It’s A the region one
Answer:
A). when the region is divided into a greater number of rectangles.
Step-by-step explanation:
This forms the basics of integration.
Integration can be use to calculate areas under the curve. To find the area under the curve we try to approximate the area under the curve by using rectangles. When we increased the number of rectangles of equal width of the rectangles, a better approximation of the area is obtained. We then find the area of each infinitesimally small rectangle and then integrate by taking two limits, the upper limit and the lower limit.
PLEASE HELP 20! POINTS
Given f(x)=4x^2+6x and g(x)=2x^2+13x+15, find(f/g)(x) . Show your work
X1= -3/2
X2= 0
F(x)=4x^2+6x
To find X-intercept/zero, substitute f(x)=0
0=4x^2+6x
Move the constant to the right
4x^2+6x=0
Factor out 2x from the expression
2x(2x+3)=0
Divide both sides of the equation
2x(2x+3)/2=0/2
X(2x+3)=0
When the product of factors equals 0, at least one factor is 0.
X=0
2x+3=0
Next you solve for X by moving the constant to the right
2x=-3
Then divide both sides by 2
X=-3/2
Hope this answers your question.
The result is (f/g)(x) = (4x² + 6x) / (2x² + 13x + 15).
To find (f/g)(x) for the given functions f(x) = 4x² + 6x and g(x) = 2x² + 13x + 15, you need to divide the function f(x) by g(x).
Step-by-Step Solution:
Write down the functions: f(x) = 4x² + 6x and g(x) = 2x² + 13x + 15.Express the division of these two functions: (f/g)(x) = (4x² + 6x) / (2x² + 13x + 15).Simplify the expression if possible by factoring the numerator and the denominator.In this case, neither the numerator nor the denominator can be factored further in a way that simplifies the fraction: 4x² + 6x and 2x² + 13x + 15 do not have common factors.Thus, the simplest form of (f/g)(x) is: (f/g)(x) = (4x² + 6x) / (2x² + 13x + 15).Therefore, (f/g)(x) stands as (4x² + 6x) / (2x² + 13x + 15).
please can someone answer this.
Answer:
• x = -4, x = 0, x = 1
Step-by-step explanation:
x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)
The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)
Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.
___
Of course, your graphing calculator can answer this almost as quickly.
When the two equations are graphed on a coordinate plane, they intersect at two points.
y=3x^2+4x+3
y=−2x+3
What are the points of intersection?
Enter your answers in the boxes.
(_,_) and (_,)
Answer:
(-2, 7) and (0, 3)
Step-by-step explanation:
A graph of the two equations clearly shows the points of intersection.
The equations are conveniently graphed by a graphing calculator (as here) or by a spreadsheet program, on-line graphing tool, or graphing app.
___
Alternate solution
You can set the two values of y equal to each other, then solve for x.
3x^2 +4x +3 = -2x +3
3x^2 +6x = 0 . . . . . subtract the right side expression
3(x)(x +2) = 0 . . . . . factor the equation
x = 0, x = -2 . . . . . . solutions that make the factors zero
y = -2{0, -2} +3 . . . . substitute the values of x into the expression for y
y = {0, 4} +3
y = {3, 7} . . . . . . . . . the values of y corresponding to x = {0, -2}
Then the points of intersection are (0, 3) and (-2, 7).
The difference of two numbers is 15, and their quotient is 6. what are the two numbers
the two numbers are 18 and 3
Which of the following points is a solution of y > |x| + 5?
