Which of the following substance is not an acid?

Substance A is tested and found to have a pH of 3.
Substance B, a common food, tastes sour.
Substance C causes metals to corrode.
Substance D feels slippery in solution.

Answer : The number of moles of [tex]CO_2[/tex] produced are, 70 moles

Solution : Given,

Moles of [tex]C_2H_2[/tex] = 35 mole

Moles of [tex]O_2[/tex] = 84 mole

The balanced chemical reaction will be,

[tex]2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O[/tex]

From the balanced reaction, we conclude that

As, 2 moles of acetylene react completely to give 4 moles of carbon dioxide

So, 35 moles of acetylene react completely to give [tex]\farc{4}{2]\times 35=70[/tex] moles of carbon dioxide

Therefore, the number of moles of [tex]CO_2[/tex] produced are, 70 moles

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

[tex]2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)[/tex]

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

[tex]35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})[/tex]

= [tex]70molCO_2[/tex]

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

[tex]35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})[/tex]

= [tex]87.5molO_2[/tex]

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

[tex]84.0molO_2(\frac{4molO_2}{5molO_2})[/tex]

= [tex]67.2molCO_2[/tex]

Oxygen is your answer

Cracking of hydrocarbons involves thermal decomposition.
This means that large hydrocarbon molecules break into
smaller molecules when they are heated. The hydrocarbons
are boiled and the hydrocarbon gases are either
mixed with steam and heated to a very high temperature or
passed over a hot powdered aluminium oxide catalyst.
The catalyst works by providing the hydrocarbon gases
with a convenient surface for the cracking to take place.

For example, decane (an alkane with 10 carbons)
can be cracked to produce octane and ethene.

decane             octane    +   ethene.
C10H22(g)          C8H18(g)  +   C2H4(g)

Octane is used as petrol.
Ethene is used in the manufacture of polymers.

Cracking an alkane produces a smaller alkane plus an alkene.
If you add up the number of hydrogen atoms in the
above reaction, you will see that there are 22 on each side.
An alkene is produced because the original alkane does
not have enough hydrogen atoms to produce two more alkanes.

hope this helps 

Decane (C₁₀H₂₂) is not typically used to produce polyethylene (poly(ethene)). Polyethylene is produced from ethylene (C₂H₄) monomers.

Polyethylene, a widely used plastic, is produced through a polymerization process using ethylene monomers. The process typically involves the use of a catalyst, such as a Ziegler-Natta catalyst or a metallocene catalyst, along with specific reaction conditions.

These conditions include elevated temperatures, typically ranging from 150 to 300 degrees Celsius, and high pressures, typically ranging from 1000 to 3000 atmospheres.

These conditions are necessary to initiate and facilitate the polymerization reaction, allowing the ethylene monomers to join together and form the long chains characteristic of polyethylene. Decane (C₁₀H₂₂), which is an alkane, is not commonly used as a raw material for polyethylene production.

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Answer:  AIP  

There are two types of substances mixture and pure substance. Mixture has NO chemical formula and a pure substance has a chemical formula. There are two types of pure substances, elements (mono atomic and molecular) and compounds ( covalent and ionic).  

Ionic compounds do not exist in independent molecular form. They form three dimensional crystal lattice, in which each ion is surrounded by oppositely charged ion.  so the ratio of ion is called the formula unit  

The correct formula units among the given options are AlP and ClO. These are formula units that accurately reflect the balanced charges of the atoms involved. PbCl and Li3Al are not correct.

In the context of this question, a correct formula unit is one that accurately represents a compound where the total charge is balanced to zero. This is a fundamental concept in chemistry when dealing with ionic compounds. Here, PbCl, AlP, Li3Al, and ClO have been mentioned.

The formula PbCl is incorrect. For Lead (II) Chloride, the correct formula would be PbCl2, as lead has a +2 charge and chloride has a -1 charge. So we need two chlorides for every lead to balance the charges.

The formula AlP is correct. It represents Aluminum Phosphide, where aluminum has a +3 charge and phosphide a -3 charge.

Li3Al is incorrect as lithium has a charge of +1 and aluminum a charge of +3, so the correct formula should be LiAl.

Finally, ClO is correct, representing Hypochlorite, where chlorine has a charge of +1 and oxygen a charge of -2, so the charges are balanced.

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B) 2n2 + h2 -> 3nh3 is your answer

The equation 5(x-9)=5x has no solution as the simplified equation results in a statement that is not true (-45 does not equal 0). Therefore, the answer is 'No Solution'.

