What is the Percent yield made if 3.9 grams of a substance were made experimentally while you calculated 3.6 grams of substance using Stoichiometry?

Answer:

salt

Explanation:

Answer:

The answer to your question is 11460 years

Explanation:

Data

Carbon-14 activity  10 cpm

half-life = 5730 yr

Real carbon-14 activity 40 cpm

Process

1.- Write a chart to solve this problem

                    Real carbon-14      40 cpm       Time  0 years

                    After a half-life      20 cpm        Time  5730 years

                    After a half-life      10 cpm        Time 5730 years

    Total time                                                            11460 years          

2.- Conclusion

The wooden object is 11460 years old.                    

The turnover number refers to the number of substrate molecules converted to product per unit time by a single enzyme molecule at saturation. The Michaelis constant (Km) indicates substrate concentration for half-maximal enzyme activity, and the maximum velocity (Vmax) is reached when enzyme active sites are saturated.

The number of substrate molecules converted to product in a given unit of time by a single enzyme molecule at saturation is referred to as the turnover number, also known as kcat. This measure of enzymatic activity provides a direct indication of the active site's catalytic efficiency within the enzyme's turnover rate.

In contrast, the Michaelis constant (Km) represents the substrate concentration at which the enzyme achieves half of its maximum reaction rate, or Vmax/2. This constant is used to determine the enzyme's affinity for a substrate, with a low Km indicating a high affinity, and vice versa.

When an enzyme operates in an environment with a high concentration of substrate, it will eventually reach a point where every active site is saturated with substrate -- this is the maximum velocity (Vmax) of the reaction. The Vmax is dependent on both the speed of the enzyme and the total number of enzyme molecules available.

The relationship between Vmax, Km, and substrate concentration ([S]) is described by the Michaelis-Menten equation, which is fundamental in the study of enzyme kinetics.

Final answer:

Carbon dioxide (CO₂) consists of two oxygen atoms bonded to a central carbon atom. Each oxygen atom forms a double bond with the carbon atom. The double bond consists of two bonding pairs of electrons. Therefore, carbon dioxide has 2 bonding pairs and 0 lone pairs of electrons.

Explanation:

Carbon dioxide (CO₂) consists of two oxygen atoms bonded to a central carbon atom. Each oxygen atom forms a double bond with the carbon atom. The double bond consists of two bonding pairs of electrons. Therefore, carbon dioxide has 2 bonding pairs and 0 lone pairs of electrons. The correct option is d) 2 bonding pairs and 2 lone pairs.

The correct option is b. 4 bonding pairs and 2 lone pairs.

To determine the number of bonding pairs and lone pairs in carbon dioxide (CO2), we need to consider the Lewis structure of the molecule. Carbon dioxide has a total of 16 valence electrons, 4 from the carbon atom and 6 from each of the two oxygen atoms.

 In the Lewis structure of CO2, the carbon atom is double-bonded to each oxygen atom. Each double bond consists of one sigma (σ) bond and one pi (Ï€) bond. Since there are two double bonds, there are a total of 4 bonding pairs of electrons (2 sigma bonds and 2 pi bonds).

The Lewis structure of CO2 is as follows:

O=C=O

 Here, the carbon atom has no lone pairs, as it forms double bonds with both oxygen atoms. Each oxygen atom has 2 lone pairs of electrons, but since we are asked about the entire CO2 molecule, we consider the lone pairs on both oxygen atoms together. Therefore, there are 2 lone pairs in total for the CO2 molecule.

 In summary, carbon dioxide has 4 bonding pairs of electrons (from the 2 double bonds) and 2 lone pairs of electrons (1 on each oxygen atom). This matches option b.

Answer:

Calcium ions.

Explanation:

The generation of the action potential helps in the transfer of information to the different body parts. This potential occurs to the difference in membrane potential inside and outside of the cell.

The sarcoplasmic reticulum is the homologous to the endoplasmic reticulum of the cells. The sarcoplasmic reticulum contains calcium ions in it and releases the stored calcium ions on the generation of the action potential. This calcium ion is important for the action of the actin and myosin.

