What is the difference between the energy of spring A, stretched 0.6 meters, and spring B, stretched 0.3 meters, if they have the same spring constant? A. Spring A has more potential energy than spring B. B. Spring A has less potential energy than spring B. C. Springs A and B have the same potential energy. D. Springs A and B have the same kinetic energy.

Answers

Answer 1

Your answer would be A, Spring A has more potential energy.

Potential energy is exactly what it sounds like - energy that has the potential to exist due to stressors, but doesn't yet. In this case, the spring is ready to jump back into its original position however it can't because of it still being stretched, therefore this tension is what creates potential energy.

When you measure potential energy, the one with greater of it is the one where it has more stress being placed on it. In this case, spring A is being stretched furthest so it has the most potential energy.

Hope this helped!

Answer 2

Answer:

a

Explanation:


Related Questions

what is the ph of 0.001 m NaOH

Answers

Answer:

11.

Explanation:

For 0.001 M NaOH:

[OH⁻] = 0.001 M.

∵ pOH = - log[OH⁻]

∴ pOH = - log(0.001 M) = 3.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 3 = 11.

The pH of a 0.001 M NaOH solution is 11.00, as NaOH is a strong base that completely dissociates in water to give a hydroxide ion concentration equal to its molarity, and the pH is calculated from the hydrogen ion concentration derived from the dissociation constant of water.

The question is asking for the pH of a 0.001 M solution of NaOH, which is a strong base. In a strong base like NaOH, it dissociates completely in water, which means that the concentration of the hydroxide ions, [OH⁻], will also be 0.001 M. To find the concentration of hydrogen ions, [H+], we use the formula [H+] = 10⁻¹⁴ / [OH⁻].

Therefore, [H⁺] = 10⁻¹⁴ / 0.001 M = 1.0 x 10⁻¹¹ M. The pH is then calculated using the formula pH = -log[H+], which gives us pH = -log(1.0 x 10⁻¹¹) = 11.00.

How many moles of sodium carbonate contain 1.773 × 1017 carbon atoms?

Answers

Answer:

2.941 × 10⁻¹⁷ mol

Explanation:

1) Chemical formula of sodium carbonate: Na₂CO₃

2) Ratio of carbon atoms:

The number of atoms of C in the unit formula Na₂CO₃ is the subscript for the atom, which is 1 (since it is not written).

Hence, the ratio is 1 C atom / 1 Na₂CO₃ unit formula.

This is, there is 1 atom of carbon per each unit formula of sodium carbonate.

3) Calculate the number of moles in 1.773 × 10⁷ carbon atoms

Divide by Avogadro's number: 6.022 × 10²³ atoms / mol

number C moles  = 1.773 × 10⁷ atoms / (6.022 × 10²³ atoms/mol)

number C moles = 2.941 × 10⁻¹⁷ mol

Since, the ratio is 1: 1, the number of moles of sodium carbonate is the same number of moles of carbon atoms.

What do electromagnetic waves carry? How are they produced Through which media can they move? Where do they transfer energy? What do they not transfer? What do mechanical waves carry? How are they produced? Through which media can they move? Where do they transfer energy? What do they not transfer?

Answers

Answer:

they are transfer from the  towers

Explanation:

How many grams of NaNO3 would have to be added to 100. grams of water at 45°C to make a saturated solution of this salt? 1. 100. 2. 110. 3. 120. 4. 130.

Answers

Answer:

2. 110.

Explanation:

Kindly find the attached image.

From the solubility curve, you can find that at 45°C to make a saturated solution of this salt, you should add 110 g of NaNO₃.

So, the right choice:  2. 110.

The dissolution of  the solute in the solvent at the specified temperature is termed as solubility. The maximum solubility of sodium nitrate in the water at 45 degree Celsius in 110 grams.

What is the solubility curve?

The increase in temperature of the solvent resulted in the weaker the intermolecular force of solvent, and increases the solubility.

