Which table represents a linear function?

Final answer:

The ratio of cups of rice to cups of water in the recipe is 2 to 3, which can also be written as 2/3.

Explanation:

The question asks us to find the ratio of cups of rice to cups of water. The recipe provided uses 2 cups of rice and 3 cups of water. To find this ratio, we simply compare the number of cups of rice to the number of cups of water and write it as a fraction or a division problem.

In this case, the ratio is:

2 cups of rice : 3 cups of water

Which we can also write as 2/3 or say that for every 2 cups of rice, there are 3 cups of water.

Sean used 3/4 cups of sugar to make 12 brownies. By dividing 3/4 by 12, we find that there is 1/16 cup of sugar in each brownie.

The subject of this problem is mathematics, specifically, it's about division in the context of fractions. In this scenario, Sean used 3/4 cups of sugar to make a dozen (12) brownies. To determine the amount of sugar in each brownie, we can divide the total amount of sugar by the total number of brownies.

So, 3/4 divided by 12 is 1/16. This means that there is 1/16 cup of sugar in each brownie.

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For anyone who still needs it, the answer is 1:3.1264.

Answer:

[tex]\left \{ 2,\frac{5}{4} \right \}[/tex]

Step-by-step explanation:

We know that for equation of type [tex](x-a)(x-b)=0[/tex], solutions are [tex]x=a\,,\,x=b[/tex] as both points x = a and x = b satisfy the equation (x-a)(x-b)=0

Given : equation (2x−4)(4x−5)=0

To find  : Solution set of this equation .

Solution :

On dividing this equation by 2 and 4, we get

[tex]\left ( \frac{2x-4}{2} \right )\left ( \frac{4x-5}{4} \right )=0\\\left ( x-2 \right )\left ( x-\frac{5}{4} \right )=0[/tex]

On comparing equation [tex]\left ( x-2 \right )\left ( x-\frac{5}{4} \right )=0[/tex] with [tex]\left ( x-a \right )\left ( x-b \right )=0[/tex], we get [tex]a=2\,,\,b=\frac{5}{4}[/tex]

Therefore, solution set is [tex]\left \{ 2,\frac{5}{4} \right \}[/tex]

Final answer:

The solution set to the equation (2x−4)(4x−5) = 0 is {2, 5/4}.

Explanation:

The equation (2x−4)(4x−5) = 0 represents a quadratic equation. To solve this equation, we can set each factor equal to zero and solve for x. So we have:

2x - 4 = 0, which gives x = 2

4x - 5 = 0, which gives x = 5/4

Therefore, the solution set to the equation is {2, 5/4}.

The answer is:  [C]:  " f(x) = 0.7(5)ˣ " .

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 Explanation:

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From all the answer choices given; 

Answer choice:  [C]:  "  f(x) = 0.7 (5)ˣ " ;  is the answer choice with a "positive number"; {which is then multiplied by: [ a "positive whole number" or a "positive number greater than "1"; that is raised to a "positive variable"] .

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How I solved this:  Further Explanation:

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A positive number multiplied by a {"number less than 1; raised to "x"] would result in increasingly lower values as "x" increases. Same with "raised to "negative x" {refer to "Answer choice [D]" }.

Answer:

The answer is:  [C]:   f(x) = 0.7(5)ˣ

Step-by-step explanation:

we know that

The Law of Syllogism says that if the following two statements are true:

(1) If p -------> then q .

(2) If q-------> then r .

Then we can derive a third true statement:

(3) If p--------> then r .

In this problem

(1) If a triangle is an isosceles triangle, then it has two sides of equal length

(2) If a triangle has two sides of equal length, then it has two angles of equal measure

Let

p-------> the statement " an isosceles triangle"

q--------> the statement " has two sides of equal length"

r--------->  the statement "has two angles of equal measure"

Then (1) and (2) can be written

1) If p , then q .

2) If q , then r .

So, by the Law of Syllogism, we can deduce

3) If p , then r

or

If a triangle is an isosceles triangle, has two angles of equal measure

therefore

the answer is

The argument is valid by the law of syllogism.

2 plates can be glazed and 0.50 glaze will be left over.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

for example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

Total bowls= 5

fraction of pint to glaze bowl= 7/8

So, pint to glaze 5 bowls

= 5 bowls x  7/8 of a pint

=  4.375 pints

and, left over after glazing the bowls.

= 6 pints - 4.375pints

= 1.625

Now, we know to glaze plate pint used= 9/16

So, number of plates will be  = 1.625 x 16/9

                                                 = 2.88 plates

Thus, we can only glaze 2 plates.

Also,  glaze left over

= 1.625 - 1.125

= 0.50 glaze left over.