Thus, the correct answer is option (D).

Explanation:

Below are attachments containing the solution

Answer:

The initial temperature is 499 K

Explanation:

Step 1: Data given

initial volume = 12 cm3 = 12 mL

Final volume = 7 cm3 = 7mL

The final temperature = 18 °C = 291 K

Step 2: Calculate the initial temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.012 L

⇒with T1 = the initial volume = ?

⇒with V2 = the final volume 0.007 L

⇒with T2 = The final temperature = 291 K

0.012 / T1 = 0.007 / 291

0.012/T1 = 2.4055*10^-5

T1 = 0.012/2.4055*10^-5

T1 = 499 K

The initial temperature is 499 K

Answer:

Net ionic equation: 2OH⁻(aq) + Fe²⁺(aq)  → Fe(OH)₂(s)

Net ionic equation: 2K⁺(aq) + CH₃COO⁻ (aq) + 2Na⁺(aq) + S⁻²(aq)  → NO REACTION

Net ionic equation: CO₃⁻²(aq) + Pb⁺²(aq) → PbCO₃(s)

Explanation:

a. Solutions of calcium hydroxide and Iron (II) chloride are mixed:

We identify the reactants:

Ca(OH)₂ , FeCl₂

In excess, the Fe(OH)₂ can make precipitate

Salts from chlorides with elements from group II are soluble.

The reaction is: Ca(OH)₂(aq) + FeCl₂(aq) →  Fe(OH)₂(s)  +  CaCl₂(aq)

Ca(OH)₂(aq) + FeCl₂(aq) →  Fe(OH)₂(s)  +  CaCl₂(aq)

We dissociate the compounds, except for the solid

Ca²⁺(aq) + 2OH⁻(aq) + Fe²⁺(aq) + 2Cl⁻(aq)  →  Fe(OH)₂(s) + Ca²⁺ + 2Cl⁻(aq)

Net ionic equation: 2OH⁻(aq) + Fe²⁺(aq) → Fe(OH)₂(s)

b. Solutions of potassium acetate and sodium sulfide are mixed:

The reactants are: KCH₃COOH and Na₂S

In this case there are no precipitates, because all the salts are soluble

We make the complete reaction:

2KCH₃COO (aq) + Na₂S(aq)  → K₂S(aq) + 2NaCH₃COO (aq)

Net ionic equation is:

2K⁺(aq) + CH₃COO⁻ (aq) + 2Na⁺(aq) + S⁻²(aq)  → 2K⁺(aq) + S⁻²(aq) + 2Na⁺(aq) + CH₃COO⁻ (aq)

c. Solutions of ammonium carbonate and lead(II) nitrate are mixed:

In this case, the reactants are: (NH₄)₂CO₃ and Pb(NO₃)₂

All salts from nitrate are soluble.

Carbonate makes a precipitate when it bonds Pb.

The complete reaction is:

(NH₄)₂CO₃(aq) + Pb(NO₃)₂(aq) → PbCO₃(s) + 2NH₄NO₃(aq)

We dissociate all of the compounds, except for the solid in order to make the net ionic equation:

2NH₄⁺(aq) +CO₃⁻²(aq) + Pb⁺²(aq) +2NO₃⁻(aq) → PbCO₃(s) + 2NH₄⁺ (aq) + 2NO₃⁻(aq)

The net ionic equation is: CO₃⁻²(aq) + Pb⁺²(aq) → PbCO₃(s)

The ions that are repeated, are called spectators ions. We all cancel them.

