WILL GIVE BRANLY Which Union general was fired from his job after the Battle of Antietam? A Lee B Scott C Sherman D McClellan

3.4(x+1.58)= - 11.288

Step 1: Distribute 3.4 to the numbers inside the parentheses (x+1.58)

3.4x + (3.4×1.58)= - 11.288

3.4x + 5.372 = -11.288

Step 2: Bring 5.372 to the right side by subtracting it to both sides

3.4x + (5.372 - 5.372 ) = (-11.288 - 5.372)

3.4x + (0) = (-16.66)

3.4x = -16.66

Step 3: Isolate x by dividing 3.4 to both sides

[tex]\frac{3.4x}{3.4}  = \frac{-16.66}{3.4}[/tex]

x = -4.9

Hope this helped!

Your question doesn't look like one, but I'll give you a set of 10 questions of arithmetic. Do not forget to use PEMDAS.

Another answer will be available in the comments just in case if this is not what you wanted.

Answer:

the answer is D. mark me brainliest if im correct.

Step-by-step explanation:

The equivalent expression for (x² - 8) - (-2x² + 4) is 3x² - 12

Option D is the correct answer.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

(x² - 8) - (-2x² + 4)

Remove the parenthesis.

x² - 8 + 2x² - 4

Add like terms.

3x² - 12

Thus,

The equivalent expression is 3x² - 12

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Answer:

[tex]\left\{x\in \mathbb {Z}\ : \ x \le 0 \right\}[/tex]

Step-by-step explanation:

Set-Builder Notation: A shorthand used to describe sets, often sets with an infinite number of elements.

The set {...,-3, -2, -1, 0} is the set of all negative integers and 0, so you can use such set-builder notation:

[tex]\left\{x\in \mathbb {Z}\ : \ x \le 0 \right\}[/tex]

Note: Here [tex]\mathbb{Z}[/tex] represents the set of all integers.

Final answer:

The set {... -3, -2, -1, 0} can be represented in set builder notation as {x ∈ ℤ | -3 ≤ x < 1 }, which describes all integers x that are greater than or equal to -3 and less than 1.

Explanation:

To express the set that includes the numbers -3, -2, -1, and 0 using set builder notation, we start by recognizing that these numbers can be described by a pattern or rule, which is that they are all the integer numbers greater than or equal to -3 and less than 1. We can then write this using set builder notation as:

{x ∈ ℤ | -3 ≤ x < 1 }

In this notation, the variable 'x' represents the elements of the set and ∈ stands for 'element of.' ℤ is the symbol for integers. The vertical bar or colon (|) stands for 'such that.' Our notation reads as 'the set of all integers x such that -3 is less than or equal to x and x is less than 1.'

Answer:

[tex]y-0=-1(x-8)[/tex]

Step-by-step explanation:

The given line passes through (0,8) and (8,0).

The slope of this line is [tex]m=\frac{8-0}{0-8} =-1[/tex].

The point-slope form is given by:

[tex]y-y_1=m(x-x_1)[/tex]

We substitute the slope and the point (8,0) to get:

[tex]y-8=-1(x-0)[/tex]

We substitute the slope and the point (0,8) to get:

[tex]y-0=-1(x-8)[/tex]

Answer:

rectangle. trapezoid. triangle. A sphere is sliced so that the cross section does not intersect the center of the sphere

Answer:

sorry im late to this but it is a triangle

Step-by-step explanation:

because when you cut it horizontally and look at the top it is a rectangle so that is wrong trapezoid is when you look at it from the side when cut horizontally so that is wrong there is no square so that instantly becomes wrong because it is a rectangular pyramid  when  perpendicular it will provide you with a triangle  

ANSWER

n=5

EXPLANATION

The area of a square is given by

[tex] {l}^{2} [/tex]

where l is the length of the sides.

If the area is

[tex] {x}^{10} [/tex]

then we can rewrite this as

[tex]( { {x}^{5}) }^{2} [/tex]

This implies that:

[tex] {l}^{2} = ( { {x}^{5}) }^{2} [/tex]

Hence,

[tex]l = {x}^{5}[/tex]

Therefore n=5

Answer:

Commutative Property

Step-by-step explanation:

"Changing the order but not the result"

Answer:

Step-by-step explanation:

(x-3)^2

Answer:

(x-3)

Step-by-step explanation:

Answer:

Angle 1 and 3

Step-by-step explanation:

Those angles are vertical angles,and vertical angles are always congruent.

