What is the distributive property of 27 + 60

a. Brand G will end up costing $159.48 less than Brand F.

Answer:

a. Brand G will end up costing $159.48 less than Brand F.

Step-by-step explanation:

If you calculate the compound interest of paying the $650 barbecue to five years the cos would be around 1050 after paying the compound interests of 13.01% monthly, and when you calculate the cost of paying off a $200 over 3 years the cost of the three would be $898, so it would be cheaper to buy the three $200 barbecues over the spam of 15 years, that would be the answer.

2l+2w=100
2(w+20)+2w=100
2w+40+2w=100
4w+40=100
4w=60
w=15
l=w+20
l=15+20
Greatest length is 35ft.

Answer:

a) The greatest possible length is 35.

b) l = w + 20

Step-by-step explanation:

The farmer wants the length of the pen to be 20ft longer than the width. If we use w to represent the width. Then the length would be w + 20

The problem first ask us to find the greatest possible length considering the fencing will be no more than 100ft.

We know that the perimeter of a rectangular area is: 2l + 2w (where l is the length and w the width)

Therefore for the fencing we would need 2l + 2w ≤ 100.

We are going to substitute the values for l and w that we mentioned at the beginning and solve for w:

2l + 2w ≤ 100

2(w+20) +2w ≤ 100

2w + 40 +2w ≤ 100

4w ≤ 100 - 40

4w ≤60

w ≤ 15

Therefore the width has to be less or equal to 15.

Since the length is 20 ft longer than the width, the greatest possible length happens when the width has its greatest value.

So when w = 15, the length is 35 and this is the greatest possible length of it.

b) The expression that represents the length (as we said before) is w + 20

25%

3.24*.25= .81
3.24+.81=4.05

Answer:

percent increase = 25%

Step-by-step explanation:

The price of a gallon of milk has increased from $3.24 to $4.05

LEt x be the percentage increase

intitial cost + initial cost times percentage = new cost

[tex]3.24 + 3.24 (\frac{x}{100})= 4.05[/tex]

Subtract 3.24 from both sides

[tex]3.24 (\frac{x}{100})= 0.81[/tex]

divide by 3.24 on both sides

[tex](\frac{x}{100})= 0.25[/tex]

Multiply both sides by 100

x= 25 %

Let

q------> the number of quarters coins

d------> the number of dollars coins

we know that

[tex]1\ quarter=\$0.25[/tex]

[tex]q+d=22[/tex]

[tex]q=22-d[/tex] ------> equation A

[tex]0.25q+d=10.75[/tex] -----> equation B

substitute equation A in equation B

[tex]0.25[22-d]+d=10.75[/tex]

therefore

the answer is the option

[tex]0.25[22-d]+d=10.75[/tex]

An equation is formed when two equal expressions are equated together with the help of an equal sign '='. The correct option is C.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given that Giuliana has 22, quarters and dollar coins worth a total of $10.75.

Let the number of dollar coins be represented by d, while the number of quarter coins be represented by (22-d). Therefore, the sum of the total amount that is with Giuliana can be written as,

(1 x d) + (0.25 x (22-d)) = 10.75

d + 0.25(22-d) = 10.75

Hence, the equation can be used to find d, the number of dollar coins Giuliana has is 0.25d + 22 – d = 10.75.

Learn more about Equation:

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So your equation will be:

2(x+6) + 2(x+2) = 2(x+4) + 2(2x-2)

First, divide everything by 2

x+6+x+2 = x+4+2x-2

Then, combine like terms

2x+8 = 3x+2

Move the variables (the x's) to one side and the numbers to the other by subtracting 2x from one side and then 2 from the other

6 = 1x or 6 = x

Now that you know that x = 6, you go back to Earl's length and width equations

Length = x+2
Width = x+6

And plug in the value of x you got (6)

Length = 6+2 = 8
Width = 6+6 = 12

There are you answers! Hope this helped! (remember to add units, in this case the units are feet)

check the picture below.

notice, the gift box is just 6 rectangles stacked up to each other at the edges,

left and right, two rectangles of 32x40

top and bottom, two rectangles of 25x32

front and back, two rectangles of 25x40

so, just get the area of all 6 rectangles, add them up, and that's the "surface area" of the rectangular prism, and that's how much paper will be needed to cover it.

Okay. We know that Center A charges $395 for an entire year. For Center B, there is a $25 sign up fee to pay one time, and then there is $15 monthly fee and $5 per aerobics class. There are 12 months in 1 year and 15 * 12 = 180. There are 52 weeks in 1 year, so 5 * 52 is 260. 260 + 180 + 25 = 465. He would pay $465 a year at Center B. Based off of the numbers, if Billy were to use a facility for only a year and go to aerobics once a week, then Center A is definitely cheaper than Center B. 