The solubility curve is drawn for the maximum amount of solute that can be dissolved in the solvent at the specified temperature.

From the solubility curve of sodium nitrate, the maximum amount of sodium nitrate in the water at 45 degree Celsius is 110 grams. Thus, option 2 is correct.

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How did Albert Einstein explain the photoelectric effect?

A) Light is made up of electrons
B) Light is made up of atoms
C) Light is made up of electricity
D) Light is made up of photons

Answers

Answer: D) Light is made up of photons

Light, Einstein said, is a beam of particles whose energies are related to their frequencies according to Planck's formula. When that beam is directed at a metal, the photons collide with the atoms. If a photon's frequency is sufficient to knock off an electron, the collision produces the photoelectric effect.

Option D, Light is made up of photons.

What is photoelectric effect?

The photoelectric effect is a phenomenon where electrons are emitted from the metal surface when the light of sufficient frequency is incident upon. The concept of the photoelectric effect was first documented in 1887 by Heinrich Hertz and later by Lenard in 1902. But both the observations of the photoelectric effect could not be explained by Maxwell’s electromagnetic wave theory of light.

What is Einstein's photoelectric effect?

Light, Einstein said, is a beam of particles whose energies are related to their frequencies according to Planck's formula. When that beam is directed at a metal, the photons collide with the atoms. If a photon's frequency is sufficient to knock off an electron, the collision produces the photoelectric effect.

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Classify these definitions as that of an Arrhenius acid, an Arrhenius base, or other. Arrhenius acid definition Arrhenius base definition OtherA substance that can donate a hydrogen ion to another substanceA substance that produces an excess of hydroxide ion (-OH) in aqueous solution.A substance that produces an excess of hydrogen ion (H+) in aqueous solution

Answers

Answer:

Explanation:

A substance that produces an excess of hydroxide ion (-OH) in aqueous solution.

       This is an arrhenius Base

According to the arrhenius theory, a base is a substance that combines with water to produce excess hydroxide ions, OH⁻ in an aqeous solution. Examples are :

Sodium hydroxide NaOHPotassium hydroxide KOH

A substance that produces an excess of hydrogen ion (H+) in aqueous solution

      This is an arrhenius Acid

An arrhenius acid is a substance that reacts with water to produce excess hydrogen ions in aqueous solutions.

Examples are;

Hydrochloric acid HClHydroiodic acid HIHydrobromic acid HBr

Seawater contains approximately 3.5%NaCl by mass and has a density of 1.02 g/mL. What volume of seawater contains 7.5 g of sodium ?

Answers

Final answer:

To find the volume of seawater containing 7.5 g of sodium, one must first convert this mass to the equivalent mass of NaCl, then calculate the total mass of seawater needed, and finally use the density of seawater to find the corresponding volume.

Explanation:

The question asks to calculate the volume of seawater that contains 7.5 g of sodium. First, we need to determine the mass of NaCl which corresponds to 7.5 g of sodium. Given that the atomic weight of sodium (Na) is approximately 23 g/mol, we can find the amount of NaCl using the ratio of the molecular weight of NaCl (58.44 g/mol) to that of Na. Once we have this mass, we can use the percentage of NaCl in seawater (3.5%) to find the total mass of seawater needed. Finally, given the density of seawater (1.02 g/mL), we can calculate the volume of seawater containing this total mass.

Final answer:

To calculate the volume of seawater that contains 7.5g of sodium, we use the concentration of NaCl in seawater and the atomic masses of Na and Cl. We find that approximately 529.00mL of seawater is needed to provide 7.5g of sodium.

Explanation:

To determine the volume of seawater containing 7.5 g of sodium, we must first understand the concentration of NaCl in seawater and the atomic mass of sodium. Seawater contains approximately 3.5% NaCl by mass. Given that the atomic masses of Na and Cl are 23.0 and 35.4 respectively, we can calculate the mass of sodium in seawater. Using the percentage by mass and the given density of seawater, we can then calculate the volume.

