Which rule is used for writing the name of an ionic base?
The chemical name begins with “hydro.”
The chemical name ends with “hydroxide.”
The “ide” ending is changed to “ic.”
The polyatomic “ate” ending is changed to “ic.”

Answer:NaCl (Sodium Chloride )

Explanation:As it has Solubility 35.7

Answer:

NaCl

Explanation:

Final answer:

To produce 10g of magnesium oxide, 6g of magnesium would be needed.

Explanation:

To find the mass of magnesium needed to produce 10g of magnesium oxide, we can use the given information about the reaction between magnesium and oxygen. From the given information, we know that when 24g of magnesium is heated in air, 40g of magnesium oxide is produced. This means that the reaction produces a 1:1 ratio between the mass of magnesium and the mass of magnesium oxide. Therefore, if 24g of magnesium produces 40g of magnesium oxide, then 10g of magnesium oxide would require (10g/40g) * 24g = 6g of magnesium.

Answer:Sulfur dioxide

CID: 1119

Molecular Formula: SO2 or O2S

UNII:0UZA3422Q4

Chemical Names: sulfur dioxide sulphur dioxide Sulfurous anhydride 7446-09-5 Sulfurous oxide More...

Molecular Weight: 64.058 g/mol

Explanation: can i have brailyest plz

Answer:

SO2

Explanation:

Answer:

a habitat

Explanation:

The correct answer is shelter and their right climate is another need of animals.

Learn more about the basic needs of animals here:-

https://brainly.com/question/12484589

#SPJ2

Answer:

22.77 g.

he limiting reactant is O₂, and the excess reactant is Mg.

Explanation:

Mg + 1/2O₂ → MgO,

1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.

no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.

no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.

So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.

∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).

Using cross multiplication:

1.0 mole of Mg produce → 1.0 mol of MgO.

∴ 0.565 mol of Mg produce → 0.565 mol of MgO.

∴ The amount of MgO produced = no. of moles x molar mass = (0.565 mol)(40.3 g/mol) = 22.77 g.

Answer:

[tex]m_{MgO}=11.3gMgO[/tex]

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]2Mg+O_2\rightarrow 2MgO[/tex]

Hence, for given amounts of magnesium and oxygen, one computes the available moles of magnesium with its given mass and atomic mass and the moles of magnesium that will completely react with 4.52 g of oxygen by using their 2:1 molar ratio in the chemical reaction in order to identify the limiting reactant:

[tex]n_{Mg}^{available}=16.3gMg*\frac{1molMg}{24gMg}=0.679molMg\\\\n_{Mg}^{reacted}=4.52gO_2*\frac{1molO_2}{32gO_2}*\frac{2molMg}{1molO_2} =0.2825molMg[/tex]

In such a way, as just 0.2825 moles of magnesium react, magnesium is identified as the excess reactant and the oxygen the limiting reactant. Furthermore, with the reacting moles, one computes the yielded grams of magnesium oxide as:

[tex]m_{MgO}=0.2825molMg*\frac{2molMgO}{2molMg}*\frac{40gMgO}{1molMgO} \\\\m_{MgO}=11.3gMgO[/tex]

Best regards.

Answer:

4.2 × 10⁻¹⁴s⁻¹

Explanation:

Given parameters:

Wavelength of light = 7.1 x 10²nm

We simplify and express this value in metres(m) to give:

⇒7.1 x 10² x 10⁻⁹m = 7.1 x 10⁽⁻²⁺⁹⁾ m

= 7.1 x 10⁷m

The wavelength is 7.1 x 10⁷m

We use the formula V = fλ

We know that Velocity of light is 3 x 10⁸ms⁻¹

Making f, frequency the subject of the formula gives :

f = V/λ

f = 3 x 10⁸ms⁻¹ / 7.1 x 10⁷m

f = 4.2 x 10⁻¹⁴s⁻¹

The frequency of light with a wavelength of 7.1 × 10² nm is 4.23 × 10^14 s⁻¹.

