William cycles at a sped of 15 miles per hour. He cycles 12 miles from home to school. If he increases his cycling speed ny 5 miles per hour how much faster will he arrive his school

Answers

Answer 1

Answer:he would arrive 0.2 miles faster.

Step-by-step explanation:

Distance = speed × time

Time = distance/speed

William cycles at a sped of 15 miles per hour. He cycles 12 miles from home to school. This means that the time it takes William to get to school from home would be

12/15 = 0.8 hours

If he increases his cycling speed by 5 miles per hour, his new speed becomes

15 + 5 = 20 miles per hour

Therefore, the new time it takes William to get to school from home would be

12/20 = 0.6 hours

The difference in both times is

0.8 - 0.6 = 0.2 hours

Therefore, he would arrive 0.2 miles faster.


Related Questions

Find the acute angle between the two given lines

y=-2x and y=x

Answers

Answer:

θ ≈ 71.6°

Step-by-step explanation:

The angle between two lines with slopes m₁ and m₂ is:

tan θ = | (m₂ − m₁) / (1 + m₁m₂) |

Here, m₁ = -2 and m₂ = 1.

tan θ = | (1 − (-2)) / (1 + (-2)(1)) |

tan θ = | 3 / -1 |

tan θ = 3

θ ≈ 71.6°

What is the value of x?

Answers

Answer:

Step-by-step explanation:

DE*s=BA  24*s=35 s=35/24

(3x+7)35/24=6x-5

35/8x+5/24=6x-5

          -5/24    -5/24

Rewrite the expression in the form y^ny n y, start superscript, n, end superscript. \dfrac{1}{y^{^{\scriptsize\dfrac54}}}= y 4 5 ​ 1 ​ =start fraction, 1, divided by, y, start superscript, start superscript, start fraction, 5, divided by, 4, end fraction, end superscript, end superscript, end fraction, equals

Answers

Answer:

y/\8

Step-by-step explanation:

(y

4

)

2

 

=y

4⋅2

=y

8

This follows from the general rule \left(x^m\right)^{n}=x^{m\cdot n}(x

m

)

n

=x

m⋅n

left parenthesis, x, start superscript, m, end superscript, right parenthesis, start superscript, n, end superscript, equals, x, start superscript, m, dot, n, end superscript.

We can also see this is correct by expanding the powers.

\begin{aligned} \left(y^4\right)^{2}&=\underbrace{y^4\cdot y^4}_\text{2 times} \\\\\\ &=\underbrace{ \underbrace{y\cdot y\cdot y\cdot y}_\text{4 times} \cdot \underbrace{y\cdot y\cdot y\cdot y}_\text{4 times}} _\text{2 times} \\\\ &=y^{8} \end{aligned}

(y

4

)

2

 

=

2 times

y

4

⋅y

4

=

2 times

4 times

y⋅y⋅y⋅y

4 times

y⋅y⋅y⋅y

=y

8

Hint #22 / 2

In conclusion, \left(y^4\right)^{2}=y^{8}(y

4

)

2

=y

8

left parenthesis, y, start superscript, 4, end superscript, right parenthesis, squared, equals, y, start superscript, 8, end superscript.

Final answer:

To rewrite the expression, divide the digit term in the numerator by the digit term in the denominator and subtract the exponents. The final expression is y^-1/4.

Explanation:

To rewrite the expression in the form yn, we can use the rules of division of exponentials. In this case, we have 1/y5/4.

To divide, we need to subtract the exponents and divide the digit term in the numerator by the digit term in the denominator.

The digit term in the numerator is 1, and the digit term in the denominator is 1.

So, the expression can be rewritten as y1 - 5/4.

Now, let's simplify the exponent. We have 1 - 5/4 = 4/4 - 5/4 = -1/4.

So, the final expression is y-1/4.

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Jessica decided to use 15% of her gross income for her down payment for a house. She makes 48,960.00 per year. How much money did jessica's budget allow for the down pyment

Answers

Answer:

[tex]Down\ payment = 7,344[/tex]

Step-by-step explanation:

Let x be the amount of 15% of gross income.

Given:

Jessica gross income = 48,960.00

She decided to use 15% amount as down payment.

We need to find the amount of 15% of gross income.

Solution:

Using percentage formula.

[tex]percentage = (\frac{Value}{Total\ value})\times 100[/tex]

Now we substitute 15 in the place of percentage and 48,960 in the place of Total value.

[tex]15=(\frac{x}{48960})\times 100[/tex]

Now, we apply cross multiplication rule.

