ANSWER
[tex]p = - 2[/tex]
EXPLANATION
The given equation is
[tex]x = - \frac{1}{8}{y}^{2} [/tex]
Multiply both sides by -8
[tex] \implies \: {y}^{2} = - 8x[/tex]
We now compare this to the general equation of the parabola:
[tex] {y}^{2} = 4px[/tex]
This implies that,
[tex]4p = - 8[/tex]
Divide both sides by 4.
[tex]p = \frac{ - 8}{4} [/tex]
[tex]p = - 2[/tex]
HELP ASAP PLEASE!!!
If f(x)=5x-1, What is f^-1 (f(2))?
A. 44
B. -2
C. -44
D. 2
Answer:
(D) 2
Step-by-step explanation:
f(x) = 5x - 1
y = 5x - 1
5x = y + 1
x = (y + 1)/5
f⁻¹ (x) = (x + 1)/5
f(x) = 5x - 1
f(2) = 5(2) - 1
f(2) = 9
f⁻¹ (x) = (x + 1)/5
f⁻¹ (f(2)) = (9 + 1)/5
f⁻¹ (f(2)) = 2
HELP PLEASE IM GIVING 50 BRAINLY POINTS!!!
According to Cavalieri’s Principle, which two solids would have congruent volumes?
A .a cone and a cylinder with equal base areas and heights
B. a cone and pyramid with equal base areas and heights
C. a cone and a rectangular prism with equal base areas and heights
D. a cylinder and a sphere with equal radii
The correct options for the Cavalieri's Principle are A and B, where the cone is paired with either a cylinder or a pyramid, both having equal base areas and heights.
Given Cavalieri's Principle which states that if two solids have the same height and cross-sectional area at every level (parallel cross-sections), then they have equal volumes.
To determine two solids would have congruent volumes,
A. A cone and a cylinder with equal base areas and heights would satisfy Cavalieri's Principle because they would have equal cross-sectional areas at every level.
B. A cone and a pyramid with equal base areas and heights would also satisfy Cavalieri's Principle.
A cone and a rectangular prism with equal base areas and heights would NOT satisfy Cavalieri's Principle because their cross-sectional areas would be different at different levels.
Also, cylinder and a sphere with equal radii would NOT satisfy Cavalieri's Principle because their cross-sectional areas would be different at different levels.
So, the correct answer is either A (cone and cylinder) or B (cone and pyramid).
What percentage of the data values represented on a box plot falls between the minimum value and the lower quartile?
Answer:
first 25%
Step-by-step explanation:
A quartile is a quarter, so the first 25% falls between the minimum and lower quartile
Answer:
A. 25%
Step-by-step explanation:
Because it asks you where one section to another section (on a box plot there are four areas containing 25% within each one.)
At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the numbers 1, 2, and 3.
What is the sample space of spinning the two wheels?
Answer:
12 possible outcomes.
Sample space:
[tex]\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}[/tex]
Step-by-step explanation:
The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.
1. There are four possible outcomes for the first wheel: F, A, I and R
2. There are three possible outcomes for the second wheel: 1, 2 and 3
So, the sample space is
[tex]\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}[/tex]
Andrew drove from his house to his sister's house in 8 hours at an average of 60 miles per hour. On the way home he drove at an average rate of 64 miles per hour. How long did it take him to drive home?
Answer:
288
Step -by-step explanation:I'm not explaining :D
Answer:
It took him 7.5 hrs to drive home.
Step-by-step explanation:
The distance is the same, going or returning.
Recall that distance = rate times time.
Here, distance from Andrew's to his sister's is (60 mph)(8 hr) = 480 mi
If distance = rate times time, then time = distance / rate.
Here we have time = 480 mi / 64 mph = 7.5 hrs
It took him 7.5 hrs to drive home.
Write the standard equation of the circle shown.
Answer:
b
Step-by-step explanation:
The equation of a circle centred at the origin is
x² + y² = r² ← r is the radius
The circle shown is centred at the origin and has a radius of 5, thus
x² + y² = 5² ⇒ x² + y² = 25 → b
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles.
