What is the domain of the function graphed below

What Is The Domain Of The Function Graphed Below

Answers

Answer 1

ANSWER

(-2,4] and [7,∞).

EXPLANATION

The domain refers to the interval on which the function is defined.

In the case of the graph, the domain refers to all the x-values for which the graph exists.

The graph is defined for x-values greater than 2 but less than or equal to 4 and

x-values greater than or equal to 7.

In interval notation, we have:

(-2,4] and [7,∞).

The second choice is correct:

Answer 2

Answer:

(-2,4] and [7, infinity)

Step-by-step explanation:


Related Questions

Can someone please help me with this quick I’m very confused

Answers

.140 I think it's that

Answer:

Step-by-step explanation:

Total number of marbles = 6 + 3 + 5 = 14

You want to draw out 3 marbles -- all of them red. In solving this, you have to assume that none are put back.

The answer is

P(Red) = 6/14 * 5/13 * 4/12

P(Red) = 3/7 + 5/13 + 1/3

numerator = 3*5*1 = 15

denominator = 7 * 13 * 3

denominator = 273

P(red) = 15 / 273

P(red) = 0.0549

If a humpback whale swam 16.8 miles per hour dor 4.5 hours how far did it swim

Answers

Answer:

easy, it traveled/swam 75.6 miles

Step-by-step explanation:

16.8 x 4.5= 75.6

hope this helps

which of the following is equivalent to the expression below?
(-3m+5)+(m-11)

A. 4m-16
B.-4m-6
C. 2m-16
D. -2m-6

Answers

Answer:

D

Step-by-step explanation:

add -3m + 1m = -2m

add 5 -11= -6

combine like terms

Hiroshi spends 30 minutes on history homework, 60 minutes on English homework, and x minutes on math homework. One fourth of his total homework time is spent on math. Which equation can be used to find the amount of time Hiroshi spends on his math homework? (x + 30 + 60) = x (x) = x(30 + 60) x(30 + 60) = x (x) = (30 + 60)

Answers

Answer:

x(x)=1/4(30+60+x)

Step-by-step explanation:

minutes spent on math homework= x

minutes spent on history homework= 30 min

minutes spent on English homework= 60 min

Total minutes spent on homework = x+30 +60

Also

x= 1/4(x+30 +60)

x= x/4 + 90/4

x-x/4= 90/4

(4x-x)/4=90/4

3x=90

x=30

Hence time spent on maths=30 min

total time spent= 30+60+30

                          = 120 min

1/4 of 120 min= 30 mins!

Answer:

A. 1/4(x + 30 + 60) = x

Step-by-step explanation:

simplify the following expression:
|-4|-|+7|​

Answers

Answer:

-3

Step-by-step explanation:

Expression: |-4| - |7|

1. Absolute value (positive distance from zero; found by removing negative sign unless positive): 4 - 7

2. Subtract: -3

The simplified expression is given by -3.

What is the absolute value of a number?

The absolute value of a number is the positive value of that number. The number, if it is negative, will become positive and a positive number will remain positive.

We can simplify the expression as follows:

It is given that the expression is: |-4|-|+7|​

We can now simplify the expression.

The expression can be simplified as follows:

|-4|-|+7|​ = 4 - 7

= -3

The given expression was simplified.

The simplified value of the given expression |-4|-|+7|​ is found to be -3.

Therefore, we have found that the simplified expression is given by -3.

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solve (1/64)^0.5x-3 =8^9x-2​

Answers

Answer:

0.8

Step-by-step explanation:

You are given the equation

[tex]\left(\dfrac{1}{64}\right)^{0.5x-3}=8^{9x-2}[/tex]

First note that

[tex]\dfrac{1}{64}=\dfrac{1}{2^6}=2^{-6}\\ \\\left(\dfrac{1}{64}\right)^{0.5x-3}=(2^{-6})^{0.5x-3}=2^{-6\cdot (0.5x-3)}=2^{-3x+18}\\ \\8=2^3\\ \\8^{9x-2}=(2^3)^{9x-2}=2^{3\cdot (9x-2)}=2^{27x-6}[/tex]

Now

[tex]2^{-3x+18}=2^{27x-6}\\ \\-3x+18=27x-6\\ \\-3x-27x=-6-18\\ \\-30x=-24\\ \\x=\dfrac{24}{30}=\dfrac{8}{10}=0.8[/tex]

Final answer:

To solve the given equation, we convert both sides to a common base and equate the exponents. After simplifying, we find that the solution is x = 8/11.

