What will the concentration of LiOH be if 27ml of a 4.5 M LiOH solution is diluted to 435ml? *

To calculate the concentration of hydronium ion and the moles in a buffer solution, use the formula [H3O+] = 10^(-pH) and Moles = Concentration x Volume.

The concentration of hydronium ion can be calculated using the formula:

[H3O+] = 10^(-pH)

For example, if the starting pH is 4.74, then the concentration of hydronium ion is 10^(-4.74) M

The moles of hydronium ion present in 20.0 mL of the buffer can be calculated using the formula:

Moles = Concentration x Volume

Assuming the concentration of hydronium ion is 10^(-4.74) M, then the moles of hydronium ion in 20.0 mL is (10^(-4.74) M) x (20.0 mL / 1000) L.

Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ

Explanation :

First we have to calculate the moles of ice.

[tex]\text{Moles of ice}=\frac{\text{Given mass ice}}{\text{Molar mass ice}}=\frac{2kg}{18g/mol}=\frac{2000g}{18g/mol}=111.1mol[/tex]

Now we have to calculate the heat energy.

As, heat energy required to melt 1 mole of ice = 6.01 kJ

So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ

                                                                                  = 667.7 kJ

Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ

Answer:

It is polar

Explanation:

Hydrogensulfate is an oxoanion of sulphur , conjugate base of a sulfuric acid and conjugate acid of a sulfate

Please see the structure of HSO4 in the attached image

Polar molecules have  electronegativity difference between the bonded atoms.

In case of Hydrogensulfate, hydrogen is positive while sulfate is negative ion.

Electronegativity of hydrogen is 2.2 while that of sulfur and oxygen is 2.58 and 3.44 respectively

Thus, it is a polar molecule.

Answer:

Explanation:em metais alcalinos, acho

Answer:

A roman numeral in parentheses follows the name of the metal.

Explanation:

Answer: Hey Brother by Avicii

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

Answers:

Though no result is wholesome without further tests and observed symptoms, these diseases could be causative for the following symptoms:

Explanation:

Answer:

Refer to pic above

Explanation:

Cl's oxidation state reduces from 0 in Cl2 to - 1 in Cl-.

For the given reaction the reduction reaction is Cl[tex]_2[/tex] + 2e⁻→ 2Cl⁻. Therefore, the correct option is option C.

Any chemical process in which a participating chemical species' oxidation number changes is known as an oxidation-reduction reaction, often known as a redox reaction. The phrase refers to a broad range of processes. Many oxidation-reduction processes are as frequent and well-known as fire, metal corrosion and disintegration, fruit browning, respiration, and photosynthesis—basic life processes.

These three processes have two things in common: (1) they are coupled, meaning that every oxidation reaction results in a subsequent reduction; and (2) they involve a typical net chemical change, meaning that an atom or electron moves through one unit of matter to the other. For the given reaction the reduction reaction is Cl[tex]_2[/tex] + 2e⁻→ 2Cl⁻

Therefore, the correct option is option C.

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Final answer:

The balanced reaction between Au3+(aq) and Cu+(aq) that forms Au(s) and Cu2+(aq) is Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq). To determine the standard cell potential, the standard reduction potentials of the associated half-reactions should be used to evaluate spontaneity.

Explanation:

The question at hand involves galvanic cells and the balancing of redox reactions.

For the balanced equation for the reaction between Au3+(aq) and Cu+(aq), the chemically accurate version is:

Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)

Standard Reduction Potentials and Galvanic Cell Potential

To determine the standard cell potential (E°), you would reference the standard reduction potentials of the half-reactions:

Oxidation: Cu(s) → Cu2+(aq) +2e−

Reduction: Au3+(aq) + 3e− → Au(s)

By adding the reduction potentials of these half-reactions together, one can ascertain whether the reaction is spontaneous under standard state conditions. Specifically, if the standard cell potential (E°) is positive, the reaction is spontaneous.

