Answer:The gravitational force of the object would increase
Explanation:
Hope this helps
Answer: c, gravitational force will increase
Explanation:
Think about earths ocean as one subsystem within the larger earth system. Describe at least two inputs and two outputs to the ocean subsystem. What are some interactions that the ocean has with other subsystems?
Answer:
There are four subsystem of earth that includes lithosphere, hydrosphere, biosphere and atmosphere.
Ocean is included in hydrosphere and is one of teh largest subsytem in the earth. The two input and output to the ocean subsytem are as following:
The wind energy (input) transfer to ocean surface affects the motion of water in the ocean and produces waves (output).Heat energy recieved from the sun (input) is transferred toward the poles and allows the heat lost to the space (output).some of the interaction of ocean with other subsytem are as following:
Interaction between biosphere and hydrosphere (ocean): ocean provide water to living organism for survival and growth.Interaction between atmosphere and ocean is water cycle. The water from ocean evaporates through heat (sun) and through rain the water again reaches to the oceans.
The ocean subsystem on Earth inputs sunlight and nutrients, supporting photosynthesis and providing a substantial part of Earth's oxygen. In exchange, it outputs oxygen and sequesters carbon dioxide to balance our climate. Its interactions with the atmospheric and geographic subsystems ensure the functioning of the Earth's ecosystems.
Explanation:Earth's ocean, as a subsystem within the larger Earth system, has both inputs and outputs that maintain its functions. Two major inputs to the ocean subsystem are sunlight and nutrients, such as nitrogen and iron, which support photosynthesis by phytoplankton near the surface of the ocean. This photosynthesis, in turn, provides approximately 40 percent of the Earth's oxygen. In terms of outputs, the ocean emits oxygen and sequesters carbon dioxide, a vital process that helps moderate the Earth's climate.
Interaction between the ocean and other subsystems is crucial for sustaining life on our planet. For instance, the ocean receives inputs from the atmospheric subsystem in the form of rainfall while also interacting with the geographic subsystem through processes like erosion and sediment transport.
Therefore, the ocean plays a key role in the overall functioning and sustainability of the Earth's numerous ecosystems.
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The _____________ variable is the variable that is purposely changed.
A: independent
B: Dependent
C: Control
Answer:
dependent
Explanation:
Answer:
Independent
Explanation:
Hope it helps!!
Two major problems occur in water intoxication; one problem is that the overhydration leads to a non-homeostatic decrease in the concentration of __________; this leads to a significant decrease in blood osmotic pressure. The second problem is that the excessive increase in water volume, due to too much water intake, increases its extracellular (intravascular and interstitial) concentration out of normal homeostatic range. This high extracellular concentration of water causes water to move down its concentration gradient into cells; cells begin to __________ to a non-physiologic size.
Options are not provided inthe question. Hence, the complete question is
Two major problems occur in water intoxication; one problem is that the overhydration leads to a non-homeostatic decrease in the concentration of __________; this leads to a significant decrease in blood osmotic pressure. The second problem is that the excessive increase in water volume, due to too much water intake, increases its extracellular (intravascular and interstitial) concentration out of normal homeostatic range. This high extracellular concentration of water causes water to move down its concentration gradient into cells; cells begin to __________ to a non-physiologic size.
A. antibodies; shrink
B. hormones; swell
C. blood solutes; swell
D. blood solutes; shrink
Answer:
C. blood solutes; swell
Explanation:
Water intoxication or hyperhydration or water poisoning is a fatal brain functional disorder caused due to excessive water consumption forces the normal electrolyte balance in the body outside safe limits.
There are two major impact sofwater intoxication on health that includes:
Due to overhydration, blood solutes concentration decreases due to imbalance in blood level and results in decrease in blood osmotic pressure.Due to intake of excessive water, extracellular concentration increases which is out of normal homeostatic range. This excessive water and high etracellular concentration allows water to move down its concentration gradient into cells and resluts into swelling of cell.Hence, the correct option is C.
In humans, "unattached" earlobes are dominant over "attached" earlobes. "Widows peak" hairline is dominant over "non-widows peak" hairline. Use E and e for the earlobe phenotype alleles, and W and w for the hairline phenotype alleles. A female and a male, both with genotype EeWw have a child. What is the probability it will be a boy, and have attached earlobes and a widows peak hairline?
Answer:
3/32
Explanation:
The probability would be 3/32
From the illustration:
Unattached earlobe E is dominant over attached earlobe e.Widows peak hairline is dominant over non-widows peak hairline.EeWw and EeWw were crossed (Assuming both traits are autosomal)
EeWw x EeWw
Progeny :
1 EEWW - unattached earlobe with widows peak
2 EEWw - unattached earlobe with widows peak
2 EeWW - unattached earlobe with widows peak
4 EeWw - unattached earlobe with widows peak
1 EEww - unattached earlobe with non-widows peak
2 Eeww - unattached earlobe with no-widows peak
1 eeWW - attached earlobe with widows peak
2 eeWw - attached earlobe with widows peak
1 eeww - attached earlobe with no-widows peak
Generally, the probability of obtaining a male or a female in a cross is 50/50 or 1/2.
From the crossing result, the probability of having attached earlobe and widows peak hairline is 3/16.
Hence, the probability of obtaining a boy with attached earlobes and widows peak airline:
1/2 x 3/16 = 3/32.
Final answer:
The probability of a child having attached earlobes and a widow's peak hairline from parents with genotypes EeWw is calculated using a Punnett square, resulting in a 18.75% chance or 3/16 probability for these traits to occur together.
Explanation:
In humans, unattached earlobes are dominant over attached earlobes, and widow's peak hairline is dominant over non-widow's peak hairline. When solving for the probability of a child inheriting attached earlobes and a widow's peak hairline from parents with genotypes EeWw, we use the Punnett square method.
First, let's determine the possible gametes for earlobes and hairline from each parent: E or e, and W or w.Create a two-trait Punnett square with these gametes to see all possible genotypes for their offspring.To calculate the probability of a child with attached earlobes (ee) and a widow's peak (either WW or Ww), we need to find the fraction of the Punnett square that corresponds to this combination.In a two-trait Punnett square, each parent can produce four types of gametes: EW, Ew, eW, and ew. The child must inherit an e from both parents for attached earlobes and at least one W for a widow's peak. The Punnett square for this cross would be a 4x4 grid, with each cell representing a possible genotype of the offspring.
After filling out the Punnett square, we find that the offspring will have a 1/4 chance (probability of 25%) for attached earlobes and a 3/4 chance (probability of 75%) for the widow's peak. The combined probability of having both attached earlobes and a widow's peak is the product of the individual probabilities, which is (1/4) × (3/4) = 3/16 or 18.75%.
In humans, having two eyebrows is a completely dominant trait. The recessive trait is
expressed as having a single connected eyebrow. If a two parents who are heterozygous for
the eyebrow trait had an offspring, what is the probability that their child would express the
dominant phenotype?
Final answer:
The probability that the offspring of two heterozygous parents will express the dominant phenotype of having two separate eyebrows is 75%.
Explanation:
In humans, having two eyebrows is a dominant trait, while having a single connected eyebrow is the recessive trait. If two parents are heterozygous for the eyebrow trait and we represent the dominant allele for two eyebrows as 'E' and the recessive allele for a connected eyebrow as 'e', each parent's genotype is Ee. When these parents conceive a child, the probability that the offspring expresses the dominant phenotype of two eyebrows can be determined using a Punnett square.
A Punnett square is a diagram that is used to predict an outcome of a particular cross or breeding experiment. It shows how the alleles from each parent combine and what genotypes and phenotypes can be expected in their offspring. In this case, when we cross two heterozygous parents (Ee x Ee), the potential genotypes of the offspring are EE (homozygous dominant), Ee (heterozygous), and ee (homozygous recessive).
The possible combinations and their corresponding probabilities are as follows:
1/4 chance of being homozygous dominant (EE)
1/2 chance of being heterozygous (Ee)
1/4 chance of being homozygous recessive (ee)
Since both the homozygous dominant (EE) and heterozygous (Ee) genotypes result in the dominant phenotype of having two eyebrows, we add their probabilities together to determine the overall chance of expressing the dominant phenotype:
1/4 (EE) + 1/2 (Ee) = 3/4 or 75%
Therefore, there is a 75% probability that the offspring of two heterozygous parents will express the dominant phenotype of having two separate eyebrows.
If there are 40 chromosomes in each body cell of an organism what is the total number of chromosomes normally present in a gamet produced by that organism ?
Answer:
The gametes are haploid, having half the number of cells as compared to somatic cells. The gametes or cells produced by the organism will have 6 chromosomes if the organism has 12 chromosomes.
Jacob and Monod proposed a unified hypothesis of gene regulation. Which of the following is/are NOT part of the hypothesis?
a) Operons contain regulatory elements that control the expression of contiguous genes.
b) Repressors and operators regulate messenger RNA.
c) Transcription is regulated specifically at the level of initiation.
d) All of the listed statements are part of the hypothesis.
Answer:
A
Explanation:
A substance made of weakened, killed, or partial pathogens designed to protect the body from future invasions of that pathogen is?
Answer:
a vaccine
Explanation:
A substance made of weakened, killed, or partial pathogens designed to protect the body from future invasions of that pathogen is called a vaccine.
Vaccines are substances that are prepared and administered to individuals with the sole focus of eliciting immune response of such individuals to a particular disease. The substances usually consist of mixture of weakened, killed or neutralized pathogens of a particular disease.
Vaccines are of different types depending on which portion or type of pathogen that is utilized in its preparation. They could be
Inactivated vaccines: consists of dead pathogens and are meant to provoke a kind of weak immune response in individuals.Attenuated vaccines: consists of weakened form of pathogens that is meant to cause little to no symptoms in individuals and elicit immune response similar to that of natural infections.Conjugate vaccines: consists of sub units of specific part of pathogens that is capable of inducing immune response in individuals against the pathogen.Other types include valence, toxoid, experimental, and heterotypic vaccines.
What moves through an ecosystem when one organism eats another?
Answer:
energy
Explanation:
Inhibitors of the electron transport chain exert their effects through a variety of mechanisms. _______ blocks electron transport and proton pumping via inhibition of Complex IV. ________blocks electron transport and proton pumping via inhibition of Complex I. ________blocks electron transport and ATP synthesis by inhibiting the exchange of ATP and ADP across the inner mitochondrial membrane. ________blocks ATP synthesis without inhibiting electron transport by dissipating the proton gradient
Answer:Azide, Rotenone, Atractyloside, DNP
Explanation:
Inhibitors of the electron transport chain exert their effects through a variety of mechanisms. AZIDE______ blocks electron transport and proton pumping via inhibition of Complex IV. _ROTENONE_______blocks electron transport and proton pumping via inhibition of Complex I. _ATRACTYLOSIDE_______blocks electron transport and ATP synthesis by inhibiting the exchange of ATP and ADP across the inner mitochondrial membrane. _DNP_______blocks ATP synthesis without inhibiting electron transport by dissipating the proton gradient
AZIDE inhibits Complex IV, ROTENONE inhibits Complex I, ATRACTYLOSIDE inhibits the exchange of ATP and ADP, while DNP blocks ATP synthesis.
Cellular respiration has three stages: glycolysis, the Krebs cycle and oxidative phosphorylation.During oxidative phosphorylation, the electron transport chain is coupled to the generation of an electrochemical proton gradient across the inner mitochondrial membrane, which is subsequently used to generate ATP.Azide inhibits cellular (mitochondrial) respiration by blocking cytochrome c oxidase (also known as Complex IV), which is a key carrier of electrons in oxidative phosphorylation.Rotenone blocks the electron transport chain by inhibiting the enzyme NADH ubiquinone reductase (also known as mitochondrial complex I), thereby preventing the availability of oxygen for cellular respiration.Atractyloside (ATR) is a natural, toxic glycoside that blocks the synthesis of ATP by inhibiting the exchange of ATP in the mitochondria with ADP in the cytosol.2,4-Dinitrophenol (DNP) is an organic compound that allows protons (H+) to pass across the inner mitochondrial membrane, thereby bypassing ATP synthase.In conclusion, AZIDE inhibits Complex IV, ROTENONE inhibits Complex I, ATRACTYLOSIDE inhibits the exchange of ATP and ADP, while DNP blocks ATP synthesis.
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Which represent correct variations of the formula for speed? Check all that apply.
Answer:
d = st
Explanation:
t =
s =
t =
s = dt
d = st
d =
The formula that represents correct variation of the formula for speed would be d = st, where d = distance traveled by an object, s = speed of the object, and t = the time taken by the object.
Speed is defined as the distance traveled by a moving object per the time taken by the object to complete the distance. Mathematically, it is represented as:
Speed (s) = [tex]\frac{distance (d)}{time (t)}[/tex].
Hence, s = [tex]\frac{d}{t}[/tex]
If the formula is cross multiplied, then we will have;
d = st
Answer:
A, B, E
t = d/s, s = s/d, d = st
The Q are 1. Emma is a 26-year-old professional woman who maintains her weight at 140 pounds by following a lacto-ovo vegetarian diet that supplies approximately 1200 calories a day. She believes that her daily intake of 40 grams of protein from milk, eggs, legumes, and nuts is adequate for her needs. , a. What is Emma’s recommended daily protein requirement?, b. What percentage of Emma’s current total energy intake comes from protein? Does it fall within the recommended range in terms of the percentage of total energy intake? Explain, c. Emma is concerned about her intake of the essential fatty acid omega-3. Can you suggest for her two food items that she can include in her diet?
2. Rank the following oils/fats according to the ease with which they would spoil, and explain how you arrived at your conclusion: coconut oil, flaxseed oil, olive oil.
Answer:
Question 1
a) What is Emma’s recommended daily protein requirement? 50.4 grams
b. What percentage of Emma’s current total energy intake comes from protein?
13.33%
Does it fall within the recommended range in terms of the percentage of total energy intake?
Yes it does fall within the recommended range in terms of the percentage of total energy intake which is 10 - 35%
c. Emma is concerned about her intake of the essential fatty acid omega-3. Can you suggest for her two food items that she can include in her diet?
i. Walnuts
ii. Flaxseeds.
Question 2
2. Rank the following oils/fats according to the ease with which they would spoil, and explain how you arrived at your conclusion: coconut oil, flaxseed oil, olive oil.
According to the ease of spoilage:
Flaxseed oil – Coconut oil – Olive oil
Explanation:
a) What is Emma’s recommended daily protein requirement?
RDA of protein for adults is given as 0.8 g per kilogram of body weight of 0.36 per pounds of body weight.
Therefore, Emma's recommended daily protein intake is calculated as:
Her body weight in pounds × 0.36
Emma's body weight = 140 pounds
140 pounds × 0.36
= 50.4 grams.
Therefore, Emma’s recommended daily protein requirement is 50.4 grams of protein.
b. What percentage of Emma’s current total energy intake comes from protein?
Since 4 calories is the energy received from 1 gram of protein
In the question, we are told that Emma takes a daily intake of 40 grams of protein.
Therefore,
1 gram of protein = 4 calories
40 grams of protein =
40 × 4 = 160 calories.
The Lacto Ovo vegeterian diet, Emma is on gives her 1200 calories per day.
Hence, the percentage of Emma’s current total energy intake comes from protein is calculated as:
(Emma's daily energy in calories from protein ÷ Daily energy in calories supplied by her Lacto ovo vegetarian diet) × 100
= (160 calories ÷ 1200 calories) × 100
= 13.33%
c.
Omega -3- fatty acids are fatty acids that are very good for the body. Even though they are fatty acids, they do not clog the arteries thereby helping in preventing the occurrence of heart disease. They also lower the blood pressure in the body.
Foods that contain omega -3- fatty acids are fatty fish such as Salmon, Mackerel as well as nuts and seed like Walnuts, Flax seeds ( Flax seed oil).
Emma is concerned about her intake of the essential fatty acid omega-3. Can you suggest for her two food items that she can include in her diet?
Since Emma takes nuts, 2 food items she can include in her diet that are rich in Omega-3 fatty acids are:
i. Walnuts
ii. Flax seeds
2. Rank the following oils/fats according to the ease with which they would spoil, and explain how you arrived at your conclusion: coconut oil, flaxseed oil, olive oil.
According to the ease of spoilage:
Flaxseed oil – Coconut oil – Olive oil
Flaxseed oil spoils more easily than coconut oil and coconut oil spoils easily than Olive oil. This is based on their exposure to heat.
When heated up, Flaxseed oil breakdown more easily , followed by coconut oil.
Coconut oil has the tendency to become cloudy after been stored for a while.
This is why even though we can use but Flaxseed and Coconut oil for cooking , Olive oil is still the best because it has the tendency to withstand a large amount of heat and it is heat stable as well as more stable at even room temperature.
which organism is able to make its own oxygen gas?
Answer:
cyanobacteria
cyanobacteria is The answer is tiny organisms known as cyanobacteria, or blue-green algae. These microbes conduct photosynthesis: using sunshine, water and carbon dioxide to produce carbohydrates and, yes, oxygen
Explanation:
Hope this helps:)
Answer:
Plants
Explanation:
Plants do photosynthesis which releases oxygen gas as a by-product.
List at least 3 different biotic (living/products of organisms) limiting factors and at least 3 different abiotic (nonliving) limiting factors of deer. Make sure you label your list (biotic & abiotic).
Answer:
If your question is referring to the factors limiting the growth and development of the species of deer,
Biotic:
1) Food sources like Grass
2) Predators like Wolf
3) parasites like leaches
Abiotic:
1)Temperature
2)Water
3) Pollutants in environment.
3.why the number of xylem are less than the number of phloem in hydrophytes plant?
Answer:
Hydrophytes are defined as the plants that grow in aquatic environment.
Xylem and phloem are part of transport system in plants. Water and minerals from roots to leaves are carried by Xylem and sugar and other organic nutrients are carried by Phloem.
Hydrophytes grow in water, so have access to abundant water. It helps water to diffuse easily in hydrophytes and hence require less number of xylem for water transport.
So, number of xylem are less than the number of phloem in hydrophytes plant.
Ashley is taking a test. She has to write why comb jellies and jellyfish belong to two different phyla. What should Ashley write?
A that jellyfish are vertebrates, while comb jellies are not
B. that jellyfish are mobile, while comb jellies are not
C. that jellyfish have stinging cells, while comb jellies do not
D.
that jellyfish have an exoskeleton, while comb jellies do not
Answer: C. That jellyfish have stinging cells, while comb jellies do not
Explanation:
Comb Jellies to the untrained eye are the same as Jellyfish but as the question says, they are different in that they belong to different phyla.
The Comb Kelly belongs to the Ctenophora Phylum while the Jellyfish belongs to the Coelenterate phylum.
Perhaps the largest difference between them is that Ctenophora do not have stinging cells as opposed to members of the Coelenterate Phylum that do.
Jellyfish and comb jellies are in different phyla because jellyfish have stinging cells for capturing prey while comb jellies do not. Hence, option C is correct.
Ashley should write that jellyfish and comb jellies belong to two different phyla because jellyfish have stinging cells, while comb jellies do not. Specifically, jellyfish are part of the phylum Cnidaria, characterized by their stinging cells called nematocysts which they use for capturing prey. On the other hand, comb jellies belong to the phylum Ctenophora, and they lack these stinging cells. Instead, comb jellies use colloblasts or sticky cells to capture prey. Additionally, while both creatures are invertebrates and live in aquatic environments, they have different biological structures and genetic makeup that necessitate their classification into separate phyla.
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Type the correct answer in the box. Spell all words correctly.
Which of the intertidal zones experiences the highest complexity and diversity of marine life?
The *BLANK* intertidal zone experiences the highest complexity and diversity of marine life.
Answer: Pacific northwest intertidal zone experiences the highest complexity and diversity of marine life.
Explanation:
Answer:
pacific northwest
Explanation:
match each feature created by erosion to the correct description
Stream- A series of connected channels that fill with water; Gully- A channel of connected grooves created by runoff; Rill- A small groove in soil created by runoff; Tributary- One of many channels that connect to form a river.
Stream: A stream is a body of water that flows continuously over a bed and through a channel. Streams are typically smaller than rivers, but they can be large enough for transportation. Streams are formed by runoff from precipitation.
Gully: A gully is a deep, narrow channel formed by runoff. Gullies can be caused by erosion from rain, snowmelt, or irrigation. Gullies can cause significant damage to land, crops, and infrastructure.
Rill: A rill is a small groove in soil that is created by runoff. Rills are often the first stage in the formation of gullies. Rills can be prevented by planting cover crops, creating contour farming, and reducing the amount of runoff.
Tributary: A tributary is a stream or river that flows into a larger stream or river. Tributaries are essential for the drainage of an area. They also help to regulate the flow of water in the larger stream or river.
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Rill: a small groove in soil created by runoff
Tributary: one of many channels that connect to form a river
Gully: a channel of connected grooves created by runoff
Stream: a series of connected channels that fills with water
1. In a study of selection on the leg length of migratory locusts, the mean leg length is 18.6 mm, the selection gradient is β = –0.13/mm, the phenotypic variance is P = 1.4 mm2, and the heritability is h2 = 0.37. What is the expected response to selection in the next generation? What do you predict the average leg length will be in the next generation?
Answer:
the average leg length will be in the next generation? = 18.082mm
Explanation:
check the attached file below for further explanation to the question. Thanks
The expected response to selection for the leg length of migratory locusts is -0.06722 mm. This implies a decrease in the mean leg length in the next generation, which is predicted to be approximately 18.53 mm.
Explanation:The response to selection is given by the Breeder's equation: R = h2βP, where R is the expected response, h2 is the heritability, β is the selection gradient, and P is the phenotypic variance.
Plugging in the given values, we have R = (0.37)(-0.13)(1.4) which results in -0.06722 mm.
This means the average leg length is expected to decrease by 0.06722 mm in the next generation. As such, we predict the average leg length of migratory locusts will be 18.6 mm - 0.06722 mm = approximately 18.53 mm in the next generation.
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What is a close relationship between two species in which both species benefit?
Answer:
A symbiosis relationship benefits both organisms.
Explanation:
What role does cellular respiration play in the water cycle?
O It removes H2O from the atmosphere during glycolysis.
O It removes H20 from the atmosphere during acetyl CoA formation.
O It releases H20 to the atmosphere during the citric acid cycle.
O It releases H2O to the atmosphere during electron transport.
Answer:A
Explanation:
on edg
The types of organisms present in a water body affect the DO concentration there (plant, bacteria, and fungi). Thus, option A is correct.
What is the importance of water in cellular respiration?Blood and other water-based fluids assist in transporting molecules to the required regions. As a result, water's function as a solvent makes it easier for molecules like oxygen to go through.
The body during cellular respiration and has a significant impact on how quickly medications can reach their intended targets in the body.
The oxygen that plants emit into the water during photosynthesis. Plants draw oxygen out of the water as they breathe. In order to break down the dead organic stuff in the stream, bacteria and fungi demand oxygen.
Therefore, During photosynthesis, water is broken down to create oxygen, and during cellular respiration, oxygen and hydrogen combine to create water.
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Name the two main parts of an angiosperm leaf. What is the function of each part?
Answer:
Stomata, Guard cells.
Explanation:
Angiosperms are known as flowering plants that contain their seeds in fruits. They are including a variety of plants such as submerged, aquatics, trees, herbs, etc. Two main parts of an angiosperm leaf are:
Stomata: They are tiny pores present on the plant epidermis, these small openings on the leaves allow gas exchange to occur in plants.
Guard cells: These cells help to controls stomata opening and closing, also helps to stimulate gas exchange and control transpiration in plants.
Final answer:
The angiosperm leaf has a blade for photosynthesis and a petiole for support and nutrient transport. Deciduous plants drop leaves to conserve water, while evergreens have needle-like leaves to reduce water loss. Variation in leaf structure among angiosperms is often an adaptation to environmental conditions.
Explanation:
The angiosperm leaf consists of two main parts: the blade (or lamina) and the petiole. The blade is the broad, flat part of the leaf which contains a high concentration of chloroplasts, making it the primary site for photosynthesis.
The petiole is the stalk that attaches the leaf blade to the stem at a node, providing support and transporting water and nutrients between the leaf and the rest of the plant.
Different environmental conditions lead to variations in leaf structure and function. Angiosperms exhibit a wide range of leaf shapes, margins, and venation patterns, which are often adaptations to specific climatic and environmental factors such as light, water availability, and temperature.
Which of the following drugs would NOT block the cell cycle, and thus would NOT be appropriate cancer treatment? Nocodazole, a drug that blocks spindle fiber (microtubule) formation 5-flurouracil, a DNA analog that blocks DNA replication Sphingosine-1-phosphate, a molecule that stimulates relay molecules in signaling Brinapant, a drug that increases apoptosis (cell death) Bevacizumab, a drug that blocks formation of new blood vessels so that less oxygen is available for cancer cells
Answer:
The correct answer is Sphingosine-1-phosphate.
Explanation:
Sphingosine-1-phosphate or S-1-P refers to a signaling sphingolipid that takes part in various of the cell proliferation procedures. Mainly the sphingosine-1-phosphate performs the work of monitoring the process of permeability, angiogenesis, and vascular stability that can further interfere in the process of metastasis.
However, it has been found that due to the tendency of developing the novel blood vessels, the sphingosine-1-phosphate also has some connection with certain kinds of cancers.
Urea... Multiple Choice is completely reabsorbed by the nephron. is secreted into the filtrate by cells of the distal convoluted tubule. None of these choices is correct. ia actively transported into the filtrate by cells of the collecting duct. diffuses out of the collecting ducts into the interstitial fluid of the medulla and then diffuses into the descending loop of Henle.
Answer:
Option B
Explanation:
Urea, the main nitrogenous excretory product of mammals and a major organic component of urine is cleared from the blood by the kidney. Urea's concentration builds up in the renal medulla as they leave through the walls of the cortical collecting duct and go into the interstitial fluid in the region of the inner medulla, then some diffuses into the descending loop of Henle.
Due to a genetic defect, an individual is unable to make T cytotoxic cells. Predict the most likely consequence. A. The individual will not be able to synthesize any antibodies. B. The individual will have SCID (severe combined immunodeficiency disease). C. The person will have frequent infections caused by Staphylococcus and Streptococcus. D. The person will not be able to adequately fight viral infections and infections caused by intracellular bacteria.
Answer:
The person will not be able to adequately fight viral infections and infections caused by intracellular bacteria.
Explanation:
Cytotoxic T lymphocytes also known as CD8+ T cells are very important in defence of the immune system against intracellular pathogens, including viruses and bacteria and for tumour check. They recognize pathogens' antigen and then become activated killing infected or malignant cells.
Thus, a genetic defect in genes that encodes for its production will lead to the individual being not able to efficiently fight against these infections.
Answer:
The correct option is D:
"The person will not be able to adequately fight viral infections and infections caused by intracellular bacteria."
