Which of the following statements is incorrect concerning the thermochemical equation below? 2SO3(g) → 2SO2(g) + O2(g); ΔH° = 198 kJ a. The enthalpy of the reactants exceeds that of the products. b. For the reaction 2SO2(g) + O2(g) → 2SO3(g), ΔH° = –198 kJ. c. The reaction is endothermic. d. The external pressure is 1 atm. e. For every mole of SO3(g) consumed, 99 kJ of heat at constant pressure is consumed as well.

Answer:

2.165 x 10^3 nm.

Explanation:

Using Rybergs equation,

1/lambda = R * (1/n1^2 - 1/n2^2)

Where,

R = rybergs constant = 109737.32 cm^-1

n1 = 7

n2 = 4

= 109737.32 * (1/7^2 - 1/4^2)

= 4619.05

Lambda = 2.165 x 10^-4 cm

Since 100 cm = 1m, 1 nm = 10^-9 m

= 2.165 x 10^-4 cm * 1 m/100 cm * 1 nm/10^-9 m

= 2.165 x 10^3 nm.

Explanation:

Reaction is first order.

Rate Constant (k) = 5.11x10-5s-1

Temperature = 472k

Initial Concentration = 3.00×10-2M

(A) What is the half-life (in hours) of this reaction?

Formular for half life of a first order reaction is;

t1/2 = 0.693 / k

t1/2 = 0.693 / (5.11x10-5)

t1/2 = 0.1386 x 10 ^ 5 s

Upon converting to hours by dividing the value by 3600;

t1/2 = (0.1386 x 10 ^ 5) / 3600 = 3.85 hours

(B) How many hours will it take for the concentration of methyl isonitrile to drop to 6.25% of its initial value?

6.25% of initial concentration;

(6.25 / 100) * 3.00×10-2 = 0.1875 x 10 ^ -2M

ln[A] = ln[A]o − kt

[A] = Final Concentration

[A]o = Initial Concentration

upon making t subject of interest;

t = (ln[A]o - ln[A] ) / k

Inserting the values;

t = [  In(3.00×10-2) - In(0.1875 x 10 ^ -2) ] / 3.85

t = 2.7726 / 3.85

t = 0.72 hours

Answer :

(a) Number of orbitals in an atom = 1

(b) Number of orbitals in an atom = 5

(c) Number of orbitals in an atom = 3

(d) Number of orbitals in an atom = 9

Explanation :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as [tex]m_l[/tex]. The value of this quantum number ranges from [tex](-l\text{ to }+l)[/tex]. When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as [tex]m_s[/tex]. The value of this is [tex]+\frac{1}{2}[/tex] for upward spin and [tex]-\frac{1}{2}[/tex] for downward spin.

Number of orbitals in an atom = (2l+1)

(a) 1s

n = 1

The value of 'l' for 's' orbital is, l = 0

Number of orbitals in an atom = (2l+1) = (2×0+1) = 1

(b) 4d

n = 4

The value of 'l' for 'd' orbital is, l = 2

Number of orbitals in an atom = (2l+1) = (2×2+1) = 5

(c) 3p

n = 1

The value of 'l' for 'p' orbital is, l = 1

Number of orbitals in an atom = (2l+1) = (2×1+1) = 3

(a) n = 3

l = 0, 1, 2

Number of orbitals for (l = 0) = (2l+1) = (2×0+1) = 1

Number of orbitals for (l = 1) = (2l+1) = (2×1+1) = 3

Number of orbitals for (l = 2) = (2l+1) = (2×2+1) = 5

Number of orbitals in an atom = 1 + 3 + 5 = 9

For the designations (a) 1s, there is one orbital; (b) 4d, there are five orbitals; (c) 3p, there are three orbitals; (d) n = 3, there are nine orbitals in total including s, p, and d subshells.

The number of orbitals in an atom that can have specific designations depends on the quantum numbers, particularly the principal quantum number (n) and the angular momentum quantum number (l). Here is the breakdown for each given designation:

Answer:

We need 7.01 grams of KOH (option 5)

Explanation:

Step 1: Data given

Volume aqueous KOH solution = 250 mL = 0.250 L

Molarity = 0.500 M

Molar mass of KOH = 56.10 g/mol

Step 2: Calculate moles KOH

Moles KOH = molarity * volume

Moles KOH = 0.500 M * 0.250 L

Moles KOH = 0.125 moles

Step 3: Calculate mass of KOH

Mass KOH = moles KOH * molar mass KOH

Mass KOH = 0.125 moles * 56.10 g/mol

Mass KOH = 7.01 grams

We need 7.01 grams of KOH

Answer:

4.94°C, the temperature for freezing the solution

Explanation:

Freezing point depression to solve this.

