Which is an equivalent equation solved for t?
FIL
The equation f = v + at represents the final velocity of an
object, f, with an initial velocity, V, and an acceleration rate,
a, over time, t.
Ot=f-v
o t=F-a
II
Ot= a(f-v)
Ot= vif- a)​

Answers

Answer 1

Answer:

Step-by-step explanation:

f = v + at....solving for t

f = v + at....subtract v from both sides

f - v = at....divide both sides by a

(f - v) / a = t or could also be : t = f/a - v/a <==

Answer 2

The equivalent equation for the given expression f = v + at  is (f - v) / a = t. The correct option is C.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

The given expression is f = v + at, where, the final velocity of an object, f, with an initial velocity, V, and an acceleration rate, a, over time, t.

The given expression for ' t ' is calculated as:-

f = v + at....solving for t

f = v + at....subtract v from both sides

f - v = at....divide both sides by a

(f - v) / a = t

The above expression can also be written as given below:-

t = f/a - v/a <==

Hence, the expression  f = v + at for t will be equal to (f - v) / a = t. Then the correct option is C.

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Related Questions

Is 1.4949949994.. a rational number

Answers

I can’t tell you for sure but I believe it’s not a rational number I could be wrong though

Distributive property of 1/2 • -2 2/5

Answers

Answer:

-6/5

Step-by-step explanation:

-2 2/5=-12/5

1/2*-12/5=-12/10=-6/5

A gym instructor has a total of 60 hand weight in her studio. Some of the hand weights are 3 pound weights and the rest are 5 pound weights. If there are 10 more 5-lb weights than 3-lb weights, then how many of each kind does she have?

Answers

Answer:

35 5-lb weights25 3-lb weights

Step-by-step explanation:

Let t and f represent the numbers of three- and five-pound weights. The problem statement tells us ...

  f + t = 60

  f - t = 10

Adding these two equations, we get ...

  (f +t) +(f -t) = (60) +(10)

  2f = 70 . . . . . eliminate parentheses

  f = 35 . . . . . . divide by 2

She has 35 5-lb weights, and 25 3-lb weights.

What is the perimeter of this red polygon?

Answers

Answer:

Answer: The perimeter of the red polygon is 26 cm.

Step-by-step explanation:

Answer:

Tangents from an external point are equal. This can be used to find the perimeter

Perimeter = 22+22+22+22+27+27+98+98

= 338 in.

Hope this helps!

How to solve 7(x+2y)=

Answers

Answer:

7x + 14y

Step-by-step explanation:

7(x + 2y)

Multiply 7 by the values inside the parenthesis (x + 2y)

7x + 14y

Hope this helps :)

A triangle has vertices at A(-7, 6), B(4,9), C(-2, -3). What are the coordinates of each vertex if the triangle is translated 4 units right and 6 units down?

Answers

Answer:

[tex]A'(-3,0),B'(8,3),C'(2,-9)[/tex]

Step-by-step explanation:

we know that

the triangle is translated 4 units right and 6 units down

so

The rule for the translation is

[tex](x,y) -----> (x+4,y-6)[/tex]

Applying the rule for the translation find the image of each vertex

1) [tex]A(-7,6) -----> A'(-7+4,6-6)[/tex]

[tex]A(-7,6) -----> A'(-3,0)[/tex]

2) [tex]B(4,9) -----> B'(4+4,9-6)[/tex]

[tex]B(4,9) -----> B'(8,3)[/tex]

3) [tex]C(-2,-3) -----> C'(-2+4,-3-6)[/tex]

[tex]C(-2,-3) -----> C'(2,-9)[/tex]

a supermarket sells 2 kg and 4 kg of sugar a shipment of 1100 bags of sugar has a total mass of 2900 kg. How many 2 kg bags and 4 kg bags are in the shipment​

Answers

Final answer:

To find the number of 2 kg and 4 kg sugar bags in the shipment, we use a system of equations. By setting x as the number of 2 kg bags and y as the number of 4 kg bags, we determine that there are 750 bags of 2 kg sugar and 350 bags of 4 kg sugar.

Explanation:

To solve the problem of determining how many 2 kg bags and 4 kg bags of sugar are in the shipment of 1100 bags with a total mass of 2900 kg, we need to set up a system of equations and solve for the variables representing the quantities of each type of bag. Let's denote x as the number of 2 kg bags and y as the number of 4 kg bags.