[tex]x= \frac{48960\times 15}{100}[/tex]

[tex]x=48960\times 0.15[/tex]

[tex]x =7,344[/tex]

Therefore: Down payment is 7,344.

Final answer:

Jessica allocated $7,344 for the down payment on a house based on her 15% gross income allocation.

Explanation:

The budget that Jessica allocated for her down payment on a house is calculated as follows:

Calculate 15% of Jessica's gross income: 15% of $48,960 is $48,960 * 0.15 = $7,344.

Therefore, the budget that Jessica allowed for the down payment on a house is $7,344.

Ripley's spelling grades are 86, 84, 90, and 90. If he scores 0 on the next spelling quiz, what will happen to the MEAN of his scores? A) It will decrease by 8.5. B) It will increase by 13.5. C) It will increased by 17.5. D) It will decreased by 17.5.

Answers

Answer:

D itll go from 87.5 to 70, so it'll drop by 17.5

Step-by-step explanation:

Answer:

The answer is actually D

Step-by-step explanation:

This is true because when you add the scores together you get 350 and then you divide that number by however many data numbers there are in the set.

86+84+90+90=350

because there are 4 numbers in the data set you so divide 350 by 4 which equals 87.5

Then he scores a 0 on the quiz, it will indeed affect the mean.

You add the numbers 86+84+90+90+0 still equals 350, however, instead of 4 numbers in the data set it's 4 because of the zero.

Instead of dividing by 4, you divide by 5

350 divided by 5 equals 70.

the original MEAN was 87.5 and now it is 70, so that means that it decreased by 17.5. there's is your answer. The answer is D 17.5

A force with magnitude 20 N acts directly upward from the xy-plane on an object with mass 4 kg. The object starts at the origin with initial velocity vs0d − i 2 j. Find its position function and its speed at time t.

Answers

Final answer:

The object's position function is y = 2.5t² - 2t derived using kinematic equations. The speed at time t is |-2 + 5t| m/s where t is the time.

Explanation:

This is a problem of mechanics related to the motion of the object under the influence of a force. First, we need to calculate the acceleration using the formula F=ma. This gives us the acceleration as a = F/m = 20N/4kg = 5m/s². The object is moving upwards so this force is in the positive y direction.

The initial velocity vector is given as vs0d − i2j. The i-component represents the x-direction, and the j-component represents the y-direction. Thus, the initial speed is sqrt((0d)² + (−2)²) = 2 m/s. However, given that this velocity is in the negative y-direction, we determine its initial speed to be -2 m/s.

Now, we can determine the position function for the y-direction using the equation y = y0 + v0y*t + 0.5*a*t², where y0 represents the initial position (origin), v0y is the initial velocity in the y-direction (-2m/s for this case), a is the acceleration (5 m/s²), and t is time. Substituting these values, the equation becomes y = 0 – 2t + 0.5*5t² = 2.5t² - 2t.

For the speed at time t, you can utilize the velocity's magnitude in the y-direction using v = v0y + a*t = -2 m/s + 5t The magnitude ||v|| = sqrt((0)² + (-2 + 5t)²) = |-2 + 5t| m/s as speed is always positive.

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We determined the object's position function to be [tex]\[ \matbf{r}(t) = -t \mathf{i} + 2t \mathf{j} + \frac{5t^2}{2} \mathf{k} \][/tex] and its speed at time t to be |v(t)| = [tex]\sqrt{5 + 25t^2}[/tex]. The calculations involved using Newton's second law and integrating the acceleration and velocity.

To find the position function and speed of the object under the given conditions, we need to use the principles of Newtonian mechanics. Let's break it down step-by-step.

Step 1: Find the acceleration

Given:

- Force ( F = 20 N ) upward

- Mass  (m = 4 kg)

Using Newton's second law (F = ma) , we can find the acceleration:

[tex]\[ \mthbf{a} = \frac{\mahbf{F}}{m} \][/tex]

Since the force is acting directly upward (which we'll take as the ( z )-direction):

F = 20k

Thus,

[tex]\[ \mahbf{a} = \frac{20 \matbf{k}}{4} = 5 \mahbf{k} \][/tex]

So, the acceleration is:

a = 5k

Step 2: Find the velocity function

The initial velocity is given as:

[tex]\[ \matbf{v}(0) = -\matbf{i} + 2\matbf{j} \][/tex]

Acceleration is constant, so we can integrate to find the velocity function:

[tex]\[ \matbf{v}(t) = \mathf{v}(0) + \mathf{a} t \][/tex]

Substituting the known values:

[tex]\[ \mathf{v}(t) = (-\matbf{i} + 2\matbf{j}) + 5 t \mahbf{k} \][/tex]

Thus,

[tex]\[ \matbf{v}(t) = -\matbf{i} + 2\matbf{j} + 5t \mthbf{k} \][/tex]

Step 3: Find the position function

To find the position function, integrate the velocity function:

[tex]\[ \mahbf{r}(t) = \mathf{r}(0) + \int \mathf{v}(t) \, dt \][/tex]

Given that the object starts at the origin:

r(0) = 0

Integrating the velocity function:

[tex]\[ \mathf{r}(t) = \int (-\mathf{i} + 2\matbf{j} + 5t \mathf{k}) \, dt \][/tex]

[tex]\[ \mahbf{r}(t) = (-\matbf{i}t) + (2\matbf{j}t) + \left( \frac{5t^2}{2} \matbf{k} \right) \][/tex]

Thus, the position function is:

[tex]\[ \matbf{r}(t) = -t \mathf{i} + 2t \mathf{j} + \frac{5t^2}{2} \mathf{k} \][/tex]

Step 4: Find the speed at time ( t )

Speed is the magnitude of the velocity vector:

[tex]\[ \mathb{v}(t) = -\mathf{i} + 2\matbf{j} + 5t \mathb{k} \][/tex]

Calculate the magnitude:

[tex]\[ \text{Speed} = |\mathbf{v}(t)| = \sqrt{(-1)^2 + (2)^2 + (5t)^2} \][/tex]

[tex]\[ \text{Speed} = \sqrt{1 + 4 + 25t^2} \][/tex]

[tex]\[ \text{Speed} = \sqrt{5 + 25t^2} \][/tex]

The depreciation of the value for the car is modeled by the equation Y equals 100,000 (.85)x or ask year since 2000. In what year was the value of the car was $61,412.50?

Answers

Answer:

Step-by-step explanation:

The car's value was $61,412.50  in the year 2006.

x = no. of years since 2000.

Acc. to ques,

100,000 × (0.85)ˣ = 61,412.50

(0.85)ˣ = 0.614125.

ln((0.85)ˣ) = ln(0.614125).

x × ln(0.85) = ln(0.614125).

x = ln(0.614125) / ln(0.85).

x = 5.832 ≈ 6

The volume of water In two containers is in the ratio of 6 to 7. If the volume of the first container is 36 liters, find the volume of the second container?

Answers

Answer:

42 liters

Step-by-step explanation:

Set up the ratios as fractions.

6/7 = 36/x

To get the volumes multiply the 6 and the 7 by 6.

This is how you got the 36 for the first volume.

The volume of the second container is 42.

7 x 6 = 42

Let f(x) = 2x + 5 and g(x) = x^2 - 3x + 2



a. 3f(x) - 2


b. f(x) - 2g(x)


c. 5f(x)/g(x)

Answers

Answer:

The answer to your question is below

Step-by-step explanation:

f(x) = 2x + 5

To solve letter a, just multiply each term of f(x) by 3 and subtract 2.

a) 3f(x) - 2 = 3(2x + 5) - 2

                 = 6x + 15 - 2

               = 6x + 13

To f(x) subtract twice g(x)

b) f(x) - 2g(x) = 2x + 5 - 2(x² - 3x + 2)

                    = 2x + 5 - 2x² + 6x - 4

                    = -2x² + 8x + 1

Multiply 5 by each term of f(x) and divide it by g(x)

c)      [tex]\frac{5f(x)}{g(x)} = \frac{5(2x + 5)}{x^{2} - 3x + 2}[/tex]  

                = [tex]\frac{10x + 25}{x^{2}-3x + 2}[/tex]

The difference between the value of the sample statistic and the value of the corresponding population parameter is called the _____. a. standard error b. statistical error c. sampling error d. proportion error

Answers

Answer: c. sampling error

Step-by-step explanation:

A population parameter is a number that is evaluated to describe the whole population . For example : Population mean , Population standard deviation etc.A sample statistic gives the estimate value of the population parameter. For example : Sample mean , sample proportion.

Since, the sample is a subset of population , so there are chances for unavoidable variation in sample mean from the population mean that varies from sample to sample .

This variation is known as sampling error.

∴ The difference between the value of the sample statistic and the value of the corresponding population parameter is called the sampling error .

Hence,the correct answer is c. sampling error .

Final answer:

The difference between the sample statistic and the population parameter is known as the sampling error. This error occurs due to the sample selected being unrepresentative of the entire population.