Formula = T° freezing pure solvent - T° freezing solution = Kf . m

With the data given, let's determine m (molality)

Molality → mol/kg (moles of solute in 1kg of solvent)

We need to convert the 344 g to kg → 344 g . 1kg/1000 g = 0.344 kg

Let's determine the moles of solute (naphtalene)

5 g / 128 g/mol = 0.039 mol

Molality → 0.039 mol / 0.344 kg → 0.113

Let's go back to the formula:

5.5°C - T° freezing of solution = 4.90°C /m. 0.113 m

T° freezing of solution = - ( 4.90°C /m. 0.113 m - 5.5°C)

T° freezing of solution =  4.94 °C

The freezing point of the solution is 4.94 °C.

The term freezing point refers to the point in which a liquid is converted to a solid.

We know that;

ΔT = K m i

K = freezing constant

m = molality of the solution

i = Van't Hoff factor

ΔT = 4.90°C/m × (5.00 g /128 g/mol)/0.344 Kg × 1

ΔT =0.56°C

Freezing point of solution = 5.5°C - 0.56°C = 4.94 °C

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Answer:

a and b are correct

Explanation:

This because both are aqueous solutions,therefore, identity of solvent is same that is water.

And because both solutions are non electrolyte they would not ionize in solution, and for the same concentration, the freezing point of both solution would also be  same. Since depression in freezing point is a colligative property this means that it depends on number of solute particles not nature of particles .

Hence answer is that  their freezing points and  Identity of the solvent shall remain the same.

Answer : The number of mmol of bromobenzene is, 20.6 mmol

Explanation :

The balanced chemical reaction will be:

[tex]C_6H_5Br+HNO_3\rightarrow C_6H_4NO_2Br[/tex]

First we have to calculate the moles of p-bromonitrobenzene.

Moles of p-bromonitrobenzene =[tex]\frac{\text{ given mass of p-bromonitrobenzene}}{\text{ molar mass of p-bromonitrobenzene}}[/tex]

Molar mass of p-bromonitrobenzene = 202 g/mol

Moles of p-bromonitrobenzene = [tex]\frac{4.17g}{23g/mole}=0.0206moles[/tex]

Now we have to calculate the mmol of bromobenzene.

From the balanced chemical reaction we conclude that,

As, 1 mole of p-bromonitrobenzene produced from 1 mole of bromobenzene

So, 0.0206 mole of p-bromonitrobenzene produced from 0.0206 mole of bromobenzene

Moles of bromobenzene = 0.0206 moles = 20.6 mmol

Conversion used : 1 moles = 1000 mmol

Thus, the number of mmol of bromobenzene is, 20.6 mmol

To find out how many millimoles of bromobenzene were used to synthesize 4.17 grams of p-bromonitrobenzene, divide the mass of p-bromonitrobenzene by its molecular weight (202 g/mol) and convert the result to millimoles, yielding 20.6 mmoles.

If you synthesized 4.17 grams of p-bromonitrobenzene, the number of millimoles (mmoles) of bromobenzene you started with can be calculated using the molecular weight of p-bromonitrobenzene. The molecular weight of p-bromonitrobenzene (C6H4BrNO2) is approximately 202 g/mol. Assuming 100% conversion, the moles of p-bromonitrobenzene synthesized would be the mass of the final compound divided by its molecular weight.

Number of moles =  rac{4.17 g}{202 g/mol} = 0.0206 moles

Since 1 mole equals 1000 mmoles, the amount in mmoles would be:

Number of mmoles = 0.0206 moles  imes 1000 = 20.6 mmoles

Therefore, you would have started with 20.6 mmoles of bromobenzene to synthesize 4.17 grams of p-bromonitrobenzene assuming 100% conversion in the reaction.

Answer : All possible values of 'ml' for the following orbitals are:

(a) At l = 3,  [tex]m_l=+3,+2,+1,0,-1,-2,-3[/tex]

(b) l = 0, 1

At l = 0,  [tex]m_l=0[/tex]

At l = 1,  [tex]m_l=+1,0,-1[/tex]

(c) At l = 1,  [tex]m_l=+1,0,-1[/tex]

Explanation:

There are 4 quantum numbers :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from [tex](-l\text{ to }+l)[/tex]. When l = 2, the value of [tex]m_l[/tex] will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as [tex]m_s[/tex]The value of this is [tex]+\frac{1}{2}[/tex] for upward spin and [tex]-\frac{1}{2}[/tex] for downward spin.

(a) l = 3 then the value of 'ml' is,

At l = 3,  [tex]m_l=+3,+2,+1,0,-1,-2,-3[/tex]

(b) n = 2 then the value of 'ml' is,

l = 0, 1

At l = 0,  [tex]m_l=0[/tex]

At l = 1,  [tex]m_l=+1,0,-1[/tex]

(c) n = 6 and l = 1 then the value of 'ml' is,

n = 6

l = 0, 1, 2, 3, 4, 5

At l = 1,  [tex]m_l=+1,0,-1[/tex]

The  orbital refers to a region in space where there is a high probability of finding an electron.

The term orbital refers to a region in space where there is a high probability of finding an electron. Within each energy level, there are orbitals.