Explanation:

We are asked to solve the equation (1/64)^0.5x-3 = 8^9x-2. To begin, we will express both sides of the equation with the same base since 64 is 2^6 and 8 is 2^3. This transformation will allow us to use the property of exponents that states when the bases are equal, the exponents must also be equal.

First, let's rewrite the equation using base 2:

(1/2^6)^(0.5x-3) = (2^3)^(9x-2)(2^-6)^(0.5x-3) = (2^3)^(9x-2)2^(-6(0.5x-3)) = 2^(3(9x-2))

Now, since the bases are the same, we can equate the exponents:

-6(0.5x-3) = 3(9x-2)-3x + 18 = 27x - 633x = 24x = 24/33x = 8/11

The solution to the equation is x = 8/11. Always remember to check for extraneous solutions when dealing with exponents and roots.

given h(×)=×^2-2 find the value of h(-3)

Answers

Answer:

h(-3) = 7

Step-by-step explanation:

Put x = -3 to the equation of the function h(x) = x² - 2:

h(-3) = (-3)² - 2 = 9 - 2 = 7

An angle in standard position measures -7x/6 radians. In which quadrant does the terminal side of this angle lie

Answers

The terminal side of an angle measuring -7x/6 radians lies in the second quadrant, considering the angle implies a clockwise rotation from the positive x-axis and one complete rotation is 2π radians.

One complete revolution is equal to 2π radians, which is approximately 6.28 radians. Negative angles imply a clockwise rotation from the positive x-axis. The given angle, -7x/6 radians, would place the terminal side in a clockwise rotation from the positive x-axis.

Angles that measure between 0 to -π/2 radians lie in the fourth quadrant, while angles between -π/2 to -π radians lie in the third quadrant, angles between -π to -3π/2 radians lie in the second quadrant, and angles between -3π/2 to -2π radians lie in the first quadrant.

Assuming the variable x represents any positive real number, the angle -7x/6 would likely be between -π and -3π/2 (or -1.57 and -4.71), and therefore, the terminal side of this angle would lie in the second quadrant.

Adam’s car traveled 465.3 miles on 16.5 gallons of gas. Which equation can be used to determine the average number of miles that the car traveled on each gallon of gas ? 16.5x= 465.3 x/16.5= 465.3 465.3x=16.5 x/465.3=16.5

Answers

Answer:

465.3 = 16.5x

Step-by-step explanation:

We can determine the miles per gallon  by taking the number of miles driven and dividing by the gallons

465.3 /16.5 =x

Rewriting by multiplying each side by 16.5

465.3 = 16.5x

Answer:

A

Step-by-step explanation:

Which of the following describes the graph of {x | x < = 1} u {x | x > = 4}?

a. closed circles on 1 and 4 with a line segment between
b. closed circles on 1 and 4 with arrows pointing outward
c. the entire number line
d. no solution

Answers

Answer:

b. closed circles on 1 and 4 with arrows pointing outward

Step-by-step explanation:

Which of the following describes the graph of {x | x < = 1} u {x | x > = 4},

We have been given the following set;

x < = 1

This set comprises of real numbers that are less than or equal to 1;

(1, 0, -1, -2, -3, -4, .......... -∞)

On the other hand, the set x > = 4 comprises of real numbers that are greater than or equal to 4;

(4, 5, 6, 7, 8, 9, ........∞)

The symbol ∪ means a union of sets. That is the set of numbers that belong in either or both sets;

