Why is a standard system of measurement important?

A. Scientists want to share measurements data that they can understand

B. Each country wants its own set of measurement standards.

C. Measurements are seldom shared with scientists in different countries

D. Scientists speak many different languages.

Correct answer choice is:

B. forefinger in the direction of the lines of force.

Explanation:

The direction of the force - and consequently the transfer of the wire - can be defined by applying Fleming’s left-hand rule.

The forefinger tends to the direction of the magnetic field. The middle finger points in the course of the current. The thumb supplies the direction of force or movement working on the conductor. Fleming's Left Hand Rule is applied in electronic engines which are utilized in coolers, appliances, printers, etc.

The components of a typical refracting telescope are basically convex object and convex eyepiece. The correct option is 1.

A typical refracting telescope is made up of a series of convex lenses. The objective lens is a convex lens positioned at the front of the telescope that collects and focuses light from distant objects. At the focus point, it creates an inverted actual picture.

The eyepiece, which is located at the telescope's back end, is likewise a convex lens. Its goal is to amplify the picture created by the objective lens so that the viewer may see a bigger, upright, magnified image.

In a standard refracting telescope, the correct combination is a convex objective lens and a convex eyepiece.

Thus, the correct option is 1.

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Your question seems incomplete, the probable complete question is:

Which are the components of a typical refracting telescope?

1.convex object and convex eyepiece

2. concave object and convex eyepiece

3. convex object and concave eyepiece

Answer:

New discoveries can either provide evidence to support or refute contemporary psychological perspectives, or they can lead to the development of new theories and perspectives.Explanation:

Final answer:

The vapor pressure of cyclohexane at its normal boiling point of 81.0 ℃ is 101.3 kPa.

Explanation:

The question is asking for the vapor pressure of cyclohexane at its normal boiling point of 81.0 ℃. By definition, the normal boiling point of a liquid is the temperature at which its vapor pressure is equal to the external atmospheric pressure at sea level, which is 101.3 kPa (or 1 atmosphere). Therefore, the vapor pressure of cyclohexane at 81.0 ℃ is 101.3 kPa.

The area which is located under the curve gives us the angle in radians; we divide this by 2π to get units in revs (revolutions).

So for 0 ≤ t ≤ 2,

number of revs = 20rad/s * 2s * 1rev/2π rads = 6.37 revs 

So for 2 ≤ t ≤ 3.9,

number of revs = 10rad/s * 1.9s * 1rev/2πrads = 3.02 revs 

Therefore the total is about:

6.37 revs + 3.02 revs = 9.39 revs ≈ 9.4 revs

To answer how many revolutions an object makes in 3.9 seconds, we require knowledge of the object's constant angular velocity or angular acceleration. With the angular velocity, the total radians rotated can be found and divided by 2π to get the number of revolutions.

The question "How many revolutions does the object make during the first 3.9 s?" involves calculating the number of complete rotations or revolutions an object makes over a given period of time. In physics, this is often related to concepts of rotational motion, including angular velocity and angular acceleration. However, to calculate the number of revolutions over a certain time, we need to know either the constant angular velocity of the object, the angular acceleration, or another related quantity that would allow us to determine how the angle changes over time.

For example, if we know the angular velocity (ω) in radians per second (rad/s), we can calculate the number of revolutions by integrating the angular velocity over the given time period (3.9 s) or multiplying it by time if the angular velocity is constant. Since one revolution is equivalent to 2π radians, we can determine the total number of revolutions by dividing the total angle rotated (in radians) by 2π.

The lowest gear on a bicycle provides the greatest mechanical advantage by amplifying the force exerted on the pedals, requiring the rider to pedal more but with less effort per stroke, due to the conservation of energy.

In order to climb a steep hill on a bicycle, a rider shifts to the lowest gear. The lowest gear has the greatest mechanical advantage because it allows the rider to apply a force over a greater distance. When a gear with many teeth drives a gear with fewer teeth, the driven gear spins more times but with a smaller turning force, amplifying the force the rider exerts on the pedals.

However, this means the rider will have to spin the pedals more times to cover the same distance, which is a trade-off.

This concept of mechanical advantage applies to all machines and is governed by the conservation of energy, which states that work input is equal to work output, minus any losses due to inefficiency like friction.

