what is the simplified form of the following expression? assume x doesn’t = 0

What Is The Simplified Form Of The Following Expression? Assume X Doesnt = 0

Answers

Answer 1

For this case we must simplify the following expression:

[tex]\sqrt [5] {\frac {10x} {3x ^ 3}}[/tex]

We rewrite the expression as:

[tex]\sqrt [5] {\frac {10x} {x * 3x ^ 2}} =[/tex]

We eliminate common factors:

[tex]\sqrt [5] {\frac {10} {3x ^ 2}} =\\\frac {\sqrt [5] {10}} {\sqrt [5] {3x ^ 2}}[/tex]

We multiply the numerator and denominator:

[tex](\sqrt [5] {3x ^ 2}) ^ 4:\\\frac {\sqrt [5] {10}} {\sqrt [5] {3x ^ 2}} * \frac {(\sqrt [5] {3x ^ 2}) ^ 4} {(\sqrt [5] {3x ^ 2}) ^ 4} =[/tex]

\frac {\ sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {\sqrt [5] {3x ^ 2} * (\sqrt [5] {3x ^ 2} ) ^ 4} =

[tex]\frac {\sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {(\sqrt [5] {3x ^ 2}) ^ 5} =\\\frac {\sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {3x ^ 2} =[/tex]

[tex]\frac {\sqrt [5] {10} * \sqrt [5] {(3x ^ 2) ^ 4}} {3x ^ 2} =\\\frac {\sqrt [5] {10} * \sqrt [5] {81x ^ 8}} {3x ^ 2} =\\\frac {\sqrt [5] {10} * \sqrt [5] {81x ^ 5 * x ^ 3}} {3x ^ 2} =[/tex]

[tex]\frac {\sqrt [5] {10} * x \sqrt [5] {81x ^ 3}} {3x ^ 2} =\\\frac {x \sqrt [5] {810x ^ 3}} {3x ^ 2}[/tex]

Answer:

[tex]\frac {x \sqrt [5] {810x ^ 3}} {3x ^ 2}[/tex]

[tex]\frac {\sqrt [5] {810x ^ 3}} {3x}[/tex]

Answer 2

Answer:

The simplified form is [tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]

Step-by-step explanation:

we need to simplify the value of x in given expression:

[tex]\sqrt[5]{\frac{10x}{3x^{3}}}[/tex]

Re- write the above as,

[tex]\sqrt[5]{\frac{10}{3x^{2}}}[/tex]

[tex]\frac{\sqrt[5]{{10}}}{\sqrt[5]{3x^{2}}}[/tex]

Multiply numerator and denominator by [tex](\sqrt[5]{3x^{2}})^{4}[/tex]

[tex]\frac{\sqrt[5]{{10}}}{\sqrt[5]{3x^{2}}} \times \frac{(\sqrt[5]{3x^{2}})^{4}}{(\sqrt[5]{3x^{2}})^{4}}[/tex]

[tex]\frac{\sqrt[5]{{10}}{\sqrt[5]{(3x^{2}}})^4}{{3x^{2}}}[/tex]

[tex]\frac{\sqrt[5]{{10}}{\sqrt[5]{81x^{8}}}}{{3x^{2}}}[/tex]

[tex]\frac{x \sqrt[5]{810 x^{3}}}{3x^{2}}[/tex]

[tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]

Hence, the simplified form is

[tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]


Related Questions

Allison can complete a sales route by herself in 6 hours. Working with an associate, she completes the route in 4 hours. How long would it take her associate to complete the route by herself?

Answers

Answer:

So, Allison averages 1/6 of the route every hour, right?

 

1/6 + 1/a = 1/4

 

Once we apply the common denominator, 12a, we only wirk with the numerators.

 

2a + 12 = 3a

a = 12

 

Her associate can finish the route in 12 hours by herself.

Step-by-step explanation:

it would take 12 hours for her associate to complete the route by herself

Further explanation

This problem is related to the speed of completing the route.