Answer:

Explanation:

check below for explicit explanation.

When the number of hydronium ions decreases in a solution containing propanoic acid and its conjugate base, the solution shifts towards the acidic side. Therefore, the structure that would predominate in this circumstance is the acidic form, that is, propanoic acid itself.

The equilibrium pH of a solution is equal to the pKa of the acid when the concentrations of the acid and its conjugate base are equal. In this case, where the propanoic acid has a pKa of 4.87 and the pH of the mixture is also 4.87, we have an equal concentration of the acid and its conjugate base. When a decrease in [H₃O⁺] occurs, the equilibrium of the solution shifts to compensate, and shifts towards the acidic side because the concentration of [H₃O⁺] (hydronium ions) has decreased. This means that the form of the propanoic acid that would predominate after a decrease in [H₃O⁺], would be the acidic form. Therefore, the structure that predominates is that of propanoic acid, CH₃CH₂COOH, not its conjugate base.

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Answer:

option B.

Explanation:

Given,

Volume,V₁ = 22.8 L

T₁ = 313 K

P₁ = 4 atm

T₂ = 341 K

P₂ = ?

Volume is constant.

Using ideal gas law

[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]

[tex]\dfrac{4}{313}=\dfrac{P_2}{341}[/tex]

[tex]P_2 = \dfrac{4}{313}\times 341[/tex]

[tex]P_ 2 = 4.36\ atm[/tex]

Pressure of the tank is equal to 4.36 atm.

Hence, the correct answer is option B.

Answer:

1210 grams

Explanation:

Message me for extra info.

snap- parkguy786

Answer:

1210

Explanation:

Answer:

5.0

Explanation:

We have a buffer system formed by a weak base (C₅H₅N) and its conjugate acid (C₅H₆N⁺). We can calculate the pOH using the Henderson-Hasselbach's equation.

pOH = pKb + log [acid]/[base]

pOH = -log 1.8 × 10⁻⁹ + log 0.02/0.01

pOH = 9.0

Then, we will calculate the pH.

pH + pOH = 14

pH = 14 - pOH = 14 - 9.0 = 5.0

Answer:

X: 2,8 = Neon

Y: 2,8,7= Chlorine

Neon has an atomic number of 10. It is referred to as a noble gas and it’s a mono atomic element.

Chlorine has an atomic number of 17. It is referred to as an Halogen. Chlorine exists in nature as a diatomic molecule.

However the question is incomplete and will need more information.

Answer:

 60.1 kJ

Explanation:

Enthalpy change ΔH = m x Δt x cρ

Given that:

100 grams water = 5.56 moles water

The enthalpy change needed to raise 100 g water from 50°C to 0°C is calculated as :

ΔH = 100g x ( 0-50) x 4.18J/gC = -2.09 X 10⁴ Joules

The Freezing water  

ΔH = ΔH fusion * mol

ΔH fus for water is = 6.01 kJ/mol

ΔH = 6.01 kJ/mol × 5.56 moles = -33.4 kJ  (since heat is released when water freezes)

Finally, The enthalpy Change during the process pf changing the  ice from  0°C to -30.0°C  is:

ΔH = m x Δt x cp

= 0.100 kg × (-30 -0)°C  × 2.00 × 10³ J/kgC

= - 6 × 10³ J

Total heat lost = -2.09  × 10⁴ J + (-33.4 × 10³ J) + (-6  × 10^3J)

= - 6.01  × 10⁴ J

=  60.1 kJ

The enthalpy change during the process in which 100.0 g of water at 50.0 °C is cooled to ice at -30.0 °C is -60.570 kJ, involving three energy changes: cooling water from 50°C to 0°C, transition from water to ice, and cooling from 0°C to -30°C.