The Least expensive club for Billy to use for a year would be; Center B

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Let just compare the cost of both the centers.

Cost of Center A:

One time charge of $495 in one complete year.

Cost of Center B:

Flat $25 dollar sign up fee

$15 per month, thus 15 x 12 = 180 dollars a year

$5 per aerobic class, so   5 x 52 = 260. dollars a year (given that Billy goes to class once a week)

There are 52 weeks in a year.

260 + 180 + 25 = 465  dollars

Hence, Center B would cost 30 dollars cheaper.

The Least expensive club for Billy to use for a year would be; Center B

Learn more about the unitary method, please visit the link given below;

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51.25% is the answer for the problem

Answer:

48.75%

Step-by-step explanation:

If total number of people that voted = 240

Number of votes Garth got = 117

% vote he got = Number of Garth vote/Total number if vote ×100℅

% vote gotten by Garth = 117/240×100%

% vote gotten by Garth = 48.75%

The answer is D since 1/4 of the pineapple juice will give you the pinejuice

Answer: D

Step-by-step explanation: y costs less than p, only  1/4

as much. This translates to y =  1/4p or y =p/4.

30-2q=16
-2q=16-30
-2q=-14
q=7

Answer:- c. 0.5sin30°

Explanation:-

Let AB= 0.5 miles be the distance across the lake to 60º north of east.

AC= distance travel to the east

Now, in right ΔABC

[tex]sin60^{\circ}=\frac{AC}{AB}\\\\\Rightarrow\ AB=ACsin60^{\circ}\\\Rightarrow\ AB=0.5\ sin60^{\circ}[/tex]

Now Distance towards west  [tex]AD=|\ -0.5\ sin60^{\circ}|[/tex] [distance is a positive quantity]

[tex]AD=0.5\ sin60^{\circ}[/tex]

[tex]AD=0.5\ cos(90^{\circ}-60^{\circ})[/tex]  [Taking complementary angle of 60° ]

[tex]AD=0.5\ cos(30^{\circ})[/tex]

Thus C. is the right option.

Answer:

the answer is C.

Step-by-step explanation:

$250. You would divide $1000 by 4 to get each 1/4 equaling $250, that would allow the dryer to be $750 which is 3x250, and 750+250 is 1000. So the washer is $750 and the dryer is $250

The washer is worth $750 the dryer is 150

Parameterize the line segment (call it [tex]C[/tex]) by

[tex]\mathbf r(t)=\langle0,0,1\rangle(1-t)+\langle2,1,0\rangle t=\langle2t,t,1-t\rangle[/tex]

where [tex]0\le t\le1[/tex]. Then the work done by [tex]\mathbf f(x,y,z)[/tex] along the line segment is

[tex]\displaystyle\int_C\mathbf f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\mathbf f(x(t),y(t),z(t))\cdot\langle2,1,-1\rangle\,\mathrm dt[/tex]
[tex]=\displaystyle\int_0^1\langle2t-t^2,t-(1-t)^2,(1-t)-(2t)^2\rangle\cdot\langle2,1,-1\rangle\,\mathrm dt[/tex]
[tex]=\displaystyle\int_0^1(t^2+8t-2)\,\mathrm dt=\frac73[/tex]

Convert 16 tenths into .16 so 
5 - .16 = 4.84

Let d = number of dimes
Let n = number of nickels

d + n = 1530

A dime is worth $0.10. d dimes are worth 0.1d.
A nickel is is worth $0.05. n nickels are worth 0.05n.

0.1d + 0.05n = 127.45

Solve the first equation for d and substitute into the second equation.

d = 1530 - n

0.1(1530 - n) + 0.05n = 127.45

153 - 0.1n + 0.05n = 127.45

-0.05n = -25.55

n = 511

Now substitute this value in the first original equation.

d + n = 1530

d + 511 = 1530

d = 1019

He has 511 nickels and 1019 dimes.

Hello!

First, let's write the problem.
[tex]9\le \:17-4x[/tex]
We are going to switch sides in order to have the x on the left side.
[tex]17-4x\ge \:9[/tex]
Subtract 17 from both sides.
[tex]17-4x-17\ge \:9-17[/tex]
[tex]-4x\ge \:-8[/tex]
We have two options, divide both sides by -4, or multiply both sides by -1 in order to reverse the inequality. Let's try the second option.
[tex]\left(-4x\right)\left(-1\right)\le\left(-8\right)\left(-1\right)[/tex]
[tex]4x\le \:8[/tex]
Divide both sides by 4.
[tex]\frac{4x}{4}\le \frac{8}{4}[/tex]

Our final answer would be,
[tex]x\le \:2[/tex]

You can feel free to let me know if you have any questions regarding this!
Thanks!