To solve this problem, we must state the formula for the speed.

[tex]\large {\boxed {v = \frac{x}{t}} }[/tex]

where:

v = speed of completing the route ( m³ / s )

x = route distance ( m³ )

t = time taken ( s )

Let's tackle the problem!

Allison can complete a sales route by herself in 6 hours.

[tex]\text{Allison Speed} = v_a = x \div t_a[/tex]

[tex]v_a = x \div 6[/tex]

Her associate can complete the route by herself in t_s

[tex]\text{Associate Speed} = v_s = x \div t_s[/tex]

[tex]v_s = x \div t_s[/tex]

Working with an associate, she completes the route in 4 hours

[tex]\text{Total Speed} = v = v_a + v_s[/tex]

[tex]\frac{x}{t} = \frac{x}{t_a} + \frac{x}{t_s}[/tex]

[tex]\frac{1}{t} = \frac{1}{t_a} + \frac{1}{t_s}[/tex]

[tex]\frac{1}{4} = \frac{1}{6} + \frac{1}{t_s}[/tex]

[tex]t_s = \frac{ 6 \times 4 }{6 - 4}[/tex]

[tex]t_s = \frac{ 24 }{2}[/tex]

[tex]t_s = 12 ~ \text{hours}[/tex]

Learn moreInfinite Number of Solutions : https://brainly.com/question/5450548System of Equations : https://brainly.com/question/1995493System of Linear equations : https://brainly.com/question/3291576

Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 27nft3. Which equation gives the volume of the sphere

Answers

Answer:

The volume of the sphere is [tex]V=18\pi\ ft^{3}[/tex]

Step-by-step explanation:

we know that

The volume of cylinder is equal to

[tex]V=\pi r^{2}h[/tex]

we have

[tex]V=27\pi\ ft^{3}[/tex]

substitute

[tex]27\pi=\pi r^{2}h[/tex]

simplify

[tex]27=r^{2}h[/tex]

Remember that

A sphere and a cylinder have the same radius and height

so

The height of cylinder is equal to the diameter of sphere

h=2r

substitute

[tex]27=r^{2}(2r)[/tex]

[tex]13.5=r^{3}[/tex] -----> equation A

The volume of the sphere is equal to

[tex]V=\frac{4}{3}\pi r^{3}[/tex]

substitute equation A in the formula of the volume of sphere

[tex]V=\frac{4}{3}\pi (13.5)[/tex]

[tex]V=18\pi\ ft^{3}[/tex]

Answer:

It's (A.) guys

Step-by-step explanation:

A grain silo is shown below: Grain silo formed by cylinder with radius 8 feet and height 172 feet and a half sphere on the top What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi. (4 points) 34,597 ft3 11,532 ft3 35,669 ft3 2,146 ft3

Answers

Answer:

Third option: [tex]35,669 ft^3[/tex]

Step-by-step explanation:

You need to use the formula for calculate the volume of a cylinder:

[tex]V_c=\pi r^2h[/tex]

Where r is the radius (In this case is 8 feet) and h is the height (In this case is 172 feet).

The formula for calculate the volume of a half sphere is:

[tex]V_s= \frac{2}{3} \pi  r^3[/tex]

Where r is the radius (In this case is 8 feet)

You need to add the volume of the cylinder and the volume of the half-sphere. Then the volume of grain that could completely fill this silo, rounded to the nearest whole number is (Remeber to use [tex]\frac{22}{7}[/tex] for [tex]\pi[/tex]):

[tex]V=(\frac{22}{7}) (8ft)^2(172ft)+ (\frac{2}{3})(\frac{22}{7})(8ft)^3=35,669 ft^3[/tex]

Answer:

The correct answer is third option 35,669 feet³

Step-by-step explanation:

It is given that, Grain silo formed by cylinder with radius 8 feet and height 172 feet and a half sphere on the top

