Which of the following is equivalent to finding the zeros of a function
A. X-intercepts
B. Y-intercepts
C. Slope
D. Origin

Mar 10, 2012 - Markups and Markdowns Word Problems - Independent Practice Worksheet. $6640. $3.201 ... 2) Fred buys a video game disk for $4. There was a discount of 20%.What is the sales price? 20% of 1 pay 8090 ... 5) Timmy wants to buy.a scooter and the price was $50. When ... at a simple interest rate of 54%.

The probability that at least one member of a married couple will vote is 0.34 or 34%. The probability of a wife voting given that her husband will vote is approximately 0.7143 or 71.43%. The probability of a husband voting given his wife will not vote is 0.06 or 6%.

The subject of this question is probability within the realm of mathematics. To find the probability of at least one member of a married couple voting, we can use the formula P(A or B) = P(A) + P(B) - P(A and B).

Therefore, the probability is 0.21 (husband voting) + 0.28 (wife voting) - 0.15 (both voting), which equals 0.34.

For (b), the probability that the wife will vote, given that her husband will vote, is P(Wife|Husband) = P(Wife and Husband)/P(Husband).

So, this probability is 0.15/0.21, which equals approximately 0.7143.

For (c), the probability that the husband will vote, given that his wife will not vote, is P(Husband|Wife not voting) = P(Husband) - P(Husband and Wife).

So, this probability is 0.21 - 0.15, which yields 0.06 or 6%.

Answer:

6.56% probability that a real emergency situation exists.

Step-by-step explanation:

We have these following probabilities:

A 0.4% probability that a real emergency situation exists.

A 99.6% probability that a real emergency situation does not exist.

If an emergency situation exists, a 95% probability that the alarm sounds.

If an emergency situation does not exist, a 2% probability that the alarm sounds.

The problem can be formulated as the following question:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

[tex]P = \frac{P(B).P(A/B)}{P(A)}[/tex]

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem:

What is the probability of a real emergency situation existing, given that the alarm has sounded.

P(B) is the probability of there being a real emergency situation. So [tex]P(B) = 0.004[/tex].

P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.

P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So

P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792

Given that the alarm has just sounded, what is the probability that a real emergency situation exists?

[tex]P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.004*0.95}{0.05792} = 0.0656[/tex]

6.56% probability that a real emergency situation exists.

Answer:

The answer to your question is 13 u²

Step-by-step explanation:

We know that the small triangle is surrounded by right triangles so we can use the Pythagorean theorem to find the lengths  of the small triangle

                 AD² = 3² + 2²

Simplify

                 AD² = 9 + 4

                 AD² = 13

                 AD = [tex]\sqrt{13}[/tex]

Find the area of the square

Area = side x side

Area = AD x AD

Area = [tex]\sqrt{13} x \sqrt{13}[/tex]

Area = 13 u²                  

Answer:

The measure is 6°.

Step-by-step explanation:

If an angle of 96 degrees is rotated 90 degrees clockwise then the measure of the new angle will be given by

= 96° - 90° = 6°

Answer:

The unit rate is 6 1/4 cups of soda per cup of pineapple juice

Step-by-step explanation:

we know that

To find out the unit rate of soda to pineapple juice in the punch, divide the cups of soda by the cups of pineapple juice

so

[tex]2\frac{1}{2} :\frac{2}{5}[/tex]

Convert mixed number to an improper fraction

[tex]2\frac{1}{2}=2+\frac{1}{2}=\frac{2*2+1}{2}=\frac{5}{2}[/tex]

substitute

[tex]\frac{5}{2} :\frac{2}{5}[/tex]

Multiply in cross

[tex]\frac{25}{4}= 6.25[/tex]

Convert to mixed number

[tex]6.25=6+0.25=6+\frac{1}{4}= 6\frac{1}{4}[/tex]

That means

The unit rate is 6 1/4 cups of soda per cup of pineapple juice

Answer:

6 1/4

Step-by-step explanation:

The farmer will need:

[tex]\boxed{191\frac{11}{12}yd}[/tex]

In order to enclose the area shown in the figure below.