The equation given is 5(x-9)=5x. To determine the number of solutions for this equation, we start by simplifying the given equation. Distributing 5 to the expression in the parentheses on the left side of the equation gives us 5x-45. When rewritten, the equation is: 5x-45=5x.

If we subtract 5x from both sides to solve for x, it results in -45=0. Since -45 does not equal 0, this equation has No Solution.

Therefore, answer A is correct.

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The term 'electron cloud' pertains to the quantum mechanical model, which posits that electrons exist in cloud-like regions around the nucleus, where they are most likely to be located. This contrasts with Bohr's model in which electrons move in defined orbits.

The term “electron cloud” describes the quantum mechanical model, explaining the location of electrons. In the quantum mechanical model, the electrons are not considered as particles moving in defined orbits (unlike in Bohr's model), but as a cloud-like region around the nucleus where they are most likely to be found.

This model gives a probabilistic description of an electron’s location, known as an electron cloud, where the electron can be anywhere in this cloud. While the Bohr model was a significant step in understanding the atom, it has its limitations and doesn't incorporate the concept of electron cloud.

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Answer: The correct answer is positive ion.

Explanation:

Ions are formed when an atom looses or gain electrons.

When an atom looses its electron, it results in the formation of a positive ion which is known as cation and when an atom gains electron, it results in the formation of a negative ion known as anion.

In the question, when potassium gave up an electron, it resulted in the formation of a positive ion which is [tex]K^+[/tex] ion.

Thus, the correct answer is positive ion.

The resulting force of the given two forces in the same direction is equal to 25N.

When an object is subject to many forces, the resultant force is the one that alone produces the same acceleration as all those forces. To determine the effect that various forces have on an object is only need one single force.

The mass 'm' of an object and the acceleration produced by the several forces that act on it, the resultant force using according to Newton's Second Law, the force F,

F = ma

and the resultant force,  R = ma

When an object is subject to several forces, F₁, F₂,......., the resultant force R is the vector sum of all these forces:

R = F₁ + F₂ + F₃........

When two forces act in the same direction, the resultant force has a magnitude equal to the sum of the magnitudes of those two forces.

Given, F₁ = 10 N and F₂ = 15 N

The resultant force, F =  F₁ + F₂ = 10 + 15 = 25 N

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For the answer to the question above, we must use the given conversion factor which is

1 quart = 0.943 liters

Now let us solve,

2.50L×(1 quart / 0.943L)

So the answer to this problem is,

=2.65quarts

The gas and liquid are at equilibrium.

In an electrically neutral atom of nickel there are 28 protons and 31 neutrons.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

0.106 moles

Explanation:

weight of substance = 5.96 g

molar mass of KOH = 39 + 16 + 1

                                 = 56 g

number of moles = weight of substance/ molar mass of substance

                             =  5.96/56

                             =  0.106 moles

Answer:

0.106

Explanation:

Answer:The half-life of an element is 20 days.

Explanation:

Radioactive decay of reaction follows first order kinetics, and  half life of an element is given as:

[tex]t_{\frac{1}{2}}=\frac{0.693}{\lambda }[/tex]

[tex]\lambda [/tex]= Decay constant

Decay constant of an element= [tex]\lambda = 3.411\%=0.03411 (day)^{-1}[/tex]

[tex]t_{\frac{1}{2}}[/tex] = half-life of an element

[tex]t_{\frac{1}{2}}=\frac{0.693}{0.03411 (day)^{-1}}[/tex]

[tex]t_{\frac{1}{2}}=20.31 days\approx 20 days[/tex]

Hence, the half-life of an element is 20 days.

The half-life of the element that decays at a rate of 3.411% per day is 20.3 days.

The half-life can be calculated using the formula:

Half-life (t1/2) = (0.693 / decay rate)

Given that the element decays at a rate of 3.411% per day, we can convert this to a decimal by dividing by 100. So, the decay rate is 0.03411. Substituting this value into the formula:

Half-life (t1/2) = (0.693 / 0.03411) = 20.3 days

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Among the options, Kr, representing krypton, is the noble gas. Noble gases are found in the right-most column of the periodic table.

The question asks which of the given elements is a noble gas. Noble gases are a group of chemical elements with similar properties on the rightmost column of the periodic table. These gases are helium, neon, argon, krypton, xenon, and radon. In relation to your options, the correct answer is (d) Kr, which represents krypton. Krypton is indeed a noble gas, while rb (rubidium), mn (manganese), and cl (chlorine) are not.