The calculation of the enthalpy change in converting 100.0 g water at 50.0 °C to ice at -30.0 °C involves calculating energy changes at different stages: cooling water from 50°C to 0°C, changing water at 0°C to ice at 0°C (enthalpy of fusion), and cooling ice from 0°C to -30°C. Below is step be step calculation.

The total enthalpy change is therefore Q total = Q1 + Q2 + Q3 = -20900 J - 33400 J - 6270 J = -60570 J, or -60.570 kJ.

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Answer:

Here are some advantages.

Explanation:

Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas.

Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.

The energy generated through hydropower relies on the water cycle, which is driven by the sun, making it a renewable power source, making it a more reliable and affordable source than fossil fuels that are rapidly being depleted.

Impoundment hydropower creates reservoirs that offer a variety of recreational opportunities, notably fishing, swimming, and boating. Most water power installations are required to provide some public access to the reservoir to allow the public to take advantage of these opportunities.

Some hydropower facilities can quickly go from zero power to maximum output. Because hydropower plants can generate power to the grid immediately, they provide essential back-up power during major electricity outages or disruptions.

In addition to a sustainable fuel source, hydropower efforts produce a number of benefits, such as flood control, irrigation, and water supply.

Some advantages of Hydro kinetic energy is, it can be used to  drive turbines and generate electricity.

Hydro kinetic energy is the energy derived from the motion of falling water.

The energy (Hydro kinetic energy) can be converted into mechanical energy of turbine which is in turn converted into electrical energy.

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Answer:seen below

Explanation:

The effects of an ocean-ocean subduction zone are the same as those of an ocean-continent subduction zone in that, the subduction zone where an oceanic plate subducts beneath another oceanic plate are the same as a continent-ocean subduction zone.

They oceanic plate and the continental plate are both convergent zones, but when an oceanic plate converges with a continental plate, the oceanic plate is forced underneath the continental plate this is because oceanic crust is thinner and denser than the continental crust. The difference is that the volcanic arc formed will be a set of islands known as an island arc.

If two plates meet at a convergent plate boundary both are of oceanic crust, the older, denser plate will subduct beneath the less dense plate into a trench, resulting in earthquakes.

Finally, When two continents meet head-on, neither is subducted under, this is because the continental rocks are relatively light and are like two colliding icebergs they resist downward motion. Instead, the crust tends to buckle and be pushed upward or sideways.

The driving forces behind ocean-continent and ocean-ocean convergent plate boundaries are similar, involving the movement of lithospheric plates due to mantle convection, the specific outcomes of these collisions differ based on the types of plates involved.

The causes of ocean-continent and ocean-ocean convergent plate boundaries are similar in that both are driven by the movement of lithospheric plates due to the convection currents in the asthenosphere. The differences in their causes lie in the density and composition of the colliding plates. Ocean-continent convergence occurs when a dense oceanic plate collides with a less dense continental plate, while ocean-ocean convergence involves the collision of two oceanic plates.

The effects of both types of convergent boundaries include the formation of mountains or island arcs, earthquakes, and volcanic activity. However, the specific effects differ due to the nature of the colliding plates. Ocean-continent convergence typically results in the subduction of the oceanic plate under the continental plate, leading to the formation of mountain ranges like the Andes and volcanic activity such as the Cascade Range. In contrast, ocean-ocean convergence leads to the creation of island arcs like the Aleutian Islands and deep ocean trenches such as the Mariana Trench. Additionally, the volcanic activity at ocean-ocean convergent boundaries tends to produce less explosive eruptions compared to the more explosive eruptions that can occur at ocean-continent boundaries.

 Convergent plate boundaries are areas where two or more tectonic plates collide. The movement of these plates is driven by convection currents in the Earth's mantle, specifically the asthenosphere, which is a more ductile layer beneath the lithosphere. These currents cause the overlying lithospheric plates to move, and when this movement is convergent, it leads to collision.