The mass percentage of NaCl in seawater is 3.5%, which means in 100g of seawater, there is 3.5g of NaCl. To find the mass of sodium only, we consider the molar mass ratio of Na to NaCl, which is 23.0 / (23.0 + 35.4). Therefore, the mass of sodium in 3.5g of NaCl is given by:
(23.0 / 58.4) × 3.5g.

To find the mass of Na in 100g of seawater, we multiply this by the mass percentage of NaCl in seawater:
(23.0 / 58.4) × 3.5g × 1.00 = 1.39g (rounded to two decimal places).

Thus, to find the amount of seawater containing 7.5g of Na, we would do the following calculation:
(100g seawater / 1.39g Na) × 7.5g Na= 539.57g of seawater.

Finally, to convert this mass to volume using the density of seawater (1.02g/mL), the volume is:
539.57g / 1.02g/mL = 529.00mL (rounded to two decimal places).

Therefore, approximately 529.00mL of seawater contains 7.5g of sodium.

Which proportionality applies to avogadro’s law?

Answers

Answer:

The volume of the gas is directly proportional and amount (moles) of the gas at constant T and P.

Explanation:

Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

For a given mass of an ideal gas, the volume of the gas is directly proportional and amount (moles) of the gas at constant T and P.

V ∝ n.

Which element forms an ionic compound when it reacts with lithium

Answers

Answer:

Fluorine

Explanation:

Flourine forms an ionic bond when combined with lithium. The valence electronic shell of lithium has just one single electron. Fluorine has 7 electrons in its valence shell but requires just a single electron to complete its octet. When lithium and fluorine combines, fluorine achieves its octet and lithium resembles Helium, a noble gas. This transfer of electron between Li and F is what results in an ionic bond between the two elements. It is also worthy to note that for an ionic bond to form, the electronegative difference between the two atoms should be greater than 0.7.

Fluorine has an electronegativity of 4.0 and that of Li is 1.0. The difference is 3.0. This implies that an ionic compound would be formed. The compound is LiF, Lithium Fluoride.

interstellar clouds are primarily composed of nitrogen and oxygen. true or false?

Answers

Answer:

The statement is false

Explanation:

Interstellar clouds are not primarily composed of nitrogen and oxygen. Interstellar clouds are generally an made up of gas, plasma, and dust in our and other galaxies.

Answer: False

Explanation:

An interstellar cloud can be defined as the accumulation of gas, plasma and dust in our galaxy or other galaxy.

The composition of interstellar clouds are determined by studying the electromagnetic radiation that is received by radio waves, gamma rays on the electromagnetic spectrum.

When The electromagnetic radiations was studied then organic compounds like vinyl chloride and methanol which was not expected.

What are the two oxidation states of nitrogen in nh4no2?

Answers

Answer:

Oxidation state of N in (NH₄) is (-3).

Oxidation state of N in (NO₂) is (+3).

Explanation:

NH₄NO₂ is dissociated according to the equation:

NH₄NO₂ → NH₄⁺ + NO₂⁻.

We can calculate the oxidation state:

NH₄⁺:

The total oxidation state of NH₄⁺ is (+1).

The oxidation state of H is known to be (+1).

∴ Oxidation state of N + 4(oxidation state of H) = +1.

∴ Oxidation state of N + 4(+1) = +1.

∴ Oxidation state of N = +1 - 4 = -3.

NO₂⁻:

The total oxidation state of NO₂⁻ is (-1).

The oxidation state of O is known to be (-2).

∴ Oxidation state of N + 2(oxidation state of O) = -1.

∴ Oxidation state of N + 2(-2) = -1.

∴ Oxidation state of N - 4 = -1.

∴ Oxidation state of N = -1 + 4 = +3.

Two oxidation states of nitrogen in NH₄NO₂ is +3 & -3.