Answer:

x-6

Step-by-step explanation:

6 pencils less than x in terms of x it would be x-6

hope it helps

In the given problem, the amount of pence that Jill has can be expressed in terms of x (the amount of pence that Jack has) as x - 6. This means Jill has 6 pence less than Jack. If Jack has a certain number of pence represented as x, then Jill would have that number minus 6.

The question asks for the amount of pence that Jill has in terms of x, where x is the amount of pence that Jack has. Given that Jill has 6 pence less than Jack, we can represent the amount of pence Jill has as x - 6. Therefore, if Jack has x pence, Jill would have x - 6 pence. For example, if Jack (x) has 10 pence, Jill would have 4 pence (x - 6 = 10 - 6).

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Final answer:

The correct pair of points that is in the solution set for the given system of linear inequalities is option a) (0, 3/2) and (3/4, 1/4). Each point in this pair satisfies both of the inequalities when substituted into them.

Explanation:

The question asks which pair of points is in the solution set for the given system of linear inequalities:

2x + y < 2

6x + 3y > 2

To verify if the points provided are solutions, we plug them into the inequalities to see if they satisfy both conditions.

Let's test each pair:

For pair a) (0, 3/2), the first inequality becomes 2(0) + (3/2) = 3/2, which is less than 2, so it satisfies the first inequality. For the second inequality, 6(0) + 3(3/2) = 9/2, which is greater than 2, so it satisfies the second inequality as well. Therefore, (0, 3/2) is a solution. However, for the second point (3/4, 1/4), the first inequality becomes 2(3/4) + (1/4) = 3/2 + 1/4 = 7/4, which is less than 2, satisfying the first inequality. But for the second inequality, we get 6(3/4) + 3(1/4) = 9/2 + 3/4 = 21/4, which is greater than 2, satisfying the second inequality, so (3/4, 1/4) is also a solution.

For pair b), to be brief, one point does not satisfy both inequalities.

For pair c), one point does not satisfy both inequalities.

For pair d), one point does not satisfy both inequalities.

Therefore, the correct pair of points is option a) (0, 3/2) and (3/4, 1/4), as they both are solutions to the system of inequalities.

Answer:

Step-by-step explanation:

This has a very brief answer when you know what it means.

f(x) + g(x) = abs(x) + 9 - 6

f(x) + g(x) = abs(x) + 3

Answer:

f + g)(x) = |x| + 3

Step-by-step explanation:

Add the two functions together:

f(x) = |x| + 9

+g(x) = - 6

------------------------

f(x) + g(x) = |x| + 9 - 6

               = |x| + 3

The label  f(x) + g(x)  can be rewritten as (f + g)(x).  

Thus, f + g)(x) = |x| + 3

Answer:

29 + n

Step-by-step explanation:

To increase 29 by n, we add n to 29. Then we get 29 + n.

hope it helps.

PS plzzzz mark me brainliest

Answer:

29 + n

Step-by-step explanation:

When we increase a number by another number, we're performing the operation of addition, so the phrase here would translate to the expression 29 + n.

Answer:

C

Step-by-step explanation:

Given

[tex]\sqrt{3x+8}[/tex] = [tex]\sqrt{4x+1}[/tex]

[ note that ([tex]\sqrt{x}[/tex])² = x ]

Square both sides

3x + 8 = 4x + 1 ( subtract 4x from both sides )

- x + 8 = 1 ( subtract 8 from both sides )

- x = - 7 ( multiply both sides by - 1 )

x = 7 → C

Answer:

x = 7.

Step-by-step explanation:

Squaring both sides:

3x + 8 = 4x + 1

3x - 4x = 1 - 8

-x = -7

7 = x.

Answer:

[tex]\large\boxed{60\pi\ sq.in.}[/tex]

Step-by-step explanation:

The formula of a lateral area of a cone:

[tex]L.A.=\pi rl[/tex]

r - radius

l - lateral height

We have the radius r = 6in and the height H = 8in.