Explanation:

The difference between the value of the sample statistic and the value of the corresponding population parameter is referred to as the sampling error. This definition directly fits the option c. Listed among the given options. A sampling error is a discrepancy that occurs due to an unrepresentative selection of observations from the whole population. The nature of statistical sampling means there will always be some level of uncertainty or error because we are making estimates based on a sample from a larger population, rather than the entire population itself.

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A bakery made 26 cherry pies, using 115 cherries for each pie. They threw away 36 cherries that were bad. If they used all the cherries they had, how many cherries did they start with?

Answers

Final answer:

To calculate the total number of cherries that the bakery started with, multiply the number of pies by cherries per pie and then add the ones thrown away, resulting in 3026 cherries.

Explanation:

The question asks how many cherries the bakery started with before making the cherry pies. To find the answer, we multiply the number of cherry pies by the cherries used per pie and then add the number of cherries thrown away.

Multiply the number of pies (26) by the number of cherries used for each pie (115).

The result from step 1 gives the number of cherries used to make the pies.

Add the number of cherries thrown away (36) to the result from step 2.

The sum from step 3 is the total number of cherries the bakery started with.

Let's do the calculations:
26 pies × 115 cherries per pie = 2990 cherries
2990 cherries + 36 bad cherries = 3026 cherries

Therefore, the bakery started with 3026 cherries.

Determine the average velocity of the cart and disk as they move together during a 24-frame interval after the collision. Use the blue dot on the left end of the cart as the point of reference for your measurement?

Answers

Answer:

The answer is 38.7 kg·m/s

Step-by-step explanation:

Considering the definition of average velocity,

The average speed of an object is defined as the distance traveled divided by the time elapsed.

Therefore, If in the frame of 320, the blue dot appears to be at 0 cm  and 24 frames later (at 344), the blue dot appears to be at 11 cm.  24 frames is 1/10 of a second, so

V = 11cm / 0.10s = 110 cm/s = 1.10 m/s

give or take.

Bonus:  initial system (cart only) momentum

p = mv = 23.8kg * 1.80m/s = 42.8 kg·m/s  

final system (cart+disk) momentum

p = (23.8+11.4)kg * 1.10m/s = 38.7 kg·m/s

PLEASE HELP!!!
Solve for x.

Answers

Answer:

x = 6.

Step-by-step explanation:

Because the the 2 angles are equal

4 / (x + 2) = 3 / (9-3)

4/(x+2) = 3/6

4 / (x + 2) = 1/2

x + 2 = 4*2 = 8

x = 8 - 2 = 6.

For any integers x and y, min(x, y) and max(x, y) denote the minimum and the maximum of x and y, respectively. For example, min (5, 2) = 2 and max(5, 2) = 5. For the integer w, what is the value of min(10, w) ?

(1) w = max(20, z) for some integer z.
(2) w = max(10, w)

Answers

∴ The value of min(10,w) = 10

Step-by-step explanation:

Given  

w = max (20,z) for some integer z

    2. and w = max (10,w)

From the first equation we get that w= 20

and it also satisfies the second equation.

∴ The value of min(10,w) = min(10,20) ∵w=20

                                        = 10

Final answer:

Considering both conditions, our w value could be 10 or greater. As we are looking for the minimum value between 10 and w, the result of min(10, w) will be 10.

Explanation:

Let's look at the two provided conditions:

Condition 1: w = max(20, z). This means that w is either 20 or some integer greater than 20.Condition 2: w = max(10, w). Here, w could be 10 or greater.

Since both conditions suggest that w could be a value 10 or greater, the exponent w in min(10, w) will be at least 10. However, because we're finding the minimum between 10 and w, the value of min(10, w) will be 10.

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Out of 200 randomly selected people who participated in a poll, 120 said that they support the new policy introduced by the current mayor of New York City. Conclusion was made that 60% of all New Yorkers support new policy. Does this statement represent descriptive or inferential statistics?

Answers

Answer:

It's descriptive.

Step-by-step explanation:

inferential statistic, means we are inferring based on a sample of our population. Many times we need to infer because the data we need to collect is too large, i.e. the population is too large e.g. the average age of high school students in the US. so we take a sample, a portion of this population and we calculate their mean age. If our sample is random enough, we can "infer" to a certain degree of accuracy the mean

But descriptive statistics, describes the data. They are numbers used to summarise and describe a data. 60% describes the data.

For some piecewise function f(x), the limit as x approaches "a" from the left is 5. The limit as x approaches "a" from the right is -3. What is the limit of f(x) as x approaches "a"?

Answers

Answer: The limit does not exist.