The diagram below shows the representation of this problem. Let:

[tex]x: The \ length \ of \ the \ rectangular \ pastures \\ \\ y: The \ width \ of \ the \ rectangular \ pastures[/tex]

We know that:

[tex]x=5\frac{5}{8}yd \\ \\ y=30\frac{2}{9}yd[/tex]

So the fencing the farmer needs can be calculated as the perimeter of the two adjacent rectangular pastures:

[tex]P=2(x+y)+y \\ \\ P=2(50\frac{5}{8}+30\frac{2}{9})+30\frac{2}{9} \\ \\ P=100\frac{10}{8}+60\frac{4}{9}+30\frac{2}{9} \\ \\ P=100\frac{10}{8}+90\frac{6}{9} \\ \\ P=100\frac{5}{4}+90\frac{2}{3} \\ \\ P=190(\frac{15+8}{12}) \\ \\ P=190(\frac{23}{12}) \\ \\ \\ Expressing \ as \ a \ mixed \ fraction: \\ \\ P=190+1+\frac{11}{12} \\ \\ P=191+\frac{11}{12} \\ \\ \boxed{P=191\frac{11}{12}yd}[/tex]

Enclosing areas: https://brainly.com/question/1904034

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n = 15

Step-by-step explanation:

For 2^-6*2^n=2^9, a = 2, m = -6 and m + n = 9

⇒ -6 + n = 9

⇒ n = 15

⇒ 2³ × 4³ can also be written as 2³ × (2²)³ = 2³ × 2^6 [This is based on the law of exponents (a^m)^n = (a)^m×n]

⇒ 2³ × 2^6 = 2^ (3 + 6) = 2^9 [Using the law of exponents a^m × a^n = a^m+n]

Answer:

a. P(X = 0)= 0.001

b. P(X = 1)= 0.001

c. P(X=2)= 0.044

d. P(X=3)= 0.117

e. P(X=4)= 0.205

f. P(X=5)= 0.246

g. P(X=6)= 0.205

h. P(X=7)= 0.117

i. P(X=8)= 0.044

j. P(X=9)= 0.001

k. P(X=10)= 0.001

Step-by-step explanation:

Hello!

You have the variable X with binomial distribution, the probability of success is 0.5 and the sample size is n= 10 (I suppose)

If the probability of success p=0.5 then the probability of failure is q= 1 - p= 1 - 0.5 ⇒ q= 0.5

You are asked to calculate the probabilities for each observed value of the variable. In this case is a discrete variable with definition between 0 and 10.

You have two ways of solving this excersice

1) Using the formula

[tex]P(X)= \frac{n!}{(n-X)!X!} * (p)^X * (q)^{n-X}[/tex]

2) Using a table of cummulative probabilities of the binomial distribution.

a. P(X = 0)

Formula:

[tex]P(X=0)= \frac{10!}{(10-0)!0!} * (0.5)^0 * (0.5)^{10-0}[/tex]

P(X = 0) = 0.00097 ≅ 0.001

Using the table:

P(X = 0) = P(X ≤ 0) = 0.0010

b. P(X = 1)

Formula

[tex]P(X=1)= \frac{10!}{(10-1)!1!} * (0.5)^1 * (0.5)^{10-1}[/tex]

P(X = 1) = 0.0097 ≅ 0.001

Using table:

P(X = 1) = P(X ≤ 1) - P(X ≤ 0) = 0.0107-0.0010= 0.0097 ≅ 0.001

c. P(X=2)

Formula

[tex]P(X=2)= \frac{10!}{(10-2)!2!} * (0.5)^2 * (0.5)^{10-2}[/tex]

P(X = 2) = 0.0439 ≅ 0.044

Using table:

P(X = 2) = P(X ≤ 2) - P(X ≤ 1) = 0.0547 - 0.0107= 0.044

d. P(X = 3)

Formula

[tex]P(X = 3)= \frac{10!}{(10-3)!3!} * (0.5)^3 * (0.5)^{10-3}[/tex]

P(X = 3)= 0.11718 ≅ 0.1172

Using table:

P(X = 3) = P(X ≤ 3) - P(X ≤ 2) = 0.1719 - 0.0547= 0.1172

e. P(X = 4)

Formula

[tex]P(X = 4)= \frac{10!}{(10-4)!4!} * (0.5)^4 * (0.5)^{10-4}[/tex]

P(X = 4)= 0.2051

Using table:

P(X = 4) = P(X ≤ 4) - P(X ≤ 3) = 0.3770 - 0.1719= 0.2051

f. P(X = 5)

Formula

[tex]P(X = 5)= \frac{10!}{(10-5)!5!} * (0.5)^5 * (0.5)^{10-5}[/tex]

