Which reaction represents cellular respiration?

a.sugar + oxygen → carbon dioxide water + atp

b.carbon dioxide + water + atp → sugar + oxygen

c.oxygen + carbon dioxide → sugar + water + atp

d.water + atp → carbon dioxide + sugar?

4 carbon chain is butane.  With a triple bond it is butane.  Since the triple bond is on the first carbon it can be called 1-butyne, or but-1-yne.

The answer is B.

ATP + Oxygen ---> ADP + P

The statement that a couples' shower is inappropriate is false. Couples' showers are a modern, inclusive celebration for both members of a couple and are deemed appropriate based on the couple's preference and cultural norms.

The assertion that it is inappropriate to give a couples' shower is false. A couples' shower is a modern take on traditional bridal showers, and is considered an appropriate event. It involves both members of the couple, regardless of gender, and allows guests who are close to both individuals to celebrate their union together. The appropriateness of a couples' shower is determined by the couple's preferences and the social norms of their community or culture.

Answer:

that a chemical change

Explanation:

because it changing properties

It’s Chemical change

Answer:

The pressure of the gas is 40atm

Explanation:

Given parameters:

P₁ = 2.0atm

V₁ = 0.2L

V₂ = 10.0mL = 10 x10⁻³L = 0.01L

P₂ =?

We apply Boyle's law to solve this kind of problem

Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

It is expressed as P₁V₁ = P₂V₂

Making P₂ the subject of the formula gives:

P₂ = P₁V₁/V₂

Inserting the values of the parameters:

P₂ = 2x0.2/0.01

P₂ = 40atm

The answer is D. 6 you multiply 2 and 3

Answer:

The correct answer is D

Explanation:

because you would take 2 and 3 and multiply them and get 6 or

3×2=6

Absolutely an acid ,because:

1)we it is sulfuric acid s molecular formula

2) in its shape H atom bonded with (O),not central atom

Answer:

A. An acid

Explanation:

Hello,

In inorganic chemistry, oxyacids are characterized by the presence of hydrogen, a nonmetal and oxygen as they are formed when an acid oxide (formed with a  nonmetal and oxygen) reacts with water. In this case, as the molecule has hydrogen, sulfur and oxygen, such constituting atoms match with the definition of an oxyacid, that is why H₂SO₄ is an acid.

Best regards.

Answer:

A - NaCl is a product

D - Cl2 is a gas

Explanation:

Based on the chemical reaction;

2Na(s) + Cl2(g) → 2NaCl2

The true statements for the reaction 2Na(s) + Cl2(g) → 2NaCl(s) are that NaCl is a product and Cl2 is a gas. Sodium (Na) is a reactant, not a product, and a chemical reaction does occur in this equation.

The reaction given is 2Na (s) + Cl2(g) → 2NaCl (s). This chemical equation is balanced, indicating that the same number and types of atoms appear on both sides of the equation. The equation demonstrates the reaction of solid sodium (Na) with chlorine gas (Cl2) to form sodium chloride (NaCl), a solid.

For the statements provided:

Key Notes to Remember:

Chlorine is one of the seven elements that exist in nature as diatomic molecules, which include H2, N2, O2, Cl2, Br2, and I2—this is important for balancing chemical equations correctly.

Answer:

Particle /                          mass number                atomic number

type of radiation

alpha / ⁴₂ He                              4                                     2

beta / e⁰                                     0                                   - 1

gamma / γ                                  0                                     0

neutron / n                                 1                                      0

Explanation:

These are the basic types of radiation: alpha (α), beta (β),  gamma (γ), and neutrons (n).

The radiation is emitted by unstable nuclei when undergo radiactive decay or by nuclei that are shooted by other particles.

Alpha radiation (⁴₂ He):

They are nuclei of helium-4 atoms: 2 protons and 2 neutrons.

Hence, the atomic number, which is the number of protons,  of these particles, is 2; and the mass number, which is the sum of protons and neutrons, is 2 + 2 = 4.

The symbol of this radiation is ⁴₂ He, where the superscript to the left of the chemical symbol is the mass number and the subscript to the left of the chemical symbol is the atomic number.

Beta (⁰₋ ₁ e)

These are electrons emiited from an unstable nucleus. The symbols used for this particle are either ⁰₋ ₁β or ⁰₋ ₁e.