B = 49°, a = 16, b = 14
The answer is:
The first triangle is:
[tex]A=59.6\°\\C=71.4\°\\c=17.6units[/tex]
The second triangle is:
[tex]A=120.4\°\\C=10.6\°\\c=3.41units[/tex]
Why?To solve the triangles, we must remember the Law of Sines form.
Law of Sines can be expressed by the following relationship:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}[/tex]
Where,
a, b, and c are sides of the triangle
A, B, and C are angles of the triangle.
We are given,
[tex]B=49\°\\a=16\\b=14[/tex]
So, solving the triangles, we have:
- First Triangle:Finding A, we have:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}\\\\Sin(A)=a*\frac{Sin(B)}{b}=16*\frac{Sin(49\°)}{14}\\\\Sin^{-1}(Sin(A)=Sin^{-1}(16*\frac{Sin(49\°)}{14})\\\\A=59.6\°[/tex]
Finding C, we have:
Now, if the sum of all the interior angles of a triangle is equal to 180°, we have:
[tex]A+B+C=180\°\\\\C=180-A-B\\\\C=180\°-59.6\°-49\°=71.4\°[/tex]
Finding c, we have:
Then, now that we know C, we need to look for "c":
[tex]\frac{14}{Sin(49\°)}=\frac{c}{Sin(71.4\°)}\\\\c=\frac{14}{Sin(49\°)}*Sin(71.4\°)=17.58=17.6units[/tex]
So, the first triangle is:
[tex]A=59.6\°\\C=71.4\°\\c=17.6units[/tex]
- Second Triangle:Finding A, we have:
[tex]\frac{a}{Sin(A)}=\frac{b}{Sin(B)}\\\\Sin(A)=a*\frac{Sin(B)}{b}=16*\frac{Sin(49\°)}{14}\\\\Sin^{-1}(Sin(A)=Sin^{-1}(16*\frac{Sin(49\°)}{14})\\\\A=59.6\°[/tex]
Now, since that there are two triangles that can be formed, (angle and its suplementary angle) there are two possible values for A, and we have:
[tex]A=180\°-59.6\°=120.4\°[/tex]
Finding C, we have:
Then, if the sum of all the interior angles of a triangle is equal to 180°, we have:
[tex]A+B+C=180\°\\\\C=180\°-A-B\\\\C=180\°-120.4\°-49\°=10.6\°[/tex]
Then, now that we know C, we need to look for "c".
Finding c, we have:
[tex]\frac{14}{Sin(49\°)}=\frac{c}{Sin(10.6)}\\\\c=\frac{14}{Sin(49)\°}*Sin(10.6\°)=3.41units[/tex]
so, The second triangle is:
[tex]A=120.4\°\\C=10.6\°\\c=3.41units[/tex]
Have a nice day!
Please help me out....
Answer:
x = 6
Step-by-step explanation:
Given that the line segment is an angle bisector then the following ratios are equal
[tex]\frac{42}{78}[/tex] = [tex]\frac{6x-1}{10x+5}[/tex], that is
[tex]\frac{7}{13}[/tex] = [tex]\frac{6x-1}{10x+5}[/tex] ( cross- multiply )
13(6x - 1) = 7(10x +5) ← distribute parenthesis on both sides
78x - 13 = 70x + 35 ( subtract 70x from both sides )
8x - 13 = 35 ( add 13 to both sides )
8x = 48 ( divide both sides by 8 )
x = 6
scientists are studying the temperature on a distant planet. they find that the surface temperature at one location is 45 Celsius. they also find that the temperature decreases by 7 Celsius for each kilometer you go up from the surface.
let T represent the temperature (in Celsius), and let H be the height above the surface (in kilometers). write an equation relating T to H, and then graph your equation using the axes.
Final Answer:
The equation[tex]\(T = 45 - 7H\)[/tex] represents the relationship between temperature (T) and height above the surface (H) on the distant planet, where the surface temperature is 45 Celsius, decreasing by 7 Celsius for each kilometer of height. Graphing this equation reveals a linear line with a negative slope, portraying the systematic decrease in temperature as one moves higher above the planet's surface.
