What is the minimum diameter mirror on a telescope that would allow you to see details as small as 5.20 km on the moon some 384000 km away? Assume an average wavelength of 550 nm for the light received.
cm

Answer: we can conclude that the wavelength is decreasing. This means that the star is moving towards the observer on earth.

Explanation:

Since light has a constant speed of 3 x 10^8m/s, and this speed is a product of its wavelength and its frequency c = f¥

Where f is the frequency and ¥ is the wavelnght.

For a decreasing wavelength, it is seen that the frequency is increasing.

According to the doppler's effect, a moving body that is a source of a wave of frequency f, moving relatively towards an observer, the frequency will increase as they move closer to a frequency f' which is greater than f. This is known as the doppler shift of light wave.

Answer:

0.467 Hz

Explanation:

Wave properties are related thus

v = fλ

v = velocity of the wave = ?

f = 0.30 Hz

λ = wavelength = 30 m

v = 0.3×30 = 9.0 m/s

But if the boat is now moving at 5.0 m/s in the direction of the oncoming wave,

The speed of the wave relative to the boat = 9 - (-5) = 14.0 m/s

f = (v/λ) = (14/30) = 0.467 Hz

Hope this helps!

Answer:

The answer to the question is;

The boat’s vertical oscillation frequency if you drive the boat at 5.0 m/s in the direction of the oncoming waves moving at 9 m/s in the opposite direction is  0.467 Hz.

Explanation:

We note the frequency of the water wave = 0.3 Hz

Distance between crests or wavelength of water wave  = 30 m

Speed v of a wave is given by Frequency f × Wavelength λ

Therefore the speed of the wave = f·λ = 0.3 × 30 = 9 m/s

(b)  Distance between crests = 30 m = wavelength λ

     Boat speed                       = 5.0 m/s v

Speed of the wave with respect to the boat = 5 + 9 = 14 m/s

From the wave speed relationship, we have

v = fλ    f = [tex]\frac{v}{\lambda}[/tex] =[tex]\frac{14}{30} = \frac{7}{15}[/tex] = 0.467 Hz which is high.

Answer:

Explanation:

UR MOM SUCKQ

Answer: 110km/h

100+10=110km/h

Explanation:

Motion is defined as a change of position. The frame of reference is usually assumed to be at rest. If one is sitting on a bus, the road appears to be moving backwards relative to the observer. If he/she now walks to the front of the bus, he has a speed relative to the earth which is now greater than that of the bus hence the answer.

Your speed relative to the road, when walking from the back to the front of a bus moving at 100km/h, is 110km/h.

Your speed relative to the road outside in this scenario will be the sum of the speed of the bus and your own speed walking within the bus. The bus is moving at 100 km/h, and you're moving toward the front of the bus at 10 km/h. Because you're moving in the same direction as the bus, you add your speeds together. Hence, your speed relative to the road outside would be 100 km/h (bus) + 10 km/h (you) = 110 km/h.

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Answer: MOTION

Explanation:

motion is defined as the displacement of an object with respect to time relative to a stationary object (reference point). A good example of an object that can serve as a reference point includes: a tree or a building. The movement of a body at constant speed towards a particular direction at regular intervals of time can be determined and it's called uniform motion.

There are different types of motion, these includes: simple harmonic motion,

linear motion,

circular motion,

Brownian motion,

Rotatory motion

Answer:rest

Explanation:

Answer: 87KN

Explanation: F= m(v-u)/t

V= h/t

V= 60/0.0100

v= 6000m/s

M=145g/1000=0.145kg

F= 0.145*6000/0 .001

F= 87000N

F= 87KN

Answer:

d. ΔU = q + w

Explanation:

Internal energy is the sum of kinetic energy (which comes from motion of molecules) and potential energy ( which comes from chemical bonds between atoms and other intermolecular forces that maybe present).

First law of thermodynamics states that: "the change in internal energy of a closed system is equal to the energy added to it in form of  heat(q) and work (w) done on the system by the surroundings.

Mathematically written as:

[tex]E_{internal}[/tex] = q + w

Conventionally, the first law is based on the system doing work and the surrounding doing work.

[tex]E_{internal}[/tex] can also be written as ΔU.

