what is 9(x+86x)-800+900x

An equation that shows two ratios are equivalent is a proportion. Proportions can be applied in various fields like economics to show equivalent satisfaction based on price paid for goods, or in unit conversion to represent equivalent quantities in different units.

An equation showing that two ratios are equivalent is a proportion. A proportion is a mathematical statement that two ratios are equal. For example, 2/4 = 1/2 is a proportion because the two ratios are equivalent. Other forms of this equation could be obtained by rearranging terms, showing the direct and indirect proportions.

In a more practical context, ratios are used to compare the relationship between different quantities. For example, we could state the ratio of the prices of two goods should be equal to the ratio of the marginal utilities. When we divide the price of good 1 by the price of good 2, this should equal the marginal utility of good 1 divided by the marginal utility of good 2. This indicates that the utility or satisfaction obtained is equivalent based on the price paid.

Also, proportions can be used as a unit conversion factor where the ratio of two equivalent quantities expressed with different measurement units can lead to a conversion factor. For example, the lengths of 2.54 cm and 1 in. are equivalent, thus providing a ratio that could be used for conversion.

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Answer:

On (-2/3, 1) the given function is decreasing

Step-by-step explanation:

Do you know calculus?  If so:

Differentiate y = 2x^3 – x^2 – 4x + 5 and set the derivative = to 0:

dy/dx = 6x^2 - 2x - 4 = 0, or 3x^2 - x - 2 = 0.

This factors as follows:  (x - 1)(3x + 2) = 0.

The roots of this equation are {1, -2/3}.  

Plot these two roots on a number line and then set up intervals as follows:

(-infinity, -2/3), (-2/3, 1), (1, infinity)

Choose a test number from each interval:  { -1, 0, 2 }

By evaluating the derivative 6x^2 - 2x - 4 at each of these three test numbers, we get:

dy/dx = 6x^2 - 2x - 4 is positive on (-infinity, -2/3), and so we conclude that the given function is increasing on that interval.

dy/dx = 6x^2 - 2x - 4 is negative on (-2/3, 1), and so we conclude that the given function is decreasing on that interval.   To the nearest tenth:

(-0.7, 1)

To find where the function y = 2x^3 - x^2 - 4x + 5 is decreasing, calculate the derivative, set it less than zero, solve for x, and use a sign chart to determine the intervals where the function is decreasing. The correct interval is (1, ∞).

To determine where the function y = 2x3 − x2 − 4x + 5 is decreasing, we need to analyze its derivative. The first derivative of the function represents the slope of the tangent line to the curve at any given point, and when this slope is negative, the function is decreasing. Let's find the first derivative, f'(x) which is 6x2 − 2x − 4. To find where f'(x) is negative, we look for the x-values that make the derivative less than zero. This inequality can be solved by looking for the critical points where the derivative equals zero or is undefined, and then testing intervals around these points to see when the derivative is negative.

By factoring or using the quadratic formula, we find the critical points of f'(x) and then use a sign chart or test values to determine where the derivative is negative. For example, if we find that the derivative switches from positive to negative at x = 1, we can conclude that the function is decreasing for x values greater than 1. Therefore, the correct answer would be that the function is decreasing over the interval (1, ∞).

Answer:

The vertex is (2, 4), the domain is all real numbers, and the range is y ≥ 4.

Step-by-step explanation:

The equation of the parabola is [tex]f(x)=(x-2)^2+4[/tex]

The vertex form of the parabola is given by

[tex]f(x)=a(x-h)^2+k[/tex], here (h,k) is the vertex.

Comparing given equation with the vertex form of the parabola, we get

h = 2, k = 4

Hence, the vertex of the parabola is (h,k) = (2,4)

Now, domain is the set of x values for which the function is defined. The given function is defined for all real values of x.

Hence, domain is all real numbers.

Range is the set of y values for which the function is defined.

Since, here a = 1>0 hence it is a upward parabola and the vertex is the minimum point of this parabola.

