Answer:
16.11(6)
Step-by-step explanation:
967/60=16 7/60
Describe Bob’s data in terms of center, spread, and shape.
Step-by-step explanation:
Bob's points per game are
5, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15
Calculating Median:
As the median is the middle number in a sorted list of numbers when there is an odd number of terms.
As the the total number of terms = 37
Therefore, the median is the center term which is 10.
5, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15
Calculating Range:
As the given data
5, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15
The range is the difference between the highest and lowest values in the data set.
The lowest value is 5
The highest value is 15
The range = 15 - 5 = 10
Calculating the interquartile range (IQR)
The interquartile range is the difference between the third and first quartiles.
The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers.So, the bottom half is
5 7 7 7 8 8 8 8 8 9 9 9 9 9 10 10 10 10
The median of these numbers is 8.5
The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers.So, the upper half is
10 11 11 11 11 11 12 12 12 12 13 13 13 14 14 14 15 15
The median of these numbers is 12
As
The third quartile is 12
The first quartile is 8.5
Therefore,
The interquartile range = 12 - 8.5 = 3.5
Finding Mode
As the given data
5, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15
The mode of a set of data is the value in the set that occurs most often.
So, It is bimodal.
Therefore, the mode is 10.
Finding Mean
The mean of a data set is the sum of the terms divided by the total number of terms. Using math notation we have:
[tex]Mean=Sum\:of\:terms\:\div Number\:of\:terms[/tex]
[tex]Sum\:of\:terms\:=\:385[/tex]
[tex]Number\:of\:terms\:=\:37[/tex]
[tex]Mean\:=\:\frac{385}{37}=10.4[/tex]
Determining whether the data is symmetrical or non-symmetrical
The data is non-symmetric, they do not have about the same shape on either side of the middle. In other words, if you fold the histogram in half, it does not look about the same on both sides. Please check the histogram attached below.
Calculating Mean Absolute Deviation
The mean deviation is a measure of dispersion, A measure of by how much the values in the data set are likely to differ from their mean.
As the given data
5, 7, 7, 7, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 14, 14, 14, 15, 15
Population size = 37
[tex]Mean=10.4[/tex]
Mean Absolute Deviation (MAD): 2.0
Keywords: mode, median, mean, non-symmetrical data, range, Interquartile Range (IQR)
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After school, Isaac skateboards directly from school to an ice cream parlor and then from the
ice cream parlor to a candy store. The ice cream parlor is 3 miles south of the school and the
candy store is 4 miles east of the ice cream parlor. What is the straight line distance between
the school and the candy store?
Answer:
The straight line distance between the school and the candy store is 5.
Step-by-step explanation:
Use Pythagorean theorem
a²+b²=c²
3²+4²=c²
9+16=c²
25=c²
5=c
The straight line distance between the school and the candy store will be 5 miles.
What is a right-angle triangle?It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function. The Pythagoras is the sum of the square of two sides is equal to the square of the longest side.
After school, Isaac skateboards directly from school to an ice cream parlor and then from the ice cream parlor to a candy store.
The ice cream parlor is 3 miles south of the school and the candy store is 4 miles east of the ice cream parlor.
Then the straight line distance between the school and the candy store will be
[tex]\rightarrow \sqrt{4^2 + 3^2}\\\\\rightarrow \sqrt{16 + 9}\\\\\rightarrow \sqrt{25}\\\\\rightarrow 5[/tex]
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Triangle ABC is a right triangle.
Triangle A B C. Angle A is x degrees, B is 90 degrees, C is (x minus 10) degrees. The exterior angle to angle C is (2 x + 40) degrees.
Which equations can be used to find the value of x? Check all that apply.
x + 90 + (x minus 10) = 180
x + 90 + (2 x + 40) = 180
2 x + 80 = 180
x + 90 = 2 x + 40
(x minus 10) + 90 = 2 x + 40
The equations that can be used to the value of x are 1) x+90+(x-10)=180 and 2) x+90+(2x+40)=180.
Step-by-step explanation:
Two properties can be used to find the value of the x.
1) Sum of Interior angles of a triangle is 180°.
⇒x+90°+(x-10)°=180.
2x+80°=180°.
2x=180°-80°.
2x=100°.
x=50°.
⇒(x-10)°=40°.
2) The Angle of the straight line is 180°.
From the given diagram, BC is a straight line ray with C as intersecting point. this will result in two angles. (refer the diagram).
The sum of those two angles will be 180°.
⇒ (x-10)°+ (2x+40)°=180°.
(3x+30)°=180°.
3x=150°.
x=50°.
∴(x-10)°=40° and (2x+40)° = 140°.
