What is the weight of a human eye ball

Answers

Answer 1
on an average the adult human eyeball weighs 0.25oz or 7.5grams

Related Questions

Metamorphic rocks may generally be distinguished from igneous rocks because

Answers

The grains in igneous rocks are interlocking but the Metamorphic rocks are not.

A train that travel 100 kilometer in 4hours is traveling at what speed?

Answers

Speed = Distance/Time = 100 km / 4 hours = 100/4 km per hour = 25 kph

A study showed that children who watch more than 5 or more hours of television a day have lower grades than children who watch less. Which of these could be a hidden variable

Answers

Children who watch more television may have parents who are home less often to help them with schoolwork.

The answer is D

Children who watch more television may have parents who are home less often to help them with schoolwork

(ii) a woman stands on a bathroom scale in a motionless elevator. when the elevator begins to move, the scale briefly reads only 0.75 of her regular weight. calculate the acceleration of the elevator, and find the direction of acceleration.

Answers

2.45 m/s^2 Elevator is moving down. The woman's weight is a function of the local gravity plus the local acceleration, an expression for this would be G + A = 0.75 G = Normal attraction due to gravity A = Weight due to acceleration. Substituting 1 for G gives 1 + A = 0.75 Solving for A 1 + A = 0.75 A = -0.25 So the acceleration experienced is -0.25 times the acceleration due to gravity. So multiply by 9.8 m/s^2 -0.25 * 9.8 m/s^2 = -2.45 m/s^2 So the woman briefly experienced an acceleration of 2.45 m/s^2 as the elevator started moving. And since her weight decreased, that means that the elevator started moving down.

Final answer:

To calculate the acceleration of the elevator when a woman's weight reads 0.75 of her regular weight, we use Newton's second law, resulting in an acceleration of -2.45 m/s². This indicates that the elevator is accelerating downwards or decelerating while moving upwards.

Explanation:

If a woman standing on a bathroom scale in an elevator observes that the scale reads only 0.75 of her regular weight, it means that the net force acting on her is reduced because the elevator is accelerating.

To calculate the acceleration of the elevator, we can use Newton's second law of motion and some assumptions about gravitational acceleration (g = 9.8 m/s2).

Let's denote the woman's mass as m, her regular weight as W = mg (where g is the acceleration due to gravity), and the scale reading when the elevator accelerates as 0.75W. When the elevator is accelerating, the apparent weight (scale reading) is W' = 0.75mg.

The net force (Fnet) acting on the woman in the elevator is her apparent weight, W', minus her actual weight, W, leading to Fnet = ma. Therefore:

Fnet = W' - W

ma = 0.75mg - mg

a = 0.75g - g = -0.25g

This gives us a = -0.25(9.8 m/s2) = -2.45 m/s2. The negative sign indicates that the acceleration is directed downwards - meaning that the elevator is accelerating downward or decelerating while going up.

A 4-kg ball has a momentum of 12 kg∙m/s. what is the ball's speed?

Answers

m= 4kg
v= ?
momentum = Mv
so
12kgms-¹ = 4kg×v
v= 12÷4 = 3ms-¹
momentum= 12kgm/s
mass=4 kg
so,speed=momentum/mass=12/4=3m/s

An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.

What is the force applied to the scale by the car?

_____N

Answers

using F = Ke
F = 39200×(25÷100) = 39200×0.25
F= 9800N

Answer:

Force, F = 9800 N

Explanation:

It is given that,

The spring constant for the industrial scale at the junkyard is, k = 39,200 N/m

The compression in the spring, x = 25 cm = 0.25 m

To find,

The force applied to the scale by the car.

Solution,

The Hooke's law gives the relation between the force and the compression in the spring. Its expression is given by :

[tex]F=-kx[/tex]

[tex]F=39200\times 0.25[/tex]

F = 9800 N

So, the force applied to the scale by the car is 9800 N.

The Kentucky derby was won in 2000 by fusaichi Pegasus in 121 s. If the race is 2011 m , what was his speed?

Answers

To find the rate of speed, simply divide the length of the race by the length of time it took for the horse to run the race. In this case, 2011 m / 121 sec = 16.619 m/sec. Converting this from m/sec to mph, the value becomes approximately 37.1778, or 37.18 mph.

