what is the total number of moles present in a 526.0-gram sample of NaNCO3(s)?

Answer:

The correct answer is B:  125 Nm

Explanation:

If an applied force causes rotation from upward to downward direction than the torque is clockwise and is called as negative clockwise torque. Minus sign represents the direction of the torque. SI unit of torque is Nm.

Given data:  

Force = 25 N

r = 5.0 m

Formula:

Torque = r x F

          = 5.0 m X 25 N

          = 125 Nm  

The clockwise torque is 125 Nm ( i.e -125 Nm. Here minus sign suggests that the torque is clockwise)

Answer:

125 Nm

Explanation:

What is the clockwise torque on the following lever?

5.0 Nm

125 Nm

250 Nm

0.0 Nm

Answer:

26.3°C.

Explanation:

Q = m.c.ΔT,

where, Q is the amount of heat absorbed by copper (Q = 1000 J).

m is the mass of the copper (m 2000 g).

c is the specific heat of copper (c = 0.385 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 25°C).

∵ Q = m.c.ΔT

∴ (1000 J) = (2000 g)(0.385 J/°C.g)(final T - 25°C)

∴ (final T - 25°C) = (1000 J)/(2000 g)(0.385 J/°C.g) = 1.299.

∴ final T = 25°C + 1.299 = 26.299°C ≅ 26.3°C.

Final answer:

There are approximately 5.045 x 10^24 molecules in 385.55g of NO2. This is calculated by first determining the number of moles in the given mass using its molar mass and then multiplying by Avogadro's number.

Explanation:

To calculate the number of molecules in 385.55g of NO2, we first need to determine the number of moles of NO2 in the given mass. The molar mass of nitrogen dioxide, NO2, is calculated as follows:

M(NO2) = 14 +(2)(16) = 46 g/mol

Then, we use the molar mass to convert grams to moles:

Number of moles of NO2 = mass (g) / molar mass (g/mol)

= 385.55g / 46 g/mol

= 8.381 mol of NO2

Afterward, we use Avogadro's number, which is 6.022 x 1023 molecules per mole, to find the total number of molecules:

Number of molecules = Number of moles × Avogadro's number

= 8.381 mol × 6.022 x 1023 molecules/mol

≈ 5.045 x 1024 molecules of NO2

Answer:

7

Explanation:

divide 35 by 5 and you get 7

or do inverse operation 7 x 5 = 35

Answer:

[tex]\boxed{\text{7 m/s}}[/tex]

Explanation:

The formula for average speed is  

[tex]\text{speed} = \dfrac{\text{distance}}{\text{time}}\\\\s = \dfrac{d}{t}[/tex]

Data:

d = 35 m

t =   5 s

Calculation:

[tex]s = \dfrac{\text{35 m}}{\text{5 s}} = \text{7 m/s}[/tex]

The average speed of the ball is [tex]\boxed{\textbf{7 m/s}}[/tex]

Answer:

1s22s22p63s1 is the electronic configuration of sodium.

Explanation:

There are 11 electrons in Sodium ( find this on the periodic table).

Then you need to arrange the electrons in the orbitals around the nucleus.

The structure would be written as A. 1s^22s^22p^63s^1

The answer is:

the molarity = 50 moles/liters

The explanation:

when the molarity is = the number of moles / volume per liters.

and when the number of moles =2.5 moles

and the volume per liters = 0.05 L

so by substitution:

the molarity = 2.5moles/0.05L

                    = 50 moles /L

MARK ME BRAINLIEST PLEASE!!!!!

Answer:

12.07 g.

Explanation:

2NH₃(g) + CO₂(g) → H₂NCONH₂(g) + H₂O(g),

It is clear that 2.0 moles of NH₃ react with 1.0 mole of CO₂ to produce 1.0 mole of H₂NCONH₂ and 1.0 moles of H₂O.

At STP, 9.0 L of NH₃ react with an excess of CO₂ gas:

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

using cross multiplication:

1.0 mol of NH₃ represents → 22.4 L.

??? mol of NH₃ represents → 9.0 L.

∴ 9.0 L of NH₃ represents = (1.0 mol)(9.0 L)/(22.4 L) = 0.4018 mol.

Using cross multiplication:

2.0 mol of NH₃ produce → 1.0 mol of H₂NCONH₂, from stichiometry.

0.4018 mol of NH₃ produce → ??? mol of H₂NCONH₂.