Since, vertex is (2,4) hence, y values never less than 4.

Hence, range is y ≥ 4.

D is the correct options.

Answer:

18.8% (gradpoint)

Step-by-step explanation:

The percent of increase from 320 to 380 is approximately 18.8%. To calculate this, find the difference between the new and original values and divide by the original value, then multiply by 100 to get the percentage.

To find the percent of increase from 320 to 380, use the formula:

Percentage increase =
[(new value - original value) / original value]
× 100%

Firstly, calculate the change in value: 380 - 320 = 60.

Then, plug this change into the formula:

Percentage increase = (60 / 320) × 100%

Now, compute the result:

Percentage increase = (0.1875) × 100%

Convert this to a percentage:

Percentage increase = 18.75%

Finally, round to the nearest tenth of a percent if necessary:

Percentage increase
= approximately 18.8%

Let q = quarter

Let d = dime

Here is your system:

q + d = 23

0.25q + 0.10d = 3.80

Take it from here.

To determine which loan will have a higher balance at the time of repayment, we need to calculate the future value of both loans. The Stafford Loan will have a higher balance by approximately $234.36.

To determine which loan will have a higher balance at the time of repayment, we need to calculate the future value of both loans. Let's start with the Stafford Loan:

Principal: $5,125

Interest Rate: 6.8%

Compounding Period: Monthly

Time: 12 months

Using the formula for future value of an ordinary annuity, we can calculate the balance of the Stafford Loan at the time of repayment:

FV = P * ((1 + r)^n - 1) / r

FV = 5125 * ((1 + 0.068/12)^(12*1) - 1) / (0.068/12)

Calculating this gives us an approximate loan balance of $5,259.35.

Now let's calculate the future value of the PLUS Loan:

Principal: $5,125

Interest Rate: 7.8%

Compounding Period: Monthly

Time: 12 months

Using the same formula, we can calculate the balance of the PLUS Loan at the time of repayment:

FV = P * ((1 + r)^n - 1) / r

FV = 5125 * ((1 + 0.078/12)^(12*1) - 1) / (0.078/12)

Calculating this gives us an approximate loan balance of $5,024.99.

Therefore, the Stafford Loan will have a higher balance at the time of repayment by approximately $234.36. The correct answer is: The Stafford Loan has a higher balance by $234.36.

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Final answer:

The cross product a~ × b~, where a~ points south and b~ points west, is directed downwards. This direction is determined using the right-hand rule and is perpendicular to the original plane formed by a~ and b~.

Explanation:

If vector a~ points south and vector b~ points west, their cross product a~ × b~ can be determined using the right-hand rule. By pointing the fingers of your right hand towards the direction of a~ (south) and then rotating your wrist to point your fingers towards b~ (west), your thumb will point downwards. Therefore, the direction of a~ × b~ is downwards, which is into the ground if you are standing in the Northern Hemisphere.

The cross product of two vectors is always perpendicular to the plane that contains the original vectors. So in this case, since a~ and b~ are orthogonal and lie in the horizontal plane, their cross product a~ × b~ will be orthogonal to this horizontal plane. As the vectors move from a~ to b~ in an anticlockwise direction, the resultant vector points downward, opposite to the upward direction that would be indicated by b~ × a~.

The solution is : 1.375 is the decimal equivalent of 11/8.

Here, we have,

given that,

equivalent of 11/8

Given the following mathematical expression;

11 /  8

We would apply the law of division for fractions.

11 /  8

= 11 ÷ 8

= 1.375

the decimal form.

Hence, The solution is : 1.375 is the decimal equivalent of 11/8.

To learn more on division click:

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Aimi can make 224 of the smaller Valentine's Day cards after allocating a whole sheet of paper to each of her 6 closest friends, using the 34 sheets of paper she has available.