Therefore [tex]E_{internal}[/tex] = ΔU = q + w

ΔU = q + w

Answer : 0.814 newton

Explanation:

force (magnetic) acting on the wire is given by

F= ? , I=2.2amp , B = 0.37 T

F = B i l sin (theta) = 0.37 x 2.2 x 2x 0.5 = 0.814N

A straight wire segment 2 m long makes an angle of 30degrees with a uniform magnetic field of 0.37 T. The magnitude of the force is

F= 0.814N

Generally, the equation for the magnitude of the force is  mathematically given as

[tex]F = B i l sin (\theta)[/tex]

Therefore

F= 0.37 x 2.2 x 2x 0.5

F= 0.814N

In conclusion, the magnitude of the force

F= 0.814N

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Answer:

d. epicentral distance scale

Explanation:

The depth of focus from the epicenter, called as Focal Depth, is an important parameter in determining the damaging potential of an earthquake. Most of the damaging earthquakes have shallow focus with focal depths less than about 70km. Distance from epicenter to any point of interest is called epicentral distance

Explanation:

Given:

u = 20 m/s

a = 5 m/s^2

v = 30 m/s

t = ?

Use the first kinematic equation of motion:

v = u + at

t = (v - u)/a = 10/5 = 2 seconds

Eddie will take 2 sec to reach a speed of 30 m/s

What is velocity ?

velocity is defined as rate of change of displacement of the object with respect to rate of change in time. In mathematics It is written as :

                                          [tex]\begin{aligned}v&=\frac{\Delta d}{\Delta t}\end{aligned}[/tex]

Here it is given that :

initial speed of car (u) = 20 m/s

acceleration of car (a) = 5 m/s²

final speed of car (v) = 30 m/s²  

it is to find the time t to achieve this speed which is calculated using the first equation of motion:

[tex]\begin{aligned}v&=u+at\\30&=20+5t\\&t=\frac{10}{5}\\&=2\text{\:sec}\end{aligned}[/tex]

Therefore, Eddie will take 2 sec to reach a speed of 30 m/s

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Explanation:

Below is an attachment containing the solution.

Answer:

Work done = 100 J

Explanation:

Given:

Distance moved by the box (d) = 10 m

Parallel force acting on it [tex](F_1)[/tex] = 10 N

Perpendicular force acting on it [tex](F_2)[/tex] = 5 N

Work done is the product of force and displacement along the line of action of force.

So, the perpendicular force doesn't do any work and it's only the parallel force that does work as the displacement caused is along the parallel force direction.

So, work done is given as:

[tex]Work=F_1\times d\\\\Work=10\ N \times 10\ m \\\\W=100\ J[/tex]

Therefore, work done is 100 J.

Options to the question :

A- blood viscosity

B- osmolarity of interstitial fluid

C- turbulence

D-length of a blood vessel

E- blood vessel diameter

Answer:

Total peripheral resistance is NOT related to B ( osmolarity of interstitial fluid).

Explanation:

Total peripheral resistance( also called systemic vascular resistance) is defined as the total opposition to the flow of blood in systemic circulation. Increase in total peripheral resistance leads to high blood pressure while it's decrease leads to low blood pressure. Factors that contributes to total peripheral resistance in systemic circulation includes:

- blood vessel diameter

- blood viscosity,

- lengthy of a blood vessel and

- turbulence.

Answer:

Moisture content

Explanation:

Air mass is a volume of air spread through a vast area may it cover hundred to thousand Kilometers and is identified on the basis of nearly equal temperature and water vapour content of the air thorough out the area.

Answer:

After 1 second and after 3 seconds.

Explanation:

the amount of medicine in time t is given by A = -40t2 + 160t.

To know the time when the amount of medicine will be 120 micrograms, we need to make the expression A equals 120, and then find the value of t:

120 = -40t2 + 160t

-40t2 + 160t - 120 = 0

dividing everything by -40, we have

t2 - 4t + 3 = 0

we have a second order equation, and to find its roots, we can use the baskhara formula:

D = b2 -4ac = 16 - 12 = 4.

The square root of D is +2 or -2

t_1 = (4 + 2)/2 = 3

t_2 = (4 - 2)/2 = 1

We have two values of t, both acceptable. So, after 1 second and after 3 seconds of the inhalation, there will be 120 micrograms of medicine in the bloodstream.

The time after inhalation when there will be about 120 micrograms of medicine in the bloodstream is approximately 2 minutes.

