2:

m2 = F / a2 = 1 / 1.5a = 0.67 kg

Mass of object 3:

m3 = F / a3 = 1 / 0.67a = 1.5 kg

Conclusion

The masses of objects 1 and 3 are 0.25 kg and 1.5 kg, respectively.

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Answer:

Chemical energy into Thermal energy and Light Energy

Explanation:

When candle is burnt then its wax which is a having chemical potential energy in it will burn and convert its chemical potential energy into light energy and thermal energy.

So here the wax will melt down after burning and few of its part will evaporate and convert its energy into thermal energy and light energy both.

So overall if we write energy transformation in this

Chemical potential energy of wax = Light Energy + Thermal energy

Answer:

Option D

Explanation:

Gravity is a force of attraction by virtue of mass of a body. It is an attractive force. It is due to gravity that the planets and hence, the solar system was formed. Starting from the nebula, the gravity caused the nebula to contract and form start. From rest of the material, the dust and gas were pulled in together due to gravity to form planet. The gravity of the Sun holds the planets in their respective orbits.

Thus, option D is correct.

The voltage is zero

Answer:

A. The total momentum of the system is conserved.

The initial velocity of the object is 0 ft/sec. The points in time when the object has a velocity of zero are at t=0 and t=3 seconds.

To answer these questions, it's important to understand what the variables represent in this equation. The object's velocity is given by v(t)=t^2−3t where v is the velocity in feet per second and t is the time in seconds.

a) The initial velocity is the velocity of the object at the start, which means at time t=0. By substituting t=0 in the equation, we obtain v(0)=(0)^2 - 3(0) = 0 feet/sec.

b) The object has a velocity of zero when v(t) = 0. In other words, we need to solve the equation t^2−3t = 0 for t. Factoring, we get t(t - 3) = 0, thus t = 0, 3 seconds are the moments at which the object's velocity is zero.

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The speed of the tip of Joe’s shadow moving from the base of the pole when he is 13 feet from the pole is 8 m/s.

Speed is defined as the SI unit of speed is measured in milliseconds per second, or m/s. It is the ratio of distance with time.

It is defined as a measurement of the length of time it takes for an object to travel a certain distance.

It can also be defined as the speed at which an object's location changes in any direction.

There are four types of speed.

8/4 = y/y-x

8y - 8x  = 4y

y = 2x

y = 2 x 4

y = 8

Thus, the speed of the tip of Joe’s shadow moving from the base of the pole when he is 13 feet from the pole is 8 m/s.

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Answer:

initial speed of sound at 30 degree C

[tex]v_1 = 349.6 m/s[/tex]

final speed of sound at 36 degree C

[tex]v_2 = 353.2 m/s[/tex]

Explanation:

As we know that velocity of the sound in air is given by the formula as

[tex]v = 331.6 + 0.6 t[/tex]

here we know that

t = temperature or air in degree celcius

so here at 30 degree celcius we can say that

[tex]v_1 = 331.6 + 0.6(30)[/tex]

[tex]v_1 = 349.6 m/s[/tex]

now at 36 degree C the speed of sound is given as

[tex]v_2 = 331.6 + 0.6(36)[/tex]

[tex]v_2 = 353.2 m/s[/tex]

Heat transfer from one substance to another results in the decrease of temperature in the substance losing heat and an increase in the substance gaining heat. At the melting or boiling points, heat absorbed is used for phase changes instead of raising the temperature. The heat required for a phase change is proportional to the substance's mass.

When heat flows from one substance to another, this process is known as heat transfer. The substance giving off heat, or the higher temperature substance, will experience a decrease in its temperature. Conversely, the substance receiving the heat, or the cooler substance, will see an increase in temperature. This heat transfer continues until both substances reach thermal equilibrium, meaning they have the same temperature.

Specifically, at the melting point or boiling point, heat flow into a substance does not change its temperature but rather is used to change its state. This is because the energy is utilized to break the intermolecular forces that hold the substance in its current phase. For example, when ice melts to become water at its melting point, the temperature remains constant until all the ice has melted. The same is true for boiling; the temperature of the liquid remains constant during the transition to a gas.