∴ The no. of moles of H₂NCONH₂ = (1.0 mol)(0.4018 mol)/(2.0 mol) = 0.201 mol.

mass = n * molar mass = (0.201 mol) * (60.06 g/mol) = 12.07 g.

The mass of urea produced from 9.0 litres of ammonia is 12.227 grams.

To solve this problem, we need to follow these steps:

1. Write down the balanced chemical equation:

[tex]\[ 2NH_3(g) + CO_2(g) \rightarrow H_2NCONH_2(g) + H_2O(g) \][/tex]

2. Calculate the molar mass of ammonia[tex](\( NH_3 \))[/tex]:

- The atomic mass of nitrogen (N) is approximately 14.01 g/mol.

- The atomic mass of hydrogen (H) is approximately 1.008 g/mol.

- Since there are 3 hydrogen atoms in ammonia, the total atomic mass for hydrogen is ([tex]\( 3 \times 1.008 \)[/tex]) g/mol.

- The molar mass of ammonia is  [tex]\( 14.01 + (3 \times 1.008) \)[/tex]  g/mol.

3. Convert the volume of ammonia to moles:

- The density of ammonia gas at standard conditions is approximately 0.771 g/L.

- Convert the volume of ammonia from litres to grams using the density.

- Then, convert grams of ammonia to moles using the molar mass calculated in step 2.

4. Use the stoichiometry of the balanced equation to find the moles of urea[tex](\( H_2NCONH_2 \))[/tex]produced:

- According to the balanced equation, 2 moles of ammonia produce 1 mole of urea.

- Therefore, the moles of urea produced will be half the moles of ammonia.

5. Calculate the molar mass of urea [tex](\( H_2NCONH_2 \))[/tex]:

- The molar mass of urea can be calculated by adding the atomic masses of the constituent atoms.

- Urea consists of 2 nitrogen atoms, 4 hydrogen atoms, 1 carbon atom, and 1 oxygen atom.

6. Convert the moles of urea to grams:

- Multiply the moles of urea by its molar mass to get the mass in grams.

Now, let's perform the calculations:

1. Molar mass of [tex]\( NH_3 \):[/tex]

[tex]\[ \text{Molar mass of } NH_3 = 14.01 + (3 \times 1.008) = 17.034 \text{ g/mol} \][/tex]

2. Mass of 9.0 liters of ammonia:

[tex]\[ \text{Mass of } NH_3 = 9.0 \text{ L} \times 0.771 \text{ g/L} = 6.939 \text{ g} \][/tex]

3. Moles of ammonia:

[tex]\[ \text{Moles of } NH_3 = \frac{6.939 \text{ g}}{17.034 \text{ g/mol}} \approx 0.4073 \text{ mol} \][/tex]

4. Moles of urea produced:

[tex]\[ \text{Moles of urea} = \frac{0.4073 \text{ mol}}{2} \approx 0.20365 \text{ mol} \][/tex]

5. Molar mass of urea[tex](\( H_2NCONH_2 \))[/tex]:

[tex]\[ \text{Molar mass of urea} = 2 \times 14.01 + 4 \times 1.008 + 12.01 + 16.00 = 60.062 \text{ g/mol} \][/tex]

6. Mass of urea produced:

[tex]\[ \text{Mass of urea} = 0.20365 \text{ mol} \times 60.062 \text{ g/mol} \approx 12.227 \text{ g} \][/tex]

 Therefore, the mass of urea produced from 9.0 litres of ammonia is approximately 12.227 grams.

 The correct answer is [tex]\boxed{12.227 \text{ g}}.[/tex]

The complete question is:

What mass of urea is produced from 9.0 litres of ammonia?

The given reaction is  [tex]2NH_3(g) + CO_2(g) = H_2NCONH_2(g) + H_2O(g)[/tex]

Answer:

chemical and nuclear reaction

Explanation:

Answer: Option (D) is the correct answer.

Explanation:

A chemical reaction is defined as a reaction that involves exchange of electrons between the combining atoms. Not every chemical reaction releases or absorbs a very large amount of energy per atom.

On the other hand, a reaction that involves change in atomic nuclei of an atom either by splitting or combining of two atomic nuclei is known as a nuclear reaction.

For example, [tex]^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy[/tex]

Nuclear fission is a reaction in which a large nucleus splits by absorption of energy into two atomic nuclei. Nuclear fusion is a reaction in which two atomic nuclei combine together to result in the formation of a large atomic nuclei along with release of energy.