What is oxidation state?

Oxidation state of any atom tells about the no. of electrons gain or looses from that atom.

NH₄NO₂ is dissociates as:

NH₄NO₂ → NH₄⁺ + NO₂⁻

Oxygen state of nitrogen in NH₄⁺ can be calculated as:

x + 4(1) = 1

x = 1 - 4 = -3

In NH₄⁺, oxidation state of hydrogen is +1 & whole charge on the ion is also +1.

Oxygen state of nitrogen in NO₂⁻ can be calculated as:

x + 2(-2) = -1

x = -1 + 4 = 3

In NO₂⁻, oxidation state of oxygen is -2 & whole charge on the ion is -1.

Hence, -3 & +3 are the oxidation states of nitrogen.

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How do you find the mass number of an element

Answers

Answer:

add up the mass of protons and neutrons

Explanation:

Answer:

To find the mass number of an element you add up the number of protons (atomic number) and neutrons.

Explanation:

The mass number is a specific property of the atoms, defined as the sum of the protons and neutrons, which are the subatomic particles that are in the nucleus of the atom.

The electrons do not count for the mass of atoms because their mass is about 1/1840 the mass of a proton or a neutron.

The relative masses of protons and neutrons is 1: 1, then they count equally.

As an example, the mass number of the atom carbon-12 is calculated in this way:

Atomic number of carbon: Z = 6 (6 protons)Number of neutrons: N = 6Mass number: A = Z + N = 6 + 6 = 12.

The number 12 added to the name in carbon-12, stands for its mass number.

Also, the mass number is indicated as a superscript to the left of the chemical symbol of the element, and the atomic number as a subscript to the left of the chemical symbol. For the example of carbon-12 that is:

[tex]^{12}_{6}C[/tex]

The number of grams per mole of something is also known as_______

Answers

Answer:

Molar mass

Explanation:

This is a counting unit which represents the mass in grams of a substance that make up one mole of the substance. This mass is calculated as follows:

Molar mass = Mass/ Number of moles

Units: grams/mol

Answer:

Molar mass is also known as number of grams/mole of something.

Explanation:

A substance's molar mass is defined as substance mass divided by the substance amount in moles. It is expressed in Kg/mol but gram/mol is used for the convenience for study.

It is often used in chemistry for the conversion of mass in grams to substance moles. The relation that is used to convert the gram top mole is that the molar mass is equal to the molecular mass in grams.

Ethanoic acid and 1-butanol can react to produce water and a compound classified as an

Answers

Answer:

Ethanoic acid and 1-butanol can react to produce water and a compound classified as an ester.

Explanation:

Ethanoic acid reacts with ethanol in the presence of concentrated sulphuric acid as a catalyst to produce the ester "butyl ethanoate" and water:

CH₃COOH + CH₃CH₂CH₂CH₂OH → CH₃COOCH₂CH₂CH₂CH₃.

Ethanoic acid reacts with 1-butanol in an esterification reaction to produce butyl ethanoate and water. This is a common type of reaction in organic chemistry, resulting in the formation of an ester.

When ethanoic acid reacts with 1-butanol, a type of chemical reaction called esterification occurs. Esterification typically involves the reaction of a carboxylic acid (in this case, ethanoic acid) with an alcohol (here, 1-butanol) to form an ester and water. The specific ester formed from ethanoic acid and 1-butanol is called butyl ethanoate, and this is the compound classified as an ester mentioned in the question. The reaction can be summarized by the following equation:

CH₃COOH (ethanoic acid) + C₄H₉OH (1-butanol) →CH₃COOC₄H₉(butyl ethanoate) + H₂O (water)

This reaction typically requires an acid catalyst to proceed, commonly sulfuric acid or hydrochloric acid. The process of creating esters like butyl ethanoate is important in both organic chemistry and industry, where esters are used as fragrances, flavors, and solvents.

