The initial velocity of go-kart is 2.5 m/s.
Explanation:
Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.
In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.
As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.
[tex]Acceleration = \frac{Final velocity -Initial velocity}{Time}[/tex]
Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,
[tex]-0.5=\frac{-\text {Initial velocity}}{5}[/tex]
Initial velocity = 0.5 × 5 = 2.5 m/s.
So the initial velocity of go-kart is 2.5 m/s.
Why does a crumpled paper land before a flat sheet of paper?
Answer:
The crumpled paper hits the ground first due to air resistance. The crumpled paper has less surface area than the flat paper, therefore the crumpled paper hits first.
I hope this helped. If you could mark brainliest that would be greatly appreciated.
Answer:
Crumpled paper
Explanation:
because it has less surface area than flat paper and resistance force is not acting on it
An object has a mass of 1kg on Earth. What is its weight on the moon?
Answer:
the Mass of 1 kg object is same in Earth & Moon.
Explanation:
Weight, on the otherhand does change with location depends on the gravity. so the answer is : Weight of one kilo on the surface of moon is 1.622 N. A body is taken from the center of the Earth to the Moon.
The weight on moon will be 166.66 grams.
We have a object on earth.
We have to identify its weight on moon.
What is weight ?Weight is a force acting on the body directed towards the center of earth and is the product of mass and acceleration due to gravity.
W = mg
According to the question -
Mass on earth = 1 Kg = 1000 grams
Now, the weight on moon is 1/6 of that of weight on earth. Therefore -
W(M) = [tex]$\frac{1}{6}[/tex] W(E)
Therefore -
W(M) = [tex]\frac{1}{6}[/tex] x 1000 = 166.66 grams
Hence, the weight on moon will be 166.66 grams.
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Matter is anything that has
Answer:
Space
Explanation:
Hope this helped
Answer:
VOLUME AND MASS IF U ;LOOK AT THE OTHERGUIYS ANSWER IS SPACE WHICH IS CORRECT BUT MY ANSSIGNMENT DOES NOT HAVE THAT ANSWER SO ITS VOLUME AND MASS
Explanation:
which refers to the measure of the amount of water vapor in yhe air?
Answer:
The amount of water vapor in the air is called absolute humidity. The amount of water vapor in the air as compared with the amount of water that the air could hold is called relative humidity. This amount of space in air that can hold water changes depending on the temperature and pressure.
The amount of water vapor in the air is represented by the term 'relative humidity'. This is the ratio of the current amount of water vapor to the maximum amount that the air could hold at that temperature, typically expressed as a percentage. The saturation point or the temperature at which the relative humidity becomes 100% is known as the 'dew point'.
Explanation:The measure of the amount of water vapor in the air refers to the concept of relative humidity. This is the ratio of the current amount of water vapor in the air (vapor density) to the maximum amount the air can hold at that temperature (saturation vapor density).
Relative humidity is expressed as a percentage. For example, if the air contains 9.40 g/m³ of water vapor, we would look up the saturation density for the current temperature. Let's say at 10.0°C, the saturation density is 9.40 g/m³. This means the air is holding as much water vapor as it can at that temperature, so the relative humidity is 100%. This temperature is known as the dew point.
As another example, if the air temperature rises or falls, it can change the amount of water vapor the air can hold, and thus change the relative humidity. This is why relative humidity often changes over the course of a day as the air temperature changes.
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A 0.300 kg mass is attached to
a 26.6 N/m spring. It is pulled
0.120 m and released. What is
the speed of the mass when it is
0.0600 m from equilibrium?
(Unit = m/s)
To calculate the speed of the 0.300 kg mass when it is 0.0600 m from equilibrium on a 26.6 N/m spring, use the conservation of energy principle to find the kinetic energy at that point and then solve for velocity.
Explanation:The problem involves a 0.300 kg mass attached to a spring with a force constant of 26.6 N/m. The mass is pulled 0.120 m from equilibrium and released. To find the speed of the mass when it is 0.0600 m from equilibrium, we can use the principle of conservation of energy. The total mechanical energy is conserved because we are ignoring any external forces like friction or air resistance.