The speed of the particle at [tex]t = 5\,{\text{s}}[/tex] is [tex]\fbox{43\,{\text{m/s}}}[/tex].

Further explanation:

Applied force is directly proportional to the mass of the body and the acceleration of the body.

Given:

The function for force is [tex]F\left( t \right) = 6{t^2} - 4t + 3[/tex].

The limit of time is [tex]t = 0\,{\text{s}}[/tex] to [tex]t = 5\,{\text{s}}[/tex].

The mass of the particle is [tex]5\,{\text{Kg}}[/tex].

Concept used:

The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.

Newton’s second law of motion states that the rate of change of momentum is equal to the applied force.

The expression for the Newton’s second law is given as.

[tex]F=ma[/tex]

Rearrange the expression for the acceleration of the body.

[tex]a=\dfrac{F}{m}[/tex]                                                              …… (1)

Here, a is the acceleration of the body, F is the force applied and m is the mass of the body.

The rate of change of speed of a body in unit time is called acceleration of the body.  

The expression for the acceleration is given as.

[tex]a=\dfrac{{dv}}{{dt}}[/tex]

Substitute [tex]\dfrac{{dv}}{{dt}}[/tex] for [tex]a[/tex] in equation (1).

[tex]\dfrac{{dv}}{{dt}} = \dfrac{F}{m}[/tex]

On integrating the above expression we get.

[tex]v = \dfrac{1}{m}\int\limits_0^5 {Fdt}[/tex]                                 …… (2)

Substitute [tex]6{t^2} - 4t + 3[/tex] for[tex]F\left(t\right)[/tex] and [tex]5\,{\text{Kg}}[/tex] for m in equation (2).

[tex]\begin{aligned} v&=\frac{1}{{\left( {5\,{\text{Kg}}} \right)}}\int\limits_0^5 {\left( {6{t^2} - 4t + 3} \right)dt}\\&=\frac{1}{{\left( {5\,{\text{Kg}}}\right)}}\left|{3{t^3}-2{t^2}+ 3t}\right|_0^5\\&=\frac{{215}}{{5\,}}\,{\text{m/s}}\\&=43\,{\text{m/s}}\\\end{aligned}[/tex]

Thus, the speed of the particle is [tex]\fbox{43\,{\text{m/s}}}[/tex].

Learn more:

1.  Motion under force https://brainly.com/question/4033012.

2.  Conservation of momentum https://brainly.com/question/9484203.

3. Motion under friction https://brainly.com/question/7031524.

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Acceleration, force, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, Newton’s laws, speed, rate of change, time , 43m/s, 5Kg.

If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

The horizontal component of the velocity during any projectile motion is constant and is given by vicosθ.

Thus, If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

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Answer:

9.83 km/h

Explanation:

Given: in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes.

To Find:  the average speed of the runner for the race.

Solution:

In a 4 kilometer race,

time required to travel first kilometer = [tex]5.9[/tex] [tex]\text{minutes}[/tex]

time required to travel seoond kilometer = [tex]6.2[/tex] [tex]\text{minutes}[/tex]

time required to travel third kilometer = [tex]6.3[/tex] [tex]\text{minutes}[/tex]

time required to travel final kilometer = [tex]6[/tex] [tex]\text{minutes}[/tex]

we know that,

[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]

Total distance traveled = [tex]4[/tex]  [tex]\text{kilometer}[/tex]

Total time taken = [tex](5.9+6.2+6.3+6)[/tex]

                           =  [tex]24.4[/tex] [tex]\text{minutes}[/tex]

                           = [tex]\frac{24.4}{60}[/tex]  [tex]\text{hours}[/tex]

putting values,

[tex]\text{Average speed}=\frac{4}{\frac{24.4}{60}}[/tex]

 [tex]\text{Average speed}=\frac{4\times60}{24.4}[/tex]

                                            =[tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]

the average speed of the runner for the race is approximately [tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]

The formula for calculating the distance at constant velocity is:

d = v * t

d = 15 t

The formula for distance at constant acceleration is:

d = v0 t + 0.5 a t^2

d = 15 t + 0.5 t^2

So after a sum distance of 164 m:

15 t + (15 t + 0.5 t^2) = 164

30 t + 0.5 t^2 = 164

t^2 + 60 t = 328

(t + 30)^2 = 328 + 30^2

t + 30 = ± 35.04

t = -65.04, 5.04

Since time cannot be negative, so the two cars are 164 m apart after about 5 seconds

