Answer:
The answer would be [tex]7(\sqrt[5]{x^{2}y } )[/tex]
Step-by-step explanation: I got it right on Edge 2020
Here is a distribution of six observations, sorted in ascending order:4.7, 9.2, 10.9, 12.3, 16.6, 18.3The mean of this distribution is 12. What is the value of 6 sigma (xi -x with a line over it)
Answer:
0 is the answer
Step-by-step explanation:
Sarah takes a full-time position that pays $32,500 per year. The government takes out 3% for Social Security, 1.2 % for Medicare, and 14% for federal income tax. She does not live in state with state income tax.
MAMDM .A.3.a: What is her gross annual income?
Answer:
$32,500
Step-by-step explanation:
Sarah's gross income is the income amount before taxes and other deductions. It is $32,500.
i need help so much please help the attachment below is the question i need help on
Answer:
[tex]\dfrac{\sqrt[12]{55296}}{2}[/tex]
Step-by-step explanation:
Rationalize the denominator, then use a common root for the numerator.
[tex]\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\\\\=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\cdot\dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{2^{\frac{1}{4}+\frac{2}{3}}3^{\frac{1}{4}}}{2}\\\\=\dfrac{2^{\frac{11}{12}}3^{\frac{3}{12}}}{2}=\dfrac{\sqrt[12]{2^{11}3^{3}}}{2}\\\\=\dfrac{\sqrt[12]{55296}}{2}[/tex]
What is the value of x? Ik im really dumb whoops
Answer:
B. 75 Degrees
Step-by-step explanation:
A triangle is up to 180 degrees. Since you're given two angles already, you can add both of those together and subtract it from 180.
75 + 35 = 105
180 - 105 = 75
75 + 75 + 35 = 180
4. At Eagle Rock High School, the probability that a student takes theatre and choir is 0.052.
The probability that a student takes choir is 0.17. What is the probability that a student takes theatre given
that the student is taking choir?
a) 2.9 %
b) 30.6%
c) 24.2%
d) 34.4%
Answer:
B
Step-by-step explanation:
Conditional probability is:
P(A given B) = P(A and B) / P(B)
Here, P(A and B) = 0.052 and P(B) = 0.17:
P(A given B) = 0.052 / 0.17
P(A given B) = 0.306
. A new cell phone comes on the market. Sales (S, in millions) increase at a steady rate for several months then decrease at about the same rate. This can be modeled by the function
S(m)= -0.375|m-12|+15
(a) Graph the function, using correct labels and units.
(b) What is the vertex? What does the vertex mean in terms of the problem?
(c) What is the rate of change of the sales?
Answer:
(a) see below for a graph
(b) the vertex is (months, sales) = (12, 15); sales is $15M at 12 months
(c) .375 million per month increasing and decreasing
Step-by-step explanation:
(a) You can read the vertex from the equation of the function. The equation is of an absolute value function translated so its vertex is at (12, 15), and vertically scaled by a factor of -0.375. The negative scale factor means the graph will open downward.
__
(b) Since graph is of sales in millions versus months, the meaning of the vertex at (12, 15) is that sales is $15 millions 12 months after the phone comes on the market.
__
(c) If the function were written as a piecewise function, the coefficient of x would be +0.375 for x < 12 and -0.375 for x > 12. The "rate of change" is 0.375 millions per month both going up and coming down.
_____
Translation of a point on the graph of f(x) by "h" horizontal units and "k" vertical units changes the function to f(x -h) +k. That is, if you can identify the function f(x), you can read the translation from the expression f(x -h) +k. For the absolute value function |x|, the vertex is normally (0, 0). Translating it to (h, k) makes the expression be |x -h|+k, the form you see in this problem. It's not a mystery. It's just pattern matching.
If θ is an angle in standard position whose terminal side passes through (3, 4), evaluate tan(1/2)θ.
1/4
3/10
1/2
4/5
The tangent half angle formula, one of several, is
[tex]\tan \dfrac a 2 = \dfrac{1 - \cos a}{\sin a}[/tex]
We have θ is opposite 4 in the 3/4/5 right triangle so
[tex]\cos \theta = \dfrac{3}{5}[/tex]
[tex]\sin \theta = \dfrac{4}{5}[/tex]
[tex]\tan \dfrac{\theta}{2} = \dfrac{1 - 3/5}{4/5} = \dfrac{5-3}{4}=\dfrac{1}{2}[/tex]
Answer: 1/2
This is actually pretty deep. It says half the big acute angle in the 3/4/5 triangle is the small diagonal angle of the 1x2 rectangle. Similarly, the small acute angle in 3/4/5 triangle is twice the small diagonal angle of the 1x3 rectangle.