The superscript 0 indicates that the relative mass of this particle is practically zero and the subscript -1 tells that the emission of electrons increases the atomic number of the nucleus that emits it.

Gamma (⁰₀γ)

The gamma rays are electromagnetic radiation of high (the highest) energy.

The both superscript and subscript are zero, meaning that this radiation does not change either the mass or atomic numbers of the nucleus.

Neutron (¹₀n):

Neutrons are also emiited from the nucleus and so they may be considered a radiation.

The atomic number of neutrons is 0 (since it does not have protons) and its mass number is 1.

Radioactive rays are divided into three, namely alpha rays, beta rays, and gamma rays.  

Check the picture below!

Types of Radioactive Rays

Based on the constituent particles, radioactive rays are divided into three, namely alpha rays, beta rays, and gamma rays.

Alfa ray (α ray)

Alpha rays are rays emitted by radioactive elements. This ray was discovered simultaneously with the discovery of the phenomenon of radioactivity, which is the decay of the nucleus which takes place spontaneously, uncontrolled, and produces radiation. Alpha rays consist of two protons and two neutrons. The following are the nature of alpha rays.

Beta Rays (β Rays)

Beta rays are high-energy electrons that originate from the nucleus. Here are some of the nature of beta rays.

Gamma Rays (Rays ˠ)

Gamma rays are radiation from electromagnetic waves that emanate from very high energy nuclei that have no mass or charge. Gamma rays also emit when a core emits alpha rays and beta rays. Gamma-ray decay does not cause changes in atomic number or atomic mass.

Gamma rays have the following natural properties:

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Class: High School

Subject: Chemistry

Keyword: Alpha, Beta, Gamma

1. Find the mole of each reactant present and determine the limiting reactant 2. determine the mole of product produced through the mole ratio of the equation 3. convert to grams if the 'amount' refers to grams

Answer:

False this is like the definition of temperature

Explanation:

Answer:

Explanation:

To answer this question you must look at your periodic table.

The elements in the periodic table are ordered in increasing order of atomic number and elements with similar chemical properties, due to the same number of valence eletrons, lay in the same column.

The column in the periodic table corresponds to the chemical group, and,  in the most modern version, is identified with a number 1 through 18.

The elments Cu (copper), Ag (silver), and Au (gold), all metals, are in the same group (column) number 11.

The elements in the columns 3 trough 12 are transition metals. The atomic numbers of thise elements, which let you to find them easily in your periodic table, are:

Those elements, along with platinum are paladium, are the metals with the lowest reactivity, which is the reason why they are found in nature in its pure form (not combined with other elements).

Cu, Ag, and Au are all in Group 11 of the periodic table, known for having eleven valence electrons and being part of the d-block transition metals. They appear in various transition series (Cu in the first, Ag in the second, and Au in the third) and can form d10 coordination complexes.

The elements Cu (Copper), Ag (Silver), and Au (Gold) all belong to Group 11 of the periodic table. These metals are collectively known as the coinage metals and are characterized by having eleven valence electrons. They are part of the d-block elements, specifically included in the transition metals category. Copper is in the first transition series, silver is part of the second, and gold falls within the third. The properties of these metals, such as their high conductivities and malleability, make them highly valuable and extensively used in coins, jewelry, and electronics.

Moreover, when these elements form complexes with coordination number 2, as seen with d10 metal ions like Cut, Ag+, and Aut, they typically exhibit a linear L-M-L structure. Such configurations can be useful in various applications including the extraction of gold from its ores.

Answer:

Explanation:

You can solve this question using just some chemical facts:

Hence, since you are asked to state the solution with the highest concentration of hydroxide ions, you just pick the highest pH. This is the option d, pH = 12.59.

These mathematical relations are used to find the exact concentrations of hydroxide ions:

Then, you can follow these calculations:

Solution    pH        pOH                            [OH⁻]

a.               3.21       14 - 3.21 = 10.79        antilogarithm of 10.79 = 1.6 × 10⁻¹¹

b.               7.00      14 - 7.00 = 7.00        antilogarithm of 7.00 = 10⁻⁷

c.                7.93      14 - 7.93 = 6.07        antilogarithm of 6.07 = 8.5 × 10⁻⁷

d.               12.59     14 - 12.59 = 1.41        antilogarithm of 1.41 = 0.039

e.               9.82      14 - 9.82 = 4.18        antilogarithm of 4.18 = 6.6 × 10⁻⁵

From which you see that the highest concentration of hydroxide ions is for pH = 12.59.