∴The equations that can be used to the value of x are x+90+(x-10)=180 and x+90+(2x+40)=180.
write the slope intercept form of the equation of the line with a slope of -2/5 that passes through 15, -9/2
The slope-intercept form of the equation of the line with a slope of -2/5 that passes through (15, -9/2) is y = -2/5x + 3/2.
Explanation:To write the slope-intercept form of the equation of a line, we use the formula y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slope is -2/5. To find the y-intercept, we substitute the coordinates of the point (15, -9/2) into the equation. Thus, we have:
y = -2/5x + b
-9/2 = -2/5(15) + b
-9/2 = -6 + b
b = -9/2 + 6 = 3/2
Therefore, the equation of the line with a slope of -2/5 that passes through (15, -9/2) is y = -2/5x + 3/2.
Final answer:
The equation of the line with a slope of -2/5 that passes through (15, -9/2) in slope-intercept form is y = (-2/5)x + 3.
Explanation:
The student is asking for the slope-intercept form of an equation of a line with a given slope and a point through which it passes. The slope-intercept form is given by y = mx + b, where m represents the slope and b represents the y-intercept. Given that the slope (m) is -2/5 and the line passes through the point (15, -9/2), we can substitute the slope and the point's coordinates into the slope-intercept formula to find b. Doing so, we get -9/2 = (-2/5)(15) + b. Solving for b, we find that the intercept is 3. Finally, the equation of the line in slope-intercept form is y = (-2/5)x + 3.
What is the domain of this relation?
Answer:
The domain is the set of all first elements of ordered pairs (x-coordinates). The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.
Step-by-step explanation:
What is x in -3x-8y=20, -5x+y=19
Answer:
x = -4
Step-by-step explanation:
solving simultaneously
how do you graph the trigonometric function y= -sin(2x)+1?
Step-by-step explanation:
[tex]\displaystyle \boxed{y = -cos\:(2x - \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 1[/tex]
OR
[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 1[/tex]
You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the centre photograph displays the trigonometric graph of [tex]\displaystyle y = -cos\:2x + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [centre photograph] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cos\:(2x - \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\pi, 1],[/tex]from there to [tex]\displaystyle [-2\pi, 1],[/tex]they are obviously [tex]\displaystyle \pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended one unit beyond the midline, hence, your amplitude. Now, there is one more piese of information you should know -- the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.
I am delighted to assist you at any time.
Nathan ordered one cheeseburger and one bag of chips for $3.75. Jack ordered two cheeseburgers and three bags of chips for $8.25.
Therefore the cost of a bag of chips is $0.75
therefore the cost of a cheeseburger is $3.
Step-by-step explanation:
i) let the cost of a cheesburger be x.
ii) let the cost of a bag of chips be y
iii) therefore it is given that x + y = 3.75
iv) it is also given that 2x + 3y = 8.25
v) multiplying the equation in iii) by 2 we get 2x + 2y = 7.50
vi) subtracting the equation in v) from the equation in iv) we get y = $0.75
vii) Therefore the cost of a bag of chips is $0.75
viii) Substituting the value of y found in vii) into iii) we get x = 3.
ix) therefore the cost of a cheeseburger is $3.
In a trapezoid ABCD with legs AB and CD, the diagonals intersect each other at point O. Compare the areas of △ABO and △CDO.
ar(ΔABO) = ar(ΔCDO)
Explanation:
The image attached below.
Given ABCD is a trapezoid with legs AB and CD.
AB and CD are non-parallel sides between the parallels AD and BC.
In ΔABD and ΔACD,
We know that, triangles lie between the same base and same parallels are equal in area.
⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.
Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)
Now consider ΔABO and ΔCDO,
Subtract ar(ΔAOD) on both sides of (1), we get
ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)
⇒ar(ΔABO) = ar(ΔCDO)
Hence, ar(ΔABO) = ar(ΔCDO).
suppose a 9 minute overseas call costs $6.48 and a 19 minute call costs $13.68. What is the cost, c, of a call of m minutes duration? write a equation to model the cost.
9m = 6.48
Divide both sides by 9:
m = 0.72
19m = 13.68
Divide both sides by 19:
m = 0.72
So a one minute call costs 72 cents. We can now set up an equation like this:
c = 0.72m
Find the perimeter of the polygon
The perimeter of a polygon is found by adding up the lengths of all its sides. The given polygon has a perimeter of 600,000 km. A side labeled 'mfi' would be 300,000 km.
Explanation:To find the perimeter of a polygon, you add up the lengths of all its sides. In this case, the given sides of the polygon are 200,000 km, 100,000 km, and 300,000 km. So adding these together gives you a perimeter of 600,000 km for this polygon.
If you're asked to find the length of a missing side (e.g., the side labeled as 'mfi'), you can subtract the lengths of the known sides from the total perimeter. So, 600,000 km (total perimeter) - 100,000 km - 200,000 km = 300,000 km. Therefore, the length of 'mfi' is 300,000 km.