Let us consider each of the levels shown;

(a) l = 3

The ml values for this orbital are; -3, -2, -1, 0, 1, 2, 3

(b) n = 2

The ml values for this orbital are; -1, 0, 1

(c) n = 6, l = 1

The ml values for this orbital are; -1, 0, 1

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Answer:

a) Mg

b) Cl

c) Mn

d) Ne

Explanation:

This electron configuration for the atom in its excited state violates the Aufbau principle or rule like we have above.

Aufbau principle states "that in the ground state of an atom or ion, electrons fill atomic orbitals of the lowest available energy levels before occupying higher levels."

We however can know and identify which element is in the excited state by knowing the sum of the electron that spread across the orbital and matching it up with the atomic number of the element in the periodic table.

The electron configurations given represent atoms in excited states. By identifying the element and writing its condensed ground-state configuration, we can gain information about the energies of unoccupied orbitals in the atom's ground state.

(a) The electron configuration 1s²2s²2p⁶3s¹3p¹ represents an atom in an excited state. By looking at the electron configuration, we can identify the element as silicon (Si). The condensed ground-state configuration for silicon is 1s²2s²2p⁶3s²3p².

(b) The electron configuration 1s²2s²2p⁶3s²3p⁴4s¹ represents an atom in an excited state. The element can be identified as sulfur (S). The condensed ground-state configuration for sulfur is 1s²2s²2p⁶3s²3p⁴.

(c) The electron configuration 1s²2s²2p⁶3s²3p⁶4s²3d⁴4p¹ represents an atom in an excited state. This electron configuration belongs to the element zinc (Zn). The condensed ground-state configuration for zinc is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰.

(d) The electron configuration 1s²2s²2p⁵3s¹ represents an atom in an excited state. From this configuration, we can identify the element as nitrogen (N). The condensed ground-state configuration for nitrogen is 1s²2s²2p³.

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Answer: The volume of NaOH required to reach the endpoint is 100 mL

Explanation:

To calculate the volume of NaOH, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]CH_3COOH[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=1\\M_1=0.250M\\V_1=50.0mL\\n_2=1\\M_2=0.125M\\V_2=?mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.250\times 50.00=1\times 0.125\times V_2\\\\V_2=\frac{1\times 0.250\times 50.0}{1\times 0.125}=100mL[/tex]

Hence, the volume of NaOH required to reach the endpoint is 100 mL

Answer:

% yield = 73.48 %

Explanation:

The fermentation reaction is:

C₆H₁₂O₆  →  2C₂H₅OH + 2CO₂          

The percent yield of C₂H₅OH is given by:

[tex] \% yield = \frac{m_{E}}{m_{T}} * 100 [/tex]

where [tex]m_{E}[/tex]: is the obtained mass of C₂H₅OH = 67.7g and [tex]m_{T}[/tex]: is the theoretical mass of C₂H₅OH.    

The theoretical mass of C₂H₅OH is calculated knowing that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH:  

[tex] m_{T} = mol * M [/tex]

where M: is the molar mass of C₂H₅OH =  46.068 g/mol

[tex] m_{T} = 2 moles * 46.068 g/mol = 92.136 g [/tex]                

Hence, the percent yield of C₂H₅OH is:

[tex] \% yield = \frac{67.7 g}{92.136 g}*100 = 73.48 \% [/tex]

I hope it helps you!                  

Taking into account definition of percent yield, the percent yield for the reaction is 73.58%.

In first place, the balanced reaction is:

C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theoretical yield} x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yield:

[tex]percent yield=\frac{67.7 g}{92 g} x100[/tex]

Solving:

percent yield= 73.58%

Finally, the percent yield for the reaction is 73.58%.

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Answer:A, C, D, E, F

Explanation:

A. True: Oxidizing agents are electron acceptors. They accept electrons and the get reduced. This means their oxidation number reduces

B. False: Reducing agents do not accept H+ ions. Reducing agents remove oxygen from another substance or give hydrogen to it.

C. True: oxidizing agents oxidizes other molecules but they accept electrons and get reduced themselves. If a molecule accepts electrons it has been reduced.

D True: Redox reactions MAY and may not involve the transfer of hydrogen ions depending on the reactants (H+). But redox in terms of acid and base means the donating and receiving of protons(H+)

E. True: A molecule that has gained H atoms is said to be reduced. Oxidizing agents are always the proton acceptor.

F. True: Oxidizing agents May and may not accept H+. In terms of acid and base oxidizing agents accept protons(H+)

Regarding redox reactions, statements C, D, and E are generally true. Statement B and F can be true in specific scenarios but not universally, while statement A is incorrect because oxidizing agents actually donate electrons.

