Answer:
It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion.
Explanation:
The formula of phosphate ion is PO₄³⁻
The formula shows a phosphorus atom surrounded by 4 oxygen atoms.
For this bond to be established, phosphorus would be covalenty bonded to the oxygen atoms.
A covalent bond arises when two atoms with similar zero or very small electronegativity difference(≤ 0.5 ) combines. The electronegativity difference between phosphorus and oxygen is less than 0.5 and the two atom would bond by sharing of their electrons.
The net charge on the resulting radical is a -3 charge which it uses to form other bond types with other atoms. The charge implies an excess of 3 electrons on the radical formed.
The correct statement describing the phosphate ion is: It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion.
The phosphate ion is composed of phosphorus and oxygen atoms with a distributed charge, breaking the octet rule in chemistry. Phosphorus can break the 'octet rule' due to d orbitals availability, and the charge on phosphate ions is evenly spread over oxygen atoms.
Phosphate group: a molecular group consisting of a central phosphorus atom bound to four oxygen atoms.
when 0.863 mol acetone is dissolved in 500 g benzene, the freezing point of benzene drops 8.84°C. what is the molal freezing point depression constant (kf) for benzene?
Answer:
Kf = 5.12 °C/mExplanation:
1) Data:
a) Solute: acetone
b) Solvent: benzene
c) n (solute) = 0.863 mol
d) mass of solvent = 500 g = 0.500 Kg
e) ΔTf = 8.84 °C
f) Kf = ?
2) Formulae:
Depression of freezing point: ΔTf = m . KfMolality: m = n (solute) / kg solvent3) Solution:
a) m = 0.863 mol / 0.500 kg = 1.726 m
b) Kf = ΔTf / m = 8.84°C / 1.726 m = 5.12 °C/m ← answer
What is the mass of 2.00 l of an intravenous glucose solution with a density of 1.15 g/ml?
Answer: The mass of intravenous glucose solution is 2300 g
Explanation:
To calculate the mass of solution, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Volume of glucose solution = 2.00 L = 2000 mL (Conversion factor: 1 L = 1000 mL)
Density of glucose solution = 1.15 g/mL
Putting values in above equation, we get:
[tex]1.15g/mL=\frac{\text{Mass of glucose solution}}{2000mL}\\\\\text{Mass of glucose solution}=2300g[/tex]
Hence, the mass of intravenous glucose solution is 2300 g
In order for a high temperature boiler or steam engine to produce superheated water, or steam: the heat source must be greater than 100°C the water must be permitted to evaporate quickly the system must be sealed and become pressurized above atmospheric pressure the vapor pressure must be kept below 760 mm(Hg)
To produce superheated steam, the heat source must exceed 100°C, and the system must be sealed to allow pressure buildup. This increased pressure raises the boiling point, permitting the water to absorb more heat, making the steam superheated.
In high temperature boilers or steam engines, such as those found in steam locomotives or industrial reactors, to produce superheated steam, several conditions have to be met. One key factor is that the heat source must be greater than 100°C, as it's necessary to not just boil the water but also to add extra energy to the steam to make it superheated. Moreover, the system must allow the water to evaporate, but not quickly .
To produce super heated steam, a high-temperature boiler or steam engine must maintain a sealed and pressurized system above atmospheric pressure, which allows the boiling point to increase and produce steam at higher temperatures, such as in steam locomotives and pressurized reactors.
In the context of steam generation and boilers, several factors are key to producing super heated steam. Based on the information provided, the system must be sealed and become pressurized above atmospheric pressure, is correct.
Raising the pressure of the steam increases the boiling point of water, thus, a steam engine or a high-temperature boiler would need to have a sealed system to maintain the pressurization necessary to produce super heated steam. For instance, at a pressure of 150 pounds or more per square inch, which is common in locomotives, the water and steam's temperature can reach 360°C or higher.