Maria throws an apple vertically upward from a height of 1.4 m with an initial velocity of +3.1 m/s. Will the apple reach a friend in a tree house 4.2 m above the ground? The acceleration due to gravity is 9.81 m/s 2 .

Answers

According to the problem, you are trying to find a height. If the height a the top of the path is greater than or equal to 4.2m, then the apple will reach Maria's friend. If the height is less than 4.2m, the apple will not reach maria's friend. You are given the known quantities: initial velocity, acceleration, and you can set final velocity = 0. This means you can use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2a\Delta x[/tex]

Explanation:

It is given that,

Initial position of the Apple, [tex]h_o=1.4\ m[/tex]

Initial velocity, u = 3.1 m/s

Position of friend, Y = 4.2 m

Using second equation of motion as :

[tex]Y=ut-\dfrac{1}{2}gt^2+h_o[/tex]

[tex]4.2=3.1t-\dfrac{1}{2}\times 9.8t^2+1.4[/tex]    

[tex]3.1t-4.9t^2-2.8=0[/tex]..............(1)

On solving the above quadratic equation we get t = 2.02 seconds

Since, the value of t is real. So, the apple will reach a friend in a tree house. Hence, this is the required solution.                                    

If earth were twice as far from the sun, the force of gravity attracing earth to the sun would be

Answers

The gravitational force between two objects of mass m₁ and m₂ if
[tex]F = G \frac{m_{1} m_{2}}{d^{2}} [/tex]
where d =  distance between the objects
G = gravitational constant

We could consider the earth and the sun as the two masses.
If the earth were twice as far from the sun, then the distance would be 2d.
Therefore the force of attraction would be
[tex]G \frac{m_{1} m_{2}}{(2d)^{2}} =G \frac{m_{1} m_{2}}{4d^{2}}= \frac{F}{4} [/tex]

Answer:
The force of gravity will decrease by a factor of 4.

The energy of motion best describes which of the following?

A) The energy of fusion

B) The energy ofan electrical charge.

C) Kinetic energy

D) Potential energy

Answers

your answer is C. Kinetic Energy

According to law of conservation of energy, energy of motion is described by kinetic energy as the kinetic energy is displayed only when the object is in motion as per how much energy is stored in the object which are equal.

What is law of conservation of energy?

According to law of conservation of energy, it is evident that energy is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of energy is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Julius Robert Mayer in the year 1842.

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Assume that on a physics diagram, you saw a croquet ball moving along the grass and above it was an arrow labeled "3.5 m/s" that indicated BOTH the speed and direction of the ball. This is an arrow is a(n) _____.

Force arrow
Acceleration arrow
Speed arrow
Vector

Answers

Answer:

a vector.

Explanation:

Final answer:

The arrow labeled '3.5 m/s' in the given scenario, which denotes both the speed and direction of a croquet ball, is called a vector. A vector, in physics, represents a quantity showcasing both magnitude (in this case, velocity measured as '3.5 m/s') and direction.

Explanation:

In the context of the question, the arrow labeled '3.5 m/s' that is indicating both the speed and the direction of the croquet ball is known as a vector. In physics, a vector is a quantity that possesses both magnitude (size or quantity) and direction. In this case, the '3.5 m/s' is the magnitude of the vector (the speed of the ball), and the direction the arrow is pointing indicates the direction the ball is moving. This is as opposed to a scalar quantity, which only has magnitude.

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how can two tectonic plates move relative to each other

Answers

They are doing the transform type of tectonic plate movement. This is a process where the plates move sideways. But they move at a rate of a few inches a year. Did that help you?

Earth has an abundant amount of iron, but also has many elements heavier than iron. Form a hypothesis

Answers

Over a period of time, the explosions of sun have become more massive to man kind, thus creating heavier elements found on Earth.

The earth has many elements heavier than iron due to the hypothesis that the explosions of sun have become more massive to man kind over a period of time, thus creating heavier elements found on Earth.

Heavy elements found on earth

Heavy elements such iron are formed by nuclear fusion reaction. Example include the heavy element of iron.

Source of these heavy elements are:

geogenic,

industrial,

agricultural,

pharmaceutical,

domestic effluents, and atmospheric sources.

Many elements that are heavier than iron has been formed over the years due to the sun explosions.