P(X = 5)= 0.2461 ≅ 0.246

Using table:

P(X = 5) = P(X ≤ 5) - P(X ≤ 4) = 0.6230 - 0.3770= 0.246

g. P(X = 6)

Formula

[tex]P(X = 6)= \frac{10!}{(10-6)!6!} * (0.5)^6 * (0.5)^{10-6}[/tex]

P(X = 6)= 0.2051

Using table:

P(X = 6) = P(X ≤ 6) - P(X ≤ 5) = 0.8281 - 0.6230 = 0.2051

h. P(X = 7)

Formula

[tex]P(X = 7)= \frac{10!}{(10-7)!7!} * (0.5)^7 * (0.5)^{10-7}[/tex]

P(X = 7)= 0.11718 ≅ 0.1172

Using table:

P(X = 7) = P(X ≤ 7) - P(X ≤ 6) = 0.9453 - 0.8281= 0.1172

i. P(X = 8)

Formula

[tex]P(X = 8)= \frac{10!}{(10-8)!8!} * (0.5)^8 * (0.5)^{10-8}[/tex]

P(X = 8)= 0.0437 ≅ 0.044

Using table:

P(X = 8) = P(X ≤ 8) - P(X ≤ 7) = 0.9893 - 0.9453= 0.044

j. P(X = 9)

Formula

[tex]P(X = 9)= \frac{10!}{(10-9)!9!} * (0.5)^9 * (0.5)^{10-9}[/tex]

P(X = 9)=0.0097 ≅ 0.001

Using table:

P(X = 9) = P(X ≤ 9) - P(X ≤ 8) = 0.999 - 0.9893= 0.001

k. P(X = 10)

Formula

[tex]P(X = 10)= \frac{10!}{(10-10)!10!} * (0.5)^{10} * (0.5)^{10-10}[/tex]

P(X = 10)= 0.00097 ≅ 0.001

Using table:

P(X = 10) = P(X ≤ 10) - P(X ≤ 9) = 1 - 0.9990= 0.001

Note: since 10 is the max number this variable can take, the cummulated probability until it is 1.

I hope it helps!

Answer:

13.5

Step-by-step explanation:

7 1/2=7.5

7.5/5*9=13.5

Answer:

The answer to your question is below

Step-by-step explanation:

43.-

x = [tex]\sqrt{27^{2} + 22^{2}- 2(27)(22)cos 73}[/tex]

x = [tex]\sqrt{865.66}[/tex]

x = 29.42

44.-

x = [tex]\sqrt{10^{2} + 14^{2} -2(10)(14)cos 66}[/tex]

x = [tex]\sqrt{182.11}[/tex]

x = 13.49

45.-

cos x = [tex]\frac{11^{2} - 17^{2} - 10^{2}}{-2(11)(17)}[/tex]

cos x = 0.7166

     x = 44.22°

46.-

x = [tex]\sqrt{16^{2} + 12^{2} -2(16)(12)cos75}[/tex]

x = [tex]\sqrt{300.61}[/tex]

x = 17.34

47.-

cos P = [tex]\frac{6^{2} - 13^{2} -11^{2}}{-2(13)(11)}[/tex]

cos P = 0.888

     P = 27.36°

sinR/13 = sinP/6

sin R = 13sin27.36/6

sinR = 0.996

   R = 84.71°

Q = 180 - 84.71 - 27.36

Q = 67.93°

48.-

D = 180 - 25 - 113

D = 42°

CD = 9Sin113/sin42

CD = 12.38

ED = 9sin25/sin42

ED = 5.68

Answer:

a) Empty set

b)  [tex]\{x : x \in N \text{ and } x < 13\}[/tex]                                        

Step-by-step explanation:

Roster form is a comma separated list form of set.

a) The set of natural numbers x that satisfy x + 4 = 1.  

[tex]x + 4 = 1\\x = -3 \notin N[/tex]

Thus, x is an empty set.

b) set-builder notation for the set  {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.

We use x to represent this set. Now x belongs to natural number and is less than equal to 12.