This principle is analogous to the increased boiling point experienced in pressurized water reactors, where water can remain liquid at temperatures significantly above 100°C. When steam does work in an engine or a turbine, it condenses and loses some temperature. High efficiency is desirable for steam engines, and it's achieved through operating at higher temperatures and pressures, which increases the proportion of the heat units utilized for work.
Gallium has two naturally occurring isotopes. One of them, gallium-69, has a mass of 68.925581 u and a percent isotopic abundance of 60.11%. What must be the mass and percent isotopic abundance of the other isotope, gallium-71?
Answer:
1) The percent isotopic abundance of Ga-71 = 39.89%.
2) The mass of Ga-71 = 70.294625 u.
Explanation:
1) The percent isotopic abundance of Ga-71:
The total sum of different isotopes = 100%.
∴ The abundance percent of Ga-69 + the abundance percent of Ga-71 = 100%.
∴ The abundance percent of Ga-71 = 100% - The abundance percent of Ga-69 = 100% - 60. 11% = 39.89%.
2) The mass of Ga-71:
∵ The amu of the mixture = (amu of Ga-69)(fraction of isotope Ga-69) + (amu of Ga-71)(fraction of isotope Ga-71).
The amu of the mixture = 69.723 u,
amu of Ga-69 = 68.925581 u, fraction of isotope Ga-69 = (abundance of Ga-69)/100 = (60.11%)/100 = 0.6011,
amu of Ga-71 = ??? u, fraction of isotope Ga-71= (abundance of Ga-69)/100 = (39.89%)/100 = 0.3989.
∴ 69.723 u = (68.925581 u)(0.6011) + (amu of Ga-71)(0.3989).
∴ (amu of Ga-71)(0.3989) = (69.723 u)(68.925581 u)(0.6011) = 28.29 u.
∴ (amu of Ga-71) = (28.29 u)/(0.3989) = 70.294625 u.
In a chemical reaction, the final amount of the products is determined by the _______.
A. Universal Gas Law
B. Law of Definite Proportions
C. air pressure
D. temperature
E. None of the Above
Please help me
Answer: I believe it is B
Explanation:
because it states that a chemical compound always contains exactly the same proportion of elements by mass
Many batteries cannot be recharged by electrolysis because they would explode.
a. True
b. False
I think the answer is true, I need a second opinion.
Answer:
True.
Explanation:
A non-rechargeable battery, which is also called a primary cell, is known to overheat and some even explode when placed in a charger. This can occur due to the toxic chemicals that might seep out when the battery is heated.
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A sample of 1.55 g of iron ore is dissolved in an acid solution in which the iron is converted into
Fe2+. The solution formed is then titrated with KMnO4 which oxidises Fe2+ to Fe3+ while the MnO4-
ions are reduced to Mn2+ ions. 92.95 mL of 0.020 M KMnO4 is required for the titration to reach
the equivalence point.
a) Write the balanced equation for the titration.
b) Calculate the percentage of iron in the sample.
Answer:a) 8H2SO4 + 2KMnO4 + 10FeSO4 → 5Fe2(SO4)3 + 8H2O + 2MnSO4 + K2SO4
B) nKMno4 = 0.001859 mol
=>nFeso4=0.009295 mol
nFe= 0.009295 mol
mFe=0.52052 g
=>percentage of iron in the sample: 33.5819%
Explanation:a) 8H2SO4 + 2KMnO4 + 10FeSO4 → 5Fe2(SO4)3 + 8H2O + 2MnSO4 + K2SO4
B) nKMno4 = 0.001859 mol
=>nFeso4=0.009295 mol
nFe= 0.009295 mol
mFe=0.52052 g
The reaction is a redox reaction.