Each nuclear reaction releases or absorbs a very large amount of energy per atom.

Therefore, we can conclude that each nuclear reaction​ releases or absorbs a very large amount of energy per atom.  

Answer: The answer would be 131.2

Explanation: How I got my answer is quite simple. In order for it to turn into standard notation, it would need to be turned into the answer of an equation. The equation here would be "1.312 x 10^2". 10^2 would be 100. Multiply 100 by 1.312 will make the decimal point move 2 times to the right, so it will end up in front of the 2. That would make the answer 131.2

I hope this info helps! :P

Answer:

The movement of electrons creates an electric current.

Explanation:

Batteries are electrochemical cells which are devices in which chemical reactions produce an electric current, that is, devices for converting chemical energy into electrical energy.

The reactions involved here are spontaneous redox reactions hence an electric current flows on its own in the external circuit.

In such reactions, there is an electronic movement which creates a potential difference between the two electrodes thereby generating a flow of an electric current in the external circuit. The current flows in the opposite direction to the electronic movement due to chemical reactions.

The flow of the electric current results in an the production of electrical energy while the electronic movement instigates a chemical energy.

Answer:

There's no one-upping that one so I'll just tell you that it was right on my test :)

Explanation:

you're welcome

Answer: A

Explanation: Chemical changes don't change the mass. I also know that D in certainly incorrect

Answer:

Explanation:

Hope it helps.

Final answer:

The components of DNA include deoxyribose sugar molecules, adenine, phosphate molecules, cytosine, and thymine. Ribose sugar molecules and uracil are components of RNA, not DNA. DNA is constructed from nucleotides, which are the building blocks containing these components.

Explanation:

Components of DNA

DNA, or deoxyribonucleic acid, is composed of three types of molecules: deoxyribose sugar molecules, phosphate molecules, and nitrogenous bases. The nitrogenous bases in DNA are adenine, cytosine, guanine, and thymine. Therefore, the components of DNA that apply from your list are deoxyribose sugar molecules, adenine, phosphate molecules, cytosine, and thymine.

Ribose sugar molecules and uracil are not components of DNA; they are present in RNA (ribonucleic acid), which is another type of nucleic acid involved in protein synthesis and gene expression. DNA utilizes thymine as a base instead of uracil, and the sugar present in DNA is deoxyribose, which differs from ribose by lacking an oxygen atom on the second carbon.

The essential building blocks of DNA are the nucleotides, which consist of a deoxyribose sugar, a phosphate group, and one of the four nitrogenous bases (adenine, guanine, cytosine, and thymine). These nucleotides come together to form the double-helical structure of DNA, which is critical for its functions in storing and transmitting genetic information.

Answer:

[tex]\boxed{\text{3.4 g}}[/tex]

Explanation:

Step 1. Calculate the moles of C₁₂H₂₂O₁₁

[tex]\text{n = 0.100 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}}=\text{0.100 mol}[/tex]

Step 2. Calculate the mass of C₁₂H₂₂O₁₁

[tex]\text{m = 0.100 mol} \times \dfrac{\text{342.30 g}}{\text{1 mol}} = \text{3.4 g}\\\\\text{The mass of sucrose needed is }\boxed{\textbf{3.4 g}}[/tex]

Final answer:

To make a 100 mL of 1.0 M solution of C12H22O11, we need 34.23 grams of powdered drink mix, by first calculating the moles required (0.1 moles) and then using the molar mass (342.30 g/mol) to find the required mass.

Explanation:

To calculate the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL using C12H22O11, we need to use stoichiometry. First, we should calculate the number of moles of C12H22O11 required for a 1.0 M solution. Since molarity is moles of solute per liter of solution, for 0.1 liters (100 mL) of a 1.0 M solution, 0.1 moles of solute is needed.

Next, we find the molar mass of C12H22O11, which is the sum of the atomic masses of each element multiplied by the number of each atom in the molecule:

The molar mass for C12H22O11 will be approximately 342.30 g/mol. The mass of the powdered drink mix needed is calculated as mass = moles × molar mass, which is 0.1 moles × 342.30 g/mol, equaling 34.23 grams. Therefore, we need 34.23 grams of C12H22O11 to make a 100 mL of 1.0 M solution.