In the case of ocean-continent convergence, the denser oceanic plate is forced beneath the less dense continental plate in a process known as subduction. This subduction can cause melting of the subducting plate, leading to the formation of magma that rises through the continental crust, resulting in volcanic activity. The collision also causes the continental crust to crumple and fold, creating mountain ranges.

Ocean-ocean convergence, on the other hand, involves two oceanic plates. When these plates collide, one plate is typically subducted under the other due to the higher density of the oceanic crust compared to the mantle below. This subduction also leads to volcanic activity, but because the volcanoes form in the ocean, they often create island arcs. The subduction of one oceanic plate beneath another also results in the formation of deep ocean trenches.

The similarities in effects between the two types of convergent boundaries include the creation of topographic highs (mountains or island arcs), seismic activity due to the release of energy as the plates move and collide, and volcanic activity from the melting of the subducting plate.

The differences in effects are primarily due to the different densities and compositions of the colliding plates. Ocean-continent convergence can lead to more dramatic mountain building and more explosive volcanic eruptions because of the interaction between the dense oceanic crust and the less dense continental crust. In contrast, ocean-ocean convergence tends to produce less explosive volcanic eruptions and the creation of island arcs and ocean trenches rather than large mountain ranges on continents.

Answer:

d:more dense and falls

Explanation:

warm air Rises around cold air bc of its lower density. and when you have a lower density fluid or sum the lower density fluid rises and the higher density falls

Answer:

Explanation:

I have the same question

Answer:

Alpha decay

Explanation:

Observing the question given, we discovered that the mass number of 240 94 Pu reduced by 4 and the atomic number reduce by 2 in the product obtained from the reaction. This clearly indicates that 240 94 Pu is undergoing alpha decay because atoms that ungoes alpha decay has a decrease of 4 in the mass number and a decrease 2 in the atomic number.

The attached photo gives further explanation...

Answer: The [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide ion concentration.

[tex]pOH=-\log [OH^-][/tex]

Putting in the values:

[tex]pOH=-\log[6.4\times 10^{-5}][/tex]

[tex]pOH=4.19[/tex]

[tex]pH+pOH=14[/tex]

[tex]pH=9.81[/tex]

[tex]9.81=-\log [H_3O^+][/tex]

[tex][H_3O^+]=1.55\times 10^{-10}[/tex]

Thus the [tex][H_3O^+][/tex] is [tex]1.55\times 10^{-10}M[/tex]

The value of [H₃O⁺] will be "1.55 × 10⁻¹⁰ M". To understand the calculation, check below.

According to the question,

The value of [OH⁻] = 6.4 × 10⁻⁵

By taking hydroxide ion concentration log,

→ pOH = log[OH⁻]

By putting the value of [OH⁻],

  pOH = log[6.4 × 10⁻⁵]

           = 4.19

hence,

→  pH + pOH = 14

   9.81 = log [H₃O⁺]

[H₃O⁺] = 1.55 × 10⁻¹⁰ M

Thus the above answer is correct.    

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Answer:

[tex]P_2=\frac{1}{2} \text{ atm}[/tex]

Explanation:

Considering ideal gas situation and initial condition as 1 and final condition as 2 all  other conditions being constant we get

[tex]P_1V_1=P_2V_2[/tex]

Here P1 = 1 atm , V1= 75L, also, V2=2V1 = 2×75 L =150 L

using above equation we have

[tex]1\times75=150\times P_2\\P_2=\frac{75}{150} = \frac{1}{2} \text{ atm}[/tex]

Answer:

Products are stearate anion and water.

Explanation:

Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.

Molecular formula of stearic acid is [tex]C_{17}H_{35}CO_{2}H[/tex].

When [tex]OH^{-}[/tex] is added into stearic acid, [tex]OH^{-}[/tex] removes a proton ([tex]H^{+}[/tex]) from acidic -COOH group and forms stearate anion and water as products.