Explanation:
Cytotoxic T lymphocytes have an important role to play in the immune system, they belong to the category of cells that have the ability to kill off another cell. Cytotoxic T lymphocytes guards the host cell against attack of viruses and, in addition, also defends against possible (bacterial) infections that can be caused by harmful pathogens that multiply inside the cells of the host.
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Explain what is meant by the term environmental justice.Explain why land use planning has to incorporate such diverse disciplines as architecture, urban planning, and environmental planning.
Answer:
Land use planning is about more than addressing the physical layout of development, how much it will cost, where it will be located and aesthetics. Land use planning also incorporates environmental impacts such as chemical pollution, noise pollution, flooding due to the loss of trees and plants, etc. In order to meet all these requirements land use planning must draw from a wide array of disciplines' expertise.
Explanation:
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why is the cycling of matter important to all living things
Answer:The cycling of matter is among the three main factors upon which life on the earth depends. Concerning the cycling of matter, because there are only finite amounts of nutrients available on the earth, they must be recycled in order to ensure the continued existence of living organisms
Explanation:
The cycling of matter, such as the carbon cycle, is essential for providing the materials necessary for life. These biogeochemical cycles ensure readily available elements for organisms to use, preventing essential elements for maintaining ecosystem sustainability.
The cycling of matter is fundamentally important to all living things as it ensures the continuous availability of essential elements like carbon, nitrogen, hydrogen, oxygen, phosphorus, and sulfur. Biogeochemical cycles involve both biotic and abiotic components and are essential for life on Earth because they provide the materials necessary for organisms to construct their bodies, carry out life processes, and maintain ecosystem sustainability.
The carbon cycle, for instance, plays a critical role in the fixation of atmospheric carbon dioxide into biomass through photosynthesis. This is a primary pathway for solar energy to be captured and converted into chemical energy that can be used by organisms.
Without the cycling of matter, essential elements could become trapped in unavailable forms, hindering the survival of living organisms. For example, if carbon were to become sequestered in crustal rocks and sediments without being recycled, living organisms would lack the raw materials needed for vital organic compounds. Also, the recycling of elements like phosphorus and sulfur is crucial as they undergo various state changes and move through the atmosphere, water, and soil, affecting many aspects of the ecosystem.
Through these cycles, matter is conserved within the biosphere, continually moving between living organisms and the environment in a balanced manner. Such processes are necessary for the production of food, energy storage, and the regeneration of raw materials which are all required for the persistence and functioning of life on Earth.
A population of cheetahs has a birth rate of 5 and a death rate of 15. Immigration is 2, and emigration is 4. What is its population growth?
Answer:
-12
Explanation:
5 - 15 + 2 - 4
-10 + -2
-12
Answer:
-12
Explanation:
Sperm can survive in the female reproductive system for six days, but they need to have 10 hours after ejaculation to undergo capacitation. Ovulation typically occurs on day 14 of a woman's menstrual cycle. An ovulated egg can survive only up to 24 hours if it is not fertilized. Given this information, what days of a woman's sexual cycle would be a window of opportunity for an egg to be fertilized
Answer:
Five days prior to ovulation and day of ovulation represents a six day fertile window of a women’s cycle
Explanation:
In the five days prior to ovulation and day of ovulation, the chances of conception are high. These six days represents the fertile window of a women’s cycle during which the sperm with a life span of five days and egg with a life span of 24 hours can fuse. However, likelihood of conceiving increases if two individuals mate in the first three days of these six days fertile window of women’s cycle.
In a 13-filament microtubule, the majority of lateral interactions are between like subunits, with alpha tubulin binding to alpha tubulin. Between the first the thirteenth protofilaments, there is a seam where alpha and beta tubulin interact. Are these heterotypic interactions likely to be stronger than, weaker than, or the same strength as homotypic interactions
Answer:
Lateral interactions between protofilaments are in general homotypic. The heterotypic interactions are weaker because these interactions involve the mix of different protofilaments within the microtubule .
Explanation:
Microtubules are cytoskeletal polymers that are formed by tubulin dimers in a head-to-tail arrangement (protofilaments).