The first equation represents the total number of bags:
x + y = 1100.

The second equation represents the total weight of the bags:
2x + 4y = 2900.

We can solve these equations using substitution or elimination methods. For simplicity, let's multiply the first equation by 2 and subtract it from the second equation:

2(x + y) = 2(1100) --> 2x + 2y = 2200(2x + 4y) - (2x + 2y) = 2900 - 22002y = 700y = 350

Now that we know y, we can substitute it back into the first equation to find x:

x + 350 = 1100x = 750

Therefore, there are 750 bags of 2 kg sugar and 350 bags of 4 kg sugar in the shipment.

Consider the transformation shown
Use the drop-down menus to complete the sentence.
The transformation is
because the
preserved
Image
Pre-image

Answers

Answer:

Nonrigid

Segment lents are not

Step-by-step explanation:

Answer:

answer in picture

Step-by-step explanation:

if anyone can answers these i will give them a brainlist.

1. A tree casts a shadow 21 m long. The angle of
elevation of the sun is 51°. What is the height of the
tree?

2.a helicopter is hovering over a landing pad 100m from where you are standing. the helicopter’s angle of elevation off the ground is 12 degrees. what is the altitude of the helicopter?

Answers

Answer:

1. X= 25.9 meters

2.X= 21.3 meters

Step-by-step explanation:

1. Tan 50°= X/21

2. Tan 12°= X/100

A man and his wife go shopping. They begin with $200 total. First, they stop for lunch, spending $15.00. Then, they buy three items at $20.00 each. Later, the wife spends twice what her husband spends. They return home with $20.00 cash. How much did the wife spend?

Answers

Amount spent by the wife is $70

Step-by-step explanation:

Given:

the total amount  = $200

Amount spent on Lunch = $15.00

They buy three items at $20.00 each

The wife spends twice what her husband spends

They return home with $20.00 cash.

To Find:

Amount spent by the wife  = ?

Solution:

Initially after spending $15.00 on lunch they balance cash with them will be

200 - 15.00 = $185

Then they are buy 3 items each of which costs $20.00

So the balance after buying the 3 items will be

= 200 - 3(20)

= 185- 60.00

= $125

Now the wife is spending twice what her husband spends

so let the amount spent be the husband be x then the amount spent by the wife will be 2x.

Now  after spending 2x+x amount they are  left with $20.00

that is

125 -2x+x  = 20

125 -3x = 20

125 -20 = 3x

105 = 3x

[tex]x = \frac{105}{3}[/tex]

x = 35

So the wife will be spending 2(35) = $70

Alegbra, K12 Question. Answer needed ASAP --- Brainliest to the correct answer!

Answers

Good evening ,

Answer:

-1

Step-by-step explanation:

From the table :

f(x) = g(x) only when x = -1 then -1 is the only solution

f(-1) = 9 = g(-1)

note : the equation could have some other solutions not shown in the table

:)

I need help -6(2x+6)=-132

Answers

Answer:

x=8

Step-by-step explanation:

First you want to distribute -6 to (2x+6) which you will then get -12x-36=-132. Now you want to get x by itself by getting rid of -36, so add 36 on both sides of the equation to get -12x=-96. Isolate x by dividing by -12 on both sides of the equation which will leave you with the equation x=8

The rectangle below has an area of 12y^2+21y^5.
The width of the rectangle is equal to the greatest common monomial factor 12y^2 and 21y^5
What is the length and width of the rectangle?
Width= ?
Length=?

Answers

Answer:

The  length of the rectangle is[tex](4+7y^3)[/tex] and its  width is[tex]3y^2[/tex]

Step-by-step explanation:

Given:

The Area of the rectangle =[tex]12y^2+21y^5[/tex].

Width is the greatest common factor of  [tex]12y^2[/tex] and[tex]21y^5[/tex]

To Find:

The length and width of the rectangle = ?

