Which of the following equalities is not correct?

1 cm3 = 1 mL

1000 mm = 1 m

100 cg = 1 g

10 kg = 1 g

The volume of 1 mole of helium gas when the pressure is 1.47 atm and the temperature is 287k is 16.02 litres.

The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.

It is a mathematical expression that relates Pressure, Volume and Temperature.

(P1 × V1)÷T1 = (P2 × V2)÷T2

Also, we can simply write it as

PV = nRT

P = 1.47 atm

V = ?

n = 1

R = 0.0821

T = 287K

V = nRT ÷ P

V = 16.02 litres

Therefore, The volume of 1 mole of helium gas when the pressure is 1.47 atm and the temperature is 287k is 16.02 litres.

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Answer:

The balanced equation is

[tex]N_{2}[/tex] (g) + 3 [tex]H_{2}[/tex](g) ⇒ 2 [tex]NH_{3}[/tex] (g)

The coefficient in front of ammonia, [tex]NH_{3}[/tex], in the balanced equation is 2.

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

In this case you can start balancing the hydrogen. On the left side there is an amount of two hydrogens, while on the right side there are three. In order to match the amount of hydrogen on both sides, the easiest way to do this is by exchanging these numbers and adding them as coefficients in front of each molecule. It is as follows:

[tex]N_{2}[/tex] (g) + 3 [tex]H_{2}[/tex](g) ⇒ 2 [tex]NH_{3}[/tex] (g)

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  So now you can calculate again the amount of elements on each side of the chemical reaction:

You can see that you have the same amount of each element on each side of the chemical equation. This indicates that the equation is balanced.

And the coefficient in front of ammonia, [tex]NH_{3}[/tex], in the balanced equation is 2.

Final answer:

p-block metals have higher electronegativities and ionization energies compared to the reactive s-block metals. d-block metals, known as transition metals, posses variable oxidation states and form colorful compounds, setting them apart from p-block and s-block elements.

Explanation:

The properties of p-block metals differ considerably compared to those in the s-block and d-block. One of the most distinguishing features of p-block metals is their position on the periodic table - they are found in the right-most six columns. Elements in the p-block, which include both metals and nonmetals, typically have higher electronegativities and ionization energies than s-block elements, which consists mostly of metals with low electronegativities like the alkali and alkaline earth metals.

d-block elements, also known as transition metals, have a much larger range of oxidation states and, due to incomplete inner d subshells, typically exhibit properties like colorful compounds, variable oxidation states, and often function as good catalysts. Electronegativity and electron affinity generally increase from left to right across the periodic table, affecting the chemical properties of these elements.

s-block elements tend to be softer and more reactive due to their single valence electron (alkali metals) or two valence electrons (alkaline earth metals). They usually have lower melting and boiling points compared to most d-block metals. The d-block elements are characterized by their partially filled d-orbitals which allow them to form a variety of complex ions and colored compounds.

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Ideal gas is a hypothetical gas. Vanderwaal gas can behave as ideal gas at low pressure and high temperature. Therefore, the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30°C is 0.00868g.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

substituting all the given values in the above equation

(2 )(0.3 ) = n(8.314 )(303)

0.6 = n(2519.142)

n = 0.00023818 mols of HCl

mass of HCl= 0.00023818 mols of HCl ×36.46g of HCl/ 1 mol of HCl

mass of HCl = 0.00868g

Therefore, the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30°C is 0.00868g.

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Final answer:

To find the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30°C, use the Ideal Gas Law to determine the number of moles, then multiply by the molar mass of HCl. The approximate mass is 0.89 grams.

Explanation:

To calculate the mass of a 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30°C, we can use the Ideal Gas Law, which is PV = nRT. In this case, we need to rearrange the equation to solve for n (the number of moles), then convert moles to mass using the molar mass of HCl.

First, convert the volume from milliliters to liters: 300 ml = 0.300 L.

Next, since the temperature is given in degrees Celsius, convert it to Kelvin: T(K) = 30°C + 273.15 = 303.15 K.