We have to find the volume of cylinder + volume of semi sphere

To find the volume of cylinder

Here r = 8 feet and f cylinder = πr²h

 = (22/7) * 8² * 172

 = 34596.57 ≈ 34597 feet³

To find the volume of hemisphere

here r = 8 feet

Volume of hemisphere = (2/3)πr³

 = (2/3) * (22/7) * 8³

 = 1072.76 ≈ 1073 feet³

To find the total volume

Total volume = volume of cylinder + volume of hemisphere

 = 34597 + 1073

 = 35,669 feet³

The correct answer is third option 35,669 feet³

Point C, is a point that is found on AB. AB is translated 3 units up and 10 units to
the right to form APB? Which of the following must be true?
1. Points A', B, and C must be collinear.
II. Ad and 8c must be of equal length.
I. AB and AB? are parallel.
I only
Il only
I and II only
I and III only

Answers

Answer:

I and III only

Step-by-step explanation:

step 1

we know that

In this problem

A, B and C are collinear

so

A', B' and C' are collinear too

because the transformation is a translation

The translation does not modify the shape or length of the figure

AB=A'B'

AC=A'C'

BC=B'C'

step 2

The distance

AA'=BB'=CC'

because AB and A'B' are parallel

Find the value of the expression 2x3 + 3y2 − 17 when x = 3 and y = 4

Answers

Answer:

85

Step-by-step explanation:

I assume by 2x3 you mean 2x^3 and 3y2 means 3y^2. If so then just plug in the values:

2x^3 + 3y^2 - 17 = ?

2(3)^3 + 3(4)^2 - 17 = ?

2(27) + 3(16) - 7 = ?

54 + 48 - 17

102 - 17 = ?

85 = ?

How do you multiply two scientific notation values?
Explain the steps you would take to find the product of
6.7 x 106 and 3.2 10 written in scientific notation.

Answers

Answer:

case 1) [tex]2.144*10^{12}[/tex]

case 2) [tex]2.144*10^{8}[/tex]

Step-by-step explanation:

case 1) If we have

[tex]6.7*10^{6}[/tex] and [tex]3.2*10^{5}[/tex]

step 1

Calculate the product of the coefficients and powers separately

[tex]6.7*3.2=21.44[/tex]

[tex]10^{6}*10^{5}[/tex] -----> Apply the product of powers rule to add the exponents

[tex]10^{6}*10^{5}=10^{6+5}=10^{11}[/tex]

step 2

we have

[tex]21.44*10^{11}[/tex]

The product is not in scientific notation because the coefficient is greater than 10

step 3

Change the coefficient by moving the decimal one place to the left and increasing the exponent by one

[tex]2.144*10^{12}[/tex]

case 2) If we have

[tex]6.7*10^{6}[/tex] and [tex]3.2*10^{1}[/tex]

step 1

Calculate the product of the coefficients and powers separately

[tex]6.7*3.2=21.44[/tex]

[tex]10^{6}*10^{1}[/tex] -----> Apply the product of powers rule to add the exponents

[tex]10^{6}*10^{1}=10^{6+1}=10^{7}[/tex]

step 2

we have

[tex]21.44*10^{7}[/tex]

The product is not in scientific notation because the coefficient is greater than 10

step 3

Change the coefficient by moving the decimal one place to the left and increasing the exponent by one

[tex]2.144*10^{8}[/tex]

Answer:

Calculate the product of the coefficients and powers separately. Apply the product of powers rule to add the exponents. The product is not in scientific notation because the coefficient is greater than 10. Change the coefficient by moving the decimal one place to the left and increasing the exponent by one.

Step-by-step explanation:

(sample response from edgenuity)

The equation of a line in slope intercept form is y=mc+b where m is the x-intercept. True or False?

Answers

The equation of a line in slope intercept form is y=mc+b where m is the x-intercept. False. M represents the slope

Answer:

False

Step-by-step explanation:

First, there is no x in your equation. I think you meant y = mx + b.

Second, m is the slope, and b is the y-intercept.