To find the value of tan(1/2)θ, we calculate θ using the fact that tan(θ) = opposite/adjacent = 4/3, then apply the half-angle formula from trigonometry. We cannot complete the calculation as we don't have the exact cosine value of θ.
Explanation:The question asks to find the value of tan(1/2)θ where θ is an angle in standard position, and its terminal side passes through the point (3, 4). In this case, first, we need to find the value of θ. This can be found using the formula tan(θ)=opposite/adjacent. Given the point (3, 4), let's consider the coordinates as (x,y). Here, 3 is the x-coordinate, which acts as the adjacent side, and 4 is the y-coordinate, which acts as the opposite side. Therefore, θ=tan^-1(4/3).
To find the value of tan(1/2)θ, we can use the half-angle formula from trigonometry: tan(1/2)θ = √((1-cos(θ))/(1+cos(θ)))
However, this question does not provide enough information to determine which option is the solution, as the cosine of θ is needed for completing the calculation.
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Bracket answer to each box to complete the paragraph proof triangle ABC Pro ma equals 66 2/3 on the unit test reasoning and proof
Answer:
889
Step-by-step explanation:
The required proof that the measure of the angle A is 60° is below in the solution part.
What is a Triangle?Triangle is defined as a basic polygonal shape of a triangle that has three sides and three interior angles.
By the triangle sum theorem, the sum of angles in a triangle is equal to 180°.
Therefore, m∠A + m∠B + m∠C = 180 using the Substitution property (3x)° + 90° + (x+10)° = 180°
To solve for x, first combine like terms to get 4x + 100 = 180,
using the subtraction property of equality, 4x = 80
using the Division property of equality, x = 20.
To find the measure of the angle A, use the substitution property to get m∠A = 3(20)°.
Finally, simplify the expression gets m∠A = 60°
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The missing figure has been attached below.
A sphere has a radius of 4 in. which equation finds the volume of the sphere?
Answer:
Step-by-step explanation:
By definition, Volume of Sphere = [tex]\frac{4}{3}[/tex]πr³
If r = 4 in,
then Volume = [tex]\frac{4}{3}[/tex]π(4)³ = 268.08 in³
Answer:
267.95
Step-by-step explanation:
4/3 * pi * 4^3
4/3 * pi *64
256/3* pi = 267.95
The temperature at midnight on a cold winter night was -2?C. Twelve hours later the temperature increased by 9?C. Then after 5 hours it decreased by 8?C. Find the temperature at 5 pm?
Answer: The temperature is -1 degrees
Step-by-step explanation: Trust me!
Which is an equation of a circle with center (2, 7) and radius 4? (x - 7)2 + (y - 2)2 = 16 (x - 2)2 + (y - 7)2 = 4 (x – 2)2 + (y - 7)2 = 16 (x + 2)2 + (y + 7)2 = 4
Answer:
Third choice
Step-by-step explanation:
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where h and k are coordinates of the center and r is the radius squared. We have h = 2, k = 7, and r = 4 (we will have to square it to fit it into the equation properly). Filling in accordingly:
[tex](x-2)^2+(y-7)^2=16[/tex]
The third choice is the one you want.
Given: PQRS is a parallelogram
Prove: PR and QS bisect each other at T
Answer:
1) given
3)being alternate angleS
5)ASA condition
6)corresponding sides of congruent triangle are equal
7)Pt=Rt and ST =QT
A pinecone drops from a tree branch that is 20 feet above the ground. The function h = –16t2 + 20 is used. If the height h of the pinecone is in feet after t seconds, at about what time does the pinecone hit the ground?
Answer:
t ≈ 1.118 . . . seconds
Step-by-step explanation:
Set h=0 and solve for t.
0 = -16t^2 +20
0 = t^2 -20/16 . . . . . . . . . . . . . . . divide by the coefficient of t^2
t = √(5/4) = (1/2)√5 ≈ 1.118 . . . . . add 5/4 and take the square root
The pinecone hits the ground about 1.12 seconds after it drops.
For the mathematical model h = -16t² + 20, corresponding to a pinecone dropping from a tree, the pinecone would hit the ground after approximately 1.118 seconds.
