solve the exponential equation using the method of relating the bases by first rewriting the equation in the form of e^u=e^v
1/e ^6x =√e ÷e ^6−x ...?
Find the length of arc XPY.
Answer:
Arc length XPY =28.26 m.
Step-by-step explanation:
Given : A circle with two arc XY and XPY and radius 6 m.
To find : Arc length XPY.
Solution : We have given that arc XY and XPY .
Radius = 6 m.
Central angle formed by arc XPY = 360 - 90 = 270.
Arc length = 2 *pi* r ( [tex]\frac{central\ angle}{360}[/tex].
Plugging the values
Arc length = 2 *3.14 * 6 ( [tex]\frac{270}{360}[/tex].
Arc length =37.68 ( [tex]\frac{3}{4}[/tex].
Arc length =37.68 * 0.75
Arc length XPY =28.26 m.
Therefore, Arc length XPY =28.26 m.
Answer:
The length of arc XPY=28.26 m
Step-by-step explanation:
We are given that a circle in which
Radius=6 m
Central angle made by arc XPY=[tex]360-90=270^{\circ}[/tex]
We have to find the length of arc XPY.
We know that
Arc length formula:[tex]\frac{central\;angle}{360^{\circ}}\times 2\pi r[/tex]
Substitute the value in the formula then we get
Length of arc XPY=[tex]\frac{270}{360}\times 2\times 3.14 \times 6=28.26 m[/tex] ([tex]\pi=3.14[/tex])
Hence, the length of arc XPY=28.26 m
James made a deposit in a savings account 5 years ago. The account pays 4% simple annual interest. Since then, he has earned $120 in interest. What is the current balance in his account?
A. $200
B. $600
C. $720
D. $780
Answer:
720 is correct
Find the solution.
(x - 3)(x + 2) = 0
A stemplot is one way to display these batting averages, as shown below. In this type of display, the entry 0.32|9 denotes one occurrence of the batting average _____.
0.32 | 9
0.33 | 0 1 1 3 3 3 4 4 4 6 7 8 8 8
0.34 | 0 0 1 1 2 2 2 4 4 5 6 9
0.35 | 6 8
0.36 | 6 ...?
Answer:
0.356
Step-by-step explanation:
Based on the batting averages denoted in the stemplot, the entry of 0.32|9 shows an occurrence of 0.329.
What average is shown by 0.32|9?In a stemplot, the numbers that are stems are on the left side and will be the first numbers that should be denoted.
The numbers on the right are leaf numbers and come after the stem. This means that a stemplot showing 0.32|9 is a way of writing 0.329.
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The graph of f(x) = 6(0.25)x and its reflection across the y-axis, g(x), are shown.
What is the domain of g(x)?
all real numbers
all real numbers less than 0
all real numbers greater than 0
all real numbers greater than or equal to 0
The correct answer is the first option: All real numbers.
I just did the quiz and got it right.
For all the non BrainlyPlus members
at how many points does the graph of the function y=16x^2-8x+1 intersect the x axis
Answer:aAPEX1
Step-by-step explanation:
the car was 28000 the car value go down at the rate of 7.25% what would its value be after 5 years
Casey is taking pictures outdoors. She knows that the darker it is outside, the stronger she needs to set her flash
The flash on Casey's camera needs to be set stronger when it is darker outside.
Explanation:The subject of this question is Physics. In physics, the behavior of light and the properties of a camera flash can be studied. When it is darker outside, Casey needs to set her flash stronger to compensate for the lack of natural light. This is because the flash provides an additional burst of light that illuminates the subject, making it clearer in the photo.
what is the value of the expression 10 C 6? A.210 B.720 C.5040 D.151,200
Answer: A. 210
Step-by-step explanation:
We know that the number of combinations of n things taking r at time is given by expression :-
[tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex] (1)
The given expression : [tex]^{10}C_{6}[/tex] which basically gives the number of combinations of 10 things taking 6 at a time.