The Ideal Gas Law in terms of n is n = PV / RT. Here, P is the pressure in atm (2.0 atm), V is the volume in liters (0.300 L), R is the ideal gas constant (0.0821 L·atm/K·mol), and T is the temperature in Kelvin (303.15 K).

Substituting the values:

Finally, we find the mass by multiplying the number of moles by the molar mass of HCl, which is approximately 36.46 g/mol.

Mass = n * molar mass of HCl = 0.0244 moles * 36.46 g/mol ≈ 0.89 g (rounded to two significant figures)

The mass of the 300 ml sample of gaseous hydrogen chloride at 2.0 atm and 30°C is approximately 0.89 grams.

Taking into account the definition of molarity, the molarity of a solution that contains 15.7g of CaCO₃ dissolved in enough water to make 275 mL of solution is 0.57 [tex]\frac{moles}{liter}[/tex].

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity= \frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

In this case, you have:

Replacing in the definition of molarity:

[tex]Molarity= \frac{0.157 moles}{0.275 L}[/tex]

Solving:

Molarity= 0.57 [tex]\frac{moles}{liter}[/tex]

Finally, the molarity of a solution that contains 15.7g of CaCO₃ dissolved in enough water to make 275 mL of solution is 0.57 [tex]\frac{moles}{liter}[/tex].

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Final answer:

Heat is transferred in three ways: conduction through direct contact, convection by fluid movement, and radiation through electromagnetic waves. Each method requires a temperature difference and can occur together.

Explanation:

Heat Transfer Methods

Heat transfer occurs through three primary methods: conduction, convection, and radiation. These processes are all driven by a temperature difference between regions or objects.

Conduction

Conduction is the transfer of heat through direct contact between materials. The rate of heat transfer (Q/t) in conduction is proportional to the temperature difference between the two objects and the area in contact, and inversely proportional to the distance between them.

Convection

Convection involves the transfer of heat by the physical movement of fluid (such as gases or liquids). This method occurs in natural phenomena like wind patterns, ocean currents, and even in heating up a pot of water on the stove.

Radiation

Radiation refers to the transfer of heat through electromagnetic waves, such as the heat from the sun reaching Earth or heat emitted from a light bulb.

These methods can occur simultaneously in various processes and are essential for understanding how heat is transferred in different contexts.

Ionization energy of an atom decreases down a group. It is due to the increase in the number of electrons and orbitals and thus screening of electrons reduces the nuclear pull.

Ionization energy is the minimum energy required to remove the loosely bound valence electron from an atom. From left to right in periodic table, the electronegativity of atoms increases thereby the ionization energy.

The positive charge of protons in the nucleus attracts the revolving electrons and each electron experiences a nuclear attractive pull which keep the electrons surrounds the nucleus.

However, one electron is shielded from the attractive pulling by its neighboring electrons and this shielding or screening increases with increases with increase in number of electrons Hence as the shielding increases, the net nuclear force decreases make it easy to remove the valence electron.

Down a group, the number of shells or orbitals increases and the electrons becomes more far from the nucleus and thus more shielded results in the decrease in ionization energy.

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Answer:8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution.

Explanation:

Volume of the solution = 400 mL

Mass by volume percentage of the solution = 2%

Mass of the glucose = m

The mass by volume percent is given by formula ;

[tex](m/v\%)=\frac{\text{mass of the solute}}{\text{Volume of the solution}}\times 100[/tex]

[tex]2\%=\frac{m}{400}\times 100[/tex]

m = 8 g

8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution.

Mass Concentration is generally denoted as mass of solute (in grams) per ml volume of solution.

Mass Concentration:

It is generally denoted as mass of solute (in grams) per ml volume of solution. It can be calculated by formula,

[tex]\bold {p = \frac{m}{v} \times 100 }[/tex]

Where,

p = mass concentration (m/v%) =  2%

m = mass in grams =  ?

v = volume in mL = 400mL

Put the values in the formula

[tex]\bold {2 = \frac{m}{400} \times 100 }[/tex]

[tex]\bold { m = 8 }[/tex]

Hence, we can conclude that the 8 g of glucose is needed to prepare 400mL of a 2%(m/v) solution.