Thus, it can be written as:

[tex]\{x : x \in N \text{ and } x < 13\}[/tex]

Answer:

a.) 0.4565

b.) 0.8656

c.) 0.4615

Step-by-step explanation:

We solve this using the probability distribution formula of combination.

nCr * p^r * q^n-r

Where

n = number of trials

r = successful trials

probability of success = p = 77% =0.77

Probability of failure= q = 1-0.77 = 0.23

a.) When exactly 3 opponents are defeated, When n = 3 and r = 3, probability becomes:

= 3C3 * 0.77³ * 0.23^0

= 1 * 0.456533 * 1

= 0.456533 = 0.4565 (4.d.p)

b.) When at least 2 opponents are defeated, that is when r = 2 and when r = 3,

When r = 2, probability becomes:

= 3C2 * 0.77² * 0.23¹

= 3 * 0.5929 * 0.23

= 0.409101

When 3 opponents are defeated, we calculated it earlier to be 0.456533

Hence, probability that at least 2 opponents are defeated

= 0.409101 + 0.456533

= 0.865634 = 0.8656(2.d.p)

c.) If 2 games are played, probability he defeat all 3 at least once in the game will be the sum (probability of defeating all 3 opponents in the first game and not defeating all 3 in the second game) + (probability of defeating all three opponents in both games)

Probability of defeating all three opponents in the first game = 0.456533

Probability of not defeating all three opponents in the second game = 1 - 0.456533 = 0.543467

Hence ,

probability of defeating all 3 opponents in the first game and not defeating all 3 in the second game = 0.465633 * 0.543467 = 0.253056

probability of defeating all three opponents in both games

= 0.456533 * 0.456533

=0.208422

Probability he defeats all three opponents at least once in 2games

= 0.253056 + 0.208422

=0.461478 = 0.4615(4.d.p)

Answer:

Correct option is (B) descriptive statistical method

Step-by-step explanation:

Descriptive statistics branch in statistics deals with the representation of the data using distinct brief coefficients. These coefficients are used as either the representative of the sample or the population.

The descriptive statistics branch is divided into two sub branches:

The three measures of central tendency are:

The measures of dispersion are:

The education researcher computes the average number of hours student study at various local colleges.

The average of a data is the mean value which is the measure of central tendency.

Thus, the researcher is using descriptive statistical method to summarize the data.

Final answer:

The education researcher is using descriptive statistical methods by calculating an average of study hours, which is a measure of central tendency, a fundamental aspect of descriptive statistics.

Explanation:

An education researcher who collects data on how many hours students study at various local colleges and then calculates an average to summarize this data is using descriptive statistical methods. Descriptive statistics involve organizing and summarizing data to provide a clear overview of its characteristics. Examples of descriptive statistics include measures of central tendency (mean, median, mode), which indicate the typical value within a data set, and measures of variability (range, variance, standard deviation), which show how spread out the data points are. The calculation of an average, or mean, falls under the measure of central tendency, making it a key component of descriptive statistics.

Answer:

c₁ = 1/2

c₂ = - e²/2

y = (1/2)*(eˣ - e²⁻ˣ)

Step-by-step explanation:

Given

y = c₁eˣ + c₂e⁻ˣ

y(1) = 0

y'(1) = e

We get y' :

y' = (c₁eˣ + c₂e⁻ˣ)'  ⇒  y' = c₁eˣ - c₂e⁻ˣ

then we find y(1) :

y(1) = c₁e¹ + c₂e⁻¹ = 0

⇒  c₁ = - c₂/e² (I)

then we obtain y'(1):

y'(1) = c₁e¹ - c₂e⁻¹ = e    (II)

⇒  (- c₂/e²)*e - c₂e⁻¹ = e

⇒  - c₂e⁻¹ - c₂e⁻¹ = - 2c₂e⁻¹ = e

⇒  c₂ = - e²/2

and

c₁ = - c₂/e² = - (- e²/2) / e²

⇒  c₁ = 1/2

Finally, the equation will be

y = (1/2)*eˣ - (e²/2)*e⁻ˣ = (1/2)*(eˣ - e²⁻ˣ)

Applying the initial conditions, it is found that the solution is:

[tex]y = \frac{1}{2}e^{x} - \frac{e^2}{2}e^{-x}[/tex]

------------------------

The solution for the PVI is given by:

[tex]y = c_1e^{x} + c_2e^{-x}[/tex]

------------------------

The condition [tex]y(1) = 0[/tex] means that when [tex]x = 0, y = 1[/tex], and thus, we get:

[tex]c_1e + c_2e^{-1} = 0[/tex]

[tex]c_1e+ \frac{c_2}{e} = 0[/tex]

[tex]c_1e^{2} + c_2 = 0[/tex]