Solution:

Step 1: Finding the greatest common factor of [tex]12y^2[/tex]and[tex]21y^5[/tex]

[tex]12 y^2[/tex]= 2 x 3 x 3 x y x y

[tex]21y^5[/tex] = 3 x 7 x y x y x y x y x y

Thus the greatest common factor is [tex]3y^2[/tex] which is the width

Step 2: Finding the length and width

The area of the rectangle  = length x breath

width x length=  [tex]12y^2+21y^5.[/tex]

Taking[tex]3y^2[/tex] commonly from each term, we get

width x length= [tex](3y^2)(4 + 7y^3)[/tex]

Teresa, Charlie, and Justin served a total of 153 orders Monday at the school cafeteria. Justin served 4 times as many orders as Charlie. Teresa served 9 more orders than Charlie. How many orders did they each serve?

Answers

Teresa served 33 orders and Charlie served 24 orders and Justin served 96 orders

Solution:

Let "a" be the orders served by Teresa

Let "b" be the orders served by Charlie

Let "c" be the orders served by Justin

Teresa, Charlie, and Justin served a total of 153 orders

Therefore,

a + b + c = 153 -------- eqn 1

Justin served 4 times as many orders as Charlie

Orders served by Justin = 4( orders served by Charlie )

c = 4b ---------- eqn 2

Teresa served 9 more orders than Charlie

orders served by Teresa = 9 + orders served by Charlie

a = 9 + b ----------- eqn 3

Let us solve eqn 1 and eqn 2 and eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

9 + b + b + 4b = 153

9 + 6b = 153

6b = 153 - 9

6b = 144

b = 24

Substitute b = 24 in eqn 3

a = 9 + 24

a = 33

Substitute b = 24 in eqn 2

c = 4(24)

c = 96

Thus Teresa served 33 orders and Charlie served 24 orders and Justin served 96 orders

An 8-oz tub of yogurt causes two dollars and a 32 ounce tube cost is six dollars what fraction of the cost of the large tube is the small tub?

Answers

The required fraction is [tex]\bold{\frac{1}{3}}[/tex]

Solution:

Given:

Cost of 32 ounces tub = $6

Cost of 8 ounces tub = $2

To find:

what fraction of the cost of the large tube is the small tub.

From the given, here we can understand that the large tub is the 32 ounces tub and the smaller one is the 8 ounces tub.

Let k be the required fraction.

Therefore, [tex]\bold{k\times6=2}[/tex]

On solving we get,

[tex]\bold{\Rightarrow k=\frac{2}{6}\rightarrow k=\frac{1}{3}}[/tex]

Select all the functions whose graphs include the point (16,4). Pick 2 answers. A. y=2x B. y=x2 C. y=x+12 D. y=x−12 E. y=1/4x

Answers

Option "D. y=x−12" and "E. y=1/4x" are the functions whose graphs include the point (16,4)

Step-by-step explanation:

In order to find the functions whose graph includes the point we will put the point in the functions one by one

So,

A. y=2x

Putting x = 16 and y = 4

[tex]4 = 2(16)\\4\neq 32[/tex]

B. y=x^2

Putting x= 16 and y=4

[tex]4 = (16)^2\\4 \neq 256[/tex]

C. y=x+12

Putting x= 16 and y=4

[tex]4 = 16+12\\4 \neq 28[/tex]

D. y=x−12

Putting x= 16 and y=4

[tex]4 = 16-12\\4 = 4[/tex]

E. y=1/4x

Putting x= 16 and y=4

[tex]4 = \frac{1}{4} * 16\\4 = 4[/tex]

Hence,

Option "D. y=x−12" and "E. y=1/4x" are the functions whose graphs include the point (16,4)

Keywords: Functions, graphing

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Answer:

Step-by-step explanation:

The answers are D and E

Complete the equation of the line through (-6,-5) and (−4,−4)
Use exact numbers.
y=
Please help me!!!!

Answers

Answer:

y=1/2x -2. Hope this helps!

A math teacher wants to buy 25 new scientific calculators for the classroom. Acme and Zenith makes two different type of calculators. Acme calculators cost $15 each. Zenith calculators cost $12 each. The math teacher has $330 to spend. How many of each calculators can she buy?

Answers

Answer: 10 Acme and 15 Zenith.

She can buy 10 Acme and 15 Zenith calculators.

What is the system of equations?

One or many equations having the same number of unknowns that can be solved simultaneously called as simultaneous equation. And simultaneous equation is the system of equation.