A. (0,5)
B. (1,7)
C. (7,1)
Answer:
B. (1,7)
Step-by-step explanation:
Answer is B. (1,7)
If x = 1 then
y > 1 + 5
7 > 6
Answer:
(1 , 7) is a solution of y > IxI + 5 ⇒ answer B
Step-by-step explanation:
* Lets revise the absolute value
- IxI = positive value
- IxI can not give negative value
- The value of x could be positive or negative
* Lets solve the problem
∵ y > IxI + 5
∴ y > x + 5 OR y > -x + 5
- Lets check the answers
∵ y > 0 + 5 ⇒ y > 5
- But y = 5, and 5 it is not greater than 5 and there is no difference
between the two cases because zero has no sign
∴ (0 , 5) not a solution
∵ y > 1 + 5 ⇒ y > 6
- Its true y = 7 and 7 is greater than 6
∵ y > -1 + 5 ⇒ y > 4
- Its true y = 7 and 7 is greater than 4
∴ (1 , 7) is a solution
∵ y > 7 + 5 ⇒ y > 12
- But y = 1 and 1 is not greater than 12
∵ y > -7 + 5 ⇒ y > -2
- Its true y = 1 and 1 is greater than -2
* we can not take this point as a solution because it is wrong
with one of the two cases
∴ (7 , 1) is not a solution
What is the y-intercept of the function f(2)=4-5x?
-5
-4
4
5
C. 4
First, rearrange the equation into slope intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. You get y = -5x + 4. This means the y-intercept is 4.
For this case we have a function of the form [tex]y = f (x)[/tex]
Where:
[tex]f (x) = 4-5x[/tex]
To find the y-intercept of the function we must do x = 0.
Then, replacing:
[tex]f (0) = 4-5 (0)\\f (0) = 4-0\\f (0) = 4[/tex]
So, the y-intercep of the function is 4
ANswer:
4
Option C
Please help! Limited time
Number 2,3,5 are true
1) Given: mLHE=84°
Find: m∠EYL.
2)Given: m∠EYL=72°
Find: m arc EHL, m arc LVE
Answer:
Part 1) The measure of angle EYL is [tex]96\°[/tex]
Part 2) The measure of arc EHL is [tex]108\°[/tex] and the measure of arc LVE is [tex]252\°[/tex]
Step-by-step explanation:
we know that
The measurement of the outer angle is the semi-difference of the arcs which comprises
Part 1)
Let
x------> the measure of arc LHE
y----> the measure of arc LVE
we know that
[tex]x+y=360\°[/tex]
[tex]x=84\°[/tex]
Find the value of y
[tex]y=360\°-84\°=276\°[/tex]
Find the measure of angle EYL
[tex]m<EYL=\frac{1}{2} (y-x)[/tex]
substitute the values
[tex]m<EYL=\frac{1}{2}(276\°-84\°)=96\°[/tex]
Part 2)
Let
x------> the measure of arc EHL
y----> the measure of arc LVE
we know that
[tex]x+y=360\°[/tex]
[tex]x=360\°-y[/tex] -----> equation A
[tex]m<EYL=72\°[/tex]
[tex]m<EYL=\frac{1}{2} (y-x)[/tex]
substitute
[tex]72\°=\frac{1}{2} (y-x)[/tex]
[tex]144\°=(y-x)[/tex]
[tex]x=y-144\°[/tex] --------> equation B
equate equation A and equation B and solve for y
[tex]360\°-y=y-144\°[/tex]
[tex]2y=360\°+144\°[/tex]
[tex]2y=504\°[/tex]
[tex]y=252\°[/tex]
Find the value of x
[tex]x=252\°-144\°=108\°[/tex]
therefore
The measure of arc EHL is [tex]108\°[/tex]
The measure of arc LVE is [tex]252\°[/tex]
A circle is a curve sketched out by a point moving in a plane. The measure of the arcEHL and arcLVE are 108° and 252° respectively.
What is a circle?A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.
As we can see in the image attached below, the radius of the circle is OE and OL while there is two tangent to the circle Ey and LY. Therefore, the measure of the ∠OEY and ∠OLY is 90°.
A.)
The sum of the angles of a quadrilateral is 360°.