Explanation:In order to know when a pinecone hits the ground, we would need to solve the equation provided for the variable t when h equals zero, as that would represent the pinecone being on the ground. The equation given is quadratic in nature: h = -16t² + 20. In this equation, h represents the height of the pinecone, and t represents time in seconds.
To find when the pinecone hits the ground (h=0), we set h to zero and solve for t:
0 = -16t² + 20
Therefore, 16t² = 20
So, t² = 20/16 = 1.25
Then, t = sqrt(1.25) = 1.118 (remember we exclude negative root as it doesn't go with time).
The pinecone hits the ground approximately at t = 1.118 seconds.
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Assume that instead of conducting experiments, Latané and Darley had used a correlational method to study the relation between the number of bystanders who witness an emergency and how quickly a victim receives help. Assume that the correlational data were compatible with results from experiments: the more bystanders, the longer it took bystanders to help. What type of correlation is this?A) a nonlinear correlationB) a zero correlationC) a positive correlationD) a spurious correlationE) a negative correlation
Answer:
C) a positive correlation
Step-by-step explanation:
More people ⇒ Longer time is a positive correlation between those variables. However, longer time is not the desired outcome.
Rather, shorter time is the desired outcome. The correlation between more people and shorter time is negative. In order to compute that correlation numerically, one would have to define a function that would give a numerical value for "shorter time" that would model the goodness of outcome as time gets shorter.
Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.
Answer:
x-2y = -12
Step-by-step explanation:
Standard form of a line is in the form Ax + By = C where A is a positive integer
y − 3 = 1/2(x + 6)
Multiply each side by 2 to eliminate the fractions
2(y-3)= 1/2*2 (x+6)
Distribute
2y -6 = x+6
Subtract x from each side
-x +2y -6 = x-x +6
-x+2y -6 = 6
Add 6 to each side
-x+ 2y -6+6 = 6+6
-x +2y = 12
Multiply each side by -1 to make A a positive integer
x-2y = -12
Use the net to find the lateral area of the prism.
___cm^2
Answer:
[tex]900\ cm^2[/tex]
Step-by-step explanation:
We can notice that the the prism provided is a rectangular prism.
By definition, The lateral area of a rectangular prism can be calculated by multiplying the perimeter of its base by its height.
The height is:
[tex]height=15\ cm[/tex]
Then, the perimeter of the base is:
[tex]Perimeter=17\ cm+17\ cm+13\ cm+13\ cm=60\ cm[/tex]
Then the lateral area is:
[tex]LA=60\ cm*15\ cm\\\\LA=900\ cm^2[/tex]
It is not possible to prove one pair of triangles congruent and then use their congruent corresponding parts to prove another pair congruent. True or false
Answer:
true
The wording does not quite mean anything,
but what I think was meant to ask is
"if we use some parts of two triangles to prove they are congruent,
can we then use that to prove that
a pair of corresponding parts not used before are congruent?"
The answer is
Yes, of course,
Corresponding Parts of Congruent Triangles are Congruent,
which teachers usually abbreviate as CPCTC.
For example, if we find that
side AB is congruent with side DE,
side BC is congruent with side EF, and
angle ABC is congruent with angle DEF,
we can prove that triangles ABC and DEF are congruent
by Side-Angle-Side (SAS) congruence.
We then, by CPCTC, can conclude that other pairs of corresponding parts are congruent:
side AB is congruent with side DE,
angle BCA is congruent with angle EFD, and
angle CAB is congruent with angle FDE.
It was possible (by CPCTC) to prove those last 3 congruence statements,
after proving the triangles congruent.
The expected answer is FALSE.
Step-by-step explanation:
A sports team came to town. The stadium filled all 10,000 seats at two-level pricing. Level 1 tickets are $50 each, and level 2 tickets are $150 each. The stadium made $75,000 in ticket sales. The system of equations that models this scenario is:
x + y = 10,000
50x + 150y = 75,000
What do the x and y represent in the system?
A.x represents the number of level 2 tickets; y represents the number of level 1 tickets
B.x represents the cost of level 1 tickets; y represents the cost of level 2 tickets
C.x represents the cost of level 2 tickets; y represents the cost of level 1 tickets
D.x represents the number of level 1 tickets; y represents the number of level 2 tickets
D. [tex]x[/tex] represents the number of level 1 tickets; [tex]y[/tex] represents the number of level 2 tickets
Explanation:The costs of the tickets are represented as constants ([tex]50[/tex] and [tex]150[/tex]), and so they are not variables.