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In a metallic bond, electrons are delocalized, meaning they are free to move around and are not associated with a single atom, forming a 'sea of electrons' around metal cations

In a metallic bond, electrons are delocalized. This means that the valence electrons are not associated with any single metal atom but are free to move throughout the entire structure of the metal. These delocalized electrons form a 'sea of electrons' around the metal cations (positive ions), leading to the characteristic properties of metals, such as conductivity of electricity and heat, ductility, and malleability.

Answer: [tex]1s^22s^22p^63s^1[/tex]

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies.

Total number of electrons of sodium are 11 as the atomic number of sodium is 11. The electronic configuration of sodium will be represented as:

[tex][Na]:11:1s^22s^22p^63s^1[/tex]

Answer:

B because it should be

Explanation:

and that is right answer??

The heat capacity of a substance is the amount of heat needed to raise its temperature by one degree Celsius. In the case of 170g of water, with a specific heat capacity of 4.18 J/g°C, the heat capacity would be approximately 710.6 J/°C.

The heat capacity of a substance is defined as the amount of heat required to raise the temperature of that substance by one degree Celsius. For water, the specific heat capacity is around 4.18 joules per gram per degree Celsius. Therefore, to find the heat capacity of 170 g of water, we multiply the mass of the water by its specific heat capacity.

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Answer: collisions between the particles of gas and the container walls

Explanation:

Pressure is defined as the force acting per unit area.

[tex]Pressure=\frac{Force}{Area}[/tex]

Thus the pressure increases as the force increases and area decreases.

The particles present in a gas have least inter molecular forces of attraction ad thus the particles are in constant motion. they keep on colliding with other particles and the walls of the container in which they are kept.

Pressure of the gas molecules is due to the bombardment of gas molecules with other gas molecules and the walls of the container.

Pressure in a closed gas container is caused by collisions between the gas particles and the walls of the container. Changes in the number or temperature of the gas particles can alter the pressure.

In a closed container of gas, pressure is caused primarily by the collisions between the particles of the gas and the walls of the container. These particles are in constant, random motion and when they hit the container walls, they exert a force on it, resulting in pressure. Neither the thickness of the container walls nor the size of the gas particles directly affect the pressure within the container. However, increasing the number of gas particles (for instance, by adding more gas) or increasing their temperature (which speeds up their motion), would increase the pressure, because these changes result in more frequent and/or harder collisions with the container walls.

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The concentration of Chloride ions in the solution of NaCl and Magnesium chloride has been 0.165 M.

The dissociation of the compound in the solution has been resulted in the formation of the constituent ions.

The concentration of the ions in the sample has been determined by the stoichiometric coefficient of the balanced equation.

[tex]\rm NaCl\;\rightarrow\;Na^+\;+\;Cl^-[/tex]

The concentration of Cl ions has been:

[tex]\rm 1\;M\;NaCl=1\;M\;Cl^-\\ 0.11\;M\;NaCl= 0.11\;M\;Cl^-[/tex]

The Cl ions from NaCl has been  0.11 M.

[tex]\rm MgCl_2\;\rightarrow\;Mg^2^+\;+\;2\;Cl^-[/tex]

The concentration of Cl ions has been:

[tex]\rm 1\;M\;NaCl=0.5\;M\;Cl^-\\ 0.11\;M\;NaCl= 0.11\;\times\;0.5\;M\;Cl^-\\0.11\;M\;NaCl=0.055\;M\;Cl^-[/tex]

The Cl ions from Magnesium chloride have been  0.055 M.

[tex]\rm Cl^-=NaCl\;+\;MgCl_2\\Cl^-=0.11\;+\;0.055\;M\\Cl^-=0.165\;M[/tex]

The concentration of Chloride ions in the solution of NaCl and Magnesium chloride has been 0.165 M.