Initially, when the mass is released from 0.120 m, the spring has some potential energy (due to being stretched) and the kinetic energy is zero since it's released from rest. When the mass is at 0.0600 m from equilibrium, there is a combination of potential energy (due to being displaced from equilibrium) and kinetic energy (since the mass is moving).
The initial potential energy (PEi) stored in the spring can be calculated using the formula PEi = 1/2 * k * x2, where k is the spring constant and x is the initial displacement. The final potential energy (PEf) is calculated similarly, with x being the final displacement of 0.0600 m.
The difference between the initial and final potential energy will give us the kinetic energy at 0.0600 m from equilibrium, since energy is conserved and the difference must have been converted to kinetic energy. The kinetic energy (KE) can be expressed as KE = 1/2 * m * v2, where m is the mass and v is the velocity we want to find.
Here's how you would set up the equations:
Calculate the initial potential energy: PEi = 1/2 * 26.6 N/m * (0.120 m)2.Calculate the final potential energy: PEf = 1/2 * 26.6 N/m * (0.0600 m)2.Find the kinetic energy at 0.0600 m by subtracting the final potential energy from the initial potential energy.Finally, solve for v in the kinetic energy equation to get the velocity of the mass at 0.0600 m from equilibrium.The speed of a 0.300 kg mass attached to a 26.6 N/m spring, when it is 0.0600 m from equilibrium, is approximately 0.978 m/s. This was determined using principles of energy conservation. Initial potential energy was converted to kinetic energy to find the speed.
Given a 0.300 kg mass attached to a spring with a force constant (k) of 26.6 N/m, we can determine the speed when the mass is 0.0600 m from equilibrium using energy conservation principles. Initially, the mass is pulled 0.120 m from equilibrium and released.
We start by calculating the total mechanical energy of the system at the maximum displacement (0.120 m):
Potential Energy (PEmax) = 1/2 k xmax²
PEmax = 1/2 x 26.6 N/m x (0.120 m)²
PEmax = 1/2 x 26.6 x 0.0144
PEmax = 0.19152 J
At the position where the mass is 0.0600 m from equilibrium, the potential energy is:
PE = 1/2 k x²
PE = 1/2 x 26.6 N/m x (0.0600 m)²
PE = 1/2 x 26.6 x 0.0036
PE = 0.04788 J
The difference in energy will be converted into kinetic energy (KE):
KE = PEmax - PE
KE = 0.19152 J - 0.04788 J
KE = 0.14364 J
Using the kinetic energy formula (KE = 1/2 mv²), we solve for the speed:
0.14364 J = 1/2 x 0.300 kg * v²
0.14364 = 0.150 x v²
v² = 0.14364 / 0.150
v² = 0.9576
v = √0.9576
v ≈ 0.978 m/s
Thus, the speed of the mass when it is 0.0600 m from equilibrium is approximately 0.978 m/s.
A student has a mass (including clothes and shoes) of 65.0 kg. She drinks a 12 oz. can of soda, with a nutritional energy content of 140 Cal. Assuming that the efficiency of her muscles is 20%, how high can she climb without losing weight?
Conversion: 1 Cal = 1,000 cal = 4,180 J
She can climb 0.92 m without losing weight.
Explanation:
Gravitational potential energy is the energy consisting of the product of mass, gravity and height.
1 cal = 4184 J
140 cal = 585760 J
Energy = 585760 J, m = 65.0 kg = 65000 g, Efficiency = 20 %
GPE = mgh
where m represents the mass
g represents the gravity,
h represents the height.
585760 = 65000 9.8 h
h = 0.92 m.
What is an input force?
the applied force on a system
the net force on a system
the force a simple machine applies to an object
the force a person applies to a simple machine
Answer:
The force a person applies to a simple machine
Explanation:
An input force is that variable that enters a simple machine to perform a particular job by multiplying the value of that input force.
As a typical example we can find a lever where a person introduces an input force, this force multiplies according to the mechanical advantage of the lever resulting in the work of a simple machine with more work.