In redox reactions, oxidation and reduction occur simultaneously. We look at the given statements:

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Answer:

a) The limiting reactant is O2.

b) 7.57 grams of P4O10 is produced

c) 7.53 grams P4O6 remains

Explanation:

Step 1: Data given

Mass of P4 = 7.55 grams

Mass of O2 = 7.55 grams

Molar mass of P4 = 123.90 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equations:

P4 + 3O2-→P4O6

P4O6 + 2O2 → P4O10

Step 3: Calculate moles P4

Moles P4 = mass P4 / molar mass P4

Moles P4 = 7.55 grams / 123.90 g/mol

Moles P4 = 0.0609 moles

Step 4: Calculate moles O2

Moles O2 = 7.55 grams / 32.0 g/mol

Moles O2 = 0.236 moles

Step 5: Calculate the limiting reactant

For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6

P4 is the limiting reactant. It will completely be consumed. (0.0609 moles)

O2 is in excess. There will react 3*0.0609 = 0.1827 moles

There will remain 0.236 - 0.1827 = 0.0533 moles O2

Step 6: Calculate moles P4O6

For 1 mol P4 we need 3 moles O2 to produce 1 mol P4O6

For 0.0609 moles P4 we will have 0.0609 moles P4O6

Step 7: Calculate limting reactant

There remain 0.0533 moles O2 and there are 0.0609 moles P4O6 produced

For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O6

The limiting reactant is O2. It will completely be reacted (0.0533 moles)

There will react 0.0533/2 = 0.02665 moles

There will remain 0.0609 - 0.02665 = 0.03425 moles P4O6

This is 0.03425 moles * 219.88 g/mol = 7.53 grams P4O6

Step 8: Calculate moles P4O10

For 1 mol P4O6 we need 2 moles O2 to produce 1 mol P4O6

For 0.0533 moles O2, we'll have 0.0533/2 = 0.02665 moles P4O10

Step 9: Calculate mass P4O10

Mass P4O10 = 0.02665 moles * 283.89 g/mol

Mass P4O10 = 7.57 grams

Answer:

- 7.4 ºC

Explanation:

The change in melting  temperature is given by:

ΔTm = Kf m

where kf is the molal freezing  point depresion  constant, and m is the molality.

The molality of a solution is calculated as

m = mol solute/ kg solvent

Since we have the % composition it is easy to calculate the molality :

In 100 g of solution we have  24.9 ethylene glycol

mol glycol = 24.9 g / 62.07 g/ mol = 0.40 mol

molality = 0.40 mol / 0.1 kg = 4 m

Km for water is 1.86 ºC/m,

therefore,  

ΔTm = Kf m = 1.86 ºC/m x 4 = 7.4 ºC

Tm = -7.4 ºC for a solution

Answer: methanol and acetone are not suitable solvents for extracting organic compounds because they are miscible with water virtually in all proportions

Explanation:

Methane and acetone both are polar solvents, which means they are soluble in water. Hence, not suitable for the extraction from aqueous solutions.

Methanol is the simplest alcohol which is volatile, colorless, and inflammable.

Acetone is an organic compound whose chemical formula is CH3CH3CO.

Acetone and methanol both contain polar ends and are miscible in water.

Polar solvents are not suitable for the extraction of any compound.

Thus, Methanol and acetone are not suitable for extracting organic compounds from aqueous solutions.

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Answer:The average energy of the particles is dependent on the molecular mass of the particle is not part of Kinetic Molecular Theory.

Explanation:

The kinetic theory of gases was postulate by Clausius in 1857. Clausius speculated on how heat energy, temperature, and molecule motion could explain gas behavior. The kinetic theory of gases includes the following:

- A gas consists of molecules in constant random motion.

-Gas molecules influence each other only by collision; they exert no other forces on each other.

-All collisions between gas molecules are perfectly elastic; all kinetic energy is conserved.

- The volume actually occupied by the molecules of a gas is negligibly small; the vast majority of the volume of the gas is empty space through which the gas molecules are moving.

The Kinetic Molecular Theory includes assumptions about gas particles' size, motion, lack of forces of attraction or repulsion, and the dependence of average kinetic energy on temperature. The statement 'Gas particles do not repel each other' is actually part of the theory.

The Kinetic Molecular Theory makes several general assumptions about gases. These include :

Looking at the options provided, the statement which is NOT part of the Kinetic Molecular Theory is option A) Gas particles do not repel each other. This is because the theory does indeed state there are no forces of attraction or repulsion between gas particles.

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Final answer:

The rate law for the reaction of iodide ions with hypochlorite ions is determined to be rate = k[OCl-][I-]. The rate constant k is calculated to be 6.044×109 M-1s-1. The rate of the reaction when [OCl-]= 1.8×10-3 M and [I-]= 6.0×10-4 M is 6.532×103 M/s.

Explanation:

When the iodide ion reacts with the hypochlorite ion, we can determine the rate law by analyzing the given rate data. To write the rate law, we need to compare how the rate changes with changes in concentrations of the reactants. Looking at the provided data:

When [OCl-] doubles while [I-] is constant, the rate doubles, implying first-order dependence on [OCl-].

When [I-] doubles while [OCl-] is constant, the rate also doubles, suggesting first-order dependence on [I-].