Given:

A math teacher wants to buy 25 new scientific calculators for the classroom.

Acme and Zenith makes two different type of calculators.

Acme calculators cost $15 each.

Zenith calculators cost $12 each.

The math teacher has $330 to spend.

Let x represents the number Acme calculators and y represents Zenith.

Now, we have the system of equations,

x + y = 25

So, y = 25 - x

And 15x + 12y = 330

Substituting the value of y,

15x + 300 - 12x = 330

3x = 330 - 300

3x = 30

x = 10

So, y = 15

Therefore, 10 Acme and 15 Zenith calculators.

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BICYCLING The bicycle path at the
park is a loop that covers a distance
of m miles. Dot biked 2 loops each on
Monday and Wednesday and 3 loops
on Friday. On Sunday, Dot biked
10 miles. Write an expression in
simplest form that represents the
total distance that Dot biked this
week.

Answers

Dot bikes 7m+10 miles this week.

Step-by-step explanation:

Distance of one loop = m miles

Distance of 2 loops = 2m

Distance of 3 loops = 3m

Distance covered on Sunday = 10 miles

Total distance = Monday + Wednesday + Friday + Sunday

Total distance = 2 loops + 2 loops + 3 loops + 10 miles

Total distance = 2m + 2m + 3m + 10

Total distance = (7m+10) miles

Dot bikes 7m+10 miles this week.

Keywords: addition, distance

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You take a pan of brownies out of the oven and set them on the counter in a room that is 70 degrees F, If the brownies start at 400 degrees F, approximately how long will it be before they are cool enough to eat at 160 degrees F? Use Newton's Law of Cooling with k = 0.035.

Answers

Answer:

i would say wait abought 50 mins

Step-by-step explanation:

i dont know whow to explain i might be wrong but its some whaere around 50 mins irl

Using Newton's Law of Cooling with a cooling constant of 0.035, it will take approximately 42.53 minutes for the brownies to cool from 400 degrees F to 160 degrees F.

To estimate the time it would take for brownies to cool from 400 degrees F to 160 degrees F using Newton's Law of Cooling, we can use the equation [tex]T(t) = T_s + (T_0 - T_s)e^{(-kt)[/tex], where T(t) is the temperature of the object at time t, T_s is the surrounding temperature, T_0 is the initial temperature of the object, and k is the cooling constant (0.035 in this case).

First, set T(t) = 160 degrees F (the desired temperature), T_s = 70 degrees F (room temperature), and T_0 = 400 degrees F (initial temperature of brownies). Plug in the values into the equation: 160 = 70 + (400 - 70)e^(-0.035t).

Simplify and solve for t. Subtract 70 from both sides: 90 = 330e^(-0.035t). Divide both sides by 330: 90/330 = e^(-0.035t), which simplifies to 0.2727 ≈ e^(-0.035t).

Take the natural logarithm of both sides to solve for t: ln(0.2727) = -0.035t. Solving for t gives t ≈ -ln(0.2727)/0.035, which calculates to approximately t ≈ 42.53 minutes.

Hence, the brownies should cool to 160 degrees F in about 42.53 minutes.

A gardener uses a wheelbarrow to move soil from a truck to his garden. On the first trip from the truck to the garden, the wheelbarrow
is half-full of soil and the gardener applies a certain force to cause it to accelerate. On the second trip, the wheelbarrow is full of soil.
Although the gardener applies the same amount of force to the wheelbarrow, he cannot move it with the same rate of acceleration.
What should the gardener do to move the wheelbarrow at the same rate of acceleration for the second trip?
A. reduce the amount of soil by one-half and apply the same amount of force
B. keep the amount of soil the same and apply less force
C. reduce the amount of soil by one-quarter and apply the same amount of force
D. double the amount of soil, and apply less force
Reset
Reset
Submit
1 of 10 Answered
Session Timer: 4:08
Session Score: 0% (0/1)

Answers

Answer:

Step-by-step explanation:

it seems to me that if he wants the same rate of acceleration as the first trip, then he would need the same amount of soil as the first trip.

Therefore, he should reduce the amount of soil by one half and apply the same force. <====

Because the first time it was half full.....and since the second trip was all the way full, if he reduced it by one half, it would contain the same amount as the first trip....so he can then get the same rate of acceleration.

