Answer:
y=6
Step-by-step explanation:
use elimination by making the ys opposite in value and eliminating them from the equation so there is only variable:
-3x+2y=6
2(4x-y=2)
-3x+2y=6
8x-2y=4
Combine like terms and divide by 5 on both sides.
5x=10
x=2
Plug x in to find y:
4(2)-y=2
8-y=2
y=6
The y-coordinate in the system of equations, we can use the elimination method. After manipulating the equations, we find that the y-coordinate of the solution is 6.
The y-coordinate of the solution for the given system of linear equations:
-3x + 2y = 6
4x - y = 2
We can use the method of substitution or elimination. Let's use elimination for this example:
Multiply the second equation by 2 to make the coefficients of y equal but opposite: -3x + 2y = 6 becomes -3x + 2y = 6 (unchanged) and 4x - y = 2 becomes 8x - 2y = 4.
Add the modified equations together: (-3x + 2y) + (8x - 2y) = 6 + 4, which simplifies to 5x = 10.
Divide by 5 to solve for x: x = 10 / 5, so x = 2.
Substitute x = 2 into one of the original equations to find y: -3(2) + 2y = 6, which simplifies to -6 + 2y = 6.
Add 6 to both sides to isolate 2y: 2y = 12.
Divide by 2 to solve for y: y = 12 / 2, so y = 6.
Therefore, the y-coordinate of the solution is 6.
please help asap!!
What is the remainder in the synthetic division problem below
Answer:
A. 7
Step-by-step explanation:
you bring down the 1 and multiply it by -2 then -2 goes to add with 2, which makes it 0. Then 0 x -2 is 0. 0 then goes to add with -3, then -3 comes down. -2 x -3 is 6. 6+1 is 7.
The remainder in the synthetic division problem is 7.
To find the remainder using synthetic division, follow these steps:
Step 1: Write the coefficients of the polynomial in descending order, including placeholders for missing terms. In this case, the polynomial is given as:
[tex]1x^3 + 2x^2 - 3x + 1[/tex]
Step 2: Since we are dividing by (x + 2), change the sign of the divisor and set it equal to zero to find the value we'll use in the synthetic division.
x + 2 = 0
x = -2
Step 3: Set up the synthetic division table:
-2 | 1 2 -3 1
Step 4: Perform the synthetic division:
Bring down the first coefficient: 1
Multiply -2 by 1: -2
Add the result to the next coefficient: 2 - 2 = 0
Multiply -2 by 0: 0
Add the result to the next coefficient: -3 + 0 = -3
Multiply -2 by -3: 6
Add the result to the next coefficient: 1 + 6 = 7
Step 5: The last entry in the synthetic division row (7 in this case) is the remainder.
The remainder in the synthetic division problem is 7.
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Graph y=sin^-1 (-1/2x) on the interval -5≤x≤5.
Answer:
Option c.
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The equation is:
y=sin^-1 (-1/2x) on the interval -5 ≤ x ≤ 5
Looking at the graph, we can tell that the correct option is
Option c.
What is the area of the base of a cylinder with a volume of 174? in.3 and a height of 12 inches? 1. Apply the formula for the volume of a cylinder: V = Bh 2. Substitute the known measures into the formula: 174? = B(12) 3. Apply the division property of equality: 174? 12 = B 12 12 The area of the base of the cyclinder is ? in.2.
Answer:
The area of the base of the cylinder is [tex]14.5\ in^{2}[/tex]
Step-by-step explanation:
we know that
The volume of the cylinder is equal to
[tex]V=Bh[/tex]
where
B is the area of the base of cylinder
h is the height of the cylinder
In this problem we have
[tex]V=174\ in^{3}[/tex]
[tex]h=12\ in[/tex]
Substitute in the formula and solve for B
[tex]174=B(12)[/tex]
Apply the division property of equality
[tex]B=174/(12)=14.5\ in^{2}[/tex]
Answer:14.5
Step-by-step explanation: just did it
For mutually exclusive events r1, r2, and r3, we have p(r1) = 0.05, p(r2) = 0.6, and p(r3) = 0.35. also, p( q | r 1 (=0.6, p (q | r 2 )=0.3, and p ( q | r 3 ) = 0.6. find p ( r1 | q ).