The pH with the highest hydroxide ion is 12.59

pH is the degree of acidity or alkalinity in a solution.

The lower the pH, the higher the acidity.The higher the pH the higher the basicity.

When the concentration is higher, it has more hydroxide ion.

Therefore, The pH with the highest hydroxide ion is 12.59 because the higher the pH the higher the concentration of the hydroxide ion.

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Answer:

54.0 g.

Explanation:

2H₂ + O₂ → 2H₂O.

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the balanced reaction.

∴ The no. of grams in 3.0 moles of water = no. of moles x molar mass = (3.0 mol)(18.0 g/mol) = 54.0 g.

Answer:

A) 54.0 g

Explanation:

Hello! The answer to your question is 54.0 grams.

2H2 + O2 --> 2H2O

Because of that, we know our result will possess 3 significant figures.

The only sensible answer here (without the calculations) would be 54.0, due to the decimal placement. Hope this helps you!

Answer:

[tex]\boxed{\text{(C) X}$_{3}$P$_{2}}[/tex]

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

[tex]\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}[/tex]

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is [tex]\boxed{\text{X}$_{3}$P$_{2}}$}[/tex].

When something is oxidized it means that oxygen is added to it. Therefore the answer is C. Oxygen!

Hope this helped!

Oxides of nitrogen result from a combination of nitrogen and oxygen. Hence, the correct answer is C. oxygen.

Oxides of nitrogen, commonly known as nitrogen oxides or NOx, are usually formed from a combination of nitrogen and oxygen. Specifically, they refer to compounds that basically contain nitrogen and oxygen atoms, such as nitrogen monoxide (NO), nitrogen dioxide (NO₂), and nitrogen trioxide (N₂O₃).

Generally, these oxides of nitrogen are often produced during high-temperature combustion processes, such as those occurring in vehicle engines, power plants, and industrial processes. The primary source of oxygen for the formation of nitrogen oxides is atmospheric oxygen (O₂).

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Answer:

1.99 grams of methane

Explanation:

A combustion reaction always produces the product carbon dioxide and water. So the chemical equation for this reaction would be:

CH₄ + O₂ → CO₂ + H₂O

To answer this question, you need to first determine which is the excess reactant. First step is to balance the equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

Next we get the number of moles of each reactant we actually have:

8.00 g of O₂ = ? moles of O₂

You can get the number of moles, by first computing how many grams of the molecule is present in 1 mole.

O = 15.999g/mole. Since there are 2 oxygens in one mole of O₂, all you need to do is add up the atomic mass of 2 oxygens. You will get:

O₂= 31.998 g/mole

You can use this then to determine how many moles of O₂ there are in 8.00g.

[tex]8.00g\times\dfrac{1mole}{31.998g}=0.250moles[/tex]

So there are 0.250 moles of O₂ in 8.00 g of O₂.

We do the same for CH₄

4.00g of CH₄=? moles of CH₄

            C           H₄

CH₄= 12.011 + 1.008(4) = 16.043 g/mole

[tex]4.00g\times\dfrac{1mole}{16.043g}=0.249moles[/tex]

So let's sum up our new given. We now have:

0.250 moles of O₂

0.249 moles of CH₄

Next we look at the molar ratio of reactants to produce products:

CH₄ + 2O₂ → CO₂ + 2H₂O

According to this equation we can assume the following:

We need 1 mole of CH₄ for every 2 moles of O₂ in this reaction. Using what we have, we will see how much of reactant of the other reactant we need to use up the other.

[tex]0.25molesofO_{2}\times\dfrac{1moleofCH_{4}}{2molesofO_{2}}=0.125molesofCH_{4}\\\\0.249molesofCH_{4}\times\dfrac{2molesofO_{2}}{1moleofCH_{4}}=0.498molesofO_{2}[/tex]

Compare the results with what we have:

What we have                   What we need

0.250 moles of O₂   <     0.498 moles of O₂

0.249 moles of CH₄ >     0.125 moles of CH₄

This means that since we have less O₂ that what we need to use up CH₄, then O₂ is the limiting reactant and CH₄ is the excess.