Using (1) , we have
[tex]^{10}C_{6}=\dfrac{10!}{6!(10-6)!}\\\\=\dfrac{10\times9\times8\times7\times6!}{6!4!}\\\\=\dfrac{10\times9\times8\times7}{4!}\ \ [\text{Cancel }6!\text{ from numerator and denominator}]\\\\=\dfrac{10\times9\times8\times7}{4\times3\times2\times1}\\\\=210[/tex]
Hence, the correct answer is A. 210 .
In a 30-60-90 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg
Why is it important to learn, in algebra, the proper order in which to read algebraic expressions and solve algebraic equations?
Learning the proper order in which to read algebraic expressions and solve algebraic equations is important in algebra for understanding the order of operations, developing logical reasoning, and ensuring consistency in mathematical communication.
Explanation:It is important to learn the proper order in which to read algebraic expressions and solve algebraic equations in algebra for several reasons:
Order of operations: Understanding the order of operations (PEMDAS) is crucial to correctly evaluating algebraic expressions. This ensures that the operations are performed in the correct order and leads to the correct result. For example, without following the order of operations, the expression 8 + 2 x 3 could be evaluated as 10 x 3 = 30 instead of 8 + 6 = 14.Logical reasoning: Solving algebraic equations requires logical reasoning and following a step-by-step process. Learning the proper order helps develop this logical reasoning and helps students approach problems systematically. It allows them to break down complex problems into simpler steps and solve them more efficiently.Consistency and communication: Following the proper order in algebra ensures consistency in mathematical communication. It allows students and mathematicians to communicate their solutions and reasoning effectively. When everyone understands and follows the same order, they can accurately communicate and discuss algebraic expressions and equations.Find y when x equals 10 if y equals eight what x equals 20
A small business purchases a
piece of equipment for $875. After 5 years the equipment will be outdated, having no value.
(a) Write a linear equation giving the value of the equipment y in terms of the time
(b) Find the value of the equipment when X=2
(c) Estimate (to two-decimal-place accuracy) the time when the value of the equipment is $200. ...?
Using the straight-line depreciation method, the linear equation for the equipment's value over time is y = -175t + 875. After 2 years, the equipment's value is $525. To find when the equipment's value is $200, solve for t and get approximately 3.86 years.
To calculate the depreciation of the equipment using a linear equation, we'll use the straight-line depreciation method. The business purchases the equipment for $875 and it will be worthless after 5 years, so it depreciates $875 over 5 years.
Part A
To write the linear equation representing the value of the equipment y over time t, we need to find the slope (m) of the line which in this case is the annual depreciation. The slope is the change in value divided by the time, thus m = -$175/year. The initial value (intercept) is $875. The equation is:
y = -175t + 875
Part B
Substitute t = 2 into the equation to find the value of the equipment at year 2:
y = -175(2) + 875
y = -350 + 875
y = $525
Part C
We want to find the time t when the value y is $200. Substitute y = $200 into the equation:
200 = -175t + 875
-175t = 200 - 875
-175t = -675
t = [tex]\frac{-675}{-175}[/tex]
Why can't quadrilaterals have four obtuse angles?
General admission tickets to the fair cost 3.50 per person. Ride passes cost an additional 5.50 per person. Parking costs 6 dollars for the family. the total costs for ride passes and parking was 51 dollars. How many people in the family attend the fair
A manufacturer of mountain bikes has found that when 20 bikes are produced per day, the average cost is $200 and the marginal cost is $150. Based on the information, approximate the total cost of producing 21 bikes per day. ...?
what is 0.83 repeating as a fraction?
Solve for x: –4(3x – 2) = 6x + 2
A.
2003-05-01-00-00_files/i0050000.jpg
B.
2003-05-01-00-00_files/i0050001.jpg
C.
2003-05-01-00-00_files/i0050002.jpg
D.
2003-05-01-00-00_files/i0050003.jpg
Hence, the value of x is:
[tex]x=\dfrac{1}{3}[/tex]
Step-by-step explanation:We have to solve for x i..e we have to find the value of 'x' by solving this equation.