Which of the following sets are discrete? Please help :(

Answers

Answer:

A,D,E

Step-by-step explanation:

If it just lists out the numbers then it is discrete.  So the following are not discrete since it isn't just a list:  B and C.

The following are lists:  A,D,E

multiply. (3.5x10^-5) (3x10^-10) express your answer in scientific notation.​

Answers

Answer:

5.69034 × 1011

Step-by-step explanation:

Decimal  

1234000000

Scientific Notation  

1.234 x 10^9

×10^  

9

1st Number  

1.234

×10^  

9

Operation  

2nd Number  

5.678

×10^  

11

What is the absolute value of the complex number -4-
2
V14
3.15
14
18

Answers

The answer to your question is 14

Pay: $8.25 per hour
Hours: 21 hours per week
per week
per month
per year​

Answers

Per week=173.25
Per year 9033.75
Per month 30 days 742.5
Per month 31 days 767.25

Answer:

Week: $173.25

Month: $693

Year: $8,316

Step-by-step explanation:

What is the interquartile range of this box plot? And how do you find it?

Please and thank you

Answers

Answer:

3.

Step-by-step explanation:

Calculate the median, which is the middle number of an ordered range with an odd number. 3.

Calculate the medians of the bottom and top halves, omitting the middle number. Since these are now even-numbered sets, we'll take the average of the middle two numbers of each. Lower is 1.5, upper is 4.5.

Calculate the difference of the upper median and lower median, so 4.5 - 1.5 = 3.

Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The discriminant is b2 – 4ac = (–8)2 – (4)(2)(–10) = .

Answers

Answer:

Part 1) The x-component of the vertex is 2 and the y-component of the vertex is -18

Part 2) The discriminant is 144

Step-by-step explanation:

we have

[tex]f(x)=2x^{2}-8x-10[/tex]

step 1

Find the discriminant

The discriminant of a quadratic equation is equal to

[tex]D=b^{2}-4ac[/tex]

in this problem we have

[tex]f(x)=2x^{2}-8x-10[/tex]

so

[tex]a=2\\b=-8\\c=-10[/tex]

substitute

[tex]D=(-8)^{2}-4(2)(-10)[/tex]

[tex]D=64+80=144[/tex]

The discriminant is greater than zero, therefore the quadratic equation has two real solutions

step 2

Find the vertex

Convert the quadratic equation into vertex form

[tex]f(x)+10=2x^{2}-8x[/tex]

[tex]f(x)+10=2(x^{2}-4x)[/tex]

[tex]f(x)+10+8=2(x^{2}-4x+4)[/tex]

[tex]f(x)+18=2(x-2)^{2}[/tex]

[tex]f(x)=2(x-2)^{2}-18[/tex] -----> equation in vertex form

The vertex is the point (2,-18)

therefore

The x-component of the vertex is 2

The y-component of the vertex is -18

Answer:

Consider the quadratic function f(x) = 2x2 – 8x – 10.

The x-component of the vertex is

✔ 2

The y-component of the vertex is

✔ –18

The discriminant is b2 – 4ac = (–8)2 – (4)(2)(–10) =

✔ 144

substitute w = 1 and w = 3 to determine if the two expressions are equivalent
4 (3w + 4) 16w + 12

Answers

Answer:

Expressions are not equivalent

Step-by-step explanation:

Given expressions are:

[tex]4(3w+4)\ and\ 16w+12[/tex]

Putting w=1 in both expressions

[tex]4(3w+4)\\=4[3(1)+4]\\=4(3+4)\\=4(7)\\=28\\\\16w+12\\=16(1)+12\\=16+12\\=28[/tex]

Both expression have value 28 on w=1

Putting w=3 in both expressions

[tex]4(3w+4)\\=4[3(3)+4]\\=4(9+4)\\=4(13)\\=52\\\\16w+12\\=16(3)+12\\=48+12\\=60[/tex]

Both expression have different values at w=3

Hence, in order for the expressions to be equivalent they both should produce same value on w=3 too.