Use the Pythagorean theorem to calculate the lateral height:

[tex]l^2=6^2+8^2\\\\l^2=36+64\\\\l^2=100\to l=\sqrt{100}\\\\l=10\ in[/tex]

Substitute:

[tex]L.A.=\pi(6)(10)=80\pi\ in^2[/tex]

Answer:

[tex]\large\boxed{\text{If is "or", then}\ x>-2\dfrac{1}{15}}\\\boxed{\text{If is "and", then}\ x>1\dfrac{9}{14}}[/tex]

Step-by-step explanation:

[tex]7x+\dfrac{3}{2}>13\qquad\text{multiply both sides by 2}\\\\14x+3>26\qquad\text{subtract 3 from both sides}\\\\14x>23\qquad\text{divide both sides by 14}\\\\x>\dfrac{23}{14}=1\dfrac{9}{14}\\=====================\\\\\dfrac{5}{2}x-\dfrac{1}{3}>-\dfrac{11}{2}\qquad\text{multiply both sides by 2}\\\\5x-\dfrac{2}{3}>-11\qquad\text{multiply both sides by 3}\\\\15x-2>-33\qquad\text{add 2 to both sides}\\\\15x>-31\qquad\text{divide both sides by 15}\\\\x>-\dfrac{31}{15}=-2\dfrac{1}{15}\\=====================[/tex]

Final answer:

To solve the compound inequality, each inequality is solved individually. The first inequality yields x > 1.64285714, and the second yields x > -2.06666667. As this is an 'or' compound inequality, the solution is the union of both, leading to x > 1.64285714.

Explanation:

To solve the compound inequality 7x + 3/2 > 13 or 5/2x - 1/3 > -11/2, we need to treat each inequality separately and then find the union of their solutions.

For the first inequality:

Subtract 3/2 from both sides to get 7x > 11.5.

Divide both sides by 7 to find x > 11.5/7, which simplifies to x > 1.64285714.

For the second inequality:

Multiply both sides by 6 to clear the fraction, leading to 15x - 2 > -33.

Add 2 to both sides to get 15x > -31.

Divide both sides by 15 to find x > -31/15, which simplifies to x > -2.06666667.

The solution is the set that satisfies at least one of these inequalities. Since x > 1.64285714 or x > -2.06666667, the overall solution is x > 1.64285714.

Answer:

12. AM= 2x+4

MB= 5x-8

AB= ?  

So to get AB, you would need to find the total measurements of AM and MB.  

AM=MB  

2x+4=5x-8

2x=5x-12

-3x=-12

x=4

20. AE= 37

21. AC=  16

Step-by-step explanation:

Answer:

±6

Step-by-step explanation:

Whenever you are finding the square root of something, it will ALWAYS result in a negative and positive number, or else depending on the situation of a problem.

Ex: Distance Formula → POSITIVE ANSWER ONLY

I am joyous to assist you anytime.

The simulation design that has an appropriate device and a correct trial for this scenario is:

The correct option is C.

The simulation which involves using a table of random digits to select a digit between 0 and 9, letting 0 - 2 represent eating dessert and 3 - 9 represent not eating dessert, and then selecting three digits has an appropriate device and a correct trial.

This simulation design is given below:

To simulate the probability of eating dessert in 3 of the 7 days this week, we would select three digits from the table of random digits and count the number of 0s, 1s, and 2s. The number of 0s, 1s, and 2s would correspond to the number of days the children eat dessert, and the number of 3s, 4s, 5s, 6s, 7s, 8s, and 9s would correspond to the number of days the children do not eat dessert.

We would repeat this process many times (e.g., 1000 times) to obtain an estimate of the probability of eating dessert 3 of the 7 days this week.

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1. simply: h+245

2. your answer is right

3. 2+1/3n (i believe)

4. 29+5m

5. I’m pretty sure the answer is 29

Answer:

1/14

Step-by-step explanation:

The total number of coins in the bag is 10+6+5, or 21.

You reach into the bag and take ONE coin.  The chances of that being a nickel is 6/21, or 2/7, since nickels compose 6 of the 21 coins in the bag.

You don't replace the nickel.

Now you have 20 coins in the bag, including 5 nickels.

The chances of your next draw being a dime is 5/20, or 1/4, since there are 5 dimes in the bag.

The joint probability of drawing a nickel and then a dime is then the product of these two probabilities:

(2/7)(1/4) = 2/28 = 1/14

I'm not the best at math, but I tried.

x= the amount of months passed

The question asks for the population of fleas in 1 year, and 1 year = 12 months, then x would equal 12 months

Therefore, you substitute that x with 12

f(x)=250(2^x)-------f(x)=250(2^12)

Now you can solve that part of the problem:

2 to the power of 12= 4096

f(x)=250(4096)

now multiply that:

250×4096= 1024000

The answer is C. 1024000

The answer is 1,024,000 fleas.

