What is the solution to the system of equations below?



y= -1/3 and x = –6

Answers

Answer 1

Answer: The Answer is (4,-6)

Step-by-step explanation:


Related Questions

Half of the product of two consecutive numbers is 105. To solve for n, the smaller of the two numbers, which equation can be used?

A.) n^2 + n – 210 = 0
B.) n^2 + n – 105 = 0
C.) 2n^2 + 2n + 210 = 0
D.) 2n^2 + 2n + 105 = 0

Answers

Answer:

A

Step-by-step explanation:

Consecutive nnumbers are spaced 1 units apart.

Such as 4,5,6,...

or 12,13,14,...

Thus,

if smaller number is n, then the next number (consecutive) is n+1

Since, half of the product of them is 105, we can write the equation as:

[tex]\frac{1}{2}((n)(n+1))=105[/tex]

We can do some algebra and make it in quadratic form as shown below:

[tex]\frac{1}{2}((n)(n+1))=105\\\frac{1}{2}(n^2 + n)=105\\n^2+n=2*105\\n^2+n=210\\n^2+n-210=0[/tex]

Answer choice A is right.

Answer:

A.) n^2 + n – 210 = 0

Step-by-step explanation:

just took edg 2022. hope this helps!

prove algebraically that the straight line with equation x=2y+5 is a tangent to the circle with equation x^2+y^2=5
I have gotten 4/5 marks but I need to get 5/5
Thank you!

Answers

Explanation:

A tangent line will have a couple of characteristics:

there is exactly one point of intersection with the circlea perpendicular line through the point of tangency intersects the center of the circle

Substituting for x in the equation of the circle, we have ...

  (2y+5)^2 +y^2 = 5

  5y^2 +20y +20 = 0 . . . . simplify, subtract 5

  5(y +2)^2 = 0 . . . . . . . . . factor

This equation has exactly one solution, at y = -2. The corresponding value of x is ...

  x = 2(-2) +5 = 1

So, the line intersects the circle in exactly one point: (1, -2).

__

The center of the circle is (0, 0), so the line through the center and point of intersection is ...

  y = -2x . . . . . . . . . slope is -2

The tangent line is ...

  y = 1/2x -5/2 . . . . . . slope is 1/2

The product of slopes of these lines is (-2)(1/2) = -1, indicating the lines are perpendicular.

__

We have shown ...

the tangent line intersects the circle in one point: (1, -2)the tangent line is perpendicular to the radius at the point of tangency.


15. Find the area of a triangle with a base of 10 in. and an altitude of 14 in. (The formula for the area of a triangle is A = bh ÷ 2.)

A. 280 sq in.
B. 24 sq in.
C. 70 sq in.
D. 140 sq in.

Answers

Hello There!

We know that the formula of a triangle is "Base Multiplied By Height And Then Divide It By 2"

First, let's plug in our numbers. Our base is going to be 10 inches so we have 10 multiplied by our height which is 14 inches and we get a product of 140.

Next, we divide 140 by 2 to get a quotient of 70.

Finally, our answer is 70in squared

Base = 10 inches
Height = 14 inches

(Base x Height) ÷ 2 = Area
(10 x 14) ÷ 2 = Area
(140) ÷ 2 = Area
70 = Area

Area = 70 square inches

Daniel is packing his bags for his vacation. He has 5 unique socks, but only 4 fit in his bag How many different groups of 4 socks can he take

Answers

Answer:

5

Step-by-step explanation:

Need help with a math question

Answers

Answer:

[tex]z =3\sqrt{13}[/tex]

Step-by-step explanation:

In the figure you can identify up to 3 straight triangles.

To solve the problem, write the Pythagorean theorem for each triangle.

Triangle 1

[tex]13^2 = z^2 + x^2[/tex]

Triangle 2

[tex]z^2 = y^2 + 9^2[/tex]

Triangle 3

[tex]x^2 = y^2 + 4^2[/tex]

Now substitute equation 2 and equation 3 in equation 1 and solve for y.

[tex]13^2 = y^2 + 9^2 + y^2 + 4^2[/tex]

[tex]13^2 = 2y^2 + 9^2 + 4^2[/tex]

[tex]169 = 2y^2 + 81 + 16[/tex]

[tex]2y^2 =72[/tex]

[tex]y^2 =36[/tex]

[tex]y =6[/tex]

substitute the value of y in the second equation and solve for z

[tex]z^2 = 6^2 + 9^2[/tex]

[tex]z^2 = 36 + 81[/tex]

[tex]z^2 = 117[/tex]

[tex]z = \sqrt{117}[/tex]

[tex]z =3\sqrt{13}[/tex]

NEED HELP WITH A MATH QUESTION

Answers

17/3 * 8 + 12 divided by 17 = 4/8

For this case we have that the total of objects is given by:

Large blue objects, small blue objects, large red objects and small red objects.