Answer: The element having partially filled f-orbital is Samarium (Sm)

Explanation:

Maximum number of electrons that can be filled in f-orbital are 14. So, for the element having 14 electrons in the f-orbital will be considered as fully-filled and the element having 7 electrons in the f-orbital will be considered as half-filled.

It will be judged by electronic configuration of the elements.

For the given options:

The atomic number of  samarium is 62 and number of electrons that are present are 62. The electronic configuration of samarium is:

[tex]Sm:[Xe]4f^66s^2[/tex]

As, this element has electrons in f-orbital. Thus, this has partially filled f-orbital.

The atomic number of osmium is 76 and number of electrons that are present are 76. The electronic configuration of osmium is:

[tex]Os:[Xe]5d^56s^2[/tex]

As, this element does not have electrons in f-orbital. Thus, this does not has partially filled f-orbital.

The atomic number of barium is 56 and number of electrons that are present are 56. The electronic configuration of barium is:

[tex]Ba:[Xe]6s^2[/tex]

As, this element does not have electrons in f-orbital. Thus, this does not has partially filled f-orbital.

The atomic number of bismuth is 83 and number of electrons that are present are 83. The electronic configuration of bismuth is:

[tex]Bi:[Xe]6s^26p^3[/tex]

As, this element does not have electrons in f-orbital. Thus, this does not has partially filled f-orbital.

Hence, the correct answer is samarium (Sm).

Answer :

(1) The net ionic equation will be,

[tex]H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)[/tex]

(2) The net ionic equation will be,

[tex]2H^+(aq)+SO_3^{2-}(aq)\rightarrow H_2O(l)+SO_2(g)[/tex]

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(1) The balanced ionic equation will be,

[tex]HClO_4(aq)+Ca(OH)_2(aq)\rightarrow Ca(ClO_4)_2(aq)+2H_2O(l)[/tex]

The ionic equation in separated aqueous solution will be,

[tex]H^+(aq)+ClO_4^-(aq)+Ca^{2+}(aq)+2OH^-(aq)\rightarrow Ca^{2+}(aq)+2ClO_4^-(aq)+2H_2O(l)[/tex]

In this equation, [tex]Ca^{2+}\text{ and }ClO_4^-[/tex] are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)[/tex]

(2) The balanced ionic equation will be,

[tex]H_2SO_4(aq)+Li_2SO_3(aq)\rightarrow Li_2SO_4(aq)+H_2O(l)+SO_2(g)[/tex]

The ionic equation in separated aqueous solution will be,

[tex]2H^+(aq)+SO_4^{2-}(aq)+2Li^+(aq)+SO_3^{2-}(aq)\rightarrow 2Li^+(aq)+SO_4^{2-}(aq)+H_2O(l)+SO_2(g)[/tex]

In this equation, [tex]Li^+\text{ and }SO_4^{2-}[/tex] are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

[tex]2H^+(aq)+SO_3^{2-}(aq)\rightarrow H_2O(l)+SO_2(g)[/tex]

Answer:

The chemical formula for Tin(IV)Phosphate is Sn3(PO4)4

Explanation:

The chemical formula for tin (IV) phosphate is Sn3(PO4)4. According to the Royal Society of Chemistry, tin (IV) phosphate is an ionic compound with a 736.0154 g/mol. molar mass.

This chemical compound is made up of three tin (IV) ions, bound ionically to four phosphate ions. Each tin (IV) ion has a 4+ charge. Each PO4, or phosphate ion, is a tetrahedral molecule, containing a central phosphorous atom that has a double bonded oxygen and three negatively charged oxygen attached.Therefore, each phosphate ion has a 3- charge. For tin (IV) phosphate, the sum of all positive and negative charges equal zero.

The chemical formula for Tin(IV)Phosphate is Sn₃(PO₄)₄ as the valencies of tin and phosphate ion are 4 and 3 respectively.

Chemical  formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols  of elements. It also makes use of brackets and subscripts.

Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form  is called empirical formula.

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Ionic bonding involves transfer of electrons while covalent bonding involves sharing. Robert Boyle is the scientist who observed gas behavior and acids are corrosive to metals. Different types of matter do melt at different temperatures.

The correct answers here are: 1. A. transfer, sharing. Ionic bonding indeed involves the transfer of electrons from one atom to another, resulting in positively and negatively charged ions that are attracted to each other. In contrast, covalent bonding involves the sharing of electrons between atoms.

2. B. Boyle. Robert Boyle is the scientist who found that gas expands to fill the space of a container and is composed of particles that can move. This is known as Boyle's law.

3. B. corrosive. When acids come into contact with metals, they can often be corrosive, causing the metal to deteriorate.