From the definition of conditional probability:
[tex]P(R_1\mid Q)=\dfrac{P(R_1\cap Q)}{P(Q)}[/tex]
By the law of total probability,
[tex]P(Q)=P(Q\cap R_1)+P(Q\cap R_2)+P(Q\cap R_3)[/tex]
[tex]P(Q)=P(Q\mid R_1)P(R_1)+P(Q\mid R_2)P(R_2)+P(Q\mid R_3)P(R_3)[/tex]
[tex]P(Q)=0.42[/tex]
Since
[tex]P(R_1\cap Q)=P(Q\mid R_1)P(R_1)[/tex]
we end up with
[tex]P(R_1\mid Q)=\dfrac{0.03}{0.42}\approx0.0714[/tex]
What is the solution of the inequality (x-4)(x+3) more then or equal to zero? Graph Solution.
ANSWER
[tex]x \leqslant - 3,x \geqslant 4[/tex]
EXPLANATION
The given inequality is
[tex](x - 4)(x + 3) \geqslant 0[/tex]
To solve this inequality, we need to solve the corresponding equation:
[tex](x - 4)(x + 3) = 0[/tex]
This implies that
[tex]x = - 3 \: or \: x = 4[/tex]
We now plot the solutions of the equation and use it to solve the corresponding inequality as shown in the attachment.
These values divide the number line into 3 regions.
The region(s) that satisfies the inequality is the solution set
From the graph the solution is
[tex]x \leqslant - 3,x \geqslant 4[/tex]
PLEASE HELP FAST
For v=-5i-2j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vectors i and j
Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
Please answer this question only if you know the answer!! 39 points and brainliest!
Answer:
No, just because the amount of recylcing has gone up this year does not mean that we can conclude it's more this year than ever before. We are only given information for this year and last year, we can't come to that conclusion unless we are given information about the amount of recyling done in all the years.
I reject this conclusion because it says that the people have recycled more this year than ever before.
Generally ever before mean since a long time ago and from the data given we only have recording of last year, not any year before that. If the conclusion had said that the people in mesopotamiaville are recycling more this year than last year. It would have been correct but instead it has given us an invalid conclusion because from the data we have been given we can not possibly gather any other information that can help us accept or reject the conclusion. So therefore the conclusion given is invalid. Hence the reason I reject this conclusion.
hope this helps
For what value of c does the following system have no solution?
1/2x+1/5y=2
5x+2y=c
Answer:
Step-by-step explanation:
[tex]\frac{1}{2}x+\frac{1}{5}y = 2 \mid 5x + 2y = c[/tex]
First let's multiply the 1st equation by 10.
[tex]5x + 2y = 20 \mid 5x + 2y = c[/tex]
So, we can see that the equations have the same coefficients and that implies they are equal.
So the equation has no solutions for. [tex]c \in R \setminus{20}[/tex]
The given system of linear equations has no solutions only when c is different than 20.
For what value of c does the system have no solution?A system of linear equations has no solutions only when both lines are parallel.
Remember that two lines are parallel if the lines have the same slope and different y-intercept.
In this case, our lines are:
(1/2)*x + (1/5)*y = 2
5x + 2y = c
Writing both of these in the slope-intercept form, we get:
y = 5*2 - (5/2)*x
y = c/2 - (5/2)*x
So in fact, in both cases, we have the same slope.
And the only condition to not have any solution is to have:
c/2 ≠ 5*2 = 10
c/2 ≠ 10
c ≠ 10*2 = 20
c ≠ 20
So if c is any value different than 20, the system has no solution.
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what are the equations for the asymptotes of this hyperbola?