So, it can be concluded that both expressions are not equivalent ..

Answer:They are both not equivalent

Step-by-step explanation:

You’re welcome

Lynda Davis bought a house for $90,000. Her expenses each month
are $70 in depreciation, $50 for property tax, $25 for insurance, $80
for repairs, and $200 for interest. She rents the house for $1,200
per month. (32) What are her total expenses for the month? (33)
– What are her expenses for the year? (34) What is her rental income
for the year? (35) What is her rate of income to the nearest tenth
_ of a percent?


please also tell me how you got the answers. I have to show my work​

Answers

Final answer:

Lynda Davis' total expenses for the month are $425. Her expenses for the year are $5100. Her rental income for the year is $14400. Her rate of income is approximately 282.35%.

Explanation:

To calculate Lynda Davis' total expenses for the month, we need to add up all of her monthly expenses. These include $70 for depreciation, $50 for property tax, $25 for insurance, $80 for repairs, and $200 for interest. So her total monthly expenses would be $70 + $50 + $25 + $80 + $200 = $425.

To calculate her expenses for the year, we can multiply her total monthly expenses by 12 since there are 12 months in a year. So her annual expenses would be $425 * 12 = $5100.

Her rental income for the year would be the monthly rental income of $1200 multiplied by 12. So her rental income for the year would be $1200 * 12 = $14400.

To calculate her rate of income, we need to find the percentage of her rental income compared to her total expenses. We can use the formula: (rental income / total expenses) * 100. So her rate of income would be ($14400 / $5100) * 100 ≈ 282.35%.

Solve for x, y, and z. Please show all steps.

Answers

Answer:

I have put my answer in the form (x,y,z)

One solution (3,2,4)

Another solution (-5,-4,-6)

Step-by-step explanation:

I'm going to try to do this by a bunch of substitution.

I'm going to solve first equation for x, second for y, and third for z.

Commutative property x+xy+y=11

Distributive property x(1+y)+y=11

Subtraction property  x(1+y)=11-y

Division property x=(11-y)/(1+y)

I'm going to do the other 2 equations in a similar way:

So the second equation solving for y:    y=(14-z)/(1+z)

The third equation solving for z:  z=(19-x)/(1+x)

I'm going to plug my new first equation into my third equation giving me:

z=(19-[(11-y)/(1+y)])/(1+[(11-y)/(1+y)]

Now I'm going to clean this up by multiplying by compound fraction by (1+y)/(1+y).

z=(19(1+y)-(11-y)]/[1(1+y)+(11-y)]

z=[19+19y-11+y]/[1+y+11-y]

z=[8+20y]/[12]

Simplify

z=(2+5y)/3

Now I'm going to sub this into my non-rewrite of equation 2:

y+(2+5y)/3+y(2+5y)/3=14

Multiply both sides by 3 to clear fractions

3y+(2+5y)+y(2+5y)=42

3y+2+5y+2y+5y^2=42

5y^2+10y+2=42

Subtract 42 on both sides

5y^2+10y-40=0

Divide both sides by 5

y^2+2y-8=0

Factor

(y+4)(y-2)=0

So y=-4 or y=2

If y=-4  then x=(11-(-4))/(1+(-4))=15/-3=-5 and z=(2+5*-4)/3=-18/3=-6

So one solution is (-5,-4,-6)

If y=2 then x=(11-2)/(1+2)=9/3=3 and z=(2+5*2)/3=12/3=4

So another solution is (3,2,4)

Three-fourth of x is added to the product of 7 and q.

Translate as algebraic expression

Answers

Answer:

3/4x + (7 × Q)

|

That's an x not multiplication

Answer:

[tex]7q + \frac{3}{4}x[/tex]

Step-by-step explanation:

[tex]\begin{array}{rcl}\text{Product of 7 and q} & = & 7q\\\\\text{Three-fourths of x} & = & \frac{3}{4}x \\\\\text{Three fourths of x added to product of 7 and q} & = & 7q + \frac{3}{4}x \\\\\end{array}[/tex]

Two parallel lines are crossed by a transversal.
What is the value of x?
??!!!??!!!!!????

