Which of Newton's Three Laws does the following statement satisfy?
For every action there is an equal and opposite reaction.
A
Newton’s First Law
B
Newton’s Second Law
C
Newton’s Third Law

Answer:

x is the displacement of spring

Explanation:

The Hooke's law gives the force acting on the spring when it is compressed or stretched. The mathematical expression for force is given by :

[tex]F=-kx[/tex]

Where

k is the spring constant of and it shows the stiffness of spring.

x shows the displacement of spring when it is stretched or compressed from equilibrium position and it acts in opposite direction.

Answer: B. heat

Explanation:

The nuclear reaction involves the simultaneous fission and fusion of the heavy metal nuclei such as uranium in control conditions of the nuclear reactor so as to produce energy in the form of heat. The heat or thermal energy is used to boil the water and convert it the form of steam. The steam is used to run the turbine of the generator which produces electricity.  

To find the ball's speed in uniform circular motion, we can use the concept of tension, gravitational force, and trigonometry. By finding the tension in the string and using the formula for speed, we can calculate the ball's speed.

To find the ball's speed, we can use the concept of circular motion. The tension in the string provides the centripetal force that keeps the ball moving in a circle. We can use the vertical component of the tension to find the gravitational force acting on the ball. The relationship between the tension, gravitational force, and the angle can be used to solve for the speed of the ball.

Using trigonometry, we can determine that the tension is equal to the gravitational force divided by the cosine of the angle. So, T = m * g / cos(26°).

Once we have the tension, we can use it to find the speed of the ball using the formula v = √(T / m), where v is the speed, T is the tension, and m is the mass of the ball. Plugging in the values, we can calculate the speed of the ball.

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Final answer:

The rate at which the area of the triangle increases when the length of one of the equal sides is 10mm is 0 mm²/s.

Explanation:

To find the rate at which the area of the triangle is increasing, we can use the formula for the area of a right triangle, which is (1/2) * base * height. Since the triangle is isosceles, the base and height are equal. Let's call the length of the equal side x. The hypotenuse is also related to x by the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We can set up the equations:

x² + x² = c²

2x² = c²

Taking the derivative of both sides concerning time, we get:

4x * (dx/dt) = 2c * (dc/dt)

Plugging in the given values, where dx/dt = 0 (since x is constant) and dc/dt = 2mm/s, we can solve for the rate at which the area is increasing:

4(10) * (0) = 2(10.3) * (dA/dt)

0 = 20.6 * (dA/dt)

(dA/dt) = 0 mm²/s

The spring constant can be calculated using Hooke's Law. By determining the force exerted by the added mass on the spring and dividing that by the distance the spring is stretched, the spring constant is found to be 6.37 N/m.

This question is regarding the concept of Hooke's law in physics, which states that the force needed to extend or compress a spring by some distance is proportional to that distance. Given that the spring stretches an additional 10 cm when a 65g mass is added, we calculate the force exerted by the mass on the spring as F = m*g = 0.065 kg * 9.79 m/s² = 0.637 N.

Then, using the equation from Hooke's Law, F = kx, where F is the force, k is the spring constant, and x is the distance the spring is stretched, we can calculate the spring constant as k = F / x = 0.637 N / 0.1 m = 6.37 N/m.

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Correct answer choice is :

C) It is a negative ion that has one more valence electron than a neutral bromine atom.

Explanation:

A bromide is a synthetic composite including a bromide ion or ligand. Potassium bromide (KBr) is a salt, usually selected as an anticonvulsant and a drug in the late 19th and early 20th centuries, with over the stand value increasing to 1975 in the US. Potassium bromide is applied as a veterinary drug, as an antiepileptic medicine for dogs.

C. It is a negative ion that has one more valence electron than a neutral bromine atom.

Answer:

36.88 light years apart

Explanation:

use law of cosines to plug in A and B and use x as the C value you need to find with cosC = cos76.04

SI (International System of Units) is a consistent system in mathematics because it provides standard and consistent measurements based on fundamental constants of nature.

In mathematics, SI (International System of Units) is considered a consistent system because it provides a standard and consistent way of measuring physical quantities such as length, mass, time, and temperature.

SI units are based on fundamental constants of nature and are internationally recognized and used. For example, the meter is defined as the distance traveled by light in a vacuum during a specific time interval.

Consistency in SI units allows for easy comparisons, calculations, and communication across different scientific disciplines and countries.

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Answer:

15.49m/s

Explanation:

Using one of the equations of motion;

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gs

Where;

v = the final velocity of the rock.

=> This is the speed at which the rock strikes the water.

u = initial velocity of the rock.

=> The rock is just dropped from that height. That means the initial velocity is zero (0).

=> u = 0

g = the acceleration due to gravity.

=> Since the rock moves downwards, the acceleration due to gravity is positive and let it have a value of 10m/[tex]s^{2}[/tex]

=> g = 10m/[tex]s^{2}[/tex]

s = the distance covered by the rock

=> s = 12m

Substituting these values into the equation above gives

[tex]v^{2}[/tex] = [tex]0^{2}[/tex] + 2(10 x 12)

[tex]v^{2}[/tex] = 240

v = [tex]\sqrt{240}[/tex]

v = 15.49m/s

Therefore the velocity(speed) with the rock strikes the water is 15.49m/s

The strength of the magnetic field is approximately 8.22 T.

To solve for the magnetic field strength B, we use the equation that relates the force due to gravity to the magnetic force.

When the rod is floating, the gravitational force is balanced by the magnetic force. The gravitational force is given by [tex]\( F_g = m \cdot g \)[/tex], and the magnetic force is given by [tex]\( F_m = I \cdot L \cdot B \), where \( B \)[/tex] is the magnetic field strength.

Setting the gravitational force equal to the magnetic force, we have:

[tex]\[ m \cdot g = I \cdot L \cdot B \][/tex]

Now we can solve for B:

[tex]\[ B = \frac{m \cdot g}{I \cdot L} \][/tex]

Given the values:

[tex]- \( m = 40.6 \) \\g \( = 40.6 \times 10^{-3} \) kg (since 1 g \( = 10^{-3} \) kg),\\ - \( g = 9.81 \) m/s^2,\\ - \( I = 0.229 \) A\\ - \( L = 2.09 \) m,[/tex]

we can plug these into the equation:

[tex]\[ B = \frac{40.6 \times 10^{-3} \text{ kg} \cdot 9.81 \text{ m/s}^2}{0.229 \text{ A} \cdot 2.09 \text{ m}} \] \[ B = \frac{40.6 \times 10^{-3} \cdot 9.81}{0.229 \cdot 2.09} \] \[ B = \frac{0.4 \cdot 9.81}{0.47711} \] \[ B = \frac{3.924}{0.47711} \] \[ B \approx 8.22 \text{ T} \][/tex]

Setting the gravitational force equal to the magnetic force, we have:

[tex]\[ m \cdot g = I \cdot L \cdot B \][/tex]

Now we can solve for B:

[tex]\[ B = \frac{m \cdot g}{I \cdot L} \][/tex]

Given the values:

[tex]- \( m = 40.6 \) g \( = 40.6 \times 10^{-3} \) kg (since 1 g \( = 10^{-3} \) kg), - \( g = 9.81 \) m/s², - \( I = 0.229 \) A, - \( L = 2.09 \) m,[/tex]

we can plug these into the equation:

[tex]\[ B = \frac{40.6 \times 10^{-3} \text{ kg} \cdot 9.81 \text{ m/s}^2}{0.229 \text{ A} \cdot 2.09 \text{ m}} \] \[ B = \frac{40.6 \times 10^{-3} \cdot 9.81}{0.229 \cdot 2.09} \] \[ B = \frac{0.4 \cdot 9.81}{0.47711} \] \[ B = \frac{3.924}{0.47711} \] \[ B \approx 8.22 \text{ T} \][/tex]

Therefore, the strength of the magnetic field is approximately 8.22 T.

Answer:

For this we use general equation for gases. Our variables represent:

p- pressure

v-volume

t- temperature

P1V1/T1 = P2V2/T2

in this equation we know:

P1,V1 and T1, T2 and V2.  

We have one equation and 1 unknown variable.

P2 = T2P1V1/T1V2 = 1.1atm

Explanation:

the guy above me is VERY correct

The initial speed of the bullet can be determined using the principles of conservation of momentum and the work-energy theorem. Conservation of momentum gives us the velocity of the block and bullet after collision, and the work-energy theorem using the friction force and the distance gives us the velocity.

This question can be solved using the principles of conservation of momentum and the work-energy theorem. Using conservation of momentum before and after the collision, we can put: Momentum before = Momentum after. Therefore, (mass of bullet * velocity of bullet) = (total mass * velocity after). This gives us the velocity of the block and bullet together. From the work-energy theorem, work done = change in kinetic energy. Or, friction force * distance = 1/2 * mass * (velocity)^2. But friction force = mass * gravity * coefficient of friction, which gives us the equation 0.20 * 9.01 * 9.81 * 0.05 = 1/2 * 9.01 * (velocity)^2. Solving the equations together will give you the initial speed of the bullet.

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The equilibrium concentration of A is [tex]\boxed{\frac{1}{3}}[/tex].

The equilibrium concentration of B is [tex]\boxed{\frac{1}{3}}[/tex].

The equilibrium concentration of C is [tex]\boxed{\frac{2}{3}}[/tex].

Further explanation:

Chemical equilibrium is the state in which the concentration of reactants and products become constant and do not change with time. This is because the rate of forward and backward direction becomes equal. The general equilibrium reaction is as follows:

 [tex]{\text{A(g)}}+{\text{B(g)}}\rightleftharpoons{\text{C(g)}}+{\text{D(g)}}[/tex]

The equilibrium constant is the constant that relates the concentration of product and reactant at equilibrium. The formula to calculate the equilibrium constant for the general reaction is as follows:

[tex]{\text{K}}=\dfrac{{\left[ {\text{D}}\right]\left[{\text{C}}\right]}}{{\left[{\text{A}} \right]\left[{\text{B}}\right]}}[/tex]

Here, K is the equilibrium constant.

The given reaction is,

[tex]{\text{aA}}\left( g \right)+{\text{bB}}\left( g \right) \rightleftharpoons{\text{cC}}\left( g \right)[/tex]

Here,

A and B are the two reactants.

C is the product formed.

a and b are the stoichiometric coefficients of A and B respectively.

c is the stoichiometric coefficient of C.

The expression of [tex]{{\text{K}}_{\text{c}}}[/tex] for the above reaction is as follows:  

[tex]{{\text{K}}_{\text{c}}}=\dfrac{{{{\left[{\text{C}}\right]}^{\text{c}}}}}{{{{\left[{\text{A}} \right]}^{\text{a}}}{{\left[{\text{B}}\right]}^{\text{b}}}}}[/tex]   ...... (1)

Here,

[tex]{{\text{K}}_{\text{c}}}[/tex] is the equilibrium constant that is concentration-dependent.

Let the change in concentration at equilibrium is x. Therefore, the concentration of C becomes x at equilibrium. The concentration of A and B become 1-x at equilibrium.

Substitute x for [C] , 1-x for [A] and 0.57-x for [B], 1 for a, 1 for b and 2 for c in equation (1).

[tex]{{\text{K}}_{\text{c}}}=\dfrac{{{{\left[ {\text{x}} \right]}^2}}}{{{{\left[{{\text{1 - x}}} \right]}^{\text{1}}}{{\left[{{\text{1 - x}}}\right]}^{\text{1}}}}}[/tex]       ...... (2)

Rearrange equation (2) and substitute 4 for [tex]{{\text{K}}_{\text{c}}}[/tex] to calculate the value of x.

[tex]{{\text{x}}^2}=\dfrac{{{\text{8x}} - 4}}{3}[/tex]

The final quadratic equation is,

[tex]{\text{3}}{{\text{x}}^2}-8{\text{x}}+4=0[/tex]

Solve for x,

[tex]{\text{x}}={\text{2 , }}\dfrac{2}{3}[/tex]

The value of x equal to 2 is not accepted as it would make the equilibrium concentration of A and B negative, which is not possible. So the value of x comes out to be 2/3.

The equilibrium concentration of [C] is equal to 2/3.

The equilibrium concentration of A is calculated as follows:

[tex]\begin{aligned}\left[ {\text{A}}\right]&=1-\frac{2}{3}\\&=\frac{1}{3}\\\end{aligned}[/tex]

The equilibrium concentration of B is calculated as follows:

[tex]\begin{aligned}\left[ {\text{B}}\right]&=1-\frac{2}{3}\\&=\frac{1}{3}\\\end{aligned}[/tex]

So the equilibrium concentrations of A, B and C are 1/3, 1/3 and 2/3 respectively.

Learn more:

1. Calculation of equilibrium constant of pure water at 25°c: https://brainly.com/question/3467841

2. Complete equation for the dissociation of  (aq): https://brainly.com/question/5425813

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Equilibrium

Keywords: equilibrium constant, A, B, C, a, b, c, 1, 1, 2, 1/3, 1/3, 2/3, Kc, concentration dependent.

Answer:

If you break a bar magnet in half, each half becomes a magnet.

Explanation:

A substance which attracts or repels another similar substance is known as magnet. When domains align in single direction in a substance, it acts as a magnet. A magnet has two poles- North pole and South pole. Like poles repel each other and unlike poles attract each other. Mono-poles do not exist. So, when a magnet is broken into two halves, each half forms another magnet with two poles.

Answer:

If you break a bar magnet in half, each half will have a new south pole, a north pole and a neutral zone.  In other words, two new magnets will be generated.

Explanation:

A magnet is a body of any material capable of producing a magnetic field and attracting itself or being attracted to another magnet or to any other body of iron, cobalt or other ferromagnetic metals (ferromagnetism is a physical phenomenon in which magnetic ordering occurs of all the magnetic moments of a sample, in the same direction and direction. In other words, the ferromagnetic interaction is the magnetic interaction that makes the magnetic moments tend to be arranged in the same direction and direction. This property makes the ferromagnetic materials they are intensely magnetized when they are placed in a magnetic field, and retain part of their magnetization when said field disappears.). Then the magnet is a material with natural or artificial ferromagnetic properties, which generate a continuous magnetic field.

Magnets are magnetically charged bodies, which generate a magnetic field around them oriented according to two poles: negative pole (also called South pole) and positive pole (also called North pole). Opposites attract each other (positive-negative) and equal poles repel each other (positive-positive or negative-negative). The line that joins both poles is called the magnetic axis. This line located in the central zone located between both poles has no attraction or repulsion capacity.

In the event that a magnet is broken into pieces, each new fragment will have a new south pole, a north pole and a neutral zone. That is, equal and opposite poles appear on each side of the breaking point. This happens even if the fragments are of different size.

Using the work-energy principle, the average force exerted by water is found to be approximately 1639.52 N. This force is non-conservative because it involves energy dissipation in the water.

(a) Determine the magnitude of the average force that the water exerts on the diver:

The average force acting underwater is bringing the diver to rest. Thus, we can say that the force (F) will be negative, or it acts opposite to the direction of displacement (d). In this case, the work done underwater should also be negative, as W = Fdcosθ, where θ = angle between force and displacement = 180° (for this case).

Displacement under water = d = 1.14 m

According to the work-energy principle, the change in kinetic energy of the diver is equal to the work done by the force (F) exerted by the water.

First, we need to find the velocity of the person just before hitting the water.

We can use the kinematic equation:

v² = u² + 2gh

where u is the initial velocity (which is 0, since the person jumps from rest), g is the acceleration due to gravity (9.8 m/s² downward), and h is the height (2.98 m downward).

Therefore:

v² = 0 + 2 × (-9.8 m/s²) × (-2.98 m)
v² = 58.408 m²/s²
v = √58.408 m/s
v ≈ 7.64 m/s

Applying the work-energy principle, we can write:

Work = Fdcosθ = -Fd = 1/2 × m × v²

Rearranging this equation to solve for F:

F = (1/2 × m × v²) / d

Substituting the values:

F = (0.5 × 64.0 kg × (7.64 m/s) ²) ÷ 1.14 m
F = (0.5 × 64.0 × 58.424) ÷ 1.14
F ≈ 1639.52 N

(b) Is this force non-conservative?

A non-conservative force is one where the work done depends on the path taken. In this case, the force exerted by the water is non-conservative because it involves dissipative forces like drag and other resistances which convert mechanical energy into heat and other forms of energy.

Explanation:

Acceleration is defined as the change in velocity over time.

When there is an increment or increase in the magnitude of velocity of a moving body then it is known as positive acceleration.

Whereas when there is a decrease in magnitude of velocity of a moving body then it is known as negative acceleration.

Thus, we can conclude that positive acceleration occurs when an object speeds up.

The acceleration that leads to the increase in the speed of the object is called as Positive acceleration.

Explanation:

The acceleration of a body is defined as the amount of change taking place in the magnitude of the velocity of the body in every second. The acceleration of the body is a vector quantity as it requires the direction along with the magnitude of change in the speed of the body.

If the acceleration of the body is acting in the direction opposite to the direction of motion of the body, then the acceleration tends to decrease the speed of the body and it is called as deceleration.

Whereas if the acceleration of a body is in the direction same as that of the direction of motion of the body, then the acceleration of the body increases the speed of the body and this acceleration is termed as the positive acceleration of the body.

Therefore, the acceleration of an object that tends to speed up the object must be acting in the direction same as the direction of motion of the body and therefore it is termed as the positive acceleration of the body.

Thus, The acceleration that leads to the increase in the speed of the object is called as Positive acceleration.