The equation is given as:
[tex]-4(3x-2)=6x+2[/tex]
firstly we will solve the bracket term as:
[tex]-4\times 3x-4\times (-2)=6x+2\\\\-12x+8=6x+2[/tex]
Now we take like terms together i..e the variable term is taken to the right hand side of the equation and the constant term is kept on the left side of the equation as:
[tex]8-2=6x+12x\\\\\\6=18x[/tex]
on dividing both side of the equation by 18, we obtain:
[tex]x=\dfrac{6}{18}\\\\x=\dfrac{1}{3}[/tex]
Hence, the value of x is:
[tex]x=\dfrac{1}{3}[/tex]
Answer:
B
Step-by-step explanation:
A water cooler can hold 50 pt of water. About how many liters of water can it hold? (1 L ≈ 1.06 qt)
23.6 L 26.5 L 94.3 L 106.0 L
A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axis that lies in the plane of the plate, passes through the center of the plate, and is parallel to the side with length b.
The moment of inertia of the thin rectangular sheet of metal about the specified axis is[tex]\( \frac{Ma^2}{4} + \frac{Mb^2}{12} \).[/tex]
To find the moment of inertia I of the thin rectangular sheet of metal about an axis passing through its center and parallel to the side with length b, we can use the parallel axis theorem.
This theorem states that the moment of inertia about any axis parallel to the axis passing through the center of mass can be found by adding the moment of inertia about the center of mass and the product of the mass and the square of the perpendicular distance between the two axes.
The moment of inertia of a thin rectangular plate about its center and perpendicular to its plane is given by:
[tex]\[ I_c = \frac{M}{12}(a^2 + b^2) \][/tex]
where M is the mass of the plate, a and b are the lengths of the sides of the rectangle.
Now, let's denote d as the perpendicular distance between the axis passing through the center and the axis parallel to the side with length b. Since the axis is passing through the center of the rectangle, d is half the length of side a, so [tex]\( d = \frac{a}{2} \)[/tex].
Using the parallel axis theorem, the moment of inertia about the desired axis is:
[tex]\[ I = I_c + Md^2 \][/tex]
[tex]\[ I = \frac{M}{12}(a^2 + b^2) + M\left(\frac{a}{2}\right)^2 \][/tex]
[tex]\[ I = \frac{M}{12}(a^2 + b^2) + \frac{M}{4}a^2 \][/tex]
[tex]\[ I = \frac{Ma^2}{12} + \frac{Mb^2}{12} + \frac{3Ma^2}{12} \][/tex]
[tex]\[ I = \frac{Ma^2}{4} + \frac{Mb^2}{12} \][/tex]
Thus, the moment of inertia of the thin rectangular sheet of metal about the specified axis is[tex]\( \frac{Ma^2}{4} + \frac{Mb^2}{12} \).[/tex]
1. 8q + 6; q = 2
10
14
20
22
2. 9 + 4g; g = −3
–3
3
21
13
3. 7x – 7; x = 4
0
21
35
28
4. 10 – 3.2n; n = 2
6.8
3.6
13.2
16.4
5. 12p + 4; p = 1.5
14
16
18
22
For questions 6–10, solve the equation using number sense.
6. 5w + 10 = 40
6
10
30
50
7. 4y – 12 = 60
12
18
48
72
8. 10k + 5 = 65
6
7
60
70
9. 2b – 15 = 33
4
9
24
48
10. 3d + 18 = 21
–1
1
3
13
help
a table that originally cost $196 is on sale for $160.00. What is the percent of decrease, rounded to the nearest tenth?
A company has started selling a new type of smartphone at the price of $120 - 0.1x where x is the number of smartphones manufactured per day. The parts for each smartphone cost $60 and the labor and overhead for running the plant cost $4000 per day. How many smartphones should the company manufacture and sell per day to maximize profit?
To maximize profit, derive the profit equation ((120 - 0.1x) * x - (60x + 4000)) and set it to zero to find the critical points. These points will dictate the number of smartphones the company needs to manufacture and sell each day.
Explanation:The subject of this question is the maximization of profit, which is a concept in economic mathematics. To maximize the profit, you'll need to determine the number of smartphones that the company should produce and sell each day.