- TetraFish

The point slope form of the line has the following form:

y – y1 = m (x – x1)

 

The slope m can be calculated using the formula:

m = (y2 – y1) / (x2 – x1)

m = (3 - 0) / (0 – 4) = - ¾

 

So the whole equation is:

y – 0 = - ¾ (x – 4)

y = - ¾ (x – 4) or

y = - 0.75 (x – 4)

Yes, because when you look at the number 6 is the hundreds, 4 is the tenths, and three is a regular number.  if you change the 3 to a zero and get rid of the 6 you would get 40 as your answer. 

Final answer:

Stacy is correct in saying that the 4 in 643 has a value of 4 tens or 40, as numbers can be broken down by place value, with each digit representing a different value depending on its position.

Explanation:

I do agree with Stacy's reasoning. The number 643 can be broken down into its place values: the 6 is in the hundreds place, representing 600; the 4 is in the tens place, representing 40; and the 3 is in the ones place, representing 3. Therefore, the value of the 4 in 643 is indeed 4 tens, or 40, as Stacy has indicated.

To visualize this, imagine the number 643 written on a place value chart:

Hundreds: 6

Tens: 4

Ones: 3

This confirms that the digit 4 in the tens place contributes 40 to the overall value of the number 643.

-9x ≥ 27
9x <= -27
  x <= -3

hope it helps

Answer:

x<=-3

Step-by-step explanation:

@countrygurl4464

snap

Given that in a national highway Traffic Safety Administration (NHTSA) report, data provided to the NHTSA by Goodyear stated that the mean tread life of a properly inflated automobile tires is 45,000 miles. Suppose that the current distribution of tread life of properly inflated automobile tires is normally distributed with mean of 45,000 miles and a standard deviation of 2360 miles.

Part A:

Find the probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is between two numbers, a and b is given by:
[tex]P(a \ \textless \ X \ \textless \ b) = P(X \ \textless \ b) - P(X \ \textless \ a) \\ \\ P\left(z\ \textless \ \frac{b-\mu}{\sigma} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles is given by:
[tex]P(42,000 \ \textless \ X \ \textless \ 46,000) = P(X \ \textless \ 46,000) - P(X \ \textless \ 42,000) \\ \\ P\left(z\ \textless \ \frac{46,000-45,000}{2,360} \right)-P\left(z\ \textless \ \frac{42,000-45,000}{2,360} \right) \\ \\ =P(0.4237)-P(-1.271)=0.66412-0.10183=\bold{0.5623}[/tex]


b. Find the probability that randomly selected automobile tire has a tread life of more than 50,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, a, is given by:
[tex]P(X \ \textgreater \ a) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of more than 50,000 miles is given by:
[tex]P(X \ \textgreater \ 50,000) = 1 - P(X \ \textless \ 50,000) \\ \\ =1-P\left(z\ \textless \ \frac{50,000-45,000}{2,360} \right)=1-P(z\ \textless \ 2.1186) \\ \\ =1-0.98294=\bold{0.0171}[/tex]


Part C:

Find the probability that randomly selected automobile tire has a tread life of less than 38,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, a, is given by:
[tex]P(X \ \textless \ a) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of less than 38,000 miles is given by:
[tex]P(X \ \textless \ 38,000) = P\left(z\ \textless \ \frac{38,000-45,000}{2,360} \right) \\ \\ =P(z\ \textless \ -2.966)=\bold{0.0015}[/tex]


d. Suppose that 6% of all automobile tires with the longest tread life have tread life of at least x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, x, is given by:
[tex]P(X \ \textgreater \ x) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at least x miles is 6%.

Thus:
[tex]P(X \ \textgreater \ x) =0.06 \\ \\ \Rightarrow1 - P(X \ \textless \ x)=0.06 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.06=0.94 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 1.555) \\ \\ \Rightarrow \frac{x-45,000}{2,360}=1.555 \\ \\ \Rightarrow x-45,000=2,360(1.555)=3,669.8 \\ \\ \Rightarrow x=3,669.8+45,000=48,669.8[/tex]
Therefore, the value of x is 48,669.8


e. Suppose that 2% of all automobile tires with the shortest tread life have tread life of at most x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, x, is given by:
[tex]P(X \ \textless \ x) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at most x miles is 2%.