{x | x < = 1} u {x | x > = 4} is same as writing;

(1, 0, -1, -2, -3, -4, .......... -∞) ∪ (4, 5, 6, 7, 8, 9, ........∞)

Therefore, the solution set will be closed circles on 1 and 4 with arrows pointing outward

Answer:

Closed circles on 1 and 4 with arrows pointing outward ⇒ answer b

Step-by-step explanation:

* Lets study the meaning of the inequality

- If a < x < b, that means the value of x is between a and b

- If a ≤ x ≤ b, that means the value of x is from a to b

- If x < a and x > b, that means the value of x is smaller than a and

 grater than b

- If x ≤ a and x ≥ b, that means the value of x is smaller than or equal a and

 grater than or equal b

* Now lets solve the problem

∵ {x I x ≤ 1}

∴ x is smaller than or equal 1

∵ {x I x ≥ 4}

∴ x is greater than or equal 4

∵ {x I x ≤1} ∪ {x I x ≥ 4}

- The meaning of ∪ is all numbers smaller than or equal 1 and all

  the numbers greater than or equal 4

∴ {x I x ≤ 1} ∪ {x I x ≥ 4} = (-∞ , 1] ∪ [4 , ∞)

- This solution represented graphically by closed circles on 1 and

 4 with arrows pointing outward

Select the equations of the lines that are parallel to the line whose equation is y = 3x + 5.

Answers

Select the equations of the lines that are parallel to the line whose equation is y = 3x + 5

Answer:

6x+2y=12

and

3y=9x

Write the expression as a single logarithm PLEASE

(log3-log4)-log2

Answers

[tex]\bf \textit{Logarithm of rationals} \\\\ \log_a\left( \frac{x}{y}\right)\implies \log_a(x)-\log_a(y) \\\\[-0.35em] \rule{34em}{0.25pt}\\[1em] [\log(3)-\log(4)]-\log(2)\implies \log\left( \cfrac{3}{4} \right)-\log(2)\implies \log\left( \cfrac{\frac{3}{4}}{~~2~~} \right) \\\\\\ \log\left( \cfrac{\frac{3}{4}}{~~\frac{2}{1}~~} \right)\implies \log\left( \cfrac{3}{4}\cdot \cfrac{1}{2} \right)\implies \log\left( \cfrac{3}{8} \right)[/tex]

To write the expression as a single logarithm, we'll use the properties of logarithms to combine them. The given expression is:
(log3 - log4) - log2
We start by combining the first two logarithms inside the parenthesis using the difference of logarithms property:
log(a) - log(b) = log(a/b)
Applying this property to (log3 - log4), we get:
log(3/4)
Now, our expression looks like this:
log(3/4) - log2
We can use the same property to combine this with the remaining logarithm:
log(a) - log(b) = log(a/b)
So we apply it with a = 3/4 and b = 2:
log((3/4)/2)
When dividing by 2, we are effectively multiplying by 1/2, so we have:
log(3/4 * 1/2)
Now we perform the multiplication inside the logarithm:
log(3/8)
And that is the expression written as a single logarithm:
log(3/8)

The recursive rule for a sequence is a^n=a^(n-1)+7,where a^1=-15. What is the explicit rule for this sequence?

Answers

ANSWER

[tex]a_n=7n - 22[/tex]

EXPLANATION

The recursive rule for the sequence is

[tex]a_n=a_{n-1}+7[/tex]

In general the recursive rule is written as:

[tex]a_n=a_{n-1}+d[/tex]

This implies that, d=7

The first term of the sequence is

[tex]a_1= - 15[/tex]

The explicit rule is given by:

[tex]a_n=a_1 + d(n - 1)[/tex]

We substitute to get;

[tex]a_n= - 15 + 7(n - 1)[/tex]

[tex]a_n= - 15 + 7n - 7[/tex]

[tex]a_n=7n - 22[/tex]

PLEASE HELP 10 POINTS

Answers

Answer:

Step-by-step explanation:

Box 1: contains 4 items, two of which are pens. the probability of choosing a pen is 2/4

Box 2: contains 7 crayons and 3 colored pencils for a total of 10. The probability of choosing 1 crayon out of that box is 7/10

Event Probability = 2/4 * 7/10 = 14/40   = 7 / 20

A farmer wants to build a rectangular pen with 80 feet of fencing. The pen will be built against the wall of the barn so one side of the rectangle won’t need a fence. What dimensions will maximize the area of the pen?