Answers

The answer for this problem: X = 12.

We can solve this problem by using the known value (115) to solve for the angle parallel to the equation.

To find the solve for the angle to the exact right of 115, subtract 115 from 180. This works because 115 and the unknown angle form to make a straight line, which is 180 degrees.

180-115=65

Now, since it is parallel, we know that 5x+5=65 degrees.

Solve the equation.

Subtract 5 on both sides.

5x=60

Divide both sides by 5 to isolate x.

5x=13

The value of x is 13.

Hope this helps!

A lock has 60 digits, and the combination involves turning right to the first number, turning left to the second number, and turning right to the third number. How many possible combinations are there?

Answers

Final answer:

A lock with 60 digits and a combination involving turning right to the first number, left to the second number, and right to the third number can have 212,400 possible combinations.

Explanation:

A lock with 60 digits and a combination involving turning right to the first number, left to the second number, and right to the third number can have 60 x 59 x 60 possible combinations.

Here's the explanation:

For the first digit, you have 60 options since you can turn right to any of the 60 digits.For the second digit, you have 59 remaining options since you turned left from the first digit and cannot choose the same digit twice.For the third digit, you have 60 options again since you turned right from the second digit.

By multiplying these options together, you get the total number of possible combinations: 60 x 59 x 60 = 212,400.

Final answer:

The total number of possible combinations for a lock with a 60-digit combination, turning right, left, and right is 60 × 60 × 60, leading to 216,000 unique combinations.

Explanation:

To calculate the number of possible combinations for a lock with a 60-digit sequence where you turn right to the first number, left to the second number, and right to the third number, you need to apply the basic principle of counting. Each of the three steps in the combination can be any of the 60 digits, with the choice of one step not affecting the choices for the other steps. Therefore, each step has 60 options, and the total number of possible combinations is the product of these options.

The calculation for the total number of combinations is: 60 × 60 × 60, which simplifies to 60^3. When you calculate that, you get 216,000 possible combinations for the lock.

Original Price:
Discount: 75%
Final Price: $85.99

Answers

Answer: $343.96

Step-by-step explanation:

x-0.75x=85.99

0.25x=85.99

Answer:

343.96

Step-by-step explanation:

The discount it 75%.  That means we pay 25%

25% of the original price is 85.99

Let x be the original price

x*25% = 85.99

.25x = 85.99

Divide each side by .25

.25x/.25 = 85.99/.25

x =343.96

The original price is 343.96

solve log(x+1)= -x^2 +10

Answers

Answer:

[tex]\boxed{x \approx 3.064}[/tex]

Step-by-step explanation:

There is no general property  that we can use to rewrite:

[tex]log_{a}(u\pm v)[/tex]

Then, we'll solve this problem graphically. Let's say that we have two functions:

[tex]f(x)=log(x+1) \\ \\ g(x)=-x^2 +10[/tex]

[tex]f(x)[/tex] is a logarithmic function translated one unit to the left of the pattern logarithmic function [tex]log(x)[/tex]. On the other hand, [tex]g(x)[/tex] is a parabola that opens downward and whose vertex is [tex](0,10)[/tex]. So:

[tex]f(x)=g(x)[/tex]

implies that we'll find the value (or values) where these two functions intersect. When graphing them, we get that this x-value is:

[tex]\boxed{x=3.064}[/tex]

Then, for [tex]x=3.064[/tex]:

[tex]f(x)=log(x+1) \\ \\ f(3.064)=log(3.064+1) \\ \\ f(3.064)=log(4.064) \\ \\ Using \ calculator: \\ \\ f(3.064) \approx 0.6 \\ \\ \\ g(x)= -x^2 +10 \\ \\ g(3.064)= -(3.064)^2 +10 \\ \\ g(3.064)=-9.388+10 \\ \\ g(3.064) \approx -0.6[/tex]

plz help your get 28 point

Answers

The figure that is shaded 6/8 is the square.