Final answer:

When a droplet is motionless in an electric field, it means the electrical force exactly balances gravity. Coulomb's law defines the electrical force as proportional to charge [tex](\( q \))[/tex] and the field strength [tex](\( E_0 \))[/tex]. Meanwhile, gravity exerts a force[tex]\( mg \)[/tex], where [tex]\( m \)[/tex] is the droplet's mass and [tex]\( g \)[/tex] is gravity's acceleration. Equilibrium occurs when these forces match:

[tex]\[ qE_0 = mg \][/tex]

Rearranging, we find the droplet's charge [tex]\( q \):[/tex]

[tex]\[ q = \frac{mg}{E_0} \][/tex]

This expression signifies the charge required for equilibrium in the given electric field.

Explanation:

To find the expression for the droplet's charge [tex](\( q \)),[/tex] we can use the equilibrium condition where the electric force [tex](\( F_{\text{electric}} \))[/tex] due to the electric field [tex](\( E_0 \))[/tex]balances the gravitational force [tex](\( F_{\text{gravity}} \))[/tex]acting on the droplet.

The electric force [tex](\( F_{\text{electric}} \))[/tex] exerted on the droplet with charge [tex]\( q \) i[/tex]n an electric field [tex]\( E_0 \)[/tex] is given by Coulomb's law:

[tex]\[ F_{\text{electric}} = qE_0 \][/tex]

The gravitational force [tex](\( F_{\text{gravity}} \))[/tex] acting on the droplet with mass [tex]\( m \)[/tex] in a gravitational field [tex]\( g \)[/tex] is given by:

[tex]\[ F_{\text{gravity}} = mg \][/tex]

At equilibrium, these forces balance each other:

[tex]\[ qE_0 = mg \][/tex]

Solving for [tex]\( q \):[/tex]

[tex]\[ q = \frac{mg}{E_0} \][/tex]

So, the expression for the droplet's charge [tex]\( q \)[/tex] is:

[tex]\[ q = \frac{mg}{E_0} \][/tex]

Use the expression -

P²k = a³---(i)

Where P is time in years, a is in AU, k is the function of the Sun's mass and set to unity.

Further, we're looking for the mass of the new star we have slightly modified Kepler's Third Law. After all, the inverse of a constant is also a constant. The reason we do it is because we want an answer in the form of K:1, where K is the mass of the HD 10180 and the mass of the Sun is 1, so k needs to start out on the other side.

Convert 600 days in years = 600/365 = 1.64 years

Put this in the expression mentioned at (i) -

1.64²k = a³

You gave us a = 1.4 AU

1.64²k = 1.4³ ; isolating k

k = 1.4³/1.64²

k = 2.744/2.702 = 1.015

So, the requisite ratio = 1.015 : 1

The ratio of the star's mass to the sun's mass is about 1.02 : 1

[tex]\texttt{ }[/tex]

Centripetal Acceleration can be formulated as follows:

[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

[tex]\texttt{ }[/tex]

Centripetal Force can be formulated as follows:

[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of the sun = M_sun = 1.99 × 10³⁰ kg

radius of the orbit = R = 1.4 AU = 2.094 × 10¹¹ m

Orbital Period of planet = T = 600 days = 600 × 24 × 3600 = 5.184 × 10⁷ seconds

Asked:

mass of the star = M = ?

Solution:

Firstly , we will use this following formula to find the mass of the star:

[tex]F = ma[/tex]

[tex]G \frac{ Mm}{R^2}=m \omega^2 R[/tex]

[tex]G M = \omega^2 R^3[/tex]

[tex]\frac{GM}{R^3} = \omega^2[/tex]

[tex]\omega = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]\frac{2\pi}{T} = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]M = \frac{4 \pi^2 R^3}{GT^2}[/tex]

[tex]M = \frac{4 \pi^2 (2.094 \times 10^{11})^3}{6.67 \times 10^{-11} \times (5.184 \times 10^7)^2}[/tex]

[tex]\boxed {M \approx 2.0 \times 10^{30} \texttt{ kg} }[/tex]

[tex]\texttt{ }[/tex]

Next , we will calculate the ratio of the star's mass to the sun's mass as follows:

[tex]M : M_{sun} = (2.0 \times 10^{30}) : (1.99 \times 10^{30})[/tex]

[tex]\boxed{M : M_{sun} \approx 1.02 : 1}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Circular Motion

Answer:

Continuity vs. Stages

Explanation:

Continuity is the gradual changes that a person may experiment throught their life, good examples are the ones given in the question, height and weght increasing or changing over time, but stages start whenever something happens that changes the way of life of the person, for example graduating college and going into the labor force, or getting married.