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The perimeter of the polygon shown is approximately 84.91 centimeters.
According to the given image
∠B = ∠D and AB = AD.
To find the perimeter, break the polygon into smaller shapes and find the perimeters of those shapes.
Note that triangle ABD is isosceles since AB = AD, so ∠ABD = ∠ADB. Draw imaginary segments BC and DC, which create two right triangles, ABC and ADC. Since ∠B = ∠D, it is clear that ∠ABC = ∠ADC. Additionally, it is given that BC = 8.5 cm and DC = 7.5 cm.Now, the Perimeter of triangle ABD is calculated in the following way:
AB = AD (given) = 6.5 cm
We can use the Pythagorean theorem on triangle ABD to find BD:
[tex]BD^2 = AB^2 - (\frac{1}{2} \times AD)^2\\BD^2 = 6.5^2 - (\frac{1}{2} \times 6.5)^2\\BD^2 = 25.5625\\BD \approx 5.05 cm[/tex]
So, the Perimeter of triangle ABD is
= AB + AD + BD
[tex]\approx 6.5 cm + 6.5 cm + 5.05 cm \\ \approx 18.05 cm[/tex]
Again, the Perimeter of triangle ABC is
AC = BC + AB = 8.5 cm + 6.5 cm = 15 cm
As ∠ABC is a right angle and AC is the hypotenuse, use the Pythagorean theorem to find AB:
[tex]AB^2 + BC^2 = AC^2\\AB^2 + 8.5^2 = 15^2\\AB^2 = 81\\AB = 9 cm[/tex]
Perimeter of triangle ABC
= AB + BC + AC = 9 cm + 8.5 cm + 15 cm = 32.5 cm
Perimeter of triangle ADC:
Similar to triangle ABC, find AD using the Pythagorean theorem:
[tex]AD^2 + DC^2 = AC^2\\AD^2 + 7.5^2 = 15^2\\AD^2 = 135\\AD = 3\sqrt{5} cm \approx 11.86 cm[/tex]
Perimeter of triangle ADC
= AD + DC + AC = 11.86 cm + 7.5 cm + 15 cm = 34.36 cm
Finally, to find the perimeter of the entire polygon, add the perimeters of the three triangles:
Perimeter of polygon = Perimeter of triangle ABD + Perimeter of triangle ABC + Perimeter of triangle ADC
Perimeter of polygon is
[tex]\approx 18.05 cm + 32.5 cm + 34.36 cm \approx 84.91 cm[/tex]
Therefore, the perimeter of the polygon is approximately 84.91 centimeters.
What is 84,396 + 29,760
Answer:
114, 156
Step-by-step explanation:
Answer: 114,156
Step-by-step explanation:
To add 84,396+29,760 you must add each row.
6+0 = 6
9+6 = 15 (Carry up the one)
3+7 = 10 + 1 = 11 (Carry up the one)
4+9 = 13 + 1 = 14 (Carry up the one)
8+2 = 10 + 1 = 11
So the answer will be 114,156
9e-7=7e-11 the answer
Answer:
e=-2
Step-by-step explanation:
9e-7=7e-11
9e-7e-7=-11
2e-7=-11
2e=-11+7
2e=-4
e=-4/2
e=-2
Answer:
e=2
Step-by-step explanation:
What is the solution of the system?
10x – 2y = 24
6x+2y = 8
Answer: x = 2 , y = 5
Step-by-step explanation:
10x - 2y = 24 ..................... equation 1
6x + 2y = 8 ........................ equation 2
solving the system of linear equation by elimination method , add equation 1 and 2
16x = 32
divide through by 16
x = 2
substitute x = 2 into equation 1 to find the value of y
10(2) - 2y = 2y
20 - 2y = 2y
20 = 4y
y = 5
Last year a bamboo plant was 17 feet tall. It grew 10 feet this year. How tall is it now?
Answer:
27 is the right answer
Step-by-step explanation:
10+17=27 :)
write the following decimals in order from smallest to largest: .021, .12, .2, .02
What is the slope of y-3=-4(x-5)
Answer:
-4
Step-by-step explanation:
y-3=-4(x-5)
y=-4x+20+3
y=-4x+23
y=mx+b where m=slope and b=y-intercept
What is the equation of points (8,16)
Answer:
86
Step-by-step explanation:
Here’s another one thank u all for helping me. I really appreciate it!
Area = Square - Circle
Area of Square = 10² = 100 m²
Area of Circle = π(5²) = 25π m²
Area of Shaded Region = 100 - 25π = 21.5 m² approx.
answer: second choice
what dose 5x+3-48 mean because im strugling in math at south county middle school and im doing this on horizon
Answer:the answer is 40
Step-by-step explanation:
Because you do 5 times x
Answer:-9
Step-by-step explanation:5x+3-48 you do 3-48 you get -45 then you divide 5x by -45 and you get the final answer of -9.