The percentage of Fe^2+ is 34.3%
The balanced overall redox reaction equation is:
[tex]MnO4^- + 8H^+ + 5Fe^2+ ----> Mn^2+ + 4H2O + 5Fe^3+[/tex]
Number of moles of permanganate = 0.020 M * 92.95/1000 L = 0.0019 moles
From the reaction equation:
5 moles of [tex]Fe^2+[/tex]reacts with 1 mole of permanganate
x moles of [tex]Fe^2+[/tex] reacts with 0.0019 moles of permanganate
x = 5 * 0.0019 /1 = 0.0095 moles of [tex]Fe^2+[/tex]
Mass of [tex]Fe^2+[/tex] = 0.0095 moles of [tex]Fe^2+[/tex] * 56 g/mol = 0.532 g
Percentage of iron = 0.532 g/1.55 g * 100 = 34.3%
https://brainly.com/question/15524448
Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 mol dm-3 NaOH. The temperature rose from 298 K to 317.4 K. The specific heat capacity is the same as water, 4.18 J/K g.
A. -101.37 kJ
B. 7055 kJ
C. 10,1365 kJ
Answer:
The correct answer is A : -101.37 KJ
Explanation:
Specific heat, s = 4.18 J/Kg
Density of water is 1g/cm3 , so 174 cm3 of total solution is = 174 g
Total mass of reaction mixture is = 174 g
Rise in tempetrature, ΔT = 317.4 K -298 K = 19.4 K
87 cm3 of 1.6 mol dm-3 of HCl = 87 cm3 of 1.6 mol dm-3 NaOH
1.6 M solution means that 1000 cm3 of solution has 1.6 moles.
So, 87 cm3 of 1.6 M solutions = 0.1392 M of HCl and NaOH
Heat evolved (q) = m x s x ΔT
= 174 g x 4.18 J/Kg X 19.4 K
=14110.0 J = 14.110 KJ (for exothermirmic reaction -14.110 KJ )
Enthalpy of neutralization = -14.110 KJ/ 0.1392 = - 101.37 KJ
Answer:
A.) -101.37 kJ
Explanation:
I got it correct on founders edtell
categorize them by Metal, Nonmetal, Metalloid
solid
brittle
semimetals
found in periodic table
ductile
non-ductile
malleable
often gain electrons
semiconductors
silicon
lithium
carbon
shiny
lose electrons easily
good conductor
poor conductor
can be liquids
elements
Answer:
METAL: found in periodic table, lithium, shiny, lose electrons easily, good conductor, elements
NONMETAL: brittle, ductile, semimetals, found in periodic table, often gain electrons, semiconductors, carbon, shiny, poor conductor, elements
METALLOID: solid, non- ductile, malleable, found in periodic table, silicon, shiny, can be liquids, elements
which substance would cantain the most energetic molicules at room temp
a. solid aluminum
b. liquid mercury
c. hydrogen gas
d. its impossible to determine the answer
Sodium (Na) reacts with chlorine gas to form the ionic compound NaCl. Which of the following statements is true?
A) Sodium ions are anions in the ionic bond.
B) The reaction leaves each atom more unstable.
C) After reacting, each ion has a stable octet.
D) Sodium gains electrons from the chlorine to form the sodium ion.
Answer:
C) After reacting, each ion has a stable octet.
Explanation:
Atoms bond to gain stability and to do that they must fill in their outer energy shell with 8 electrons, which we call an octet. In the case of sodium and chlorine, the sodium atom donates one electron to chlorine. When an atom loses an electron, the protons outnumber the electrons, so they become positively charged. This means it will become a cation.
Answer:
C) After reacting, each ion has a stable octet.
Explanation:
What is the empirical formula. A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, and 42.13% oxygen. The empirical formula is Fe S O
Answer:
FeSO4.
Explanation:
We divide the percentages by the relative atomic masses of the elements:
Iron = 36.76 / 55.845= 0.6583
Sulphur = 21.11 / 32.06 = 0.6584
Oxygen = 42.13 / 15.999 = 2.6333
Simplifying the ratios:
Fe : S : O =
0.6583: 0.6584: 2.6333
= 1 : 1 : 4
The empirical formula is FeSO4. (Ferrous Sulphate).