The function f(x)=250(2^x) gives the population of fleas after x months. To find out how many fleas there will be after 1 year, substitute x=12 into the function:
f(12) = 250(2^12) = 250 * 4096 = 1,024,000 fleas.

Answer:

Hyperbola:

[tex]x^2-y^2-8x+6y-1=0[/tex]

Step-by-step explanation:

the given hyperbola has equation:

[tex]x^2-y^2=8[/tex]

This is an equation of a hyperbola centered at the origin.

This hyperbola is translated so its center is now at T(4,3)

[tex](x-4)^2-(y-3)^2=8[/tex]

We expand to get:

[tex]x^2-8x+16-(y^2-6y+9)=8[/tex]

[tex]x^2-8x+16-y^2+6y-9=8[/tex]

[tex]x^2-8x-y^2+6y+7=8[/tex]

[tex]x^2-8x-y^2+6y+7-8=0[/tex]

[tex]x^2-y^2-8x+6y-1=0[/tex]

Answer:

Its B

Step-by-step explanation:

it just is lol

Answer:

A

Step-by-step explanation:

Note that

x² + 12x + 36 is a perfect square → (x + 6)², hence

[tex]\sqrt{x^2+12x+36}[/tex] = [tex]\sqrt{(x+6)^2}[/tex] = (x + 6)

Hence

f(x) × g(x)

= (x + 6)(x³ - 11)

= [tex]x^{4}[/tex] - 11x + 6x³ - 66

= [tex]x^{4}[/tex] + 6x³ - 11x - 66 → A

(f·g)(x) in mathematics denotes the product of two functions, f(x) and g(x). Its interpretation and output may vary depending on the functions f(x) and g(x), but essentially, it is a multiplication of these two functions.

In mathematics, expressing (f·g)(x) indicates the product of two functions at a given x-coordinate. This is equivalent to f(x) multiplied by g(x). For instance, if f(x) = 2x and g(x) = 3x, then (f · g)(x) would yield (2x)(3x), resulting in 6x².

It's important to note that mathematical functions can vary, and this expression can take on various forms based on the nature of f(x) and g(x).

The provided reference information appears to be a mix of rules from differential calculus and mathematical definitions, which lack a direct relation to the original question about (f·g)(x). The primary concept here is understanding function multiplication.

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Answer:

[tex]\large\boxed{(7x+5)(2x^3-4x^2+9x-3)=14x^4-18x^3+43x^2+24x-15}[/tex]

Step-by-step explanation:

Use FOIL: (a + b)(c + d) = ac + ad + bc + bd

[tex](7x+5)(2x^3-4x^2+9x-3)\\\\=(7x)(2x^3)+(7x)(-4x^2)+(7x)(9x)+(7x)(-3)\\+(5)(2x^3)+(5)(-4x^2)+(5)(9x)+(5)(-3)\\\\=14x^4-28x^3+63x^2-21x+10x^3-20x^2+45x-15\\\\\text{combine like terms}\\\\=14x^4+(-28x^3+10x^3)+(63x^2-20x^2)+(-21x+45x)-15\\\\=14x^4-18x^3+43x^2+24x-15[/tex]

Answer:

A)

Step-by-step explanation:

We know that the expression (x^2 - a^2) can be written as (x-a)(x+a). So an expression of this type: (x^2 - a^2) wouldn't be completely factored because it could be factorized even more.

So we know that 36 = 6^2, 49= 7^2 and 81 = 9^2. So if we choose any of these options (Option B, C and D) it wouldn't be completely factored.

The correct is the option A, given that if a=12, it wouldn't be a perfect square, so it would be completely factored.

So I just did the problem and im pretty sure the answer is A

Answer:

(a)

Step-by-step explanation:

To rationalise the fraction multiply the numerator/denominator by the conjugate of the denominator.