The equation given is A = -40t^2 + 160t. To find the time, 't', when the amount of medicine in the bloodstream is 120 micrograms, we should set 'A' equal to 120 and solve for 't'. So, 120 = -40t^2 + 160t. Simplify this equation to 40t^2 - 160t + 120 = 0. Here, you can observe that all terms are divisible by 10, thus simplifying it further gives 4t^2 - 16t + 12 = 0. Splitting the middle term, we get 4t^2 - 8t - 8t + 12 = 0. On factorizing, we get 4t(t - 2) - 4(2t - 3) = 0. Hence, (4t-4)(t-2) = 0, implies that t = 1 or t = 2. Since 't' cannot be negative, t = 1 minute is invalid in this context (as the amount of medicine isn't enough), we have t = 2 minutes as the valid solution.

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Answer:

Acceleration = 1.428m/s2

Tension = 102.85N

Explanation:

The detailed solution is attached

Answer:

The acceleration of the system is 1.401 m/s² and

The tension in the cord is 100.902 N

Explanation:

Let the 9 kg mass be m

Let the 12 kg mass be M

By Newton's second law of motion we have

For the 9 kg mass, T - mg = ma and for the 12 kg mass we have T - Mg  = -Ma

Here we took the upward acceleration as positive a of the 9 kg mass and the downward acceleration of the 12 kg mass as -a

Solving for T for the 9 kg mass we have

T = mg + ma

Substituting  the value of T in to the 12 kg mass equation, we have

mg + ma - Mg = -Ma or  a = [tex](\frac{M-m}{M+m} )g[/tex] therefore the acceleration is

1.401 m/s²

and the tension is T = mg + ma = 9×(9.81+1.401) = 100.902 N

Answer:

option A.

Explanation:

given,

rate constant. k = 0.241/min

[A_0] = 0.859 M

[A_t] = ?

t = 10 minutes.

using first order reaction formula

[tex]k=\dfrac{2.303}{t}log(\dfrac{[A_0]}{[A_t]})[/tex]

[tex]0.241=\dfrac{2.303}{10}log(\dfrac{[0.859]}{[A_t]})[/tex]

[tex]log(\dfrac{[0.859]}{[A_t]}) = 1.0464[/tex]

[tex]\dfrac{[0.859]}{[A_t]} = 11.129[/tex]

[tex][A_t]=\dfrac{0.859}{11.129}[/tex]

[tex][A_t]=0.0772\ M[/tex]

the concentration of A after 10 minutes is equal to 0.0772 M.

Hence, the correct answer is option A.

The isochoric process involving a gas at constant volume undergoes a temperature change from 270 K to 378 K, resulting in a change in internal energy of approximately 40.4 kJ.

1. Identify the process:

This problem describes an isochoric process, meaning the volume of the gas remains constant throughout the pressure change. Since the volume doesn't change, we can utilize the pressure-temperature relationship for ideal gases.

2. Apply the pressure-temperature relationship:

The pressure-temperature relationship for an ideal gas at constant volume is:

P₁V₁ = P₂V₂

where:

P₁ is the initial pressure

V₁ is the initial volume (constant in this case)

P₂ is the final pressure

V₂ is the final volume (constant in this case)

Since the volume remains constant, we can rewrite the equation as:

P₁ = P₂ * (T₁ / T₂)

where:

T₁ is the initial temperature (270 K)

T₂ is the final temperature (unknown)

3. Solve for the final temperature:

We are given that the final pressure (P₂) is 1.4 times the initial pressure (P₁). Substitute this information into the equation:

P₁ = 1.4 * P₁ * (T₁ / T₂)

Simplify the equation:

1 = 1.4 * (T₁ / T₂)

Solve for T₂:

T₂ = 1.4 * T₁

T₂ = 1.4 * 270 K

T₂ = 378 K

4. Calculate the change in internal energy:

For an ideal gas at constant volume, the change in internal energy (ΔU) is given by:

ΔU = n * Cv * ΔT

where:

n is the number of moles (30 mol)

Cv is the heat capacity at constant volume (unknown)

ΔT is the change in temperature (T₂ - T₁)

5. Relate Cv and Cp:

We are given the heat capacity at constant pressure (Cp) as 32.0 J/(mol*K). However, we need Cv for the internal energy calculation. We can utilize the relationship between Cv and Cp for ideal gases:

Cv = Cp - R

where:

R is the gas constant (8.314 J/(mol*K))

Substitute the given value of Cp:

Cv = 32.0 J/(mol*K) - 8.314 J/(mol*K)

Cv = 23.686 J/(mol*K)

6. Calculate the change in internal energy:

Now, substitute all the known values into the equation for ΔU:

ΔU = 30 mol * 23.686 J/(mol*K) * (378 K - 270 K)

ΔU = 40429.8 J

7. Convert to kilojoules and round the answer:

Convert the answer to kilojoules:

ΔU = 40429.8 J / 1000 J/kJ

ΔU ≈ 40.4 kJ

Therefore, the change in internal energy of the gas is approximately 40.4 kJ.