Correct question:

An 8.10-g sample of SO3 was placed in an evacuated container, where it decomposed at 590°C according to the following reaction:

SO3(g) <-----> SO2(g) + 1/2 O2 (g)

At equilibrium the total pressure and the density of the gaseous mixture were 1.83 atm and 1.57 g/L respectively. Calculate Kp for this reaction

Answer:

Kp for this reaction is 0.149atm

Explanation:

Given details

The state reaction

SO3(g) <-----> SO2(g) + 1/2 O2 (g)

Density = 1.57 g/L

Temperature = 590°C = 863K

The given mass of SO3 is 8.10g

The molar mass of SO3 is

S + 3O = {(32) + 3(16)} = 80g/mol

Numbers of mole =

Given mass/molar mass = 8.10/80

Numbers of mole of SO3 = 0.1013mol

From density = mass/volume

Volume V = 8.10/1.56 = 5.2L

Initial pressure from PV = nRT

R = Universal gas constant

R = 0.0821 atm/K/mol

P = (0.1013*0.0821*863)/5.2

P = 1.38 atm

At equilibrium

moles SO3 = 0.10 - X

moles SO2 = X

moles O2 = X/2

moles total = (0.10 - X) + X + X/2

Total mole = 0.10 + X/2

Ptot = (0.10 + X/2)*0.0821*863/5.2 = 1.83

(0.10 + X/2)* 70.8523 = 9.516

X/2 = 0.1343 -0.10 = 0.0343

X = 0.0686

At equilibrium

moles SO3 = 0.10 - X = 0.10 - 0.0686 = 0.0314

moles SO2 = X = 0.0686

moles O2 = X/2 = 0.0343

moles total = 0.10 + X/2 = 0.10 + 0.0343 = 0.1343

P(SO3) = Ptot*X(SO3) = 1.83*0.0314/0.1343 = 0.428atm

P(SO2) = 1.83*0.0686/0.1343 = 0.935atm

P(O2) = 1.83*0.0343/0.1343 = 0.467atm

Kp for this reaction is

Kp = [P(SO2)*P(O2)^1/2]/P(SO3)

Kp = {0.935*(0.467)^0.5}/0.428

Kp = 0.149atm

Answer:

Number of moles of Cl₂ = 0.3 mol

Explanation:

Given data:

Number of moles of Cl₂ = ?

Pressure = 0.966 atm

Volume = 8.00 L

Temperature = 45°C

Solution:

The given problem will be solve by using general gas equation, which is,

PV = nRT

R = general gas constant (0.0821 atm.L/mol.K)

Now we will convert the °C into K.

Temperature = 45+ 273 = 318 K

Now we will put the values in formula.

n = PV/RT

n = 0.966 atm × 8.00 L / 318 K ×0.0821 atm.L/mol.K

n = 7.728/26.1078 /mol

n = 0.3 mol

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal. Here the given equation is C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.

This means that new products are formed due to the change in the chemical composition of the reactants.

Hence, the equation shows a chemical reaction - the breaking and forming of chemical bonds that leads to a change in the composition of matter.

1. The equation is C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.

2. And, in the given equation CO₂ is a product.

3. In the equation, C₆H₁₂O₆ is a reactant.

4. In O₂, the type of bond that holds the two oxygen atoms together is a non-polar covalent bond.

5. In H₂O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a polar covalent bond.

6. The number of oxygen atoms on the left side of the equation is equal to the number of oxygen atoms on the right side.

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Answer:

[tex]\large \boxed{\text{86.8 L}}[/tex]

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

[tex]p_{1}V_{1} = p_{2}V_{2}[/tex]

Data:

[tex]\begin{array}{rclrcl}p_{1}& =& \text{0.579 atm}\qquad & V_{1} &= & \text{150 L} \\p_{2}& =& \text{1.00 atm}\qquad & V_{2} &= & ?\\\end{array}[/tex]

Calculations:  

[tex]\begin{array}{rcl}0.579 \times 150 & =& 1.00V_{2}\\86.85 & = & 1.00V_{2}\\V_{2} & = &\dfrac{86.85}{1.00}\\\\& = &\textbf{86.8}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{86.8 L}}[/tex]

Answer:

The answer to your question is below

Explanation:

Data

mass of Sr(NO₃)₂ = 6.67 g       Final volume = 0.750 L

Sample  0.100 L

[Na₃PO₄] = 0.046 M

a) [Sr(NO₃)₂

MM = 211.64 g

                          211.64 g ---------------------- 1 mol

                             6.67 g ---------------------- x

                             x = (6.67 x 1) / 211.64

                             x = 0.032 mol

Molarity = 0.032 / 0.75

Molarity = 0.042

b)

             3Sr(NO₃)₂  +  2Na₃PO₄  ⇒  Sr₃(PO₄)₂  +  6NaNO₃

              Reactants             Elements         Products

                    3                           Sr                      3

                    6                            N                      6

                    6                            Na                    6

                    2                            P                       2

                  24                           O                     24

c)

Calculate the moles of Sr(NO₃)₂ in 100 ml or 0.1 L

Molarity = moles / volume

Moles = Molarity x volume

Moles = 0.042 x 0.1

Moles = 0.0042

                  3 moles of Sr(NO₃)₂ --------------- 2 moles of Na₃PO₄

                  0.0042 moles of Sr(NO₃)₂ -------- x

                  x = (0.0042 x 2) / 3

                  x = 0.0028 moles of Na₃PO₄

Molarity = moles / volume

Volume = moles / Molarity

Volume = 0.0028 / 0.046

Volume = 0.060 L or 60.9 mL

Answer:

NEGATIVE CHARGE can best fill in the gap

Explanation:

The Na /K pump functions to maintain resting potential so that the cells will be kept in a state of a low concentration of sodium ions and high levels of potassium ions within the cell.

The processes of Na - K pump illustrates active transport since it moves Na+ and K+ ions against their concentration gradient. The energy required is supplied by the breakdown of ATP (adenosine triphosphate) to ADP (adenosine diphosphate). In nerve cells the pump is used to generate gradients of both sodium and potassium ions.

How does the sodium-potassium pump contribute to the net negative charge of the interior of the cell?

The sodium-potassium pump forces out three (positive) Na+ ions for every two (positive) K+ ions it pumps in, thus the cell loses a positive charge at every cycle of the pump.

Answer:

a basic solution has [OH-] > [H3O+]

Answer:

Explanation:

The answer choices are:

The correct formula is:

         [tex]Al_2O_3[/tex]

What you must know to answer this question is that the chemical formulas indicate the number of atoms of each element in the formula by placing a subscript to the right of the chemical symbol that represents the atom.

Thus, we can deal with each statement:

A. The coefficient 3 indicates that there are a total of three atoms of oxygen present in the substance.

Incorrect. 3 is not a coefficient but a subscript. Thus this option is wrong.

B. The subscript 2 indicates that two atoms of oxygen are present in the substance.

Incorrect. The subscript 2 is to the right of tha aluminum symbol, thus it does not represent the number of atoms of oxygen.

C. The chemical symbol Al indicates that oxygen is present in the substance.

Incorrect. The chemical symbol Al indicates that aluminum is present in the substance. Thus, this is wrong.

D. The subscript 2 indicates that two atoms of aluminum are present in the substance.

Correct. The subscript 2 is to the right of the symbol Al, which is the chemical symbol for aluminum. Thus, this indicates that there are two atoms of aluminum in the substance.

This is an incomplete question, here is a complete question.

The rearrangement of methyl isonitrile (CH₃NC) to acetonitrile (CH₃NC) is a first-order reaction and has a rate constant of 5.11 × 10⁻⁵ s⁻¹ at 472 K. If the initial concentration of CH₃NC is 3.00 × 10⁻² M :

How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 % of its initial value?

Answer : The time taken will be, 10.7 hours

Explanation :

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  = [tex]5.11\times 10^{-5}s^{-1}[/tex]

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = 14 % of 100 = 14

Now put all the given values in above equation, we get

[tex]t=\frac{2.303}{5.11\times 10^{-5}}\log\frac{100}{14}[/tex]

[tex]t=38482.72s=\frac{38482.72}{3600}=10.7hr[/tex]

Therefore, the time taken will be, 10.7 hours

Answer:

b

Explanation:

Answer:  Number of moles of NaCl per liter of solution

Explanation: Molarity can be defined as the number of moles

of solute per liter of solution.