[tex]c_2 = -c_1e^{2}[/tex]

------------------------

The derivative is:

[tex]y^{\prime}(x) = c_1e^{x} - c_2e^{-x}[/tex]

Applying the condition [tex]y^{\prime}(1) = e[/tex], we get:

[tex]c_1e - \frac{c_2}{e} = e[/tex]

Considering [tex]c_2 = -c_1e^{2}[/tex]:

[tex]c_1e + c_1\frac{e^2}{e} = e[/tex]

[tex]c_1e + c_1e = e[/tex]

[tex]2c_1e = e[/tex]

[tex]2c_1 = 1[/tex]

[tex]c_1 = \frac{1}{2}[/tex]

------------------------

The second constant is:

[tex]c_2 = -c_1e^{2} = -\frac{e^2}{2}[/tex]

And the solution is:

[tex]y = \frac{1}{2}e^{x} - \frac{e^2}{2}e^{-x}[/tex]

A similar problem is given at https://brainly.com/question/13244107

Answer:

15 Nickels, 11 Pennies

Step-by-step explanation:

Simplify your life and take out the decimals

5*N + P = 86

P + 4 = N (4 more nickels than pennies)

By substitution of the second eq into the first: 5*(P+4) + P = 86

5*P + 20 + P = 86

6P = 66

P = 11, so N = 4 + 11 = 15

Answer:Ruby has 11 pennies and 15 nickels.

Step-by-step explanation:

The worth of a penny is 1 cent. Converting to dollars, it becomes

1/100 = $0.01

The worth of a nickel is 5 cents. Converting to dollars, it becomes

5/100 = $0.05

Let x represent the number of pemnies that Ruby has.

Let y represent the number of nickels that Ruby has.

She has 4 more nickels than pennies. This means that

y = x + 4

Ruby has $0.86 worth of pennies and nickels. This means that

0.01x + 0.05y = 0.86 - - - - - - - - - - - 1

Substituting y = x + 4 into equation 1, it becomes

0.01x + 0.05(x + 4) = 0.86

0.01x + 0.05x + 0.2 = 0.86

0.06x = 0.86 - 0.2 = 0.66

x = 0.66/0.06

x = 11

y = x + 4 = 11 + 4

y = 15

Hello, you haven't provided the system of equations, therefore I will show you how to do it for a particular system and you can follow the same procedure for yours.

Answer:

For E1 -> Exactly one

For E2 -> None

For E3 -> Infinitely many

Step-by-step explanation:

Consider the system of equations E1:  y = -6x + 8 and 3x + y = 4, replacing equation one in two 3x -6x +8 = 4, solving x = 4/3 and replacing x in equation one y = 0. This system of equations have just one solution -> (4/3, 0)

Consider the system of equations E2:  y = -3x + 9 and y = -3x -7, replacing equation one in two -3x + 9 = -3x -7, solving 9 = -3. This system of equations have no solution because the result is a fallacy.

Consider the system of equations E3:  2 = -6x + 4y and -1 = -3x -2y, taking equation one and solving y = 1/2 + 3/2x, replacing equation one in two -1 = -3x -1 +3x, solving -1 = -1. This system of equations have infinitely many solution because we find a true equation when solving .

Answer:

The probability that the object will emerge from the + side of this device is 1/2

Step-by-step explanation:

Orienting the magnetic field in a Stern-Gerlach device in some direction(y - direction) perpendicular to the direction of motion of the atoms in the beam, the atoms will emerge in two possible beams, corresponding to ±(1/2)h. The positive sign is usually referred to as spin up in the direction, the negative sign as spin down in the explanation, the separation has always been in the y direction. There can be some other cases where magnetic field may be orientated in x-direction or z-direction.

Answer:

[tex]5.796\times 10^{-29}m^3[/tex]

Step-by-step explanation:

Atomic radius of metal=0.137nm=[tex]0.137\times 10^{-9}[/tex]m

[tex]1nm=10^{-9}m[/tex]

Structure is  FCC

We know that

The relation between edge length and radius  in FCC structure

[tex]a=2\sqrt 2r[/tex]

Where a=Edge length=Side

r=Radius

Using the relation

[tex]a=2\sqrt 2\times 0.137\times 10^{-9}=0.387\times 10^{-9}m[/tex]

We know that

Volume of cube=[tex](side)^3[/tex]

Using the formula

Volume of unit cell=[tex](0.387\times 10^{-9})^3=5.796\times 10^{-29} m^3[/tex]

The volume of a unit cell is approximately 0.0580 nm³.