Answer:

Therefore the average thermal power is = 19.61 W

Explanation:

Given that the mass of the rock = 20.0 kg

initial velocity (u) = 8.00m/s

Final velocity = 0

Kinetic fiction [tex](\mu_k)[/tex] = 0.20.

Friction force = Kinetic fiction× weight

                      =[tex]\mu_k mg[/tex]

Force = mass × acceleration

[tex]\Rightarrow acceleration =\frac{Force}{mass}[/tex]

                        [tex]=-\frac{\mu_kmg}{m}[/tex]

                        [tex]=-\mu_kg[/tex]

To find the time , we use the the following formula,

v=u+at

Here a [tex]=-\mu_kg[/tex]

[tex]\Rightarrow 0=8+(-\mu_kg)t[/tex]

[tex]\Rightarrow 0.20 \times 9.8\times t=8[/tex]

⇒t = 4.08 s

Now,

Thermal energy= work done by friction = change of kinetic energy

The change of kinetic energy

= [tex]\frac{1}{2} mu^2-\frac{1}{2} mv^2[/tex]

[tex]=\frac{1}{2}\times 20\times 8 -\frac{1}{2}\times 20\times 0[/tex]

=80 J

Thermal energy=80 J

Thermal power = Thermal energy per unit time

                          [tex]=\frac{80}{4.08}[/tex] w

                         =19.61 W

Therefore 19.61 W average thermal power is produced as the rock stops.

Answer:

Explanation:

Given

Spring force constant [tex]k=5\ N/m[/tex]

Relaxed length [tex]l_0=2.59\ m[/tex]

mass is attached to the end of spring and allowed to come at rest with relaxed length [tex]l_2=3.86\ m[/tex]

Potential energy stored in the spring

[tex]U=\frac{1}{2}k(\Delta x)^2[/tex]

[tex]\Delta x=l_2-l_0[/tex]

[tex]U=\frac{1}{2}\times 5\times (3.86-2.59)^2[/tex]

[tex]U=4.03\ J[/tex]

Answer: Internetwork

Explanation:

Internetworking is the process of connecting different networks together by the use of intermediary devices such as routers or gateway devices. Internetworking helps data communication among networks owned and operated by different bodies.

Answer:

Internetwork

Explanation:

Internetwork involves having a central network system which is shared into other systems and location through the help of intermediary devices such as routers. This usually helps to increase the orderliness and precision by which data is shared between the various connections.

The magnitude of the attractive force on each one will be F.

Explanation:

As two small balls are experiencing gravitational force between them ,then they will obey universal law of gravity. As per the universal law of gravity, the gravitational force acting between two objects will be directly proportional to the product of the masses of the objects and inversely proportional to the square of the distance between the two objects.

So if the mass of the two small balls A and B are considered as M and m, respectively, with the distance of separation be considered as r. Then the gravitational force of attraction acting between A and B will be

[tex]F = \frac{GMn}{r^{2} }[/tex] , This is the original or initial gravitational force between A and B.

Now, if the masses of A and B are doubled, then the new masses will be M' = 2 M and m' = 2m, respectively. Similarly, if the separation of the balls is also doubled then r' = 2r. So the new gravitational force exerting between A and B is

[tex]F' = \frac{GM'm'}{r'^{2} } = \frac{G*2M*2m}{(2r)^{2} } =\frac{4GMm}{4r^{2} } = \frac{GMm}{r^{2} }=F[/tex]

So after doubling the masses as well as the distance of separation, there will be no change in the gravitational force. So the magnitude of the attractive force on each one will be F.

Answer:

Incomplete questions

This is the complete question

The half-life of a radioactive isotope is the time it takes for a quantity for the isotope to be reduced to half its initial mass. Starting with 150 grams of a radioactive isotope, how much will be left after 6 half-lives

Explanation:

Let analyse the question generally first,

The the mass of the radioactive element be M.

We want to know it mass after n half life

Then,

After first half life, it mass is

M1=M×½

After second half life, it mass is

M2= M×(½)²

After third half life, it mass is

M3= M×(½)³

But now we can see a pattern developing, because for each new half-life we are dividing the quantity by 2 to a power that increases as the number of half-lives.