To compute how much we have in excess, we use the number of moles produced when we use up limiting reactant which we did earlier and convert it into grams to determine how much in grams we used up.

Earlier we solved that we need 0.125 moles of CH₄ to use up all the O₂. Now convert that value into grams:

[tex]0.125molesofCH_{4}\times\dfrac{16.043gofCH_{4}}{1moleofCH_{4}}=2.005g of CH_{4}[/tex]

This means that 2.005g of CH₄ will be used up.

Subtract that from the CH₄ we already have:

4.00 g - 2.005 g =1.99 g of CH₄

Answer:

(a) The change in cell voltage is 0.05V

(b) The change in cell voltage is 0.03V

Explanation:

Redox reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases.

Further explanation:

The image taken in context is attached below.

The standard reduction potentials for iron and silver are:

[tex]E^o_{(Fe^{2+}/Fe)}=-0.44V\\E^o_{(Ag^{+}/Ag)}=+0.80V[/tex]

In the given cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

From the standard reduction potentials we conclude that, the substance having highest positive [tex]E^o[/tex] potential will always get reduced and will undergo reduction reaction.

So, silver will undergo reduction reaction will get reduced. Iron will undergo oxidation reaction and will get oxidized.

The given cell reactions are:

Oxidation half reaction (anode): [tex]Fe\rightarrow Fe^{2+}+2e^-[/tex]

Reduction half reaction (cathode): [tex]Ag^{+}+e^-\rightarrow Ag[/tex]

Thus, the anode and cathode will be [tex]E^o_{(Fe^{2+}/Fe)}[/tex]

and [tex]E^o_{(Ag^{+}/Ag)}[/tex] respectively.

The overall cell reaction will be,

[tex]2Ag^{+}+Fe\rightarrow Fe^{2+}+2Ag[/tex]

To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:

[tex]E^o_{cell}=E^o_{cathode}-E^o_{anode}[/tex]

[tex]E^o=E^o_{(Ag^{+}/Ag)}-E^o_{(Fe^{2+}/Fe)}[/tex]

[tex]E^o=(+0.80V)-(-0.44V)=1.24V[/tex]

Now we have to calculate the cell potential.

Using Nernst equation :

[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]

where,

n = number of electrons in oxidation-reduction reaction = 2

[tex]E_{cell}[/tex] = emf of the cell = ?

Now put all the given values in the above equation, we get:

[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(1M)}{(1M)^2}[/tex]

[tex]E_{cell}=1.24V[/tex]

Thus, the emf of cell potential is 1.24 V

Part (a):

The ion concentrations in the cathode half-cell [tex](Ag^+/Ag)[/tex] are increased by a factor of 10 from 1 M to 10 M.

The emf of the cell potential will be,

Using Nernst equation :

[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]

where,

n = number of electrons in oxidation-reduction reaction = 2

[tex]E_{cell}[/tex] = emf of the cell = ?

Now put all the given values in the above equation, we get:

[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(1M)}{(10M)^2}[/tex]

[tex]E_{cell}=1.29V[/tex]

The change in cell voltage will be,

[tex]E_{cell}=1.29V-1.24V=0.05V[/tex]

Thus, the change in cell voltage is 0.05V

Part (b):

The ion concentrations in the anode half-cell [tex](Fe^{2+}/Fe)[/tex] are increased by a factor of 10 from 1 M to 10 M.

The emf of the cell potential will be,

Using Nernst equation :

[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]

where,

n = number of electrons in oxidation-reduction reaction = 2

[tex]E_{cell}[/tex] = emf of the cell = ?

Now put all the given values in the above equation, we get:

[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(10M)}{(1M)^2}[/tex]

[tex]E_{cell}=1.27V[/tex]

The change in cell voltage will be,

[tex]E_{cell}=1.27V-1.24V=0.03V[/tex]

Thus, the change in cell voltage is 0.03V

Learn more:

Spontaneity of reaction; https://brainly.com/question/13151873 (answer by Kobenhavn)

Standard reduction potential;  https://brainly.com/question/8739272 (answer by RomeliaThurston)

Keywords:

Nernst equation, standard reduction potential, spontaneity of the reaction.