Thus, the rate law is rate = k[OCl-][I-].

To calculate the rate constant (k), we can use any set of data. Using the first set:

1.36×104 M/s = k(1.5×10-3 M)(1.5×10-3 M)

k = 1.36×104 M/s / (2.25×10-6 M2)

k = 6.044×109 M-1s-1

To calculate the rate when [OCl-]= 1.8×10-3 M and [I-]= 6.0×10-4 M:

rate = (6.044×109 M-1s-1)(1.8×10-3 M)(6.0×10-4 M)

rate = 6.532×103 M/s

The question happens to be in an incorrect order but the correct question can be seen below;

What concentration of [tex]SO^{2-}_3[/tex] is in equilibrium with [tex]Ag_2SO_{3(S)}[/tex] and [tex]7.10*10^{-3}M[/tex] [tex]Ag^+[/tex]? (The [tex]K_{sp}[/tex] of  

Answer:

[tex]2.96*10^{-10}M[/tex]

Explanation:

The concentration of [tex]SO^{2-}_3[/tex]  can be determined by using the solubility concept.

Given ionic solid is [tex]Ag_2SO_{3(S)}[/tex] ;

The Equilibrium Equation for the ionic compound will be:

[tex]Ag_2SO_{3(S)}[/tex] ⇄[tex]2Ag_{(aq)}[/tex] + [tex]SO^{2-}_3_{(aq)}[/tex]

Now, the solubility product  ([tex]K_{sp}[/tex]) of the ionic compound will be;

[tex]K_{sp}[/tex] [tex]= [Ag^+]^{2}[SO^{2-}_3][/tex]

Given that;

the concentration [tex]Ag^+[/tex] is [tex]7.10*10^{-3}M[/tex] ; &

solubility product of the given ionic solid is  [tex]1.5*10^{-14}[/tex]

∴

  [tex]K_{sp}[/tex] [tex]= [Ag^+]^{2}[SO^{2-}_3][/tex]

[tex]1.5*10^{-14}[/tex] [tex]= (7.10*10^{-3})^2[/tex]  [tex][SO^{2-}_3][/tex]

[tex][SO^{2-}_3][/tex] = [tex]\frac{1.5*10^{-14}}{ (7.10*10^{-3})^2}[/tex]

          = 2.97560008 × 10⁻¹⁰

          ≅ [tex]2.96*10^{-10}M[/tex]

Thus, the concentration of [tex][SO^{2-}_3][/tex] is [tex]2.96*10^{-10}M[/tex]

Answer:

Explanation:

This limit is a consequence of Heisenberg´s uncertainty principle:

Δp x Δx > =  h

This state that the product of the uncertainty in momentum ( or  velocity since p = mv ) times the uncertainty in position, Δx , must be greater or equal to Planck´s constant ( 6.626 x 10⁻³⁴ J·s ).

Later models refined this equation to:

Δp x Δx > =   h/4π

This is the consequence of duality wave matter of the electron and Schrodinger´s equation, in which we can talk of probabilities of finding an electron and not confined to specific distances from the nucleus as in the Bohr atom.

Now think of think of this relation in terms of the uncertainty it describes. If we know the position of the electron with great exactitude, the velocity of the particle will be very high since the mass of hte electron is very small.

This a principle in nature and has nothing to do with the precision of our instruments for particles at the subatomic level.

The reason we do not observe this effect  with everyday objects is that the obbects have masses so large compare to  subatomic particles that the term mΔv becomes large enough, allowing us to know the position and velocity of macroscopic objects with small uncertainties:

Δp  x  Δx > = h/4π,  Δp  very large  ( because the mass is very big ) then  Δx is very small

The same does not have with small masses of the subatomic levels.

Answer:

∆=2dn/n

Explanation:

Where∆ = lamda

the construction of the 10.20 cm into feet so which which Alina dispersion form 400-700 NM assuming the dielectric has a refractive index of 1.32.

construction of the interference which is described by

∆=2dn/n

the concept of interference which can be described by the calculation of the thickness of the wage at both end to do this report you to the wavelengths of absorption band and the thickness of dielectric constant.

That is

∆=2dn/n

d=∆R/2n

Where ∆ is equal wavelength d = thickness

n = interference order

R = refractive index of dielectric medium

range of linear dispersion is 400nm to 700nm

∆1 = 400nm

∆2 = 700nm

n = 1.32

d = ∆1R/2n

d = 400*10^-9m*1.32/2*1

d = 2.64*10^-7m

For ∆2

d = 700*10^-9m*1.32/2*1

d=4.62*10^-7m

Details of the construction is simply calculation of the thickness of the wedge at both ends

Final answer:

To build a 10.0-cm interference wedge with linear dispersion from 400 to 700 nm using a dielectric with refractive index 1.32 involves precision crafting of a wedge where the thickness incrementally increases, causing a linear change in path length and hence wavelength dispersion.