Then we can take the original quantity and quickly compute for

nth half-lives:

So after nth half life will be

Mn= M × (½)ⁿ

Generally,

Now, let apply it to our questions

Give that the mass of the radioactive isotope is 150grams

It mass after 6th half life

Then, n=6

So applying the formula

Mn= M × (½)ⁿ

M6= 150 ×(½)^6

M6= 150×1/64

M6=2.34grams

The mass of the radioactive isotope after 6th half life is 2.34grams

Answer:

[tex]x=4.2\ mm[/tex]

Explanation:

Given:

Change in length due to temperature can be  given as:

[tex]\Delta l=l.\alpha.(T_u-T_l)[/tex]

[tex]\Delta l=12\times 10^{-5}\times (50-(-30))[/tex]

[tex]\Delta l=0.0096\ m=9.6\ mm[/tex]

Now at temperature 15°C:

[tex]\Delta l'=12\times 10^{-5}\times (15-(-30))[/tex]

[tex]\Delta l'=0.0054\ m=5.4\ mm[/tex]

Hence the expansion crack between the slabs at this temperature must be:

[tex]x=\Delta l-\Delta l'[/tex]

[tex]x=9.6-5.4[/tex]

[tex]x=4.2\ mm[/tex]

Answer:

a) 38.3mA

b) 109.396A/m^2

c) 1.283cm/s

d) 226.582V/m

Explanation:

The equation for current is given by:

I = V/R = 35.6/ 935 = 0.03829 A Approximately 38.3mA

b) The equation to find the magnitude is given by:

J = I/A = 0.03829/ 0.000350m^2

J = 109.396A/m^2

c) The equation to calculate drift velocity of the electron is given by: Vd = J/ ne = 109.396/( 5.33×10^23 )(1.60×10^-19)

Vd = 0.01283 approximately 1.283cm/s

d) The magnitude of electric field in the block, E = V/L = 35.8/ 0.158m = 226.582V/m

Answer:

The correct answer is

a little less than 15 km/s.

Explanation:

The distance between the sun and Jupiter varies by about 75 million km between the perihelion and the aphelion with an average distance of 778 million km from the sun for which it takes Jupiter about 12 years to complete its orbit round the sun giving it an orbital speed of about 13.07 km/s

The size of Jupiter is more than the twice the combined size of all the other planets, which is about 1.300 times the size of earth.

Jupiter is orbiting the Sun from b. 15 km/s.

Jupiter orbits the Sun at an average distance (semi-major axis) of about 5.2 Astronomical Units (AU), where 1 AU is the average distance from the Earth to the Sun, approximately 149.6 million kilometers.

Using Kepler's third law of planetary motion and the fact that Jupiter takes approximately 11.86 Earth years to complete one orbit around the Sun, we can estimate its average orbital speed. The orbital speed (v) of a planet can be roughly calculated by the formula:

[tex]v = \frac{2 \pi r}{T}[/tex]

where:

Converting the semi-major axis from AU to kilometers:-

[tex]r = 5.2 \times 149.6 \times 10^6 \text{ km} \\= 777.92 \times 10^6 \text{ km}[/tex]

Converting the orbital period from years to seconds:

[tex]T = 11.86 \text{ years} \times 3.154 \times 10^7 \text{ seconds/year} \\= 3.74 \times 10^8 \text{ seconds}[/tex]

Now, plugging in these values to our formula:

[tex]v = \frac{2 \pi \times 777.92 \times 10^6}{3.74 \times 10^8} \text{ km/s} \\\approx 13.07 \text{ km/s} \ {or} 15 km[/tex]

Answer:

If the same volume of air is inhaled and exhaled, the air we breathe out normally weighs more than the air we breathe in.

Since the output from the body normally exceeds the input, breathing leads to weight loss.

Explanation:

If equal volumes of gas is inhaled and exhaled, the exhaled gas is heavier.

The inhaled gas contains Oxygen and majorly Nitrogen.

The exhaled gas contains CO₂, H₂O and a very large fraction of the unused inhaled air that goes into the lungs.

So, basically, the body exchanges O₂ with CO₂ and H₂O (and some other unwanted gases in the body) in a composition that CO₂, the heavier gas of the ones mentioned here, is prominent.

So, because the mass leaving the body is more than the mass entering, breathing leads to a loss of weight. This is one of the reasons why we need food for sustenance. Breathing alone will wear one out.