Answer:
The force a simple machine applies to an system
Explanation:
why does a passenger jumping out of a rapidly moving bus fall forqard with his face downwards
Answer:
Explanation:
It's Newton's first law of motion, and object in motion continues to stay in motion unless acted upon by an unbalanced force. In this case, your body is the force that's moving on the bus. When you jump(the unbalanced force) your body is still used to being in motion, which makes you fall and not land on your feet.
2 Points
What type of electromagnetic radiation is being used in the picture?
Answer:
Ultraviolet radiation.
Paul the penguin loves to skate on ice. If he glides 40 Meters in 12 seconds toward the north’s what is Paul velocity
Paul the penguin's velocity is 3.33[tex]ms^{-1}[/tex].
Explanation:
Paul glided (displaced) 40 meters towards north.
The time he taken to displace is 12 seconds.
∴displacement d= 40m.
time t= 12s.
The speed of a body in a certain direction is the measure of Velocity.
The velocity of the an moving object is given by ratio of the rate of change in the distance by the time taken.
⇒Velocity v= [tex]\frac{displacement}{time}[/tex].
=[tex]\frac{40}{12}[/tex].
=3.33 [tex]ms{-1}[/tex].
Thus the velocity of the Paul the penguin glided on ice is 3.33 [tex]ms{-1}[/tex].
In this section of a circuit, a current of 2.6 A flows across R1. What is the potential difference V between point x and point y (across R2)? Let R1 = 4.0 ohm, R2 = 8.0 ohm, and R3 = 1.0 ohm.
Answer:
V=21V
Explanation:
In series combination current is same
I=2.6A
R2=8ohm
V2=2.6×8
V2=20.8
V2=21V
Answer:
Explanation:
21 v
What statement is true about Newton's second law?
A. When the net force of an object increases, the object's acceleration decreases.
B. When the net force of an object decreases, the object's acceleration decreases.
C. When the net force of an object decreases, the acceleration doesn't change.
D. When the net force of an object decreases, the object's acceleration increases.
Please answer quickly!
The given statement "When the net force of an object decreases, the object's acceleration decreases" is true about Newton's second law.
Answer: Option B
Explanation:
Newton’s second law of motion states that the object’s acceleration depends on two variable:
Directly proportionate to the object’s force existed Inversely proportionate to the mass of the objectsThe equation can be given as below,
Force = mass × acceleration
Hence, from the above, it is concluded that force is directly proportionate to mass and acceleration of the objects. So, when force increases both mass and acceleration increases. Similarly, if force decreases, both mass and acceleration get decreased. Therefore, the given statement in option B would be correct answer.
A vitamin called folic acid is very important for neural tube development, which is the development of the baby's
Answer:
Explanation:
Folic acid is the form of folate found in vitamin supplements and fortified foods. Fortified foods, also called enriched foods, are foods that have specific nutrients added to them.
Neural tube defect happen when the tissues and bone around the brain and spine do not grow well. Neural tube can happen in the third and fourth week after conception (the first or second week after your first missed period). This could be before you know that you are pregnant.
Folic acid lowers the risk of your unborn baby having a neural tube defect . Neural tube are a group of serious birth defects that affect a baby’s spinal cord, brain and skull. Some babies with severe Neural tube defect birth are stillborn or do not survive long after birth. Spina Bifida is the most common Neural tube defect.
hi :) In a pendulum experience , what affects the period & explanation too? Thank you sm :))
Answer:
T=2π[tex]\sqrt{l/g}[/tex] (simple pendulum)
length of the string and gravity mainly effect the pendulum period
Explanation:
I need help with this problem.
Answer:
-6, [tex]-5\frac{2}{5}[/tex], [tex]-4\frac{1}{5}[/tex]
Explanation:
The solution of answer is in the picture attached
How can stars form from dust and gasses
Answer:
A is right in my opinion
Two spheres exert a gravitational attraction on each other. Which of the following changes to this system would reduce the gravitational attraction by one half?