As it is mentioned in the problem the measure of the angle made by arc LHE is 84° which means the measure of ∠EOL is 84°. Therefore, the sum of all the angles can be written as,
[tex]\text{Sum of angles} = 360^o\\\\\angle OEY + \angle OLY + \angle EOL + \angle EYL = 360^o\\\\90^o+90^o+84^o +\angle EYL = 360^o\\\\\angle EYL = 96^o[/tex]
B.)
The sum of the angles of a quadrilateral is 360°.
As it is mentioned in the problem the measure of ∠EYL is 72°. Therefore, the sum of all the angles can be written as,
[tex]\text{Sum of angles} = 360^o\\\\\angle OEY + \angle OLY + \angle EOL + \angle EYL = 360^o\\\\90^o+90^o+ \angle EOL +72^o = 360^o\\\\ \angle EOL= 108^o\\\\ \rm arc EHL=108^o[/tex]
Since a complete circle measures 360°, therefore, the sum of the angles made by arc EHL and arc LVE can be written as,
arcEHL + arcLVE = 360°
108° + arcLVE = 360°
arcLVE = 252°
Thus, the measure of the arcEHL and arcLVE are 108° and 252° respectively.
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What is the solution with steps?
2cosx=-sin^2x
Try this option, the answer is marked with red colour.
which fraction is equivalent to 1 use the number line to help answer the question
10/10 it simplifies to 1
Answer: 10/10
Step-by-step explanation:
10 divided by 10 is 1.
The graph shown is only a small part of a larger graph. The table shows two additional points that are part of the function but are not shown on the graph.
Do either of the points prevent the function from being a linear function?
A. No, both points indicate this function is linear because the x and yvalues can be substituted into the equation y=mx+b to create a true equation.
B. Yes; Point A prevents this function from being linear because (-12, 16) would only satisfy the function if the function was exponential.
C. Yes; Point B prevents this function from being linear because (12, -16) would only satisfy a function with a variable rate of change.
D. No; both points indicate this function is linear because they both follow the pattern of the line.
Answer:
C. Yes; Point B prevents this function from being linear because (12, -16) would only satisfy a function with a variable rate of change.
Step-by-step explanation:
Point B is not on the line shown in the graph, so the function would have to be non-linear to include point B.
Answer this question please; number 5... show all work thank you
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
Explain why x = 3 makes 4x − 1 ≤ 11 true but not 4x − 1 < 11.
In technical translation, 4 x 3 - 1 is less than or equal to 11 (it's equal). 4 x 3 - 1 < 11 is not true because 11 is not less than 11.
Hope this helps!
Explaining why x = 3 satisfies 4x − 1 ≤ 11 but not 4x − 1 < 11:
When x = 3, we can evaluate the inequalities:
For 4x − 1 ≤ 11: 4(3) - 1 ≤ 11, which simplifies to 12 ≤ 11, making it true.
For 4x − 1 < 11: 4(3) - 1 < 11, which simplifies to 12 < 11, making it false.
Therefore, when x = 3, the first inequality is true while the second one is false.
Derive the quadratic formula from the standard form (ax2 + bx + c = 0) of a quadratic equation by following the steps below.
1. Divide all terms in the equation by a.
2. Subtract the constant (the term without an x) from both sides.
3. Add a constant (in terms of a and b) that will complete the square.
4. Take the square root of both sides of the equation.
5. Solve for x.
Answer:
The result is the well-known quadratic formula: x = (-b±√(b²-4ac))/(2a)
Step-by-step explanation:
Start with the standard form quadratic equation:
ax² +bx +c = 0
1. Divide by a
x² +(b/a)x +(c/a) = 0
2. Subtract the constant
x² +(b/a)x = -(c/a)
3. Complete the square
x² +(b/a)x + (b/(2a))² = (b/(2a))²-(c/a)
(x +b/(2a))² = (b²-4ac)/(2a)²
4. Take the square root
x +b/(2a) = ±√(b²-4ac)/(2a)
5. Subtract the constant on the left to get x by itself
x = (-b±√(b²-4ac))/(2a)
Final answer:
The quadratic formula, which provides the solution to the standard quadratic equation ax² + bx + c = 0, is derived through a series of algebraic manipulations, including dividing by a, completing the square, taking the square root, and solving for x.