In total we have: [tex]17 + 3 + 8 + 12 = 4[/tex]0 objects.

If we want to find the probality of obtaining small and blue objects we have to:

[tex]p = \frac {3} {40}[/tex]

ANswer:

[tex]p = \frac {3} {40}[/tex]

If tuvw is an an isoaceles trapezoid with tu parallel to wv, name a pair of similar traingles. Explain

Answers

Answer:

  TUW ~ UTV, TWV ~ UVW

Step-by-step explanation:

An isosceles trapezoid is symmetrical about the perpendicular bisector of its bases. A triangle formed by deleting a vertex on one side of that line of symmetry will be similar to the corresponding triangle formed by deleting the symmetrically opposite vertex on the other side. The two pairs listed above are the possibilities.

Below is the beginning of the construction of a line parallel to the y-axis through point P. What is the next step of this construction?


A. Measure the distance from the intersection of the transversal to point P.

B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis.

C. Draw another transversal.

D. Connect the arc intersections using a straight edge.

Thanks!

Answers

Answer:

  B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis

Step-by-step explanation:

Creating a parallel line through a point involves copying the angle a transversal makes with the given line. The copied angle has the given point as its vertex, and the transversal as one side.

Copying an angle uses the steps of ...

draw an arc through the sides of the given angledraw an arc with the same radius centered at the new vertex...

The step this question is referring to is the first bullet above. The given angle is the angle between the transversal and the y-axis.

The quoient of two rational numbers is positive. What can you conclude about signs of the dividend and the divisor?

Answers

Answer:

  the two signs are the same

Step-by-step explanation:

Whenever the quotient or product of two operands is positive, the signs of the operands are both the same, both negative or both positive.

__

Comment on the general case

Whenever the product of any number of operands is positive, the number of negative signs among the factors is even.

A quotient is the product of one operand and the reciprocal of another (the denominator). A number and its reciprocal have the same sign.

Someone please help me with this...

Answers

Answer:

The total number of points you score is dependent variable Because it change when x is change.

The number of question you answer correctly is independent variable Because it can change itself when you got more correct answers.

The top put a dot for dependent variable,
The bottom put independent variable.

Hope this helps!

How does the graph of y= sec(x-2)+2 comparé to the graph of y= sec(x) ?

Answers

Answer:

The function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards., compared to y=sex(x).

Step-by-step explanation:

To solve this problem we need to know the rules for translation of graphs:

Given the function y = f(x):

y=f(x-a) is the same graph shifted 'a' units to the right. If 'a' is negative, then, the graph is shifted to the left. y = f(x) - a is the same graph, but shifted 'a' units downwards. If 'a' is negative, then the graph will be shifted upwards.

In this case, our main function is y=sec(x). And the function y= sec(x-2)+2 is shifted two units to the right and 2 units upwards.

Answer:

D. it is shifted two units up and two units right

Step-by-step explanation:

this is the correct answer on ed-genuity, hope this helps! :)

Given: △ABC is equilateral. The radius of each circle is r. Find: AB

Answers

Answer:

2r (1 + √3)

Step-by-step explanation:

Circle O₁ is tangent to AB.  Let's call the point of intersection point D.  If we draw a radius from the center O₁ to D, we know this forms a right angle.

△ABC is an equilateral triangle, so we know m∠A = 60°.  If we draw a line from A to O₁, we know that bisects the angle, so m∠DAO₁ = 30°.

So △DAO₁ is a 30-60-90 triangle.  We can find the length AD:

AD = r √3

Now on the other side, circle O₃ is tangent to AB.  Let's call the point of intersection point E.  We know it's the same triangle we found earlier, so:

EB = r √3

And finally, we can draw a rectangle connecting O₁, O₃, E, and D.  The distance between O₁ and O₃ is 2r, so:

DE = 2r.

Therefore:

AB = r√3 + 2r + r√3

AB = 2r√3 + 2r

AB = 2r (1 + √3)

Here's a graph showing the steps.  Hopefully this helps, let me know if you have questions!

desmos.com/calculator/hgaonfzxsm

If the given sequence is a geometric sequence, find the common ratio.