Therefore the molarity of an aqueous solution of NaCl is thus defined as the number of moles of NaCl per liter of solution.

Answer:

The pressure in the bottle is 826 mmHg

Explanation:

In this case it is assumed that the volume of the soda bottle does not change, so it remains constant with a value of 2.00 L. Then it is possible to apply the Gay Lussac law.

This law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature decreases, gas pressure decreases. That is, the gas pressure is directly proportional to its temperature.

Gay-Lussac's law can be expressed mathematically as follows:

[tex]\frac{P}{T}=k[/tex]

Where P = pressure, T = temperature and K = Constant

Having a gas that is at a pressure P1 and a temperature T1, as the temperature varies to a new T2 value, then the pressure will change to P2. It is then fulfilled:

[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]

Remember that the temperature must be in degrees Kelvin (° K) and that 0 ° C is 273.15 ° K

In this case you know:

Replacing:

[tex]\frac{728 mmHg}{298.15K} =\frac{P2}{338.15K}[/tex]

Resolving you get:

[tex]\frac{728 mmHg}{298.15K} *338.15K=P2[/tex]

P2=825.67 mmHg≅826 mmHg

The pressure in the bottle is 826 mmHg

The pressure of the bottle is 825.7 mmHg

The parameters given in the question are

Pressure 1= 728 mmHg

Temperature 1= 25°C

= 25+273

T1= 298K

Temperature 2= 65°C

= 65 +273

= 338K

P1/T1= P2/T2

728/298= P2/338

Cross multiply

298 × P2= 728 × 338

298 × P2= 246,064

P2= 246,064/298

P2= 825.7

Hence the pressure in the bottle is 825.7 mmHg

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The mass of barium iodide in 188 ml of a 0.532M solution is calculated to be approximately 39.11 grams using concepts of molarity, moles, and molar mass.

The question is asking to find out the mass of barium iodide in a solution, given a certain volume and a concentration. The question is a standard calculation involving molarity and volume. Molarity (M) is defined as the number of moles of solute per liter of solution. Therefore, you can calculate the number of moles of solute first using the formula M = n/V, where n is the number of moles and V is the volume in liters. We can convert 188 mL to liters (0.188 L) and we know the molarity is 0.532M, so the number of moles in the solution is 0.532M * 0.188 L = 0.10 moles of iodide ions. To find the mass of barium iodide, we multiply this number by the molar mass of barium iodide, which is roughly 391.136 g/mol (from barium's molar mass of 137.327 g/mol and iodine's molar mass of 253.809 g/mol). Thus, the mass of barium iodide is 0.10 moles * 391.136 g/mol = 39.11 g.

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Answer:

Reverse; since the value of Q is greater than the value of K

Explanation:

The equation for the reaction can be expressed as:

[tex]HCN + H_2 O[/tex]     ⇄    [tex]H_3O^+ +CN^{-}[/tex]                [tex]k_a = 6.2 * 10^ {-10[/tex]

[tex]Q = \frac{[H_3O^+][CN^-]}{[HCN]}[/tex]  

[tex]Q = \frac{(0.1)(0.1)}{(0.1)}[/tex]

Q = 0.1

[tex]k_a = 6.2 * 10^ {-10[/tex]

Q > [tex]K_{a}[/tex]

If the value of Q is greater than [tex]K_{a}[/tex] Value; the reaction will definitely shift to reverse direction.

Answer : The correct option is, (d) 80 %

Solution : Given,

Mass of [tex]C_6H_{12}O_6[/tex] = 1 g

Mass of [tex]O_2[/tex] = 1 g

Molar mass of [tex]C_6H_{12}O_6[/tex] = 180 g/mole

Molar mass of [tex]O_2[/tex] = 32 g/mole

Molar mass of [tex]H_2O[/tex] = 18 g/mole

First we have to calculate the moles of [tex]C_6H_{12}O_6[/tex] and [tex]O_2[/tex].