- Decreasing one of the masses to 1/2 of its original value
- Increasing the distance by a factor of [tex]\sqrt{2}[/tex]
Explanation:
There are no options provided, however we can still answer the question.
In fact, the magnitude of the gravitational force between two objects is given by the equation:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
We notice that:
The gravitational force is proportional to the product between the massesThe gravitational force is inversely proportional to the square of the distance between the massesTherefore, in order to reduce the gravitational attraction by one half, we can do one of the following changes:
- Decreasing one of the masses to 1/2 of its original value: for example, if [tex]m_1'=\frac{1}{2}m_1[/tex], the gravitational force becomes
[tex]F'=G\frac{m_1' m_2}{r^2}=G\frac{\frac{1}{2}m_1m_2}{r^2}=\frac{1}{2}(G\frac{m_1m_2}{r^2})=\frac{1}{2}F[/tex]
- Increasing the distance by a factor of [tex]\sqrt{2}[/tex]: in fact, if [tex]r'=\sqrt{2}r[/tex], the gravitational force becomes
[tex]F'=G\frac{m_1 m_2}{r'^2}=G\frac{m_1m_2}{(\sqrt{2}r)^2}=\frac{1}{2}(G\frac{m_1m_2}{r^2})=\frac{1}{2}F[/tex]
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Predict what would happen to an organism if food suddenly became more abundant?
Answer:
hunger or mutation
Explanation:
If food suddenly becomes more available, the population of an organism might increase (population boom), potentially face increased predation, and show altered genetic variation in future generations.
Explanation:If food suddenly became more abundant for an organism, several potential outcomes could occur, largely dependent on the specific conditions of a species' environment.
Broadly, one would expect the organism's population to increase due to increased resources for growth and reproduction. This is called a population boom. This is because with more food available, more individuals can be sustained and reproductive success may be higher.
Furthermore, if a species is heavily preyed upon and suddenly has more food available, it may face increased predation; predators may not avoid eating this suddenly more abundant prey. However, these effects can also sometimes be offset by an increased individual health and reproductive success in the prey species, allowing its population to persist or even grow despite increased predation.
Lastly, a sudden increase in food can also change the genetic variation within the population. If food was scarce and suddenly becomes abundant, organisms that were historically well-adapted for survival in harsh conditions might not be as well-adapted to the new conditions. This could potentially increase genetic variation in the future generations.
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A ball is falling after rolling off a tall roof
The ball has what type of energy.
Answer:
Linear and rotational Kinetic Energy + Gravitational potential energy
Explanation:
The ball rolls off a tall roof and starts falling.
Let us first consider the potential energy or more specifically gravitational potential energy ([tex]mgh[/tex]; [tex]m[/tex] = mass of the ball, [tex]g[/tex] = acceleration due to gravity, [tex]h[/tex] = height of the roof). This energy comes because someone or something had to do work to take the ball to the top of the roof against the force of gravity. The potential energy is naturally maximum at the top and minimum when the ball finally reaches the ground.
Now, the ball starts to roll and falls off the roof. It shall continue rotating because of inertia (Newton's first law). This contributes to the rotational kinetic energy ([tex]\frac{1}{2}I\omega^2[/tex]; [tex]I[/tex]=moment of inertia of the ball & [tex]\omega[/tex] = angular velocity).
Finally comes the linear kinetic energy or simply, kinetic energy ([tex]\frac{1}{2}mv^2[/tex]) which is caused due to the velocity [tex]v[/tex] of the ball.