3/3, 3/12, 3/48, 3/192, 3/768

a. 4

b. 1/30

c. 30

d. 1/4

Answers

Answer:

  d.  1/4

Step-by-step explanation:

The ratio of adjacent terms is the common ratio:

  (3/12)/(3/3) = 3/12 = 1/4

Two bags contain blue and red marbles. The first bag contains 3 blue and 5 red marbles. The second bag contains
2 blue and 4 red marbles. A marble is drawn from each bag. What is the probability that both marbles are blue?​

Answers

Answer: 1/8

Step-by-step explanation:

First Bag   and      Second Bag

[tex]\dfrac{3\ blue}{8\ total}[/tex]        x            [tex]\dfrac{2\ blue}{6\ total}[/tex]        =  [tex]\dfrac{6}{48}[/tex]

which reduces to [tex]\boxed{\dfrac{1}{8}}[/tex]

NEED HELP FAST PULEASEE

Please help fast asap

What is the probability of drawing three black cards, one at a time with replacement, from a standard deck of 52 cards?


A.'3/52

Its not b

C.1/8

d.75/676


Need help fasttt

GIve p(6,6) and q=(-5,-3) find the magnitude of 2p+3q



A.2 sqr3


B. 3 sqr2


its not C


D.14



According to NFL statistics, the Cincinnati Bengals will lose 13 out of 16 games, regardless of opponent. What are the odds of Cincinnati losing a game?



A.3;13


its not b


C.13;3


D16;13



Determine which trigonometric function to use to solve for the hypotenuse. Then,


solve for the length of the hypotneuse.

b=9

A=55.8


A.cosin, .062

B.sin,10.8

C.sin,16.0

its not D

Answers

Answer:

6

Step-by-step explanation:

What is the opposite of squaring a number

Answers

The opposite of squaring a number is taking the square root. They are inverse operations.

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

What is a perfect square?

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

Perfect squares are those integers whose square root is an integer.

Let x-a be the closest perfect square less than x,

Let x-a be the closest perfect square less than x, and let x+b be the closest perfect square more than x, then we get x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).

Then, we get:

[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]

Thus, these are the closest integers, less than and more than the value of[tex]\sqrt{x}[/tex]. (assuming x is a non-negative value).

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

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Please explain how you got this answer.

-Aparri

Answers

Answer:

She got a 87 on her chemistry test

Step-by-step explanation:

(72 + 85 + 92 + x)/4 = 84

249 + x = 336

x = 87

what is the value of x

Answers

Answer:

Correct me if I am wrong, but I believe it is B.

Step-by-step explanation:

Answer:

C. 28

Step-by-step explanation:

From the diagram diagram; [tex]\angle BAC=(x+6)\degree[/tex] and [tex]\angle ABD=2x\degree[/tex].

The opposite sides of a rhombus are parallel.The diagonals act as transversals. Therefore the co-interior angles will add up to 180 degrees.

The pair of co-interior angles are [tex]\angle BAD[/tex] and [tex]\angle ABC[/tex].

Also the diagonals of a rhombus bisect corner angles.

This implies that:

[tex]\angle BAD=2(\angle BAC)\implies \angle BAD=2(x+6)\degree[/tex].

[tex]\angle ABC=2(\angle ABD)\implies \angle ABC=2(2x)\degree[/tex].

The co-interior angles are supplementary  so we form the equation:

[tex]\angle BAD+\angle ABC=180\degree[/tex]

[tex]\implies 2(x+6)\degree+2(2x)\degree=180\degree[/tex]

Expand the parenthesis to get:

[tex]\implies 2x+12+4x=180\degree[/tex]

Group the similar terms:

[tex]\implies 2x+4x=180-12[/tex]

Simplify

[tex]\implies 6x=168[/tex]

Divide both sides by 6.

[tex]\implies \frac{6x}{6}=\frac{168}{6}[/tex]

[tex]\therefore x=28[/tex]

The correct answer is C.

In △ M N O , points R and T are the midpoints of their respective sides. MT and OR intersect at point C.

1. 14 units

2. None of the listed answers are correct

3. 15 units

4. 16.5 units

5. 12.5 units

Answers

Answer:

  3.  15 units

Step-by-step explanation:

When medians intersect, the point of intersection divides the median into parts in the ratio 2:1. That is ...

