Answer:
Electric energy moves through the wire to the lamp's bulb. In the bulb's filament, electric energy transforms into thermal energy and light energy.
Explanation:
Suppose you throw a baseball downward from a roof so that it initially has 120 J of gravitational potential energy, and 10 J of kinetic energy. What will be true of the kinetic energy at the ground?
A.
It will be 0 J.
B.
It will be greater than 10 J.
C.
It will decrease from 10 J.
D.
It will equal 10 J.
Answer:
B.
It will be greater than 10 J.
Explanation:
The total mechanical energy of an object is the sum of its potential energy (PE) and its kinetic energy (KE):
E = PE + KE
According to the law of conservation of energy, when there are no frictional forces on an object, its mechanical energy is conserved.
The potential energy PE is the energy due to the position of the object: the highest the object above the ground, the highest its PE.
The kinetic energy KE is the energy due to the motion of the object: the highest its speed, the largest its KE.
Here at the beginning, when it is at the top of the roof, the baseball has:
PE = 120 J
KE = 10 J
So the total energy is
E = 120 + 10 = 130 J
As the ball falls down, its potential energy decreases, since its height decreases; as a result, since the total energy must remain constant, its kinetic energy increases (as its speed increases).
Therefore, when the ball reaches the ground, its kinetic energy must be greater than 10 J.
Answer:
the correct answer is BExplanation:
You serve a volleyball with mass of 2.1kg. The call leaves your hand at 30m/s. The ball has Energy calculate it
Answer: 945 joules
Explanation:
Given that:
mass of volleyball = 2.1kg.
Speed at moving volleyball = 30m/s. Energy possessed by volleyball = ?
Recall that the energy possessed by a moving object is known as kinetic energy. Thus, the moving volleyball has kinetic energy.
So, apply the formula for kinetic energy
K.E = 1/2 x mass x speed^2
K.E = 1/2 x 2.1kg x (30m/s)^2
K.E = 0.5 x 2.1kg x 900
K.E = 945 Joules
Thus, the volleyball has kinetic energy of the 945 joules
Gabby puts a 5.8 kg weight on a spring and it stretches 1.4 m. What is the spring constant of the spring? (Remember kg is not a force it is a mass) (F = Kx)
Answer:
40.6 N/m
Explanation:
From Hooke's law we relate the extension of a spring and the applied force by the formula F=kx where F is the applied force, k is spring constant and x is extension of spring.
Making k the subject of the formula then we have
[tex]k=\frac {F}{x}[/tex]
We also know that F=gm where g is acceleration due to gravity which we take as 9.81 m/s2 while m is the mass. Substituting F with gm into the formula we get that
[tex]k=\frac {gm}{x}[/tex]
Substituting m for 5.8 kg and x for 1.4 m we get the spring conatant as
[tex]k=\frac {9.81\times 5.8}{1.4}=40.641428571428\ N/m\approx 40.6\ N/m[/tex]
Therefore, the spring constant is approximately 40.6 N/m
A 0.14 -kg baseball is moving at 41 m/s. A 0.058-kg tennis ball is moving at 67 m/s. Which of the two balls has higher kinetic energy?
Answer:The answer is tennis ball
Explanation:
i know this cause I'm good at math and why wouldn't you trust a random guy off the internet.
The drawing shows two thermometers, A and B, whose
temperatures are measured in °A and °B. The ice and boiling
points of water are also indicated.
(a) Using the data in the drawing, determine the number of B
degrees on the B scale that correspond to 1 A° on the A scale.
(b) If the temperature of a substance reads +40.0°A on the A
scale, what would that temperature read on the B scale?
(Cutnell 354)
a) 1 A° corresponds to 1.22 B°
b) [tex]105.4^{\circ}B[/tex]
Explanation:
a)
The image of the problem is missing: find it in attachment.
Here we have two temperature scales:
- In scale A, the freezing point is at [tex]-30.0^{\circ}A[/tex], while the boiling point is at a temperature of [tex]+60.0^{\circ}A[/tex]
- In scale B, the freezing point is at [tex]+20.0^{\circ}B[/tex], while the boiling point is at a temperature of [tex]+130.0^{\circ}B[/tex]
The freezing point and the boiling point must be at the same absolute temperature on the two scales: this means that the interval
(boiling point - freezing point)
must be the same in the two scales.
For scale A, this interval is equal to:
[tex]\Delta T_A = +60.0-(-30.0)=90.0^{\circ}A[/tex]
For scale B, this interval is equal to:
[tex]\Delta T_B=+130-(+20)=110^{\circ}B[/tex]
Therefore, 1 degree on the A scale corresponds to:
[tex]\frac{x^{\circ}B}{1^{\circ}A}=\frac{110^{\circ}B}{90.0^{\circ}A}\\x^{\circ}B=\frac{110}{90}\cdot 1=1.22[/tex]
So, 1 A° corresponds to 1.22 B°.
b)
The temperature of the substance on the A scale is
[tex]T_A=+40.0^{\circ}A[/tex]
This means that the difference of its temperature relative to the freezing point on the A scale is
[tex]\Delta T_A=+40.0-(-30.0)=70.0^{\circ}A[/tex]
In part A, we stated that 1 degree on the A scale corresponds to 1.22 degrees on the B scale, so this temperature interval on the B scale is
[tex]\Delta T_B=1.22\Delta T_A=1.22(70)=85.4^{\circ}B[/tex]
And therefore, the temperature of the substance on the B-scale is equal to the freezing point (on the B scale) plus this interval:
[tex]T_B=+20.0+85.4=105.4^{\circ}B[/tex]
To convert temperature readings from scale A to scale B, find the ratio of the differences between the boiling and ice points on each scale, then use this ratio to multiply the temperature on scale A.
Explanation:The subject matter of the question is temperature conversion between two different scales - scale A and scale B. To answer the questions:
(a) to determine the number of degrees B that correspond to 1 degree A, one would need to calculate the difference in degrees on B scale between the ice and boiling points, and divide that by the difference in degrees on the A scale between the same two points.(b) to find out what a temperature reading in A would be in B, we would multiply the A temperature by the ratio we calculated in the first step.
For example, if the boiling point of water is 100A and 80B, and the ice point is 0A and 20B, the calculation would be (80B-20B)/(100A-0A) = 0.6 B/A. Therefore, if a temperature reads +40.0A, it would read 0.6*40=24B on the B scale.
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The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.
Answer:
The correct statements are:
A. The electric field is nonuniform.D. Charge Q is positive.E. If charge A moves toward charge Q, it must be a negative chargeExplanation:
The answer choices are:
A. The electric field is nonuniform.B. The electric field is uniform.C. Charge Q is negative.D. Charge Q is positive.E. If charge A moves toward charge Q, it must be a negative charge.F. If charge A moves toward charge Q, it must be a positive charge.SolutionThe electric field is the electrostatic force per unit of charge,
[tex]\vec E=\dfrac{\vec F}{Q}[/tex]
around around a charge, where another charge would experience the electrostatic force.
The electric field lines are shown in a diagram with arrows ditributed radially away from a positive charge and radially toward a negative charge.
Since the arrows are away from Q, Q is a positive charge: statement D.
Since the size of the arrows decreases as you move away from Q the stregth of the field is not uniform: statement A.
Since the charge Q is positive, a negative charge would be attracted toward it: statement E.
In the following diagram, the voltage is 1.5 volts and the resistance is 0.35 ohms. Use Ohm's Law to determine the current in the circuit.
Answer:
I = 4.28 [amp]
Explanation:
To solve this type of problems we must have knowledge of the law of ohm, which tells us that the voltage is equal to the product of resistance by current.
Initial data:
v = 1.5 [volt]
R = 0.35 [ohms]
v = I * R
therefore:
I = 1.5 / 0.35
I = 4.28 [amp]
Final answer:
Using Ohm's Law, the current in the circuit with a voltage of 1.5 volts and a resistance of 0.35 ohms is calculated to be approximately 4.286 amperes.
Explanation:
To determine the current in the circuit, we can use Ohm's Law, which is stated as I = V/R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms. Given that the voltage (V) is 1.5 volts and the resistance (R) is 0.35 ohms, we can substitute these values into the equation to calculate the current.
Thus, the current (I) can be calculated as follows:
I = 1.5V / 0.35Ω = 4.286 amperes (approx).
This means that the current flowing through the circuit is approximately 4.286 amperes.
What contributes the most to food waste in America
According to the USDA, 40% of our food worth $161 billion is not even harvested, lost in processing, thrown away in restaurants and homes or ended up rotting in America’s landfills. It is also reported that 50% of the produce is never consumed.
Disparities in food distribution and availability imply that numerous communities and neighborhoods have very constrained access to fresh affordable food. Also, a significant number of those with a bounty of food choose to toss it rather than donate it.
Another type of food waste comes from produce discarded by millions of backyard cultivators due to their gardens producing far more fruits and vegetables than they might use, preserve or give to friends and neighbours.
_____ All elements in this series are radioactive?
Answer:
Actinide series : All the elements in the actinides series are radiactive
Explanation:
The question is to fill in the blank which series of elements in the periodic table are radiactive.
The answer is the actnide series.
The actinide series is the elements in the same row as actinide since the same actnide (atomic number 89) to the lawrencium (atomic number 103).
Among other elements, this series include thorium, uranium and plutonium which are very known as radiactive elements, since they are used in nuclear reactors, which use nuclear fission reactions.
The reason for the radioactivity of these elements is the massive unstable nucleus.
A heavy nucleus means a large amount of positive charge (protons) concentrated in a tiny region (the nucleus of the atom).
The electrostatic repulsion among those so many protons is not balanced by the strong nuclear force (from the neutrons) resulting in the unstability (radioactivity) of the nucleus.
In a radioactive decay series, not all elements are radioactive. The series includes most of the naturally radioactive elements, but each series concludes with a stable, non-radioactive end-product, typically a stable isotope of lead.
Explanation:The question you've asked relates to Radioactive Decay Series. Naturally occurring radioactive isotopes of the heaviest elements fall into decay series. These series include most of the naturally radioactive elements of the periodic table such as the uranium series, the actinide series, and the thorium series. However, not all elements in these series are radioactive; each chain ultimately concludes with a stable end-product. For example, for all three mentioned series, the end-product is a stable isotope of lead. The concept of a decay series results from heavy nuclei decaying to a lighter one, with the lighter, daughter nucleus becoming the parent nucleus for the next decay.
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An object is given an initial velocity. What will happen to the object if no other forces act on it?
The object will slow down and eventually come to a stop.
The object will accelerate at a constant rate.
The object will move at a constant rate in a straight line.
The object will travel in an elliptical path forever.
Answer:
The object will travel at a constant rate in along a straight line.
Explanation:
In the given situation, it is mentioned that there is no external force acting on the given object. Thus, it will retain its initial velocity along a straight path.
An object given an initial velocity and no other forces acting on it will move at a constant rate in a straight line.
Explanation:The object will move at a constant rate in a straight line.
If an object is given an initial velocity and no other forces act on it, it will continue to move at a constant speed in a straight line. This concept is a fundamental principle in physics known as Newton's first law of motion or the law of inertia. According to this law, an object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force. In reality, there are usually forces like gravity and friction that can affect an object's movement, but, in theory (or in a vacuum), without those forces, an object's motion would remain unchanged.
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The centre of gravity of a body may not be necessary on the body. Justify
Answer:
Your center of gravity
Explanation:
like everyone has there own center of gravity by there weight because that is going to see hows your balance, if I'm right
The center of gravity is the point where the total weight of a body is concentrated, but it may not always be on the body itself. This can be observed in situations like an unbalanced car wheel or a human standing, where the center of mass does not align with the geometric center.
The center of gravity of a body is the point where the total weight of the body is assumed to be concentrated. However, it does not necessarily need to be located on the body itself. This concept is particularly important in understanding the balance and stability of objects. For instance, a car wheel that has not been balanced properly has a center of mass that does not coincide with its geometrical center. Moreover, in a situation like a human standing, by shifting their weight, they can cause the center of mass to hang in space - a point that might not correspond with any actual material part of the body.
Three-dimensional bodies demonstrate this when they are in motion, such as when a stick is thrown in the air and seems to rotate around a single point. This occurs because the center of mass carries the whole mass of the body, contributing to the observed motion. Even large structures, such as buildings or cruise ships, despite their size, are located in a uniform gravitational field on Earth, which means the acceleration due to gravity is constant and the center of gravity and center of mass coincide.
Objects with odd shapes or missing parts can also have a center of gravity outside their physical form. Imagine a horseshoe where the center of gravity would be somewhere near the bottom, even though there's no material there.
Consider a hollow ring, the mass is concentrated around the rim, not in the center. As a result, the center of gravity would lie somewhere within the ring, not necessarily on the actual body.
The answer and how to do it?? Thanks
The acceleration of the block is 4 m/s².
To find the acceleration of the 1kg block in the given diagram, we need to calculate the total force acting on the block and then divide it by the mass of the block.
Since there are three forces acting on the block, we can find the resultant force by adding these forces together.
In this case, the forces are 5N, 4N, and 5N in different directions.
Combining these forces, we get a net force of 4N in the horizontal direction.
Since the mass of the block is 1kg, the acceleration can be calculated using Newton's second law of motion: F = ma.
Therefore, the acceleration of the block is 4 m/s².
A 82-kg skydiver has a speed of 40 m/s at an altitude of 490 m above the ground. Calculate the total mechanical energy of the skydiver.
Answer:
[tex]ME=459,364J[/tex]
Explanation:
Mechanical Energy=Potential Energy+ kinetic Energy
[tex]m=82kg,g=9.8N/kg,h=490m,v=40m/s[/tex]
To calculate Kinetic Energy:-
[tex]KE=\frac{1}[2}mv^2\\=\frac{1}{2}\times82kg \times(40m/s)^2\\=65600J[/tex]
To calculate Potential Energy:-
[tex]PE=mgh\\=82kg \times9.8N/kg \times490\\=393764[/tex]
therefore,
[tex]ME=KE+PE\\=65600+393764\\=459364J[/tex]
The skydiver's total mechanical energy is 459365J
Final answer:
The total mechanical energy of an 82-kg skydiver moving at 40 m/s at an altitude of 490 m above the ground is calculated as 458876 Joules, which includes both kinetic and potential energy.
Explanation:
Calculating Total Mechanical Energy of a Skydiver
To calculate the total mechanical energy of a 82-kg skydiver moving at a speed of 40 m/s at an altitude of 490 m above the ground, we need to consider both kinetic and potential energy.
Kinetic energy (KE) is given by the formula: KE = 0.5 Times m times v2
Gravitational potential energy (PE) is given by the formula: PE = m times g Times h
Where:
m is the mass of the skydiver (82 kg)
v is the velocity (40 m/s)
g is the acceleration due to gravity (9.8 m/s2)
h is the height above the ground (490 m)
Now we perform the calculations:
KE = 0.5 imes 82 kg times (40 m/s)2 = 0.5 times 82 times 1600 = 65600 J
PE = 82 kg times 9.8 m/s2 times 490 m = 82 times 9.8 times 490 = 393276 J
The total mechanical energy (Etotal) is the sum of kinetic and potential energy:
Etotal = KE + PE = 65600 J + 393276 J = 458876 J
Therefore, the total mechanical energy of the skydiver is 458876 Joules.
The field lines around one end of a bar magnet are shown
below
Based on the diagram, what can you conclude about the
pole of the magnet?
A.)It is a south pole because the field lines spread out from
this end
B.)It is a north pole becaust the field lines spread out from
this end
C.)It is a south pole because the field lines enter the
magnet at this end.
D.)It is a north pole because the field lines enter the
magnet at this end.
Answer:
Explanation:
Field lines are lines of forces around a bar magnet. The show the direction of force field in a magnet.
Usually, around a bar magnet, the field lines originates and spreads out from the north pole.
Then they converge and enter through the south pole.
Therefore, we can make our choice by inspecting the given diagram. If the lines enters through the pole, it is the south pole.
Where they originate or leave is the north pole.
In a magnet, the lines (forces) always enter through the south pole and leave through the north pole.
I hope that helps ya'll.
- sincerelynini
PLEASE MARK BRAINLIEST!A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from
the wire.
Answer:
[tex]1.67\cdot 10^{-5} T[/tex]
Explanation:
The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where:
[tex]\mu_0=4\pi \cdot 10^{-7} H/m[/tex] is the vaacuum permeability
I is the current in the wire
r is the distance from the wire
The direction of the magnetic field lines is tangential to concentric circles around the wire.
In this problem, we have:
[tex]I=37.9 A[/tex] is the current in the wire
[tex]r=45.5 cm = 0.455 m[/tex] is the distance from the wire
Solving for B, we find the magnitude of the magnetic field:
[tex]B=\frac{\mu_0 I}{2\pi r}=\frac{(4\pi \cdot 10^{-7})(37.9)}{2\pi (0.455)}=1.67\cdot 10^{-5} T[/tex]
A liquid with a mass of 75 g is at its boiling point. It completely boils off when AQ = 15000000) of heat energy is added to it. Calculate the substance's latent heat of vaporization.
Temperature
Specific Heat
Latent Heat of
la
C - Celsius Temp (°C)
Answer:
2 × 10⁸J/kg
Explanation:
Specific latent heat of vaporization (steam) is the quantity of heat required or needed to change a unit of mass of liquid to gaseous state at constant temperature (boiling point) and pressure.
It can be calculated mathematically using,
Q = mL
Where, Q = quantity of heat
m= mass in kg
L = specific latent heat (J/kg)
Therefore,from the question
Q= 15000000J
mass (m) = 75g = 75/1000 kg = 0.075kg
Q = mL
L = Q/m
L = 15000000 ÷ 0.075
L= 200000000J/kg
L = 2 × 10⁸J/kg
I hope this was helpful, please mark as brainliest
a 60 kg child sits on on the outer edge a playground merry-go-around with radius of 4 meters that spins around at 1 revolution every 5 seconds, mercilessly bringing the child ever closer to nausea. What is the child's angular momentum? ( Remember to include the units.) What is the angular momentum of another child with the same mass who is sitting half way out from the center?
Answer:
a) [tex]1209.6 kg m^2/s[/tex]
b) [tex]302.4 kg m^2/s[/tex]
Explanation:
a)
The angular momentum of an object in circular motion is given by the formula
[tex]L=m\omega r^2[/tex]
where
m is its mass
[tex]\omega[/tex] is its angular velocity
r is the distance of the object from the axis of rotation
For the child in this problem, we have:
m = 60 kg is his mass
r = 4 m is the radius of the merry-go-around
Here the child completes 1 revolution every 5 seconds; so his frequency is
[tex]f=\frac{1}{5}=0.2 Hz[/tex]
And so his angular speed is
[tex]\omega=2\pi f=2\pi 0.2=1.26rad/s[/tex]
Therefore, the angular momentum is
[tex]L=(60)(1.26)(4)^2=1209.6 kg m^2/s[/tex]
b)
For a child sitting halfway of the merry-go-around, his distance from the axis of rotation is
[tex]r=\frac{4 m}{2}=2 m[/tex]
The mass of the child is the same as before,
m = 60 kg
And the angular speed is the same as well: in fact, the merry go around is a rigid body, so all its points cover the same angle in the same time; so, they all have the same angular speed. Therefore,
[tex]\omega=1.26 rad/s[/tex]
Therefore, the angular momentum here is:
[tex]L=m\omega r^2 = (60)(1.26)(2)^2=302.4 kg m^2/s[/tex]
F= 90 N
D= 5 m
W= ?
A. 18 j
B. 0.05 j
C. 450 j
D. 550 j
Answer:
c I hope this helpssssss :)
which best describes oil and water
The correct answer is option C. The hydrogen bonding between the water molecules is much stronger than the dipole induced dipole forces between the water and nonpolar oil molecules.
Option C is correct because water’s hydrogen bonding is much stronger than the dipole induced dipole interactions between water and nonpolar oil molecules.
Why other options are incorrect:
Option A is incorrect because the lack of ionization is not the reason; oil is nonpolar and does not interact well with polar water.Option B is incorrect because dispersion forces in oil are not significantly stronger than the forces between water and oil; the primary issue is the mismatch in polarity.Option D is incorrect because density is not the factor; the issue is the difference in polarity between water and oil.The complete question is:
Which of the following best explains why oil and water don't mix?
a) Oil molecules can't dissociate into ions on dissolution into water.
b) The dispersion forces between the oil molecules are much stronger than the dipole induced dipole forces between the water and nonpolar oil molecules.
c) The hydrogen bonding between the water molecules is much stronger than the dipole induced dipole forces between the water and nonpolar oil molecules.
d) Water is too dense to allow the oil to dissolve in it of the water is too oil is.
Which statement correctly describes the formation of an electric current? A resistance causes electric charges to move from lower to higher potential. A voltage causes electric charges to move from lower to higher potential. A resistance causes electric charges to move from higher to lower potential. A voltage causes electric charges to move from higher to lower potentia
Answer:
.
Explanation:
Answer:
d. A voltage causes electric charges to move from higher to lower potential.
Explanation:
How is atomic mass calculated?
Answer:
To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.
Explanation:
which land class has the least restrictions and is best for cultivation
Answer:
land scaping
Explanation:it makes your yard look lit imfao
Answer:
class #3
Explanation:
The soils are deep, well-drained, easily worked, hold water well and are either fairly well supplied with plant nutrients or highly responsive to the application of fertilizers.
a current-carrying wire has the maximum magnetic force in it when it is placed in a constant magnetic field when
Answer:
Maximum magnetic force on current carrying wire when wire is placed at 90 degree with magnetic field
Explanation:
As we know that the magnetic force on current carrying conductor is given as
[tex]\vec F = i(\vec L \times \vec B)[/tex]
here we have
[tex]F = i L Bsin\theta[/tex]
here we know that
[tex]\theta [/tex] = angle between length vector and magnetic field vector
so if we would like to have maximum magnetic force on the current carrying wire then
[tex]\theta = 90 [/tex]
so we have
[tex]F_{mex} = iLB[/tex]
explain why magnets have poles
Answer: The force of a magnetic field on a particle with spin causes the particle to rotate it's spin to align with the magnetic field. ... Taking these two ideas together, then, the Earth's magnetic field will cause the magnet to align north to south. That's why people named them the north and south poles.
Explanation: Hope i could help please mark as brainliest!
A driver starts is parked car and within 5 seconds reaches a speed of 60km/h, as he travels east. What his acceleration?
The acceleration of the car is 3.3 m/s²
Explanation:
Given-
Speed of the car, (we can represent as s) = 60 km/hr = 60 × [tex]\frac{5}{18}[/tex] = 16.67 m/s
Time,(we can represent as t) = 5 s
Acceleration, (we can represent as a) = ?
We know,
a = [tex]\frac{s}{t}[/tex]
a = [tex]\frac{16.67}{5}[/tex]
a = 3.334 m/s²
The acceleration of the car is 3.3 m/s²
Girl who’s mass is 52kg, experienced a net force of 1800N at bottom of a roller coster loop during her school physics field to the local amusement park, determine Sophia’s acceleration at location.
Answer:
34.62m/s^2
Explanation:
Force = mass x acceleration
Given
Force = 1800N
Mass = 52kg
Therefore
1800 = 52 x a
Divide both sides by 52
1800/52 = 52/52 x a
34.62 = a
a = 34.62m/s^2
Light travels through a substance at 1.97 x 10^8 m/s. What is the index of the liquid? What type of liquid is it?
The refractive index of the liquid is 1.52. The substance is a crown glass.
Explanation:
Given:
Velocity of light through the substance, v = 1.97 X 10⁸ m/s
Refractive index of the liquid, μ = ?
We know,
μ = [tex]\frac{c}{v}[/tex]
where, c = velocity of light in air
v = velocity of light in the substance
speed of light in air is 3 X 10⁸m/s
[tex]= \frac{3 X 10^8}{1.97 X 10^8} \\\\= 1.52\\[/tex]
Therefore, refractive index of the liquid is 1.52. The substance is a crown glass.
n = 1.52
Index of the liquid = 1.52
The type of the liquid is Crown glass.
Explanation:
In finding the index of refraction, we use this formula
n = c/v
where n is the index of refraction
c is velocity of light in vacuum which is constant and is equivalent to [tex]3 \times 10^{8} \mathrm{m} / \mathrm{s}[/tex]
v is the velocity of light in a particular medium
Here we use [tex]1.97 \times 10^{8} \mathrm{m} / \mathrm{s}[/tex]
Using the formula,
n = c/v
n = [tex]3 \times 10^{8} / 1.97 \times 10^{8}[/tex]
n = 1.52284264
n = 1.52
Thus, the index of the liquid is 1.52
If an object has a mass of 10 kilograms, how much does it weigh in Newton’s?
Answer:
Explanation:
Weight is the earth pull of an object to itself.
The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity.
The unit of weight is Newton and it is a vector quantity, it is directed downward vertically.
W= mg.
Where g varies but the gravity on earth is 9.81m/s² approximately.
Given that,
m=10kg, g=9.81
Then,
W=mg
W=10×9.81
W=98.1N
what is the best book for physics practicals??(pdf)
Answer:
I would strongly recommend Exploring Quantum Physics through Hands-on Projects for physics practicals.
Explanation:
Though it is not about books, but it is solely on you how you want to get knowledge. If you are truly passionate about learning physics in a practical way "Exploring Quantum Physics through Hands-on Projects" will be the best one out there.Besides "Laboratory Projects in Physics, a Manual of Practical Experiments for Beginners" is also a promising one.There are detailed chapters on important topics like light as a wave and particles, atoms and radioactivity, Schrödinger, etc.If you wisely follow these books, you will surely get all your doubts cleared and learn new mechanisms easily.The best book for physics practicals, particularly for university-level students, is often considered to be 'Principles and Practice of Physics' by Eric Mazur due to its clear examples and structured sequence. OpenStax's 'University Physics I' is an excellent alternative with open-source availability. A balance of textbooks, resources, and instructor guidance can provide a robust physics learning experience.
When searching for the best book for physics practicals, the University Physics I by Eric Mazur, entitled Principles and Practice of Physics, comes highly recommended. This book is known for its clear explanations, terminology consistency with other resources, and its sequence of content presentation. It is packed with worked-out examples and offers self-quiz conceptual questions that are crucial for understanding practical aspects of physics.
Alternatively, students looking for online and open-source textbooks can turn to resources like University Physics I at OpenStax, which offers an abundance of exercises and a more traditional presentation style. For computational physics enthusiasts, texts like A Practical Introduction to Computational Physics and Scientific Computing could be explored.
Ultimately, these books along with different ways to digest physics concepts, such as discussions with instructors and accessing resources in the Physics library, can cater to the diverse needs of physics students. It's important to consider one's own learning style and curriculum requirements when choosing the right practical physics text.
A 10 N force is applied to a hockey puck over a period of 0.1 s. What is the change in momentum of the hockey puck?
Final answer:
The change in momentum of the hockey puck is 1 kg·m/s.
Explanation:
The change in momentum of an object can be calculated using the equation: change in momentum = force x time.
In this case, the force applied to the hockey puck is 10 N and the time period over which the force is applied is 0.1 s. Therefore, the change in momentum of the hockey puck is 10 N x 0.1 s = 1 kg·m/s.