We know [tex]x[/tex] is level 1 tickets and [tex]y[/tex] is level 2 tickets because the price of a level 1 ticket is $50 and the second equation contains [tex]50x[/tex]. Similarly, the cost of a level 2 ticket is $150 and the equation contains [tex]150y[/tex].
Answer:
(D) X represents the number of level 1 tickets.
please help will give brainliest
Apply the distributive property to factor out the greatest common factor.
Answer:
9 + 15 = 3(3 + 5)
Step-by-step explanation:
The greatest common factor of 9 and 15 is 3.
Factor 3 out of both 9 and 15.
9 + 15 = 3(3 + 5)
What are the vertices of the hyperbola with equation 4y^2 - 25x^2 = 100?
bearing in mind that the variable with the positive sign is the "y", meaning the hyperbola is opening vertically, and thus its vertices/foci will be along the center's y-coordinate.
[tex]\bf \textit{hyperbolas, vertical traverse axis } \\\\ \cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h, k\pm a)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]
[tex]\bf 4y^2-25x^2=100\implies \cfrac{4y^2-25x^2}{100}=1\implies \cfrac{4y^2}{100}-\cfrac{25x^2}{100}=1 \\\\\\ \cfrac{y^2}{25}-\cfrac{x^2}{4}=1\implies \cfrac{(y-0)^2}{5^2}-\cfrac{(x-0)^2}{2^2}=1\qquad \begin{cases} h=0\\ k=0\\ a=5\\ b=2 \end{cases} \\\\\\ \stackrel{\textit{vertices}}{(0, 0\pm 5)}\implies \begin{cases} (0,5)\\ (0,-5) \end{cases}[/tex]
A and B are complementary. If B = 26°, what is the measure of A?
1) 26°
2) 64°
3) 154°
4) 74°
Answer:
2) 64°
Step-by-step explanation:
If A and B are complementary, that means that they add up to 90. Therefore, A + 26 = 90 and A = 64.
Answer:
2.) 64 degrees
Step-by-step explanation: 90-26 = 64
Reminder: Complementary are 90 degrees angle
Supplementary are 180 degrees angle
If Rick wishes to reduce his BMI to 27, he needs to eat fewer kcalories than he expends. For an adolescent who carries excess fat, the recommended maximal weight loss is one pound per week. Since there are 3500 kcalories in a pound of body fat, a deficit of 3500 kcalories for the week or 500 kcalories per day would be required. Calculate the maximum number of kcalories Rick can consume per day to achieve a weight loss of one pound per week. Assume that his weight is 205 pounds and that his physical activity factor is "low active."
This question is not complete because his height and age was not indicated in the above question.
Complete Question:
Rick is a healthy 19-year-old college student who is 70 inches tall and weighs 205 pounds. He has decided to "get a six-pack" over the summer with a diet and exercise program. As part of his new plan, he has stopped drinking soda and is eating more salads in addition to his usual diet. Besides of these changes, he is unclear on how to proceed to reach his fitness goal. Rick's mother wants to make sure his approach will not interfere with his normal growth and development, and has asked him to seek reliable information to help him make a reasonable plan.
If Rick wishes to reduce his BMI to 27, he needs to eat fewer kcalories than he expends. For an adolescent who carries excess fat, the recommended maximal weight loss is one pound per week. Since there are 3500 kcalories in a pound of body fat, a deficit of 3500 kcalories for the week or 500 kcalories per day would be required. Calculate the maximum number of kcalories Rick can consume per day to achieve a weight loss of one pound per week. Assume that his weight is 205 pounds and that his physical activity factor is "low active."
Answer:
2696 kilocalories
Step-by-step explanation:
STEP 1
First we need to calculate Rick's Basal Metabolic Rate( BMR)
Weight in pounds = 205 pounds
Age = 19 years
Height in inches = 70 inches
The formula for calculating Basal Metabolic Rate for men =
BMR = 66.47 + ( 6.24 × weight in pounds ) + ( 12.7 × height in inches ) − ( 6.755 × age in years )
BMR = 66.47 + ( 6.24 × 205 ) + ( 12.7 × 70 ) − ( 6.755 × 19)
= 2247
STEP 2:
The next step is to calculate the maximum amount kilocalories per day Rick should consume
Formula is given as :
For a person with physical activity factor of a ' low Active'
Maximum amount of kilocalories to consume per day = Basal Metabolic rate × 1.2
= 2247 × 1.2
= 2696 Kilocalories (kcalories) per day
A bag contains 4 red marbles, 3 green marbles, and 2 yellow marbles. The probability of randomly picking a yellow marble is . What is the probability of not picking a yellow marble?