Answer: the boiling point of a substance dosent bater how muc hof there it is if there is 100 gallons of water it still boils at 100 c jus takes longer due to more space but if you do 1 gallon it is also 100 c but is faster due to less space to heat up

Part 1:

It appears from the question that M refers to the boiling point of water when the mass is 2, and N refers to the boiling point of Soybean Oil also at a mass of 2. Without the exact figures for M and N given in the question, one can deduce that if both substances have the same mass, N, the boiling point of soybean oil, is greater than M, the boiling point of water. This is because water's boiling point is known to be 100 °C, which is significantly lower than that of soybean oil.

Part 2:

The boiling points of substances heavily depend upon intermolecular forces. Water has a high boiling point relative to its molar mass because of the strong hydrogen bonds between water molecules. However, soybean oil, which consists of long-chain hydrocarbons, likely has different intermolecular forces, such as London dispersion forces, which are stronger due to the larger molar mass and lead to an even higher boiling point.

Therefore, based on our understanding of intermolecular forces and the given information that soybean oil has a boiling point of 300 °C, we can confirm that N is greater than M.

Methane because I just know and it is very hard to explain

The organisms living in the hydrothermal vent are provided by the energy with methane. Thus, option C is correct.

Hydrothermal vents are the fissures near the volcanos in the seafloor that supports the ecosystem deep inside the sea.

The animals near the hydrothermal vents are octopus, crabs, zoarcid fishes, etc. The living of the organism in the cold water in the vent is supported by the absence of sunlight. The carbon compound act as the energy source at the hydrothermal vent.

Thus, the organisms in the hydrothermal vent are supported with energy by methane molecules. Hence, option C is correct.

Learn more about the hydrothermal vent, here:

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Answer:

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O.

Explanation:

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O.

1.0 mole of octane is combusted completely with 25.0 mole of O₂ to produce 16.0 mole of CO₂ and 18.0 mole of H₂O.

Answer: The answer is (B).

Explanation:

Answer (A) is too broad because all chromosomes have alleles that control certain traits. This doesn't tell us anything about the species indicated in the question.

Answer (B) is the correct answer because homologous chromosomes can pair up during meiosis while heterogenous chromosomes cannot.

Answer (C) is incorrect because most species of animals and plants are diploids, meaning their chromosomes come in matching sets called homologous pairs.

Answer (D) is too broad because all chromosomes have DNA that is made up of genes. This doesn't tell us anything about the species indicated in the question.

Answer:

A. 6

Explanation:

369 132 000 s

The important rules are

• Digits other than zero are significant

• Trailing zeroes before the decimal point are not significant

The decimal point is after the last zero, so the three zeroes are not significant,

Thus, the underlined digits in 369 132 000 are significant.

There are six significant figures in the measurement.

A. 6

is the answer for this problem

Answer: propanal and propanoic acid

Explanation: first of all Oxidation of alcohol with mild oxidizing reagent PCC gives Carbonyl compounds and with strong oxidizing agent like CrO3 and kmno4 gives carboxylic acids.

And primary alcohol gives Aldehyde with mild oxidizing reagent and carboxylic acids with strong oxidizing agent.

And ketone is formed with secondary alcohol by both mild and strong Oxidizing agent.

Here our compound is primary alcohol hence we will get propanal and propanoic acid depending on type of Oxidizing agent

Answer:

propanoic acid

Explanation:

One of the properties of alkanols is the fact that they can be oxidized to various products depending on the structure of the alkanol.

A primary alkanol (such as 1-propanol) is oxidized to an alkanal and subsequently to an alkanoic acid.

A secondary alkanol is oxidized to an alkanone while a tertiary alkanol is not oxidized.

This implies that the final product of the oxidation of 1-propanol is propanoic acid as shown in the answer.

Answer:

3 Aluminum Oxide

Explanation:

It is not an element but a coumpound.

Al is Aluminum

O is oxygen.

Answer:

e

Explanation:

This equilibrium for a buffer solution: CH3COOH + H2O CH3COO- + H3O + When a small amount of acid is added to this system,

E. [CH3COO-] has increased and pH remains relatively constant.

acidic buffer

A mixture of a weak acid and its salt with a strong base serves as an acidic buffer. The reaction shows that some acetic acids react with the OH– from the base and converts it to water.

HCl and NaCl. Buffer is an equimolar mixture of weak acid and salt with a strong base.

To learn more about  a buffer solution, refer

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Answer:

Herring might be eaten by anothe kind of fish that gulls eat.

Many chefs today are taught using a culinary arts book written in 1903.