QUICKLY! Help on 6 and 7, please? I don't know wHAT to do
6a) Acceleration of the bullet: [tex]1.44\cdot 10^5 m/s^2[/tex]
6b) Final velocity of the bullet: 360 m/s
7a) Acceleration of the truck: [tex]1.50 m/s^2[/tex]
7b) Net force on the truck: 54,000 N
7c) The acceleration will triple
Explanation:
6a)
The acceleration of the bullet can be found by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:
[tex]F=ma[/tex]
where
F is the force
m is the mass
a is the acceleration
For the bullet in this problem, we have
F = 3600 N (force)
m = 0.025 kg (mass of the bullet)
Therefore, the acceleration is
[tex]a=\frac{F}{m}=\frac{3600}{0.025}=1.44\cdot 10^5 m/s^2[/tex]
6b)
The motion of the bullet is a uniformly accelerated motion, so we can use the following suvat equation:
[tex]v=u+at[/tex]
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time elapsed
In this problem, we have:
u = 0 (the bullet starts from rest)
t = 0.0025 s (time)
[tex]a=1.44\cdot 10^5 m/s^2[/tex] (acceleration)
So we can solve to find v, the final velocity of the bullet as it leaves the rifle:
[tex]v=0+(1.44\cdot 10^5)(0.0025)=360 m/s[/tex]
7a)
The acceleration of a body is defined as the rate of change of its velocity:
[tex]a=\frac{v-u}{t}[/tex]
where
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
a is the acceleration
For the truck in this problem, we have
u = 0 (it starts from rest)
v = 28 m/s (final velocity)
t = 18.7 s (time elapsed)
Substituting, we find the acceleration
[tex]a=\frac{28-0}{18.7}=1.50 m/s^2[/tex]
7b)
The net force on the truck can be calculated using Newton's second law:
[tex]F=ma[/tex]
where
F is the force
m is the mass
a is the acceleration
For the truck in this problem,
m = 36,000 kg is the mass of the truck
[tex]a=1.50 m/s^2[/tex] is the acceleration
So, the net force on the truck is
[tex]F=(36,000)(1.50)=54,000 N[/tex]
7c)
We said that the relationship between the net force on the truck and its acceleration is
[tex]F=ma[/tex]
The equation can be rewritten as
[tex]a=\frac{F}{m}[/tex]
We notice that the acceleration is directly proportional to the acceleration.
Here we are told that the net force on the truck is tripled, therefore
[tex]F'=3F[/tex]
As a consequence, the new acceleration of the truck would be
[tex]a'=\frac{F'}{m}=\frac{3F}{m}=3\frac{F}{m}=3a[/tex]
So, the acceleration also triples.
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5. How are humans affecting global climate change?
Answer:
Due to the generation of carbon dioxide
Explanation:
Climate change occurs due to global warming generated by greenhouse gases. Carbon dioxide is the gas that does not leave or allow solar radiation from the sun to rise from the Earth's surface, increasing the average temperature of the planet.
Burning fossil fuels for energy generation such as coal is another source of carbon dioxide generation. The generation of energy should be directed towards the production of renewable energies, using sources such as solar and wind energy.
Please help question in photo
Answer:
A.) the car
Explanation:
hope this helped <3
what force is necessary to accelerate a 1,200kg car at a rate of 35m/s^2
Answer:
42000N
Explanation:
F=mass *acceleration
F= 1200*35
F=42000N
Juliana walks 45 meters East, 45 meters south and 45 meters north. What is her resultant displacement?
Her resultant displacement is (45 Meters East.)
She originally walks 45 meters east, then she goes south 45 meters, then north 45 meters. The south and north placements just make her go back to where her previous placements were before them. Making her 45 meters east.
Can someone pleaseeee answer this !!!!!!
Answer:
The person with locked legs will experience greater impact force.
Explanation:
Let the two persons be of nearly equal mass (say m)
The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,
[tex]v=\sqrt{2gH}[/tex]
([tex]g[/tex] = acceleration due to gravity)
which can be derived from Newton's equation of motion,
[tex]v^2=u^2+2aS[/tex]
Now, the time taken (say [tex]t[/tex] ) for the momentum ( [tex]mv[/tex] ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.
We know that,
[tex]Force=\frac{\Delta(mv)}{t}[/tex]
Naturally, the person who bends his legs will experience lesser force since [tex]t[/tex] is larger.
Bone has a Young's modulus of about
1.8 x 100 Pa. Under compression, it can
withstand a stress of about 1.58 x 10° Pa be-
fore breaking.
Assume that a femur (thigh bone) is 0.54 m
long, and calculate the amount of compression
this bone can withstand before breaking.