What does the term, nuclear waste (from a nuclear facility), refer to?
a) material that still contains radioactive particles and atoms
b) unused chemical energy in fissionable reactants
c) green radioactive slime stored in barrels
d) non-radioactive material left over from the production, assembly, and use of nuclear reactors
Answer:
d) non-radioactive material left over from the production, assembly, and use of nuclear reactors
Which of the following variables is not considered to be a fundamental way of changing the rate of a chemical reaction?
a. Temperature
b. Surface Area
c. Concentration
d. Catalyst
e. Time
Quite certain the answer is Time but I need a second opinion.
Answer:
Yeah, same i believe it's Time.
Explanation:
Hope my answer has helped you!
Answer:
e. Time
Explanation:
That is correct.. All the others may be active in affecting the rate of a reaction.
Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 C? The freezing point for pure water is 0.0 C and K_f is equal to 1.86 C/m
Answer:
108.43 g.
Explanation:
Adding solute (KNO₃) to water causes depression of freezing point of water (collegative properties).We can predict the change in the freezing point (ΔTf) of water using the relation:ΔTf = i.Kf.m,
where, ΔTf is the elevation in boiling water (ΔTf = 0.0°C - (- 14.5°C) = 14.5 °C).
i is van 't Hoff factor, The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.
i for KNO₃ = 2/1 = 2.
Kf is the molal freezing constant of water (Kf = 1.86 °C/m).
m is the molality of the solution.
∵ ΔTf = i.Kf.m,
∴ m = (ΔTf)/(i.Kf) = (14.5°C)/(2)(1.86 °C/m) = 3.9 m.
molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.m = (no. of moles of KNO₃)/(mass of water (kg)) = (mass/molar mass of KNO₃)/(mass of water (kg)).
∴ 3.9 m = (mass of KNO₃ / 101.1 g/mol)/(0.275 kg).
∴ mass of KNO₃ = (3.9 m)(101.1 g/mol)(0.275 kg) = 108.43 g.
To create a solution that freezes at -14.5 °C, calculate the required molality using the freezing point depression formula, adjust for the dissociation of KNO3 into 2 ions, and then use this to find the moles and mass of KNO3 needed. In this case, 108.35 grams of KNO3 must be added to 275 mL of water.
Explanation:To determine how many grams of KNO3 must be added to produce a solution that freezes at -14.5 °C, we use the freezing-point depression formula: ΔTf = Kf x m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant (1.86 °C/m for water), and m is the molality. First, we calculate the molality needed for the desired freezing point depression:
ΔTf = -14.5 °C (because the freezing point is 14.5 °C below that of pure water)
Kf = 1.86 °C/m
So, m = ΔTf / Kf = -14.5 °C / 1.86 °C/m = -7.795 m
Since KNO3 dissociates into K+ and NO3−, each mole of KNO3 will produce 2 moles of ions. For KNO3, the van't Hoff factor (i) is 2. The molality (m) considering dissociation will now be half the earlier calculated value due to the doubling of particles when dissociation occurs:
m = -7.795 m / 2 = -3.8975 m
The molality is negative because freezing point depression is a negative value. But for the purpose of calculations, we use the positive value of 3.8975 m. We use the formula molality (m) = moles of solute / kilograms of solvent to find the moles of KNO3 needed;
0.275 kg water (275 mL of water converted to kg) x 3.8975 m = moles of KNO3
Moles of KNO3 = 1.0715 mol (after calculation)
Finally, to find the mass of KNO3, multiply the moles by the molar mass (101.1 g/mol for KNO3):
Mass = 1.0715 mol x 101.1 g/mol = 108.35 g (rounded to two decimal places)
Therefore, 108.35 grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 °C.
Why is it important that radioisotopes used in diagnostic tests have short half-lives?
Answer:
It minimizes the harmful side effects of the radiation.
Explanation:
Radioisotopes with short half-lives are used in medical diagnostics to minimize the exposure time and overall radiation dose to the patient, ensuring safety and reducing potential radioactive damage.