This Is "TRUE"

True penn foster student also a job corps student ik cause my teacher told me this

Explanation:

Answer:

So, the right answer is

No. of moles of FeS₂ = 0.25 mole

Explanation:

From the balanced

4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2

it is clear that 4 mol  FeS₂ react with O₂ to give Fe₂O₃ and 8 mol of SO₂

First, we have to convert mass of SO₂ into No. of moles as following:

SO₂ has molar mass = 64 g/mol

No. of moles of SO₂ = (mass / molar mass) = (32 g / 64 g/mol) = 0.5 mol

we know that  

4 mol  FeS₂  gives→ 8 mol of SO₂

1 mol  FeS₂  gives→ 2 mol of SO₂

??? mol  FeS₂  gives→ 0.5 mol of SO₂

No. of moles of FeS₂ = (0.5 mol * 1 mol ) / 2 mol = 0.25 mol

So, the right answer is

No. of moles of FeS₂ = 0.25 mol

To produce 32g of SO₂, 0.25 moles of FeS₂ are required. This is determined using the balanced chemical equation and mole ratio conversions. The calculation involves determining the moles of SO₂ and then using the ratio from the equation.

Number of moles of FeS₂ are required to produce 32g of SO₂, we start by looking at the balanced chemical equation for the reaction: 4 FeS₂ + 11 O₂ → 2 Fe₂O₃ + 8 SO₂

From the equation, 4 moles of FeS₂ produce 8 moles of SO₂. We need to determine the moles of SO₂ present in 32g:

Step 1: Calculate moles of SO₂
Molar mass of SO₂ = 32.07 (S) + 2*16.00 (O) = 64.07 g/mol
Moles of SO₂ = 32g / 64.07 g/mol = 0.5 moles of SO₂

Step 2: Use the mole ratio to find moles of FeS₂
According to the balanced equation, the mole ratio of FeS₂ to SO₂ is 4:8 or 1:2.
Therefore, moles of FeS₂ required = 0.5 moles SO₂ * (4 moles FeS₂ / 8 moles SO₂) = 0.25 moles of FeS₂

Thus, we need 0.25 moles of FeS2 to produce 32g of SO2.

Answer:

c

Explanation:

Answer:

I want to say the answer is B

Explanation:

Answer:

 0.1648

Explanation:

The specific heat of a metal measures the amount of heat energy required to raise its temperature. It is measured in cal/g.°C and varies depending on the type of metal.

The specific heat of a metal is a property that measures the amount of heat energy required to raise the temperature of a certain amount of the metal by a certain number of degrees Celsius. It is typically measured in units of cal/g.°C.

For example, let's say we have a metal with a specific heat of 0.5 cal/g.°C. This means that it takes 0.5 calories of heat energy to raise the temperature of 1 gram of the metal by 1 degree Celsius.

Specific heat can vary depending on the type of metal. Different metals have different atomic structures, which affect how they absorb and retain heat. Therefore, each metal has its own specific heat value.

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Answer:

1. Control of Radioactivity

This requires being able to control the neutron flux. Recall that in a nuclear reactor when a neutron is captured by a fuel nucleus (generally uranium) the nucleus splits releasing radioactive particles (or undergoes fission). Hence if we decrease the neutron flux we decrease the radioactivity. The most common way to reduce the neutron flux is include neutron-absorbing control rods. These control rods can be partially inserted into the reactor core to reduce the reactions. The control rods are very important because the reaction could run out of control if fission events are extremely frequent. In modern nuclear power plants, the insertion of all the control rods into the reactor core occurs in a few seconds, thus halting the nuclear reaction as rapidly as possible. In addition, most reactors are designed so that beyond optimal level, as the temperature increases the efficiency of reactions decreases, hence fewer neutrons are able to cause fission and the reactor slows down automatically.

2. Maintenance of Core Cooling

In any nuclear reactor some sort of cooling is necessary. Generally nuclear reactors use water as a coolant. However some reactors which cannot use water use sodium or sodium salts.

3. Maintenance of barriers that prevent the release of radiation

There is a series of physical barriers between the radioactive core and the environment. For instance at the Darling Nuclear Generation Station in Canada the reactors are enclosed in heavily reinforced concrete which is 1.8m thick. Workers are shielded from radiation via interior concrete walls. A vacuum building is connected to the reactor buildings by a pressure relief duct. The vacuum building is a 71m high concrete structure and is kept at negative atmospheric pressure. This means that if any radiation were to leak from the reactor it would be sucked into the vacuum building and therefore prevented from being released into the environment.