Answer:
D
Step-by-step explanation:
The question is on asymptotes of a hyperbola
General equation for a hyperbola is; (x-h)² /a² - (y-k)²/b² =1
given y²/36 - x²/121 =1
then h=0 and k=0 thus Center of hyperbola= (0,0) at the origin.
b²=36,b⇒6 a²=121, a⇒11
Vertices of hyperbola v=( h+a, k) and (h-a, k) = (11,0) and (-11, 0)
Equation of asymptotes is given by;
y=k ± b/a (x-h) and we have found that a=11 and b=6
hence y=0 ± 6/11(x-0)
y=6/11 x and y= -6/11 x
Answer: Option D
[tex]y=\frac{6}{11}x[/tex]
and
[tex]y=-\frac{6}{11}x[/tex]
Step-by-step explanation:
We know that the general equation of a hyperbola with transverse vertical axis has the form:
[tex]\frac{(y-h)^2}{a^2}-\frac{(x-k)^2}{b^2} =1[/tex]
Where the point (h, k) are the coordinates of the center of the ellipse
2b is the length of the transverse horizontal axis
2a is the length of the conjugate axis
The asymptotes are lines to which the hyperbola graphic approaches but never touches.
The asymptotes have the following equation
[tex]y -y_1=\±m(x-x_1)\\\\[/tex]
Where
[tex]m=\frac{a}{b}\\\\y_1 = h\\\\x_1 = k[/tex]
In this case the equation of the ellipse is:
[tex]\frac{y^2}{36} -\frac{x^2}{121}=1[/tex]
Then
[tex]h=y_1= 0\\\\k =x_1= 0[/tex]
[tex]m = \frac{\sqrt{36}}{\sqrt{121}}[/tex]
The asymptotes are:
[tex]y -0=\±\frac{\sqrt{36}}{\sqrt{121}}(x-0)\\\\[/tex]
[tex]y=\±\frac{6}{11}x[/tex]
see the attached image
If the point P(π,6) lies on the graph of h(θ)=asin(θ−π/2)+4, then the value of a is:
2
-10
-2
10
Answer:
2
Step-by-step explanation:
We should put π in place of [tex]\theta[/tex] and 6 in place of [tex]h(\theta)[/tex] in the equation given and then do algebra to find the value of [tex]a[/tex]. Steps are shown below:
[tex]h(\theta)=aSin(\theta-\frac{\pi}{2})+4\\6=aSin(\pi-\frac{\pi}{2})+4\\6=aSin(\frac{\pi}{2})+4\\6=a(1)+4\\6=a+4\\a=6-4\\a=2[/tex]
The answer is 2
Note: the value of [tex]Sin(\frac{\pi}{2})[/tex] is 1
PLEASE HELP!
What is the value of P(X=4 or X=1)?
Enter your answer in the box.
ANSWER: 0.2
ANSWER
P(X=4 or X=1)=0.2
EXPLANATION
From the table, the probability that X=4 is P(X=4)=0.15
and the table, the probability that X=1 is P(X=1)=0.05
We want to find P(X=4 or X=1)
Recall that
P(X=4 or X=1)=P(X=4)+P(X=1)
We substitute the given probability values to obtain:
P(X=4 or X=1)=0.15+0.05
P(X=4 or X=1)=0.2
Answer: 0.2 is the answer
Step-by-step explanation:
hope this helps :]
If a quadrilateral with a point of (-5,-2) where to be reflected across the x-axis, would that point be (-5,2) or (-2,5)?
Answer:
(-5,2)
Step-by-step explanation:
what is the equation of a line that passes through point (6, 3) and is perpendicular to a line with a slope of -3/2?
For this case we have that by definition, the slope point equation of a line is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cutoff point with the y axis
By definition, if two lines are perpendicular, the product of their slopes is -1. That is to say:
[tex]m_ {1} * m_ {2} = - 1\\If\ it\ tells\ us: m_ {1} = - \frac {3} {2}:\\- \frac {3} {2} * m_ {2} = - 1\\m_ {2} = \frac {2} {3}[/tex]
Substituting:
[tex]y = \frac {2} {3} x + b[/tex]
We substitute the point to find "b":
[tex]3 = \frac {2} {3} 6 + b\\3 = 4 + b\\b = 3-4\\b = -1[/tex]
Finally:
[tex]y = \frac {2} {3} x-1[/tex]
Answer:
[tex]y = \frac {2} {3} x-1[/tex]
Find the volume of a cone with diameter 12 m and height 20 m.
a.40 pi m3
c.120 pi m3
b.240 pi m3
d.720 pi m3
if the cone has a diameter of 12, thus its radius is half that, namely 6.