Explanation:
Derivation of the Quadratic Formula
The objective is to derive the quadratic formula from the standard quadratic equation (ax² + bx + c = 0). Following the given steps:
Divide all terms by a: x² + (b/a)x + (c/a) = 0.Subtract c/a from both sides to isolate the x terms: x² + (b/a)x = -c/a.Add the square of half the coefficient of x to both sides to complete the square: (b/2a)². Now the equation is x² + (b/a)x + (b/2a)² = (b/2a)² - c/a.Take the square root of both sides: x + (b/2a) = ±√(b² - 4ac)/2a.Solving for x leads to the quadratic formula: x = (-b ± √(b²- 4ac))/(2a).Someone help me understand how to do this
Answer:
6.7 cm
Step-by-step explanation:
To make use of the Law of Sines for finding b, you need to know the missing angle B. Since the sum of the angles of a triangle is 180°, you can find angle B as ...
B = 180° -82° -55° = 43°
Now, you put the numbers you know into the formula given and solve for b.
sin(A)/a = sin(B)/b
sin(55°)/(8 cm) = sin(43°)/b
Cross multiplying gives ...
b·sin(55°) = (8 cm)·sin(43°)
and dividing by the coefficient of b gives you ...
b = (8 cm)·sin(43°)/sin(55°) ≈ 6.7 cm
Answer:
6.7 cm
Step-by-step explanation:
Given: m KP =2m IP , m IVK =120° Find: m∠KJL.
Will give 99 points!!!
Answer:
KJL = 40 degrees
Step-by-step explanation:
KJL = 1/2*( arc KP - arc IP)
arc IPK=360-120=240
KP=2(IP)
Kp=2x, IP = x
3x=240, x=80
KP=160
IP=80
KJL=(160-80) / 2 = 40 degrees
Answer:
40°
Step-by-step explanation:
What is the degree of x?
Subtract the smaller angle from the larger angle and divide by 2.
66 -14 = 52
52/2 = 26
x = 26
Find the value of x in the triangle above
Answer:
62 degrees
Step-by-step explanation:
degrees in a triangle: 180
this triangle is isosceles, so remaining 2 angles must be congruent
2x+56=180
2x=124
x=62
What’s the indicated angle (also can you maybe show me how to do it please)
Step-by-step explanation:
it is solved in the diagram
Solve the system below for m and b.
1239 = 94m + b
810 = 61m + b
Answer:
m=13 b=17
Step-by-step explanation:
Answer:
m=13 b=17
hope this helps
Two tracking stations are on the equator 148 miles apart. A weather balloon is located on a bearing of N41°E from the western station and on bearing of N21°E From the eastern station. How far is the balloon from the western station? Round to the nearest mile from the nearest station. A 404 mil B 382 mi C 413 mil D 373 mi
Answer:
A 404 mi
Step-by-step explanation:
If we designate the points of the triangle A, B, and C for the locations of the western station, eastern station, and balloon, respectively, we have the following:
∠CAB = 90° - 41° = 49°
∠CBA = 90° + 21° = 111°
∠ACB = 41° -21° = 20°
side "c" (opposite ∠ACB) is 148 miles
The distance we're asked to find is AC = b, the longest side of the triangle. The law of sines tells us ...
b/sin(B) = c/sin(C)
b = c·sin(B)/sin(C) = (148 mi)·sin(111°)/sin(20°) ≈ 403.98 mi ≈ 404 mi
Using trigonometry and the law of sines, the distance from the balloon to the western station is approximately 373 miles.