Learn more about unitary method here:

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Answer:

infinite number of values in domain and range

Step-by-step explanation:

need points for finals

For a function of the form f(x) = m, the domain is all real numbers and the range is the single real number m. Thus, there are no values that are in both the domain and the range.

In a function of the form f(x) = m, where m is a real number greater than 0, the domain encompasses all real numbers since there are no restrictions on any values of x that would make the function undefined. Since the function gives the same result (m) regardless of what x is, f(x) remains constant. Thus, the range only contains one real number, which is m.

The correct option from the ones given, therefore, is: There are no values that are in the domain and the range. This is because the domain contains all real numbers, while the range contains only one number (m), and these sets do not overlap.

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Given fx (x) = λe^λx

Fx (x) = 1 – e^-λx      x…0

To find distribution of Min (X1,….Xn)

By applying the equation

fx1 (x) = [n! / (n – j)! (j – 1)!][F(x)]^j-1[1-F(x)]^n-j f(x)

For minimum j = 1

[Min (X1,…Xn)] = [n!/(n-1)!0!][F(x)]^0[1-(1-e^-λx)]^n-1λe^-λx

= ne^[(n-1) λx] λe^(λx)

= nλe^(-λx[1+n-1])

= nλe^(-nλx)

The distribution of min(x1, . . . , xn) for independent exponential random variables with common parameter λ is given by the exponential distribution with parameter λ*n.

The distribution of min(x1, . . . , xn) for independent exponential random variables with common parameter λ is given by the exponential distribution with parameter λ*n.

To determine this, we can use the fact that the minimum of a set of random variables is less than or equal to a given value if and only if each of the individual random variables is less than or equal to that value. So, we can find the cumulative distribution function (CDF) of the minimum by raising the CDF of each individual exponential random variable to the power of the number of variables in the minimum. The resulting distribution is an exponential distribution with parameter λ*n.

1. any number times2 then subtracted by the same number can't = 0 , so it is Null Set

2. 2^2 = 4 +12 = 16, 8*2 = 16, answer is 2

I did this question already. The answer is 2

1. 2 and 7 are equal

2. angle 1 = 68 degrees

3. 1st answer

Answer: Answer is 1

Step-by-step explanation:

edge

Answer:-(2a,a) coordinates he should assign to the fourth vertex of the parallelogram.

Explanation:-

Let ABCD be the vertices of the given parallelogram such that A=(0.,0) , B=(a,0) , C(x,y) and D=(a,a)

Construct the diagonals AC and BD of parallelogram ABCD .

We know that diagonals of a parallelogram bisect each other.

⇒ mid point of AC= mid point of BD...(1)

Mid point of BD[tex]=(\frac{a+a}{2},\frac{0+a}{2})=(\frac{2a}{2},\frac{a}{2})=(a,\frac{a}{2})[/tex]........(2)

Mid point of AC[tex]=(\frac{0+x}{2},\frac{0+y}{2})=(\frac{x}{2},\frac{y}{2})[/tex]......(3)

Substitute (2) and (3) in (1), we get

[tex](\frac{x}{2},\frac{y}{2})=(a,\frac{a}{2})\\\Rightarrow\frac{x}{2}=a;\frac{y}{2}=\frac{a}{2}[/tex]

 [tex]\Rightarrow\ x=2a\ and\ y=a[/tex]

⇒C=(2a,a)

⇒ (2a,a) coordinates he should assign to the fourth vertex of the parallelogram.

The statement is false. The domain of the composite function (f◦g)(x) is not always the same as the domain of g(x). It includes only the values of x for which both g(x) and f(g(x)) are defined.

The statement is False. The domain of the composite function (f◦g)(x) is not always the same as the domain of g(x). In a composite function (f◦g)(x), the domain includes only the values of x for which both g(x) and f(g(x)) are defined.

For example, if g(x) = sqrt(x) and f(x) = 1/x, the domain of g(x) would be all real numbers x ≥ 0, but the domain of the composite function (f◦g)(x) = 1/sqrt(x) would be x > 0, because 1/sqrt(x) isn't defined for x = 0.

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Answer:

D

Step-by-step explanation:

Answer:

Sample Answer:

When a linear function is expressed in different forms, its slope and y-intercept remain the same. The slope from the equation is -1, and the y-intercept from the equation is 3. The slope from the table is -1, and the y-intercept from the table is −3. These are not the same functions.

Step-by-step explanation:

Answer:

When a linear function is expressed in different forms, its slope and y-intercept remain the same. The slope from the equation is -1, and the y-intercept from the equation is 3. The slope from the table is -1, and the y-intercept from the table is −3. These are not the same functions.

Step-by-step explanation: