Answer:
b) Particles that are emitted from a strip of metal are electrons.
Explanation:
Which observation provided Albert Einstein the clue that he needed to explain the photoelectric effect?
b) Particles that are emitted from a strip of metal are electrons.
the metal is injected by photon which leads to electron emission called photo-electron.
Answer:
D is the correct answer
Explanation:
1. Describe the conditions at altitude that could limit the ability to perform physical activity.
2. What types of exercise are detrimentally influenced by exposure to high altitude and why?
3. When someone ascends to an altitude of over 1,500 m, describe the physiological adjustments that occur within the first 24 h.
4. Describe the theoretical advantage of living high and training low.
5. What are the health risks associated with acute exposure to high altitude and how can they be minimized?
Answer:
1. Lower Barometric Pressure
2. Aerobic exercise
3. Basal Metabolic Rate Increase
4. improvements in some short duration sea-level performances
5. Vomiting, insomnia , dyspnea, nausea, and headache
Explanation:
1. Lower Barometric Pressure
-Hypobaric environment of the particular altitude
-Low atmospheric pressure or Hypobaria
Reduced atmospheric pressure
- Reduced PO2 air breathed in
Reduced PO2
-Caps pulmonary oxygen diffusion from the lungs
-Restricts O2 transport to the tissues
Low PO2 content in the air
-Also known as hypoxia
Hypoxia
-Low O2
Associated Low PO2 in the blood
-Hypoxemia
2. what types of exercise are detrimentally influenced by exposure to high altitude and why
aerobic exercise
The oxygen requirements of aerobic exercise leads to increased heart rate and , resulting tiredness within a short period of time
3. When someone ascends to an altitude of over 1500 m, describe the physiological adjustments that occur within the first 24 h
- Basal Metabolic Rate Increase
- Arterial PO2 Reduction
- Progressive Decrease In Blood plasma volume
- Blood pH increases
- Decreases in Pressure Gradient
- Drop in Alveolar PO2
- Increases in Ventilation
4. Describe the theoretical advantage of living high and training low
The logic in this system is that acclimatising the body to altitude by living there, and maintaining training intensity by training at sea level provides the harnessing of the gains of altitude exposure and avoiding some of the negative effects of altitude exposure. There are improvements in some short duration sea-level performances by keeping to the above technique.
5. Vomiting, insomnia , dyspnea, nausea, and headache
Consider the ascent rate, the altitude intended to be ascended, and the experience of the individual with the altitude to reduce the likelihood for symptoms to manifest.
At high altitudes, low oxygen levels can lead to acute mountain sickness and limit sustained aerobic exercise. Physiological adjustments such as increased breathing rate (hyperpnea) and red blood cell production occur within the first 24 hours, and 'living high, training low' offers competitive advantages by leveraging acclimatization benefits. Acute high altitude exposure risks can be mitigated through gradual ascent, hydration, and avoiding strenuous activity.
Explanation:Conditions at high altitudes can significantly impede physical activity due to the low partial pressure of oxygen, which leads to low blood and tissue levels of oxygen. Acute mountain sickness (AMS) is a potential consequence of such exposure, marked by symptoms like headaches, disorientation, and nausea. These can become more severe during physical exertion, underlining the importance of acclimatization.
Exercise types that involve sustained aerobic performance, like endurance running or cycling, are especially detrimentally influenced at high altitudes. The availability of oxygen is crucial for aerobic respiration, and with less oxygen available, performance can drop significantly.
Within the first 24 hours of ascending to over 1,500 m, physiological adjustments occur, including an increase in breathing rate (hyperpnea) and depth to compensate for lower oxygen levels, a phenomenon also known as hyperventilation. Over days to weeks, the body starts to produce more red blood cells, improving the oxygen-carrying capacity of the blood.
The theoretical advantage of living high and training low centers around the physiological benefits of acclimatization, such as increased red blood cell count, while still being able to train at peak capacity at lower altitudes with more oxygen available.
Health risks associated with acute exposure to high altitudes include AMS, cerebral edema, and pulmonary edema. Minimizing these risks involves a gradual ascent to allow for acclimatization, staying hydrated, and avoiding over-exertion.
Discuss the uses for topographic surveys Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer? Help Reset Topographic surveys are used whenever elevation data is required in the end product. Some examples include.(1) creating maps for highway construction ; (2) creating maps for construction design surveys (3) creating maps for flood plain delineation ; (4) creating maps for site location of buildings; and so on.
Complete Question
The complete question is on the first uploaded image
Answer:
Topographic Survey
This can be defined as a process that involves gathering data about the elevation of points on a piece of land and represent them as a outlines or contour lines on a plan.The reason for carrying out topographic survey is to collect survey data about the natural and the man-made features of the land,as well as its elevations.
The uses for topographic survey
Topographic surveys are used to map and identify the terrain of a land area.They efficiently account for any exiting objects on or near the surface, such as streets,buildings ,manholes,walkways,retaining walls,utility poles ,and trees, topographic also takes into account differences in elevation, which are marked on the survey by contour lines.
Topographic survey helps to assess a land for a new construction or the addition of new development.it is invaluable for showing what the the land looks like and how it would impact or affect construction, and this assessment is relevant for all kind of projects such as road improvements,new housing ,complex construction, major highway construction ,grading ,bridge erection,septic system installation,and drainage projects,e.t.c.
Topographic survey is also very important in for identifying areas that construction may not be feasible or where grading will be required in order to make it feasible. This survey provides architects and builders with required information so as to determine how the land will have be shaped and molded to provide a suitable base for the planned construction.
On completion of an initial project topographic survey can be used as basis for a other subsequent plans and designs.Topographic survey can be used for environmental reclamation projects. This survey and the information they provide on elevation and terrain features can help in the accurate and successful reconstruction of a given landscape.
Considering the question that requires filling the blank space
We see that Geological has to do with beneath the land hence its not suitable
Hence
The first blank should be filled with TOPOGRAPHIC
The second blank should be CONSTRUCTION
The third blank should be filled with SURVEY
Note: A construction survey is one that gives the location and sites for construction activities,
The Fourth blank should be DELINEATION
Delineation can be defined as the act of drawing sketching or tracing an outline.
Explanation:
A circus acrobat is shot out of a cannon with an initial upward speed of 34 ft/s. if the acrobat leaves the cannon 4 ft above the ground, how long will it take him to reach a net that is 8 ft above the ground
This physics problem can be solved using the principles of motion under gravity, we plug our known values into the equation of motion and solve the resulting quadratic equation for time.
Explanation:This is an example of a physics problem under the theme of motion, specifically vertical motion under gravity. To answer this, you must apply the principles of physics to determine the total time the acrobat will spend in the air from the moment he is shot out of the cannon until the moment he touches the net.
In this situation,l we'll use the equation of motion, Y = Yo + Vot + 0.5gt² , where
Y is the final height (which is the height of the net, 8 ft), Yo is the initial height (which is the height the acrobat is shot from, 4 ft), Vo is the initial vertical speed (which is 34 ft/s), g is the acceleration due to gravity (which on earth is -32 ft/s² because it is downward), andt is the time we are trying to solve for.Plugging the known values into the equation, we obtain a quadratic equation in terms of t. Solving this quadratic equation will give us two solutions for t, one for the upward journey and one for the downward journey. The acrobat reaches the height of the net along his upward journey from the cannon, so we pick the smaller t as the correct solution (as it occurs first).
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The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 40-m-diameter loop-the-loop. What is the car's speed at the top?
Answer:
Explanation:
Given
Diameter [tex]d=40\ m[/tex]
radius [tex]r=20\ m[/tex]
From diagram, at top point
If Normal force is equal to Gravitational force
[tex]N=mg[/tex]
where N=normal reaction
m=mass of car
Normal reaction will provide centripetal force
[tex]N=\frac{mv^2}{r}[/tex]
thus
[tex]\frac{mv^2}{r}=mg[/tex]
[tex]v=\sqrt{2gr}[/tex]
[tex]v=\sqrt{2\times 9.8\times 20}[/tex]
[tex]v=19.79\ m/s[/tex]
The speed of a roller coaster car at the top of a 40-m-diameter loop, when the normal force equals the gravity, is 20 m/s.
Explanation:The question asks for the speed of a roller coaster car at the top of the loop. In this scenario, it is said that the normal force equals the magnitude of the gravitational force. The normal force is the force exerted by a surface to support the weight of an object resting on it. When the roller coaster car is at the top of the loop, the gravitational force (Fg) and normal force (Fn) are acting in the same direction and their sum provides the necessary centripetal force (Fc) for the car to continue its circular motion.
Therefore, we have Fn + Fg = Fc, but as it's mentioned Fn = Fg, so it will be 2Fn = mv²/r. Here, Fn=mg so we can replace it to the equation which is 2mg = mv²/r. Because 'm' (mass) is on both sides of the equation, we can eliminate it, which leaves 2g = v²/r. Rearranging the equation to solve for 'v' (velocity) gives v = square root of (2gr). Given that g (gravity) = 9.8 m/s² and r (radius) = 20 m (half of the 40 m diameter), we solve the equation: v = square root of (2 * 9.8 m/s² * 20 m) = 20 m/s.
Therefore, the roller coaster's speed at the top of a 40-m-diameter loop is 20 m/s.
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Two force vectors are perpendicular, that is, the angle between their directions is ninety degrees. If their magnitudes are 4.52 newtons and 7.33 newtons, then what is the magnitude of their sum?
F=__________ newtons
Explanation:
Resultant, R of two vectors P and Q is given by,
[tex]R=\sqrt{P^2+Q^2+2PQcos\theta }[/tex]
Here P = 4.52 N
Q = 7.33 N
θ = 90°
Substituting
[tex]R=\sqrt{4.52^2+7.33^2+2\times 4.52\times 7.33\times cos90 }\\\\R=8.61N[/tex]
Magnitude of their sum, F = 8.61 N
A(n) 26000 kg freight car is rolling along a track at 3.3 m/s. Calculate the time needed for a force of 1150 N to stop the car. Answer in units of s.
Answer:
The time = 74.61 s.
Explanation:
From Newton's Third law of motion,
The force needed to stop is equal and opposite to the propelling force from the engine of the freight car.
F = ma ........................ Equation 1
Where F = force needed to stop the the freight car, m = mass of the freight car, a = acceleration of the freight car.
a = F/m....................... Equation 2.
Given: F = - 1150 N(Opposite in direction to the motion of the car) m = 26000 kg.
Substituting into equation 2
a = -1150/26000
a = -0.04423 m/s²
Also
v = u + at
t = (v-u)/a.................... Equation 3
Where t = time needed for the force to stop the car, v = final velocity, u = initial velocity, a = acceleration.
Given: u = 3.3 m/s v = 0 m/s (brought to rest), a = -0.04423 m/s²
Substituting into equation 3
t = (0-3.3)/-0.04423
t = -3.3/0.04423
t = 74.61 sec.
Thus the time = 74.61 s
A laser is thrown upward with a speed of 12 m/s on the surface of planet X where the acceleration due to gravity is 1.5 m/s2 and there is no atmosphere. What is the maximum height reached by the laser?
Answer:
48 m
Explanation:
Initial speed of laser,u=12 m/s
Acceleration due to gravity=-[tex]1.5m/s^2[/tex]
Because laser goes against to gravity when it is thrown in upward direction.
Final velocity of laser=v=0
We know that
[tex]v^2-u^2=2as[/tex]
Substitute the values then we get
[tex]0-(12)^2=2(-1.5)s[/tex]
[tex]-144=-3s[/tex]
[tex]s=\frac{144}{3}[/tex]
[tex]s=48 m[/tex]
Hence, the maximum height reached by the laser= 48 m
The maximum height reachedby the laser is 48 m.
To calculate the maximu height reached by the laser, we use the formula below.
Formula:
v² = u²+2gH........... Equation 1Where:
u = Initial velocityv = final velocityg = accceleration due to gravity of planet XH = maximum height reached by the laser.Make H the subject of the equation
H = (v²-u²)/2g........... Equation 2From the question,
Given:
v = 12 m/su = 0 m/sg = 1.5 m/s²Substitute these values into equation 2
H = (12²-0²)/(2×1.5)H = 144/3H = 48 mHence, The maximum height reachedby the laser is 48 m.
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The sun’s energy hits earth’s surface at the most direct angle at which locations?
Answer:
at the Equator
Explanation:
The four seasons are determined by four main positions in the Earth's orbit in its turn around the Sun (ecliptic plane), which are called solstices and equinoxes: winter solstice (Capricorn point, December 22), spring equinox (Aries point, around March 21-22), summer solstice (Cancer point, June 21) and autumn equinox (Libra point, around September 22-23).
In the equinoxes, the axis of rotation of the Earth is perpendicular to the sun's rays, which fall vertically over the equator. In solstices, the axis is inclined 23.5º, so that the sun's rays fall vertically on the Tropic of Cancer (summer in the northern hemisphere) or Capricorn (summer in the southern hemisphere).
When falling vertically on Ecuador, it generates a greater impact on the surface of the Tierre reaching a greater amount of energy and therefore UV rays.
Technician A says that shop air pressure usually ranges from 100–150 psi. Technician B says shop air pressure is around 300 psi. Who is correct?
Answer:
technician A.
Explanation:
Commonly, air pressure rating of standard shop air compressor's is between the range of 100 psi and 150 psi. And over the years since, the plant pressure creep's up , the level of pressure increases from 100 psi to at max 150 psi but not more than that. Therefore, in the given question technician A is correct and technician B is incorrect.
If the cold temperature reservoir of a Carnot engine is held at a constant 331 K , what temperature should the hot reservoir be kept at so that the engine efficiency is 0.55 ?
Answer:
735.56 K
Explanation:
Carnot Engine: A Carnot engine is a an engine that operates on Carnot cycle.
A Carnot cycle: is defined as an ideal reversible closed thermodynamic operation, in which there are four successive and reversible cycles. These operations include isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression.
The efficiency of a Carnot engine is given below,
η=(Th-Tc)/Th.................................................... Equation 1
η = 1-(Tc/Th)........................................ Equation 2
Where Th = temperature of the hot reservoir, Tc = temperature of the cold reservoir, η = efficiency of the Carnot engine.
Given: Th = 331 K, η = 0.55
Substitute into equation 2
0.55 = 1-(331/Th)
0.55-1 = -331/Th
-0.45 = -331/Th
331/Th = 0.45
Th = 331/0.45
Th = 735.56 K.
Thus the temperature of the hot reservoir is 735.56 K.
To determine the hot reservoir temperature required for a Carnot engine to operate with a given efficiency, you can use the equation ηc = 1 - Tc/Th, where ηc is the engine's efficiency, Tc is the cold reservoir temperature, and Th is the hot reservoir temperature. Given an engine efficiency of 0.55 and a cold reservoir temperature of 331K, you can rearrange the equation to solve for the hot reservoir temperature.
Explanation:The efficiency of a Carnot engine is given by the equation ηc = 1 - Tc/Th, where ηc is the engine's efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir. Given that the engine's efficiency (ηc) is 0.55 and the cold reservoir temperature (Tc) is 331K, you can rearrange the equation to solve for the hot reservoir temperature (Th):
Th = Tc / (1 - ηc)
Substituting the given values into this equation yields the hot reservoir temperature required for the engine to operate with an efficiency of 0.55.
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Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is moving upward with increasing speed, your weight will be:
Answer:increased
Explanation:
It is given that elevator speed is increasing while moving upward i.e.its acceleration is increasing .
This causes the apparent to be increased if measured using weighing machine.
considering upward direction to be positive
N-mg=ma
N=m(g+a)
where N=Normal reaction=Apparent weight
a=acceleration of Elevator
thus you feel as if your weight is increased.
When an elevator accelerates upwards, your weight feels heavier due to the additional force pushing you into the floor.
Explanation:Acceleration is the rate of change of an object's velocity with respect to time. It is a vector quantity, measured in meters per second squared in the International System of Units (SI). Acceleration can be positive (speeding up), negative (slowing down), or zero (constant velocity), and it plays a crucial role in describing the dynamics of motion.
When an elevator starts moving upwards with increasing speed, your weight will feel heavier compared to when the elevator is at rest. This increase in weight is due to the upward acceleration experienced by both you and the elevator. The force of gravity acting on your body remains the same, but now there is an additional force pushing you against the floor of the elevator, resulting in the feeling of increased weight.
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The breastbone is posterior to the spine.. Unselected The collarbone is superior to the shoulder blade. Unselected The elbow is proximal to the wrist. Unsure I AM UNSURE The naval is distal to the chin.
Answer:
The breast bone is anterior to the spine. The collarbone is superior to the shoulder blade. The elbow is proximal to the wrist. The navel is distal to the chin.
Explanation:
The spine, also known as the backbone, is posterior to the breast bone.
The collarbone (also known as the clavicle), which is part of the shoulder girdle, lies superior in position to the shoulder blade (also known as the scapula).
The elbow is the joint between the arm and the wrist. it is proximal to the wrist.
The navel, located on the anterior abdominal wall, is distal to the chin that is part of the face.
If the surface of Earth were to suddenly turn white, the temperature of the planet would ________ because ________ insolation would be absorbed.
Answer: decrease; less
Explanation:
Insolation, refers to the amount of solar radiation that is received by earth. If the surface of earth was white, the radiation, will be reflected back into space. This reflective activity of a white surface will in turn cause the temperature of the planet to drop as there would be less energy to be converted to heat.
Answer:
A. Earth would cool down because it would reflect more solar radiation.
Explanation:
was right on edge :)
What is the net force that accelerates an object on an inclined plane due to the effect of gravity, normal force and friction of the inclined plane on the object?
The net force that accelerates an object on an inclined plane is the parallel component of the weight minus the force of friction.
Explanation:When an object rests on an inclined plane that makes an angle with the horizontal surface, the weight of the object can be resolved into components that act perpendicular and parallel to the surface of the plane.
The net force that accelerates an object on an inclined plane is the component of the weight that acts parallel to the plane, minus the force of friction. The force of gravity acting on the object is divided into two components: a force acting perpendicular to the plane (normal force) and a force acting parallel to the plane. The parallel component of the weight causes the object to accelerate down the incline.
If there is friction present on the inclined plane, the force of friction opposes the motion of the object and must be subtracted from the parallel component of the weight. The net force can then be calculated by subtracting the force of friction from the parallel component of the weight.
An electrically neutral object is given a negative charge. In principle, does the object's mass increase, decrease, or stay the same as a result of being charged?
Answer:
Decreases fundamentally for getting positive charge and increases in case of obtaining a negative charge.
Explanation:
As we know that the basic elemental unit of charge is an electron. All the charges are fundamentally quantized in multiples of an electron charge.
So, whenever a neutral object is charged, it either looses electron to get a positive charge or gains electron to be negatively charged and precisely electron has some mass so there is change in the mass of the object at microscopic level when it gets charged.
The student has access to the following measurement equipment: a spring scale, a meterstick, and a stopwatch. The student uses the spring scale to pull the cart starting from rest along a horizontal surface such that the reading on the spring scale is always constant. All frictional forces are negligible. In addition to the spring-scale reading, which two of the following quantities could the student measure with the available equipment and then use to determine the inertial mass of the cart? Select two answers.
A) The total distance traveled by the cart after it has been in motion
B) The average speed of the cart while in motion
C)The acceleration of the cart while in motion
D)The time during which the cart is in motion
Answer:
(A) and (D)
With the meter rule the boy can measure the total distance travelled by the cart by application of a constant force.
With the stopwatch he can measure the time it took the cart to cover that distance.
Explanation:
Knowing the distance covered by the cart and how long it took to cover that distance, the equation of constant acceleration motion can be used to find the acceleration of the cart during that motion.
S = ut + 1/2at²
S = distance covered
a = acceleration of the cart and
t = time taken.
The student can measure the acceleration of the cart and the total distance traveled to determine the inertial mass of the cart.
Explanation:The student can measure the acceleration of the cart while in motion by using the stopwatch and the meterstick. They can measure the time it takes for the cart to reach a certain distance and calculate the acceleration using the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity (which is zero in this case), and t is the time taken.
The student can also measure the total distance traveled by the cart after it has been in motion using the meterstick. By measuring the total distance and knowing the time, they can calculate the average speed of the cart using the formula v = d / t, where v is the average speed, d is the distance traveled, and t is the time taken.
Therefore, the two quantities that the student can measure to determine the inertial mass of the cart are the acceleration of the cart and the total distance traveled by the cart.
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The scientific method is a process by which scientists: prove theories to be known facts gain confidence in theories by failing to prove them wrong show all theories to be wrong test the ideas of Aristotle?
Answer:
The scientific method is the process by which scientists gain confidence in theories by failing to prove them wrong.
Explanation:
Scientific method is a step by step process of creating and carrying out experiments. These processes to be performed are derived from logical and rational application of knowledge concerning a particular subject matter. Through these processes, scientists reach a conclusion about the world, these makes them confident in their findings.
The steps involved in scientific method include:
Observation: it is the first step. It enables you organise in your mind how you want the experiment to.
HYPOTHESIS is the result you imagine you'll find.
PREDICTION is how you think about the scientific idea- It solely relies on the hypothesis made.
EXPERIMENT is used to test your hypothesis. It is the tool designed to check if your idea is right or wrong.
CONCLUSION is the final step. It is the result gotten from the experiment. It can approve the hypothesis or reject the hypothesis.
A theory is formed when hypothesis has been tested to be true by many scientists. Hence scientists gain confidence in theories when the scientific method is approved.
A scientific theory is a well-approved explanation of an aspect of the natural world. The approval is based on thoroughly confirmed hypothesis and experiments carried out by many scientists.
Asexual reproduction of freshwater and some marine sponges that involves the formation of resistant capsules containing masses of amoeboid cells called ____________________..
Answer:
The answer is gemmules.
Explanation:
When the parent freshwater sponge dies in the winter, it releases gemmules, which can survive both freezing and drying. When favorable conditions return in the spring, amoe-boid cells stream out of a tiny opening, called the micropyle, and organize into a sponge.
The scientific theory for the origin of our solar system, involving the condensation and collapse of interstellar material in a spiral arm of the Milky Way galaxy, is the ____________________ theory.
Answer:
The Solar Nebula theory
Explanation:
The solar nebula theory describes the origin and formation of the solar system. It explains how the solar system originated from a gaseous cloud, that was comprised of interstellar dust particles and gases. From this giant cloud, the sun formed at the center, and the rest of the planets were formed by the process of condensation. These planets gradually started to rotate and revolve around the sun and were controlled within an elliptical or circular path due to the presence of a strong gravitational force of attraction.
This solar system was constructed in a spiral arm of the huge milky way galaxy.
This solar nebula theory was the ancient accepted theory for the formation of the solar system.
The scientific theory for the origin of our solar system is the nebular hypothesis, which states that the Sun and the planets formed from the collapse of a giant cloud of gas and dust called a nebula.
Explanation:The scientific theory for the origin of our solar system, involving the condensation and collapse of interstellar material in a spiral arm of the Milky Way galaxy, is the nebular hypothesis. According to this hypothesis, the Sun and the planets of our solar system formed about 4.6 billion years ago from the collapse of a giant cloud of gas and dust, called a nebula. The material in the nebula gradually came together due to gravity, forming a spinning disk. Within this disk, smaller clumps of matter called planetesimals started to form, which eventually coalesced to form the planets and moons.
A 100-coil spring has a spring constant of 540 N/m. It is cut into four shorter springs, each of which has 25 coils. One end of a 25-coil spring is attached to a wall. An object of mass 76 kg is attached to the other end of the spring, and the system is set into horizontal oscillation. What is the angular frequency of the motion? Number Entry field with incorrect answer now contains modified data Units Entry field with correct answer
Answer:
w = 5.3311 rad/sec
Explanation:
n = 100 has a k = 540 N/m
k depends on the number of coils by:
[tex]k = \frac{G*d^4}{8*n*D^3}[/tex]
By the design equation we see that the spring stiffness k has an inverse relationship with number of coils n.
Hence, when n = 25 coils ; k = 4* 540 = 2160 N/m
The relationship between angular frequency and k is:
[tex]w = \sqrt{\frac{k}{m} }\\\\Hence,\\\\w = \sqrt{\frac{2160}{76} }\\\\w = 5.3311 rad/sec[/tex]
The angular frequency is approximately 5.34 rad/s.
To determine the angular frequency of the motion, we need to follow these steps:
Determine the spring constant of the shorter spring.Use the spring constant and mass to calculate the angular frequency.Calculate the spring constant of one of the 25-coil springs.
Since the original spring has 100 coils and a spring constant of 540 N/m, the spring constant of one 25-coil spring, k(short), is:
k(short) = 4 * k(original) = 4 * 540 N/m
k(short) = 2160 N/m
Calculate the angular frequency, ω, using the formula:
ω = √(k / m)Where:
k = 2160 N/mm = 76 kgThus,
ω = √(2160 N/m / 76 kg) ω ≈ 5.34 rad/sThe angular frequency of the motion is approximately 5.34 rad/s.
A mother and daughter are on a seesaw in the park. How far from the center must the 124 lb mother sit in order to balance the 46 lb daughter sitting 8 ft from the center. Answer in ft
1. 4.31
2. 2.35
3. 3.08
4. 3.47
5. 3.36
6. 3.94
7. 1.99
8. 3.646
9. 2.96
10. 2.435
Answer:
2.97 ft
Explanation:
for balance ;
suppose mother is sitting on the right
clockwise moment = anti-clockwise moment
124*x = 46*8
124x = 368
x = 2.97 ft
Peter and Fred are skateboarding in a large semicircular halfpipe. Peter starts out from rest at a height h and collides with Fred standing at the bottom. Peter and Fred have about the same mass. After the collision, which height will Fred reach?
Answer:
The answer is h/4
Explanation:
When Peter collides with Fred, the collision is inelastic & they both proceed with a velocity of V/2.
let m represent the masses for Peter & Fred
v represent the initial velocity of Peter
V represent final velocity of both of them
mv + 3m × 0 = (m+m)V
V = v/2
Using the expression; H = v² / 2g .............Eqn 1
Upon substitution of V/2 into Eqn 1 above,
H = (V/2)² / 2g
H = (V²/4) ÷ 2g
Therefore height will be h/4
Final answer:
In a semi-circular halfpipe scenario, Peter starting from rest at a height h and colliding with Fred will result in an inelastic collision, where they would not reach the initial height h due to the combined mass and shared kinetic energy post-collision.
Explanation:
The question you are asking regards a physical scenario involving conservation of energy and momentum in a skateboarding situation. When Peter, starting from rest at a height h, collides with Fred, who is at the bottom, the collision will exchange energy and momentum between the two. Assuming they have the same mass and the collision is perfectly inelastic (they stick together), they will move together with a combined mass of 2m (where m is the individual mass of Peter or Fred) and reach a new height that is less than h.
Based on the conservation of energy, because there are no external forces doing work (ignoring friction and air resistance), the potential energy at the initial height h will be equal to the kinetic energy at the bottom of the halfpipe. In an inelastic collision where the two objects stick together, they move with a common velocity after the collision. Since the kinetic energy after the collision must be shared by both masses, the combined system must have less kinetic energy per unit mass than Peter did alone before the collision, therefore, they won't reach the original height h.
A 450-g black crow is raiding the recently-filled bird feeder. As someone runs out the back door to scare the crow away, it pushes off the 670-gram feeder with a takeoff speed of 1.5 m/s. Determine the speed at which the feeder initially recoils backwards.
Answer:
2.50 m/s
Explanation:
This question can be solved using momentum conservation equation
combined mass of crow and feeder = 450+670=1120 gm
let the recoil speed of feeder be v m/s
Then applying momentum conservation we get;
1120×1.5 = 670×v
v= 2.50 m/s
the speed at which the feeder initially recoils backwards = 2.50 m/s
Final answer:
By applying the conservation of momentum principle, the feeder initially recoils at a speed of approximately 1.007 meters per second when a 450-gram crow pushes off of it with a takeoff speed of 1.5 m/s.
Explanation:
The question you've asked is rooted in the principle of conservation of momentum in physics. When the crow pushes off from the feeder, both the crow and the feeder will have momenta that are equal in magnitude and opposite in direction, assuming no external forces act on the system. The situation described can be solved using the formula for conservation of linear momentum, which states that the total momentum of a closed system remains constant if no external forces are acting on it.
To find the speed at which the feeder recoils, we use the fact that the initial momentum of the system (before the crow pushed off) was zero since the feeder was at rest. Consequently, the momentum of the crow after pushing off and the momentum of the feeder must cancel each other out:
Mass of crow imes Velocity of crow = Mass of feeder imes Velocity of feeder
(450 g) imes (1.5 m/s) = (670 g) imes Velocity of feeder
We now need to solve the Velocity of the feeder:
Velocity of feeder = (450 g imes 1.5 m/s) / (670 g)
Velocity of feeder = (675 g imes m/s) / (670 g)
Velocity of feeder \ 1.007 m/s
Note that we converted the masses to kilograms in the calculation (which isn't shown above) because the unit of mass in the formula for momentum (p = mv) should be in kilograms to match with the unit for velocity in meters per second (m/s). The feeder recoils at a speed of approximately 1.007 meters per second.
A country produces pears and barley . 1.) using the 3-point curved line drawing tool, draw a representative ppc for this country. label it 'ppc'. 2.) using the point drawing tool, show a production point that is efficient. label it 'a'. 3
Answer:
1) The representative PPC for the country is shown on the first uploaded image.
2)The point labeled A on the uploaded image is the efficient production point
Explanation:
In order to gain an understanding for how the solution was gotten we need to gain an understanding of what PPC( Production Possibility curve) is
PPC (Production Possibility curve):
The Production Possibility curve (PPC) can be defined as a curve that give insight on various combinations of the amounts of two goods which can be produced within the given resource and technology it can also be as a graphical representation showing all the possible options of output for two products that can be produced using all factors of production,given that all the available resources are fully and efficiently utilized.
Looking at the diagram uploaded the TT⁾ curve represents the PPC of this economy that we are considering.The slope of the of PPC is MRT (Marginal Rate Transformation) and this measures the rate at which how much production of one goods has to be reduced to increase the production of another goo.looking at the curve we see that this PPC is negatively sloped which implies that as the production of one good increases,the production of the other goods decreases.
The point A on the curve is the efficient point because all point on the PPC curve are efficient ,since all points on the PPC represents the maximum production of goods utilizing the given resources in the best way,and the given technology.
A train moving near the speed of light enters a tunnel. According to a person standing in the middle of the tunnel, the back end of the train enters the tunnel just as the front end is emerging. What happens according to someone sitting in the middle of the train?
Answer: The person sitting in the middle of the train sees the back of the train enter ing the tunnel before the front end comes out.
Explanation:
Learning Goal: To practice Problem-Solving Strategy 7.1 Rotational dynamics problems. Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the angular acceleration when it has an angle of 10.0 degrees from the vertical?
Final answer:
To find the angular acceleration of a falling pencil, use the equation angular acceleration = gravitational acceleration * sin(theta) / length. Plug in the provided values and solve for angular acceleration. With the given angle and assuming a pencil length, the angular acceleration is 1.07 rad/s^2.
Explanation:
To find the angular acceleration of a falling pencil, we can use the equation:
[angular acceleration = gravitational acceleration * sin(theta) / length].
Given that the angle is 10.0 degrees and the length of the pencil is not provided, we can assume a typical length of a pencil (15 cm). The gravitational acceleration can be taken as 9.8 m/s^2. Plugging in these values into the formula, we get:
[angular acceleration = 9.8 m/s^2 * sin(10.0 degrees) / 0.15 m].
Simplifying the equation, we get angular acceleration = 1.07 rad/s^2.
A very elastic rubber ball is dropped from a certain height and hits the floor with a (2pts) downward speed v. Since it is so elastic, the ball bounces back with the same speed v going upward. Which of the following statements about the bounce are correct? (There could be more than one correct choice.) 1. The balrs mpmentum was conserved during the bounce. 2. The ball ha the same momentum just before and just after the bounce. 3. The magnitude of the ball's momentum was the same just before and just after the bounce. 4. All of the above 5. None of the above
Answer:
3.True. The magnitude of momentum is the same
Explanation:
Let's propose the solution of the problem
The initial moment is
p₀ = m v
The final moment
[tex]p_{f}[/tex] = m (-v)
p₀ = - [tex]p_{f}[/tex]
Now we can review the claims
1. False. We see that the moment module is the same, but its direction changes
2. False. The impulse is a vector
3.True. The magnitude of momentum is the same
A car travels 120 miles in the same amount of time that it takes a truck to travel 100 miles. The car travels 10 miles per hour faster than the truck. True or false?
Answer:
The affirmation is only true if the truck is traveling at 50 mi/h.
Explanation:
Hi there!
Let´s use the equation of average velocity (AV) to solve this problem:
AV = Δx / t
Where:
Δx = traveled distance.
t = time.
For the car, its average velocity (vc) will be:
vc = 120 miles / t
For the truck:
vtr = 100 miles / t
If we solve both equations for t and then equalize them (since the time is the same for both vehicles):
vc = 120 miles / t
t = 120 mi / vc
vtr = 100 miles / t
t = 100 mi / vtr
120 mi / vc = 100 mi / vtr
multiply both sides by vc and divide by 100:
120 mi / 100 mi = vc / vtr
1.2 = vc / vtr
1.2 · vtr = vc
The car travels 1.2 times faster than the truck.
Let´s see at which velocity of the truck, the car is traveling 10 mi/h faster. In this case, vc = 10 mi/h + vtr:
1.2 · vtr = 10 mi/h + vtr
1.2 vtr - vtr = 10 mi/h
0.2 vtr = 10 mi/h
vtr = 10 mi/h / 0.2
vtr = 50 mi/h
The affirmation is only true if the truck is traveling at 50 mi/h.
Suppose that the Sun were to collapse from its current radius of about 700,000 km to a radius of only about 6000 km (about the radius of Earth). What would you expect to happen as a result?
Answer:
Only there will be a change in density of sun.
Explanation:
As your question says only the radius of sun is decreased and there is no change in the mass. So it means that the center of gravity will be the same and as a result the gravitational force remains the same. Only the density of sun changes as it shrinks.
Answer: Nothing significant.
Explanation: The energy flux emited by the sun will remain the same even if the sun's radius reduces drastically.
The energy from the sun reaching the Earth is given by the Stefan-Boltzmann equation.
Energy flux = Boltzmann's constant * T⁴
Energy flux = {{5.67*EXP(-8) watt per meter² per K⁴}*{5800K}⁴} = 63*EXP(6) Watt per meter²
Where EXP means 10^, and T= sun blackbody temperature 5800K.
It is good to know that the energy flux from the sun reaching the Earth does not depend on radius ( either it increases or decreases). The energy it supplies to earth remain the same.
Which of the following is an obstacle to creating computer-based models for tracking a hurricane?
1. Hurricanes form over water, where it is difficult to observe them.
2. Most sources of data about hurricanes are anecdotal and unreliable.
3. Forecasters must consider a large number of variables that affect the path of the storm.
4. all of the above
Final answer:
All of the options mentioned are obstacles to creating computer-based models for tracking a hurricane. Hurricanes form over water, making them difficult to observe accurately, most sources of data about hurricanes are anecdotal and unreliable, and forecasters need to consider a large number of variables that affect the path of the storm.
Explanation:
All of the above options are obstacles to creating computer-based models for tracking a hurricane.
Hurricanes form over water, making them difficult to observe accurately. Most sources of data about hurricanes are anecdotal and unreliable, which poses a challenge for accurate modeling. Additionally, forecasters need to consider a large number of variables that affect the path of the storm, such as wind speed, atmospheric pressure, and temperature.