[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=6\\ h=20 \end{cases}\implies V=\cfrac{\pi (6)^2(20)}{3}\implies V=240\pi \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill V\approx 753.98~\hfill[/tex]
The volume of cone is 240π m³.
What is volume?The mathematical term "volume" indicates the amount of three-dimensional space that an object or closed surface occupies. The volume is measured in cubic units like m³, cm³, in³, and so on.
Volume is also sometimes referred to as capacity.
Given diameter of cone = 12m
radius = diameter/2 = 12/2 = 6m
height of cone = 20m
volume of cone is given by 1/3πr²h
where r = radius and h = height
volume = 1/3 x π x (6)² x 20
volume = 240π m³
Hence the volume is 240π m³.
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What is the height of the triangular prism below if the volume equals 1,638 cubic millimeters? 65 mm 63 mm 26 mm 28 mm.
Answer:
The height of the triangular prism is [tex]26\ mm[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The volume of the triangular prism is equal to
[tex]V=Bh[/tex]
where
B is the area of the triangular base
h is the height of the prism
Find the area of the base B
[tex]B=\frac{1}{2}(7)(18)=63\ mm^{2}[/tex]
we have
[tex]V=1,638\ mm^{3}[/tex]
[tex]h=x\ mm[/tex]
substitute and solve for x
[tex]1,638=(63)x[/tex]
[tex]x=1,638/(63)=26\ mm[/tex]
Answer:
C. 26mm
Step-by-step explanation: Just did the assignment
Liz babysits for $10 per hour and tutors for $25 per hour. She wants to make at least $175 each week. Write an inequality that models how much she earns form babysitting and tutoring.
Let b represent the number of hours Liz babysits. Let t represent the number of hours she spends tutoring.
We are gonna use the formula y=mx+b
Then, B= 10 T=25
So, the final equation is: 10b+25t(greater than or equal to) 175
An inequality that models how much Liz earns from babysitting and tutoring is 10b+25t≥175.
What are inequalities?Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.
It is mostly denoted by the symbol <, >, ≤, and ≥.
Let b represent the number of hours Liz babysits. Let t represent the number of hours she spends tutoring.
Given Liz babysits for $10 per hour and tutors for $25 per hour. She wants to make at least $175 each week. Therefore, the inequality can be written as,
($10 × b) + ($25 × t) ≥ $175
10b + 25t ≥ 175
Hence, an inequality that models how much Liz earns from babysitting and tutoring is 10b+25t≥175.
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Ryan invested some money in his bank he agreed a simple interest rate of 4% per annum for a 2 years At the end of the 2- years period the value of his investment increased by ?24
Final answer:
Ryan invested £300 in a simple interest account with a 4% annual rate to achieve a £24 increase over 2 years.
Explanation:
Understanding Simple Interest Calculations
Ryan's investment scenario involves calculating simple interest, which is straightforward and doesn't compound over time. To find the principal amount Ryan invested, we can use the simple interest formula:
I = PRT
Where I is the interest, P is the principal amount, R is the rate of interest per year, and T is the time in years. Given that the interest (£24) accrued over 2 years at a rate of 4%, we can set up the equation:
£24 = P * 0.04 * 2
Rearranging the equation to solve for P gives us:
P = £24 / (0.04 * 2)
So, the principal amount Ryan invested would be £300. This is the amount that, when increased by a 4% simple interest rate over 2 years, resulted in a £24 increase in value.
Two cars started from the same town at the same time. One car traveled 50 miles an hour for 4 hours. The other car traveled 60 miles an hour for 8 hours. How many miles farther did the second car travel?
While 50 miles per hour so 50 multiplied by 4 will give you 200 miles
The second vehicle traveling at 60 miles per hour traveling for 8 hours so multiply 60 x 8 and you will get 480
280 miles farther the second car travels.