The formation of these heavy elements occurs due to the process called neutron capture, where neutrons penetrate an atomic nucleus in explosions of the sun.

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While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. while driving back home moments later at the same speed but in the opposite direction, you see that the rain is falling straight down. from these observations, determine the speed and angle of the raindrops relative to the ground?

Answers

Answer:

[tex]v = 68.7 m/s[/tex]

angle made with the vertical

[tex]\theta = 21.3 degree[/tex]

Explanation:

Velocity of rain with respect to the car with vertical direction makes 38 degree angle

so let say rain velocity is

[tex]v_r = v_x\hat i + v_y \hat j[/tex]

[tex]v_{rc} = v_r - v_c[/tex]

[tex]v_{rc} = (v_x + 25)\hat i + v_y[/tex]

now we have

[tex]tan38 = \frac{v_x + 25}{v_y}[/tex]

while return to home

[tex]v_{rc} = (v_x - 25)\hat i + v_y[/tex]

now the angle with vertical is zero

so we have

[tex]v_x = 25[/tex]

now we have

[tex]tan38 = \frac{50}{v_y}[/tex]

[tex]v_y = 64 m/s[/tex]

so we have

[tex]v_r = 25 \hat i + 64 \hat j[/tex]

now magnitude of the speed is

[tex]v = \sqrt{25^2 + 64^2}[/tex]

[tex]v = 68.7 m/s[/tex]

angle made with the vertical

[tex]\theta = tan^{-1}\frac{25}{64}[/tex]

[tex]\theta = 21.3 degree[/tex]

Find the density of a 5 kg solid cylinder. the cylinder is 5 cm tall and has a radius of 2 cm.

Answers

Density=mass/volume 

mass= 5kg 

volume: πr²h 
= π(2)²(5) 
=62.83 cm³ or 0.06283 m³

density: m/v 
d= 5/0.06283 m³
d=79.57 kg/m³

Hope I helped :) 

An endothermic reaction is one that uses which form of energy?

A) Electrical Energy

B) Sound Energy

C) Chemical Energy

D) Nuclear Fusion

Answers

C( Chemical Energy because the process includes chemical energy turning into thermal energy

An endothermic reaction is the one that makes use of chemical energy.

What is endothermic reaction?

An endothermic reaction is defined as a chemical reaction which is a thermodynamic process  accompanied by an increase in enthalpy  of the system.In this process, a system absorbs energy from the surroundings  which is mainly thermal energy.

Thus an endothermic reaction leads to an increase in the temperature of the system with a decrease in the temperature of the surroundings.Endothermic reactions usually involve the formation of bonds which requires input of energy.In endothermic reactions, entropy of the surrounding decreases.

Many endothermic processes involve the physical changes rather the chemical changes.In an endothermic reaction ,the potential energy of products is greater than that of reactants.

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What kind of front involves three air masses of different temperatures?

Answers

Answer:  "an occluded front" .
_____________________________________

An occluded front involves three air masses of different temperatures: two cold air separated by a warm air .

What is occluded front?

Due to different densities, when big amounts of warm and cold air collide, they do not mix. They instead create a front that is typically hundreds of miles long. When a warm air mass is sandwiched between two cold air masses, an occluded front forms. As the cool air masses collide in the centre, the warm air mass rises. As the warm air mass is "cut off" from the earth and forced upward, the temperature decreases. Such fronts have the potential to produce violent winds and copious rain.

Typically, mature low pressure zones are where occluded fronts form.

Early occlusion of an extratropical cyclone in the Northern Hemisphere

Occlusion comes in two flavours, warm and cold:

In a cold occlusion, the cool air mass in front of the warm front is pushed aside by the cold air mass that is overtaking it because it is colder.In a warm occlusion, the warm air is lifted by the warm front's overtaking cold air mass, which is warmer than the cool air ahead of the warm front.

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As you move from left to right on the periodic table, what generally happens to the electronegativity? *

Answers

it increases as the number of protons and electrons in the shell increases

What is the input and output of a microwave?

Answers

Microwave oven wattage input or output. Power consumption is energy consumed by the device from your home power grid. The energy output is actual power emitted by the magnetron in the form of microwaves for heating the food.

If a ball is thrown vertically upward from the ground with a velocity of 96 ft/s, then its height after t seconds is s = 96t − 16t2. what is the maximum height reached by the ball?