Explanation:

Constructing a 10.0-cm interference wedge with a linear dispersion from 400 to 700 nm involves creating a transparent object with a slight and uniform increase in thickness from one end to the other, using a dielectric material with a known refractive index, which in this case is 1.32.

The wedge must be carefully designed so that the path length difference between the top and bottom surfaces changes by exactly 300 nm (the range from 400 to 700 nm) over the 10 cm length. This incremental change in path length creates a linear dispersion of wavelengths when light is shone through the wedge.

At the thinnest point, light with a wavelength of 400 nm should experience constructive interference, whereas at the thickest point, light with a wavelength of 700 nm should interfere constructively. The process involves precision cutting and polishing to ensure consistent graduation of thickness across the wedge.

Answer:

27.8 minutes

Explanation:

The reaction follows a first order

Rate = k[A] = change in concentration/time

k = 9×10^-3s^-1

Let the original concentration of A be y

Concentration of A at time t = 6.25% × y = 0.0625y

Change in concentration = y - 0.0625y = 0.9375y

0.009 × 0.0625y = 0.9375y/t

t = 0.9375y/0.0005625y = 1666.7sec = 1666.7/60 = 27.8 minutes

It takes approximately 12.8 minutes for the concentration of the reactant [A] to drop to 6.25% of the original concentration.

To determine the time it takes for the concentration of a reactant [A] in a first-order reaction to drop to 6.25% of its original concentration, we can use the first-order kinetics equation:

ln([A]₀/[A]) = kt

where ln is the natural logarithm, [A]₀ is the initial concentration of A, [A] is the concentration of A at time t, k is the rate constant, and t is the time in seconds. To find t when [A] is 6.25% of [A]₀, we can set [A]/[A]₀= 0.0625 (since 6.25% is equivalent to 0.0625 in decimal form).

Using the given rate constant 9.00×10⁻³ s⁻¹, the equation becomes:

ln(1/0.0625) = (9.00×10⁻³) × t

Solving this gives t = 768 seconds. Since there are 60 seconds in a minute, this is equivalent to 12.8 minutes.

Therefore, it takes approximately 12.8 minutes for [A] to drop to 6.25% of its original concentration in a first-order reaction at 45 °C with a rate constant of 9.00×10⁻³ s⁻¹.

Explanation:

Answer:

Marble 1 and 2 will repel each other, but no interaction occurs with marble 3.

Explanation:

Rubbing the marbles 1 and 2 with silk makes them lose the electrons and they become slightly positively charged. However the marble 3 is neutral as it's not rubbed with silk. So upon briging them all close together, the positively charged marbles repel each other as the same charges repel.  However there will be no interaction with marble 3.

Final answer:

Charged glass marbles 1 and 2, when brought close together, will repel each other, and if brought near uncharged marble 3, an initial attraction may occur followed by repulsion if charges are transferred.

Explanation:

When two glass marbles (marbles 1 and 2) are rubbed against silk, they become positively charged due to the transfer of electrons from the marbles to the silk, leaving the marbles with an excess of positive charges. This is because, according to the principles of electrostatics, rubbing materials together can transfer electrons from one material to another, resulting in one becoming positively charged and the other negatively charged. As a result, if marbles 1 and 2 are brought close together, they will repel each other, as indicated in Figure 18.4 (b), which shows that two similarly charged glass rods repel. When either of these charged marbles is brought near an uncharged marble (marble 3), an initial attraction may occur due to induced charges in the uncharged marble. However, if any charge is transferred upon contact, the like charges will cause marble 3 to then also be repelled by the charged marbles 1 and 2.

Final answer:

The condensed ground-state electron configurations of transition metal ions are given, and it is stated which ions are paramagnetic.

Explanation:

The condensed ground-state electron configurations of the transition metal ions are as follows:

(a) Mo³⁺: [Kr]4d³

(b) Au⁺: [Xe]5d¹⁰

(c) Mn²⁺: [Ar]3d⁵

(d) Hf²⁺: [Xe]4f¹⁴5d²×

Out of these, Mo³⁺ and Mn²⁺ are paramagnetic because they have unpaired electrons in their d orbitals, which allows them to be attracted to a magnetic field.

Answer:

6.25 μg/mL

Explanation:

When a dilution is made, the mass of the solute is conserved (Lavoiser's law), so the mass pipetted will be the mass in the assay. The mass is the concentration (C) multiplied by the volume (V). If the pipet solution is called 1, and the assay 2:

m1 = m2

C1*V1 = C2*V2

C1 = 250 μg/mL

V1 = 25 μL

V2 = 975 μL + 25 μL = 1000 μL (is the final volume of the assay after the addition of LDH)

250*25 = C2*1000

C2 = 6.25 μg/mL

The final concentration of LDH in the assay is 6.25 ug/ml.