*Giving Brainly with the points* Best answer gets it
List two uses of high-density polyethylene other than those listed in the
table.
Two plastics that are targeted for recycling from household waste are
polyethylene terephthalate (PETE) and high density polyethylene (HDPE).
One of the problems of recycling such materials is separating them. Suppose
you have been hired to set up a process for separating large quantities of
waste plastic that is a mixture of PETE and HDPE. Describe how you might
perform this separation.

Answers

List two uses of high density polyethylene other than those listed in the table:
HDPE plastic is also used to store bleach, baby powder, and vitamins.

Two plastics that are targeted for recycling from household waste are polyethylene terephthalate (PETE) and high density polyethylene (HDPE). One of the problems of recycling such materials is separating them. Suppose you have been hired to set up a process for separating large quantities of waste plastic that is a mixture of PETE and HDPE. Describe how you might perform this separation:
To separate PETE and HDPE plastics on an industrial scale, you could place large quantities of recycled products in a vat water so the PETE products sink while the HDPE products float.

Describe the methods by which an electric potential develops in primary cells and dry cells.

Answers

Answer:

In a primary cell, two electrodes (one of copper and other of zinc) of metal atoms are used. These electrodes are dipped in an electrolyte solution that causes the metals to produce their respective positive and negative ions.

In this way, the flow of charges takes place and supply the electricity to the source.

Unlike a primary cell, a dry cell contains paste of an electrolyte instead of the solution. The contents of electrolyte paste react with each other through a chemical process and convert the chemical energy into electrical energy.

Answer:

In primary cells, an electric potential develops through chemical action between the plates within the cell. Positively charged ions of zinc enter the acid and free electrons released from zinc atoms collect on the zinc plate, which results in a negative charge. At the same time, positively charged ions of hydrogen from the acid remove free electrons from the copper plate, which becomes positively charged. Through a conducting material connecting the plates, free electrons move from the zinc plate to the copper plate as long as the chemical reaction lasts.

Dry cells also develop electric potential via chemical actions within the cell. Free electrons removed from the carbon rod collect on a zinc can. The rod exhibits a positive charge and the can becomes negatively charged; this allows for an electric potential to develop between these two items. Through a conducting material connecting the can to the rod, free electrons move from the can to the rod as long as the conducting path exists.

Explanation:

straight from Penn

Compared with the freezing-point depression of a 0.01 m c6h12o6 solution, the freezing-point depression of a 0.01 m nacl solution is

Answers

Answer:

Twice  as much.

Explanation:

That's because the freezing point depression depends on the total number of solute particles.

C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)

0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.

NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)

1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).

That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.

A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO3 in a coffee cup calorimeter. If both solutions were initially at 35.00°C and the temperature of the resulting solution was recorded as 37.00°C, determine the ΔH°rxn (in units of kJ/mol NaOH) for the neutralization reaction between aqueous NaOH and HCl. Assume 1) that no heat is lost to the calorimeter or the surroundings, and 2) that the density and the heat capacity of the resulting solution are the same as water. - 34.4 kJ/mol NaOH -169 kJ/mol NaOH -55.7 kJ/mol NaOH -27.9 kJ/mol NaOH -16.7 kJ/mol NaOH

Answers

Answer:

[tex]\boxed{\text{-55.8 kJ/mol NaOH}}[/tex]

Explanation:

NaOH + HNO₃ ⟶ NaNO₃ + H₂O

There are two energy flows in this reaction.