Answers

Answer:

The length of the rectangular pen is [tex]40\ ft[/tex]

The width of the rectangular pen is [tex]20\ ft[/tex]

Step-by-step explanation:

Let

x-----> the length of the rectangular pen

y----> the width of the rectangular pen

we know that

The perimeter of the rectangular pen in this problem is equal to

[tex]P=x+2y[/tex] ---> remember that one side of the rectangle won’t need a fence

[tex]P=80\ ft[/tex]

so

[tex]80=x+2y[/tex]

[tex]y=(80-x)/2[/tex] -----> equation A

The area of the rectangular pen is equal to

[tex]A=xy[/tex] -----> equation B

Substitute equation A in equation B

[tex]A=x*(80-x)/2\\ \\A=-0.5x^{2}+40x[/tex]

The quadratic equation is a vertical parabola open downward

The vertex is a maximum

The x-coordinate of the vertex is the length of the rectangular pen that maximize the area of the pen

The y-coordinate of the vertex is the maximum area of the pen

using a graphing tool

The vertex is the point (40,800)

see the attached figure

so

[tex]x=40\ ft[/tex]

Find the value of y

[tex]y=(80-x)/2[/tex] ----> [tex]y=(80-40)/2=20\ ft[/tex]

therefore

The length of the rectangular pen is [tex]40\ ft[/tex]

The width of the rectangular pen is [tex]20\ ft[/tex]

Answer:

length is 40

Width is 20

Step-by-Step explanation:

The value of x ?

A)3
B)27
C)54
D)6

Answers

Answer:

A) 3

Step-by-step explanation:

We know that the diagonals of the parallelogram intersect in half.

Therefore we hawe the equation:

x - 30 = -9 - 6x              add 30 to both sides

x = 21 - 6x              add 6x to both sides

7x = 21            divide both sides by 7

x = 3

X=3 hope this helps sorry if I’m wrong

Use algebraic rules of equations to predict the solution type to the system of equations. Include all of your work for full credit.
{ x+2y=10
{6y=-3x+30

Answers

Answer:

0=0

Step-by-step explanation:

When you  combine both expressions  you multiply the first one  by -3

As result all the terms in the second expression are cancelled when both expressions are added

-3x -6y = -30

3x  + 6y =30

0   +  0  = 0

angles of a triangle are 38° and 27°, what is the third angle

Answers

Answer:

115°

Step-by-step explanation:

A triangle always has 3 angles, and thew sum of the angles is always 180°. Therefore,

38° + 27° + x° = 180°

65° + x° = 180°

x° = 115°

Which of the following is equivalent to x+1/y divided by g+1/h
A) x/y times h/g
B) x + 1/y times h/g+1
C) x+ 1/y divided h/g+1
D) y/x+1 divided g+1/h





Answers

Answer:

B) x + 1/y times h/g+1

Step-by-step explanation:

We need to divide [tex]\frac{x+1}{y}[/tex] by [tex]\frac{g+1}{h}[/tex] then match with given choices to find the correct equivalent result.

where given choices are:

A) x/y times h/g

B) x + 1/y times h/g+1

C) x+ 1/y divided h/g+1

D) y/x+1 divided g+1/h

So let's divide  [tex]\frac{x+1}{y}[/tex] by [tex]\frac{g+1}{h}[/tex]

[tex]\frac{\left(\frac{x+1}{y}\right)}{\left(\frac{g+1}{h}\right)}[/tex]

we are allowed to flip the bottom fraction and change division sign into multiplication. So we get:

[tex]=\left(\frac{x+1}{y}\right)\cdot\left(\frac{h}{g+1}\right)[/tex]

Hence correct choice is: B) x + 1/y times h/g+1

Let's start by simplifying the given expression step-by-step:
\[ \text{Given Expression:} \quad \frac{x + \frac{1}{y}}{g + \frac{1}{h}} \]
Firstly, we will find a common denominator for the numerator and denominator of the given fraction.
For the numerator, we already have a single term x and a fraction \( \frac{1}{y} \), which can be combined without altering the denominator.
For the denominator, we have term g and a fraction \( \frac{1}{h} \). To combine these, we need to multiply both terms by h to get a common denominator.
So, the expression becomes:
\[ \frac{x + \frac{1}{y}}{g + \frac{1}{h}} = \frac{xy + 1}{y} \cdot \frac{h}{gh + 1} \]
Next, we will multiply the separated fractions across the numerator and the denominator:
\[ \frac{xy + 1}{y} \cdot \frac{h}{gh + 1} = \frac{(xy + 1) \cdot h}{y \cdot (gh + 1)} \]
Now, let's consider the given options and check which one is equivalent to our simplified expression:
Option A) \( \frac{x}{y} \times \frac{h}{g} \)
This option simplifies to \( \frac{xh}{yg} \), which is not equivalent to the expression we have because we have \( xy + 1 \) in the numerator, not just \( xh \).
Option B) \( (x + \frac{1}{y}) \times \frac{h}{g+1} \)
For this option, if we simplify, we do not obtain a single fraction with the term \( xy + 1 \) in the numerator and \( y(gh + 1) \) in the denominator, instead, this option gives us \( xh + \frac{h}{y(g+1)} \), which is different from our simplified expression.
Option C) \( \frac{x + \frac{1}{y}}{h/(g + 1)} \)
To simplify this option, we take the reciprocal of the denominator and multiply it with the numerator:
\[ \frac{x + \frac{1}{y}}{h/(g + 1)} = (x + \frac{1}{y}) \times \frac{g + 1}{h} \]
\[ = \frac{(x + \frac{1}{y})(g + 1)}{h} \]
\[ = \frac{xg + x + \frac{g}{y} + \frac{1}{y}}{h} \]
\[ = \frac{xg + x + \frac{g + 1}{y}}{h} \]
This is not equivalent to our simplified expression either because it involves terms like \( xg \) and \( x \), which do not appear in our expression and does not fit the form \( \frac{(xy + 1) \cdot h}{y \cdot (gh + 1)} \).
Option D) \( \frac{y/(x+1)}{g + \frac{1}{h}} \)
To simplify this option, we multiply by the reciprocal of the denominator:
\[ \frac{y/(x+1)}{g + \frac{1}{h}} = \frac{y}{x+1} \times \frac{h}{gh + 1} \]
\[ = \frac{yh}{(x+1)(gh + 1)} \]
Again, this is not equivalent to our simplified expression, since the expressions \( y/(x+1) \) and \( (xy + 1)/y \) are different.
None of the options (A, B, C, or D) match the simplified form:
\[ \frac{(xy + 1) \cdot h}{y \cdot (gh + 1)} \]
Therefore, none of the given options are equivalent to the original expression \( \frac{x + \frac{1}{y}}{g + \frac{1}{h}} \).

what is this simplified?

Answers

Hello!

The answer is:

The second option: 2

[tex]\sqrt[4]{81}=3[/tex]

Why?

We can solve the problem and find the simplified expression using the following root property:

[tex]\sqrt[n]{x^{m} }=x^{\frac{m}{n} }[/tex]

We are given the expression:

[tex]\sqrt[4]{81}[/tex]

Which can be rewrite like this:

[tex]\sqrt[4]{81}=\sqrt[4]{3^{4}}[/tex]

Now, simplifying we have:

[tex]\sqrt[4]{3^{4}}=3^{\frac{4}{4} }=3[/tex]

Hence, the answer is the second option:

[tex]\sqrt[4]{81}=3[/tex]

Have a nice day!