Learn More:

1. Transnational kinetic energy brainly.com/question/9078768.

2.  Motion under friction brainly.com/question/7031524.  

3. Conservation of momentum brainly.com/question/9484203

Answer Details:

Grade: High School

Subject: Physics

Chapter: Acceleration

Keywords:

acceleration, rate of change, velocity, speed, increase, per second, direction, opposite, motion, along, speed up.

Answer:

Vector

Explanation:

Acceleration is defined as the rate of change of velocity. As velocity is a vector quantity, so acceleration is also a vector quantity.

If a car starts from rest and attains some velocity after some time, then car is accelerating and the firection of acceleration is same as the direction of velocity.

If a car is moving and after applying the brakes it come to rest it means the motion of car has negative acceleration which means the direction of velocity and the direction of acceleration is opposite to each other.

Final answer:

To determine the vertical distance climbed by the mountain hiker, we can use the relationship between air pressure and altitude. By applying the barometric formula and substituting the given values, we can solve for the change in altitude. The vertical distance climbed is 12.1 meters.

Explanation:

To determine the vertical distance climbed by the mountain hiker, we can use the relationship between air pressure and altitude. The change in air pressure, ΔP = P₁ - P₂, can be related to the change in altitude, Δh. Assuming the air density to be constant, we can use the barometric formula to find the change in altitude. The formula is given by ΔP = ρgh, where ρ is the air density, g is the acceleration due to gravity, and h is the change in altitude.

By substituting the given values into the formula, we can solve for Δh. We have ΔP = 930 mbars - 780 mbars = 150 mbars and ρ = 1.20 kg/m³. We know that g is approximately 9.8 m/s². Solving for Δh, we get Δh = ΔP / (ρg) = 150 mbars / (1.20 kg/m³ * 9.8 m/s²) = 12.1 m.

Therefore, the vertical distance climbed by the mountain hiker is 12.1 meters.

Final answer:

The vertical distance climbed by the hiker is approximately 1269 meters, calculated using the barometric pressure difference and average air density.

Explanation:

To determine the vertical distance climbed by the hiker, we can use the barometric pressure reading along with the average air density. The pressure difference (ΔP) can be used to calculate the height difference (h) using the barometric formula ΔP = ρgh, where ρ is the density of the air, g is the acceleration due to gravity (9.81 m/[tex]s^2[/tex]), and h is the height difference.

First, we convert the pressure difference from millibars to pascals (since 1 mbar = 100 pascals):
ΔP = (930 mbar - 780 mbar) × 100 Pa/mbar = 15000 Pa

Now, we can solve for h:
15000 Pa = (1.20 kg/[tex]m^3[/tex]) × (9.81 m/[tex]s^2[/tex]) × h
h = 15000 Pa / ((1.20 kg/[tex]m^3[/tex]) × (9.81 m/[tex]s^2[/tex]))
h ≈ 1269 meters

Therefore, the vertical distance climbed by the hiker is approximately 1269 meters.

By comparing the Waxing Crescent and Waxing Gibbous lunar phases, it can be seen that the Waxing Crescent is more illuminated while the Waxing Gibbous is less illuminated. Hence option A is correct.

The second stage of the cycle of phases is the Waxing Crescent. Once a month, this Moon phase lasts for 7.38 days before transitioning into the First Quarter phase. It rises at 9 AM and sets at 9 PM. The reason this phase is known as the Waxing Crescent is because the region of the Moon's surface that is lit resembles the shape of a crescent, and waxing refers to growth. The Earth, Moon, and Sun are practically perpendicular at this phase because it is one cycle away from the First Quarter phase. This indicates that the gravitational attraction of the tides from the Sun and Moon cancels out, resulting in a smaller tidal pull. At this time, the Earth's tides are practically at neap tide.

Hence option A is correct.

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The correct answer to compare the lunar phase of the Waxing Crescent to the Waxing Gibbous is D: The Waxing Crescent is less than half illuminated and the Waxing Gibbous is more than half illuminated.

Both phases are increasing in illumination as the visible portion of the moon grows. During the Waxing Crescent, there is a growing small portion, about 1/4, on the right side of the moon that is lit. As the moon moves towards the Waxing Gibbous phase, the illuminated portion increases to more than half, approximately 3/4, on the right side of the moon.

In both waxing phases, the angle formed by pointing one arm at the Moon and one arm at the Sun demonstrates an increase in the lit portion of the moon we see. In the Waxing Crescent phase, this angle is acute, and it becomes obtuse during the Waxing Gibbous phase, indicating the moon's journey towards a full moon, when the angle is 180°, and the entire near side of the moon, as viewed from Earth, is illuminated.