It is important that radioisotopes used in diagnostic tests have short half-lives to limit the radiation dose to the patient. The half-life of a radioisotope is the time it takes for half of the isotope to decay. Short-lived radioisotopes decay more quickly, reducing the duration of radiation exposure to the body's tissues and thus minimizing potential radioactive damage. This is essential in medical imaging where the balance between obtaining a clear image and reducing patient exposure to radiation must be carefully managed.
For example, radioisotopes like technetium-99m, with a half-life of only 6 hours, are ideal for medical diagnostic purposes because they decay quickly, limiting the time radiation can interact with body cells. Additionally, having radioisotopes that clear rapidly from the body prevents unnecessary radiation exposure and makes it safer for both the patient and the environment.
1. How many joules of heat are required to raise the temperature of 750 g of water from 11.0 oC to 19.0 oC?
2. 8750 J of heat are applied to a piece of aluminum, causing a 66.0 oC increase in its temperature. The specific heat of aluminum is 0.9025 J/g oC. What is the mass of the aluminum?
3. A 250 g sample of water with an initial temperature of 98.8 oC loses 6500 joules of heat. What is the final temperature of the water?
4. 4786 Joules of heat are transferred to a 89.0 gram sample of an unknown material, with an initial temperature of 23.0 oC. What is the specific heat of the material if the final temperature is 89.5 oC?
5. A piece of copper has a temperature of 75.6 0C. When the metal is placed in 100.0 grams of water at 19.1 0C, the temperature rises by 5.5 0C. What is the mass of the metal?
6. The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants. Thus, ΔH for the reaction = - 890.4 kJ. A negative symbol for ΔH indicates an exothermic reaction.
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l); ΔH = - 890.4 kJ
a) How much energy is given off when 2.00 mol of CH4 are burned?
b) How much energy is released when 22.4g of CH4 are burned?
7. What is the change in enthalpy when 9.75 g of aluminum reacts with excess ammonium nitrate (NH4NO3) according to the equation:
2Al + 3NH4NO3 3N2 + 6 H2O + Al2O3 ΔH = -2030kJ
8. How much enthalpy/heat is transferred when 0.5113 g of ammonia (NH3) reacts with excess oxygen according to the following equation:
4NH3 + 5O2 4NO + 6H2O ΔH = -905.4kJ
9. According to the following reactions, would the burning of 5.50 g of methane (CH4) or propane (C3H8) release more heat?
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g) ΔΗ = -2043 kJ
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ΔΗ = -890. kJ
Please show all work and answer ASAP thank you so much
Answer:
25080 J146.9 g92.58 °C0.808 J/g°C117.09 ga. 1708.8 kJ b.1246.56 kJ368.55 kJ6.81 kJ5.50 grams of methane produces more heat than 5.5 grams of propane.Explanation:
The specific heat capacity of water=4.18 J/gKThe enthalpy change is calculated using the formula: ΔH=MC∅ where ΔH is the change in enthalpy, M the mass of the substance, C the specific heat capacity of the substance and ∅ the temperature change.
Thus, ΔH= 750g × 4.18 J/gK × (19-11)K
=25080 J
2. Enthalpy change= mass of substance × specific heat capacity of the substance× Change in temperature.
ΔH= MC∅
M= ΔH/(C∅)
Substituting for the values in the question.
M=8750 J/(0.9025/g°C×66.0 °C)
=146.9 grams
3. Enthalpy change =mass × specific heat capacity × Temperature
ΔH= MC∅
∅ = ΔH/(MC)
=6500 J/(250 g × 4.18 J/g°C)
=6.22° C
Final temperature =98.8 °C - 6.22°C
=92.58 °C
4. Specific heat capacity =mass × specific heat capacity × Temperature change.
ΔH=MC∅
C= ΔH/(M∅)
Substituting with the values in the question.