The frequency of light with a wavelength of 7.1 × 10² nm can be calculated using the formula:

$$ \nu = \frac{c}{\lambda} $$

where c is the speed of light (3.00 × 10^8 m/s) and λ is the wavelength in meters.

Plugging in the values, we get:

$$ \nu = \frac{3.00 \times 10^8 \, \text{m/s}}{7.1 \times 10^{-9} \, \text{m}} = 4.23 \times 10^{14} \, \text{s}^{-1} $$

Therefore, the frequency of light with a wavelength of 7.1 × 10² nm is 4.23 × 10^14 s⁻¹.

Answer:

Oh, I don't run

Explanation:

Alex Russo

Elizabeth is getting ready to run a marathon, her thinking incorrect due to lack of training and unrealistic Expectations.

Lack of Training: Marathon runners need to be properly trained and condition themselves. Elizabeth's reasoning can be flawed if she hasn't had enough training since she might underestimate the physical difficulties and the risks involved in the marathon. Without adequate training, she can experience fatigue, injuries, or other health problems while competing.

Elizabeth might have exaggerated expectations on how well she will perform in the marathon. She would be mistaken in her reasoning, for instance, if she thought she could run the marathon in a relatively short amount of time without any training or prior experience. Setting reasonable objectives that take into account one's ability and level of fitness is crucial.

To know more about marathon, here:

https://brainly.com/question/30603442

#SPJ6

Answer:

155 kJ of energy will be released.

Explanation:

The [tex]\rm \Delta H\textdegree[/tex] ([tex]\rm \Delta H \textdegree_\text{rxn}[/tex] in some textbooks) here stands for standard enthalpy change per mole reaction. To find the amount of energy released in this reaction, start by finding the number of moles of this reaction that will take place.

How many moles of atoms in 4.72 grams of carbon?

Relative atomic mass data from a modern periodic table:

[tex]\displaystyle n = \frac{m}{M} = \rm \frac{4.72\;g}{12.01\; g\cdot mol^{-1}} = 0.393006\; mol[/tex].

The coefficient of carbon in the equation is one. In other words, each mole of the reaction will consume one mole of carbon. Oxygen is in excess. As a result, [tex]\rm 0.393006\; mol[/tex] of carbon will support [tex]\rm 0.393006\; mol[/tex] of the reaction.

How much energy will be released?

The [tex]\rm \Delta H\textdegree{}[/tex] value here is negative. But don't panic. [tex]\rm \Delta H\textdegree{}[/tex] is the same as the chemical potential energy of the reactants minus the products in one mole of the reaction. [tex]\rm \Delta H\textdegree{} = -393.5\;kJ[/tex] means that the chemical potential energy drops by [tex]\rm 393.5\; kJ[/tex] during each mole of the reaction (with the coefficients as-is.) Those energy difference will be released as heat. In other words, one mole of the reaction will release [tex]\rm 393.5\;kJ[/tex] of energy.

The 4.72 grams of carbon will support [tex]\rm 0.393006\; mol[/tex] of this reaction. How much heat will that [tex]\rm 0.393006\; mol[/tex] of reaction release?

[tex]Q = n \cdot (-\Delta \text{H}\textdegree{}) = \rm 0.393006\times 393.5 = 155\;kJ[/tex].

As a side note, the mass of carbon 4.72 grams is the least significant data in this question. There are three significant figures in this value. As a result, keep more than three significant figures in calculations but round the final result to three significant figures.

The energy released when 4.72g of carbon reacts with excess oxygen to form CO₂ is -154.8 kJ.

To determine how many kJ of energy are released when 4.72g of carbon reacts with excess oxygen to produce carbon dioxide, we use the given enthalpy change (ΔH) for the reaction:

First, we need to find the number of moles of carbon in 4.72g:

Molar mass of carbon = 12 g/mol

Moles of carbon = mass / molar mass = 4.72 g / 12 g/mol = 0.3933 mol

The reaction for the combustion of carbon to form CO₂ is exothermic, with ΔH = -393.5 kJ/mol.