Explanation:
The equation [tex]\(T = 45 - 7H\)[/tex] is derived from the given information about the distant planet's temperature. The surface temperature is 45 Celsius, and for each kilometer above the surface (represented by H), the temperature decreases by 7 Celsius.
The equation reflects this linear relationship. The term 45 is the starting temperature at the surface, and the term -7H represents the decrease for each kilometer above.
For example, let's substitute H = 1 into the equation to find the temperature at a height of 1 kilometer:
[tex]\[ T = 45 - 7(1) = 45 - 7 = 38 \][/tex]
This calculation shows that at a height of 1 kilometer, the temperature is 38 Celsius. Similarly, for H = 2:
[tex]\[ T = 45 - 7(2) = 45 - 14 = 31 \][/tex]
This process can be repeated for different values of H to create a set of coordinates (H, T) that form a linear relationship. Graphing these points produces a straight line with a negative slope, illustrating the temperature decrease with increasing height.
In essence, the detailed calculation demonstrates how the equation captures the specified temperature-height relationship on the distant planet. It provides a mathematical representation of the observed data and allows scientists to predict temperatures at various heights above the surface.
Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1 squared divided by 64 equals 1.
Vertices: (-1, 3), (-1, -13); Foci: (-1, -13), (-1, 3)
Vertices: (3, -1), (-13, -1); Foci: (-13, -1), (3, -1)
Vertices: (-1, 1), (-1, -11); Foci: (-1, -15), (-1, 5)
Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
Answer:
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
Step-by-step explanation:
Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.
a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;
Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)
Answer:
Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
Step-by-step explanation:
Ok so we have 5x[tex]\frac{5x^{2} }{36}-\frac{y^{2} }{64}=1[/tex]
As you know we have the equation of the hyperbola as (x-h)^2/a^2-(y-k)^2/b^2, so the formula of the foci is [tex](h+-c,k) and for vertices (h+-a,k)[/tex]
then we have to calculate c using pythagoras theorem we have that
a=6 because is the root of 36
b=8 beacause is the root of 64
And then we have that [tex]c^{2}=a^{2}+b^{2}[/tex]
[tex]c=\sqrt{36+64}[/tex]
So the root of 100 is equal to 10
Hence c=10
Using the formula given before and the equation we know that
h=-5
k=-1
And replacing those values on the equation we have that the foci are
(-5-10, -1)=(-15,-1)(-5+10,1)=(5,-1)And the vertices are:
(-5-6, -1)=(-11,-1)(-5+6, 1)= (1,-1)So the correct answer is D
Can someone please help with this question it’s confusing me
The answer might be 2.66
Answer:
0.5
Step-by-step explanation:
12 is the total amount of bags
(2*1/6+ 2*1/3 + 3*1/2 + 4*2/3 + 1*5/6 ) / 12 =
[1/3 + 2/3 + 3/2 + 8/3 + 5/6]/12 = [(1+2+8)/3 + (3*3+5)/6 ]/12 =
(11/3+14/6)/5 = [(22+14)/6 ]/12 = (36/6) /5 = 6/12=0.5
help plsssssssssssssssssssssssssssssss
Answer:
[tex]t\le 4[/tex]
Step-by-step explanation:
Let t hours be the number of hours needed to rent the room. If one hour costs $8.30, then t hours cost $8.30t. The reservation fee is $34, so the total cost is
[tex]\$(34+8.30t).[/tex]
The history club wants to spend $67.20, thus
[tex]34+8.30t\le67.20\\ \\8.30t\le 67.20-34\\ \\8.30t\le 33.20\\ \\t\le \dfrac{33.20}{8.30}=\dfrac{332}{83}=4[/tex]
The maximum possible whole number of hours is 4 hours.
1) Find f(x) if it is known that f(5a)=5a−2.
2) Find g(x) if it is known that g(2t)=8t−1.