How many miles farther did the second car travel?Given:
Two cars started from the same town at the same time.One car traveled 50 miles per hour for 4 hours.The other car traveled 60 miles an hour for 8 hours.Find:
How many miles farther did the second car travelSolution:
So, as it is given that one car traveled 50 miles per hour for 4 hours that means it travels 50*4 miles = 200 miles.
So, this car travels 200 miles.
Now, the second car traveled 60 miles an hour for 8 hours which means it travels 60*8 miles = 480 miles.
So, the second car travels 480 miles.
Now, for getting how farther the second car traveled we have to subtract the miles traveled by the first car from the second car.
Therefore, second car travels farther = 480 - 200 = 280 miles.
Hence, the second car travels 280 miles farther from the first car.
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What are the coordinates of the center of the circle shown below?
Express your answer in the form (a,b) without using spaces.
[tex]x^2+y^2-2x+6y+9=0[/tex]
Answer:
Step-by-step explanation:
Rewrite this equation in standard form:
x² - 2x + 1 - 1 + y² + 6y + 9 = 0, or
(x - 1)² + (y + 3)² = 1
Compare this to:
(x + h)² + (y + 3)² = r²
We see here that (h, k), the center of the circle, is (1, -3), and the radius of the circle is 1.
Answer:
the center is at (1, -3)
Step-by-step explanation:
The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r".
So we need to write the ecuation x^2 + y^2 - 2x + 6y + 9 = 0 in the format above.
So we have:
x^2 + y^2 - 2x + 6y + 9 = (x^2 -2x + 1) + (y^2 + 6y + 9) - 1
(x^2 -2x + 1) + (y^2 + 6y + 9) - 1 = (x-1)^2 + (y+3)^2 - 1
So now, looking at the equation: (x-1)^2 + (y+3)^2 = 1
We know that h=1 and k=-3. So the center is at (1, -3)
The table below shows the values of y for different values of x:
x 7 8 9 10 11 12 13
y 13 10 7 6 5 3 0
The correlation coefficient for the data is −0.9847. Which statement is true about the data in the table?
There is no relationship between x and y.
There is a weak negative relationship between x and y.
There is a strong positive relationship between x and y.
There is a strong negative relationship between x and y.
Answer:
There is a strong negative relationship between x and y
Step-by-step explanation:
we know that
The correlation coefficient r measures the direction and strength of a linear relationship. It can take a range of values from +1 to -1.
Values between 0.7 and 1.0 (-0.7 and -1.0) indicate a strong positive (negative) linear relationship
In this problem
The correlation coefficient for the data is −0.9847
therefore
Is a strong negative correlation
Answer:
D.. Just took . the test
Step-by-step explanation:
Amanda wants to make this design of circles inside an equilateral triangle. a. What is the radius of the large circle to the nearest hundredth of an inch? b. What are the radii of the smaller circles to the nearest hundredth of an inch?
Without further context or diagrams, it's challenging to determine the radii of the stated circles. In general, properties of the equilateral triangle and the relationship between the radius of the circle and the side of the triangle are used in these geometrical problems. More details would permit applying these principles to reach a solution.
Explanation:Based on the information provided, it appears that there might be some missing context or diagrams for this question. Without further elucidation on Amanda's particular design, it would be difficult to accurately determine the radius of the 'large circle' and the 'smaller circles'.
Generally, in such geometric problems which have circles inside an equilateral triangle, one often uses properties of the equilateral triangle and relations between the radius of the circle and side of the triangle. For instance, in an equilateral triangle, where a circle fits exactly inside the triangle (incircle), the radius could be found by the formula (side of equilateral triangle) / (2*sqrt(3)). Similarly, when a circle is drawn outside the triangle (circumcircle), encompassing it, the radius is calculated as (side of equilateral triangle) / sqrt(3).
However, without additional context or a clear diagram, it's impossible to apply these principles to solve Amanda's challenge.
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A square is 4 inches. Kelsey drew a rectangle with the same area as the square. The length of Kelsey's rectangle is 8 inches. What is the perimeter,in inches, of Kelsey's rectangle?