2b + 8 - 5b + 3 = -13 + 8b - 5
Answer:
The final value of [tex]b=\frac{29}{11}[/tex] .
Step-by-step explanation:
Given:
[tex]2b + 8 - 5b + 3 = -13 + 8b - 5[/tex]
We have to find the value of [tex]b.[/tex]
[tex]2b + 8 - 5b + 3 = -13 + 8b - 5[/tex]
Steps to be followed:
Step 1:Bring all the variables one left side of the equation.Subtract 8b both side.
[tex]2b + 8 - 5b + 3-8b = -13 + 8b - 5-8b[/tex]
[tex]2b - 5b -8b+ 3 +8= -13 - 5[/tex]
Step 2:Add the variable and constants on each side.[tex]2b - 5b -8b+ 3 +8= -13 - 5[/tex]
[tex]-11b+11=-18[/tex]
Step 3:Subtract 11 on both side.[tex]-11b+11=-18[/tex]
[tex]-11b+11-11=-18-11[/tex]
[tex]-11b=-29[/tex]
Step 4:Divide -11 on both sides of the equation.[tex]-11b=-29[/tex]
[tex]b=\frac{-29}{-11} =\frac{29}{11}[/tex]
So the final value of b is 29/11.
Round 1,208.7438 to the nearest hundredth.
A. 1,208.73
B. 1,208.74
C. 1,208.743
D. 1,208.75
Answer:
the answer is 1,208.74
Please help me with this!
Answer:
Step-by-step explanation:
i don't know I am a forth grader
.10.A cone with a height of 15 yards has a volume of 457.17 yd3 . Find the diameter of the cone
[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=457.17\\ h = 15 \end{cases}\implies 457.17=\cfrac{\pi r^2(15)}{3}\implies 457.17=5\pi r^2 \\\\\\ \cfrac{457.17}{5\pi }=r^2\implies \sqrt{\cfrac{457.17}{5\pi }}=r\implies 5.39 \approx r~\hfill \boxed{\stackrel{diameter = 2r}{2(5.39) = 10.78}}[/tex]
Write the equation of a line parallel to the line y=2x that passes through the given points. a. (0,4) b.(-2,-1) c.(2,0)
Answer:
ju mmmmmmjjum,,,,i,,,,, enjoy
Step-by-step explanation:
Answer:
its option b: (-2,-1)
Step by step:
y=2x
-2=2(-1)
-2=-2
Infinitely many solutions
What should be subtracted from 3x^2-4y^2+5xy+20 to obtain x^2+y^2+6xy+20?
Answer:
2x² − 5y² − xy
Step-by-step explanation:
3x²- 4y² + 5xy + 20
−
x² + y² + 6xy + 20
________________
2x² − 5y² − xy + 0
8 1/3 subtract 2 2/3
Answer:
5 2/3........................
The solution set for -18 < 5 x - 3 is _____.
a -3 < x
b 3 < x
c -3 > x
d 3 > x
-18 < 5x - 3 Isolate/get x by itself, first add 3 to both sides of the equation
-18 + 3 < 5x - 3 + 3
-15 < 5x Divide 5 on both sides
-3 < x Your answer is A
You flip the sign [</>] if you multiply or divide a negative number to both sides of the equation.
Jane sold 100 tickets for her school auction. Adult tickets cost $12 and the children tickets cost $8. Jane collected a total of $944. Write a system of equations for this situation
Answer:
see the explanation
Step-by-step explanation:
Let
x ----> number of adult tickets
y ----> number of children tickets
we know that
Jane sold 100 tickets for her school auction
so
[tex]x+y=100[/tex] ----> equation A
Jane collected a total of $944
[tex]12x+8y=944[/tex] ----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (36,64)
see the attached figure
therefore
The number of adult tickets sold was 36 and the number of children tickets sold was 64
You are told that in a billiards shot, the cue ball was shot at the eight ball, which was 8 inches away. As a result, the eight ball rolled into a pocket, which was 6 inches away.
Knowing that the angle made with the path of the cue ball and the resulting path of the eight ball is larger than 90°, it can be determined that the original distance from the cue ball to the pocket was greater than ____ inches
DISCLAIMER:
I know the answer is 10 but I don't know why, I thought I did the math right but I got 100. I'll give brainliest if you explain it well!
Answer:It is greater than 10 because as you add both distances from the image its greater than 10 by a bit, looking at the angle it gives you a bigger perspective in how far the cue ball is from the pocket
Its basically 8+6 which equals 14 but adding the way the angle is going the distance is shorter than 14 but greater than 10
Answer:
10 inches
Explanation:
correct on edge