The conjugate of [tex]\sqrt{3}[/tex] + [tex]\sqrt{x}[/tex] is [tex]\sqrt{3}[/tex] - [tex]\sqrt{x}[/tex]

Hence

[tex]\frac{\sqrt{9}(\sqrt{3}-\sqrt{x} )  }{(\sqrt{3}+\sqrt{x} )(\sqrt{3}-\sqrt{x} )  }[/tex]

= [tex]\frac{3(\sqrt{3}-\sqrt{x}  }{3-x}[/tex]

= [tex]\frac{3\sqrt{3}-3\sqrt{x}  }{3-x}[/tex] → (a)

Answer:

[tex]A=452.39\ cm^2[/tex]

Step-by-step explanation:

The formula to calculate the surface area of a sphere is the following:

[tex]A=4\pi r^2[/tex]

Where A is the area of the sphere and r is the radius of the sphere.

In this case we know that the diameter d of the sphere is:

[tex]d = 12\ cm[/tex]

The diameter is:

[tex]d = 2r[/tex].

Thus

[tex]r = \frac{d}{2}\\\\r = \frac{12}{2}\\\\r=6\ cm[/tex]

Then the surface area of the sphere is:

[tex]A=4\pi (6)^2\\\\A = 144\pi\ cm^2\\\\A=452.39\ cm^2[/tex]

Answer is provided in the image attached.

Answer:

96 deg

Step-by-step explanation:

Polygon ABCDE is a regular hexagon. The sum of the measures of the interior angles is (n - 2)180 = (6 - 2)180 = 4(180) = 720. Since it's a regular hexagon, each interior angle measures 720/6 = 120 deg.

For the interior angle, m<CDE = 120

On the exterior of the polygon, m<CDJ = 136

m<CDE + m<CDJ + m<EDJ = 360

120 + 136 + m<EDJ = 360

m<EDJ + 256 = 360

m<EDJ = 104 deg

Triangle EHG is regular. The sum of the measures of the angles of a triangle is 180. For a regular triangle, each angle measures 60 deg.

m<EGH = 60

For exterior angle m<HGJ = 220

m<HGJ(exterior) + m<EGH + m<EGJ = 360

220 + 60 + m<EGJ = 360

m<EGJ + 280 = 360

m<EGJ = 80

m<EGJ = m<GED, so

m<GED = 80

Polygon DEGJ is a quadrilateral. The sum of the measures of its interior angles is 360 deg.

m<EGJ + m<GED + m<EDJ + m<GJD = 360

80 + 80 + 104 + m<GJD = 360

m<GJD + 264 = 360

m<GJD = 96 deg

Answer:

The measure of angle GJD is 96°.

Step-by-step explanation:

It is given that HGJ=220° on the exterior of the polygon, EGJ is congruent to GED, and CDJ=136° on the exterior of the polygon.

Each side and each interior angle of a regular polygon are same.

It is given that ABCDEF and EHG are regular polygons. It means each interior angle of regular hexagon ABCDEF is 120° and each interior angle of regular triangle EHG is 60°.

[tex]\angle EGH+\angle EGJ+\angle HGJ(exterior)=360^{\circ}[/tex]

[tex]60^{\circ}+\angle EGJ+220^{\circ}=360^{\circ}[/tex]

[tex]\angle EGJ+280^{\circ}=360^{\circ}[/tex]

[tex]\angle EGJ=360^{\circ}-280^{\circ}[/tex]

[tex]\angle EGJ=80^{\circ}[/tex]

[tex]\angle GED=\angle EGJ=80^{\circ}[/tex]

[tex]\angle CDE+\angle EDJ+\angle CDJ(exterior)=360^{\circ}[/tex]

[tex]120^{\circ}+\angle EDJ+136^{\circ}=360^{\circ}[/tex]

[tex]\angle EDJ+256^{\circ}=360^{\circ}[/tex]

[tex]\angle EDJ=360^{\circ}-256^{\circ}[/tex]

[tex]\angle EDJ=104^{\circ}[/tex]

The sum of all interior angles of a quadrilateral is 360°.

[tex]\angle GED=\angle EGJ+\angle EDJ+\angle GJD=360^{\circ}[/tex]

[tex]80^{\circ}+80^{\circ}+104^{\circ}+\angle GJD=360^{\circ}[/tex]

[tex]264^{\circ}+\angle GJD=360^{\circ}[/tex]

[tex]\angle GJD=360^{\circ}-264^{\circ}[/tex]

[tex]\angle GJD=96^{\circ}[/tex]

Therefore the measure of angle GJD is 96°.