Answer:
The answer is 20 inches
Step-by-step explanation:
Brenda's scores on the first three of four 100-point science tests were 95, 92, and 89. What score does she need on her fourth science test to ensure an average score of at least 93?
Answer:
96 or better
Step-by-step explanation:
Brenda has scored relative to her desired average +2, -1, and -4 points, or a total of -3 points. To ensure her average is 93, she must score at least 3 points above her desired average: 96 or better.
Square ABCD is located on a coordinate plane. The coordinates for three of the vertices are listed below.
A (2,7) , C (8,1),D (2,1)
Square ABCD is dilated by a scale factor of 2 with the center of dilation at the origin, to form square A’B’C’D’. What are the coordinates if vertex B’?
ANSWER
B' has coordinates (16,14).
EXPLANATION
The given coordinates of square ABCD are :
A (2,7) , C (8,1),D (2,1)
In order to form a square, the coordinates of B should be: (8,7)
The mapping for dilation with a scale factor 2, about the origin is
[tex](x,y)\to (2x,2y)[/tex]
This implies that:
[tex]B(8,7)\to B'(2 \times 8,2 \times 7)[/tex]
When we simplify we get:
[tex]B(8,7)\to B'(16,14)[/tex]
Hence B' has coordinates (16,14).
Carlos is almost old enough to go to school! Based on where he lives, there are 6 elementary schools, 3 middle schools, and 2 high schools that he has the option of attending. How many different education paths are available to Carlos?
The answer is -- 36
Answer:
the answer is 36
Step-by-step explanation:
What are the characteristics of the graph of the inequality x ≤ -8?
It will use an open circle.
The ray will move to the right.
It will use a closed circle.
The ray will move to the left.
Answer:
Step-by-step explanation:
Both of the following are characteristics of this graph
It will use a closed circle.
The ray will move to the left.
the locus of all points that are the same distance from two given points is a ___. A. Line B. Square C. Circle D.Parabola
Answer:
A.
Line
Step-by-step explanation:
In geometry a straight line is defined as the shortest distance between any two given points. Using the concept of locus, a Line is defined as the locus of all points that are equidistant from two given points.
On the other hand, the locus definition of a circle is the locus of a point that moves at a fixed distance from a center point. This fixed distance is called the radius of the circle.
Final answer:
The correct answer to the student's question is a circle, as it is the locus of all points equidistant from two coinciding points, which are special case foci of an ellipse.
Explanation:
The locus of all points that are the same distance from two given points is called a perpendicular bisector, but this is not one of the options provided. Among the given options, the correct answer is a circle. Thinking geometrically, if the two given points are the foci of an ellipse, the locus of points equidistant to the foci would indeed be a circle, specifically when the foci coincide at the center of the circle. This characteristic relates closely to the definition of an ellipse as provided, which is a closed curve wherein the sum of the distance from the foci to any point on the curve is constant. However, this definition does not fully match the question's condition of being the same distance from the two points, which is a special case of an ellipse where the foci are at the same place, thus forming a circle.
Who was the first person to prove the pythagorean theorem?
Pythagoras & his colleagues
Answer:
It was named after Pythagoras, a Greek mathematician and philosopher. The theorem bears his name although we have evidence that the Babylonians knew this relationship some 1000 years earlier.
Step-by-step explanation:
Someone PLEASE HELP! I'm on a timed assignment and only have 15 minutes to answer this.... I'll GIVE YOU BRAINLIEST.
Answer:
3/10
Step-by-step explanation:
Answer:
the answer to that is 1/10
Step-by-step explanation:
Help with this question, please!! I don't understand!
Answer:
FE = 30°
Step-by-step explanation:
arc FGC = arc FG + arc GB + arc BC
220° = 90° + arc GB + 70° . . substitute known values
60° = arc GB . . . . . . . . . . . . . subtract 160°
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External angle A is half the difference of arcs EG and GB:
30° = (1/2)(arc FE +90° -60°) . . . substitute known values
60° = arc FE + 30° . . . . . . . . . . . multiply by 2 and simplify
30° = arc FE . . . . . . subtract 30°
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The key to this problem is the relationship between external angle A and the measures of the arcs it subtends.