Explanation:This is a problem involving trigonometry, particularly the use of the law of sines. The two tracking stations and the balloon form a triangle. The angle at the western station is 41°, the angle at the eastern station is (180 - 21 - 41) = 118°, and the distance between the two stations (the side opposite to the 41° angle) is 148 miles. According to the Law of Sines, the ratio of each side of the triangle to the sine of its opposite angle is constant. Thus, we can set up the equation sin(41°) / x = sin(118°) / 148 miles, where x represents the distance from the balloon to the western station. Solving for x gives us approximately 373 miles.
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a ball is thrown with a slingshot at a velocity of 110ft/sec at an angle of 20 degrees above the ground from a height of 4.5 ft. approximentaly how long does is take for the ball to hit the ground. Acceleration due to gravity is 32ft/s^2
Answer:
[tex]t=2.47\ s[/tex]
Step-by-step explanation:
The equation that models the height of the ball in feet as a function of time is
[tex]h(t) = h_0 + s_0t -16t ^ 2[/tex]
Where [tex]h_0[/tex] is the initial height, [tex]s_0[/tex] is the initial velocity and t is the time in seconds.
We know that the initial height is:
[tex]h_0 = 4.5\ ft[/tex]
The initial speed is:
[tex]s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s[/tex]
So the equation is:
[tex]h (t) = 4.5 + 37.62t -16t ^ 2[/tex]
The ball hits the ground when when [tex]h(t) = 0[/tex]
So
[tex]4.5 + 37.62t -16t ^ 2 = 0[/tex]
We use the quadratic formula to solve the equation for t
For a quadratic equation of the form
[tex]at^2 +bt + c[/tex]
The quadratic formula is:
[tex]t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}[/tex]
In this case
[tex]a= -16\\\\b=37.62\\\\c=4.5[/tex]
Therefore
[tex]t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}[/tex]
[tex]t_1=-0.114\ s\\\\t_2=2.47\ s[/tex]
We take the positive solution.
Finally the ball takes 2.47 seconds to touch the ground
please help, i have no idea how to do this
Answer:
8 square units
Step-by-step explanation:
The figure is a trapezoid. The area of it is given by the formula ...
A = (1/2)(b1 +b2)h
where b1 and b2 are the lengths of the parallel bases and h is the distance between them.
Your figure shows the base lengths to be 5 and 3, and their separation to be 2. Filling the numbers in the formula, we have ...
A = (1/2)(5 +3)(2) = (1/2)(8)(2) = 4·2 = 8
The area of the figure is 8 square units.
_____
The right-pointing arrows on the horizontal lines identify those lines as being parallel. The right-angle indicator and the 2 next to the dotted line indicate the perpendicular distance between the parallel lines is 2 units.
Amanda bought $500 bond with a 6% coupon that matures in 20 years. What are amanda's total annual earnings for this bond?
A.) $30.00
B.) $6.00
C.) $50.00
D.) $60.00
Answer:
it is $30.00
Step-by-step explanation:
How do I find the diagonal length?
B. 16 Inches The original length was 12 inches but since you are cutting across the cheese it will be longer. Since you are cutting across that means the width of the cheese will come into the equation as well.
Just add 12 and 4.
Check the picture below.
Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such that f '(c) = 0. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) c = Based off of this information, what conclusions can be made about Rolle's Theorem? This contradicts Rolle's Theorem, since f is differentiable, f(−27) = f(27), and f '(c) = 0 exists, but c is not in (−27, 27). This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−27, 27). This contradicts Rolle's Theorem, since f(−27) = f(27), there should exist a number c in (−27, 27) such that f '(c) = 0. This does not contradict Rolle's Theorem, since f '(0) does not exist, and so f is not differentiable on (−27, 27). Nothing can be concluded.
I guess the function is [tex]f(x)=9-x^{2/3}[/tex]. Then [tex]f(-27)=0[/tex] and [tex]f(27)=0[/tex].