Thus:
[tex]P(X \ \textless \ x)=0.02 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.02=0.98 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 2.054) \\ \\ \Rightarrow \frac{x-45,000}{-2,360}=2.054 \\ \\ \Rightarrow x-45,000=-2,360(2.054)=-4,847.44 \\ \\ \Rightarrow x=-4,847.44+45,000=40,152.56[/tex]
Therefore, the value of x is 40,152.56

1. slope = (n-k)/(m-j) 2. slope = (n-k))/(m-j) 3. P" = (m,n+e-3) 1. The slope of a line is the ratio between the change in y in regard to the change in x. Since we have two known points on the line r, we can simply subtract their respective x and y coordinates and divide. So slope = (n-k)/(m-j) One thing to pay attention to is to do the subtraction IN THE SAME ORDER. The actual order doesn't matter as long as it's the same for both top and bottom. For instance, this is another equation for the slope that's just as valid. slope = (k-n)/(j-m) 2. This is the exact same way. Just subtract the different y coordinates and divide by the difference between the x coordinates. slope=((n+e)-(k+e))/(m-j) Now because of the associative property, we can do some rearrangement of the expression to get slope=(n+e-k-e))/(m-j) and the "e" terms cancel each other, giving slope=(n-k))/(m-j) And you'll see that the slope is the same as for problem #1 above. 3. For this, let's look at the coordinates of point P' P' = (m,n+e) Since we want to move it 3 units down, just subtract 3 from the y coordinate, so P" = (m,n+e-3)

least 3/5, 0.65, 0.75, 7/8 greatest

the answer is A 5(5^3/2/5)^2

5(5^3/2/5)^2

= 5 (125/2/5)^2


= 5 ( 125/2  x 1/5 ) ^2

= 5 ( 12.5) ^2 

= 5 x 156.25

= 781.25 >>>>>>>>>>>>>>>>>>>>>>>> Not equal to 125

= 

The decimal... lol  thats what mt grandmom told me

The decimal point without the decimal point there is no decimal at all. 
i hoped that works ill give you an example if you are still confused 

if you are trying to turn this number 89 into a decimal you would have to do 8.9 if you don't than  89 is just a number not a decimal if you forget the decimal you will more than likely get the question incorrect.

24 is the result. 1/3 of 36 is 12 so you are subtracting 12 from 36.

 1/3=0.33 so then you do 36.00-0.33=35.67 

Hope i helped

Hello there! You can do something like:
2/3 of a cake was sitting in the kitchen. You decide to eat 1/4 of it. How much of the whole cake did you eat?
Hope this helps you!

You made
2/3 batch of cookies but then you decided to give away
1/4 to some friends... How much did you give away?

Answer:

→Number of people in the fitness club= 36 People

→Number of people who lifted weights [tex]=\frac{3}{8}\times 36=\frac{108}{8}[/tex]

→Number of people who did cross training [tex]=\frac{1}{3}\times 36=12[/tex]

=12 People

→Number of people who were running

 [tex]=1-\frac{3}{8}-\frac{1}{3}\\\\=\frac{24-9-8}{24}\\\\=\frac{7}{24}[/tex]

To determine the fraction of people running in the fitness studio, subtract the fractions of people lifting weights and doing cross training from the total, which comes to 7/24.

The fraction representing the number of people running can be found by adding the fractions of people lifting weights and doing cross training and subtracting that from the total, which gives the fraction of people running. Here's how:

Given: 3/8 lifting weights, 1/3 doing cross training, and the total is 1 (representing the whole).To find the fraction running: 1 - (3/8 + 1/3) = 1 - (9/24 + 8/24) = 1 - 17/24 = 7/24.

subtract 5ooo from 26800

26800 - 5000 = 21800

 now multiply that by 15%

15% = 0.15

21800 * 0.15 = 3270

 he paid $3,270 in taxes

The tomato is not picked because they do not need it nomore and that it only ways 4 ounces.

The length of the curve of intersection of the cylinder 4x2 + y2 = 4 and the plane x + y + z = 9 is found by parameterizing the ellipse formed by the intersection, finding the derivatives with respect to the parameter, and integrating these derivatives over one period of the parameter.

Since the equation of the cylinder has x and y terms, we'll start by solving the plane's equation for z: z = 9 - x - y. Substituting this into the cylinder's equation gives 4x² + y² = 4, which is indeed the equation of an ellipse in terms of x and y. Next, we parameterize this ellipse using trigonometric functions: x = cos(t), y = 2sin(t), where 0 ≤ t < 2π.

Substituting these into the plane's equation gives z = 9 - cos(t) - 2sin(t). Now we'll use the formula for arc length, which is the integral of the square root of the sum of the derivatives squared:

L = ∫ √((dx/dt)² + (dy/dt)² + (dz/dt)²) dt. We evaluate this integral from t = 0 to t = 2π using the derivatives of x, y, and z with respect to t.

Finally, we can compute this integral and round the result to four decimal places. The analytical computation of the integral may be complex and require special functions such as elliptic integrals, depending on the resulting expression after derivatives are calculated.