From Newton’s law of motion, the relation for velocity, acceleration and displacement is given by v^2 = vo^2 + 2as. Where v and vo are final and initial velocity respectively, and a, s are the acceleration and displacement respectively. From Newton’s second law, F = ma. Where m is the mass.

The magnitude of the frictional fore can be calculated only before estimating the ston’s acceleration. The initial speed of stone is mentioned in the problem as 3 m/s. Also, after 40m, the stone will stop. This means that its final speed is 0 m/s and the displacement is 40m.The acceleration of rock is calculated as:

(0 m/s)^2 = (3 m/s)^2 + 2a (40m).

9 m^2/s^2 = -2a(40m)

a= -9m^2/s^2/80m = 0.1 m/s^2.

This means that deceleration will occur and this will stop the stone. Substituting to Newton’s second law of motion,

-F = 20kg * -0.1 m/s^2. Further solve,

F = 20kg * 0.1 m/s^2 = 2N. Hence, the magnitude frictional force is 2N. 

In curling, the final position of the stone depends on its initial speed and the force of friction. Team members can use brooms to adjust the stone's speed and trajectory. The force of friction opposes the stone's motion.

In the winter sport of curling, the final position of the stone depends on the initial speed at which it is launched and the force of friction between the ice and the stone. Team members can use brooms to sweep the ice, which can adjust the stone's speed and trajectory. By judicious sweeping, they can lengthen the travel of the stone by a few meters. The force of friction between the ice and the stone will oppose the motion of the stone and slow it down.

The initial speed at which the stone is launched will determine how far it travels before coming to rest. If the stone is launched with a higher initial speed, it will travel a farther distance. The force of friction between the ice and the stone will also influence the distance the stone travels. A higher frictional force will cause the stone to slow down more quickly, resulting in a shorter travel distance.

Answer: The correct answer is constructive interference.

Explanation:

Interference is the phenomenon in which there is superposition of the two waves. Interference are of two types: Constructive interference and Destructive interference.

Constructive interference occurs when the there is a superposition of the two waves. The resulting wave has a large amplitude.

Destructive interference occurs when the there is a superposition of the two waves. The resulting wave has a low amplitude.

Therefore, Constructive interference occurs when two waves overlap and the resulting wave has a larger amplitude.

Answer:

B. Constructive

The liquid's index of refraction is approximately 1.88.

To find the index of refraction for the liquid, we can use the formula:

n₁ / n₂ = λ₁ / λ₂

where n₁ and n₂ are the indices of refraction for air and the liquid, respectively, and λ₁ and λ₂ are the wavelengths of light in air and the liquid, respectively.

In this problem, we are given that the wavelength of light in air is 495 nm and the wavelength in the liquid is 434 nm. Plugging in these values, we get:

n₁ / n₂ = 495 nm / 434 nm

n₂ ≈ n₁ * (434 nm / 495 nm)

n₂ ≈ 1 * (434 nm / 495 nm)

n₂ ≈ 0.876

To convert the index of refraction to its decimal form, we add 1, giving us:

n₂ ≈ 0.876 + 1

n₂ ≈ 1.876

The liquid's index of refraction is approximately 1.876, which can be rounded to 1.88.

The total displacement and total distance of the object that traveled should be -2cm and 16 cm.

Given that,

Based on the above information, the calculation is as follows:

The total displacement is

= 0 - 3 + 7 - 6

= -2 cm,

Thus,  the object shifts 2 cm to the left-hand side.  

Now

The total distance is  

= 0 + 3 + 7 + 6

= 16 cm

Therefore we can conclude that the total displacement and total distance of the object that traveled should be -2cm and 16 cm.

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Answer:

The object moves ✔ 2 cm to the left.

What is the total distance the object travels? ✔ 16 cm.