Answer:

A.

Step-by-step explanation:

According to Newton's second law of motion, an object with a larger mass requires more force to accelerate it at a certain rate than an object with less mass. This means that an object with a larger mass requires more force to accelerate.

To move the wheelbarrow at the same rate of acceleration for the second trip, the amount of soil must be the same as in the first trip. Since the gardener first filled only one-half of the wheelbarrow with soil, the gardener must reduce the amount of soil by one-half and apply the same amount of force.

The coordinates of the midpoints of GH are M (4,3) and the coordinates of one endpoints are G (5,-6) the coordinates of the other endpoints are

Answers

Answer:

The co - ordinates of another end point is

(x,y) = (3, 12)

Step-by-step explanation:

step :-

mid point formula:-

Let [tex](x_{1} ,y_{1} ) and (x_{2} ,y_{2} )[/tex] be any two end points

Mid point of two given points are

[tex](\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2} )[/tex]

let (x,y ) be the another end point

given one end point is (5,-6)

now by using mid-point formula , we get

[tex](\frac{x+5}{2} , \frac{y-6}{2} )[/tex]  this is equating to given mid-point is M(4,3)

now [tex](\frac{x+5}{2} , \frac{y-6}{2} )=(4,3)[/tex]

simplify , we get

[tex]\frac{x+5}{2} =4 and \frac{y-6}{2} =3[/tex]

cross multiplication and simplify

[tex]x+5 = 8 and y-6=6[/tex]

x = 3 and y = 12

The another point is (x,y) = (3,12)

Find the next two terms of this sequence
112, 28, 7, ...........​

Answers

Answer:

1.75, 0.4375

Step-by-step explanation:

Note there is a common ratio between consecutive terms, that is

r = 28 ÷ 112 = 7 ÷ 28 = 0.25

Thus the sequence is geometric.

To obtain a term in the sequence multiply the previous term by 0.25

7 × 0.25 = 1.75

1.75 × 0.25 = 0.4375

The next 2 terms in the sequence are 1.75, 0.4375

Eight less than 1/3 a number n is -13?

Answers

the answer would be 13.86 I believe

PLS I NEED ASAP WILL GIVE BRAINLIEST
Which equation is linear?
y=2x+2
2
y=2x^+2
3
y=2x^+2
4
y=2x^+2

Answers

For this case we have that by definition, a linear equation is of the form:

[tex]ax + b = 0[/tex]

The variable (s) involved in the equation always have exponent 1.

Some examples of linear equations are:

[tex]x + 5 = 3y\\y + 6 = 3x\\y = 2x + 2[/tex]

Answer:

In a linear equation the variables have exponent 1.

[tex]y = 2x + 2[/tex]

rearrange the equation so b is the independent variable a-7=3(b+2)

Answers

Answer:

Step-by-step explanation:

a - 7 = 3(b + 2)

a - 7 = 3b + 6

a - 7 - 6 = 3b

a - 13 = 3b

(a - 13) / 3 = b <====

Answer:

-13-1/4 b

Step-by-step explanation:

b is on the outside of the fraction not with the four.

-13-\frac{1}{4b}

Find the value of the polynomial 3xy+7x^2−3x^2y+3y^2x−2x^2−2xy+4x^2y−2y^2x, when x=1 and y=−2

Answers

Answer:

[tex]5[/tex]

First Method:

Substitute the given values in for [tex]x[/tex] and [tex]y[/tex].Solve.

This isn't the only method, but it seems the least likely to result in an incorrect answer.

If [tex]x=1[/tex] and [tex]y=-2[/tex], find the solution to:

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x[/tex]

Substitute [tex]1[/tex] for [tex]x[/tex] and [tex]-2[/tex] for [tex]y[/tex].

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x\\3(1)(-2)+7(1)^2-3(1)^2(-2)+3(-2)^2(1)-2(1)^2-2(1)(-2)+4(1)^2(-2)-2(-2)^2(1)[/tex]

Wow. That's a lot. Let's try simplifying things. I'd start by multiplying all our [tex]1[/tex]'s because any number multiplied by [tex]1[/tex] is that very same number, so we can easily reduce the length of our equation without much worry for messing up our math in the process.