The design of the reactor also includes multiple back-up components, independent systems (two or more systems performing the same function in parallel), monitoring of instrumentation and the prevention of a failure of one type of equipment affecting any other.

Further, regulation requires that a core-meltdown incident must be confined only to the plant itself without the need to evacuate nearby residence.

Safety is also important for the workers of nuclear power plants. Radiation doses are controlled via the following procedures,

The handling of equipment via remote in the core of the reactor

Physical shielding

Limit on the time a worker spends in areas with significant radiation levels

Monitoring of individual doses and of the work environment

Answer:

4.5L

Explanation:

Given parameters:

Inital volume, V₁ of the dry air = 1.50L

Initial pressure P₁ = 3.0atm

Temperature = 25°C

Final pressure P₂ = 1.0atm

Final volume of gas,  V₂  = ?

To solve gas related problem, we apply Boyle's law based on the parameters given.

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure provided that temperature is constant.

The law is simply expressed as:

                 P₁V₁ = P₂V₂

From the parameters given, the unknown V₂ which is the final volume.

Making  V₂ the subject of the equation gives:

                   V₂ = [tex]\frac{P_{1} V_{1} }{P_{2} }[/tex]

                   V₂ = [tex]\frac{3x1.5}{1}[/tex] = 4.5L

Answer:

Here you go! 50% of your writing piece

Explanation:

Foods produced from or using GM organisms are often referred to as GM foods.

GM foods are developed and marketed because there is some advantage either to the producer or consumer of these GM foods. GM seed developers wanted their products to be accepted by producers and have concentrated on innovations that bring direct benefit to farmers and generally the food industry.

One objective for developing plants based on GM organisms is to improve crop protection. The GM crops currently on the market are mainly aimed at an increased level of crop protection through the introduction of resistance against plant diseases caused by insects or viruses or through increased tolerance towards herbicides.

Resistance against insects is achieved by incorporating into the food plant the gene for toxin production from the bacterium Bacillus thuringiensis. GM crops that inherently produce this toxin have been shown to require lower quantities of insecticides in specific situations, where pest pressure is high.

GMOs are organisms with artificially altered DNA through genetic engineering, used in agriculture, medicine, and conservation. They offer benefits like improved crops and medicinal advances but are also subject to regulatory scrutiny and public debate over safety and environmental impact.

Genetically Modified Organisms (GMOs)

Genetically modified organisms (GMOs) are those whose genetic material has been altered in ways that do not occur naturally. This process, also known as genetic engineering or recombinant DNA technology, enables the introduction of new traits to an organism. For example, genes conferring pest resistance or tolerance to herbicides can be transferred from one organism to another, even between nonrelated species. This technology has applications in agriculture for crop protection, enhancing nutritional content, and improving food production efficiency. Additionally, GMOs have promising applications in environmental conservation, medicine production, and may even address issues like plastic pollution.

However, GMOs are subject to intense debate regarding consumer safety, environmental impact, and ethical concerns. Despite their benefits, such as reduced pesticide use and increased yields, concerns about potential ecological effects, unintended health consequences, and gene transfer to non-target species lead to strict regulation and public caution. Yet, after comprehensive research, GMOs have been deemed safe for consumption.

here is the answer:

if we take the molecular formula, then

28 g Nitrogen forms 17 g ammoni.

so, 11 g Nitrogen forms 17/28 × 11=6.67 g ammonia.

Hence 6.67 g NH3 is formed by 11 g N2

Answer:

13.35 grams of NH₃ is made if 11 grams of N₂ are used.

Explanation:

First of all you should know that the balanced reaction is:

N₂(g) + 3 H₂-> 2 NH₃(g)

Then, it is possible to determine the mass of each compound that reacts or is produced in the reaction by knowing the atomic mass of each element:

Then:

By reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that they react or are obtained in moles:

Then, by the reaction stoichiometry of the reaction, you can see the amounts of mass that react or are obtained:

To calculate the amount of NH₃ mass produced if 11 grams of N₂ are used, it is possible to use a rule of three knowing the stoichiometry of the reaction. The rule of three used is the following: if 28 grams of N₂ produce 34 grams of NH₃, 11 grams of N₂ how many grams of NH₃ will they produce?

[tex]gramsofNH_{3} =\frac{11gramsofN_{2} *34gramsofNH_{3} }{28 grams of N_{2} }[/tex]

grams of NH₃=13.35

Then, 13.35 grams of NH₃ is made if 11 grams of N₂ are used.