[tex]\begin{array}{cccl}\text{Heat from neutralization} & + &\text{Heat absorbed by water} & = 0\\q_{1} & + & q_{2} & =0\\n\DeltaH & + & mC\Delta T & =0\\\end{array}[/tex]

Data:

V(base) = 100.0 mL; c(base) = 0.300 mol·L⁻¹

V(acid) = 100.0 mL; c (acid) = 0.300 mol·L⁻¹  

        T₁ = 35.00 °C;          T₂ = 37.00 °C

Calculations:

(a) q₁

[tex]n_{\text{NaOH}} = \text{0.1000 L } \times \dfrac{\text{0.300 mol}}{\text{1 L}} = \text{0.0300 mol}\\\\n_{\text{HNO}_{3}} = \text{0.1000 L } \times \dfrac{\text{0.300 mol}}{\text{1 L}} = \text{0.0300 mol}[/tex]

We have equimolar amounts of NaOH and HNO₃

n = 0.0300 mol

q₁ = 0.0300ΔH

(b) q₂

 V = 100.0 mL + 100.0 mL = 200.0 mL

m = 200.0 g

ΔT = T₂ - T₁ = 37.00 °C – 35.00 °C = 2.00 °C

q₂ = 200.0 × 4.184 × 2.00 = 1674 J

(c) ΔH

0.0300ΔH + 1674 = 0

          0.0300ΔH = -1674

                      ΔH = -1674/0.0300

                      ΔH = -55 800 J/mol

                      ΔH = -55.8 kJ/mol

[tex]\Delta_{r}H^{\circ} = \boxed{\textbf{-55.8 kJ/mol NaOH}}[/tex]

Final answer:

The neutralization of NaOH and HNO3 is exothermic, releasing heat which raises the temperature of the solution. The heat of the reaction can be calculated by considering the total mass of the solution and the rise in temperature, and should be divided by the moles of NaOH used to give the enthalpy change in kJ/mol.

Explanation:

When aqueous NaOH is mixed with HNO3 in a coffee cup calorimeter, a neutralization reaction occurs. The equation for this reaction is NaOH (aq) + HNO3(aq) → NaNO3(aq) + H2O(l). Since it is a strongly exothermic reaction, heat is released causing the rise in observed temperature. To determine the ΔH°rxn, calculate the heat change using the equation q = ms ΔT, where m is the total mass of the solution, s is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature. Convert this energy to kj, and because no heat is lost to the surroundings, the heat absorbed by the solution is the same as the heat released by the reaction. This heat of reaction is then divided by the amount of NaOH used in the reaction to give the enthalpy change in kJ/mol NaOH, which can be used to pick one of the possible answers provided.

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4 what is the net amount of heat released when two moles of c2h6(g) are formed from its elements at 101.3 kpa and 298 k?


I know the final answer is -168 bc somehow you get -84 from somewhere i'm just not sure where that comes from.

Answers

Answer:

because reference table I shows that delta h for one mole of c2h6(g) is 84.0 kj so for 2 moles of c2h6(g) is 168.0kj

168 kJ/mol is the net amount of heat released when two moles of C₂H₆ are formed from its elements at 101.3 kpa and 298 K.

What is Enthalpy of formation ?

The standard reaction enthalpy for formation of the compound from the atoms or molecules at stable states that is temperature 298 K and Pressure 1 bar is called as enthalpy of formation.  

What is the enthalpy of ethane ?

1 Atm (Atmospheric pressure) = 101.3 KPa (Kilopascal)

At 1 atm and 298 K the enthalpy of formation of ethane is -84 kJ/mol.

The enthalpy of formation of 1 mole of C₂H₆ is 84 kJ/mol because heat is released here so enthalpy of formation is positive.

Therefore, the enthalpy of formation of 2 mole of C₂H₆ = 2 × 84 kJ/mol

                                                                                            = 168 kJ/mol

Thus from the above conclusion we can say that 168 kJ/mol is the net amount of heat released when two moles of C₂H₆ are formed from its elements at 101.3 kpa and 298 K.

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Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?

Answers

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

Divide the given moles through by the smallest which is C, 0.052mol. Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio. This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

Final answer:

The empirical formula of a compound containing 0.104 mol of potassium (K), 0.052 mol of carbon (C), and 0.156 mol of oxygen (O) is K2CO3, based on the smallest whole number ratio of moles of each element.