The change in the cell voltage when the ion concentrations in the ANODE half-cell are increased by a factor of 10 is 0.030  V

What is the change in the cell voltage when the ion concentrations in the ANODE half-cell are increased by a factor of 10?

The Nernst equation

[tex]E=E^o - \frac{RT}{nF} lnQ[/tex]

The given electrochemical cell has both aqueous species Fe 2 +  and  Ag +  at  1  M  concentration

If the anode concentration is increased by a factor of  10 , the cell potential will change by the correction term:  

[tex]\Delta E = -\frac{RT}{nF} lnQ[/tex]

Now we determine the overall reaction

[tex]Fe(s) -> Fe^{2+}(aq)+2e [anode]\\2*(Ag^+(aq)+e -> Ag(s)) [cathode]\\Fe(s)+2Ag^+(aq)->Fe^{2+}(aq)+2Ag(s)  [overall][/tex]

n=2 electrons were transferred

[tex]Q=\frac{[Fe^{2+}]}{[Ag^+]^2}[/tex]

The change in cell potential is

[tex]\Delta E = - \frac{RT}{nF} ln \frac{[Fe^{2+}]}{[Ag^+]^2}[/tex]

Note that [tex][Fe^{2+}]=10M[/tex] and assume that T=298.15 K

[tex]\Delta E = - \frac{8.314J/molK*298.15K}{2*96485C/mol} ln \frac{10M}{1M^2}\\\Delta E = -0.030 V[/tex]

Therefore the cell potential will decrease by 0.030 V

Grade:        9

Subject:  chemistry

Chapter:   the ion concentrations

Keywords:  the cell voltage, the ion concentrations, the cathode half-cell,   the anode, factor

Answer:

Explanation:

The relation between the momentum and the wavelength of a particle is given by De Broglie's equation:

Therefore, as per De Broglie's equation, the momentum of an electron and its wavelength are inversely related, meaning that if the momentum of an electron were doubled its wavelength would be shortened to half the original value.

The partial pressure of oxygen in a mixture with a total pressure of 800.0 mm Hg, where oxygen makes up 40% of the mixture, is 320.0 mm Hg.

To find the partial pressure of oxygen in a mixture of gases, you can use the formula P = (Patm) X (percent content in mixture). Given that the total pressure of the mixture is 800.0 mm Hg and oxygen makes up 40% of this mixture by volume, the partial pressure of oxygen can be calculated as follows:

PO2 = (800.0 mm Hg) X (0.40)

PO2 = 320.0 mm Hg

Therefore, the partial pressure of oxygen in this mixture is 320.0 mm Hg.

Answer:

= 4

Explanation:

The pH of a solution is given by;

pH = - log [H+] , while

pOH = - log [OH-]

But; pH + pOH = 14

Therefore;

pH = 14 - pOH

     = 14 - 10

     = 4

4 is the correct answer

Answer:

D: Increasing the amount of water.

Explanation:

Choice A: ­ increasing the pressure can force the liquid to stay a liquid  and affect the boiling point (decrease it).

Choice B and C: ­ both involve colligative properties, adding a solute to water will  increase the boiling point  of water.

Choice D: ­ just having more water does not change the boiling point of the water as this minimize the effect of any external factor.

So, the right choice is: D: Increasing the amount of water.

Answer:

2.38

Explanation:

119 divided by 50 =2.38

i hope you get it right :)

A neutral atom of tin has 50 protons, 50 electrons, and 69 neutrons. The number of protons and electrons is determined by the atomic number, while the number of neutrons is calculated by subtracting the atomic number from the mass number.

An atom of tin (Sn) is described by its atomic number and its mass number. The atomic number refers to the number of protons in the nucleus of the atom, and in a neutral atom, it also equals the number of electrons. Therefore, a neutral tin atom has 50 protons and 50 electrons.

The mass number, on the other hand, is the sum of protons and neutrons in the nucleus. Therefore, to find out the number of neutrons, you have to subtract the atomic number from the mass number: 119 - 50 = 69. So, a neutral tin atom has 69 neutrons.