The total energy released is calculated as follows:

Energy released = moles of carbon x ΔH
Energy released = 0.3933 mol x -393.5 kJ/mol = -154.8 kJ

Thus, the energy released when 4.72g of carbon reacts with excess oxygen is -154.8 kJ.

yes because the

0。5 that's left may stop the batter from over flowing

Answer:

True.

Explanation:

the answer to your question is True !

Answer:

0.1612 mol.

Explanation:

2Ca₃(PO₄)₂ + 6SiO₂ + 10C → 6CaSiO₃ + P₄ + 10CO.

2.0 moles of Ca₃(PO₄)₂ react with sufficient SiO₂ and C to produce 1.0 mole of P₄ and other products.

no. of moles of Ca₃(PO₄)₂ = mass / molar mass = (100.0 g)/(310.18 g/mol) = 0.3224 mol.

Using cross-multiplication:

2.0 moles of Ca₃(PO₄)₂ produce → 1.0 mole of P₄.

0.3224 mole of Ca₃(PO₄)₂ produce → ??? mole of P₄.

∴ The no. of moles of phosphorous (P₄) will be produced = (1.0 mole)(0.3224 mole)/(2.0 mole) = 0.1612 mol.

Answer:

1.  A.  silicon dioxide

2. D.  Hydrogen

Explanation:

Answer:

the earth

Explanation:

because the moon is blocking the light of the sun

The energy speed!!!!

Answer:

Motor

Explanation:

This actuation of electric energy to mechanical energy is due to reverse magnetic induction. When you pass a wire coil, with electricity passing through it, along a magnetic field, the coil will rotate according to Fleming’s Left Hand Hand Rule. This principle is harnessed in the making of motors that can be used to power equipments such as fans.

Answer:

D) electric motor

Explanation:

Thats the answer for apex. A) electric generator B) power surge C) battery D) electric motor

Final answer:

To find the volume of the balloon when it burst at 99 mmHg, we use Boyle's Law. The final volume was calculated to be approximately 28.28 liters.

Explanation:

The volume of the balloon when it burst at 99 mmHg atmospheric pressure can be determined using Boyle's Law, which states that the product of pressure and volume is constant for a given mass of enclosed gas when the temperature is constant (P1V1 = P2V2).

Here, we know the initial pressure (P1) is 700.0 mmHg, the initial volume (V1) is 4.0 liters, and the final pressure (P2) upon bursting is 99 mmHg. To find the final volume (V2), we rearrange the equation to V2 = (P1V1) / P2 and substitute the known values. Doing so gives us V2 = (700.0 mmHg × 4.0 L) / 99 mmHg, which calculates to a volume of approximately 28.28 liters.

Answer:

The carbon cycle is the biogeochemical cycle by which carbon is exchanged among the biosphere, pedosphere, geosphere, hydrosphere, and atmosphere of the Earth.

The carbon cycle is a biological and geological system composed of two interconnected sub-cycles - the biological carbon cycle and the biogeochemical carbon cycle. The biological carbon cycle involves the exchange of carbon among living organisms through processes like photosynthesis and respiration, while the biogeochemical carbon cycle involves the long-term cycling of carbon through the Earth's atmosphere, water bodies, and interior. Human activities like burning of fossil fuels can accelerate these cycles and contribute to global climate change.

The carbon cycle is a type of system in biology that can be broadly divided into two interconnected sub-cycles. One sub-cycle deals with the rapid exchange of carbon among living organisms, and the other deals with the long-term cycling of carbon through geologic processes. These processes together help in the transfer and recycling of carbon in different forms throughout the ecosystem.

In the Biological Carbon Cycle, living organisms play a crucial role. Autotrophs, like plants, absorb carbon dioxide from the atmosphere and convert it into glucose through photosynthesis. This glucose is used by heterotrophs, like animals, for their energy needs. In this process, carbon gets incorporated in their bodies. When these animals die, the carbon gets returned to the atmosphere through decomposition. Moreover, marine autotrophs obtain carbon dioxide in the dissolved form (carbonic acid, H₂CO3). Through this biological carbon cycle process, photosynthetic organisms are responsible for maintaining approximately 21 percent of the Earth's oxygen content.