Probability of randomly picking a yellow marble is [tex]\frac{2}{9}[/tex].
Probability of not picking a yellow marble is [tex]\frac{7}{9}[/tex].
What is probability?Probability denotes the possibility of the outcome of any random event. The meaning of this term is to check the extent to which any event is likely to happen.
According to the question
A bag contains 4 red marbles, 3 green marbles, and 2 yellow marbles.
Probability of randomly picking a yellow marble is
Number of favorable outcomes = 2
Total number of favorable outcomes = 4 + 3 + 2 = 9
Probability of randomly picking a yellow marble is [tex]\frac{2}{9}[/tex].
Probability of not picking a yellow marble
= 1 - Probability of randomly picking a yellow marble
= 1 - [tex]\frac{2}{9}[/tex]
= [tex]\frac{9-2}{9}[/tex]
= [tex]\frac{7}{9}[/tex]
Probability of not picking a yellow marble is [tex]\frac{7}{9}[/tex].
Hence,
Probability of randomly picking a yellow marble is [tex]\frac{2}{9}[/tex].
Probability of not picking a yellow marble is [tex]\frac{7}{9}[/tex].
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The probability of not picking a yellow marble from a bag with 9 marbles total, where only 2 are yellow, is 7/9 or approximately 77.78%.
The question is related to calculating the probability of an event not occurring—in this case, not picking a yellow marble from a bag that contains different colored marbles. The total number of marbles is 4 red marbles + 3 green marbles + 2 yellow marbles = 9 marbles. To find the probability of not picking a yellow marble, we consider the total marbles that are not yellow, which are 4 red + 3 green = 7 marbles. The probability is then the number of non-yellow marbles divided by the total number of marbles, so it's 7/9. To calculate this, we divide the 7 non-yellow marbles by the total of 9 marbles, resulting in a probability of 7/9, or about 77.78%.
Most animals give birth during a general time of year. This is because animals naturally breed so that their young will be born at the time of year when there will be adequate food supply. The bar graph shows the number of live births of a jackrabbit native to California over the course of Year X. Based on the data, which of the following would be an appropriate conclusion?
A) In general, rabbits give birth during the spring months
B) In general, rabbits give birth during the summer months
C) In general,m California jackrabbits give birth during the spring months
D) In general, California jackrabbits give birth during the summer months
Answer:
I guess c I just plain out guessed
4x(3x − 7) − 19x2
the 2 behind the x is an exponent
Answer:
-7x(x + 4)
Step-by-step explanation:
Not sure exactly what you're doing with this, but I know you're not solving it for x because there's no " = " there so I am assuming you're simplifying it as much as possible. I'm going with that.
First thing is to distribute through the parenthesis by multiplying 4x by 3x and then 4x by -7 to get:
[tex]12x^2-28x-19x^2[/tex]
Now combine like terms to get
[tex]-7x^2-28x[/tex]
The last thing you could do now is pull out what's common between each of those terms which is -7x. When you do that, you're left with
-7x(x + 4)
Help calculus module 6 DBQ
please show work
1. Let [tex]a,b,c[/tex] be the three points of intersection, i.e. the solutions to [tex]f(x)=g(x)[/tex]. They are approximately
[tex]a\approx-3.638[/tex]
[tex]b\approx-1.862[/tex]
[tex]c\approx0.889[/tex]
Then the area [tex]R+S[/tex] is
[tex]\displaystyle\int_a^c|f(x)-g(x)|\,\mathrm dx=\int_a^b(g(x)-f(x))\,\mathrm dx+\int_b^c(f(x)-g(x))\,\mathrm dx[/tex]
since over the interval [tex][a,b][/tex] we have [tex]g(x)\ge f(x)[/tex], and over the interval [tex][b,c][/tex] we have [tex]g(x)\le f(x)[/tex].