The amount of heat required for these phase changes is directly proportional to the mass of the substance undergoing the change. In other words, larger amounts of substance will require more heat to complete the phase transition.

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

a) Variables:

  - [tex]\( h_1 \)[/tex] = Initial height of the hill (22.4 m)

  - [tex]\( h_2 \)[/tex] = Height of the next hill (8.59 m)

  - [tex]\( v_{i1} \)[/tex] = Initial speed of the tire (2.10 m/s)

  -[tex]\( v_{f1} \)[/tex] = Final speed at the top of the first hill

  - [tex]\( v_{f2} \)[/tex] = Final speed at the top of the next hill

  - g = Acceleration due to gravity (-9.8 m/s²)

b) Equation for the first hill:

[tex]\[ v_{f1}^2 = v_{i1}^2 + 2gh_1 \][/tex]

c) Calculate [tex]\( v_{f1} \)[/tex]:

[tex]\[ v_{f1}^2 = (2.10 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(22.4 \, \text{m}) \][/tex]

[tex]\[ v_{f1} \approx 16.83 \, \text{m/s} \][/tex]

d) Equation for the next hill:

[tex]\[ v_{f2}^2 = v_{f1}^2 + 2gh_2 \][/tex]

e) Solve for [tex]\( v_{f2} \)[/tex]:

[tex]\[ v_{f2}^2 = (16.83 \, \text{m/s})^2 + 2(-9.8 \, \text{m/s}^2)(8.59 \, \text{m}) \][/tex]

[tex]\[ v_{f2} \approx 15.12 \, \text{m/s} \][/tex]

The speed of the tire at the top of the next hill, which is 8.59 m high, is approximately 15.12 m/s.

Final answer:

The speed of the tire at the top of the next hill is 21.2 m/s.

Explanation:

To find the speed of the tire at the top of the next hill, we can use the principle of conservation of energy.

According to the principle of conservation of energy, the initial potential energy of the tire at the top of the first hill is equal to the final potential energy of the tire at the top of the next hill.

Therefore, we have:

mgh = 1/2 × mv²

Where m is the mass of the tire, g is the acceleration due to gravity, h is the height difference between the two hills, and v is the final velocity of the tire at the top of the next hill.

Plugging in the values, we get:

10.5 × 9.8 × 22.4 = 1/2 × 10.5 × v²

Solving for v, we find:

v = sqrt((2 × 10.5 × 9.8 × 22.4) / 10.5)

v = 21.2 m/s

The normal force exerted on the book is 9.8067 N, which is calculated using the mass of the book, the acceleration due to gravity, and the cosine of the slope angle (60°).

To determine the normal force exerted on the book, we need to consider the forces at play when a book is held on an inclined plane with a slope of 60.0°. The weight of the book (mass times the acceleration due to gravity) acts vertically downward. This weight can be broken down into two components: one perpendicular to the slope (which contributes to the normal force) and one parallel to the slope. The parallel component is counteracted by the horizontal force that keeps the book in equilibrium, and hence does not affect the normal force. The component of the weight perpendicular to the slope is what contributes to the normal force. Thus, with a mass of 2.0 kg and using the value of the acceleration due to gravity (9.8067 m/s²), the normal force can be calculated as the product of the mass, the acceleration due to gravity, and the cosine of the slope angle, which is 60.0° in this case.

As the book is in equilibrium, the normal force is equal to the weight component perpendicular to the slope. The force due to gravity is Fg = m × g, where m is mass and g is acceleration due to gravity. Therefore:

The correct answer is that the normal force exerted on the book is 9.8 N.

To solve this problem, we need to consider the forces acting on the book in the direction perpendicular to the inclined board. The normal force (N) is the force exerted by the board on the book that is perpendicular to the surface of the board.

First, we need to break down the gravitational force acting on the book into two components: one parallel to the inclined board and one perpendicular to it. The gravitational force [tex](F_g)[/tex] acting on the book is the product of its mass (m) and the acceleration due to gravity (g), which is approximately 9.8 m/s².