Answer:
Step-by-step explanation:
One
f(5a) means that wherever you see an x, you put in 5a
x = 5a
f(x) = x/5t * 5t - 2
f(x) = x - 2
===============
Two
g(2t) = 8t - 1
x = 2t
g(x) = 8t/2t*x - 1
g(x) = 4x - 1
1)for the first one you can put a=(1/5)a in the function and it will be:
[tex]f(a) = a - 2[/tex]
so in a function , alphabet is not important and you can rewrite it to this:
[tex]f(x) = x - 2[/tex]
2)the same as the first , we can put t=(1/2)t and conclusion is :
[tex]g(t) = 4t - 1[/tex]
and then change the t to x:
[tex]g(x) = 4x - 1[/tex]
Lionel needs money quite frequently and doesn't need much interest at all. Which of these options for saving money is best for him?
A. savings bond
B. money market account
C. certificate of deposit
D. savings account
Answer: Savings account - Apex
Answer:
Option D is the correct answer.
Step-by-step explanation:
The saving bonds are a good way to earn money but they work at fixed rate of interest over a set time period.
Money market accounts give a limited access to account and not more than three checks are written in a month. Its a type of short term savings.
The certificate of deposit or CD's have higher interest rate than savings account. But one cannot withdraw the money before the term maturity otherwise penalty is to be paid.
Savings account are deposit accounts that can be accessed whenever needed. These yield less interest as compared to money market accounts or CD's.
Therefore, the best option for Lionel to choose will be Savings account
PLEASE HELP FAST!
A marble is selected from a bag containing eight marbles numbered 1 to 8.
The number on the marble selected will be recorded as the outcome.
Consider the following events.
Event A: The marble selected has an even number.
Event B: The marble selected has a number from 3 to 6.
Give the outcomes for each of the following events.
If there is more than one element in the set, separate them with commas.
Answer:
A and B: {4, 6}
A or B: {2, 3, 4, 5, 6, 8}
Complement of B: {1, 2, 7, 8}
Step-by-step explanation:
A and B refer to the elements that are in both A and B at the same time
The even numbers from 1 to 8 are {2, 4, 6, 8}
The numbers from 3 to 6 are {3, 4, 5, 6}
Look for the common elements between both sets.
A and B: {4, 6}
A or B is the union of the two sets
Join the elements of both sets
A or B: {2, 3, 4, 5, 6, 8}
The complement of B are all the elements that are not in B.
Write all the elements of the sample space except those of event B
Complement of B: {1, 2, 7, 8}
Event A: 2, 4, 6, 8; Event B: 3, 4, 5, 6.
Explanation:In probability theory, events are outcomes or sets of outcomes from a random experiment. They are subsets of the sample space, representing possible results. Simple events consist of a single outcome, while compound events involve more than one outcome. Probability measures the likelihood of events occurring.
Event A consists of the even numbers 2, 4, 6, and 8.
Event B consists of the numbers 3, 4, 5, and 6.
The outcomes for Event A are 2, 4, 6, and 8.
The outcomes for Event B are 3, 4, 5, and 6.
Learn more about marble selection here:https://brainly.com/question/16661450
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PLEASE Explain how to prove one of the following: In an isosceles trapezoid, how do you prove the base angles are congruent or in a kite the long diagonal of a kite is a perpendicular bisector to the short diagonal, how can you prove that adjacent sides are congruent in a kite?
Final answer:
Adjacent sides in a kite are congruent, which can be proven using the definition of a kite, the Reflexive Property of Equality, and the SAS Postulate to show that the two triangles formed by the diagonal are congruent.
Explanation:
To prove that adjacent sides are congruent in a kite, recall the definition of a kite: a quadrilateral with two distinct pairs of adjacent sides that are congruent. Let's name the kite ABCD where AB and AD are one pair of congruent sides, and BC and DC are the other pair. The longer diagonal, which we'll call AC, bisects the kite into two congruent triangles, ∆ABC and ∆ADC. By the definition of a kite, we know that AB = AD and BC = DC.
Now, since AC is the common side in both ∆ABC and ∆ADC, by the Reflexive Property of Equality, AC = AC. With two sides and the included angle (BAC and DAC are congruent as they are both angles cut by diagonal AC) congruent in both triangles, we apply the SAS Postulate (Side-Angle-Side) to prove that the triangles are congruent. Once the triangles are proven congruent, all their corresponding parts are congruent. Therefore, AB = AD and BC = CD, which means the adjacent sides in the kite are indeed congruent.