To determine the final concentration of LDH in the assay, you need to consider the volumes of LDH and assay buffer used. In this case, you pipet 25 ul of 250 ug/ml LDH into 975 ul of assay buffer. To calculate the final concentration, you can use the formula:

Final Concentration = (Volume of LDH x Concentration of LDH) / Total Volume of Assay

Substituting the values, the final concentration of LDH in the assay is:

Final Concentration = (25 ul x 250 ug/ml) / (25 ul + 975 ul) = 6.25 ug/ml

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Answer:

m = 341.22 g

Explanation:

∴ V = 242 mL

∴ m = (δ)×(V)

⇒ m = (1.41 g/mL)×(242 mL)

⇒ m = 341.22 g

The mass of 242 mL of sulfuric acid with a density of 1.41 g/mL is 341.22 g.

To calculate the mass of 242 mL of sulfuric acid, we can use the density of the acid, which is 1.41 g/mL. The formula for calculating mass is:

Mass = Volume x Density

Substituting the given values into the formula:

Mass = 242 mL x 1.41 g/mL

Calculating the multiplication:

Mass = 341.22 g

Therefore, the mass of 242 mL of sulfuric acid is 341.22 g.

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Answer:

The mass of the element is 28.085 amu

Explanation:

Step 1: Data given

Masses of isotopes:

27.977 amu ⇒

28.976 amu ⇒ 4.68%

29.973 amu ⇒  3.09%

Step 2: Calculate the abundance of the other isotope

100% - 4.68% - 3.09 % = 92.23 %

Step 3: calculate the mass othe element

0.9223 * 27.977 + 0.0468 * 28.976 + 0.0309*29.973 = total mass of the element

Total mass of the element = 28.085 amuj

The mass of the element is 28.085 amu

The weighted average atomic mass of the given element is calculated using the masses and relative abundances of its isotopes. The mass is found to be 28.085 amu. The correct answer is Option C.

The average atomic mass of an element is calculated by multiplying each isotope's mass by its relative abundance (as a decimal), and then adding up these products. We can use the given information: the element has three stable isotopes with masses of 27.977 amu, 28.976 amu, and 29.973 amu. The abundance of the first isotope can be determined by subtracting the abundances of the other two isotopes from 100% as only these three isotopes are stable. We have: (27.977 * x) + (28.976 * 0.0468) + (29.973 * 0.0309) = average atomic mass of the element. Solving this equation x(assuming it to be in percentage form)= 1- 0.0468 - 0.0309 = 0.9223 (or 92.23% in percentage form). Substituting the value of x we get: (27.977 * 0.9223) + (28.976 * 0.0468) + (29.973 * 0.0309) = 28.085 amu. Hence, the correct answer is (C) 28.085

Learn more about Atomic Mass here:

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Answer : The balanced chemical reaction will be:

[tex]H_2O(l)\rightleftharpoons H^+(aq)+OH^-(aq)[/tex]

Or,

[tex]H_2O(l)+H_2O(l)\rightleftharpoons H_3O^+(aq)+OH^-(aq)[/tex]

Explanation :

Autoionization of water  : The autoionization of water means that the reaction water with water means self ionization.

In the autoionization of water, one water molecule loses an hydrogen ion and another one gains it.

The balanced chemical reaction will be:

[tex]H_2O(l)\rightleftharpoons H^+(aq)+OH^-(aq)[/tex]

Or,

[tex]H_2O(l)+H_2O(l)\rightleftharpoons H_3O^+(aq)+OH^-(aq)[/tex]

The autoionization of water is a chemical reaction where two water molecules react to form hydronium and hydroxide ions. This is represented as H₂O(l) + H₂O(l) = H3O+(aq) + OH¯(aq). The ion-product constant for water (Kw) is a measure of this process.

The autoionization of water is a process in which water molecules, acting as both an acid and a base, react with each other to form ions. This can be represented by the chemical reaction: H₂O(l) + H₂O(l) = H3O+(aq) + OH¯(aq). In this equation, the (l) denotes the liquid state of water and (aq) designates aqueous, or water-dissolved, ions.

The ion-product constant for water, Kw, is equal to the product of the concentrations of the hydronium and hydroxide ions: Kw = [H3O+][OH¯]. At 25 °C, the value of Kw is approximately 1.0 × 10-14, indicating very slight ionization. This value increases with temperature, indicating an endothermic reaction.

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Answer: The partial pressure of gas A is 6.34 atm and that of gas B is 17.1 atm

Explanation:

To calculate the pressure of the gas, we use the equation given by ideal gas, which follows:

[tex]PV=nRT[/tex]       ......(1)

where,

P = pressure of the gas

V = Volume of the gas

T = Temperature of the gas

R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]

n = number of moles of gas

We are given:

[tex]V=7.07L\\T=30.4^oC=[30.4+273]K=303.4K\\n=1.80mol[/tex]

Putting values in equation 1, we get:

[tex]p_A\times 7.07L=1.80mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 303.4K\\\\p_{A}=\frac{1.80\times 0.0821\times 303.4}{7.07}=6.34atm[/tex]

We are given:

[tex]V=7.07L\\T=30.4^oC=[30.4+273]K=303.4K\\n=4.86mol[/tex]