Answer:

The correct answer is second option

3

Step-by-step explanation:

From the attached question we can see that,

⁴√81

To find the correct option

We know that 3⁴ = 81

⁴√81 can be written as,

⁴√81 = ⁴√(3 * 3 * 3 * 3)      

 = ⁴√(3)⁴

 = 3

Therefore the answer is 3

The correct option is  second option.  3

The perimeter of kite LMNO is 80 feet. Side MN = 3x + 5 and side NO = x – 7 . What is the length of NO?

Answers

Answer:

The length of NO is [tex]14\ ft[/tex]

Step-by-step explanation:

step 1

Find the value of x

we know that

The Kite  has two pairs of equal-length adjacent (next to each other) sides.

so

The perimeter is equal to

[tex]P=2[MN+NO][/tex]

[tex]P=80\ ft[/tex]

so

[tex]80=2[MN+NO][/tex]

[tex]40=[MN+NO][/tex]

substitute the values and solve for x

[tex]40=[(3x+5)+(x-7)][/tex]

[tex]40=[4x-2][/tex]

[tex]4x=42[/tex]

[tex]x=21\ ft[/tex]

step 2

Find the length of NO

[tex]NO=(21-7)=14\ ft[/tex]

Which are true about the regular hexagon? Check all that apply.

Answers

Answer:

It is 2, 4, & 5.

Step-by-step explanation:

just got it right on edge.

the sum of two consecutive integers is -239 find the two integers​

Answers

Answer:

The two consecutive integers are -119 and -120

Step-by-step explanation:

As we know that these two integers are consecutive, that means that they will have a difference of 1. This means that we can find the two integers by adding 1 to the sum of -239 and then dividing it by two

[tex]1-239=-238\\\frac{-238}{2} =-119\\-119-1=-120[/tex]

Final answer:

When needing to determine two consecutive integers with a given sum, they can be represented as 'x' and 'x+1'. The equation x + (x + 1) = -239 gives us the solution of the two integers as -120 and -119.

Explanation:

In the given question, since we are dealing with consecutive integers, we can represent the integers as 'x' and 'x+1'. As per the information in the question, we know that the sum of these two consecutive integers is -239. Therefore, we can create the equation:

x + (x + 1) = -239

Solving this equation gives us:

2x + 1 = -239

Therefore,

2x = -240

So, x = -120

This indicates that our first integer is -120. Because we are dealing with consecutive integers, the next integer would be -120 + 1 = -119. Thus, the two consecutive integers are -120 and -119.

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What are the zeros of the function? f(x)=3x^3−3x^2−6x

Answers

Answer:

-1, 0, 2

Step-by-step explanation:

[tex]\text{The zeros is for}\ f(x)=0.\\\\f(x)=3x^3-3x^2-6x\\\\f(x)=0\iff3x^3-3x^2-6x=0\qquad\text{divide both sides by 3}\\\\x^3-x^2-2x=0\qquad\text{distributive}\\\\x(x^2-x-2)=0\\\\x(x^2+x-2x-2)=0\\\\x\bigg(x(x+1)-2(x+1)\bigg)=0\\\\x(x+1)(x-2)=0\\\\\text{The product is equal to 0, when one of the factors is equal to 0.}\\\text{Therefore:}[/tex]

[tex]x(x+1)(x-2)=0\iff x=0\ \vee\ x+1=0\ \vee\ x-2=0\\\\x=0\ \vee\ x=-1\ \vee\ x=2[/tex]

Which choices are equivalent to the expression below? 6 to the square root of 3

Answers

For this case we must indicate an algebraic expression corresponding to the following:

"6 to the square root of 3"

Then, we must indicate an expression of the form:

[tex]a ^ n[/tex]

Where:

[tex]a = 6\\n = \sqrt {3}[/tex]

Thus, the expression is:

[tex]6 ^ {\sqrt {3}}[/tex]

ANswer:

[tex]6 ^ {\sqrt {3}}[/tex]

What is the probability that Ron picks a red ball from bag 1, a blue ball from bag 2, and a
green ball from bag 3?