Step-by-step explanation: The limit of a piecewise function f(x) as it approaches "a" will exist if and only if the value of the limit of f(x) as x approaches "a" from the left is the same with the value of the limit of f(x) as x approaches "a" from the right.

From the given question the value are not the same. We have 5 (limit from the left) and -3 (limit from the right). So, we can conclude that the limit of f(x) as x approaches "a" does not exist.

Use the formula to evaluate the series 1+2+4+8...-a10

Answers

Answer:

Sum = 1,023

Step-by-step explanation:

The given series is:

1 + 2 + 4 + 8 + ........ + a₁₀

The given series is a geometric series.

It is required to find the sum of the first 10 terms

The sum to n terms of a geometric series given by:  [tex]S_{n} = \frac{a(r^n-1)}{r-1}[/tex]

Where: a = the first term = 1

            r = common ratio = 2/1 = 2

           n = number of terms = 10

So,

[tex]S_{n} = \frac{a(r^n-1)}{r-1}[/tex] = [tex]\frac{1*(2^{10} -1)}{2-1} = 2^{10} -1 = 1024 - 1 = 1,023[/tex]

So, the summation of the series = 1,023

What is the simplified version of (-3x^3y^2) (5xy^-1)?
A. 15x^2/y^2
B. -15x^3y^2
C.-15x^4y
D. 15x^4y

Answers

Answer:

-15x^4y

Step-by-step explanation:

(-3x^3y^2)(5xy^-1)

-15x^4y^2/y

-15x^4y

Answer:

C.  -15x^4y.

Step-by-step explanation:

(-3x^3y^2) (5xy^-1)

= -3*5 x^(3+1)y^(2 - 1)

= -15x^4y.

I need help with my algebra fraction assignments. I need help with page 2, 3,4,5 and 7. I also have additional albebra fraction assignments that I need help with. If you can help me with my homeworkwork please leave a comment regarding each homework page. Thanks!

Answers

Answer:

Step-by-step explanation:

#2 the answer is B, -16/9

do 1/4-5/2

to do this, find the least common denominator. it's 4

1/4-10/4=-9/4

then divide 4 by -9/4. This is the same as 4*-4/9. That is -16/9

#3 the answer is A 9x/x-8

first factor the denominator of the first fraction using special products

x^2-6x-16=(x-8)(x+2)

if you look at the first fraction, you can simplify x+2 leaving you with the fraction 1/x+8

multiply that by 9x, and you get 9x/x-8

#4 the answer is C (2x+1)/2x^2

first add x/4 and 1/8

find the least common denominator. its 8

2x/8 + 1/8 is equal to (2x+1)/8

then multiply that by x^2/4 because dividing a fraction is the same as multiplying its reciprocal

you get (2x+1)/2x^2

#5 the answer is C (x-8)/(x+3)

using special products you can factor the numerator

x^2-4x-32 is the same as (x-8)(x+4)

then, using special products you can also factor the denominator

x^2+7x+12 is the same as (x+4)(x+3)

you can see that both the numerator and the denominator is multiplied by (x+4) you can simplify that. That leaves you with (x-8)/(x+3)

#7 the answer is D 3m

in the numerator in the second fraction, you can factor out 5m^2

leaving you with 5m^2(m-6)/5m^2. simplify the 5m^2 and the m-6

after you simplify both of those, you will get 3m

Cameron bought twelve pounds of candy corn for 79 cents a pound and eighteen pounds of M&Ms for $1.09 a pound, planning to make packages of candy for a fund-raiser. The two types of candy will be mixed and sold in one-pound bags. What is the least price that Cameron can charge for each of the thirty bags, in order to make at least a 25% profit.

Answers

Final answer:

To make at least a 25% profit, Cameron should charge a minimum of $1.22 per bag for the mixed candy. The cost per bag is found by adding the total cost of candy corn and M&Ms, then multiplying by 125% and dividing by the number of bags to distribute the cost and profit evenly.

Explanation:

The student's question involves calculating the minimum selling price for candy bags to achieve a certain profit margin, which is a common type of problem in Mathematics, specifically in the field of algebra and business mathematics.

To find the least price Cameron can charge for each of the thirty bags to make at least a 25% profit, we first calculate the total cost of the candy. Cameron bought twelve pounds of candy corn at 79 cents a pound and eighteen pounds of M&Ms at $1.09 a pound.

Candy corn cost: 12 pounds × $0.79/pound = $9.48M&Ms cost: 18 pounds × $1.09/pound = $19.62Total cost: $9.48 + $19.62 = $29.10

Now, we calculate the total cost including the desired 25% profit.