A rectangle measures 3 inches by 4 inches. If the lengths of each side double,what will its area be
6x8= 48 inches
3 doubled=6
4 doubled=8
What is the solution to the system of equations?
x+y+3z=-4
2x-z=-3
-x-y-2z=5
a. (-1, -6, 1)
b. (1, -6, 1)
c. (-1, 6, 1)
d. (-1, -6, -1)
Answer:
a
Step-by-step explanation:
Let's use the elimination method on equations 1 and 3 and see what happens:
x + y + 3z = -4
-x - y - 2z = 5
It looks like both the x terms and the y terms cancel out leaving us with the fact that z = 1.
Let's go back to the second equation now and sub in a 1 for z:
2x - z = -3 implies 2x - 1 = -3 and x = -1.
Pick any equation now to sub in the known values to find y. I chose the first one, just because:
x + y + 3z = -4 implies -1 + y + 3(1) = -4 and
-1 + y + 3 = -4 so
y + 2 = -4 and
y = -6
So the solution set is (-1, -6, 1)
Use technology or a z-score table to answer the question.
Scores on a standardized military exam are normally distributed with a mean of 57 and a standard deviation of 9. Consider a group of 4000 military students.
Approximately how many students will score less than 66 on the test?
A. 200
B. 634
C. 3366
D. 3800
Answer:
C
Step-by-step explanation:
Finding the z-score:
z = (x - μ) / σ
z = (66 - 57) / 9
z = 1
Using a z-score table or calculator:
P(z < 1) = 0.8413
84.13% of 4000 is:
0.8413 (4000) = 3365.2
Rounding up to the nearest whole number, approximately 3366 students will score less than 66. Answer C.
Using the normal distribution, it is found that approximately 3366 students will score less than 66 on the test.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.In this problem, the mean and the standard deviation are given as follows:
[tex]\mu = 57, \sigma = 9[/tex]
The proportion of students that scored less than 66 is the p-value of Z when X = 66, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{66 - 57}{9}[/tex]
Z = 1
Z = 1 has a p-value of 0.8413.
Out of 4000 students:
0.8413 x 4000 = 3366, which means that option C is correct.
More can be learned about the normal distribution at https://brainly.com/question/24663213
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during the first years of growth the height of a tree can be modeled with the function h=-t^2 +12t+10 where t is the time in years since being planted and h is the height in inches. Enter the average rate cof change, in inches per year, from year 1 to year 5.
ANSWER
6 inches
EXPLANATION
The given function is
[tex]h(t) = - {t}^{2} + 12t + 10[/tex]
The average rate of change from t=1 to t=5 is given by:
[tex] = \frac{h(5) - h(1)}{5 - 1} [/tex]
[tex]h(5) = - {(5)}^{2} + 12(5) + 10[/tex]
[tex]h(5) = - 25 + 60+ 10[/tex]
[tex]h(5) = 45[/tex]
Also,
[tex]h(1) = - {(1)}^{2} + 12(1) + 10[/tex]
[tex]h(1) = - 1+ 12+ 10[/tex]
[tex]h(1) = 21[/tex]
The average rate of change is now
[tex] = \frac{45 - 21}{4} [/tex]
[tex] = \frac{24}{4} [/tex]
[tex] = 6[/tex]
Convert 17π/8 to degrees.
Answer:
382.5°
Step-by-step explanation:
Multiply
17π 180°
------ by the conversion factor ------------
8 π
obtaining:
(17)(180)°
------------- = 382.5°
8
If you park 3 levels below the lobby floor of a hotel and take the elevator to the 15th floor, how many floors apart are you from your vehicle? Floors
I think 18 because 3+15=18
Answer:
I think it's 12
Step-by-step explanation:
15-3=12
Given the value of cos 50° ? 0.6428, enter the sine of a complementary angle. Use an expression relating trigonometric ratios of complementary angles.
ANSWER
[tex]\sin(40) \degree = 0.6428[/tex]
EXPLANATION
The sine and cosine ratios are complementary.