Answer in units of mm.
Answer: 4.74 mm
Explanation:
We can solve this problem with the following equation:
[tex]Y=\frac{stress}{strain}[/tex] (1)
Where:
[tex]Y=1.8(10)^{10} Pa[/tex] is the Young modulus for femur
[tex]stress=\frac{F}{A}=1.58(10)^{8} Pa[/tex] is the stress (force [tex]F[/tex] applied per unit of transversal area [tex]A[/tex]) on the femur
[tex]strain=\frac{\Delta l}{l_{o}}[/tex]
Being:
[tex]\Delta l[/tex] the compression the femur can withstand before breaking
[tex]l_{o}=0.54 m[/tex] is the length of the femur without compression
Writing the data in equation (1):
[tex]Y=\frac{\frac{F}{A}}{\frac{\Delta l}{l_{o}}}[/tex] (2)
[tex]1.8(10)^{10} Pa=\frac{1.58(10)^{8} Pa}{\frac{\Delta l}{0.54 m}}[/tex] (3)
Isolating [tex]\Delta l[/tex]:
[tex]\Delta l=\frac{(1.58(10)^{8} Pa)(0.54 m)}{1.8(10)^{10} Pa}[/tex] (4)
[tex]\Delta l=0.00474 m[/tex] (5) This is the compression in meters
Converting this result to millimeters:
[tex]\Delta l=0.00474 m \frac{1000 mm}{1 m}=4.74 mm[/tex]
Orange juice has a lower or higher viscosity than chocolate syrup
Answer:
Orange juice has a lower viscosity than chocolate syrup.
Explanation:
Viscosity is the measure we use to determine essentially how thick a fluid is. So, a liquid that has a high viscosity, is thicker than a liquid that has a lower viscosity. Viscosity is also benchmarked against that of water since water is considered to he the least viscous fluid. Therefore, the more "watery" the substance, the less viscous it is.
Its easy to imagine how orange juice would have a lower viscosity. When we imagine, we think about how quickly both orange juice and chocolate syrup would flow if they both were to be spilled. Basically, we would be looking at their "flow rate" where orange juice would wash away quickly while chocolate syrup would tend to stick to the surface and be slower. But lets also look why this happens. This happens because of the size of the particles. Orange juice is diluted and has a lot of water molecules which are small and can move very quickly. Chocolate syrup on the other hand is comprised of molecules that are larger and heavier and therefore take a longer time to move. So a liquid with lower viscosity is "less resistant to flow".
A softball is thrown straight up. To what height will it go if it takes 2.0 sec to reach the highest point?
Answer:
4.4 m
Explanation:
Given:
v = 0 m/s
a = -9.8 m/s²
t = 2.0 s
Find: Δy
Δy = vt − ½ at²
Δy = 0 − ½ (-9.8) (2.0)²
Δy = 4.4 m
Five 60 ohm resistors are connected in parallel. What is their equivalent resistance?
Answer:
i think the answer is 12 ohms
plz mark me as brainliest :)
Answer:
12 ohms
Explanation:
The five 60 Ohms resistance can be represented as follows:
R1 = 60 Ohms
R2 = 60 Ohms
R3= 60 Ohms
R4 = 60 Ohms
R5 = 60 Ohms
Rt =?
Since they are in parallel connections, the equivalent resistance (Rt) can be calculated as follows :
1/Rt = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5
1/Rt = 1/60 + 1/60 + 1/60 + 1/60 + 1/60
1/Rt = ( 1+1+1+1+1)/60
1/Rt = 5/60
1/Rt = 1/12
Cross multiply to express in linear form
Rt = 12 ohms
Therefore the equivalent resistance is 12ohms
A ball is falling after rolling off a tall roof. The ball has what type of energy.
Answer:
Correct answer: Kinetic energy of rotation, kinetic energy of translation and potential energy
Explanation:
Before it began to rotate it possessed potential energy. After being released from the rest it starts to roll on the roof and get kinetic energy of rotation, kinetic energy of translation along with potential energy.
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