  OC : CR = 2 : 1 = 4 units : 2 units . . . . . . OR = (4+2) units = 6 units

  MC : CT = 2 : 1 = 6 units : 3 units . . . . . . MT = (6+3) units = 9 units

The sum of lengths OR + MT is ...

  6 units + 9 units = 15 units

Final answer:

The given question is incomplete. Without information about dimensions or additional information of the triangle or the lines, we cannot solve for lengths.

Explanation:

Unfortunately, the question is incomplete, so it is impossible to answer it accurately. In the given situation, we have a triangle △MNO and points R and T are the midpoints of their respective sides. The lines MT and OR intersect at a point C. However, without explicit dimensions or additional information about the triangle or the lines, we cannot determine the length of any line segment. In geometry problems like this, it's crucial to have a complete set of given information before proceeding with the solution.

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Lisa has $150 at most to spend on clothes. She wants to buy a pair of jeans for $58 and will spend the rest on t-shirts that cost $14 each. (5 points each) 2. Create an inequality to represent the number of t-shirts that Lisa can purchase. You can create a visual model in a paint program if that helps. Make sure you explain what the variable represents in your inequality

Answers

The inequality used in this situation will be 14x + 58 < 150.

What is inequality?

The word inequality means a mathematical expression in which the sides are not equal to each other.

Let the no. of T-shirts Lisa can buy be = X

Cost of each T-shirt = $14

No. of jeans she bought = 1

Cost of jeans = $58

Total money she has = $150

Hence, the inequality will be 14X + 58 < 150.

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Final answer:

Lisa can spend a maximum of $92 on T-shirts after buying jeans, and with each T-shirt costing $14, she can buy up to 6 T-shirts as represented by the inequality 14t <= $92, where t is the number of T-shirts.

Explanation:

To create an inequality representing the number of T-shirts Lisa can purchase, let's define the variable t to represent the number of T-shirts. Lisa has $150 to spend, and she wants to buy a pair of jeans for $58, leaving $150 - $58 = $92 for T-shirts. Each T-shirt costs $14, so if Lisa buys t T-shirts, the cost for the T-shirts is 14t. The inequality to represent the maximum number of T-shirts Lisa can buy is 14t ≤ $92.

Now, to solve for t, we divide both sides of the inequality by 14: t ≤ $92 / $14, which simplifies to t ≤ 6.57. Since Lisa cannot buy a fraction of a T-shirt, the maximum number of T-shirts she can buy is 6.

The cost of a long-distance phone call is $0.45 for the first minute and $0.36 for each additional minute. If the
total charge for a long-distance call is $6.93, how many minutes was the call?
The call was for
minutes.

Answers

Answer:

19 minutes

Step-by-step explanation:

cost = .45+.36m

If we take 6.93 minus .45 for the minute, we get 6.48. We take 6.48 and divide it by .36 for each additional minute, which is 18. We take the 18 and add one more minute to it since .45 was covered for the first minute.

Final answer:

The long-distance phone call that cost $6.93 was 19 minutes long. This was calculated by first deducting the cost of the first minute from the total cost, then dividing the remaining cost by the cost of each additional minute, and finally adding back the first minute.

Explanation:

The subject of this question is mathematics, and it involves understanding the cost structure of a long-distance phone call. So here's how we solve the problem:

Subtract the first minute's cost from the total cost. So, $6.93 - $0.45 = $6.48.Then divide the remaining total by the cost of each additional minute. So, $6.48 / $0.36 = 18 additional minutes.Last, add back in the first minute that we subtracted at the start. So, 18 minutes + 1 minute = 19 minutes total.

Therefore, the duration of the long-distance phone call that cost $6.93 was 19 minutes.

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what is the measure of DEF

Answers

Answer:

The measure of arc DEF is 204° ⇒ answer C

Step-by-step explanation:

* Lets talk about some facts in the circle

- If the vertex of an angle on the circle and the two sides of the

 angle are chords in the circle, then this angle is called  

 an inscribed angle

- Each inscribed angle subtended by the opposite arc, the arc name

 is the starting point and the ending point of the angle

- The measure of any circle is 360°

# Ex: ∠CAB is inscribed angle subtended by arc CB

- There is a relation between the inscribed angle and its  

  subtended arc, the measure of the inscribed angle equals half

  the measure of its subtended arc

* Now lets solve the problem

- ∠DEF is an inscribed angle subtended by arc DF

∴ m∠DEF = (1/2) measure of arc DF

∵ The measure of ∠DEF = 78°

∴ 78° = (1/2) measure of arc DF ⇒ multiply both sides by 2

∴ The measure of arc DF = 78° × 2 = 156°

∵ The measure of arc DF + The measure of arc DEF = The measure of

   the circle

∵ The measure of the circle = 360°

∵ The measure of the arc DF = 156°

∴ 156° + measure of arc DEF = 360° ⇒ subtract 156 from both sides

∴ The measure of arc DEF = 360° - 156° = 204°

* The measure of arc DEF is 204°

Answer: OPTION C.