C = 4786 J/(89.0 g×(89.5° C-23°C))
=0.808 J/g°C
5. Heat lost lost copper is equal to the heat gained by water.
ΔH(copper)= ΔH(water)
MC∅(copper)=MC∅(water)
M×0.385 J/g°C× (75.6°C- (19.1 °C+5.5°C))=100.0g×4.18 J/g°C×5.5 °C
M=(100.0g×4.18J/g°C×5.5°C)/(0.385 J/g°C×51 °C)
=117.09 grams.
6 (a). From the equation 1 mole of methane gives out 890.4 kJ
There fore 2 moles give:
(2×890.4)/1= 1780.8 kJ
(b) 22.4 g of methane.
Number of moles= mass/ RFM
RFM=12 + 4×1
=16
No. of moles =22.4 g/16g/mol
=1.4 moles
Therefore 1.4 moles produce:
1.4 moles × 890.4 kJ/mol=
=1246.56 kJ
7. From the equation, 2 moles of aluminium react with ammonium nitrate to produce 2030 kJ
Number of moles = mass/RAM
Therefore 9.75 grams = (9.75/26.982) moles of aluminium.
=0.3613 moles.
If 2 moles produce 2030 kJ, then 0.3613 moles produce:
(0.3631 moles×2030 kJ)/2
=368.55 kJ
8. From the equation, 4 moles of ammonia react with excess oxygen to produce 905.4 kJ of energy.
Number of moles= mass/molar mass
RMM= 14+3×1= 17
Therefore 0.5113 grams of ammonia = (0.5113 g/17g/mole) moles
= 0.0301 moles
If 4 moles produce 905.4 kJ, then 0.0301 moles produce:
(0.0301 moles×905.4 kJ)/4 moles
=6.81 kJ
9. From the equations, one mole of methane produces 890 kJ of energy while one mole of propane produces 2043 kJ.
Lets change 5.5 grams into moles of either alkane.
Number of moles= Mass/RMM
For propane, number of moles= 5.5g/ 44.097g/mol
=0.125 moles
For methane number of moles =5.5 g/ 16g/mol
=0.344 moles
0.125 moles of propane produce:
0.125 moles×2043 kJ/mol
=255.375kJ
0.344 moles of methane produce:
0.344 moles× 890 kJ/mol
= 306.16kJ
Therefore, 5.5 grams of methane produces more heat than 5.5 grams of propane.
Which of these describes the rate of this chemical reaction?
H2 + Cl2 → 2 HCl
a. an increase in the concentration of HCl and H2 with time
b. an increase in the concentration of HCl with time
c. an increase in H2 and Cl2 with time
d. a decrease in HCl and Cl2 with time
Answer:
b.an increase in concentration of HCl with time.
Explanation:
The measurement of reaction rate is simply based on the dissapearance of a reactant or appearance of a product with increasing reaction time.
For this kind of chemical reaction, the rate would increase if the concentration of the reactants increase.
The reactants are made up of gaseous particles, for gases reacting, the rate of the reaction is directly proportional to concentration. The concentration of a gaseous system is also directly proportional to the pressure and we can use pressure in place of concentration.
For this reaction, we don't know the order of reaction of the reactants. This would not make the gaseous reactants suitable to monitor the rate of the reaction.
Since it is only the appearance of the product we are sure of, we simply monitor the concentration of the product to determine the rate.
The correct answer is option b) an increase in the concentration of HCl with time. The rate of the reaction [tex]H_2 + Cl_2 \rightarrow 2HCl[/tex] as HCl is the product and its concentration increases over time.
The reaction given is [tex]H_2 + Cl_2 \rightarrow 2HCl[/tex].
We need to determine which option correctly describes the rate of this reaction. Considering the options:
An increase in the concentration of HCl and H₂ with time.
This option is incorrect because H₂ is a reactant and its concentration should decrease over time.An increase in the concentration of HCl with time.
This option is correct as HCl is the product, and its concentration will increase over time as the reaction proceeds.An increase in H₂ and Cl₂ with time.
This option is incorrect because both H2 and Cl2 are reactants and their concentrations should decrease over time.A decrease in HCl and Cl₂ with time.