Answers

The maximum height is reached by the ball: the height is 96(3) - 16(9) = 144 ft.

The maximum height achieved by the ball thrown vertically upwards is 243.9 ft.

What is a time - varying function?

A time varying function is a function whose final value varies with time.

Example - f(t) = 2t + 5

Given is a ball which is thrown vertically upward from the ground with a velocity of 96 ft/s, then its height after [t] seconds is S = 96t − 16t².

We can write -

S = 96t − 16t²

Differentiating with respect to 't', we get -

dS/dt = 96 - 2 x 16 x t

dS/dt = 96 - 32t

Now, for maximum height -

dS/dt = 0

96 - 32t = 0

32t = 96

t = 96/32

t = 3 seconds

At t = 3 seconds, the height will be maximum. Now, it is given that -

[u] = 96 ft/sec

[v] = 0  (at maximum height)

[g] = - 9.8 m/s²

Using the second equation of motion, we get -

S = ut + 1/2 gt²

S [max] = 96 x 3 - 0.5 x 9.8 x 3 x 3

S [max] = 288 - 44.1

S [max] = 243.9 ft

Therefore, the maximum height achieved by the ball thrown vertically upwards is 243.9 ft.

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When water has a temperature greater than 100c?

Answers

When water has a temperature greater than 100c, it's boiling

What happens to the free energy released as electrons are passed from photosystem II to photosystem I through a series of electron carriers?

Answers

It is used to establish and maintain a proton gradient.

A swimmer can swim in still water at a speed of 9.50 m/s. he intends to swim directly across a river that has a downstream current of 3.75 m/s. 46.
a. what must the swimmer’s direction be?
b. what is his velocity relative to the bank?

Answers

send more info please what area are u on

What is the wavelength of light emitted when the electron in a hydrogen atom moves from the n=5 state to the n=2 state? give your answer in nm?

Answers

may be answer is  303 nm

The velocity of a car changes from 60. meters per second north to 45 meters per second north in 5.0 seconds. the magnitude of the car's acceleration is

Answers

The answer to the problem is 3.0 m/s2.

A skater increases her speed uniformly from 2.0 meters per second to 7.0 meters per second over a distance of 12 meters. the magnitude of her acceleration as she travels this 12 meters is

Answers

The magnitude of her acceleration as she travels this 12 meters is 1.875m/s^2

A skater moves with an initial velocity of 2 m/s, and a final velocity of 7 m/s by which he covers 12 meters, so the acceleration will be 1.875 m/s².

What is Velocity?

A vector measurement of the direction and speed of the motion is what is meant by the term "velocity" in physics. In more detail, the rate of change in an object's position relative to a frame of reference and time can also be described as the object's velocity.

Velocity, which is defined as the rate of motion of an object in a specific direction, tells us how quickly an object is traveling. The speed at which anything is traveling is determined by this.

Given information according to the question,

Initial velocity, u = 2 m/s

Final velocity, v= 7 m/s

Distance, d = 12 m

Use the equation of motion to find the acceleration of the skater,

v² - u² = 2as

7² - 2² = 24a

a = 45/24

a = 1.875 m/s².

Therefore, the acceleration of the skater is 1.875 m/s².

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A stubborn 130 kg pig sits down and refuses to move. to drag the pig to the barn, the exasperated farmer ties a rope around the pig and pulls with his maximum force of 800 n. the coefficients of friction between the pig and the ground are μs=0.80 and μk=0.50. part a calculate the force which farmer needs to apply to budge the pig.

Answers

Final answer:

To calculate the force needed to budge the stubborn pig, we need to consider the frictional forces acting on it. Given the given values of μs and the weight of the pig, the force required to budge the pig can be found by subtracting the force of friction from the maximum force the farmer can exert.

Explanation:

To calculate the force needed to budge the stubborn pig, we need to consider the frictional forces acting on it. The friction force can be calculated using the formula F_friction = μs ×F_normal, where F_normal is the normal force acting on the pig. The normal force is equal to the weight of the pig, which is given by F_weight = m × g, where m is the mass of the pig and g is the acceleration due to gravity.

Using the given values of μs and the weight of the pig, we can calculate the force of friction. Given that the maximum force the farmer can exert is 800 N, the force required to budge the pig can be found by subtracting the force of friction from the maximum force.