Step-by-step explanation:

By definition:

[tex]Inscribed\ Angle = \frac{1}{2} Intercepted\ Arc[/tex]

Then we can calculate the measure of DF. This is:

[tex]78\°=\frac{1}{2}DF\\\\DF=(2)(78\°)\\\\DF=156\°[/tex]

We know that there are 360 degrees in a circle, therefore, in order to find the measure of DEF, we need to make the following subtraction:

[tex]DE[/tex][tex]F[/tex][tex]=360\°-156\°[/tex]

[tex]DE[/tex][tex]F[/tex][tex]=204\°[/tex]

 You can observe that this matches with the option C.

What is the length of the missing side? What is the area of the figure?
Show ALL work.​

Answers

Answer:

Missing side=25 units.

Area of the figure= 470 sq units.

Step-by-step explanation:

The figure is made up of a rectangle and a triangle.

To get the base of the triangle, we find the difference between the two parallel sides, that is, 16ft and 31 ft.

31ft-16ft=15ft  

The height of the triangle is 20 since it is parallel and equal to the length of the rectangle.

We therefore use pythagoras theorem to find ?

a²+b²=c²

15²+20²=c²

625=c²

c=25

ii. The figure is a trapezium therefore we use the following formula to find the area.

A= 1/2(a+b)h, where a and b are the two parallel sides. and h the distance between them.

=(1/2)(31+16)×20

=470 sq units

Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. 254°

Answers

Answer: 614° and -106°

Step-by-step explanation:

You have this angle in degrees:

254°

Then, in order to find  the measure of a positive angle conterminal with the given angle in degrees (254°), you need to add  360 degrees. Therefore, the measure of the positive angle is:

[tex]254\°+360\°=614\°[/tex]

Now, to find the measure of a negative angle coterminal with the given angle in degrees (254°), you need to subtract  360 degrees. Therefore, this is:

[tex]254\°-360\°=-106\°[/tex]

What should be the next letter in the following series? A z e b i y o _ ?_

Answers

Answer:  c

Step-by-step explanation:

Notice the pattern (vowel, consonant, vowel, consonant):

A: first vowel            z: last consonant

e: second vowel                                        b: first consonant      

i: third vowel             y: second to the last consonant

o: fourth vowel                                           c: second consonant

Divide the binomial by the monomial to find the quotient.

48x^4y-72x^6y^2
-------------------------
-12x^2y

Answers

Answer:

  -4x² +6x⁴y

Step-by-step explanation:

Deal with it term by term, factor by factor.

[tex]\dfrac{48x^4y-72x^6y^2}{-12x^2y}=\dfrac{48x^4y}{-12x^2y}+\dfrac{-72x^6y^2}{-12x^2y}\\\\=\dfrac{48}{-12}\cdot\dfrac{x^4}{x^2}\cdot\dfrac{y}{y}+\dfrac{-72}{-12}\cdot\dfrac{x^6}{x^2}\cdot\dfrac{y^2}{y}=-4x^2+6x^4y[/tex]

Final answer:

To divide the binomial by the monomial, divide each term's coefficients and subtract their exponents, resulting in the quotient [tex]-4x^2 + 6x^4y[/tex].

Explanation:

To divide the given binomial by the monomial, we divide each term in the numerator by the term in the denominator. In this case, we need to divide both terms of the binomial [tex]48x^4y - 72x^6y^2[/tex] by the monomial[tex]-12x^2y[/tex]. This involves dividing the coefficients (the numbers in front of the variables) and subtracting the exponents for like bases according to the rules of division of exponentials.

Starting with the first term:

[tex]\frac{48x^4y}{ -12x^2y} = -4x^{(4-2)}y^{(1-1)} = -4x^2y^0 = -4x^2[/tex]

Now the second term:

[tex]\frac{-72x^6y^2}{-12x^2y } = 6x^{(6-2)}y^{(2-1)} = 6x^4y[/tex]

The final quotient of dividing the binomial by the monomial is:

[tex]-4x^2 + 6x^4y[/tex]

Ben drew 3 two-dimensional shapes that had II angles in all. Draw shapes Ben could have drawn.