So, the gravitational force is:

[tex]\[ F_g = m \cdot g = 2.0 \, \text{kg} \cdot 9.8 \, \text{m/s}^2 = 19.6 \, \text{N} \][/tex]

The component of the gravitational force parallel to the inclined board [tex](F_parallel)[/tex] can be found using the sine of the angle of the incline:

[tex]\[ F_{\text{parallel}} = F_g \cdot \sin(\theta) \][/tex]

[tex]\[ F_{\text{parallel}} = 19.6 \, \text{N} \cdot \sin(60.0\°) \][/tex]

[tex]\[ F_{\text{parallel}} = 19.6 \, \text{N} \cdot \frac{\sqrt{3}}{2} \][/tex]

[tex]\[ F_{\text{parallel}} = 19.6 \, \text{N} \cdot 0.866 \][/tex]

[tex]\[ F_{\text{parallel}} = 17.0 \, \text{N} \][/tex]

The component of the gravitational force perpendicular to the inclined board [tex](F_perpendicular)[/tex] can be found using the cosine of the angle of the incline:

[tex]\[ F_{\text{perpendicular}} = F_g \cdot \cos(\theta) \][/tex]

[tex]\[ F_{\text{perpendicular}} = 19.6 \, \text{N} \cdot \cos(60.0\°) \][/tex]

[tex]\[ F_{\text{perpendicular}} = 19.6 \, \text{N} \cdot \frac{1}{2} \][/tex]

[tex]\[ F_{\text{perpendicular}} = 9.8 \, \text{N} \][/tex]

Since the book is in equilibrium, the sum of the forces in the perpendicular direction must be zero. This means that the normal force (N) must be equal in magnitude and opposite in direction to the perpendicular component of the gravitational force:

[tex]\[ N = F_{\text{perpendicular}} \][/tex]

[tex]\[ N = 9.8 \, \text{N} \][/tex]

The Earth's atmosphere can shield against various forms of electromagnetic radiation, mostly blocking gamma rays and allowing radio waves and visible light to penetrate. Thus, gamma rays are the form of radiation primarily shielded by our atmosphere.

The Earth's atmosphere provides a natural shield against various forms of electromagnetic radiation, including gamma rays, X-rays, and ultraviolet (UV) light. These types of radiation pose a potential risk to living organisms due to their high energy levels. However, while the atmosphere blocks most gamma rays and X-rays, completely shielding against all electromagnetic radiation is a different matter.

The atmosphere does allow visible light to pass through, enabling us to see the world around us. Radio waves, especially those on the lower frequency end, can also penetrate the atmosphere, which is why we can receive radio signals. On the other hand, gamma rays, which have the shortest wavelength and highest energy, are indeed absorbed by the atmosphere. This absorption is critical for protecting life on Earth from their potentially harmful effects.

To clarify: Gamma rays are mostly absorbed by the atmosphere, radio waves can generally penetrate it, and visible light travels through it to reach the Earth's surface. Therefore, the correct answer to the question about which form of radiation can be shielded by Earth's atmosphere is primarily gamma rays. However, it's worth noting that the question wording implies all of them can be 'shielded' to an extent, but gamma rays are the ones that are most effectively blocked.

Our galaxy, the Milky Way, appears to be a band of stars in the sky, but it's actually a disk. Hundreds of billions of stars are clumped into lines called spiral arms. Earth is located about half-way between the center of the Milky Way and its outer edge.

The value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 Newtons would be 181.81 Newtons.

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem we have to find the  value of the normal force if the coefficient of kinetic friction is 0.22 and the kinetic frictional force is 40 newtons,

Friction force =(coefficient of friction)*Normal force

40 = 0.22* Normal force

Normal Force = 40/0.22

                       =181.81 Newtons

Thus, the normal force comes out to be 181.81 Newtons.

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hydroelectric  uses water

Answer: water

Explanation: I got it right on odyssey.

Correct answer choice is :

B) That could not be divided.

Explanation:

Democritus was a Greek scholar who lived within 470-380 B.C. He elaborated the theory of the atom, Greek for permanent. Democritus thought that everything in the world was made up of atoms, which were tiny and durable. They assumed that matter was made up of very small particles. They named these particles atoms, which comes from an antique Greek word signifying permanent. These atoms were supposed to be absolutely indivisible and forever.