To find the volume of the unit cell for a metal with a face-centered cubic (FCC) crystal structure given an atomic radius of 0.137 nm, follow these steps:

Thus, the volume of the unit cell is approximately 0.0580 nm³.

Answer:

Parameter                                            

Step-by-step explanation:

We are given the following in the question:

The average age of men who had walked on the moon was 39 years, 11 months, 15 days.

Population and sample:

Parameter and statistic:

Population of interest:

men who had walked on the moon

Value:

average age of men who had walked on the moon

Thus, the give value describes a population and hence, it is a parameter.

Answer:

18 in^2

Step-by-step explanation:

1  )The three sides of the gutter add up to 12

            2x+ y = 12  

2)  Subtract 2x from both sides.

           y = 12 — 2x  

3 )Find the area of the rectangle in terms of x and simplify.

    Area = xy = x(12 — 2x) = -2x^2+12x = f(x)  

4 )  x=-b/2a

     x co-ordinate of the vertex= -12/2(-2)=3

5 )Plug in 3 for x into they equation.

    y co-ordinate of the vertex= 12 — 2(3) = 6  

6  )  Plug in 3 for x and 6 for y.  

      Area= xy = 3(6) = 18  

RESULT  

            18 in^2

The student is undertaking an English language assignment designed to strengthen their understanding of vocabulary, word formation, and spelling through a variety of exercises including word scrambles, pattern recognition, spelling reviews, and word categorization.

The student appears to be working on a language arts activity related to vocabulary and word structure. The question likely requires them to engage with various linguistic exercises such as word scrambles, identifying patterns in spelling or pronunciation, reviewing correct spellings, and categorizing words. Such tasks are designed to help students learn about word formation, synonyms, antonyms, and the nuances of English spelling.

Word Scrambles and Patterns

For word scrambles, students are expected to rearrange the letters to form meaningful words. In doing this, they might uncover a hidden word that pertains to the lesson's focus. Identifying patterns in words might involve recognizing prefixes, suffixes, or roots that appear consistently across different words.

Reviewing Spelling

The student is also asked to choose the word with the correct spelling. This likely involves comparing similar words and identifying the correctly spelled one, perhaps with the aid of a dictionary for verification.

Categorizing Words

In the task of sorting words into groups, students might have to classify words based on different criteria such as part of speech, phonetic features, or spelling patterns. This reinforces their understanding of language structure and proper spelling conventions.

Answer:

A = -10

Step-by-step explanation:

A/2 = -5

Multiply both sides by the denominator of the fraction

We have A/2 x2 = -5 x 2

A = -10

Answer:

-10

Step-by-step explanation:

It is the easiest equation.

A/2= -5

At first, we have to multiply both the sides by 2. Therefore, we can get,

[tex]\frac{A*2}{2}[/tex] = (-5 × 2)

or, A = -10

Therefore, the value of A is -10. It remains negative because we cannot multiply both the sides by -1. If we do that, we cannot determine the constant.

Answer: A = -10

Answer:

a) A^² is a Hermitian operator

b) A^B^ is not a Hermitian operator

c)  A^B^+ B^A^  is a Hermitian operator

d) It is not possible to be complex it must be a real number

Step-by-step explanation:

In order to understand this solution we need to define the concept Hermitian

HERMITIAN

 This can be defined as a matrix whose elements are real and symmetrical i.e. it a square matrix that is equal to its own conjugate, or we can simply put that its a matrix in which those pairs of element that are symmetrically placed with respect to the principal diagonal are complex conjugates.i.e the diagonal elements( Hermitian operators) are real numbers while others are complex numbers.

The solution to the question above are on the first and second uploaded image.

Answer:

A. 0.52

Step-by-step explanation:

Let D be the event that person used Debit card and C b the event that person used coupon.

We have to find the probability of customer does not use coupons given that a customer does not pay with a debit card,

P(C'/D')=P(C')P(D'/C')/[P(C')P(D'/C')+P(D')P(D'/C')]

We are given that P(D)=0.35, P(C)=0.30 and P(D/C)=0.5.

P(D')=1-0.35=0.65

P(C')=1-0.3=0.7

P(D'/C')=0.5.