Answers

1. 1/3 to get a red ball.

2. 4/13 to get a blue ball.

3. 3/7 to get a green ball.

Hope this helps!

Jamie needs a bin for her school
supplies. A blue bin has a length of
(12 inches, a width of 5 inches, and a
height of 4 inches. A green bin has a
length of 10 inches, a width of 6 inches,
and a height of 5 inches. What is the
volume of the bin with the greatest
volume?


Please help me :< ​

Answers

Answer:

the answer is the green bin

Step-by-step explanation:

12•5•4 is 240

10•6•5 is 300

so, the answer is the green bin

hope this helps!

have a blessed day!

please give brainliest!

Which of the functions have a range of all real numbers? Check all that apply.
A. y = sec x
B. y = tan x
C. y = cot x
D. y = csc x

Answers

Answer:

B. y = tan x  and  C. y = cot x

Step-by-step explanation:

Range:

range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.

Given:

From the given options

the range of tanx and cotx are all real numbers

as the period of tanx and cotx are π

where as range of secx is all real numbers except π/2 + n*π i.e.

(-∞ , -1] U [1 , + ∞)

And range of cscx is all real numbers except n*π i.e.

(-∞ , -1] U [1 , + ∞)

So from the given option:

option B and C are correct while A and D are not !

Hello!

The answer is:  The correct options are B. Tan(x) and C. Cot(x)

Why?

The range is the output of a function when we evaluate the function with inputs (domain), not all functions have a range of all real numbers, however it's more common to find functions without range or domain restrictions.

Both options B. Tan(x) and C. Cot(x) have a range of all real numbers while the functions Sec(x) and Csc (x) have a restricted range.

Sec(x) and Csc(x):

Domain, all real numbers.

Range, from -1 to 1 or  [-1,1]

Tan(x) and Cot(x):

Domain, all real numbers except [tex]\frac{\pi }{2}+-n\pi[/tex]

Range, all real numbers.

Hence, the correct options are B. Tan(x) and C. Cot(x)

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3 coins are tossed and two six-sided dice are rolled. how many possible outcomes are there?​

Answers

there are 36 possible outcomes

What is the solution set of {x | x < - 5} n {x | x > 5} ?

a. all numbers less than -5 and greater than 5
b. the numbers between -5 and 5
c. the empty set
d. all real numbers

Answers

Answer:

c. the empty set

Step-by-step explanation:

set of {x | x < - 5} n {x | x > 5}

The set x < - 5 comprises of real numbers that are less than -5;

(-6, -7, -8, -9, -10, -11, ......)

On the other hand, the set x > 5 comprises of real numbers greater than 5;

(6, 7, 8, 9, 10, 11, ......)

Clearly, the intersection of the above sets is empty, in that the intersection has no elements.

Therefore, {x | x < - 5} n {x | x > 5} is an empty or null set

Answer:

The solution set empty set or null set ⇒ answer c

Step-by-step explanation:

* Lets study the meaning of the inequality

- If a < x < b, that means the value of x is between a and b

- If a ≤ x ≤ b, that means the value of x is from a to b

- If x < a and x > b, that means the value of x is smaller than a and

 grater than b

- If x ≤ a and x ≥ b, that means the value of x is smaller than or equal a and

 grater than or equal b

* Now lets solve the problem

∵ {x I x < -5}

∴ x is smaller than -5

∵ {x I x > 5}

∴ x is greater than 5

∵ {x I x < -5} ∩ {x I x > 5}

- The meaning of ∩ is the common numbers between the

 two sets, but there is no common numbers between the

 two sets

∴ {x I x < -5} ∩ {x I x > 5} = { }

∴ The solution set empty set or null set

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