The balanced acid-base reaction is given as:

                  [tex]C_{17}H_{35}CO_{2}H+OH^{-}\rightleftharpoons C_{17}H_{35}CO_{2}^{-}+H_{2}O[/tex]

Structure of products are given below.

Answer:

A) The reaction is exothermic reaction

B) 46 gm CH3CH2OH  = 1236KJ

15.3 gm ch3ch2OH = 1236/46 x 15.3

= 411.10 KJ..........released

therefore  1 KJ = 0.239 K cal

so, 411.10 x 0.239 kcal

= 98.2529 .................. released

c) 54 gm of H2O produced = 1236KJ

so, 42.7 gm H2O produced = 1236/54 x 42.7KJ

= 977.35 KJ released.

Explanation:

Answer:

alkene

Explanation:

Since the end only has CH2 it would be an alkene.

Alkene means their is a double bond present.

Carbon always wants 4 bonds (4-2=2) Therefore this shows us that it is a double bond, known as an alkene.

Also,

alcohol = OH

alkane = single bond

alkene = double bond

alkyne = triple bond

- Hope this helps! Please let me know if you want further explanation.

The chemical formula CH3CH2CH2CH2CH2CH2 represents a type of hydrocarbon known as hexane, a straight-chain alkane with six carbon atoms commonly used as a solvent in labs and a constituent in gasoline.

The formula CH3CH2CH2CH2CH2CH2 represents a hydrocarbon named Hexane. Hexane is a straight-chain alkane with six carbon atoms. The general formula for an alkane is CnH2n+2, which in the case of hexane explains the presence of 14 hydrogen atoms. Hexane is commonly used as a solvent in laboratories and a constituent in gasoline.

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Answer:

Explanation:

A) Formal charges represent an actual separation of charges.(FALSE)

(B) ΔHo rxn can be estimated from the bond enthalpies of reactants and products.(TRUE)

C)All second-period elements obey the octet rule in their compounds(FALSE).

(D)The resonance structures of a molecule can be separated from one another in the laboratory.(FALSE)

Bond enthalpy which is also reffered to as bond energy is the amount of energy that is required to break one mole of a bond.

taking the single bond between Oxygen and Hydrogen into considerationthe bond energy between their single bond is 463 kJ/mol.

formal charge is used for the comparison of the number of electrons present around an atom in a particular molecule with the number of electrons present around a neutral

Final answer:

Formal charges do not represent actual charge separation, ΔH°rxn can be estimated using bond enthalpies, not all second-period elements obey the octet rule, and resonance structures cannot be physically separated.

Explanation:

Addressing the truthfulness of the given statements:

Answer:

Earth is not flat because the spheroidical shape provides a more effective shape in terms of exposed surface area for absorbing and radiating radiation, and also for a relatively more uniform gravity pull on different points on its surface which might not be so for a flat surface.

You live in your country, not mine because you have evolved over time to be more adapted to living in your own kind of envoirment. Members of a certain species (like you and me as humans) have been spread to maximize the survivability of their species compared to if they were clustered to a particular place.

Answer:

PbSO4 (s) only

Explanation:

Answer:0.8742j/g°C

Explanation: SOLUTION

GIVEN

length of bar=1.25m

mass 382g

temperature= 20°C to 288°C

Q=89300J

Specific Heat Capacity  will be calculated using

Q=mC∆T

where

C = specific heat capacity

Q = heat

m = mass

Δ T = change in temperature

C=Q/ m∆T

=89300/382X(288-20.6)

=0.8742j/g°C

Answer:

D) Ca2+ < K+ < Ar < Cl-

Explanation:

The isoelectronic series is correctly arranged in order of increasing radius is option D. Ca2+ < K+ < Ar < Cl.

Since k+, Ca2+, Cl- and Ar represent the same kind of e- (18) due to this the positive charge increased. The size should be decreased due to the net attraction on outer e- increased and a negative charge should increase the size because the electronic repulsion should be increased.

Therefore, the option d is correct.

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