This means that:
[tex] \cos(x \degree) = \sin(90 - x) \degree[/tex]
We were given that,
cos(50°)=0.6428
We want to find the sine of the complement of this angle.
[tex] \cos(50\degree) = \sin(90 -5 0) \degree[/tex]
[tex]\cos(50\degree) = \sin(40) \degree[/tex]
This implies that,
[tex] \sin(40) \degree = 0.6428[/tex]
The graph shows the number of paintballs a machine launches, y, in x seconds:
A graph titled Rate of Launch is shown. The x axis label is Time in seconds, and the x axis values are from 0 to 10 in increments of 2 for each grid line. The y axis label is Number of Balls, and the y axis values from 0 to 60 in increments of 12 for each grid line. A line is shown connecting points on ordered pair 2, 12 and 4, 24 and 6, 36 and 8, 48.
Which expression can be used to calculate the rate per second at which the machine launches the balls?
A.) 2/12
B.) 12/2
C.) 2/48
D.) 48/2
Answer:
Option B.) 12/2
Step-by-step explanation:
we know that
The rate of a linear equation is equal to the slope m
The slope is equal to
points (2,12) and (4,24)
m=(24-12)/(4-2)
m=12/2
m=6 balls/sec
Rico's backpack weighed 3.6 pounds. Then he added his school books which weighed an additional 24.76 pounds. How much did Rico's backpack weigh with his school books?
Answer:
The answer should be 28.36
Step-by-step explanation:
You add them together
Hope this helps!
Answer:
28.36
Step-by-step explanation:
3.6 + 24.7 = 28.36
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
The number of unshelled peanuts in a 1 lb container is normally distributed with a mean of 375 peanuts and a standard deviation of 24 peanuts.
Suppose 4000 different 1 lb containers are in a warehouse.
About how many containers contain more than 447 peanuts?
Answer: a) 6
Step-by-step explanation:
The mean is 375 which has a z-score of 0.
The standard deviation is 24 so:
z-score of 1 is: 375 + 24 = 399z-score of 2 is: 399 + 24 = 423z-score of 3 is: 423 + 24 = 477A z-score of 3 is 99.85% from the left (or 1 - 99.85% from the right = 0.15%)
Since we are looking for the "more than" a z-score of 3, it is 0.15% of the total.
4000
× 0.0015
6.0000
The function, f(t)= 1.2 cos 0.5t, does not have an amplitude and has a period of 4π.
Answer:
False
Step-by-step explanation:
Given in the question a function,
f(t)=1.2cos0.5t
Standard form of cosine function is
f(t)=acos(bt)
Amplitude is given by = |a|
Period of function is given by = 2π/b
So the amplitude is |1.2| = 1.2
the period is 2π/0.5 = 4π
Answer:
False
Step-by-step explanation:
The given function is
[tex]f(t)=1.2\cos 0.5t[/tex]
This function is of the form:
[tex]f(t)=A\cos(Bt)[/tex]
where A=1.2 and B=0.5
The amplitude of this function is given by;
|A|=|1.2|=1.2
The period of this function is given by;
[tex]T=\frac{2\pi}{|B|}[/tex]
[tex]T=\frac{2\pi}{|0.5|}[/tex]
[tex]T=\frac{2\pi}{0.5}=4\pi[/tex]
The correct answer is False
Amy has 3 children, and she is expecting another baby soon. Her first three children are girls. Is the sex of the fourth baby dependent or independent of the first three?
A) Independent. With every child, there is a 50% chance of having a boy or girl.
Eliminate
B) Dependent. Amy has not had a boy yet, so her chance of having a boy is greater.
C) Dependent. Every time Amy has a baby, the chances of having another girl increase.
D) Independent. Only the mom and dad determine the sex of that baby, not the siblings.
Answer:
I would say D.) is the best choice in this situation, The amount of female children you have does not determine the Gender that your child will be, The kids have nothing to do with the situation, The Father and Mother are what determine the Gender.
Answer:
Option A is right
Step-by-step explanation:
Given that Amy has 3 children, and she is expecting another baby soon. Her first three children are girls.