The derivative is [tex]f'(x)=-\dfrac23 x^{-1/3}[/tex], but there is no [tex]c[/tex] such that
[tex]-\dfrac23c^{-1/3}=0[/tex]
This doesn't contradict Rolle's theorem because [tex]f'(0)[/tex] does not exists. In other words, [tex]f[/tex] is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")
The function f(x) = 9 - x²/3 is even, and its derivative f'(c) equals to zero at c=0, which lies within the interval (-27, 27). Therefore, it does not contradict Rolle's theorem.
Explanation:The function in question is f(x) = 9 - x²/3. When we substitute x with -27 and 27, we get f(-27) = 9 - ((-27)²/3) = -243 and f(27) = 9 - (27²/3) = -243. This confirms that the function is even as f(-27) = f(27).
To find the critical values, we'll take the derivative of the function, which gives us f'(x) = -2x/3. We set f '(c) = 0, solving for c, and determine c = 0. Rolle's Theorem states that if a function is continuous on a closed interval [a, b], differentiable on the open interval (a, b), and f(a) = f(b), then there exists at least one c in the interval (a, b) such that f '(c) = 0. With f(-27) = f(27) and the derivative proving to be zero at c=0 (which is inside the interval (-27,27)) this does not contradict Rolle's theorem.
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Pam invested money into a small stock market account. After several years of continued growth, the table below shows how much her investment earned.
Investment Earnings
Years 1 2 3 4 5
Money Earned $31.25 $125 $500 $2,000 $8,000
Which of the following functions would best model the data above?
Answer:
Exponential
Step-by-step explanation:
i took that
The graph of the function y = cos(2x) is shown below.
Answer:D pie
Step-by-step explanation:
You get 2pie/2 cancel out you get pie
The period of y=cos(2x) is π, so the frequency is 1/π.
The key features of the graph are:
Amplitude: The amplitude of the graph is 1, which means the function oscillates between −1and 1.
Period: The period of the graph is π, which means the function completes one cycle every πunits on the x -axis. This is because the frequency of the function is 2, which means it completes two cycles for every 2π units on the x -axis.
Midline: The midline of the graph is y=0. This is because the function is neither shifted up nor down.
Extrema: The graph has maxima at x=2kπ for any integer k, and minima at x=2(2k+1)πfor any integer k.
The graph of the function y=cos(2x). The frequency of a trigonometric function is the reciprocal of its period. The period of y=cos(2x) is π, so the frequency is 1/π.
A cone shaped block that has a slant height of 6 inches and has a radius of 4 inches . How many square inches of paper would it take the cover the surface?
Answer:
[tex]T.S.A=40\pi in^2[/tex]
Step-by-step explanation:
The total surface area of the cone is
[tex]\pi r^2+\pi rl[/tex]
The radius of the cone is 4 inches.
The slant height of the cone is l=6 inches.
We substitute these values into the formula to obtain;
[tex]T.S.A=\pi \times (4)^2+\pi \times 4\times6[/tex]
[tex]T.S.A=16\pi+24\pi[/tex]
[tex]T.S.A=40\pi in^2[/tex]
Or
[tex]T.S.A=125.7in^2[/tex] to the nearest tenth.
Which function has a vertex at (2, 6)? f(x) = 2|x – 2| – 6 f(x) = 2|x – 2| + 6 f(x) = 2|x + 2| + 6 f(x) = 2|x + 2| – 6
Answer: Second Option
[tex]f (x) = 2 | x-2 | +6[/tex]
Step-by-step explanation:
For a function of the form:
[tex]f (x) = a | x-h | + k[/tex]
The vertex is always at the point (h, k)
In this case we know that the vertex is in the point (2, 6) and [tex]a = 2[/tex]
This means that
[tex]h = 2\\\\k = 6[/tex]
Therefore the function that has its vertivce in the point (2, 6) is:
[tex]f (x) = 2 | x-2 | +6[/tex]
The correct answer is the second