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Answer:

Ionic compounds typically have much higher melting points than molecular compounds. ... To melt a molecular substance, you need to break these weak intermolecular forces between neutral molecules, which is why ionic compounds generally have much higher melting points than molecular compounds.

Explanation:

Answer:

Potassium (K)

Explanation:

First, you need to know the possible alkali metals, which are:

Sodium (Na), Litium (Li), Potassium (K) and Cesium (Cs), rubidium (Rb).

Now, the reaction that is taking place is the following:

M + O2 ------> M2On

Where n should be the oxidation state of the metal. In this case, most of the alkalin metals have an oxidation state of +1, so, this number should be 1. However some elements can produce the peroxyde, like litium, sodium and potassium.

The following reaction would be:

M2O + H2O --------> MOH

Now, the hint here is that the solution is tested with a flame. This, would be, the final hint to know which element this is.

In the case of sodium, litium and potassium, the reactions being held are as following:

Li + O2 ------> Li2O2         Li2O2 + 2H2O ------> 2LiOH + H2O2

Na + O2 ------> Na2O2         Na2O2 + 2H2O ------> 2NaOH + H2O2

K + O2 ------> K2O2         K2O2 + 2H2O ------> 2KOH + H2O2

Now, all of these elements throw a different color in the flame. Litium is a red or crimson. Sodium is usually yellow, and finally the potassium is always purple.

Therefore the identity of this metal would have to be potassium.

The number of molecules of ammonia present in 3.0 g of ammonia is equal to 1.1×10²³.

Avogadro’s number expressed the number of units in one mole of any substance. Generally, these units can be atoms, ions, electrons, protons, or molecules depending upon the type of the reaction or reactant and product.

The value of Avogadro’s number is 6.022×10²³. Avogadro’s number is usually denoted by the symbol ‘N[tex]_A[/tex]’.

Given, the mass of the ammonia = 3g

The molecular mass of the ammonia (NH₃) = 14 + 3(1) = 17g

As one mole of the ammonia contains molecules = Avogadro number

It means 17 grams of ammonia has molecules = 6.022×10²³

Then, 3 grams  of ammonia will have molecules of ammonia

=  6.022 × 10²³ × (3/17)

= 1.1 × 10²³ molecules

Therefore, the number of molecules of ammonia in 3 g of ammonia is   1.1 × 10²³ molecules.

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Final answer:

To find the number of ammonia molecules in 3.0g of ammonia, you calculate moles from the given mass and molar mass, then use Avogadro's number to find the molecule quantity. The result is approximately 1.06 × 10²³ molecules, matching closely to option C in the question.

Explanation:

To determine how many molecules of ammonia (NH₃) are present in 3.0g of ammonia, we first need to calculate the molar mass of NH₃. The atomic masses of nitrogen (N) and hydrogen (H) are approximately 14.01 g/mol and 1.01 g/mol, respectively. A single molecule of NH₃ consists of one nitrogen atom and three hydrogen atoms, which gives us:

Molar mass of NH₃ = (1 × 14.01 g/mol) + (3 × 1.01 g/mol) = 14.01 g/mol + 3.03 g/mol = 17.04 g/mol

Next, we use the molar mass to convert grams of NH₃ to moles:

Moles of NH₃ = mass (g) ÷ molar mass (g/mol) = 3.0 g ÷ 17.04 g/mol = 0.176 moles of NH₃

Now we can use Avogadro's number (≈ 6.022 × 10²³ molecules/mol) to find the number of molecules:

Number of molecules = moles × Avogadro's number = 0.176 moles × 6.022 × 10²³ molecules/mol

This calculation gives us approximately:

Number of molecules ≈ 1.06 × 10²³ molecules of NH₃

Looking at the options provided, the closest answer to our calculated value is C) 1.1 × 10²³, which must be a rounded version of the value we obtained.