[tex]\displaystyle\int_a^b\left(\dfrac{x+1}3-\cos x\right)\,\mathrm dx+\int_b^c\left(\cos x-\dfrac{x+1}3\right)\,\mathrm dx\approx\boxed{1.662}[/tex]
2. Using the washer method, we generate washers with inner radius [tex]r_{\rm in}(x)=2-\max\{f(x),g(x)\}[/tex] and outer radius [tex]r_{\rm out}(x)=2-\min\{f(x),g(x)\}[/tex]. Each washer has volume [tex]\pi({r_{\rm out}(x)}^2-{r_{\rm in}(x)}^2)[/tex], so that the volume is given by the integral
[tex]\displaystyle\pi\int_a^b\left((2-\cos x)^2-\left(2-\frac{x+1}3\right)^2\right)\,\mathrm dx+\pi\int_b^c\left(\left(2-\frac{x+1}3\right)^2-(2-\cos x)^2\right)\,\mathrm dx\approx\boxed{18.900}[/tex]
3. Each semicircular cross section has diameter [tex]g(x)-f(x)[/tex]. The area of a semicircle with diameter [tex]d[/tex] is [tex]\dfrac{\pi d^2}8[/tex], so the volume is
[tex]\displaystyle\frac\pi8\int_a^b\left(\frac{x+1}3-\cos x\right)^2\,\mathrm dx\approx\boxed{0.043}[/tex]
4. [tex]f(x)=\cos x[/tex] is continuous and differentiable everywhere, so the the mean value theorem applies. We have
[tex]f'(x)=-\sin x[/tex]
and by the MVT there is at least one [tex]c\in(0,\pi)[/tex] such that
[tex]-\sin c=\dfrac{\cos\pi-\cos0}{\pi-0}[/tex]
[tex]\implies\sin c=\dfrac2\pi[/tex]
[tex]\implies c=\sin^{-1}\dfrac2\pi+2n\pi[/tex]
for integers [tex]n[/tex], but only one solution falls in the interval [tex][0,\pi][/tex] when [tex]n=0[/tex], giving [tex]c=\sin^{-1}\dfrac2\pi\approx\boxed{0.690}[/tex]
5. Take the derivative of the velocity function:
[tex]v'(t)=2t-9[/tex]
We have [tex]v'(t)=0[/tex] when [tex]t=\dfrac92=4.5[/tex]. For [tex]0\le t<4.5[/tex], we see that [tex]v'(t)<0[/tex], while for [tex]4.5<t\le8[/tex], we see that [tex]v'(t)>0[/tex]. So the particle is speeding up on the interval [tex]\boxed{\dfrac92<t\le8}[/tex] and slowing down on the interval [tex]\boxed{0\le t<\dfrac92}[/tex].
SEE PHOTO! If 1 measures 135°, what is the measure of 8? (Lines b and c are parallel.)
A) 45°
B) 135°
C) 65°
D) 67.5°
Answer:
Measure 8 is 135°
Step-by-step explanation:
Measure 1 and Measure 8 are alternate exterior angles.
Answer:
B) 135°
Step-by-step explanation:
<1 = <4 vertical angles
<4 = <5 alternate interior angles
<5 = <8 vertical angles
Therefore <1 = <8
Since <1 = 135, we know <8 = 135
y-8/5 = 3 solve for y
a. 23
b. 7
c. -7
d. -23
Answer:
[tex]\large\boxed{a.\ 23}[/tex]
Step-by-step explanation:
[tex]\dfrac{y-8}{5}=3\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{y-8}{5\!\!\!\!\diagup_1}=5\cdot3\\\\y-8=15\qquad\text{add 8 to both sides}\\\\y-8+8=15+8\\\\y=23[/tex]
Identify the image of a triangle with vertices L(−3,4), M(−2,1), and N(0,2) under a dilation with a scale factor of −3 centered at the origin. HELP ASAP!!
Answer:
see below
Step-by-step explanation:
The image is reflected across the origin and enlarged by a factor of 3.
___
The first choice shows some funny combination of translation, rotation, and dilation. The last choice has point N invariant, which means that is the center of the (horizontal only) dilation. Neither of these matches the problem description.
HELP ASAP PLEASE!!
the heights of two different projectiles after they launched are modeled by f(x) and g(x).
The approximate difference in the maximum height achieved by the two projectiles is 5.4 ft. (Option C).
How to calculate the difference between two maximum heights?
The approximate difference in the maximum height achieved by the two projectiles is calculated as follows;
The given function of one of the projectile;
f(x) = -16x² + 42x + 12
The function of the second projectile shown in the table, shows that the maximum of the function, g is 33
g(1) = 33 ft (maximum height)
The maximum height attained by the projectile with f(x) function occurs at x = 1
f(1) = -16(1)² + 42(1) + 12
f(1) = 38 ft
The difference between two maximum heights;
Δh = f(1) - g(1)
Δh = 38 ft - 33 ft
Δh = 5 ft
The option that is approximately 5 ft is option C (5.4 ft).