[tex]\text{ Moles of }C_6H_{12}O_6=\frac{\text{ Mass of }C_6H_{12}O_6}{\text{ Molar mass of }C_6H_{12}O_6}=\frac{1g}{180g/mole}=0.00555moles[/tex]

[tex]\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{1g}{32g/mole}=0.0312moles[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

[tex]C_6H_{12}O_6+6O_2\rightarrow 6H_2O+6CO_2[/tex]

From the balanced reaction we conclude that

As, 6 mole of [tex]O_2[/tex] react with 1 mole of [tex]C_6H_{12}O_6[/tex]

So, 0.0312 moles of [tex]O_2[/tex] react with [tex]\frac{0.0312}{6}=0.0052[/tex] moles of [tex]C_6H_{12}O_6[/tex]

From this we conclude that, [tex]C_6H_{12}O_6[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]O_2[/tex] is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of [tex]H_2O[/tex]

From the reaction, we conclude that

As, 6 mole of [tex]O_2[/tex] react to give 6 mole of [tex]H_2O[/tex]

So, 0.0312 mole of [tex]O_2[/tex] react to give 0.0312 mole of [tex]H_2O[/tex]

Now we have to calculate the mass of [tex]H_2O[/tex]

[tex]\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O[/tex]

[tex]\text{ Mass of }H_2O=(0.0312moles)\times (18g/mole)=0.562g[/tex]

Theoretical yield of [tex]H_2O[/tex] = 0.562 g

Experimental yield of [tex]H_2O[/tex] = 0.45 g

Now we have to calculate the percent yield of the reaction.

[tex]\% \text{ yield of reaction}=\frac{\text{ Experimental yield of }H_2O}{\text{ Theoretical yield of }H_2O}\times 100[/tex]

[tex]\% \text{ yield of reaction}=\frac{0.45g}{0.562g}\times 100=80\%[/tex]

Therefore, the percent yield of reaction is, 80 %

Answer:

The yield would D. 80%!

Explanation:

Since 1 gram of O2 only produces 0.56 g of H2O, whereas 1 g of C6H12O6 produces 0.60 g of H2O, the O2 is the limiting reagent.

Answer:

The final temperature is 131 K

Explanation:

Step 1: Data given

The initial pressure = 120 kPa = 1.18431 atm

The final pressure = 50 kPa = 0.493462 atm

The initial volume = 45 L

The final volume = 40 L

The initial temperature = 81 °C = 354 K

Step 2: Calculate the final temperature

(P1*V1)/T1 = (P2*V2)/T2

⇒with P1 = the initial pressure = 1.18431 atm

⇒with V1 = the initial volume = 45 L

⇒with T1 = the initial temperature = 354 K

⇒with P2 = the final pressure = 0.493462 atm

⇒with V2 = the final volume = 40 L

⇒with T2 = the final temperature = ?

(1.18431 * 45)/354 = (0.493462*40)/T2

0.15054788 = 19.73848/T2

T2 = 19.73848/0.15054788

T2 = 131 K

The final temperature is 131 K

Final answer:

To determine the final temperature of a gas with given initial and final pressures and volumes, one applies the combined gas law. After converting the initial Celsius temperature to Kelvin, the final temperature is calculated to be 262.33K.

Explanation:

The problem at hand involves the application of the combined gas law, which allows us to calculate changes in a gas's condition. This law is represented as (P1 * V1) / T1 = (P2 * V2) / T2, where P stands for pressure, V for volume, and T for temperature in Kelvin. Given that the pressure of a gas changes from 120kPa to 50kPa and its volume changes from 45L to 40L, with an initial temperature of 81°C (which is 354.15K), we can find the final temperature.