Let's calculate the force:

Calculate the weight of the pig using the formula F_weight = m × g, where m is the mass of the pig (130 kg) and g is the acceleration due to gravity (9.8 m/s^2).Calculate the force of friction using the formula F_friction = μs × F_normal, where μs is the static coefficient of friction (0.80) and F_normal is the normal force (weight of the pig).Subtract the force of friction from the maximum force the farmer can exert to find the force required to budge the pig.

The force required to budge the pig is approximately 520 N.

Which kelvin temperature is equivalent to â24°c?

Answers

0 degrees Celsius is equal to 273.15 degrees Kelvin:
0 °C = 273.15 K.
The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius (°C) plus 273.15:
T(K) = T(°C) + 273.15.

Bernoulli's principle describes the property of a(n) _________.

Answers

Final answer:

Bernoulli's principle describes the relationship between pressure and velocity in fluids and is applicable in various fluid flow situations.

Explanation:

Bernoulli's principle describes the property of a fluid where there is an inverse relationship between the pressure and velocity of the fluid. According to Bernoulli's equation, for an incompressible, frictionless fluid, the sum of pressure, kinetic energy, and potential energy per unit volume is constant. This principle is applicable in various situations involving fluid flow, such as in the analysis of fluid devices and systems.

Bernoulli's principle serves as a fundamental concept in fluid dynamics, providing insights into the interplay between pressure and velocity within a flowing fluid. Its application extends to understanding phenomena like lift in aviation, the operation of carburetors, and the behavior of blood flow in arteries. By recognizing the conservation of energy in fluid motion, Bernoulli's principle contributes to the analysis and design of fluid-based systems across diverse fields.

A horizontal force of 30 n pulls a block of mass 2.5 kg across a level floor. the coefficient of kinetic friction between the block and the floor is μk = 0.25. if the block begins with a speed of 7.0 m/s and is pulled for a distance of 14 m, what is the final speed of the block?

Answers

We want to find vf. We're given vi and d. An equation that incorporates all these variables is:

vf^2 = vi^2 + 2ad

You'll notice we're missing an acceleration, a. However, we can figure this out using the rest of the information given in the question. We know the acceleration is going to be related to the net force, F(net), give by F(net) = ma. The net force is going to be the combination of the applied force and the frictional force; in other words:

F(net) = F(app) - f
ma = F(app) - umg
2.5a = 30 - 0.25(2.5)(9.8)
a = 9.6 m/s^2

Now we can plug this value into the original equation:

vf^2 = vi^2 + 2ad
vf^2 = 7^2 + 2(9.6)(14)
vf = 17.8 m/s

The final speed is approximately 17.79 m/s. The final speed of the block is determined by calculating the net force and resulting acceleration, then using kinematic equations.

Final Speed of the Block

To determine the final speed of the block, we first need to calculate the net force acting on the block. Given:

Horizontal force (F) = 30 NMass of the block (m) = 2.5 kgInitial speed [tex](v_0) = 7.0 m/s[/tex]Coefficient of kinetic friction [tex](\mu_k) = 0.25[/tex]Distance (d) = 14 m

The force of kinetic friction (Ffriction) is calculated as:

[tex]F_{friction} = \mu_k \times N[/tex]

Where N is the normal force, and on a level floor N = mg:

[tex]N = m \times g = 2.5 kg \times 9.8 m/s^2 = 24.5 N[/tex]

Thus, the force of friction:

[tex]F_{friction} = 0.25 \times 24.5 N = 6.125 N[/tex]

The net force (F_{net}) acting on the block is:

[tex]F_{net} = F - F_{friction} = 30 N - 6.125 N = 23.875 N[/tex]

Using Newton's second law (F = ma) to find acceleration (a):

[tex]a = F_{net} / m = 23.875 N / 2.5 kg = 9.55 m/s^2[/tex]

We use the kinematic equation to find the final speed (v):

[tex]v^2 = v_0^2 + 2ad\\v = \sqrt{((7.0 m/s)^2 + 2 \times 9.55 m/s^2 \times 14 m)} = \sqrt{(49 + 267.4)} = \sqrt{(316.4)} = 17.79 m/s[/tex]

Therefore, the final speed of the block is approximately 17.79 m/s.

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