This option is incorrect because HCl is the product, and its concentration should increase.Therefore, the correct answer is option b.
The table shows the rate of reaction for two unknown time intervals during a chemical change. Reaction Rates Time Intervals (s) Rate (M/s) T1 1.8 × 10−6 T2 1.0 × 10−6 Which of the following is true for the two time intervals? T1 is longer than T2, and the concentration of reactants at the end of T1 is lower than that of T2. T1 is longer than T2, and the concentration of products at the end of T1 is lower than that of T2. T1 is shorter than T2, and the concentration of reactants at the end of T1 is higher than that of T2. T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.
Answer:
T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.
Explanation:
The rate of the reaction is defined as the change in the concentration of reactants (decrease) or products (increase) with time.Rate of the reaction = - d[reactants]/dt = d[products]/dt
It is clear that the rate of the reaction is inversely proportional with time.∵ Rate at T1 (1.8 x 10⁻⁶ M/s) > rate at T2 (1.0 x 10⁻⁶).
∴ T1 < T2, which means that T1 is shorter than T2.
Also, it is clear that the rate of the reaction is directly proportional to the change of reactants.
As, the rate increases, the remaining of the reactants decrease and products formed increase.
So, concentration of reactants at the end of T1 is lower than that of T2 and the concentration of products at the end T1 is higher than that of T2.
So, the right choice is:
T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.
Melting can be best described as a process in which molecules?
a)lose kinetic energy and move slowly.
b)lose kinetic energy and remain stationary. c)gain kinetic energy and escape into the atmosphere.
d)gain enough kinetic energy to get past each other.
Answer:
D.gain enough kinetic energy to get past each other.
Explanation:
Melting can be best described as a process in which molecules gain enough kenetic energy to put past each other.
Answer:
D
Explanation:
Edge 2020
If you fill a glass to the brim with ice water and the ice melts, what will happen?
Hello There!
When the ice melts, the water level will drop slightly but not much.
REMEMBER Ice expands so when ice melts, it shrinks back to the state of being liquid.
No change is witnessed as the weight of the ice and water is equal.
Explanation:At the point when an ice cube is set in a glass of water, it uproots enough water to help its weight and leads to the condition:
Weight of an ice cube = mass of water/thickness of water.
After the ice cube melts totally the water level continues as before as the water uprooted is currently satisfied by the measure of water present in the ice (3D shape). Indeed, even in the wake of liquefying, the measure of water in the ice cube will gauge is equal mass of ice block/thickness of water.
As the weight stays same, the measure of water dislodged doesn't change and the water level continues as before. But, there are some water droplets around the glass.
A sample of gas occupies 7.80 liters at 425°C? What will be the volume of the gas at 35°C if the pressure does not change? 4.65 liters 3.65 liters 3.44 liters 7.65 liters 5.89 liters
Answer:
3.44 liters
Explanation:
before we start we must convert the celcius to kelvin by adding 273
Next we must Know we are using charles law and the eqation is V1/T1= V2/T2 we must convert it to V1 T1 / T2
so its must equal 7.80 times 698 divided by 308 wich gives you 3.44 liters
Answer:
3.44 or answer c on treca
Explanation:
What five things is the element carbon a part of?
Answer:
oceans,air,rocks,soil, also living things
Explanation:
When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+MgCl2(aq)→2AgCl(s)+Mg(NO3)2(aq) What mass of silver chloride can be produced from 1.50 L of a 0.118 M solution of silver nitrate?
What is the atomic number of an atom that has 6 protons
Answer:
Its atomic mass is 14 ( = 6 protons + 8 neutrons). In chemistry, the number of protons in an atom is more important than the number of neutrons. Scientists call the number of protons the "atomic number"
Explanation:
How many moles are equivalent to 3.58x1023 formula units of ZnCl2? a. 0.555 mol ZnCl2 c. 0.621 mol ZnCl2 b. 1 mol ZnCl2 d. 0.595 mol ZnCl2
Answer:
There are approximately d. 0.595 mol of ZnCl₂ in 3.58×10²³ formula units.