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cl2>F2>H2

we can do this by molar mass

Hydrogen - 1

clorine - 35 x2 = 70

flourine- 18 x 2 = 36

flourine - 18

Molar mass has a direct relationship with entropy. The order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H[tex]_2[/tex].

Entropy is a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty. It has several applications in physics and chemistry, as well as in biological systems as well as how they relate to life.

The phrase and the idea are employed in many different contexts, including information theory and classical thermodynamics. Molar mass has a direct relationship with entropy. The order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H[tex]_2[/tex].

Therefore, the order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H.

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-59 kj/mol exothermic

The enthalpy change for the reaction of ethylene with hydrogen bromide to form ethyl bromide is -59 kJ/mol. This means that the reaction is exothermic, meaning that it releases heat.

The bond energies of the relevant bonds are as follows:

C-C bond energy: 347 kJ/mol

C-H bond energy: 413 kJ/mol

H-Br bond energy: 363 kJ/mol

C-Br bond energy: 276 kJ/mol

Reactants:

Ethylene: 2 C-H bonds + 1 C-C bond

Hydrogen bromide: 1 H-Br bond

Products:

Ethyl bromide: 3 C-H bonds + 1 C-C bond + 1 C-Br bond

Enthalpy change:

ΔH = Σ(bond energies broken in reactants) - Σ(bond energies formed in products)

ΔH = (2 × 413 kJ/mol + 1 × 347 kJ/mol) - (1 × 363 kJ/mol + 3 × 413 kJ/mol + 1 × 276 kJ/mol)

ΔH = -59 kJ/mol

Therefore, the enthalpy change for the reaction of ethylene with hydrogen bromide to form ethyl bromide is -59 kJ/mol. This means that the reaction is exothermic, meaning that it releases heat.

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the burning of ethanon is an exothermic reaction.

exothermic = releases heat.

knowing this, we can see that the atoms are released into the atmosphere, it then reacts with oxygen, producing cardon dioxide, water, and heat.

Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, the correct option is option A.

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

q = n ×ΔH

where

q = amount of heat

n = no of moles

ΔH = enthalpy

n = w / M.M

w = given mass

M.M = molar mass

A) C₆H₆

melting point =5.5° C

boiling point =80.1 ° C

Heat of fusion = 9.92 kJ/mol

Heat of vaporization =30.8kJ/mol

B) CH₃CH₂CH₂CH₂CH₂COH₆ is solid

C) NaCl is solid

D) NH₃

melting point = -77.73 °C

boiling point =  -33.34 °C

Therefore, the correct option is option A.

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Answer:

[tex]\boxed{\text{B. HC}}[/tex]

Explanation:

The blow-by gases that escape past the piston rings and get into the crankcase are mostly unburned fuel-air mixture.

The fuel is largely a mixture of hydrocarbons (HCs) .

The PCV system captures these gases and feeds them back to the cylinder for further combustion.

A. is wrong. Carbon dioxide exits through the exhaust.

C. is wrong. Most of the oxygen in the incoming air is used for combustion in the cylinders.

D is wrong. The NOx gases exit via the exhaust and are trapped by the catalytic converter.

The balanced equation for the dissociation of chromium(III) nitrate in water is Cr(NO3)3 (s) → Cr3+ (aq) + 3 NO3- (aq), illustrating the separation into chromium(III) ions and nitrate ions.

The balanced equation that describes the dissociation of chromium(III) nitrate in water is as follows:

Cr(NO3)3 (s) → Cr3+ (aq) + 3 NO3− (aq)

When chromium(III) nitrate dissolves in water, it separates into chromium(III) ions and nitrate ions. Each formula unit of the solid compound yields one chromium(III) ion and three nitrate ions. The equation is balanced with respect to both mass and charge, fulfilling the law of conservation of mass and the principle of electroneutrality.

To describe the process, it is important to note that chromium(III) nitrate is a salt, and like most salts, it dissociates completely in water to give its constituent ions.

Answer:

Conserved

Explanation:

In balancing nuclear reaction equations, there is conservation of mass numbers and atomic numbers, i.e the sum of the mass number on the product side must be equal to the sum of mass numbers on the reactant side.

Also, the sum of the atomic numbers on the product side must be equal to the sum of the atomic numbers on the reactant side.

Note: A nuclear reaction is a process in which a nucleus reacts with an elementary particle.