In the Biogeochemical Carbon Cycle, carbon is stored in what are known as carbon reservoirs that include the atmosphere, bodies of liquid water (mostly oceans), ocean sediment, soil, land sediments (including fossil fuels), and the Earth's interior. Over longer periods, microorganisms capable of digesting non-bioavailable carbon like coal can release it as gas, making it available for other living organisms. This process accelerates when humans burn fossil fuels, releasing large amounts of carbon dioxide into the atmosphere. Most scientists agree that the high atmospheric carbon dioxide is a major cause of global climate change.

https://brainly.com/question/30508567

#SPJ3

Hey there!

Here goes your answer ↓

Question :- What is the percent composition of silicon in silicon carbide (SiC)?

A. 28%

B. 50%

C. 70%

D. 142%

Answer :- The percentage of silicon content in silicon carbide (SiC) is option (C) 70%.

Hope it helps you.

Have a great day ahead!

Answer : The correct option is, (C) 70%

Explanation : Given,

Molar mass of Si = 28.09 g/mole

Molar mass of C = 12 g/mole

Molecular mass of SiC = 28.09 + 12 = 40.09 g/mole

To calculate the mass percent of an element in a compound, we use the equation:

[tex]\text{Percent composition of Si}=\frac{\text{Mass of Si in compound}}{\text{Mass of the compound}}\times 100[/tex]

Now put all the given values in above equation, we get:

[tex]\text{Percent composition of Si}=\frac{28.09g}{40.09g}\times 100=70\%[/tex]

Hence, the percentage composition of Si in the given compound is 70%

Answer:

Aluminium oxide

Explanation:

This is not an element but a coumpound.

Al is Aluminum

And O is Oxygen

Answer:

2

Explanation:

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

Using Boyle's law, which states that the pressure and volume for a gas is a constant if the temperature is constant, we can determine that the new volume of the gas occupying 4.31 liters at 0.755 atm when the pressure is increased to 1.25 atm is 2.62 L. Similarly, when the pressure of a gas occupying 600.0 mL at 8.00 atm is reduced to 2.00 atm the new volume will be 2400 mL.

To solve these problems, we can use the principles of Boyle's law, which states that the product of the pressure and volume for a gas is a constant if the temperature and the amount of gas remain unchanged. In other words, P1*V1 = P2*V2.

Problem 13

Let's use Boyle's law to calculate the new volume (V2) when the pressure (P2) is increased to 1.25 atm (P2). We know that the initial volume (V1) is 4.31 L, and the initial pressure (P1) is 0.755 atm.

V2 = P1*V1/P2 = (0.755 atm * 4.31 L) / 1.25 atm = 2.62 L

The initial volume (V1) is 600 mL and the initial pressure (P1) is 8.00 atm. The new pressure (P2) is 2.00 atm. So, we can calculate the new volume (V2) as:

V2 = P1*V1/P2 = (8.00 atm * 600.0 mL) / 2.00 atm = 2400 mL

https://brainly.com/question/21184611

#SPJ3

Answer:6

Explanation:

U welcome

Final answer:

The bond between calcium (Ca) and bromine (Br) is an ionic bond, where calcium donates electrons to form Ca2+ ions, and bromine atoms each gain an electron to form Br- ions, creating an ionic compound.

Explanation:

The bond between calcium (Ca) and bromine (Br) in the compound CaBr2 is an ionic bond. This type of bond is formed when one atom (in this case, calcium) donates one or more electrons to another atom (in this case, bromine).

Calcium is a metal with a tendency to lose electrons and form a positive ion (Ca2+), while bromine is a non-metal with a tendency to gain electrons and form a negative ion (Br−).

When calcium gives up two electrons, one for each bromine atom, each bromine atom gains one electron, resulting in two Br− ions. These oppositely charged ions attract each other, creating an ionic bond.