Putting values in equation 1, we get:

[tex]p_B\times 7.07L=4.86mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 303.4K\\\\p_{B}=\frac{4.86\times 0.0821\times 303.4}{7.07}=17.1atm[/tex]

Hence, the partial pressure of gas A is 6.34 atm and that of gas B is 17.1 atm

Answer:

The partial pressure of gas A is 6.34 atm

The partial pressure of gas B is 17.12 atm

Explanation:

Step 1 :Data given

Volume of cylinder = 7.07 L

Number of moles gas A = 1.80 moles

Number of moles gas B = 4.86 moles

Temperature =30.4 ° C = 303.55 K

Step 2: Calculate pressure of gas A

p*V = n*R*T

p =(n*R*T)/V

⇒ with p = the partial pressure of gas A

⇒ with V = The volume of the cylinder = 7.07 L

⇒ with n = the number of moles gas A = 1.80 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 303.55 K

p = (1.80 *0.08206 *303.55)/7.07

p = 6.34 atm

Step 3: Calculate pressure of gas B

p*V = n*R*T

p =(n*R*T)/V

⇒ with p = the partial pressure of gasB

⇒ with V = The volume of the cylinder = 7.07 L

⇒ with n = the number of moles gas B = 4.86 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 303.55 K

p = (4.86 *0.08206 *303.55)/7.07

p = 17.12 atm

The partial pressure of gas A is 6.34 atm

The partial pressure of gas B is 17.12 atm

Answer:

The order of the reaction is 4.

The rate law of the reaction will be :

[tex]R=k[NO]3[H_2]^1[/tex]

Rate constant of the reaction: k =[tex] 6\times 10^5 M^{-3}s^{-1}[/tex]

Explanation:

[tex]2NO(g) +2H_2 (g)\rightarrow N_2(g) + 2H_2O(g)[/tex]

Let the stoichiometric coefficient of the NO and [tex]H_2[/tex] in rate law be x and y .

Rate of the reaction is given  by :

[tex]R=k[NO]^[H_2]^y[/tex]

1) When , [tex][NO]=0.0100 M, [H_2]=0.0100 M[/tex]

R =  0.00600 M/s

[tex]0.00600 M/s=k[0.0100 M]^x[0.0100 M]^y[/tex]..[1]

2) When , [tex][NO]=0.0200 M, [H_2]=0.0300 M[/tex]

R =  0.144 M/s

[tex]0.144 M/s=k[0.0200 M]^x[0.0300 M]^y[/tex]..[2]

3) When , [tex][NO]=0.0100 M, [H_2]=0.0200 M[/tex]

R =  0.0120 M/s

[tex]0.0120 M/s=k[0.0100 M]^x[0.0200 M]^y[/tex]..[3]

Dividing [1] and [3]

[tex]\frac{0.00600 M/s}{0.0120 M/s}=\frac{k[0.0100 M]^x\times [0.0100 M]^y}{k[0.0100 M]^x\times [0.0200 M]^y}[/tex]

y = 1

Dividing [1] and [2]

[tex]\frac{0.00600 M/s}{0.144 M/s}=\frac{k[0.0100 M]^x\times [0.0100 M]^1}{k[0.0200 M]^x\times [0.0300 M]^1}[/tex]

x = 3

The order of the reaction = x + y = 3 + 1 = 4

The rate law of the reaction will be :

[tex]R=k[NO]3[H_2]^1[/tex]

Rate constant of the reaction: k

When , [tex][NO]=0.0100 M, [H_2]=0.0100 M[/tex]

R =  0.00600 M/s

[tex]0.00600 M/s=k[0.0100 M]^3[0.0100 M]^1[/tex]..[1]

[tex]k=\frac{0.00600 M/s}{[0.0100 M]^3[0.0100 M]^1}=6\times 10^5 M^{-3}s^{-1}[/tex]

Final answer:

The reaction between nitrogen monoxide and hydrogen is second-order with respect to NO, first-order with respect to H2, and third-order overall. The rate law is rate = k[NO]²[H₂], where k is the rate constant specific to the reaction conditions.

Explanation:

The rate law expression for the reaction between hydrogen and nitrogen monoxide to form dinitrogen monoxide and water vapor can be determined using the given rate equation. By analyzing the equation rate = k[NO]²[H₂], we can deduce the orders of reaction with respect to each reactant and the overall order.

The rate law shows that the reaction rate is directly proportional to the square of the concentration of nitric oxide (NO) and linearly proportional to the concentration of hydrogen (H₂). Therefore, the order of reaction with respect to NO is 2 (second order), and with respect to H₂, it is 1 (first order). The overall order of the reaction is the sum of these individual orders, which is 2 + 1 = 3 (third order).

The rate constant (k) would be determined experimentally by measuring the reaction rates at known concentrations of reactants. It is specific to the reaction's conditions, such as temperature and pressure, and would be stated in units that correspond to a third-order reaction.