Answers

The figure is attached to show the shapes Ben could have drawn

He could have drawn  2 four angled polygon , 1 triangle and  1 pentagon , 2 triangles .

What are Two Dimensional Shapes ?

The shapes which lie on two coordinate axis and has length ,and breadth are called Two dimensional shapes.

A polygon is included in two dimensional shapes.

It is given in the question that

Ben drew 3 two-dimensional shapes that had 11 angles in all.

11 angles mean

2 four angled polygon , 1 triangle

2 quadrilaterals ( rectangle , square , rhombus etc.) and a triangle

1 pentagon , 2 triangles

A figure is attached  for the above stated answer .

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Please help, I'm taking the semester test.

Drag and drop an answer to each box to correctly explain the derivation of the formula for the volume of a pyramid.

Consider a prism and a pyramid with the same base and height.
The volume of the prism is blank, the volume of the pyramid.
The formula for the volume of a prism is V=Bh ,
where B is the area of the base and h is the height, so the formula for the volume of a pyramid is blank


Picture shown below


Answers

Final answer:

The volume of a pyramid is one-third of the volume of a prism with the same base area and height, yielding the formula V = (1/3)Bh for the volume of a pyramid.

Explanation:

When comparing the volume of a prism and a pyramid with the same base and height, the volume of a pyramid is one-third of the volume of the prism. Therefore, the formula for the volume of a prism is V = Bh, where B is the base area and h is the height. Applying this to the pyramid, the pyramid's volume becomes V = (1/3)Bh. This formula tells us that the volume of a pyramid is equal to one-third of the product of the area of its base and its height.

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A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude of 41,000 feet. Model the most fuel-efficient altitudes using a compound inequality.

x ≥ 29,000 and x ≤ 41,000
x ≤ 29,000 and x ≥ 41,000
x ≥ 41,000 and x ≥ 29,000
x ≤ 41,000 and x ≤ 29,000

Answers

Answer:

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

[tex]x\geq 29,000[/tex]

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

[tex]x\leq 41,000[/tex]

All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval ------> [29,000,41,000]

option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using compound inequality.

We need to identify the correct compound inequality describing the altitude at which the aircraft operates most efficiently. The best fuel efficiency altitudes range from 29,000 ft to 41,000 ft, meaning the altitude must be at least 29,000 ft and at most 41,000 ft.

So, to represent that the altitude must be at least 29000 ft we use the mathematical expression:

[tex]x\geq 29,000[/tex]

To represent that the altitude must be 41000 ft at most we use the mathematical expression:

[tex]x\leq 41,000[/tex]

These two expression can be represented as a compound inequality as follows:

[tex]x\geq 29,000\[/tex] and [tex]x\leq 41,000[/tex]

Therefore, option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using a compound inequality.

if y is the midpoint of xz, y is located at (3,-1), and z is located at (11,-5), find the coordinates of x

Answers

[tex]\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ X(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad Z(\stackrel{x_2}{11}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{11+x}{2}~~,~~\cfrac{-5+y}{2} \right)=\stackrel{\stackrel{midpoint}{y}}{(3,-1)}\implies \begin{cases} \cfrac{11+x}{2}=3\\[1em] 11+x=6\\ \boxed{x=-5}\\ \cline{1-1} \cfrac{-5+y}{2}=-1\\[1em] -5+y=-2\\ \boxed{y=3} \end{cases}[/tex]

We define midpoint formula as

[tex]Y(x_m, y_m)=Y(\dfrac{x_2+x_1}{2}, \dfrac{y_2+y_1}{2})[/tex]

Also here are the coordinates of every point in variables so you won't get confused.

[tex]

Y(x_m, y_m) \\

X(x_1, y_1) \\

Z(x_2, y_2)

[/tex]

Which means there are two equations. One to find x of point X and one to find y of point X.

[tex]

x_m=\dfrac{x_2+x_1}{2}\Longrightarrow 3=\dfrac{11+x_1}{2} \\

6=11+x_1\Longrightarrow\underline{x_1=-5} \\ \\

y_m=\dfrac{y_2+y_1}{2}\Longrightarrow-1=\dfrac{-5+y_1}{2} \\

-2=-5+y_1\Longrightarrow\underline{y_1=3}

[/tex]

So point X has coordinates: [tex]\boxed{X(-5, 3)}[/tex]

Hope this helps.

r3t40

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