The fourth baby is independent of first three babies
As regards child birth, each trial is independent of the other with probability for a girl or boy equally likely with p = 0.5 = q
Hence option A is right answer.
Option B is wrong because the previous 3 girls have nothing to affect the sex of 4th child
Option C is wrong, since each trial is independent
D) is wrong since even mom and dad cannot determine the sex of that baby, it is nature and pure chance.
simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
Answer:
The simplest form is x/(x + 3)
Step-by-step explanation:
* To simplify the rational Expression lets revise the factorization
of the quadratic expression
* To factor a quadratic in the form x² ± bx ± c:
- First look at the c term
# If the c term is a positive number, and its factors are r and s they
will have the same sign and their sum is b.
# If the c term is a negative number, then either r or s will be negative
but not both and their difference is b.
- Second look at the b term.
# If the c term is positive and the b term is positive, then both r and
s are positive.
Ex: x² + 5x + 6 = (x + 3)(x + 2)
# If the c term is positive and the b term is negative, then both r and s
are negative.
Ex: x² - 5x + 6 = (x -3)(x - 2)
# If the c term is negative and the b term is positive, then the factor
that is positive will have the greater absolute value. That is, if
|r| > |s|, then r is positive and s is negative.
Ex: x² + 5x - 6 = (x + 6)(x - 1)
# If the c term is negative and the b term is negative, then the factor
that is negative will have the greater absolute value. That is, if
|r| > |s|, then r is negative and s is positive.
Ex: x² - 5x - 6 = (x - 6)(x + 1)
* Now lets solve the problem
- We have two fractions over each other
- Lets simplify the numerator
∵ The numerator is [tex]\frac{x+2}{x^{2}+2x-3}[/tex]
- Factorize its denominator
∵ The denominator = x² + 2x - 3
- The last term is negative then the two brackets have different signs
∵ 3 = 3 × 1
∵ 3 - 1 = 2
∵ The middle term is +ve
∴ -3 = 3 × -1 ⇒ the greatest is +ve
∴ x² + 2x - 3 = (x + 3)(x - 1)
∴ The numerator = [tex]\frac{(x+2)}{(x+3)(x-2)}[/tex]
- Lets simplify the denominator
∵ The denominator is [tex]\frac{x+2}{x^{2}-x}[/tex]
- Factorize its denominator
∵ The denominator = x² - 2x
- Take x as a common factor and divide each term by x
∵ x² ÷ x = x
∵ -x ÷ x = -1
∴ x² - 2x = x(x - 1)
∴ The denominator = [tex]\frac{(x+2)}{x(x-1)}[/tex]
* Now lets write the fraction as a division
∴ The fraction = [tex]\frac{x+2}{(x+3)(x-1)}[/tex] ÷ [tex]\frac{x+2}{x(x-1)}[/tex]
- Change the sign of division and reverse the fraction after it
∴ The fraction = [tex]\frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}[/tex]
* Now we can cancel the bracket (x + 2) up with same bracket down
and cancel bracket (x - 1) up with same bracket down
∴ The simplest form = [tex]\frac{x}{x+3}[/tex]
ANSWER
[tex]\frac{x}{x + 3}[/tex]
EXPLANATION
We want to simplify:
[tex] \frac{x +2 }{ {x}^{2} + 2x - 3} \div \frac{x + 2}{ {x}^{2}- x} [/tex]
Multiply by the reciprocal of the second fraction:
[tex] \frac{x +2 }{ {x}^{2} + 2x - 3} \times \frac{{x}^{2}- x}{ x + 2} [/tex]
Factor;
[tex] \frac{x +2 }{ (x + 3)(x - 1)} \times \frac{x(x - 1)}{ x + 2} [/tex]
We cancel out the common factors to get:
[tex] \frac{x}{x + 3} [/tex]
Suppose a sample mean is distributed normally. if the sample size increases, what happens to the shape of the sampling distribution of the sample mean?
a. distribution becomes wider and flatter.
b. distribution becomes narrower and taller.
c. distribution remains the same.
d. distribution turns upside down and inside ou
Answer:
(b)
Step-by-step explanation:
(b) is correct: the distribution becomes narrower and taller.