Explanation:
Consider the Avogadro's Constant [tex]N_A[/tex] or equivalently, [tex]L[/tex]:
[tex]N_A \approx \rm 6.02\times 10^{23}\;mol^{-1}[/tex].
In other words, there are [tex]\rm 6.02\times 10^{23}\;mol^{-1}[/tex] constituent particles (Wikipedia) in each mole of a substance. In this case,
Zinc chloride [tex]\rm ZnCl_2[/tex] is the substance, and[tex]\rm ZnCl_2[/tex] formula units are the constituents.[tex]N = 3.58\times 10^{23}[/tex].
[tex]\displaystyle n = \frac{N}{N_A} =\rm \frac{3.58\times 10^{23}}{6.02\times 10^{23}\;mol^{-1}} = 0.595\;mol[/tex].
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a temperature of 52.0 degrees celsius. what is the minimum volume the container can have?
Answer:
The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.
Explanation:
Assume that ethane behaves as an ideal gas under these conditions.
By the ideal gas law,
[tex]P\cdot V = n\cdot R\cdot T[/tex],
[tex]\displaystyle V = \frac{n\cdot R\cdot T}{P}[/tex].
where
[tex]P[/tex] is the pressure of the gas,[tex]V[/tex] is the volume of the gas,[tex]n[/tex] is the number of moles of particles in this gas,[tex]R[/tex] is the ideal gas constant, and[tex]T[/tex] is the absolute temperature of the gas (in degrees Kelvins.)The numerical value of [tex]R[/tex] will be [tex]8.314[/tex] if [tex]P[/tex], [tex]V[/tex], and [tex]T[/tex] are in SI units. Convert these values to SI units:
[tex]P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa[/tex];[tex]V[/tex] shall be in cubic meters, [tex]\rm m^{3}[/tex];[tex]T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K[/tex].Apply the ideal gas law:
[tex]\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}[/tex].
Which is the electron configuration for boron?
Answer: The electronic configuration is given below.
Explanation:
Electronic configuration tells us about the number of electrons that are present in an atom. It also determines the atomic number of an element.
Boron is the 5th element of the periodic table having 5 electrons.
The electronic configuration for the given element = [tex]1s^22s^22p^1[/tex]
This element has 3 valence electrons.
Thus, the electronic configuration is given above.
50 POINTS! NEED ANSWER ASAP.
What type of organic compound contains the following functional group? (2 points)
Answer:
Isocyanates
Explanation:
The functional group is cyanate ion of the formula NCO⁻. The atoms in this functional group occur in a straight line giving it a linear structure. It has a singe C-O bond and a triple N ≡ C bond. It forms cyanate salts when it reacts with pure elements like sodium and other reactive metals as it has some acidic properties. It also forms complexes like silver cyanato [Ag(NCO)₂]⁻
An example of something that stores chemical energy is
Hello There!
Chemical energy is energy that is stored in the bonds and atoms of molecules.
A battery is an example of an item that stores atoms and molecules in the bonds.
Gasoline and organic molecules like sugars and fats are examples of things that store chemical energy. This energy can be transformed during combustion in cars or through metabolic processes in living cells into usable forms of kinetic or ATP energy.
Explanation:An example of something that stores chemical energy is gasoline, which stores energy in the bonds of its molecules. This chemical energy is released as heat during combustion in a car engine, converging into kinetic (mechanical) energy that moves the car.
Another scenario is found within our bodies. Organic molecules such as sugars and fats also store chemical energy. Your cells evolve to convert this chemical energy through a series of chemical reactions into a usable form of energy stored in molecules of ATP (Adenosine Triphosphate), an energy-carrying molecule found in the cells of all living things. This energy is easily accessible to do work such as muscle contraction, transport materials, power the motion of cilia or flagella, etc.
Learn more about Chemical Energy here:https://brainly.com/question/1371184
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