Total cost with profit: $29.10 × (1 + 0.25) = $36.375

Since Cameron is making thirty bags, we divide the total cost with profit by the number of bags.

Minimum selling price per bag: $36.375 / 30 bags = $1.2125

However, as prices are generally rounded to the nearest cent, the minimum charge per bag would be $1.22 to ensure a 25% profit.

I draw five cards from a randomly shuffled deck. What is the probability that those five cards are in either ascending or descending order

Answers

Answer: The probability of drawing 5 cards in either ascending or descending order out of the deck of 52 standard playing cards is 0.84%.

Step-by-step explanation: We have the following cards in a deck: 1(ace), 2, 3, 4, 5, 6, 7, 8, 9, 10, 12(Jack), 13(Queen), 14(King) (thirteen different in total). There are 4 copies of each of them yielding 52 cards in total. First to draw all of the cards in the ascending order all of the drawn cards need to be different. Imagine you have 13 piles of 4 identical cards. Let us calculate the number of ways you can select 5 different ones (the order matters). First you select 5 different piles (this secures that each card is different) and this is possible to do in [tex]\frac{13!}{(13-5)!}[/tex] (we use the formula for variations since the order matters). Now, each card in the pile can be selected in [tex]4[/tex] different ways so the total number of sequences with [tex]5[/tex] different cards is [tex]4^5\frac{13!}{(13-5)!}[/tex]. Now we select out of these sequences the clases of those that contain exactly the same cards but in different order. Only 4 of the sequences within the same class will be in ascending order out of 4*5! which is the total number of the sequences within the class! This means that we have to multiply our total number of sequences of 5 different cards by [tex]\frac{4}{4\cdot 5!}=\frac{1}{5!}[/tex] and this yields the final answer of total number of ascending sequences to be

[tex]4^5\frac{13!}{(13-5)!5!}.[/tex]  

The total number of possible ways to draw 5 out of 52 cards is just

[tex]\frac{52!}{(52-5)!}.[/tex]

This yields for the probability

[tex]\frac{4^5\frac{13!}{(13-5)!5!}}{\frac{52!}{(52-5)!}}=0.42\%[/tex]

Exactly the same calculation applies for the descending order. So the probabilty of the cards being in either ascending or descending order is just the sum of these two (the events are mutually exclusive, you cannot have both the ascending and descending order at the same time) yielding the final probability of [tex]0.84\%[/tex].

Some large hardware stores, such as Home Depot, boast of carrying as many as 20,000 different products in each store. This volume of goods is the result of?

Answers

Answer:

the choice of consumers regarding what to purchase to satisfy their wants and the choice of producers regarding what to produce to maximize profits.

Step-by-step explanation:

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that he must stop at the first signal is 0.4, the analogous probability for the second signal is 0.55, and the probability that he must stop at at least one of the two signals is 0.65. What is the probability that he must stop.a.) At both signals?b.) At the first signal but not at the second one?c.) At exactly on signal?

Answers

Answer:

a) The probability is 0.3

b) The probability is 0.1

c) The probability is 0.35

Step-by-step explanation:

Lets call S1 and S2 the events ' he must stop at signal 1 ' and 'he must stop at signal 2' respectively.

a) We know that

0.65 = P(S1 ∪ S2) = P(S1) + P(S2) - P(S1 ∩ S2) = 0.4+0.55-P(S1 ∩ S2) = 0.95 - P(S1 ∩ S2)

Hence P(S1 ∩ S2) = 0.95-0.65 = 0.3

It stops at both signals with probability 0.3

b) Note that, due to the theorem of total probability we have

0.4 = P(S1) = P(S1 ∩ S2) + P(S1 ∩ S2^c) = 0.3 + P(S1∩S2^c)

Where S2^c is the complementary event of S2. Therefore

P(S1∩S2^c) = 0.4-0.3 = 0.1

The probability to stop at the first signal but not at the second one is 0.1

c) The probability of stopping at exactly one signal is equal at the sum of the probabilities of stopping only at the first signal and the probability of stopping only at the second one.

That is P(S1 ∩ S2^c) + P(S1^c ∩ S2) = 0.1 + P(S1^c ∩ S2)

The same way as before:

0.55 = P(S2) = P(S1 ∩ S2) + P(S1^c ∩ S2) = 0.3 + P(S1^c ∩ S2)

Therefore

P(S1^c ∩ S2) = 0.55-0.3 = 0.25

And as a result, the probability of stopping at exactly one signal is 0.25 + 0.1 = 0.35.

The probability that he must stop at both signals 0.30.

The probability to stop at the first signal but not at the second one is 0.1.

The probability that he must stop at exactly 0.35.

Given that,

The probability that he must stop at the first signal is 0.4,

The analogous probability for the second signal is 0.55,

The probability that he must stop at at least one of the two signals is 0.65.

We have to determine,

What is the probability that he must stop.

According to the question,

F = Event that a certain motorist must stop at the first signal.

S = Event that a certain motorist must stop at the second signal.

He must stop at signal 1 ' and 'he must stop at signal 2' respectively.

P(S1 ∪ S2) = P(S1) + P(S2) - P(S1 ∩ S2) =0.65

0.4 +0.55 - P(S1 ∩ S2) = 0.65

0.95 - P(S1 ∩ S2) = 0.65

Hence, P(S1 ∩ S2) = 0.95 - 0.65 = 0.30

It stops at both signals with probability 0.30.

The probability that he must stop at both signals 0.30.

By using the theorem of total probability,

P(S1) = P(S1 ∩ S2) + P(S1 ∩ S2^c)

0.4 = 0.3 + P(S1∩S2^c)

Where S2^c is the complementary event of S2. Therefore

P(S1∩S2^c) = 0.4 - 0.3 = 0.1

The probability to stop at the first signal but not at the second one is 0.1.

The probability of stopping at exactly one signal is equal at the sum of the probabilities of stopping only at the first signal and the probability of stopping only at the second one.

= P(S1 ∩ S2^c) + P(S1^c ∩ S2)

= 0.1 + P(S1^c ∩ S2)

Then,

= P(S2) = P(S1 ∩ S2) + P(S1^c ∩ S2) = 0.5

= 0.3 + P(S1^c ∩ S2) = 0.5

Therefore,

P(S1^c ∩ S2) = 0.55 - 0.3 = 0.25

And the probability of stopping at exactly one signal is 0.25 + 0.1 = 0.35.

The probability that he must stop at exactly 0.35.

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The high school marching band has 196 members,and 28 of them are a part of the percussion.How many members are on the marching band but not part of the percussion?

Answers

Answer:

168 members are on the marching band but not part of the percussion.

Step-by-step explanation:

Given:

The high school marching band has 196 members,and 28 of them are a part of the percussion.

Now, to find the members on the marching band but not part of the percussion.

Total members of marching band = 196.

Members of them who part of percussion = 28.

So, to get the members of the marching band who are not the part of the percussion we subtract members of them who part of percussion from total members of marching band:

[tex]196-28[/tex]

[tex]=168.[/tex]

Therefore, 168 members are on the marching band but not part of the percussion.

Which graph represents g(x)=−(x−3)2−5 ?

Answers

The graph is the C one

Answer:

The answer to your question is picture 1

Step-by-step explanation:

- This is a quadratic equation, so we look for a parabola. The four graphs show parabolas.

- We can notice a negative sign before the term (x - 3)², which indicates that it is a down-parabola. We discard the second and the fourth pictures.

- Get the vertex

                         y = -(x - 3)² - 5

                         y + 5 = - (x - 3)²      Vertex = (-5, 3)  

                                                         because we change signs

- With all this information, we conclude that the answer is picture 1 because its vertex is (-5, 3)

Find a third-degree polynomial equation with rational coefficients that has the given numbers as roots. 1 and 3i

Answers

Answer:

x³ − x² + 9x − 9 = 0

Step-by-step explanation:

Imaginary roots come in conjugate pairs.  So if 3i is a root, then -3i is also a root.

(x − 1) (x − 3i) (x − (-3i)) = 0

(x − 1) (x − 3i) (x + 3i) = 0

(x − 1) (x² − 9i²) = 0

(x − 1) (x² + 9) = 0

x (x² + 9) − (x² + 9) = 0

x³ + 9x − x² − 9 = 0

x³ − x² + 9x − 9 = 0

Final answer:

To find a third-degree polynomial equation with rational coefficients that has the given roots, we consider the conjugate of the complex root. The equation can be written as (x - 1)(x - 3i)(x + 3i) and simplified to x^3 - x^2 + 9x - 9.

Explanation:

To find a third-degree polynomial equation with rational coefficients that has the given roots of 1 and 3i, we need to consider the conjugate of 3i, which is -3i. Therefore, the roots of the equation are 1, 3i, and -3i.

To find the polynomial equation, we start by noting that the polynomials with rational coefficients will have complex conjugate pairs of roots. Thus, we can write the equation as (x - 1)(x - 3i)(x + 3i). Simplifying, we get (x - 1)(x^2 + 9). Expanding further, the equation is x^3 - x^2 + 9x - 9.

Therefore, the desired third-degree polynomial equation with rational coefficients is x^3 - x^2 + 9x - 9.

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Assume a color display using 8 bits for each of the primary colors (red, green, blue) per pixel and a frame size of 1280 × 1024. What is the minimum size in bytes of the frame buffer to store a frame?

Answers

-8bits is equivalent yo 1 byte

-bit is(0 or 1)

So each pixel requires 3 bytes

Primary colors are RGB(red,green and blue),so each color represent one byte.

The frame size is:

1280×1024=1310720 pixels

So that the frame contained 1310720 pixels

The size of the frame buffer is equal to the product of RGB and frame pixels:

=3 × 1310720

=3932160 bytes

Final answer:

The minimum size of the frame buffer to store a frame of 1280 x 1024 pixels, with 8 bits used for each of the three primary colors (red, green, blue) per pixel, is 3932160 bytes.

Explanation:

When calculating the size of a frame buffer, you want to take into account the number of pixels in the frame, the number of bits used to represent each primary color per pixel, and the number of primary colors. In this case, the frame is 1280 x 1024 pixels, and 8 bits are used for each of the three primary colors (red, green, blue) per pixel.

Therefore, the calculation will be as follows:

Calculate the total pixels on the screen: 1280 x 1024 = 1310720 pixels.Calculate total bits per pixel by multiplying the bit size of each color by the number of colors: 8 bits x 3 colors = 24 bits.Calculate total bits for the frame: 1310720 pixels x 24 bits/pixel = 31457280 bits.Convert bits to bytes by dividing by 8 (since there are 8 bits in a byte): 31457280 bits ÷ 8 = 3932160 bytes.

So, the minimum size of the frame buffer to store a frame in this context would be 3932160 bytes.

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State aid and state B or among the states with the most remaining and drive in movie screens state a has six more screen stay in state be there are 48 screens total in the two states how many drive-in movie screens remain in each state

Answers

Answer:

State A has 27 screens and state B has 21 screens.

Step-by-step explanation:

Let the number of screens in state B be 'x'.

Given:

Number of screens in state A is 6 more than state B

Total number of screens = 48.

Now, as per question:

Number of screens in state A = 6 more than state B.

Framing in equation form, we get:

Number of screens in state A = [tex]6+x[/tex]

Now, total number of screens is the sum of the screens in state A and number of screens in state B. Therefore,

Total number of screens = 48

Number of screens in state A + Number of screens in state B = 48

Substituting the given values, we get:

[tex]6+x+x=48\\\\6+2x=48\\\\2x=48-6\\\\2x=42\\\\x=\frac{42}{2}=21[/tex]

So, state B has 21 screens.

State A has = 6 + 21 = 27 screens.

Therefore, state A has 27 screens and state B has 21 screens.

If L leases property to T, and L subsequently assigns L’s interest to L2, whom may T hold liable when X, a paramount title holder, ejects T?

Answers

Answer: T may hold either L or L2

Step-by-step explanation: Going by Landlord and Tenant's law, when L leases a property to T and afterwards assigns his or her own interest to L2. T can either hold L or L2 when a paramount title holder X ejects T from the property.

According to the Law, L (in this case can be referred to as the Landlord) can actually assign all of his or her own rent rights and reversion to L2 (can be referred to as Landlord 2 or assignee). Whatever agreements or contracts made between L and T according to the lease of the property automatically ropes in L2. In this case, T is ejected by X who is a paramount title holder. This goes against the contract agreement between L and T, and therefore gives T the right to hold either L or L2.

I hope this helps.  

Let A denote the event that a disk has high shock resistance, and let B denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Input your answers in the fractional form (do not simplify).P(A)=86/100
P(B)=79/100
P(A')=7/50
P(A U B)=95/100
P(A' U B)= ???

Answers

Answer:

P(A' U B) = 84/100

Step-by-step explanation:

We have, P(A) = 86/100

P(B) = 79/100

P(A') = 7/50

P(A U B) = 95/100

-: P(A intersection B) = P(A) + P(B) - P(A U B)

P(A intersection B) = 86/100 + 79/100 - 95/100

P(A intersection B) = (86+79-95)/100 = (165-95)/100

P(A intersection B) = 70/100

Now, P(A' U B) = P(A') + P(A intersection B)

P(A' U B) = 7/50+70/100

P(A' U B) = (7*2+70)/100 = (14 + 70)/100

P(A' U B) = 84/100

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