Explanation:

To determine the empirical formula of a compound from the amount of moles of each element, you need to find the smallest whole number ratio of the moles of each element. For the compound mentioned with 0.104 mol K (potassium), 0.052 mol C (carbon), and 0.156 mol O (oxygen), you can do this by dividing each mole value by the smallest of the amounts of moles present.

In this case, the smallest value is 0.052 mol (carbon). So you would divide the number of moles of each element by 0.052 mol:

K: 0.104 mol / 0.052 mol = 2C: 0.052 mol / 0.052 mol = 1O: 0.156 mol / 0.052 mol = 3

Therefore, the empirical formula is K2CO3.

A 1.50-liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25°C. Without changing the temperature, a piston is moved in the cylinder until the pressure in the cylinder is reduced to 1.00 atmospheres. The volume of the gas is _____.

Answers

Answer:

4.50 liters

Explanation:

Boyles law P1 · V1 =P2 · v2

V2=P1·V1÷P2

V2= 3 · 1.5 ÷ 1

What is the name of the ionic compound formed from lithium and bromine

Answers

Answer:

Lithium bromide, or LiBr, is the name of the iconic compound formed from lithium and bromine.

The ionic compound formed from lithium and bromine is called Lithium Bromide.

What more should you know about Lithium Bromide?

Lithium Bromide has the chemical formula LiBr. Lithium is a metal that belongs to the alkali metal group, while bromine is a non-metal that belongs to the halogen group.

When lithium and bromine react, they form an ionic compound, in which lithium donates an electron to bromine. Lithium becomes a positively charged ion, called a lithium ion, while bromine becomes a negatively charged ion, called a bromide ion.

The lithium ions and the bromide ions are then attracted to each other by the force of electrostatic attraction.

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All the chemical reactions that go on in organisms, whether they be plant or animal, are catalyzed by enzymes.
a. True
b. False

I think the answer is true but I need a second opinion.

Answers

Answer:

A. True

Explanation:

You are right, the answer is a. true!

if 58.67g of mercuric oxide were completely decomposed to generate 54.34 g of mercury how many grams of oxygen should have been produced

Answers

Answer:

4.33g

Explanation:

The reaction equation is given as:

        2HgO → 2Hg + O₂

Given parameters:

Mass of HgO = 58.67g

Mass of Hg produced = 54.34g

Unknown:

Mass of oxygen produced = ?

Solution

From the reaction equation, using the mole concept, it is possible to determine the mass of oxygen gas produced.

To do this, we first determine the molar composition of the mass of the given mercury oxide. Then we use the balanced reaction equation to determine the mass of oxygen produced:

Number of moles of HgO = [tex]\frac{mass of HgO}{Molar mass of HgO}[/tex]

Molar mass of HgO = 200.6 + 16 = 216.6gmol⁻¹

Number of moles of HgO = [tex]\frac{58.67}{216.6}[/tex] = 0.271mol

From the reaction equation, we know that:

           2moles of HgO produced 1 mole of O₂

           0.271moles of HgO would also produce, 0.136mol

Therefore, mass of O₂ gas produced = number of moles of O₂ x molar mass

    Molar mass of O₂ = 16x2 = 32gmol⁻¹

Mass of O₂ gas = 0.136 x 32 = 4.33g

Elements in group 2 are all called alkaline earth metals. What is most similar about the alkaline earth metals?

Answers

Answer:

A main similitary all the elments have in that group is they all have 2 valance electrons

Explanation:

Explanation:

As it is known that elements present in group 2 are also known as alkaline earth metals.

Elements that belong to this group are beryllium, magnesium, calcium, strontium, barium, and radium.

Since, all of them are placed in group 2 this means that all these elements have 2 valence electrons.

Hence, all these elements will also have similar chemical properties.

Please help on this one?