4. True, different types of matter indeed melt at different temperatures. This is part of the fundamental understanding of different states of matter.

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Answer:

The answer is (1) Hg

Explanation:

Hg is mercury. It is a metal, so the elemental substance have Hg atoms that interact each other by metallic bonds.

The other options do not contain metallic bonds:

(2) H₂O is water, and contains covalent bonds

(3) NaCl is sodium chloride and is a ionic compound (ionic bonds)

(4) C₆H₁₂O₆ is glucose, and the atoms are covalently bonded.

Answer: (1) [tex]Hg[/tex]

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals. Example: [tex]H_2O[/tex] and [tex]C_6H_{12}O_6[/tex]

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal. Example: [tex]NaCl[/tex]

Metallic bond is defined as the bond which is formed between positively charged atoms having free electrons and are shared among a lattice of cations. This is usually formed between metals. Example: [tex]Hg[/tex]

Answer:

Part A:

Average oxidation state of vanadium is 2.38.

Part B:

Percentage of the vanadium atoms are in the lower oxidation state=62%

Explanation:

Part A:

1 atom vanadium(V) combines with 1.19 atoms of O to form [tex]VO_{1.19[/tex].

Formula:

[tex]\sum(Oxidation\ number\ of\ atoms\ in\ molecule* Number\ of\ atoms)=Oxidation\ number\of\ molecule[/tex]

In our Case:

Note: Oxidation number of O is always -2

[tex](Oxidation\ number\ of\ V* Number\ of\ atoms\ of\ vanadium)+(Oxidation\ number\ of\ O* Number\ of\ atoms\ of\ Oxygen)=Oxidation\ Number\ of\ VO_{1.19}\\\\(Oxidation\ number\ of\ V* 1)+(-2* 1.19)=Oxidation\ Number\ of\ VO_{1.19}\\\\\\Since, Oxidation\ Number\ of\ VO_{1.19}\ is\ 0\ as\ it\ is\ neutral\ molecule.\\(Oxidation\ number\ of\ V* 1)+(-2* 1.19)=0\\Oxidation\ number\ of\ V=2.38[/tex]

Average oxidation state of vanadium is 2.38.

Part B:

Let's say we have total 100 atoms of vanadium, a will show +2 oxidation state while (100-a) will show +3 oxidation state.

Now:

[tex]Total\ Atoms* Average\ oxidation\ number\ of\ Vanadium=(Oxidation\ number* Number\ of\ atoms\ of\ with\ +2\ oxidation\ number )+(Oxidation\ number* Number\ of\ atoms\ of\ +3\ oxidation\ number)\\\\100*\ Average\ oxidation\ number\ of\ Vanadium\ = \ (+2*a)+[+3*(100-a)]\\100*2.38=2a+300-3a\\\\a= 62 atoms (+2\ oxidation\ state)[/tex]

[tex]Percentage=\frac{62}{100}*100\ =62\%[/tex]

Percentage of the vanadium atoms are in the lower oxidation state=62%

c. deceives others, whether intentionally or unintentionally

An unreliable narrator is a reciter whose reliability has been severely discredited. Wayne C. Booth in The Rhetoric of Fiction 1961 has discovered the term unreliable narrator. While untrustworthy storytellers are first-person narrators, whereas evidence has been made for the occurrence of unreliable second- and third-person narrators, primarily within the circumstances of film and television, although sometimes also in history.

In chemistry, a trisubstituted cyclohexane compound in chair conformation can be depicted by drawing wedge-and-dash bonds to show the positions of the substituents on a flat piece of paper. It's crucial to include hydrogen atoms on asymmetric carbons and ensure the stereochemistry is accurately depicted by drawing both wedge/dash bonds on the outside of the ring.

A trisubstituted cyclohexane compound in its chair conformation can be represented in a planar format using wedge-and-dash bonds to indicate the positions of the substituents. This method is used to represent three-dimensional molecular structures on a two-dimensional plane. We use wedge bonds to represent bonds that project out of the plane of the paper towards the viewer, and dash bonds to represent bonds that extend behind the plane of the paper away from the viewer.

For a proper representation, the hydrogen atoms have to be included on the chirality centers (asymmetric carbons). The stereochemistry of the molecule is maintained when both the wedge/dash bonds are drawn on the outside of the ring. Otherwise, it may be interpreted as square planar which is structurally different. To best understand this, practicing drawing out the structure following these guidelines would be helpful.

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To draw the chair conformation of a trisubstituted cyclohexane compound, follow the steps provided.

To draw the chair conformation of a trisubstituted cyclohexane compound, follow these steps:

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