Final answer:

The air we exhale likely has less mass than the air we inhale due to the replacement of dense oxygen with less dense carbon dioxide and water vapor.

Explanation:

When we inhale, we take in air that is rich in oxygen, and when we exhale, we expel air with a higher concentration of carbon dioxide and water vapor. Given that a liter of oxygen weighs more than the same volume of water vapor, and we replace some of the oxygen with the less dense carbon dioxide, the air we exhale likely has less mass than the air we inhale.

The breathing process does result in weight loss, but only in small amount attributable to the exhaled carbon dioxide which comes from the metabolic processes in the body. As for the volume and density of our bodies, taking a deep breath increases the volume, but because the density of air is much smaller than that of the body, the overall density decreases.

During gas exchange, oxygen flows from the bloodstream into the body's cells, while carbon dioxide flows out of the cells into the bloodstream to be expelled. This process is driven by the differing partial pressures of oxygen and carbon dioxide in the blood and the cells, facilitating diffusion across the cellular membrane.

Answer:

[tex]w_c[/tex] = 28 mm

Explanation:

Displacement from the central maximum to minimum is as deterrmined as follows;

[tex]y_m[/tex] = [tex]\frac{m \lambda D}{a}[/tex]

If first minimum (m) = 1

single- Slit width is 170 times the wavelength of the light.

i.e

a = 170 λ

[tex]y_1[/tex]  = [tex]\frac{(1) \lambda (2,.4m)}{170 \lambda}[/tex]

[tex]y_1[/tex]  = 0.014 m

width of the central maximum can now be determined as:

[tex]w_c[/tex] = [tex]2y_1[/tex]

[tex]w_c[/tex] = 2(0.014 m)

[tex]w_c[/tex] = 0.028 m

[tex]w_c[/tex] = 28 mm

Hence, the width (in mm) of the central maximum on a screen 2.4 m behind the slit

= 28 mm

The width of the central maximum in a single-slit experiment is calculated by deriving the angle of the first minimum using light wavelength and slit width, and then applying it to the distance to the screen. The resulting value is an estimation.

In a single-slit experiment, the width of the central maximum can be calculated with the use of physics and understanding of light's behavior. The primary formula that guides this phenomenon is given as sin θ = λ/a, where θ is the angle of the first minimum, λ is the wavelength of the light, and a is the width of the slit. Given that the slit width is 170 times the wavelength of the light, the angle of first minimum will be very small and approximated as θ = λ/a.

Now, the angular width of the central maximum would be twice this angle in radians (θ), as the central maximum extends θ on either side of the central point. To find the actual width in mm on a screen 2.4 m away, you would multiply the total angular width (2*θ) by the distance of the screen (L) behind the slit, i.e. W = 2*θ*L. Please note that this is an approximation that widely works when the angle θ is small.

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Explanation:

The work done on the body = force applied x displacement

in this case , the acceleration of body a = [tex]\frac{Force}{Mass}[/tex] = [tex]\frac{4.9}{14}[/tex] = 0.35 ms⁻²

The displacement in first second S₁ = u + [tex]\frac{1}{2}[/tex] a x t²

here u = 0 , because body was at rest

Thus S₁ = [tex]\frac{1}{2}[/tex] x 0.35 x ( 1 )² = = 0.175 m

The work done = 4.9 x 0.175 =  0.86 J

The displacement in 2 seconds = [tex]\frac{1}{2}[/tex] x 0.35 x ( 2 )² = 0.7 m

Work done in 2 seconds = 4.9 x 0.7 = 3.43 J

Work done in second second = 3.43 - 0.86 = 2.57 J

The displacement in three seconds = [tex]\frac{1}{2}[/tex] x 0.35 x ( 3 )² = 1.575 m

Work done in three seconds = 4.9 x 1.575 = 7.7 J

Work done in third second = 7.7 - 3.43 = 4.3 J

The power at the end of third second is 4.3 watt

Because 4.3 J of work is done in the last second .

Answer:

Number of revolution made by tire is 1.57 x 10⁷

Explanation:

Radius of tire, r = 0.220 m

Circumference of tire, C = 2πr

Substitute the value of r in the above equation.

C = 2 x π x 0.220 m = 1.38 m

Total distance covered by tire in a year, D = 13500 miles

But 1 mile = 1609.34 m

So, D = 13500 x 1609.34 m

Number of revolutions take by tire, N = [tex]\frac{D}{C}[/tex]

[tex]N=\frac{13500\times1609.34}{1.38}[/tex]

N = 15743543