Answers

Answer:

[tex]\text{C. } _{36}^{85}\text{Kr}[/tex]

Explanation:

Your nuclear equation is  

[tex]_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}[/tex]

The main point to remember in balancing nuclear equations is that

the sum of the superscripts and must be the same on each side of the equation.the sum of the subscripts must be the same on each side of the equation.  

Then  

85 = 0 + y, so y = 85 - 0 = 0  

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.  

The nuclear equation becomes  

[tex]_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}[/tex]

Answer:

C

Explanation:

Which is the electron configuration for bromine? 1s22s22p63s23p64s23d104p5 1s22s22p63s23p64s23d104p6 1s22s22p63s23p44s23d104p5 1s22s22p63s23p64s23d94p5

Answers

Answer : The correct option is, [tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^5[/tex]

Explanation :

The given element bromine belongs to the group 17 and period 4. The symbol of bromine is, Br.

The atomic number of bromine = 35

The total number of electrons present in bromine element = 35

Electronic configuration : It is defined as the arrangement of electrons around the nucleus of an atom.

Hence, the correct electronic configuration of bromine is,

[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^5[/tex]

I believe the correct answer choice is A

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a lower temperature than a solution containing 5.00 g of compound B in 100. g of water. Which compound has the greater molar mass? Explain how you arrived at your answer.

Answers

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

[tex]\Delta T_{\text{f}} = K_{\text{f}} b[/tex]

where b is the molal concentration

[tex]b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}[/tex]

If m is constant (5 g), then

[tex]n \propto \dfrac{1}{M}[/tex]

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

Solute compound A caused a greater freezing point depression than compound B, suggesting that compound A has fewer particles in solution. Therefore, compound A must have the greater molar mass compared to compound B.

The question pertains to the concept of colligative properties, particularly, freezing point depression. Compound A, when dissolved in water, caused the freezing point to decrease more than compound B did under the same conditions. This behavior is explained by the colligative property of freezing point depression, which states that the freezing point of a solvent will decrease when a solute is dissolved in it.

The amount of freezing point depression is directly related to the number of solute particles in solution. Because both solutions contain the same mass of solute but compound A caused a larger freezing point depression, it must be that compound A has fewer particles in solution compared to compound B. Since fewer particles correspond to a larger molar mass, compound A has the greater molar mass.

Which terms could have a greatest common factor of 5m2n2? Check all that apply.m5n55m4n310m4n15m2n224m3n4

Answers

Answer:

The second and the third terms from the choices:

5m⁴n³, and10m⁴n¹⁵

Explanation:

The greatest common factor of a set of numbers is found by:

         1) Write each number as a product of prime factors, each factor raised to the corresponding exponent (power);

         2) Choose only the common prime factors, with the least exponent.

Example: find the greatest common factor of 35x²y³ and 15xy²

Prime factorization: 35x²y³ = 5¹ . 7¹ . x² . y³

                                         15xy² = 3¹ . 5¹ . x¹ . y²

Common factors (each raised to its least exponent): 5¹, x¹, and y²

Greatest common factor (make the product): 5 . x . y² = 5xy²

Now apply the process to the given terms:

m⁵n⁵ : these are prime factors

5m⁴n³: these are prime factors

10m⁴n¹⁵: prime factors = 2 . 5 . m⁴ n¹⁵

.

m²n²: these are prime factors

24m³n⁴: prime factors = 2³ . 3 . m³ n⁴

The terms that could have a greatest common factor of 5m²n², are those that include 5m²n², and those are:

5m⁴n³, and

2 . 5 . m⁴ n¹⁵ = 10m⁴n¹⁵

These are the second and the third terms from the choices.

Answer:

5m⁴n³, and

10m⁴n¹⁵

Explanation:

Easy Points


0°C = 273°k
True of False

Happy Summer

Answers

Answer:

True

Explanation:

0°C = 273°k

0°C = 273°k ....

It is true.

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