The subject of the question is mathematics, specifically working with fractions and multiplication to solve a real-world application problem. Aimi is making Valentine's Day cards for her class and needs to calculate how many smaller cards she can make from the paper she has available. She is allocating a whole sheet of paper for each of her 6 closest friends and then needs to determine how many 1/8 sheet cards can be made with the remaining paper.

To solve this, we first calculate the amount of paper used for her close friends: 6 sheets (one for each friend). Then, we subtract this number from the total amount of paper she has, 34 sheets, leaving us with 34 - 6 = 28 sheets for the rest of the class.

The smaller cards use 1/8 of a sheet each, so we divide the remaining sheets by 1/8 to determine how many such cards she can make: 28 ÷ (1/8) = 28 × 8 = 224. Therefore, Aimi can make 224 of the smaller Valentine's Day cards.

Final answer:

After accounting for the 6 full sheets of paper used for her closest friends, Aimi can make 224 of the smaller Valentine's Day cards using the remaining 28 sheets.

Explanation:

Aimi is interested in creating Valentine's Day cards for her class and needs to determine how many of the smaller cards she can make after allocating a whole sheet of paper for each of her 6 closest friends. First, we need to calculate the total amount of paper Aimi will use for her 6 closest friends, which is 6 sheets since she is using one whole sheet per friend. Next, we'll subtract those 6 sheets from the total 34 sheets she has available, leaving us with 28 sheets for the rest of the class.

Since each of the smaller cards uses 1/8 of a sheet of paper, we'll divide the remaining sheets by 1/8 to find out how many of those cards she can make. We perform the following calculation: 28 sheets ÷ 1/8 which equals 224 cards. Therefore, Aimi can make 224 of the smaller Valentine's Day cards.

Final answer:

Using the provided exponential growth function for frog population, 42000 (1.3^t/2), with t=3 for next year, the fraternity should order approximately 59621 tags.

Explanation:

To calculate the number of tags the Epsilon Delta fraternity should order for next year, we need to use the exponential population growth function provided: 42000 (1.3^{t/2}), where t is the number of years since the initial tagging. Since two years ago was t = 0, this year is t = 2. Next year will be t = 3.

Plugging t = 3 into the function, we get:

Tags needed = 42000 (1.3^{3/2})

This is an arithmetic problem involving an exponential function representing the population growth of frogs.

To solve the equation, first calculate 1.3^{3/2}, which is approximately 1.41907. Then multiply this by 42000 to get the number of tags needed for next year.

Tags needed ≈ 42000 * 1.41907

Tags needed ≈ 59621

So the fraternity should order approximately 59621 tags for next year.

Answer:$1000

Step-by-step explanation:my frend found this

The number of bottles which could be filled are:

   Approx 4 bottles ( since we got 4.260 )

One can case of cola holds- 355 mL

This means that:

 24 can case of cola will hold= 24×355 mL

                                                =  8520 mL

Also, 1 L=1000 mL

This means that:

1 mL= 0.001 L

Hence,

8520 mL= 8.520 L

Total amount of cola is: 8.520 L

Now, the number of bottles of 2 L which could be filled from this liquid is:

8.520/2=4.260 bottles.

yep, your answer is A.

Answer: 1) ASA

2) none

3) ASA

Step-by-step explanation:

In the first picture we have two angles and one included side of one triangle is congruent to corresponding two angles and one included side of another triangle, therefore by ASA postulate of congruence both triangles are congruent.

In the second picture , the two have two equal angles, the third angle of both triangles by using angle sum property =[tex]180^{\circ}-70^{\circ}-30^{\circ}=80^{\circ}[/tex],

Now, two corresponding angles and one included side (10 units) of both triangles are congruent  therefore by ASA postulate of congruence both triangles are congruent.

In the third picture, we have two triangle with one same vertex, then their vertical angles must be congruent.

Thus, in third picture, two angles and one included side of one triangle is congruent to corresponding two angles and one included side of another triangle, therefore by ASA postulate of congruence both triangles are congruent.