If you split the square on more time along like a box pizza, you will get 8 slices and 6 of them shaded.

Solve the equations for x and match the solutions.

Answers

Answer:

1. x = -a/6

2. x = 3/a

x = -6/a

Step-by-step explanation:

1. 4 = (6/a)x+5

subtract 5 from both sides

-1 = (6/a)x

divide by 6/a on both sides

x = -a/6

To make that last part simpler, you could think of it as first multiplying by a and then dividing by 6.

2. 7+2ax = 13

subtract 7

2ax = 6

divide by 2

ax = 3

divide by a

x = 3/a

3. -ax-20 = -14

add 20

-ax = 6

divide by -a

x = 6/-a = -6/a

Final answer:

To solve for x in an equation linked with equilibrium concentration and solubility, identify known values, select the right conversion equations, utilize the ICE table method, and substitute the known values into the solubility product expression. Rearrange the equation to solve for x.

Explanation:

In this question, we are looking to solve equations linked with equilibrium concentration and solubility. First, we will identify known values from the problem and list them out. This includes figuring out the terms we need to substitute into the solubility product expression and identifying our unknown, x. Afterwards, we need to select the right conversion equations and substitute the known values.

The chemical reaction gives us an ICE (Initial, Change, Equilibrium) table, which is a simplified method used to solve equilibrium problems. Sometimes it might be necessary to consider momenta in the x and y directions to solve for the unknown. When we have the equilibrium concentrations, we substitute these terms into the solubility product expression and solve for x.

Always remember that the goal is to rearrange the equation so that x is on one side by itself, making it easier to solve for. This kind of problem requires a clear understanding of solubility, equilibrium, and algebraic conventions.

Learn more about Chemical Equilibrium here:

https://brainly.com/question/32227445

#SPJ3

How do I know they are similar.

Answers

Answer:

The figures are not similar

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

so

Verify

BC/JI=AB/FJ=ED/GH

substitute the given values

5.1/3.6=2.8/2.1=3.7/2.7

1.417=1.333=1.370 ------> is not true

therefore

The figures are not similar

Using the segment addition postulate, which is true?



AB + BC = AD
AB + BC = CD
BC + CD = AD
BC + CD = BD

Answers

Answer:

D

Step-by-step explanation:

For the segment addition postulate, two segments added together have to equal the third segment. In other words, if we added them together, the sum should be the first letter of the first line and the second letter of the second line.

BC + CD = BD

The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function? The domain is all real numbers. The range is {y|y < 16}. The domain is all real numbers. The range is {y|y ≤ 16}. The domain is {x|–5 < x < 3}. The range is {y|y < 16}. The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}.

Answers

Answer:

The domain is all real numbers. The range is {y|y ≤ 16}

Step-by-step explanation:

we have

[tex]f(x)=-x^{2}-2x+15[/tex]

This is the equation of a vertical parabola open downward

The vertex is a maximum

Find the vertex of the quadratic equation

[tex]f(x)-15=-x^{2}-2x[/tex]

[tex]f(x)-15=-(x^{2}+2x)[/tex]

[tex]f(x)-15-1=-(x^{2}+2x+1)[/tex]  

[tex]f(x)-15-1=-(x^{2}+2x+1)[/tex]

[tex]f(x)-16=-(x^{2}+2x+1)[/tex]

[tex]f(x)-16=-(x+1)^{2}[/tex]

[tex]f(x)=-(x+1)^{2}+16[/tex] -----> equation in vertex form

The vertex is the point (-1,16)

therefore

The domain is the interval ----> (-∞,∞)  All real numbers

The range is the interval ----> (-∞,16]  All real numbers less than or equal to 16

Answer:

The Answer Is B

Step-by-step explanation:

domain is all real numbers. The range is {y|y ≤ 16}.