The profit is the revenue (the money earned from selling goods) minus the costs. Revenue is given by the equation R = (120 - 0.1x) * x, and the total cost is given by the equation C = 60x + 4000, where x is the number of smartphones produced.
So, the profit P becomes P = R - C = (120 - 0.1x) * x - (60x + 4000). To maximize this profit, we'd take the derivative of P in terms of x and set it equal to zero to find the critical points. After finding the critical points, we then test these values back in the profit equation to find which gives the highest value and hence maximizes the profit.
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The shop charges $60 per hour and 7% sales tax on parts (no tax on labor). The total cost of the repair is $180.80. A. True B. False The statement is False.
Round 7.832 to the nearest tenth
A classmate claims that having no slope and having a slope of 0 are the same. Is your classmate correct? Explain. ...?
A total of 376 tickets were sold for the school play. they were either adult tickets or student tickets. the number of student tickets sold was three times the number of adult tickets sold. how many adult tickets were sold?
Final answer:
Using algebra, we set up equations based on the information given: the number of student tickets is three times the number of adult tickets, and the total number of tickets is 376. Solving for the number of adult tickets, we find that 94 adult tickets were sold.
Explanation:
The question asks us to figure out how many adult tickets were sold for the school play when a total of 376 tickets were sold, and student tickets sold were three times the number of adult tickets.
Let's denote the number of adult tickets sold as A and the number of student tickets sold as S. According to the problem, S = 3A. We are also told that the total number of tickets sold is 376, so A + S = 376.
Substituting the first equation into the second one, we get A + 3A = 376. Simplifying this equation, 4A = 376. Dividing both sides by 4, A = 94. Therefore, 94 adult tickets were sold.
Final answer:
As per the values, 94 adult tickets were sold.
Explanation:
The question asks us to determine how many adult tickets were sold for a school play, given a total number of tickets and a ratio of student tickets to adult tickets.
To solve this problem, let's define adult tickets as x and student tickets as 3x, since there are three times as many student tickets as adult tickets.
The total tickets sold is 376, therefore the equation we need to solve is:
x + 3x = 376
Combining like terms, we get:
4x = 376
Dividing both sides by 4, we find that:
x = 94
Therefore, 94 adult tickets were sold.
Find the dimensions of a rectangle with area 343 m2 whose perimeter is as small as possible.
For a rectangle with a given area, the smallest possible perimeter is achieved when the rectangle is a square. Hence, for a rectangle with an area of 343 m², the dimensions that give the smallest perimeter are approximately 18.5 m x 18.5 m.
Explanation:The subject of this question is related to the optimization problems in Calculus. Given that the area of a rectangle is 343 m², we are looking for the smallest possible perimeter. The area of a rectangle can be defined as the product of its length and width (l*w), and the perimeter is defined as the sum of all sides (2l + 2w).
According to the properties of rectangles, a rectangle will have the smallest possible perimeter if it is a square, because rectangles with the same area have larger perimeters as their shapes become more elongated.
So, if the rectangle is a square, its area is side² or s². Given that the area is 343 m², s² = 343, thus the side s equals the square root of 343, which is approximately 18.5202591775 meters. Therefore, the dimensions of the rectangle with the smallest possible perimeter are approximately 18.5 m × 18.5 m.
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A cable 20 feet long connects the top of a flagpole to a point on the ground that is 16 feet from the base of the pole. How tall is the flagpole?
The height of the flagpole is 12 feet.
To determine the height of the flagpole, we can use the Pythagorean theorem.
Given: The length of the cable (hypotenuse) is 20 feet.The distance from the point on the ground to the base of the flagpole (one leg) is 16 feet.Let the height of the flagpole be h (the other leg).Using the Pythagorean theorem:
c² = a² + b²
Here, c = 20 feet (length of cable), a = 16 feet (distance from flagpole base to ground point), and h = b (height of the flagpole).
Therefore, we have:
202 = 162 + h²
400 = 256 + h²
To find h, subtract 256 from 400:
400 - 256 = h²
144 = h²
h = √144 = 12.