Answer:

[tex]\boxed{\text{(a) 0.001 66 mol MOH; (b) 200 g/mol}}[/tex]

Explanation:

I am assuming that the unknown acid is monobasic. Then the general equation for the reaction is

HA + MOH ⟶ MA + H₂O

(a) Moles of MOH

[tex]\text{Moles of MOH}= \text{0.008 72 L MOH} \times \dfrac{\text{0.19 mol MOH}}{\text{1 L MOH}} = \text{0.001 66 mol MOH}[/tex]

(b) Moles of HA

Now, you use the molar ratio from the balanced chemical equation to find the moles of unknown acid.

[tex]\text{Moles of HA = 0.001 66 mol MOH} \times \dfrac {\text{1 mol HA}}{\text{1 mol MOH }} = \text{0.001 66 mol HA}[/tex]

(c) Molar mass of HA

[tex]\text{MM} =\dfrac{\text{mass}}{\text{moles}}= \dfrac{\text{0.33 g}}{\text{0.001 66 mol}} = \text{200 g/mol}[/tex]

The molar mass of the unknown acid is [tex]\boxed{\textbf{200 g/mol}}[/tex]

Great Question!

The Answer Would Be "B" The "RESPONDING" Variable

The variable that a scientist observes to change while conducting an experiment is called the responding variable.

Acids have a pH below 7 (option c), indicating a higher concentration of hydronium ions.

The correct answer is: c. They have a pH below 7.

In chemistry, acids are substances that have a pH value lower than 7. This lower pH indicates a higher concentration of hydronium ions (H₃O⁺) compared to pure water. For example, vinegar, which tastes sour, is an acid with a pH lower than 7. Strong acids are particularly notable for being able to damage materials, demonstrating their high acidity.

Here's why the other options are incorrect:

A:Coefficients B:Element C:subscripts D:Reactants E:Products

The term for an underground stem that sends up new plants at intervals is a rhizome, while a stem that does this above ground is referred to as a stolon or runner.

The term that best describes an underground stem that grows along, sending up new plants at intervals, is a rhizome. Rhizomes are modified stems that grow horizontally underground and can branch at nodes to produce new plants. A well-known plant that reproduces from rhizomes is the iris. However, if the stem grows above the ground, it's called a stolon or runner, like those seen in strawberry plants. These runners develop adventitious roots at their nodes, and the axillary buds can turn into independent plants.

Another form of modified stem includes corms, which are fleshier and store food, and unlike rhizomes and stolon, don't typically give rise to new plants at intervals along their length.

Answer:

36.0%.

Explanation:

The mass of water = mass of hydrated copper (II) sulfate - mass of copper (II) sulfate after heating = 4.56 g - 2.92 g = 1.64 g.

The percent by mass of water in the hydrate = (mass of water/mass of hydrated copper (II) sulfate)*100 = (1.64 g/4.56 g)*100 = 35.96% ≅ 36.0%.

Answer:

Explanation:

Hund's Rule of Maximum Multiplicity states that electrons go into degenerate orbitals of sub-orbitals(p, d and f) singly before pairing commences.

Hund's rule is useful in determining the number of unpaired electrons in an atom. Hence, it explains some of the magnetic properties of elements.

An element whose atoms or molecules contain unpaired electrons is paramagnetic.

The element whose atoms or molecules contain orbitals that are all filed up with paired electron is diamagnetic.

Hund's rule states that in degenerate orbitals, electrons must occupy orbitals singly and with parallel spins before pairing up. This ensures the lowest-energy electron configuration. A common example is seen in the p orbitals for nitrogen.

Hund's Rule

Hund's rule states that the lowest-energy electron configuration for an atom is the one that has the maximum number of electrons with parallel spins in degenerate orbitals. This means that in any given sub-level other than the s orbital, electrons will occupy each orbital singly before starting to pair up. For instance, in the p sublevel, which has three degenerate orbitals, each of these orbitals will get one electron before any one of them gets a second electron with the opposite spin.

An easy way to visualize this is by considering the p orbitals (px, py, and pz) for an atom like nitrogen, which has three electrons in its p sublevel. According to Hund's rule, each of these three electrons will occupy one of the p orbitals singly, with parallel spins, resulting in a more stable and lower-energy configuration.