To solve, we start with the conversion of temperatures to Kelvin and then apply the formula. The rearranged formula to find the final temperature (T2) is T2 = ((P2 * V2) * T1) / (P1 * V1). By substituting the given values, T2 = ((50kPa * 40L) * 354.15K) / (120kPa * 45L), we get a final temperature of 262.33K.

Explanation:

It is given that total energy is -443 kJ/mol and formula to calculate the lattice energy is as follows.

       Total energy = heat of sublimation + bond dissociation energies + ionization energy for Cs + EA of [tex]Cl^{-}[/tex] + lattice energy

       -443 kJ/mol = 76 + 121 + 376 - 349 + Lattice energy

   Lattice energy = (-443 - 76 -121 - 376 + 349) kJ

       Lattice energy = -667 kJ

Therefore, we can conclude that -667 kJ is the magnitude of the lattice energy for CsCl.

Answer:

There are five main types of acyl derivatives. Acid halides are the most reactive towards nucleophiles, followed by anhydrides, esters, and amides. Carboxylate ions are essentially unreactive towards nucleophilic substitution, since they possess no leaving group

Answer:

The specific heat of the object [tex]C_{obj}[/tex] = 0.457 [tex]\frac{KJ}{kg K}[/tex]

Explanation:

Mass of the object [tex]m_{obj}[/tex] = 23.2 gm

Initial temperature [tex]T_{obj}[/tex] = 97 ° c

Mass of the water [tex]m_{w}[/tex] = 90 gm

Initial temperature of water [tex]T_{w}[/tex] = 20.5 ° c

Final temperature of both water & object [tex]T_{f}[/tex] = 22.6 ° c

It is given that heat lost by the object = heat gain by the water

⇒ [tex]m_{obj}[/tex] [tex]C_{obj}[/tex] ( [tex]T_{obj}[/tex] - [tex]T_{f}[/tex] ) =  [tex]m_{w}[/tex] [tex]C_{w}[/tex] ( [tex]T_{f}[/tex] - [tex]T_{w}[/tex])

Put all the values in above formula we get

⇒ 23.2 × [tex]C_{obj}[/tex] ( 97 - 22.6 ) = 90 × 4.18 × ( 22.6 - 20.5 )

⇒ [tex]C_{obj}[/tex] = 0.457 [tex]\frac{KJ}{kg K}[/tex]

This is the specific heat of the object.

Answer: iron (II) Chloride can be used instead of AlCl3

Explanation:

Friedel–Crafts alkylation reaction involves the introduction of alkyl group in  an aromatic ring with an alkyl halide using a strong Lewis acid, such as aluminium chloride, ferric chloride, or other MXn reagent, as catalyst.

The function of AlCl3​ or fecl3 in Friedel-Craft reaction, is to produce electrophile, which later adds to benzene ring. This electrophilic aromatic substitution allows the synthesis of monoacylated products from the reaction between arenes and acyl chlorides or anhydrides. The products are deactivated and do not undergo a second substitution. Normally, a stoichiometric amount of the Lewis acid catalyst is required for both the substrate and the product form complexes.

AlCl3​ or fecl3 (and other Lewis acids like it) will coordinate to halogens, and facilitate the breaking of these bonds. In doing so, it increases the electrophilic nature of its binding partner, making it much more reactive as to complete the reaction.

The First 2 statements stated above were false whereas the third one is a true statement.

Explanation:

Reason - The viscosity of bitumen is about not 100 times greater than the viscosity of water, it is actually 100, 000 times greater.

Reason- Oil from oil sand deposits is not obtained by first heating the sands at high temperatures but by using steams

Answer:

B. Increasing atmospheric carbon dioxide will cause mean global temperature to increase by 2 degrees Celsius over the next century.

Explanation:

By definition, a hypothesis is a tentative statement or prediction with little or no experimental test. Hypotheses are always formulated such that they can be rejected if experimental findings are against them.

Hypotheses are predictive and as such, the tone is often in future tense.

From the available options, only option B sound predictive of what might happen in the future.

Hence, the correct option is B.