What is the value of x is?

Answers

Answer:

96

Step-by-step explanation:

Answer:

e^x = -3 = -1*3  

x = ln(-3) = ln(-1) + ln(3)  

= (2n+1)iπ + ln(3)  

where n is any integer. For the principal value, choose n=0:  

= iπ + ln(3)

Step-by-step explanation:

What is the absolute value of the complex number -4-sqrt2i

Answers

Answer:

=√18

Step-by-step explanation:

The absolute value of a complex number is its distance from zero on graph. The formula for absolute value of a complex number is:

|a+bi|= √(a^2+b^2 )

where a is the real part of the complex number and b is the imaginary part of the complex number.

So for the given number,

a= -4

b=-√2

Putting in the formula:

|-4-√2 i|= √((-4)^2+(-√2)^2 )

= √(16+2)

=√18  ..

ANSWER

[tex]3 \sqrt{2} \: units[/tex]

EXPLANATION

The absolute value of the complex number

[tex] |a +b i| = \sqrt{ {a}^{2} + {b}^{2} } [/tex]

This is also known as the modulus of the complex number.

This implies that:

[tex]| - 4 - \sqrt{2} i| = \sqrt{ {( - 4)}^{2} + {( - \sqrt{2} )}^{2} } [/tex]

[tex]| - 4 - \sqrt{2} i| = \sqrt{ 16 +2 } [/tex]

We simplify further to get;

[tex]| - 4 - \sqrt{2} i| = \sqrt{ 18 } = 3 \sqrt{2} \: units[/tex]

Evaluate the following expression. Round your answer to two decimal places Log7^e

A. 0.43

B. 1.47

C. 0.51

D. 1.95

Answers

The value of the given expression [tex]\log_{7} e[/tex] will be 0.51, i.e. option C.

What is expression ?

Expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

 [tex]\log_{7} e[/tex]

So,

Using the log rule,

On solving we get,

[tex]\log_{7} e =0.51[/tex]

So,

This the value of the given expression.

Hence, we can say that the value of the given expression [tex]\log_{7} e[/tex] will be 0.51, i.e. option C.

To know more about expression click here

https://brainly.com/question/953809

#SPJ2

Final answer:

The given expression Log₇^eA can be simplified and evaluated to approximately 0.43 when rounded to two decimal places.

Explanation:

Logarithms:

The expression Log₇^eA can be rewritten as Log₇(e). Applying the change of base formula to convert it to a common logarithm form, Log₇(e) = ln(e) / ln(7). Since ln(e) = 1, the result is approximately 0.43, rounded to two decimal places.

find the greatest common factor of the polynomial: 10x^5+15x^4-25x^3

10x^5

x^3

5x^3

5

Answers

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the greatest common factor of the polynomial

10x^5+15x^4-25x^3

The greatest common factor is the number that is divisible by all 3 terms of the polynomial.

so, the common factor is 5x^3 for above polynomial

Taking out the common factor

5x^3(2x^2+3x-5)

Now the term in the bracket has no other common factor

So, the greatest common factor of 10x^5+15x^4-25x^3 is 5x^3

So, Option C is correct.

Answer:

Third option.

Step-by-step explanation:

The greatest common factor (GCF) for a polynomial is defined as the largest monomial that divides each term.

Given the polynomial [tex]10x^5+15x^4-25x^3[/tex], the GCF of the coefficients can be found by descompose each one of them into their prime factors:

[tex]10=2*5\\15=2*5\\25=5*5[/tex]

You can observe that the GCF of the coefficients is:

[tex]GFC_{(coefficients)}=5[/tex]

Now you need to find the GCF of the variables. You can notice that each term has at least one x³, then:

 [tex]GFC_{(variables)}=x^3[/tex]

Threfore, the GCF of the polynomial is:

[tex]GCF=5x^3[/tex]

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