[tex]3(-2)+7-3(-2)+3(-2)^2-2-2(-2)+4(-2)-2(-2)^2[/tex]

It still looks like torture trying to figure out this equation, but let's take it in chunks instead of all at once.

[tex]3(-2)+7-3(-2)+3(-2)^2-2-2(-2)+4(-2)-2(-2)^2[/tex]

First, I'm going to deal with all the exponents, and turn them into integers.

[tex]3(-2)+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)[/tex]

Notice that things are starting to look less complicated. We are taking our math in chunks. This will make it less likely for us to mess up, although it is more time consuming.Now, let's do multiplication. Any number within a parentheses is going to be multiplied by the number next to it. Remember that this only applies when there is no sign between them. I'm going to go one at a time.

[tex]3(-2)+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7-3(-2)+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7+6+3(4)-2-2(-2)+4(-2)-2(4)\\-6+7+6+12-2-2(-2)+4(-2)-2(4)\\-6+7+6+12-2+4+4(-2)-2(4)\\-6+7+6+12-2+4-8-2(4)\\-6+7+6+12-2+4-8-8\\[/tex]

This is a lot of steps, but hopefully it doesn't looks as bad after seeing that I just did multiplication over and over. I'll go over another method after this that may make things less complicated.Now, we add these together. It doesn't matter what order you do this in.

[tex]-6+7+6+12-2+4-8-8\\7+4+6+12-6-2-8-8\\11+18-8-16\\29-24\\5[/tex]

Our final answer is [tex]5[/tex].

Here's another method:

If [tex]x=1[/tex] and [tex]y=-2[/tex], find the solution to:

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x[/tex]

Because we know that any number multiplied by [tex]1[/tex] will be that same number, let's just substitute in [tex]x[/tex] for now.

[tex]3xy+7x^2-3x^2y+3y^2x-2x^2-2xy+4x^2y-2y^2x\\3(1)y+7(1)^2-3(1)^2y+3y^2(1)-2(1)^2-2(1)y+4(1)^2y-2y^2(1)\\[/tex]

Now, just like before, we can multiply [tex]1[/tex] without doing complicated math. Just basically get rid of it even when it's squared because [tex]1^2=1*1=1[/tex].

[tex]3(1)y+7(1)^2-3(1)^2y+3y^2(1)-2(1)^2-2(1)y+4(1)^2y-2y^2(1)\\3y+7-3y+3y^2-2-2y+4y-2y^2\\3y^2-2y^2+3y-3y-2y+4y+5\\y^2+2y+5[/tex]

Looks a LOT less complicated. Substitute [tex]-2[/tex] in for [tex]y[/tex] and get your final answer.

[tex]y^2+2y+5\\(-2)^2+2(-2)+5\\4-4+5\\5[/tex]

3x = x+6 show the steps please​

Answers

Answer:

x = 3

Step-by-step explanation:

Given

3x = x + 6 ( subtract x from both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Answer:

Step-by-step explanation:

3x = x + 6.....subtract x from both sides

3x - x = x - x + 6

2x = 6 ...divide both sides by 2

(2/2)x = 6/2

1x = 6/2

x = 3 <=====

(-8,-4)&(2,-9) fint the distance between each pair of points

Answers

Answer:

[tex]5 \sqrt{5} [/tex]

Step-by-step explanation:

We want to find the distance between (-8,-4) and (2,-9).

We use the distance formula:

[tex]d = \sqrt{ {(x_2-x_1)^2} +(y_2-y_1)^2 } [/tex]

We substitute the coordinates to get:

[tex]d = \sqrt{ {(2- - 8)^2} +( - 9 - - 4)^2 } [/tex]

We simplify to obtain:

[tex]d = \sqrt{ {(2 + 8)^2}+( - 9 + 4)^2 } [/tex]

Add the numbers within the parenthesis to get:

[tex]d = \sqrt{ {(10)^2}+( -5)^2 } [/tex]

Find the squares of the numbers under the radical

[tex]d = \sqrt{ {100}+25} [/tex]

[tex]d = \sqrt{125} = 5 \sqrt{5} [/tex]

Graph the system of linear inequalities. y≥2/3 x-3 y<-4x+7

Answers

Answer:

The answer is given in the graph attached.

Step-by-step explanation:

i) The answer is given in the graph attached.

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