P(C'/D')=0.7(0.5)/[0.7(0.5)+0.65(0.5)]

P(C'/D')=0.35/[0.35+0.325]

P(C'/D')=0.35/[0.35+0.325]

P(C'/D')=0.35/0.675

P(C'/D')=0.5185=0.52

Thus, the probability of customer does not use coupons given that a customer does not pay with a debit card is 0.52.

Answer:

The variance of this distribution is 0.0036.

Step-by-step explanation:

The variance of n binomial distribution trials with p proportion is given by the following formula:

[tex]Var(X) = \frac{p(1-p)}{n}[/tex]

In this problem, we have that:

About 90% of defendants are found guilty in criminal trials. This means that [tex]p = 0.9[/tex]

Suppose we take a random sample of 25 trials. This means that [tex]n = 25[/tex]

Based on a proportion of .90, what is the variance of this distribution?

[tex]Var(X) = \frac{p(1-p)}{n}[/tex]

[tex]Var(X) = \frac{0.9*0.1}{25} = 0.0036[/tex]

The variance of this distribution is 0.0036.

Answer:

The chi-square null hypothesis for the study that "socioeconomic status is related to smoking behavior" is False

Step-by-step explanation:

The chi-square null hypothesis is false because the chi-square null hypothesis states that no relationship exists on the categorical variables in a population, they are all independent of each other.

Answer:

a) The person traveled 2.83 hours.

b) The person travels 220.17 kilometers.

Step-by-step explanation:

We have that the speed is the distance divided by the time. Mathematically, that is

[tex]s = \frac{d}{t}[/tex]

(a) how much time is spent on the trip and

The peron's average speed is 77.8 km/h, which means that [tex]s = 77.8[/tex]

The person distance traveled is:

22 min is 22/60 = 0.37h.

So for  the time t1, the person traveled at a speed of 89.5 km/h. Which has a distance of 89.5*t1.

For 0.37h, the person was at a stop, so she did not travel. This means that the total distance is

[tex]d = 89.5t1 + 0 = 89.5t1[/tex]

The total time is the time traveling t and the stoppage time 0.37. So

[tex]t = t1 + 0.37[/tex]

We want to find t1, which is the time that the person was driving.

So

[tex]s = \frac{d}{t}[/tex]

[tex]77.8 = \frac{89.5t1}{t1 + 0.37}[/tex]

[tex]77.8t1 + 77.8*0.37 = 89.5t1[/tex]

[tex]11.7t1 = 28.786[/tex]

[tex]t1 = \frac{28.786}{11.7}[/tex]

[tex]t1 = 2.46[/tex]

The total time is

[tex]t = t1 + 0.37 = 2.46 + 0.37 = 2.83[/tex]

The person traveled for 2.83 hours.

(b) how far does the person travel?

The person traveled 2.46 hours at an average speed of 77.8 km/h. So

[tex]s = \frac{d}{t}[/tex]

[tex]77.8 = \frac{d}{2.83}[/tex]

[tex]d = 77.8*2.83 = 220.17[/tex]

The person travels 220.17 kilometers.

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August.  t = 1 corresponds to the end of August.  t = 2 corresponds to the end of September.  So on and so forth.  So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

Answer:

The original​ values are : 16, 25, 25, 49, 49, 64, 121.

Step-by-step explanation:

We know that  a researcher took square roots of the counts. Some of the resulting​ values, which are reasonably​ symmetric, were 4​, 5​, 5​, 7​, 7​, 8​, and 11.  We calculate the original​ values:

[tex]4^2=16\\5^2=25\\5^2=25\\7^2=49\\7^2=49\\8^2=64\\11^2=121\\[/tex]

The original​ values are : 16, 25, 25, 49, 49, 64, 121.

We conclude that the  original data is not simmetric.

The original values obtained by reversing the square root transformation are 16, 25, 25, 49, 49, 64, and 121. These values show variability in the number of employees across different small companies in the town. The transformed dataset was made more symmetrical for statistical analysis.

When a researcher applies a square root transformation to a dataset, the purpose is often to make the data more symmetrical and easier to analyze using certain statistical methods.

Given the transformed values 4, 5, 5, 7, 7, 8, and 11, we can reverse the transformation to find the original values.

The square of each transformed value yields the original data points:

Thus, the original values are 16, 25, 25, 49, 49, 64, and 121. These values are distributed with some repeated data points and a range from 16 to 121.

This distribution indicates variability in the number of employees across the small companies studied.